2 decimal places as needed!!!
A truck with 18 -in.-diameter wheels is traveling at 55{mph} . Round answers to 2 decimal places as needed. How many revolutions per minute do the wheels make? rpm What is the angular spe

Answer:

Step-by-step explanation:

red

Answer:

\(\sf x =\dfrac{2}{3}\)

Explanation:

\(\sf \rightarrow \dfrac{x+1}{2} = \dfrac{7x-3}{2}\)

cross multiply

\(\sf \rightarrow 2(x+1) = 2(7x-3)\)

divide both sides by 2

\(\sf \rightarrow x + 1 = 7x-3\)

isolate variables

\(\sf \rightarrow x -7x = -3-1\)

simplify

\(\sf \rightarrow -6x = -4\)

divide both sides by -6

\(\sf \rightarrow \dfrac{-6x}{-6} = \dfrac{-4}{-6}\)

simplify

\(\sf \rightarrow x =\dfrac{2}{3}\)

Answer:

\(x=\dfrac{2}{3}\)

Step-by-step explanation:

Given equation:

\(\dfrac{x+1}{2}=\dfrac{7x-3}{2}\)

Step 1: Multiply both sides by \(2\).

\(\implies 2\left(\dfrac{x+1}{2}\right)=2\left(\dfrac{7x-3}{2}\right)\)

\(\implies x+1=7x-3\)

Step 2: Subtract \(7x\) from both sides.

\(\implies x-7x+1=7x-7x-3\)

\(\implies -6x+1=-3\)

Step 3: Subtract \(1\) from both sides.

\(\implies -6x+1-1=-3-1\)

\(\implies -6x=-4\)

Step 4: Divide both sides by \(-6\) and simplify.

\(\implies \dfrac{-6x}{-6}=\dfrac{-4}{-6}\)

\(\implies x=\dfrac{4}{6}=\boxed{\dfrac{2}{3}}\)

Answer:

exact form: n=378/13

decimal form: n=29.0769....

mixed number form: n=\(29\frac{1}{13}\)

Step-by-step explanation:

Answer:

n = 21

Step-by-step explanation:

\(\frac{n}{2}-\frac{3n}{9}+\frac{5n}{9}=21\\\\\frac{9n}{18}-\frac{6n}{18}+\frac{10n}{18}=21\\\\\frac{3n}{18}+\frac{10n}{18}=21\\\\\frac{13n}{18}=21\\\\13n=273\\\\n=21\)

Steps:

1. Write as fractions

2. Make the fractions have the same denominator

3. Collect like terms

4. Collect like terms

5. Multiply both sides by 18

6. Divide both sides by 13.

According to the given statement the slope of the tangent line at x=2 for the function y=x²-2x is 2.

To find the slope of the tangent line at x=2,

we need to find the derivative of the function y=x²-2x.

The derivative represents the rate of change of the function at a particular point.

Step 1: Find the derivative of the function using the power rule.

For any term of the form xⁿ, the derivative is n*xⁿ⁻¹.

y' = d/dx (x²-2x)
  = 2x²⁻¹ - 2*1*x¹⁻¹
  = 2x - 2

Step 2: Substitute x=2 into the derivative to find the slope at that point.
slope at x=2 = 2*2 - 2
             = 4 - 2
             = 2

The slope of the tangent line at x=2 for the function y=x²-2x is 2.

The tangent line represents the instantaneous rate of change of the function at that point.

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Using hypothesis test we obtain that that the soft drink market share of Coca-Cola at the school is different from 47%.

To determine whether the soft drink market share of Coca-Cola at the school is different from 47%, we can conduct a hypothesis test using the data provided.

Let's set up the null and alternative hypotheses:

Null Hypothesis (H0): The soft drink market share of Coca-Cola at the school is 47%.

Alternative Hypothesis (H1): The soft drink market share of Coca-Cola at the school is different from 47%.

To perform the hypothesis test, we can use the chi-square goodness-of-fit test, which compares the observed frequencies with the expected frequencies under the assumption of the null hypothesis.

First, let's calculate the expected frequencies under the assumption that Coca-Cola's market share is 47%:

Expected frequency of Coca-Cola = (47% of 216) = 0.47 * 216 = 101.52

Expected frequency of other soft drinks = 216 - 101.52 = 114.48

Now, we can set up a chi-square test statistic:

χ^2 = Σ [(Observed frequency - Expected frequency)^2 / Expected frequency]

χ^2 = [(81 - 101.52)^2 / 101.52] + [(216 - 114.48)^2 / 114.48]

χ^2 = 7.96

Next, we need to determine the critical value for the chi-square test at a specified level of significance (e.g., α = 0.05).

The degrees of freedom for this test would be (number of categories - 1) = 1.

Looking up the critical value in a chi-square distribution table or using a statistical software, the critical value for α = 0.05 and 1 degree of freedom is approximately 3.841.

Since our test statistic (χ^2 = 7.96) is greater than the critical value (3.841), we can reject the null hypothesis.

Therefore, based on the given data, we have evidence to suggest that the soft drink market share of Coca-Cola at the school is different from 47%.

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Answer: 9.7 seconds

Step-by-step explanation:

\(16t^2=1503\\\\t^2 =\frac{1503}{16}\\\\t=\sqrt{1503/16} \text{ } (t > 0)\\\\t \approx 9.7\)

The null hypothesis to test for instruments' relevance is option D) H0:π2=0 or π3=0 or π4=0.In order to test the relevance of the instrument, the first stage equation's null hypothesis should be stated as: H0: π2 = 0 or π3 = 0 or π4 = 0.The relevance requirement will be fulfilled if we can refute the null hypothesis.

The null hypothesis will not be rejected if the F-statistic is less than 10.0. However, if the F-statistic is greater than 10.0, the null hypothesis will be rejected, indicating that the variables are relevant and that the instrument satisfies the relevance requirement.In summary, to test for instruments' relevance in TSLS, the null hypothesis of the first stage equation is stated as H0: π2 = 0 or π3 = 0 or π4 = 0.

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Answer:

C)  y = -2x - 5

Step-by-step explanation:

\(\sf let \ (x_1,y_1)=(-3,1)\\\\let \ (x_2,y_2)=(0,-5)\)

\(\sf slope=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-5-1}{0-(-3)}=-2\)

Point-slope formula: \(\sf y-y_1=m(x-x_1)\)

\(\sf \implies y-1=-2(x-(-3))\)

\(\sf \implies y=-2x-5\)

Slope:-

Equation in point slope form

Answer:

The directional bearing of the boat is N 30º E

Step-by-step explanation:

Let \(\vec v = (25, 25\sqrt{3})\), where \(\vec v\) is the vector velocity. Given that such vector is represented in rectangular, a positive value in the first component is the value of the vector in the east direction, whereas a positive value in the second component is in the north direction. The directional bearing of the boat (\(\theta\)), measured in sexagesimal degrees, is determined by trigonometrical means:

\(\theta = \tan^{-1}\frac{v_{y}}{v_{x}}\) (1)

If we know that \(v_{x} = 25\) and \(v_{y} = 25\sqrt{3}\), then the directional bearing of the boat is:

\(\theta = \tan^{-1} \sqrt{3}\)

\(\theta = 60^{\circ}\)

In consequence, we conclude that the direction bearing of the boat is 30 degrees to the East from the North (N 30º E).

Answer:

A) N 30 E

Step-by-step explanation:

Answer:

300

Step-by-step explanation:

330/110

=3=value of 1%

3*100

=300

or

x=(330*100)/110

=300

The final design of the LPDA with one extra element added to each end would have a total of 12 dipole elements with the first and last elements extended by half a wavelength at the lowest frequency, and a spacing of 0.225 meters between the additional elements.

LPDA (Log-Periodic Dipole Array) antennas are popular for their wideband characteristics, which makes them useful for a variety of applications. In this case, we need to design an LPDA to operate from 470 to 890 MHz with 9-dB gain and add one extra element to each end.

To design the LPDA, we need to determine the physical parameters such as the length and spacing of the dipole elements. One way to do this is to use the following formulas:

Length of dipole element (in meters) = 0.95 × (speed of light / frequency)

Spacing between dipole elements (in meters) = 0.47 ×(speed of light / frequency)

where the speed of light is 299,792,458 meters per second.

Using these formulas, we can calculate the length and spacing for the LPDA as follows:

For the lower frequency of 470 MHz, the length of the dipole element is 1.34 meters and the spacing between the elements is 0.67 meters.

For the higher frequency of 890 MHz, the length of the dipole element is 0.71 meters and the spacing between the elements is 0.35 meters.

Next, we need to determine the number of dipole elements required to achieve the desired gain of 9 dB. One way to do this is to use the following formula:

Number of dipole elements = log10(higher frequency / lower frequency) / log10(cos(angle of radiation))

where the angle of radiation is typically between 50 and 60 degrees.

Assuming an angle of radiation of 55 degrees, we can calculate the number of dipole elements required as follows:

Number of dipole elements = log10(890 MHz / 470 MHz) / log10(cos(55 degrees)) = 9.7

Since we can't have fractional elements, we'll round up to 10 dipole elements.

To add an extra element to each end, we can simply extend the first and last dipole elements by half a wavelength at the lowest frequency. This will provide additional gain at the lower frequency while not affecting the performance at the higher frequency.

Finally, we need to determine the spacing between the additional elements. We can use the same formula as before to calculate the spacing between the additional elements as 0.47 × (speed of light / 470 MHz) = 0.225 meters.

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To design an LPDA for 470-890 MHz with 9 dB gain. Use the LPDA formula to calculate the length and spacing of each element, and adjust the values to optimize performance.

To design an optimum LPDA (Log-Periodic Dipole Array) with a frequency range from 470 to 890 MHz and a gain of 9 dB, follow these steps:

1. Determine the length of the LPDA by using the formula:

   L = (0.95 x c) / fmin

  where L is the total length of the LPDA, c is the speed of light (3 x 10^8 m/s), and fmin is the minimum frequency (470 MHz).

  L = (0.95 x 3 x 10^8 m/s) / 470 MHz = 0.62 m

  Therefore, the total length of the LPDA should be approximately 0.62 meters.

2. Calculate the number of elements required using the formula:

   N = log(fmax/fmin) / log(2)

  where N is the number of elements, fmax is the maximum frequency (890 MHz).

  N = log(890 MHz/470 MHz) / log(2) = 1.26

  Round up the result to the nearest integer, which is 2.

  Therefore, the LPDA should have a total of 2+1=3 elements.

3. Determine the spacing between each element by using the formula:

   D = 0.25 x c / fmin / cos(θ)

  where D is the spacing between each element, θ is the half-power beamwidth of the LPDA (typically between 50-70 degrees).

  Let's assume a half-power beam width of 60 degrees.

  D = 0.25 x 3 x 10^8 m/s / 470 MHz / cos(60) = 0.075 m

  Therefore, the spacing between each element should be approximately 0.075 meters.

4. Calculate the lengths of the elements by using the formula:

   Ln = L x 10^-Cn / 2

  where Ln is the length of each element, L is the total length of the LPDA, and Cn is a constant that depends on the element number.

  For a three-element LPDA, the values of Cn are typically 0, -0.25, and -0.5.

  L1 = 0.62 x 10^(-0/2) = 0.62 m

  L2 = 0.62 x 10^(-0.25/2) = 0.54 m

  L3 = 0.62 x 10^(-0.5/2) = 0.48 m

  Add one extra element to each end, which should be shorter than the other elements. Let's assume each end element is half the length of the other elements:

  L4 = L1/2 = 0.31 m

  L5 = L3/2 = 0.24 m

5. Assemble the LPDA by attaching each element to a support structure and connecting the elements together with a balun or transformer.

By following these steps, an optimum LPDA can be designed to operate from 470 to 890 MHz with 9 dB gain, while adding one extra element to each end.

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Find the slope of the given line

If we put the line 2x - 5y = 35 into the y = mx + c form, the coefficient of x (m) is the slope.

                           since     2x - 5y = 35

                               ⇒              5y = 2x - 35

                                                   y = ²/₅ x - 7

                  ∴      the slope of the line is ²/₅

Identify the slope of the parallel line

When two lines are parallel, they have the same slope.

              ∴ the slope of the parallel is also ²/₅  

Determine the equation of the parallel line

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line where (x₁ , y₁) is (5,−2) :    

                             y - (-2)  =  ²/₅   (x - 5)

                              y + 2 = ²/₅   (x - 5)

If we were to write the equation in the same form as the line that was given:

                                 since  y + 2 = ²/₅   (x - 5)

                                                  y =  ²/₅  x - 2 - 2

                                      y -  ²/₅  x  = - 4      [multiply through by 5]

                                         5y - 2x = -20

To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.

Based on the mentioned informations and provided values, 21 red beads were removed.

Let the number of red beads removed be x. Then we have:

Total points = (7x + 5y + 3z + 2w) = 147000, where y, z, w are the number of yellow, green, and blue beads removed, respectively.

We can also write the above Linear equation as:

7x = 147000 - 5y - 3z - 2w

Since 147000 is divisible by 1000, we can divide both sides by 1000 to get:

7x = 147

x = 21

Therefore, 21 red beads were removed.

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Multiple Regression is the regression analysis involving one dependent variable and more than one independent variable.

A regression is a technique that relates a dependent variable [response]  to one or more independent (explanatory) variables.

The linear regression equation is in the form, y = mx + b ., where X is an Independent variable and Y is a Dependent variable.

Multiple regression is a  technique that can be used to analyze the relationship between a single dependent variable and several independent variables.

The objective of multiple regression analysis is to use the independent variables whose values are known to predict the value of the single dependent value.

Y = a + b₁X₁+ b₂X₂ + .........+ bₙXₙ

Hence, Multiple Regression analysis involving one dependent variable and more than one independent variable.

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Answer:

m<HJF = \(56^{o}\)

Step-by-step explanation:

From the given diagram, ΔFHJ is similar to ΔFEG. So that;

m<HJF = m<EGJ

⇒ 10x + 36 = 6x + 44

10x - 6x = -36 + 44

4x = 8

x = \(\frac{8}{4}\)

x = 2

Substitute the value of x in the expression for m<HJF to have,

m<HJF = 10x + 36

           = 10(2) + 36

           = 20 + 36

m<HJF = \(56^{o}\)

The measure of angle HJF is \(56^{o}\).

Answer:

14 feet

Step-by-step explanation:

We solve the above question by using the Greatest Common Factor method

We find the factors of 56 and 98

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

The factors of 98 are: 1, 2, 7, 14, 49, 98

Then the greatest common factor is 14.

Therefore, the greatest possible length you can cut the rope so all pieces will be the same is 14 feet

Answer:

1. AB= 8.94,

2. AB= 7.28

3. AB= 16.4

4. AB= 19.21

Step-by-step explanation:

This is fun! Well you have to find the (1,4) (or point e) point and count the distance to the other points point a and point b.

4 units from a to e and 8 b to e

a² + b² = c²

8² + 4² = c²

64 +16 = c

√80 = √c²

8.94 = c

It dose not matter which units you plug in for a and b but c has to be the long side of the triangle/ hypotonuse.

Follow the same steps for the rest of the problems.

On proplems 3 and 4 plot points first you can subtract the x-x and y-y as a short cut to find the units.

Answer

Number 14: 7 faces, 15 edges, and 10 vertices.

Number 15: 10 faces, 24 edges, and 16 vertices.

Number 16: 7 faces, 12 edges, and 7 vertices.

:D

Step-by-step explanation:

When a car aerial absorbs radio waves, it induces a small electric current in the electrical circuit. This current flows through the circuit, reaching the radio receiver, where it is processed and amplified to produce an audible sound.

The car aerial, also known as an antenna, is designed to capture radio waves from the surrounding environment. These radio waves are electromagnetic waves that carry information in the form of varying frequencies. When the aerial absorbs these radio waves, it acts as a receiving element.

The electrical circuit connected to the car aerial plays a crucial role in the process. The radio waves induce a small alternating current in the aerial. This current is generated due to the interaction between the radio waves and the conductive components of the aerial. The induced current flows through the circuit, which typically includes a coaxial cable, connectors, and the necessary wiring.

The current travels from the aerial to the radio receiver, which is usually located in the car's dashboard. The receiver detects the current and processes it using electronic components such as transistors and integrated circuits. The received signal is amplified and filtered to extract the desired radio frequency. Finally, the amplified signal is sent to the car's speakers, allowing the listener to hear the audio content carried by the radio waves.


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Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

tanx = \(\frac{sinx}{cosx}\) , sin²x + cos²x = 1, secx = \(\frac{1}{cosx}\)

Consider left side

tanAsinA + cosA

= \(\frac{sinA}{cosA}\) × sinA + cosA

= \(\frac{sin^2A}{cosA}\) + cosA

\(\frac{sin^2A+cos^2A}{cosA}\)

= \(\frac{1}{cosA}\)

= secA = right side , thus proven

The smallest possible inside length of the cubical steel tank that can hold 275 liters of water is approximately 0.640 meters.

The side length of the cube is found by converting the volume of water from liters to cubic meters, as the unit of measurement for the side length is meters.

Given that the volume of water is 275 liters, we convert it to cubic meters by dividing it by 1000 (1 cubic meter = 1000 liters):

275 liters / 1000 = 0.275 cubic meters

Since a cube has equal side lengths, we find the side length by taking the cube root of the volume. In this case, we find the cube root of 0.275 cubic meters:

∛(0.275) ≈ 0.640

Rounded to the nearest 0.001 meters, the smallest possible inside length of the tank is approximately 0.640 meters.

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Answer:

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

\(2x^{2}\) = 36

\(\sqrt{2x^{2}}\) = \(\sqrt{36}\)

2x = 6

\(\frac{2x}{2}\) = \(\frac{6}{2}\)

x = 3

hope this helps!

Answer:

A is the right answer for your question.

The volume of the cube-shaped  = 1,331 volume of the hole cut out of the block = 125 cubic inches Subtract 1331 - 125 = 1206, the correct option is A

volume of the hole cut out of the block = 5 inches x 5 inches x 5 inches

volume of the hole cut out of the block = 125 cubic inches.

volume of the cube-shaped block = 11 inches x 11 inches x 11 inches

volume of the cube-shaped block = 1,331

To find the volume of the wood remaining after the hole is cut out, we can subtract the volume of the hole from the volume of the block:

1,331 cubic inches - 125 cubic inches = 1,206 cubic inches

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Answer:

D

Step-by-step explanation:

simplify:

3x+9>x+33

2x>24

x>12

now see the graphs, and B and D both are marked with 12

but D has no filled circle, so that is the right answer

I hope this helped, and if my answer was right, please mark this as brainliest! Thank you!

Answer:

C 2496 in3

Step-by-step explanation:

Answer:

2496 in3

Step-by-step explanation:

Volume = LWH

24*8*13 = 2496

Answer:

x = 68°

Step-by-step explanation:

∠ DCB = ∠ EDC = 27° ( alternate angles )

Thus ∠  ECB = 23° + 27° = 50°

The sum of the 3 angles in a triangle = 180°, thus

x = 180° - (62 + 50)° = 180° - 112° = 68°

Answer:

68°

Step-by-step explanation:

DE ║ BC

So, ∠DBC = ∠ADE = 62° (∵ Corresponding Angles are equal )

In triangle DEC ,

∠EDC+ ∠ECD = ∠AED (∵ Exterior Angle Sum Property of a triangle )

⇒ ∠AED = 23° + 27° = 50°

Now in triangle AED ,

∠EAD + ∠ADE + ∠AED = 180°

⇒ x° + 62° + 50° = 180°

⇒x° = 180° - 112° = 68°

Answer:

Benidorm quiz  

1. Where is Benidorm holiday resort located?  

JORDAN  

2. What is the average temperature of Benidorm in summer?  

26 C  

3. Before 1950s Benidorm was a small ___FISHING______ village.  

4. Why did the town council encourage tourism in Benidorm?  

TO VISIT BENIDORM  

5. How many hotels were found in Benidorm in 1959?  

6. Explain package holidays as they were used in Benidorm                                                                                

7. Give three reasons why Benidorm is an excellent tourist resort  

(a)  

(b)  

©  

8. State four tourist attractions at Benidorm

Step-by-step explanation:

Benidorm quiz  

1. Where is Benidorm holiday resort located?  

JORDAN  

2. What is the average temperature of Benidorm in summer?  

26 C  

3. Before 1950s Benidorm was a small ___FISHING______ village.  

4. Why did the town council encourage tourism in Benidorm?  

TO VISIT BENIDORM  

5. How many hotels were found in Benidorm in 1959?  

6. Explain package holidays as they were used in Benidorm                                                                                

7. Give three reasons why Benidorm is an excellent tourist resort  

(a)  

(b)  

©  

8. State four tourist attractions at Benidorm