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An atom, which is an isotope of an element, is characterized by -
O having more electrons in its nucleus.
O having more neutrons in its nucleus.
having fewer protons in its nucleus.
having more protons in its nucleus.

Answer:

121.67 g is to be added to 500 g of water

Explanation:

Given that:

Pressure = 750 mmHg

Temperature T₁= 99.63⁰C = (273 + 99.63 ) = 372.63K

mass of water = 500 g

Temperature T₂  = 100⁰C = ( 273 + 100) K = 373 K

where;

Kb for water 0.52 K Kg mol-1

For sucrose; C₁₂ H₂₂ O₁₁

Molar mass =  ( 12 × 12 )+ ( 1 × 22 ) + ( 16 × 11 )

Molar mass = 342 g/mol

ΔT = T₂  - T₁

ΔT = (373 - 372.63)K

ΔT = 0.37 K

∴ the amount of sucrose to be added to  500 g of water is:

 \(= \dfrac{0.37\times 342 \times 500}{0.52 \times 1000 }\)

\(= \dfrac{6327}{52}\)

= 121.67 g

Thus; 121.67 g is to be added to 500 g of water

The electron configuration of valence electrons of carbon before and after sp hybridization are shown below:Before hybridization: 2s2 2p2After hybridization: sp2 2p2The orbital diagram before sp hybridization shows two electrons in the 2s orbital and two electrons in each of the 2p orbitals. After hybridization, the 2s orbital mixes with one of the 2p

orbitals to form two sp hybrid orbitals. These sp hybrid orbitals are oriented at 180° to each other, which allows maximum overlap with two 2p orbitals of the carbon atom. The remaining 2p orbital remains unhybridized and

unchanged. Therefore, the hybridized orbitals contain only one electron each and the unhybridized 2p orbital has two electrons.The boxes with arrows in the orbital diagram represent the orbitals and their electrons. The label "2s" is

dragged to the box representing the 2s orbital before hybridization. Similarly, the labels "2p" and "sp" are dragged to the boxes representing the unhybridized and hybridized orbitals after hybridization, respectively. The label "2p" is also dragged to the unhybridized 2p orbital after hybridization.

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The actual yield of the product obtained in the experiment must be divided by the theoretical yield of the product that could be achieved. The reaction's percent yield is 32% as a result.

The amount of product produced in a chemical reaction or manufacturing process is referred to as yield, and it is typically expressed in mass or volume. Theoretical yield, actual yield, and percent yield are a few of the several types of yield. Theoretical yield, under the assumption that the reaction continues to completion without any losses or side reactions, is the greatest quantity of product that can be produced from a specific amount of reactants. The amount of product that is actually produced during an experiment or production process is known as the "actual yield." The actual yield to theoretical yield ratio, stated as a percentage, is known as percent yield. The efficiency and profitability of a chemical reaction or manufacturing process are significantly influenced by yield.

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1. A proper progression utilizing conversion factors would be km to feet to inches.

2. Conversion factors allow you to effectively cross out the appropriate units along each step of the problem.

3. 246,000 mm is how many Km is 0246.

4. There are 2 electrons in the s orbital, and 3 in the p orbital.

A conversion factor is a number used to convert one set of units to another set by multiplication or division. If the conversion is required, the values ​​should be equal using the appropriate conversion factor. To find the electron configuration of an atom, we first need to know how many electrons the atom has. Aluminum has an atomic number of 13, so it has 13 electrons.

The last shell after the electron configuration is called the valence shell. The total number of electrons in the valence shell is called valence electrons. The electron configuration of the aluminum shows that there are three electrons in the last shell of aluminum. Therefore the valence electron of aluminum is 3 The outermost valence shell of aluminum has three electrons. Al now has an electronic configuration similar to the noble gas neon so it can donate three electrons to form a cation.

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Answer: Oxidation number of chlorine in potassium chlorate...

so, oxidation state of chlorine in potassium chlorate is +1. and yea!!

Explanation: hope this help

The ionic species, when added to pure water, would result in a change in pH is A. I and II

The addition of ionic species to pure water can result in a change in pH due to their ability to either donate or accept protons. In this case, the ionic species that can cause a change in pH are those that contain a weak acid or a weak base. Option I, KHCOO, is a weak acid salt and can undergo hydrolysis in water, resulting in the formation of H+ ions and therefore a decrease in pH. Option II, NaF, is a salt of a weak base and a strong acid. It will not have a significant effect on the pH of pure water.

Option III, Ba(NO³)², is a salt of a strong acid and a strong base, and it will also not have a significant effect on the pH of pure water. Option IV, CH³NH³Br, is a salt of a weak base and a strong acid and can undergo hydrolysis in water, resulting in the formation of OH⁻ ions and therefore an increase in pH. Therefore, the correct answer is A. I and II, as only KHCOO and CH³NH³Br can cause a change in pH when added to pure water.

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Answer:

The function of the mitochondria is to obtain and convert energy. What body system has a similar function?

Explanation:

Chloroplasts are very similar to mitochondria, but are found only in the cells of plants and some algae. Like mitochondria, chloroplasts produce food for their cells. Chloroplasts help turn sunlight into food that can be used by the cell, a process known as photosynthesis

The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.

Case 1: HD​:pSun ​=rhoMan ​=pTue ​=pWed ​=pThu ​=pFri ​=pSat ​=71​
Ha​ : Not all proportions are equal.

Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\)  where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.  
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)

We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)

Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)

Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)

The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)

From the above percentages, we can see that Friday has the highest percentage of traffic accidents.

Case 2:
HD​: Not all proportions are equal.

Ha​:pSun ​=pMon ​=pTue ​=rhoWed ​=pThu ​=rhoFri ​=rhoSat ​=71

Test Statistic

\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)

We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic can be computed as:

\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

Case 3:

All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic is,

\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)

The p-value is 0.1664.

Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

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The term is used to describe the electrons present in the outermost energy level is the valence electrons.

The number of the electrons in the outermost shell of the particular atom that determines its reactivity, or the tendency to form the chemical bonds with the other atoms. This is the outermost shell and is known as  valence shell, and the electrons present in it are called the valence electrons.

The electrons are on the outermost energy level of the atom are called the valence electrons. These are the electrons that involved in the bonding and the chemical reactions. The other electrons are the  core electrons.

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The presence of the ions in the HCl would make the solution to conduct electricity.

Because it separates into ions (H+ and Cl-) when hydrochloric acid is dissolved in water, HCl (hydrochloric acid) solution conducts electricity. The electric charge of the H+ and Cl- ions allows them to travel and convey current across the solution.

The dissociation constant (Ka) of HCl describes how much of the compound separates into ions depending on the concentration of the solution. A higher HCl concentration will produce more ions, which will increase conductivity.

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The nucleus of the radioactive carbon isotope before any decay contains 6 protons and 8 neutrons.

The radioactive carbon isotope mentioned in the passage is most likely carbon-14 (C-14). Carbon-14 has an atomic number of 6, which means it has 6 protons in its nucleus. Protons are positively charged particles found in the nucleus of an atom.

To determine the number of neutrons in the nucleus of carbon-14, we need to subtract the atomic number (protons) from the atomic mass. Carbon-14 has a mass number of 14, so subtracting the atomic number of 6 from the mass number gives us 8 neutrons.

Therefore, the nucleus of the radioactive carbon isotope before any decay contains 6 protons and 8 neutrons.

In summary:
- Atomic number of carbon-14: 6
- Protons in the nucleus: 6
- Mass number of carbon-14: 14
- Neutrons in the nucleus: 14 - 6 = 8


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Answer:

Explanation:

There are seven periods in the periodic table, with each one beginning at the far left. A new period begins when a new principal energy level begins filling with electrons. Period 1 has only two elements (hydrogen and helium), while periods 2 and 3 have 8 elements.

Answer:

2,3-dimethyl pentane.........

Answer:

Two Helium atoms

If two carbon atoms underwent fusion (of 600 million kelvin) you would get two helium atoms.

The mass percent of gold in the piece is 79.08%

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

Thus,

Mass = density × volume

Mass = density × volume

Mass of gold = 19.3 × V

Mass of gold = 19.3V

Mass = density × volume

Mass of silver = 10.5 × (1.25 - V)

Mass of silver = 13.125 - 10.5V

Mass of piece = mass of gold + mass of silver

20.5 = 19.3V + 13.125 - 10.5V

Collect like terms

19.3V - 10.5V = 20.5 - 13.125

8.8V = 7.375

Divide both sides by 8.8

V = 7.375 / 8.8

Volume of gold = 0.84 cm³

Thus,

Mass of gold = 19.3V

Mass of gold = 19.3 × 0.84

Mass of gold = 16.212 g

Mass percent of gold = (mass of gold / mass of piece) × 100

Mass percent of gold = (16.212 / 20.5) × 100

Mass percent of gold = 79.08%

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Answer: Possibility of a single replacement reaction

Explanation:

The activity of the series of element is determined by the single replacement reactions. The activity series of element can be used to predict the possibility of a single replacement reaction.

A single replacement reaction is one in which one substance is replacing the other. The replacement of a metallic ion in solution by a metal atom higher in the activity series than the metal in solution falls into this category of reactions.

The reaction is depending on the reactivity of the elements. If the reactivity of the elements is very low, then the reaction very slow, some time reaction can not take place. To get reaction there is some driving force is needed.

The relative position of the two elements in the activity series provides the driving force for this kind of reaction. More active elements undergo readily reaction then less reactive like noble gas elements. It very necessary to elements very active to get react.

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Answer:

See the attached worksheet.

Explanation:

The attached file explains the the radioactive decay reactions shown in the figure.  There are a variety of nuclear decay routes:  alphs, beta, gamma, and electron capture are the more common.  Conservation of matter apples to these decay reactions.  The mass of the particles produced will equal the starting mass.  The loss of a proton from a nucleus changes the element:  Elements are defined by the number of protons in their nucleus, regardless of their heritage.

Answer:

To make sure all the sulphuric acid has been used up

Answer:

A mixture of salt and sugar can be separated by the process of filtration.

Answer:

A meso compound is a non-optically active member of a set of stereoisomers, at least two of which are optically active.

The diffusion rate of carbon dioxide out of the shell can be calculated using Fick's first law of diffusion, which states that the diffusion rate is proportional to the diffusion coefficient, the surface area, and the concentration difference.

First, we need to calculate the surface area of the shell:

The diameter of the shell is given as 4.5 cm, so the radius is half of that, which is 2.25 cm.

The surface area of a sphere is given by the formula A = 4πr^2.

Plugging in the radius, we get A = 4π(2.25 cm)^2 = 63.59 cm^2.

Next, we need to calculate the concentration difference:

The carbon dioxide concentration inside the shell is given as 2.0 atm, while the concentration outside the shell is essentially zero. The concentration difference is therefore 2.0 atm - 0 atm = 2.0 atm.

Now we can calculate the diffusion rate using the formula diffusion rate = diffusion coefficient * surface area * concentration difference. Plugging in the given values, we get diffusion rate = (2.5×10^(-12) m^2/s) * (63.59 cm^2) * (2.0 atm) = 3.18×10^(-9) cm^3·atm/s.

To convert this to molecules per second, we need to use Avogadro's number, which is 6.022×10^23 molecules/mol. Since carbon dioxide has a molar mass of approximately 44 g/mol, we can convert the diffusion rate to molecules per second by multiplying it by Avogadro's number and dividing by the molar mass of carbon dioxide. The molar mass of carbon dioxide is 44 g/mol = 44000 mg/mol.

diffusion rate (in molecules/s) = (3.18×10^(-9) cm^3·atm/s) * (6.022×10^23 molecules/mol) / (44000 mg/mol) = 4.34×10^14 molecules/s.

So, the diffusion rate of carbon dioxide out of the shell is 4.34×10^14 molecules/s.

For Part B, we can use the diffusion rate from Part A to calculate the time it takes for the carbon dioxide pressure to decrease to 1.0 atm.

The initial pressure is 2.0 atm and the final pressure is 1.0 atm.

Since the rate is constant, we can use the formula time = (final pressure - initial pressure) / diffusion rate.

Plugging in the values, we get time = (1.0 atm - 2.0 atm) / (4.34×10^14 molecules/s) = -2.3×10^(-15) s.

To convert this to hours, we divide by 3600 s/hour and take the absolute value to get time = |(-2.3×10^(-15) s) / (3600 s/hour)| = 6.4×10^(-19) hours.

So, it will take approximately 6.4×10^(-19) hours for the carbon dioxide pressure to decrease to 1.0 atm, assuming a constant diffusion rate.

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The statement, that describes the appropriate number of significant figures is "11.345."

Significant figures represent figures of value that have relevance in terms of measuring resolution. In positional notation, significant figures are digits in a number that are dependable and necessary to express the quantity of something.

The quantity of digits in a measurement, usually a measurement, that contribute to the value's accuracy.

Significant figures

= 15.225 - 3.88

= 11.345

It has 5 significant figures.

Hence the correct answer is 11.345.

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Answer:

Explanation:

got it right

The region can be a curve, surface, or solid. The term region refers to a specific area of space that can be expressed as a curve, surface, or solid.

A curve is a line that follows a path through space. A surface is a two-dimensional area that can be defined by an equation or a set of coordinates.

A solid is a three-dimensional object that has a length, width, height, firm, hard, or compact substance: solid ground. having relative firmness, coherence of particles, or persistence of form, as matter that is not liquid or gaseous

Therefore, the region can be any of the three, depending on how it is defined and expressed.

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Answer:

116 years

Explanation:

To solve this, we will use the half life equation;

A(t) = A_o(½)^(t/t_½)

Where;

A(t) is the amount of strontium left after t years;

A_o is the initial quantity of strontium that will undergo decay;

t_½ is the half-life of strontium

t is the time it will take to decay

We are given;

A(t) = 7.5 g

A_o = 120 g

From online values, half life of strontium-90 is 29 years. Thus, t_½ = 29

Thus;

7.5 = 120 × ½^(t/29)

Divide both sides by 120 to get;

7.5/120 = ½^(t/29)

0.0625 = ½^(t/29)

In 0.0625 = (t/29) In ½

-2.772589 = (t/29) × (-0.693147)

(t/29) = -2.772589/(-0.693147)

t/29 = 4

t = 29 × 4

t = 116 years

Answer:

Can you explain your question I don't understand

Answer:

2Mg+O=2MgO

Explanation:

32gram of reacting

Answer: band of stability

Explanation: my chem teacher told me so

If the stable isotopes are plotted according to the number of protons and neutrons it would form a pattern called the band of stability.

Isotopes are defined as substances having same number of protons but different number of neutrons.Number of protons is characteristic for determining position of elements in the periodic table.

Since,all isotopes have the same number of protons and hence have same position.They have similar chemical properties as they have same number of electrons.

They find applications in the field of nuclear medicine and oil and gas research . There are 2 types of isotopes : stable and unstable

Unstable isotopes are radioactive and are called as radioisotopes.Some of these isotopes are man -made and hence also called as artificial isotopes.Every element has an isotope which is either man-made or natural .

Many properties of isotopes depend on mass which is measured in atomic mass unit. The difference in actual mass and mass number is called mass defect.

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