Based on the discussion, try to identify the ineffective or faulty study habits that
you have and suggest ways on how you can change it that are doable on your part​

Answer:

145°C is allowed

Explanation:

step step by step explanation

To determine the grams of zinc chloride formed, we need to use the stoichiometry of the balanced  chemical equation:

Zn + 2HCl -> ZnCl2 + H2

From the balanced equation, we can see that 1 mole of zinc (Zn) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of zinc chloride (ZnCl2).

To calculate the grams of zinc chloride formed, we can follow these steps:

1. Convert the given mass of zinc (Zn) to moles using its molar mass.

2. Use the mole ratio from the balanced equation to determine the moles of zinc chloride (ZnCl2) formed.

3. Convert the moles of zinc chloride to grams using its molar mass.

Given:

Mass of zinc (Zn) = 130.74 grams

Step 1: Convert mass of zinc to moles.

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc (Zn) = Mass / Molar mass

Moles of zinc (Zn) = 130.74 g / 65.38 g/mol

Moles of zinc (Zn) = 2.000 moles

Step 2: Determine moles of zinc chloride formed.

According to the balanced equation, 1 mole of zinc (Zn) reacts to form 1 mole of zinc chloride (ZnCl2).

Moles of zinc chloride (ZnCl2) = Moles of zinc (Zn)

Moles of zinc chloride (ZnCl2) = 2.000 moles

Step 3: Convert moles of zinc chloride to grams.

Molar mass of zinc chloride (ZnCl2) = 136.29 g/mol

Mass of zinc chloride (ZnCl2) = Moles of zinc chloride * Molar mass

Mass of zinc chloride (ZnCl2) = 2.000 moles * 136.29 g/mol

Mass of zinc chloride (ZnCl2) = 272.58 grams

Therefore, 130.74 grams of zinc would react to form 272.58 grams of zinc chloride.

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Answer:

Molarity of potassium bromide in the solution is approximately 9.24 M.

Molarity = moles of solute / volume of solution in liters.

First,  the moles of potassium bromide in the solution - Mass of potassium bromide = 13.0 g.

Density of solution = 1.10 g/mL,

Density = mass/volume rearranged to get the volume of solution: volume of solution = mass / density = 13.0 g / 1.10 g/mL ≈ 11.82 mL

Now, let's convert this volume to liters: 11.82 mL = 11.82 × 10⁻³ L = 0.01182 L.

Moles of potassium bromide = mass of potassium bromide / molar mass of potassium bromide.

The molar mass of potassium bromide is 119 g/mol.

Therefore, Moles of potassium bromide = 13.0 g / 119 g/mol ≈ 0.1092 mol .

Molarity = moles of solute / volume of solution in liters

Molarity of potassium bromide in the solution is approximately 9.24 M.

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Answer:

Stirring brings fresh portions of the solvent in contact with the solute, therefore allows the solute to dissolve faster.

There are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

The number of moles of a substance can be calculated by multiplying the molarity by the volume.

No. of moles = Molarity × volume

According to this question, 3L of a KBr solution are contained in a 0.4M.

no. of moles = 3L × 0.4M = 1.2moles

Therefore, there are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

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Explanation:

leading zeros do not count as significant figures, Hence, this number correct to four significant figures should be written as in option E.

Answer:I’m not for sure

Explanation:

\(\\ \sf\longmapsto H_2+Br_2\longrightarrow HBr\)

\(\\ \sf\longmapsto H_2+Br_2\longrightarrow 2HBr\)

On reactant side:-

On products side

The balanced chemical equation for the synthesis of hydrogen bromide is \(\rm H_2\;+\;Br_2\;\rightarrow\;2\;HBr\).

The balanced chemical equation has been given as the reaction in which the number of atoms for each element on the product and the reactant side is equal.

The HBr has been formed with the reaction of the hydrogen and the bromine. The balanced chemical equation for the reaction has been:

\(\rm H_2\;+\;Br_2\;\rightarrow\;2\;HBr\)

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The flame test can be effectively used to identify a cation in a solution because when a cation is placed in a flame, it will emit a different color with

visibile light.

Ions are charged particles that form when atoms gain or lose electrons. When an atom gains electrons, it forms negatively charged ions called negative ions. On the other hand, positively charged ions, called cations, are formed when atoms lose electrons. These ions can be detected in solution using special tests. The flame test involves exposing a joint to a flame and identifying the joint by flame color. The color of the flame test is due to the fact that electrons in metal cations are excited and jump to higher energy levels.

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Radiocarbon dating is used to determine the age of an object.

Radiocarbon dating is a method used to estimate the age of organic materials based on the decay of radioactive carbon-14 isotopes. This technique is widely employed in archaeology, geology, and other scientific fields. When living organisms, such as plants or animals, are alive, they maintain a ratio of carbon-14 to stable carbon-12 isotopes.

However, once they die, the carbon-14 begins to decay at a known rate. By measuring the remaining carbon-14 and comparing it to the initial ratio, scientists can calculate the time that has passed since the organism's death. This method is particularly useful for dating objects that are up to around 50,000 years old. Palynology is the study of pollen grains, taphonomy focuses on the process of decay and fossilization, and paleontology deals with the study of fossils but not specifically dating methods.

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Fatty acids and glycerol are referred to as the monomers of lipids.

What does a lipid molecule look like?

Triacylglycerols, often known as triglycerides (TGs), are naturally occurring lipid molecules in our bodies that are composed of one glycerol molecule connected to three molecules of fatty acids (saturated/unsaturated or both) via ester bonds.

Where are the lipid monomers?

Monomer units theoretically do not exist in lipids. They are neither macromolecules nor polymers. Lipids will differ in their structural makeup. For instance, triglycerides are composed of one glycerol molecule and three tails of fatty acids.

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Answer:

V = 127.57 mL

Explanation:

In this case, we are having an acid base titration, and this, according to the overall reaction:

2H₃PO₄ + 3Ca(OH)₂ -----> Ca₃(PO₄)₂ + 6H₂O

This reaction was neutralized, so, it's a neutralization reaction, therefore, we can use the following expression for neutralization reactions:

n₁ = n₂  (1)

This is because, in the equivalence point, both moles of the reagents are the same. Now we need to do a relation between this and the actual moles that we have according to the overall reaction.

In this case, we have 2 moles of acid reacting with 3 moles of base, so, the equation (1) is re-written like this:

2n₁ = 3n₂   (2)

Knowing this, and that we have values of concentrations and volume, we can write the expression of moles in terms of molarity and volume:

n = M * V    replacing in (2):

2M₁V₁ = 3M₂V₂   From here, we can solve for V₂ which is the volume of the base:

V₂ = 2M₁V₁ / 3M₂   (3)

Now, all we have to do is replace the given values to obtain the volume of the base:

V₂ = 2 * 1.6 * 59.8 / 3 * 0.5

Answer:

\(V_{Ca(OH)_2}=0.287L=287mL\)

Explanation:

Hello,

In this case, given the reaction:

\(2 H_3PO_4 + 3 Ca(OH)_2 \rightarrow Ca_3(PO_4)_2 + 6 H_2O\)

We first compute the moles of phosphoric acid that are actually reacting given the volume (must be in litres) and the molarity:

\(n_{H_3PO_4 }=1.60\frac{mol}{L}*59.8mL*\frac{1L}{1000mL} =0.0957molH_3PO_4\)

Next, we compute the moles of calcium hydroxide that are reacting by using the 3:2 molar ratio with phosphoric acid:

\(n_{Ca(OH)_2}=0.0957molH_3PO_4*\frac{3molCa(OH)_2}{2molH_3PO_4} =0.144molCa(OH)_2\)

Finally, by knowing the 0.500 M of the calcium hydroxide solution we compute the required volume:

\(V_{Ca(OH)_2}=\frac{n_{Ca(OH)_2}}{M_{Ca(OH)_2}}=\frac{0.144mol}{0.500\frac{mol}{L} } \\ \\V_{Ca(OH)_2}=0.287L=287mL\)

Best regards.

The chemical formula for the solvation reaction in cold packs is given below as follows:

The dissolution of NH₄Cl in water is an endothermic process, and energy in the form of heat would be added to the product side of the reaction.

The chemical formula for the solvation reaction in cold packs involving solid ammonium chloride (NH₄Cl) dissolving in water (H₂O) is given below as follows:

NH₄Cl (s) + H₂O (l) ⟶ NH₄⁺ (aq) + Cl⁻ (aq)

In this reaction, solid ammonium chloride (NH₄Cl) reacts with water (H₂O) to form aqueous ammonium ions (NH₄⁺ ) and chloride ions (Cl-). The dissolution of NH₄Cl in water is an endothermic process, meaning that energy is absorbed in the form of heat from the surroundings usually the body.

Therefore, energy in the form of heat would be added to the product side of the reaction.

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Answer: D

Explanation: The Eukarya differ from the Archea and Bacteria in that their cells are eukaryotic, meaning they contain a membrane enclosed nucleus and other membrane enclosed organelles.

Eukarya is different from organisms classified as Archaea and Bacteria because Eukarya have membrane-bound nuclei. Therefore, option (D) is correct.

The type of cell of the organism can be classified into three domains. First is the bacteria which have no nucleus present in cells. Then Archaea have no nucleus in the cells but they have a different cell wall than bacteria. Then Eukarya have a nucleus in them.

The domains of Archaea and Bacteria are both composed entirely of small, single-celled organisms but they also have differences. All are composed of prokaryotic cells, which are nucleus-less cells.  T

All the cells in the Eukarya domain contain their genetic material or DNA within the nucleus. Four classes make up the Eukarya domain: Plantae, Fungi, Animalia, and Protista.

Therefore, the domain of the Eukarya is different from organisms classified as Archaea and Bacteria as Eukarya have membrane-bound nuclei.

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Answer:

The ecological relationship between termites and the wood-digesting protozoans that live in their gut is an example of  mutualism. Thank you for posting your question here at brainly. I hope the answer will help you.

Answer:

Fair Labor Standards Act

Explanation:

It is correct. I just took the test on Clever

Answer:

I would say it’s B

Explanation:

The pKa value of HCN is 9.21. The pKa value of \(H_3O^+\) is -1.74.From the given values, it is concluded that the equilibrium is shifted to the left side.

Identifying each compound as an acid or a base on each side of the equilibrium arrow there is a Bronsted-Lowry acid-base pair:

Given: \(HCN(aq) + H_2O(l)\) ⇌ \(H_3O^+(aq) + CN^{-}(aq)\)

In the given equation: \(H_2O(aq) + CN^{-}(aq)\) ⇌ \(OH^{-}(aq) + HCN(aq)\)

Therefore, On the left side, \(H_2O\) is the base, and \(CN^-\) is the acid. On the right side, \(H_3O^+\) is the acid, and \(CN^-\) is the base.

Identifying each compound as an acid or a base on each side of the equilibrium arrow there is a Lewis acid-base pair:

Given:\(HCN(aq) + H_2O(l)\) ⇌ \(H_3O^+(aq) + CN^-(aq)\)

On the left side, \(H_2O\) is a base, and HCN is an acid. On the right side, \(H_3O^+\) is an acid, and \(H_2O\) is a base.

Identifying the Lewis acid-base pair on the left side of the equilibrium: The Lewis acid-base pair on the left side of the equilibrium is \(H_2O\) and HCN. Using the pKa values, The pKa value of HCN is 9.21. The pKa value of \(H_3O^+\) is -1.74.From the given values, it is concluded that the equilibrium is shifted to the left side.

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The symbol "en" in this context is not related to the chemical reaction given in the question. "en" is actually an abbreviation for ethylenediamine, which is a type of ligand commonly used in coordination chemistry.

When water is added to anhydrous copper(II) sulfate, two observations are made:

The blue color of anhydrous copper(II) sulfate turns into a deep blue color as the water is added. This is because the anhydrous copper(II) sulfate is undergoing an exothermic reaction with the water to form hydrated copper(II) sulfate, which is blue in color.

As more water is added, the color becomes lighter and eventually the solution becomes clear. This indicates that all of the anhydrous copper(II) sulfate has reacted with water to form hydrated copper(II) sulfate.

Cobalt chloride can be used as a test for the presence of water because it is a hydrate that changes color when it loses its water of hydration. Anhydrous cobalt chloride is blue in color, while hydrated cobalt chloride is pink. When water is added to anhydrous cobalt chloride, it reacts with the water to form hydrated cobalt chloride, which is pink in color. This color change can be used to test for the presence of water in a sample.

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Answer:

1.VOLUME– The amount of space an object takes up. Basic Unit (SI Unit) for Solids – Cubic Meter, m3. LENGTH/DISTANCE – The measurement between two points.

2.one particle per cubic meter.

3.it means it is heavier

4.In a liquid the particles are still close together but a little further apart than in a solid.

5.In gases the particles are much further apart than in solids or liquids.

Explanation:

thats all i can type lol

Answer:

Mass and Volume

Explanation:

The formula for density is

\(\frac{Mass}{Volume}\)

Answer:

Yes

Explanation:

Why is glycerol more viscous than water?

The glycerine is more viscous than water because due to presence of hydrogen atoms , we all know that glycerine has more hydrogen bonding than water molecule , which makes an aggregation which means that glycerine is more viscous than water , in simple words glycerine can't flow as that of water molecule.

Answer:

a. how much So² can be made in moles?

= 0.2 moles

b. how much So² can be made in grams?

= 12.8 grams

c. what is the Excess reactant?

= O²

Explanation:

mass of ZnS= 19.6g

mass of O²= 33.6g

i. start by determining if the equation is balanced (it is)

ii. calculate the molar mass of each reagent

- molar mass of ZnS

= (65) + (32) = 97g/mol

- molar mass of O²

= (16 x 2) = 32g/mol

iii. determine the reactants' number of moles

- no of moles of ZnS = mass of ZnS / molar mass of ZnS

= 19.6 / 97

= 0.2 mol

- no of moles of O² = mass of O² / molar mass of O²

= 33.6 / 32

= 1.05 mol

iv. determine the reactant mole ratio

0.2 moles of ZnS reacted with 1.05 moles of O²

ratio = 1.05 / 0.2 which will approximately be 5

therefore, we can say that there are x5 as many molecules of O² than ZnS

v. determine the reactant ideal ratio

from the equation, 2 moles of ZnS reacted with 3 moles of 0². therefore, the ideal ratio is 2:3, with O² having the greater ratio once again

vi. determine the limiting and excess reactant

we can say from both the mole and ideal ratio that O² is the excess reactant and ZnS is the limiting reactant (answer to the third question)

next phase,

vii. determine the ratio of limiting reactant to the product

from the equation,

2 moles of ZnS produced 2 moles of So²

therefore, mole ratio = 2:2 which is also 1:1

viii. to determine how much So² can be made in moles

= no of moles of limiting reactant x mole ratio of reactant and product

= 0.2 moles of ZnS x 1/1

= 0.2 x 1

= 0.2 moles of So² (answer to the first question)

ix. to determine how much So² can be made in grams

= no of moles of So² produced x molar mass of So²

- molar mass of So²

= 32 + (16 x 2)

= 32 + 32

= 64g/mol

therefore, how much So² produced in grams

= 0.2 x 64

= 12.8g of So² (answer to the second question)

answerer's note: I recently started learning about theoretical yield in school and so this is the result of what I know so far. You're free to make confirmations from others who are more experienced :)

Answer:The gaseous material primarily extruded from a hydrothermal vent is primarily Hydrogen Sulfide (H2S).

Explanation:

Hydrothermal vents are underwater geothermal systems that occur on the ocean floor. They are formed when seawater seeps into the Earth's crust, gets heated by volcanic activity, and then rises back to the surface. These vents are often found near tectonic plate boundaries, such as mid-ocean ridges.

The primary gaseous material extruded from hydrothermal vents is hydrogen sulfide (H2S). Hydrogen sulfide is a colorless and highly toxic gas with a distinct rotten egg odor. It is produced as a result of chemical reactions that occur within the vent system.

At hydrothermal vents, seawater reacts with hot rocks and minerals in the Earth's crust. This process leads to the formation of various chemical compounds, including hydrogen sulfide. The hot, mineral-rich water released from the vents carries dissolved hydrogen sulfide gas along with other dissolved gases.

The release of hydrogen sulfide gas from hydrothermal vents has significant ecological implications. It serves as an energy source for specialized bacteria that thrive in these extreme conditions. These bacteria, known as chemosynthetic bacteria, use the hydrogen sulfide as an energy source to convert it into organic matter through a process called chemosynthesis. This chemosynthetic activity forms the basis of unique ecosystems around hydrothermal vents, supporting diverse communities of organisms.

While other gases may also be present in lower concentrations, hydrogen sulfide is the primary gaseous material extruded from hydrothermal vents due to its abundance and importance in supporting the unique ecosystems that exist in these extreme environments.

The gaseous material primarily extruded from a hydrothermal vent is hydrogen sulfide (H2S).

High amounts of hydrogen sulphide gas, as well as other gases including carbon dioxide (CO2) and methane (CH4), are known to be released from hydrothermal vents.

The habitats and microbial communities that are found surrounding hydrothermal vents are unique because of the chemical composition and conditions that these gases contribute to. So hydrogen sulphide is the right response.

A seafloor fissure known as a hydrothermal vent is where hot, mineral-rich fluids are released into the surrounding water. Typically at mid-ocean ridges or in regions where tectonic plates are sliding apart, these vents are found in volcanically active regions.

Magma that exists beneath the surface of the Earth heats the fluids that are emitted by hydrothermal vents. When seawater seeps into fissures and fractures, it heats up and reacts with the nearby rocks, leaching away different minerals and metals in the process.

Hot, mineral-rich fluids are released via the vent apertures when the superheated water hits the seafloor.

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If a particular substance can be separated into simpler substances by physical means, then that substance could be a mixture.

A mixture is a combination of two or more substances that are physically combined and can be separated by physical means. Physical methods such as filtration, distillation, chromatography, and evaporation can be used to separate the components of a mixture based on their physical properties such as size, boiling point, solubility, or density.

On the other hand, a pure substance, such as an element or a compound, cannot be separated into simpler substances by physical means alone. Elements are made up of only one type of atom, while compounds are made up of two or more elements chemically bonded together.

Separation of elements or compounds typically requires chemical reactions or processes. If a substance can be separated into simpler substances by physical means, it indicates that the substance is a mixture rather than a pure substance.

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The balanced redox reaction can be separated into two half-reactions: the oxidation half-reaction and the reduction half-reaction. Oxidation half-reaction: 2Cl^- → Cl2 + 2e^-, Reduction half-reaction: Cl2 + 2e^- → 2CuCl

In the oxidation half-reaction, chloride ions (Cl^-) are oxidized to form chlorine gas (Cl2) and release two electrons (2e^-). This represents the loss of electrons, which is characteristic of an oxidation process. In the reduction half-reaction, chlorine gas (Cl2) gains two electrons (2e^-) to form copper chloride (CuCl). This represents the gain of electrons, which is typical of a reduction process. When combined, the two half-reactions form the overall balanced redox reaction: 2Cl^- + Cl2 → 2CuCl.

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Since 1 L of water has 1,000 g, 0.1374 L or 137.4 g of water must be added to 8.27 g of acetic acid.

To make a 0.175 m aqueous acetic acid solution, you should add 8.27 g of acetic acid (HC2H3O2) to sufficient water to make the total solution mass equal to 8.445 g. This is because the molar mass of acetic acid is 60.05 g/mol, so 8.27 g can form a 0.137 m solution. To get this up to 0.175 m, a total mass of 8.445 g must be added, so 0.175 g of water must be added to the 8.27 g of acetic acid.

Making an aqueous acetic acid solution is simply a matter of combining the right amounts of acid and water. The amount of water to be added is easily calculated, since acetic acid has a known molar mass of 60.05 g/mol. The mass of the solution needs to be equal to the mass of the acetic acid plus the additional mass of water.

In this case, 8.27 g of acetic acid must be combined with 0.175 g of water, to produce a 0.175 m aqueous acetic acid solution.

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