The solution to the initial value problem y" - 2y' + 10y = 0, y(0) = 0, y'(0) = 6 is y(t) = 6\(e^t\) × sin(3t).
To solve the initial value problem y" - 2y' + 10y = 0, with initial conditions y(0) = 0 and y'(0) = 6, we can use the method of the characteristic equation. Let's solve it step by step:
Step 1: Characteristic equation
We assume the solution has the form y = \(e^{(rt)\), where r is a constant. Substituting this into the differential equation, we get:
r² - 2r + 10 = 0
Step 2: Solve the characteristic equation
Solving the quadratic equation, we find the roots:
r = (2 ± sqrt(2² - 4(1)(10))) / 2
r = (2 ± sqrt(-36)) / 2
r = 1 ± 3i
Step 3: General solution
Since the roots are complex, the general solution of the differential equation can be written as:
y(t) = \(e^{(1t)\) (A × cos(3t) + B × sin(3t))
Step 4: Apply initial conditions
Using the initial condition y(0) = 0, we substitute t = 0 into the general solution:
0 = A × cos(0) + B × sin(0)
0 = A
Using the initial condition y'(0) = 6, we substitute t = 0 into the derivative of the general solution:
6 = (A × 1 × cos(0) - 3B × sin(0))
6 = A
Step 5: Final solution
Now we have A = 0 and B = 6. Substituting these values into the general solution, we obtain the particular solution:
y(t) = \(e^t\) × (0 × cos(3t) + 6 × sin(3t))
y(t) = 6\(e^t\) × sin(3t)
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plz answer right i need it for a quiz
Answer:
a
Step-by-step explanation:
that is the answer
Events M and N have probabilities such that P(M) = 0.4, P(N) = 0.28, P(M ∪ N) = 0.56, and P(M ∩ N) = 0.12. Are events M and event N independent?
A.
Yes, because P(M) + P(N) = P(M ∪ N).
B.
No, because P(M) ∙ P(N) ≠ P(M ∩ N).
C.
Yes, because P(M) ∙ P(N) ≠ P(M ∪ N).
D.
No, because P(M) - P(N) = P(M ∩ N).
i need this asap
Answer: The answer is B.
Step-by-step explanation:
This is using the independent probability
Are events M and event N independent. No, because P(M)·P(N) ≠ P(M ∩ N).
What do you mean by independent events?
A and B are said to be independent events if the probability of an event A occurring is unaffected by the occurrence of another event B whereas dependent events influence the probability of other events Independent events can have common outcomes.
If two events A and B are independent of each other, then A and B have equal probability of occurring as
P(A∩B) = P(A) · P(B)
Event M and N have probabilities such that P(M) = 0.4, P(N) = 0.28 , P(M∪N) = 0.56 and P(M∩N) = 0.12
P(M)·P(N) = 0.4 × 0.28 = 0.112
and P(M∩N) = 0.12 (Given)
So, P(M∩N) ≠ P(M)·P(N)
This shows that both the events are not independent events.
Therefore, Event M and N are not independent event.
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One palm tree is 11.4 inches another is 11.36 and another is 11.309 and the last 11.44 which is the tallest
Answer:
11.44
Step-by-step explanation:
tallest to smallest:
11.44, 11.4, 11.36, 11.309
Which of the following is not a fundamental identity? A. cot θ = cos θ/sinθ. B. sec θ = 1/cosθ. C. sec^2 + 1 = tan^2θ. D. 1 + cot^2θ = csc^2θ.
A fundamental identity is an equation that relates the values of the trigonometric functions for a given angle. The equation cot θ = cos θ/sinθ is an example of a fundamental identity.
This identity states that the cotangent of an angle is equal to the cosine of the angle divided by the sine of the angle. The equation sec θ = 1/cosθ is another example of a fundamental identity. This identity states that the secant of an angle is equal to the reciprocal of the cosine of the angle. The equation sec^2 + 1 = tan^2θ is also a fundamental identity. This identity states that the square of the secant of an angle plus one is equal to the square of the tangent of the angle. The equation 1 + cot^2θ = csc^2θ is not a fundamental identity. This equation states that one plus the square of the cotangent of an angle is equal to the square of the cosecant of the angle. This equation is not a fundamental identity because it does not relate the values of the trigonometric functions for a given angle.
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Which box plot represents a set of data that has the greatest mean absolute deviation?
A box-and-whisker plot. The whiskers have a range of 9 units, and the box has a range of 6 units.
A box-and-whisker plot. The whiskers have a range of 10 units, and the box has a range of 2 units.
A box-and-whisker plot. The whiskers have a range of 6 units, and the box has a range of 2 units.
Answer:
d
Step-by-step explanation: i took the test and pasted
Answer
Graph 2
Step-by-step explanation:
What are the 5 rules of congruence?.
Two shapes of the same size and shape are congruent. There are five conditions or rules for two triangles to be congruent. They are SSS, SAS, ASA, AAS, and RHS joint properties.
Triangle Congruence:
The congruence of two or more triangles depends on the measurements of their sides and angles. The three sides of a triangle determine its size, and its three angles determine its shape.
Two triangles are considered congruent if their pairs of corresponding sides and corresponding angles are equal.
SSS (side-side-side) :
According to this criterion, two triangles are congruent if his three sides of one triangle are equal to the corresponding sides of the other triangle.
ASA ( Angle-Side-Angle ) :
According to the ASA criterion, two triangles are congruent if any two angles and the inner side of one triangle between them are equal to the corresponding angles and inner sides of the other triangle.
SAS (Side Angle Side)
According to this criterion, two triangles are congruent if two sides and included angles of one triangle are equal to the corresponding sides and included angles of the other corresponding triangle.
AAS ( Angle - Angle Side) :
According to the AAS standard, two triangles are congruent if any two angles and the excluded side of one triangle are equal to the corresponding angles and the excluded side of the other triangle
RHS (Right Angle Two-sided)
According to this criterion, two triangles are congruent if the hypotenuse and side of one right triangle are equal to the hypotenuse and corresponding side of another right triangle.
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3 If the first two statements are true, is the third statement true? 1. All dogs like walks. 2. Bandit doesn't like walks. 3. Bandit is not a dog. Yes, it's true B No, it's false C Uncertain, there's not enough information OK✔
Answer: Bandit is not a dog
3rd satment is true
Step-by-step explanation
Mrs. Rivera ran 5 1/4 miles and Ms. Carter ran 4 3/4 miles. How many miles did they run in all?
Answer:
10 miles
Step-by-step explanation:
5 1/4+ 4 3/4 = 10
Answer:
10 miles
Step-by-step explanation:
Can y’all help me please I will give Brainlist
Answer:
It would be a five
Step-by-step explanation:
What is the value of n? 9.6x10^9=(2x10^5)(4.8x10^n)
\(9.6\times 10^9~~ = ~~(2\times 10^5)(4.8\times 10^n)\implies \cfrac{9.6\times 10^9}{2\times 10^5}~~ = ~~4.8\times 10^n \\\\\\ \cfrac{9.6}{2}\times \cfrac{10^9}{10^5}~~ = ~~4.8\times 10^n\implies 4.8\times 10^{9-5}~~ = ~~4.8\times 10^n \\\\\\ 4.8\times 10^4~~ = ~~4.8\times 10^n\implies \cfrac{4.8\times 10^4}{4.8}=10^n\implies \cfrac{4.8}{4.8}\times 10^4=10^n \\\\\\ 1\times 10^4=10^n\implies 10^4=10^n\implies 4 = n\)
Jim has $84,410 in a savings account that earns 15% interest per year. How much will he have in 4 years?
Answer:
50,646
Step-by-step explanation:
Jim would have saved 50,646 in 4 years
1 Year= 12.6615
12.6615 x 4=50,646
Jim will have $5,149,010 in 4 years.
What is Simple Interest?Simple interest is a method for figuring out how much interest was paid on a sum of money during a specific time period at a specific rate. Simple interest has a constant principle amount. Simple interest is a clear-cut and simple method for computing financial interest.
We have,
P = $84,410.
R= 15%
T = 4 years
Using Simple Interest
SI = (P x R x T) / 100
SI = (84410 x 15 x 4)/100
SI = 5,064,000
So, the amount is
= 84,410 + 5,064,000
= 5,149,010
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simple way to differentiate between speed and average speed.
Answer:
speed
1)the distance travelled by a body per unit time is known as speed.
2) speed is speed, or something how fast is going,
3) while velocity is speed how fast something is going in a specific direction.
average speed
1) average speed is the speed added up and divided by number of speed .
2)the average of all the instantaneous speed in a give time interval.
3) the average speed as the duration of the time interval approaches zero.
Mr. Jones' tally showed that 0.6 of
the students brought in scissors.
What fraction of the students did
not bring in scissors?
Answer:
Mr. Jones' tally showed that 0.6 of the students brought in scissors, so the remaining fraction of students would be 0.4 or 40%, who did not bring in scissors.
Step-by-step explanation:
simple
Answer:
40% of the students did not bring in scissors
Step-by-step explanation:
Since % means out of 1.
0.6 would equal 60%
1.0 - 0.6 = 0.4
Other forms of 0.4 would include:
0.40
40%
2/5s
4/10s
40/100s
If the simple interest on a $5,000 for 8 years is $2,000, then what is the interest rate?
Given data:
The principal is
\(P=\text{ \$5,000}\)The time is
\(t=8\)The interest is
\(=\text{ \$2,000}\)Concept:
The formula to calculate interest rate (R) is given below as
\(\begin{gathered} I=\frac{P\times R\times T}{100} \\ 100I=P\times R\times T \\ divide\text{ both sides by PT} \\ R=\frac{100I}{PT} \end{gathered}\)By substituting the values in the formula above, we will have
\(\begin{gathered} R=\frac{100I}{PT} \\ R=\frac{100\times2000}{5000\times8} \\ R=\frac{200000}{40000} \\ R=5 \end{gathered}\)Hence,
The final answer is 5%
Which pair of expressions is equivalent using the Associative Property of Multiplication?
A6(4a ⋅ 2) = 24a ⋅ 12
B 6(4a ⋅ 2) = (4a ⋅ 2) ⋅ 6
C6(4a ⋅ 2) = 6 ⋅ 4a ⋅ 2
D6(4a ⋅ 2) = (6 ⋅ 4a) ⋅ 2
Answer:
Step-by-step explanation:
In the associative property of multiplication, the product of the multiplication of 3 or more numbers is the same irrespective of how they are grouped. This means that irrespective of the bracket or which number comes first, the product will always be the same.
From the given scenarios, the pair of expressions that are equivalent using the Associative Property of Multiplication are
B 6(4a ⋅ 2) = (4a ⋅ 2) ⋅ 6
C 6(4a ⋅ 2) = 6 ⋅ 4a ⋅ 2
D6(4a ⋅ 2) = (6 ⋅ 4a) ⋅ 2
The results are the same irrespective of the arrangement of the numbers.
Find two irrational numbers between 5 9 and 16 5
Answer:
Step-by-step explanation:
I am assumimg you mean 5/9 and 16/5.
2 irrational numbers between these values are e and π.
Two irrational numbers between 5 / 9 and 16 / 5 are,
⇒ 0.56674549....
⇒ 0.588454755....
What is Rational number?A number which can be written in the form of fraction p / q , where q is non zero, are called Rational numbers.
Given that;
Two rational numbers are,
⇒ 5 / 9 and 16 / 5
Now, We get;
⇒ 5 / 9 = 0.5555
⇒ 16 / 5 = 3.2
Hence, Two irrational numbers between 5 / 9 and 16 / 5 are,
⇒ 0.56674549....
⇒ 0.588454755....
Thus, Two irrational numbers between 5 / 9 and 16 / 5 are,
⇒ 0.56674549....
⇒ 0.588454755....
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the use of a ""thumbs-up"" gesture to symbolize the statement ""good luck""
The use of a "thumbs-up" gesture to symbolize the statement "good luck" is a common practice in many cultures. This gesture is typically used to express approval or agreement, but it can also be used to convey positive wishes, such as wishing someone good luck before an exam or a job interview.
It is believed that this gesture originated in ancient Rome, where it was used as a sign of approval in the gladiatorial arena. Today, the thumbs-up gesture has become a universal symbol of positivity and encouragement. So, if you want to wish someone good luck, a thumbs-up gesture is a great way to do it!
The use of a "thumbs-up" gesture to symbolize the statement "good luck" involves the following steps:
1. Extend your arm: To perform the thumbs-up gesture, first extend your arm in the direction of the person you want to wish good luck.
2. Make a fist: Close your fingers into a fist, with your thumb pointing upwards.
3. Show your thumb: Ensure that the thumb is clearly visible and pointing upwards. This represents the "thumbs-up" gesture.
4. Make eye contact: Look at the person you're wishing good luck to, so they know the gesture is directed at them.
By performing the thumbs-up gesture, you're using a universally recognized symbol to convey your positive sentiment and wish someone good luck in their endeavors.
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the measure of an angle is 82°. What is the measure of its supplementary angle?
Answer:
98
Step-by-step explanation:
180 means supplementary so we subtract that by 82 which gives us 98
Answer:
Below
Step-by-step explanation:
The two supplementary angles sum to 180 °
180 - 82 = other angle = 98°
Solve -6x - 7 = 17.
X=_
Answer:
x=-4
Step-by-step explanation:
-6x=17+7
-6x=24
x=-4
Answer:
x = -4
Step-by-step explanation:
Add 7 to each side of the equation (left and right of the equal sign) which should get you to -6x = 24. Then multipy both sides by -1 to make the -6x positive and turn the 24 negative. That should leave you with 6x = -24, then divide by 6 on each side and your answer should be x = -4
(2.9x10^3)-(6.4x10^-1)
The optimal amount of x1, x2, P1, P2 and income are given by the
following:
x1= 21/ 7p1 x2= 51 / 7p2
The original prices are: P1=10 P2=5 The original income is: I
=4189 The new price of P1 is the foll
The total change in the consumed quantity of x₁ as per given price and income is equal to 213.
x₁ = (21/7)P₁
x₂ = (51/7)P₂
P₁ = 10
P₂ = 5
P₁' = 81
To calculate the total change in the quantity consumed of x₁ when the price of P₁ changes from P₁ to P₁',
The difference between the quantities consumed at the original price and the new price.
Let's calculate the quantity consumed at the original price,
x₁ orig
= (21/7)P₁
= (21/7) × 10
= 30
x₂ orig
= (51/7)P₂
= (51/7) × 5
= 36.4286 (approximated to 4 decimal places)
Now, let's calculate the quantity consumed at the new price,
x₁ new
= (21/7)P1'
= (21/7) × 81
= 243
x₂ new
= (51/7)P2
= (51/7) × 5
= 36.4286
The total change in the quantity consumed of x₁ can be calculated as the difference between the new quantity and the original quantity,
Change in x₁
= x₁ new - x₁ original
= 243 - 30
= 213
Therefore, the total change in the quantity consumed of x₁ is 213.
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The above question is incomplete, the complete question is:
The optimal amount of x1, x2, P1, P2 and income are given by the following:
x1= 21/ 7p1 x2= 51 / 7p2
The original prices are: P1=10 P2=5 The original income is: I =4189 The new price of P1 is the following: P1'=81 Assume that the price of x1 has changed from P1 to P1'. What is the total change in the quantity consumed of x1?
Please answer step by step
a computer software retailer used a markup rate of 40% for a computer game that cost the retailer $25
Answer:
35$
Step-by-step explanation:
25 x 1.40 = 35
9+3.5g=11−0.5g i need this anwser plz help
Answer:
g = 1/2
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesStep-by-step explanation:
Step 1: Define equation
9 + 3.5g = 11 - 0.5g
Step 2: Solve for g
Add 0.5g on both sides: 9 + 4g = 11Subtract 9 on both sides: 4g = 2Divide 4 on both sides: g = 1/2Step 3: Check
Plug in g into the original equation to verify it's a solution.
Substitute in g: 9 + 3.5(1/2) = 11 - 0.5(1/2)Multiply: 9 + 1.75 = 11 - 0.25Add/Subtract: 10.75 = 10.75Here we see that 10.75 does indeed equal 10.75.
∴ g = 1/2 is a solution of the equation.
Answer: g= 0.5
Step-by-step explanation:
Add
3.5g and 0.5g. to get
9+4g=11
then subtract 9 from the 11 and you should get 4g=2.
then divide 4 from 2 and you should get the answer of 2/4.
simplify it and you should get the answer g=0.5
adjustment data: a. office supplies used during the month, $1,800. b. depreciation for the month, $200. c. one month insurance has expired. d. accrued interest expense, $75.
Adjusted data:
a. Decrease Office Supplies, Increase Office Supplies Expense by $1,800.
b. Decrease Depreciation Expense, Increase Accumulated Depreciation by $200.
c. Decrease Prepaid Insurance, Increase Insurance Expenses by one month's value.
d. Increase Interest Expense, Increase Accrued Interest Payable by $75.
We have,
Based on the adjusted data provided:
a. The office supplies used during the month would result in a decrease in assets and an increase in expenses.
This adjustment would decrease the Office Supplies account and increase the Office Supplies Expense account by $1,800.
b. Depreciation for the month would result in a decrease in assets and an increase in expenses.
This adjustment would decrease the Depreciation Expense account and increase the Accumulated Depreciation account by $200.
c. The expiration of one month of insurance would result in a decrease in assets and an increase in expenses.
This adjustment would decrease the Prepaid Insurance account and increase the Insurance Expense account by the value of one month's insurance.
d. Accrued interest expense would result in an increase in expenses and a corresponding increase in liabilities.
This adjustment would increase the Interest Expense account and also increase the Accrued Interest Payable liability account by $75.
Thus,
Adjusted data:
a. Decrease Office Supplies, Increase Office Supplies Expense by $1,800.
b. Decrease Depreciation Expense, Increase Accumulated Depreciation by $200.
c. Decrease Prepaid Insurance, Increase Insurance Expenses by one month's value.
d. Increase Interest Expense, Increase Accrued Interest Payable by $75.
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what is the correct answer answer
Line segment BD is 12 units
Using the pythagorean theorem a^2 + b^2 = c^2
A manager of a deli gathers data about the number of sandwiches sold based on the number of customers who visited the deli over several days. The
table shows the data the manager collects, which can be approximated by a linear function.
Customers
104
70
111
74
170
114
199
133
163
109
131
90
Sandwiches
If, on one day, 178 customers visit the deli, about how many sandwiches should the deli manager anticipate selling?
To estimate the number of sandwiches the deli manager should anticipate selling when 178 customers visit the deli, we can analyze the given data and approximate it using a linear function.
By observing the table, we notice that the number of sandwiches sold varies with the number of customers. This indicates a relationship between the two variables.
To estimate the number of sandwiches, we can fit a line to the data points and use the linear function to make predictions. Using a statistical software or a spreadsheet, we can perform linear regression analysis to find the equation of the best-fit line. However, since we are limited to text-based interaction, I will provide a general approach.
Let's assume the number of customers is the independent variable (x) and the number of sandwiches is the dependent variable (y). Using the given data points, we can calculate the equation of the line.
After calculating the linear equation, we can substitute the value of 178 for the number of customers (x) into the equation to estimate the number of sandwiches (y).
Please provide the data points for the number of sandwiches sold corresponding to each number of customers so that I can perform the linear regression analysis and provide a more accurate estimate for you.
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find the solution to the following system using subsitution or elimination y=2x-1 y=5x-7
assume that the weight loss for the first month of a diet program varies between 6 and 12 pounds
The probability of the weight loss falling between 8 pounds and 11 pounds is 1/2
Variation of weight = Between 6 to 12.
It is required to ascertain the percentage of the overall range that corresponds to that interval in order to calculate the chance that the weight reduction will fall between 8 pounds and 11 pounds.
Calculating the total range of weight -
Range = Higher weight - Lower weight
= 12 - 6
= 6
Similarly, calculating the total range of weight for 8 pounds and 11 pounds
Range = Higher weight - Lower weight
= 11 - 8
Calculating the probability -
Probability = Range of interest / Total range
= 3 / 6
= 1/2.
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Complete Question:
Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds, and is spread evenly over the range of possibilities, so that there is a uniform distribution. Find the probability of the given range of pounds lost between 8 pounds and 11 pounds
a. 1/2
b. 1/4
c. 2/3
d. 1/3
How do you find these
What is the measure of segment DC?
What is the measure of segment C'B'?
What is the measure of segment AD?
What is the measure of segment A'B'?
What is the measure of angle C?
What is the measure of angle A'?
What is the measure of angle D'?
What is the measure of angle B'?
What is the measure of angle A?
Measure of segment DC is 24
Measure of segment C'B' is 16
Measure of segment AD is 10
Measure of segment A'B' is 7
Measure of angle C is 49 degrees
Measure of angle A' is 111 degrees
Measure of angle D' is 65 degrees
Measure of angle B' is 135 degrees
Measure of angle A is 111 degrees
How to determine the measuresTo determine the measures, we need to know the properties of parallelograms, we have;
Opposite angles are equal.Opposite sides are equal and parallel.Diagonals bisect each other.Sum of any two adjacent angles is 180°We have that the two parallelograms are equal
Now, trace the angles from one to other
Angle A = 360 - (49 + 135 + 65)
add the values, we have;
Angle A = 360 -249
Angle A =111 degrees
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In a queueing system, customers arrive once every 6 seconds (standard deviation = 8) and services take 4 seconds (standard deviation = 5.9). What is the average number of customers in the queue? Note: Do not round intermediate calculations. Round your answer to 3 decimal places?
In a queueing system with customer arrivals every 6 seconds and service times of 4 seconds, the task is to calculate the average number of customers in the queue
To calculate the average number of customers in the queue, we can use Little's Law, which states that the average number of customers in a stable queueing system is equal to the average arrival rate multiplied by the average time spent in the system.
First, we need to calculate the average arrival rate. Since customers arrive once every 6 seconds, the arrival rate is 1 customer per 6 seconds or 1/6 customers per second.
The total service time is 4 seconds, and the standard deviation is 5.9. Therefore, the average service time is 4 seconds.
Using Little's Law, we multiply the average arrival rate (1/6 customers per second) by the average service time (4 seconds) to obtain the average number of customers in the queue.
Average number of customers in the queue = (1/6) * 4 = 2/3 ≈ 0.667
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