1) By using the definition, show that the following sets are disconnected. 2) Find all the connected) components of the following sets. (a) Z (b) [0, 1] U [2,3] (C) R \ {0} (d) R\Q

Answers

Answer 1

The sets Z, [0,1] U [2,3], R{0}, and R\Q have been analyzed for connectedness. The connected components of each set have been identified, demonstrating their disconnected nature.

Given, we need to determine whether the sets are connected or disconnected using the definition of connected and disconnected sets. Also, we need to find all the connected components of each given set.

(a) \($Z$\) (the set of integers):

We can show that \($Z$\)is disconnected by splitting it into two open sets. Let \(S1 = {...,-2, -1, 0, 1, 2, ...}$ and $S2 = {..., -3, -2, -1, 0}$\). It can be seen that $S1$ and $S2$ are disjoint and open in \($Z$\). Hence, $Z$ is disconnected. Connected components of \($Z$\) is \($Z$\) itself.

(b) \($[0,1]\cup[2,3]$\) (the union of two disjoint intervals):

To show that the given set is connected, consider any two open sets\(, $U $ and $ V$, such $ that $[0,1]\cup[2,3]\subseteq U\cup V$\). WLOG, let \($0\in U$\).

Then \([0,1]\subseteq U$. But $U$\) is open, so there must exist an open interval of the form \($(a,b)$\) which contains \($0$\) and is a subset of \($U$\). Clearly, \($a < 0$\). Now, \($(a, b)\cup [2, 3]\subseteq U\cup V$\). Since \($(a, b)\cup [2, 3]$\) is connected, it follows that either \((a, b)\cup [2, 3]\subseteq U$ or $(a, b)\cup [2, 3]\subseteq V$\).

Now, if \((a, b)\cup [2, 3]\subseteq U$, then $2\in U$\). Again, \($U$\) is open, so there exists an open interval of the form \((c,d)$ such that $2\in (c, d)$ and $(c, d)\subseteq U$\).

It can be easily shown that \($(c, d)\cup [0, 1]\subseteq U$\). Hence, \($U = [0, 1] \cup [2, 3]$\) which is connected. Similarly, it can be shown that \($V$\) is connected if it contains both \([0, 1]$ and $[2, 3]$. Thus, $[0,1]\cup[2,3]$\) is connected. Connected components of \([0,1]\cup[2,3]$ are $[0,1]$ and $[2,3]$\).

(c) \($R{0}$\) (the set of non-zero real numbers):

Let \(A = {x\in R | x < 0}$ and $B = {x\in R | x > 0}$\). Clearly, \($A$\) and \($B$\) are open and disjoint in \($R{0}$\) such that $A \cup B = R{0}$. Hence, \($R{0}$\) is disconnected. Connected components of \(R{0}$ are $A$ and $B$\).

(d) \($R\Q$\) (the set of irrational numbers):

Let \(A = {x\in R\Q | x < a}$ and $B = {x\in R\Q | x > a}$\). Clearly, \($A$\) and \($B$\) are open and disjoint in \($R\Q$\) such that \($A \cup B = R\Q$\). Hence, \($R\Q$\) is disconnected. Connected components of \(R\Q$ is $R\Q$\) itself.

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Related Questions

what is the force of an object that has a mass of 20 kg and is accelerating at a rate of 15 m/s/s

Answers

Formula for force: F = m • a (force equals mass times acceleration)

Acceleration: 15 m/s/s
Mass: 20kg


20kg • 15 m/s/s = 300 Newtons

how can we use variations in luminosity to set limits on the sizes of their emitting regions? quasars

Answers

The variation in luminosity of quasars can be used to set limits on the sizes of their emitting regions by using the time delay between the variations in different wavelengths.

The variation in luminosity of a quasar is caused by changes in the amount of material that is accreting onto the supermassive black hole at the center of the quasar. This material emits radiation as it falls into the black hole, and the luminosity of the quasar is proportional to the rate at which material is falling in.

The emitting region of the quasar is thought to be the region around the black hole where this material is falling in and emitting radiation.

Since the emitting region is thought to be relatively small, on the order of a few light-days to a few light-weeks in size, the variations in luminosity should occur on very short timescales. By measuring the time delay between the variations in different wavelengths of light, astronomers can determine the size of the emitting region.

If the time delay between the variations is longer than expected for a particular size of emitting region, then that size can be ruled out. By studying the variations in luminosity over time, astronomers can build up a picture of the size and structure of the emitting region of a quasar.

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The ratio of useful energy output to total energy input is called energy

efficacy
transformation
efficiency
loss

Answers

Answer:

efficiency

Explanation:

The ratio of useful energy output to total energy input is called energy efficiency.

Which object is in the sample of chemical change?

* Digesting a salad

* Mixing a salad dressing

* Dicing an onion

* Preparing a salad

Can someone answer this quickly, sorry if it’s rushed. ~Ty

Answers

Answer:

Digesting a salad

Explanation:

All the other ones are physical changes because you're changing its form but not its chemical identity and not changing the substance. Digesting a salad is a chemical change because you're both changing its form AND its chemical identity

Digesting a salad is the answer, because when you mix a salad dressing the chemicals still remain , when you dice a onion it’s a physical change , when you prepare a salad everything chemically is the same but with digesting it chemically it changes while the enzymes break down your food please mark me brainliest

Name two ways to decrease the electric force between two charged objects.

Answers

Answer:

Inverse relationships are common in nature. In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

Explanation:

Two ways to decrease the electric force between two charged objects:

by lessen charge of the test objects.by increasing distance between test change and source charge.What is coulomb force?

As a result of their electric charge, particles or objects are attracted to or repelled by the Coulomb force, also known as electrostatic force or Coulomb interaction. Charles-Augustin de Coulomb, a French scientist who published the findings of an experimental inquiry into the proper quantitative description of this force in 1785, gave the electric force its name. The electric force is one of the fundamental physical forces.

Positive or negative electric charges that are similar to one another repel one another in a straight line between their centers. Positive and negative charges that are opposite each other are drawn together along a straight line connecting their centers.

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Two similar spheres A and B, have charges of +2 * 10 ^ -6 * C and + 1 * 10 ^ -6* C The of the electrostatic force on A due to B is 2.4 Newtons. What is the magnitude of electrostatic force on B due to A. Why ?

Show work please and explain.

Answers

The magnitude of the electrostatic force on sphere B due to sphere A is also 2.4 N, because the forces are equal in magnitude but opposite in direction as they form an action-reaction pair.

How to find the magnitude of electrostatic force on B due to A?

First by Coulomb's Law, the electrostatic force F between two point charges Q1 and Q2, separated by a distance r, is given by

F = k * (Q1 * Q2) / r^2

Where k is the Coulomb constant, which has a value of 9 × 10^9 N·m^2/C^2.

In this case, we have two spheres A and B, with charges +2 * 10^-6 C and +1 * 10^-6 C, respectively. The electrostatic force on A due to B is given as 2.4 N.

To find the electrostatic force on B due to A, we can use Coulomb's Law and the fact that the force between the two spheres is an action-reaction pair, meaning that the forces on A and B are equal in magnitude but opposite in direction. Therefore, the magnitude of the electrostatic force on B due to A is also 2.4 N.

We can see this by rearranging Coulomb's Law as:

F = k * (Q1 * Q2) / r^2

=> Q2 = (F * r^2) / (k * Q1)

where

Q2 is the charge on sphere B, R is the distance between the two spheres, and we have used the known force and charge on sphere A.

Substituting the values given, we get:

Q2 = (2.4 N * (1 m)^2) / (9 × 10^9 N·m^2/C^2 * 2 × 10^-6 C) = 0.133 C

Therefore, the magnitude of the electrostatic force on sphere B due to sphere A is also 2.4 N, because the forces are equal in magnitude but opposite in direction as they form an action-reaction pair.

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Two planets are orbiting a star in a distant galaxy the first has a semimajor axis of 150 x 10^6 km an eccentricity of 0. 20 and a period of 1. 0 earth years

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For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km,  the period of the second plane  is mathematically given as

T=2.2earth year

What is the period of the second planet?

Generally, the equation for the time period  is mathematically given as

\(T^{2} \appox a^{3}\)

Therefore, for planet one

\(1^2\approx (150 x 10^6)^3\)

In conclusion, For planet 2

T^2=(250/150)^3

T=√4.632

T=2.2earth year

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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.

What is the time period of the revolution?

The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.

The equation of the time period is found as;

\(\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year\)

Hence the time period of the planet will be 2.2 earth years.

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An unnamed professor is walking to class when an office chair (travelling in the same direction) collides with them. The professor fails into the chair and remains in the chair after collision. The professor, with a mass of 113kg, is travelling at 1.56 m/s. The chair has a velocity of 6.5 m/s, and a mass of 10kg. After the collision, and ignoring any effects of professor falling, what would be the speed of the chair professor system

Answers

Answer: 1.96 m/s

Explanation:

Given

Mass of Professor \(m_1=113\ kg\)

Velocity of professor \(u_1=1.56\ m/s\)

mass of chair \(m_2=10\ kg\)

velocity of chair \(u_2=6.5\ m/s\)

Suppose  after the collision, v is the common velocity

Conserving momentum

\(\Rightarrow m_1u_1+m_2u_2=(m_1+m_2)v\\\\\Rightarrow v=\dfrac{113\times 1.56+10\times 6.5}{113+10}=\dfrac{241.28}{123}\\\\\Rightarrow v=1.96\ m/s\)

8cm^3 of hydrogen gas and 20cm^3 of oxygen gas was exploded. calculate the volume of unreached oxygen.

Answers

The volume of unreached oxygen after the explosion is 16 cm³.

To calculate the volume of unreached oxygen after the explosion, we need to determine the stoichiometry of the reaction between hydrogen and oxygen and then use the given volumes of hydrogen and oxygen to find the limiting reactant.

The balanced chemical equation for the reaction between hydrogen and oxygen to form water is:

2H₂ + O₂ → 2H₂O

From the equation, we can see that the stoichiometric ratio between hydrogen and oxygen is 2:1. This means that for every 2 volumes of hydrogen, we need 1 volume of oxygen to react completely.

Volume of hydrogen gas = 8 cm³

Volume of oxygen gas = 20 cm³

To determine the limiting reactant, we compare the volumes of hydrogen and oxygen using their stoichiometric ratio.

Based on the stoichiometric ratio, we can calculate the required volume of oxygen for complete reaction by dividing the volume of hydrogen by 2:

Required volume of oxygen = (8 cm³) / 2 = 4 cm³

Since the given volume of oxygen (20 cm³) is greater than the required volume of oxygen (4 cm³), we can conclude that oxygen is in excess.

To calculate the volume of unreached oxygen, we subtract the required volume of oxygen from the given volume of oxygen:

Volume of unreached oxygen = Volume of oxygen - Required volume of oxygen

Volume of unreached oxygen = 20 cm³ - 4 cm³

Volume of unreached oxygen = 16 cm³

Therefore, the volume of unreached oxygen after the explosion is 16 cm³.

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A laser pulse of duration 25 ms has a total energy of 1.4 J. The wavelength of this radiation is
567 nm. How many photons are emitted in one pulse? Let 1 eV = 1.60 x 10-19 J, the mass of
an electron m=9.11 10-31
kg, the speed of light c= 3.00 x 108 m/s, and Planck's constant h
= 4.136 10-15 eV .s.

Answers

Answer:

n = 4 x 10¹⁸ photons

Explanation:

First, we will calculate the energy of one photon in the radiation:

\(E = \frac{hc}{\lambda}\\\\\)

where,

E = Energy of one photon = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m

Therefore,

\(E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}\)

E = 3.505 x 10⁻¹⁹ J

Now, the number of photons to make up the total energy can be calculated as follows:

\(Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\\)

n = 4 x 10¹⁸ photons

15. A ball attached to a string is being swung in a clockwise circular path as shown in Figure 3-1. In which direction
will the acceleration on the ball be when the ball passes point A?
a. direction a
b. direction b
c. direction c
d. direction d

Answers

A ball attached to a string is being swung in a clockwise circular path as shown in Figure 3-1. direction will the acceleration on the ball be when the ball passes point A is direction a. Hence option A is correct.

Angular velocity is "rate of change of angular displacement with respect to time". i.e. ω= dθ/dt. it is also defined as angular displacement over time. i.e. ω = angular displacement/Time.

Angular velocity shows how much angle can be covered in unit time. It's SI unit rad/s. direction of the Agular velocity is given by right hand thumb rule.

Angular acceleration is rate of change of Angular velocity with respect to time.

i.e. α = dω/dt if an object changes its angular velocity in short time, we can say that it has greater angular acceleration. It is expressed in rad/s².

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Which is not a piece of evidence that most scientists use to prove the origin of our universe?
A. Movement of the galaxies (expansion)
B. Cosmic microwave background
C. Presence of hydrogen and helium in the
correct percentages throughout the
universe
D. The contraction of objects in space

Answers

Answer:

D) The contraction of objects in space

Explanation:

A) Expansion of the universe as originated from the Big Bang is an important evidence, as B) the Cosmic microwave background which is thought to be left over from the Big Bang. The right proportion of hydrogen and helium as unprocessed material that has been detected as the basic elements from where the universe started.

The only out of context option is option D

label each statement 1 2 or 3 for the law of motion it illudtrates​

label each statement 1 2 or 3 for the law of motion it illudtrates

Answers

Answer:

2

1

2

1

3

1

Explanation:

I'm pretty sure these are right. you might want to go back and check the first and third, but the other 4 are right

The greater mass will have greater acceleration is a fact from second law of motion. Thus, first situation is an example of second law. Spilling of water from the glass indicates the first law , that is law of inertia.

What are laws of motion ?

Newton' s first law of motion states that, every body tends to continue on the state of motion or rest until an external force acts upon it. This law is called law of inertia.

Second law states that the force applied on a body is directly proportional to the mass and acceleration.

Newton's third law states that, for every action there is an equal and opposite reaction. The first statement indicates the second law of motion and water spilling indicates the law of inertia.

As the mass increases, more force to be applied and acceleration decreases with mass. Thus third situation indicates second law. The magician pulling the cloth from stationary, hence it is first law.

A rocket launches by a force applied on the space and an opposing force from the fuel make it move indicating the third law. The last situation indicates the first law. Hence, the labeling is as 2,1,2,1,3,1.

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The process of losing an electron, such as when a free radical steals an electron from a stable molecule is called:______

Answers

The process of losing an electron, such as when a free radical steals an electron from a stable molecule, is called electron dissociation.

Electron dissociation occurs when an electron is removed from a stable molecule, resulting in the formation of an ion. This process can be initiated by various mechanisms, including the interaction of the molecule with other reactive species like free radicals. Free radicals are highly reactive molecules that contain an unpaired electron, and they often seek to stabilize themselves by acquiring an electron from nearby molecules.

When a free radical steals an electron from a stable molecule, it causes the molecule to lose an electron and become ionized. This electron dissociation process can have important implications in various chemical reactions and biological processes, as it can lead to the formation of new chemical species and impact the overall reactivity of molecules.

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1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"

Answers

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Consider a 8.96 gram copper block of 24.44JK−1 mol−1 constant molar heat capacity at 85∘C placed in 125 g water constant molar heat capacity 75.29JK−1 mol−1at 25∘C. Consider the heat capacities as constant within the temperature range and calculate for each the change in entropy

Answers

Mass of copper block, m = 8.96 g

Constant molar heat capacity of copper, c1 = 24.44 J K⁻¹ mol⁻¹

Initial temperature of copper block, T1 = 85°C

Mass of water, M = 125 g

Constant molar heat capacity of water, c2 = 75.29 J K⁻¹ mol⁻¹

Initial temperature of water, T2 = 25°C

Heat is transferred from the copper block to the water until both reach a common temperature, T. We are to find the change in entropy for each process using the following formula:

Change in entropy, ΔS = Q / T

where Q is the amount of heat transferred and T is the common temperature of the system. Since the process is reversible, we can also write this as:

ΔS = ∫ dQ / T

Change in entropy of copper block:

The amount of heat transferred from the copper block to the water, Q1 = mc1ΔT = (8.96/63.546) × 24.44 × (T - 85) J/K

where ΔT = T - T1 is the change in temperature.

Using the formula for change in entropy:

ΔS1 = Q1 / T = (8.96/63.546) × 24.44 × (T - 85) / T J/K

Change in entropy of water:

The amount of heat transferred from the copper block to the water is the same as the amount of heat gained by the water, Q2. So,

Q2 = -Q1 = -(8.96/63.546) × 24.44 × (T - 85) J

Using the formula for change in entropy:

ΔS2 = Q2 / T = -(8.96/63.546) × 24.44 × (T - 85) / T J/K

Therefore, the change in entropy for the copper block is given by:

ΔS1 = (8.96/63.546) × 24.44 × (T - 85) / T J/K

And the change in entropy for water is given by:

ΔS2 = -(8.96/63.546) × 24.44 × (T - 85) / T J/K

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Kato is out camping with his family, and they decide to start a campfire because of the cold air. After everyone roasts marshmallows to a crispy golden brown, they eat them, and then they decide to go to sleep. Before going to sleep, Kato pours water over the campfire to put it out. He notices that steam drifts from the burned wood and ashes even though the fire is gone and the coals have stopped glowing.

Which statements best describe how energy is conserved in this scenario?

Select all that apply.

Kato is out camping with his family, and they decide to start a campfire because of the cold air. After

Answers

The statement that best describes how energy is conserved in this scenario is that the cold air absorbed energy from the water vapor, so it condensed and formed steam and the liquid water absorbed the energy of the fire, so it changed into a gas and evaporated. That is option B and D respectively.

What is conservation of energy?

The law of conservation of energy states that energy is neither created nor destroyed but can be changed from one form to another.

At the camping, energy from a lighter is being transferred to the wood and is being sustained by the chemical energy in the wood.

Upon the use of water to extinguish the fire, the liquid water absorbed the energy of the fire, so it changed into a gas and evaporated.

Also around the fire is the cold air which can absorb heat to form steam after condensation.

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In the diagram shown above, all the vehicles are traveling at 40 miles per hour. Which of the following statements is FALSE?



All three vehicles are traveling at the same constant speed


Only the truck is accelerating


All three vehicles are accelerating


The minivan and sedan have a constant velocity

In the diagram shown above, all the vehicles are traveling at 40 miles per hour. Which of the following

Answers

The false statement is all three vehicles are accelerating.

It is given that all the vehicles are travelling at 40 miles per hour. So, they are having the same speed.

From the diagram, it is shown that,

The truck is turning to the right. So, we can say that the direction of motion of the truck is changing. That means, the velocity changes in the direction but, not in magnitude.

Therefore, the truck is accelerating.

The other two vehicles are travelling at constant velocity.

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Answer:

All three vhicles are accelerating.

Explanation:

Acceleration is a change in speed. It doesn't matter if the object is slowing down or speeding up, as long as the speed is changing it is accelerating.

If a storm is 7. 5 kilometers away, how much time is expected between observations of lightning and thunder? Round your answer to one decimal place. Seconds.

Answers

The expected time period between the observations of lightning and thunder would be 22.5 s.

How to calculate the time of sound waves?

The time taken by sound to reach a certain position can be calculated by the speed formula,

\(S = \dfrac dt\)

Where,

\(S\) - speed = 0.343 km/s

\(d\) - distance = 7.5 km

\(t\) - time = ?

Put the values in the formula,

\(0.343 = \dfrac {7.5} t\\\\t = \dfrac {0.343}{7.5}\\\\t = 22.5\)

Therefore, the expected time period between the observations of lightning and thunder would be 22.5 s.

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1. When energy is being transformed, what is increasing? decreasing?​

Answers

Answer:

most likely it will stay the same

The density of mercury is 13,580 kg/m3 and the density of water is 1000 kg/m3. the specific gravity of mercury is _____.

Answers

A fluid's specific gravity is determined by comparing its density to the density of a standard reference fluid, often water.

13,580,1000 ≈ 13.6

What is the weight density of mercury?

Mercury is a highly heavy, dense metal that is silver-white and liquid at normal temperature. Because water has a density of 1.0 g/mL, and mercury has a density of 13.5 g/mL, it feels quite weighty for such a small amount of mercury.

Mercury also has a very high surface tension, which causes tiny mercury droplets to condense on glass to create virtually spherical beads. Liquid mercury can be used in thermometers like the lab thermometer below because it expands and shrinks predictably with temperature. However, due to the element's health risks, the usage of mercury thermometers has generally been discontinued.

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Suppose you flip 20 fair coins:
a) How many possible outcomes (microstates) are there?
b) What is the probability of getting the sequence: HTHHTTTHTHHHTHHHHTHT (in exactly that order)?
c) What is probability of getting 12 heads and 8 tails (in any order)?

Answers

There are 1,048,576 possible outcomes (microstates) when flipping 20 fair coins. The probability of getting the sequence "HTHHTTTHTHHHTHHHHTHT" in exactly that order is approximately 9.5367e-07.

a) There are 2 possible outcomes (heads or tails) for each coin flip, and since there are 20 coin flips, the total number of possible outcomes, or microstates, is given by 2²⁰

Answer: 2²⁰= 1,048,576 possible outcomes.

b) To calculate the probability of getting the sequence "HTHHTTTHTHHHTHHHHTHT" in exactly that order, we need to determine the probability of obtaining each individual outcome (head or tail) and multiply them together.

Since each coin flip is independent and has a 1/2 chance of resulting in either heads or tails (assuming the coins are fair), the probability of obtaining the desired sequence is (1/2)²⁰

Answer: (1/2)²⁰≈ 9.5367e-07

c) To calculate the probability of getting exactly 12 heads and 8 tails in any order, we need to determine the number of ways to arrange 12 heads and 8 tails within the 20 coin flips.

This can be calculated using the binomial coefficient, also known as "n choose k." The formula for the binomial coefficient is:

C(n, k) = n! / (k! * (n-k)!)

Where n is the total number of coin flips and k is the number of heads.

Using this formula, the probability can be calculated as follows:

P(12 heads and 8 tails) = C(20, 12) * (1/2)^20

Calculating C(20, 12):

C(20, 12) = 20! / (12! * (20-12)!)

          = 20! / (12! * 8!)

          = (20 * 19 * 18 * 17 * 16 * 15 * 14 * 13) / (8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)

          = 125,970

P(12 heads and 8 tails) = 125,970 * (1/2)^20

Answer: P(12 heads and 8 tails) ≈ 0.12013435364 (approximately)

a) There are 1,048,576 possible outcomes (microstates) when flipping 20 fair coins.

b) The probability of getting the sequence "HTHHTTTHTHHHTHHHHTHT" in exactly that order is approximately 9.5367e-07.

c) The probability of getting exactly 12 heads and 8 tails in any order is approximately 0.12013435364.

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What is the resistance of a light bulb if a potential difference of 120 V will produce a current of 0. 5 A in the bulb? 0. 0042 0. 5 60 240.

Answers

Answer is 240 ohms

Use the equation V=IR, rearranging it to make R (resistance) the subject.

R = V/I

Substitute the values:
V = 120
I = 0.5

Resistance = 120 / 0.5

Resistance = 240 ohms


The recorded lines from a seismograph
that show the magnitude and duration of
an earthquake is called a

Answers

Answer:

seismogram

A seismograph is the primary earthquake measuring instrument. The seismograph produces a digital graphic recording of the ground motion caused by the seismic waves. The digital recording is called a seismogram. A network of worldwide seismographs detects and measures the strength and duration of the earthquake’s waves.

Determine la densidad de un objeto cuya masa es de 10 kg y tiene un volumen de 120 cm3

Answers

Answer:

dttydghcghcghdytdftygfvghxk,ghc

Explanation:

A weather balloon has a volume of 90 L when it is released at sea level (P = 101 kPa) What is the pressure when it has grown to 175 L?

Answers

The pressure when the balloon has grown to 175 L is approximately 52 kPa.

What is the pressure when it has grown to 175 L?

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

We know that P1 = 101 kPa, V1 = 90 L, and V2 = 175 L.

Solving for P2:

P2 = (P1 × V1) / V2

P2 = (101 kPa × 90 L) / 175 L

P2 = 52 kPa

Therefore, the final pressure is approximately 52 kPa.

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given the balance chemical equation​

given the balance chemical equation

Answers

Answer:

in probability theory, a balance equation is an equation that describes the probability flux associated with a Markov chain in and out of states or set of states.

Explanation:

How long will your trip take if you travel 4000 m at an average speed of 8m/s

Answers

Answer:8.3mins

Explanation:

S=Vt

where V=average speed

S=4000m V=8m/s

4000=8×t

t=4000/8

t=500s

t=500/60

t=8.3min

Answer:

500 sec

8 min 20 sec

Explanation:

Hi there !

8 m ................ 1 s

4000 m ........ x s

x = 4000m×1s/8m = 500 sec = 8 min 20 sec

Good luck !

three examples of situations in which mass is the main factor determining an object's momentum?​

Answers

Situations in which mass of an object is the main factor of momentum are :

A three wheeled vehicle at relatively fast speedA truck moving at a relatively average speed A baseball on motion Factors affecting momentum

The factors that have a direct effect on an object's momentum are ;

Speed/ velocity MassDirection ( where necessary )

The momentum of an object is determined by the multiplication of the mass of object by its velocity/speed. therefore some examples of situation in which mass is a main factor determining momentum are as listed above.

p ( momentum ) = M* V

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Please help me on this!!

Please help me on this!!

Answers

B or A ima go with B
I would say b or a but b is a more reasonable answer
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