Answer:
21/8 or 2 5/8
Step-by-step explanation:
What angle can be constructed by bisecting a 45° angle?.
Angle constructed by bisecting a 45° angle: By bisecting a 45° angle, we can construct an angle with a measure of 22.5 degrees.
To bisect an angle means to divide it into two equal parts. When we bisect a 45° angle, we are essentially dividing it in half to create two angles of equal measure.
To construct the bisector of a 45° angle, we can follow these steps:
Begin by drawing a ray (a straight line extending indefinitely in one direction) to serve as one side of the angle.
Using a protractor, measure and mark a 45° angle on the ray. This will be our original angle.
Place the point of the compass on the vertex (the point where the two sides of the original angle meet) and draw an arc that intersects both sides of the angle.
Without changing the compass width, place the compass point on one of the intersection points of the arc with the angle.
Draw another arc that cuts across the first arc, creating two points of intersection.
Finally, draw a ray connecting the vertex of the angle to one of the points of intersection on the second arc. This ray will be the bisector of the 45° angle.
Upon completing these steps, we will have constructed an angle bisector that divides the 45° angle into two equal angles, each measuring 22.5 degrees.
It's important to note that bisecting an angle is a fundamental geometric construction technique and can be used to divide any given angle into two equal parts. The process described above is specifically for bisecting a 45° angle, but the same principles can be applied to bisect angles of different measures.
In summary, by bisecting a 45° angle, we can construct an angle with a measure of 22.5 degrees. This construction involves drawing an arc from the vertex, creating two intersection points, and connecting the vertex to one of those points to form the angle bisector.
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Jake has a shipping box with the following dimensions.
length: 12 inches
width: 4 inches
height: 8 inches
Havana has a shipping box similar to Jake's box, but each dimension is half as long.
How many times greater is the volume of Jake's box than Havana's box?
Jake's box is 8 times greater than Havana's box.
What is the volume of the cuboid?The volume of a cuboid is found by multiplying the length by the breadth by the height.
Given here: Two boxes Jake's and Havana's with Havana's box with dimensions half of Jake's
Therefore the ratio of the volume is = 12× 4 ×8 /6× 2× 4
=8
Hence, ake's box is 8 times greater than Havana's box.
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Use the table or s = 50m + 200
9. What is the savings after 6 months?
Months Savings
0 $200
1 $250
2 $300
3 $350
(1-j9)x+(2+j10)y=4+j3
(2-j2)x+(7-j6)y=-5+j17
What is the magnitude of x?
To find the magnitude of x, we need to solve the system of equations given: (1-j9)x + (2+j10)y = 4+j3, (2-j2)x + (7-j6)y = -5+j17. The magnitude of x is approximately √745 i.e., approximately 0.313.
We can use any method to solve this system, such as substitution or elimination. For simplicity, we'll use elimination:
Multiplying the first equation by 2-j2 and the second equation by 1-j9, we get:
(2-j2)(1-j9)x + (2-j2)(2+j10)y = (4+j3)(2-j2)
(1-j9)(2-j2)x + (1-j9)(7-j6)y = (-5+j17)(1-j9)
Simplifying, we get:
(20-18j)x + (26+26j)y = 2+14j
(20-18j)x + (61-47j)y = -112-122j
Now we can subtract the first equation from the second:
(61-47j)y - (26+26j)y = -112-122j - (2+14j)
35-73j)y = -110-136j
Solving for y, we get:
y = (-110-136j)/(35-73j)
To find x, we can substitute this value of y into either of the original equations and solve for x. Let's use the first equation:
(1-j9)x + (2+j10)(-0.565-0.169j) = 4+j3
Simplifying, we get:
x = (4+j3 - (2+j10)(-0.565-0.169j))/(1-j9)
x = 0.235-0.206j
Now we can find the magnitude of x:
|x| = sqrt(0.235^2 + (-0.206)^2)
|x| = 0.313
Therefore, the magnitude of x is approximately 0.313.
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Please help me with these ty!!!!
The volleyball team is having a carwash fundraiser. The cost of each car wash is $5. They sold some season ticket packages, which brought in $1640. The goal of the team is to make at least $2000 from the combined totals of the two fund-raisers. How many cars must they wash in order to meet the team goal of $2000?
Answer:
They need to wash 72 cars
Step-by-step explanation:
2000 - 1640 = 360
360/5 = 72
Tell whether the given value is a solution of the inequality. x - 5 ≤ 10 , x=6 yes or no
As per the given equation, the given value x = 6 is a solution of the inequality x - 5 ≤ 10.
To determine whether the given value x = 6 is a solution of the inequality x - 5 ≤ 10, we can substitute the value of x into the inequality and check if the resulting statement is true or false.
Substituting x = 6 into the inequality, we get:
6 - 5 ≤ 10
Simplifying the left side, we have:
1 ≤ 10
Since 1 is indeed less than or equal to 10, the statement is true.
Therefore, the given value x = 6 is a solution of the inequality x - 5 ≤ 10.
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on a coordinate plane, kite h i j k with diagonals is shown. point h is at (negative 3, 1), point i is at (negative 3, 4), point j is at (0, 4), and point k is at (2, negative 1).
On a coordinate plane, kite HIJK with diagonals is shown. Point H is located at (-3, 1), point I is at (-3, 4), point J is at (0, 4), and point K is at (2, -1). The diagonals of this kite connect points H and J, and points I and K, creating an intersecting pattern within the shape.
Based on the information provided, we know that a kite shape has been loaded onto a coordinate plane with points h, i, j, and k located at specific coordinates. The coordinates for point h are (-3, 1), for point i are (-3, 4), for point j are (0, 4), and for point k are (2, -1). Additionally, we know that the kite has diagonals, but we are not given any information about their lengths or intersection points.
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Answer:
B is the answer
Step-by-step explanation:
A student states that −x is always equal to a negative integer. Complete the following statement to determine if the student is correct.
Answer:
iF X IS POSITIVE THEN -X IS ALWAYS NEGATIVE
IF X IS NEGATIVE, THEN -X IS ALWAYS POSITIVE
THE NEGATIVE OF A POSITIVE IS ALWAYS POSITIV
THE NEGATIVE OF A NEGATIVE IS ALWAYS POSITIVE
Step-by-step explanation:YS
−x is always equal to a negative integer is an incorrect statement.
The student is not correct.
What is Number system?A number system is defined as a system of writing to express numbers.
−x is always equal to a negative integer when x is positive integer
−x is always equal to a positive integer when x is negative integer
Which means the value of -x changes on the integer of x.
If x is positive then -x will be always negative, If x is negative then -x is positive.
The negative of a negative integer is positive and the negative of positive integer is negative.
Hence −x is always equal to a negative integer is an incorrect statement.
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yesterday, eric had m baseball cards. today, he got 10 more. using m , write an expression for the total number of baseball cards he has now. as an equation
Answer:
m+10
Step-by-step explanation:
We know that yesterday, eric had m baseball cards. Thus, we can denote that the total number of baseball cards he had yesterday is m.
We know that he got 10 more today. Since he is receiving more, he is adding to his collection. Since he is getting more, we have to add 10 to how many baseball cards he used to have. He used to have m baseball cards, so today he has m+10 baseball cards.
This is the answer as we cannot combine 10 and m. Since m is a variable with no set value as of now, and 10 is a constant number that has no variable, they are not like terms and cannot be added. So the answer is m+10 baseball cards.
I hope this helped.
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how much external financing is required by berea for the coming year?
The external financing required by Berea for the coming year is $34 million.
Given data,
Capital expenditure program for the coming year= $70 million
Earnings before interest and taxes for the next year= $45 million
Increase in dividend payments= $1 million
Increase in current asset needs= $4 million
Increase in current liabilities, excluding short-term bank borrowings= $4 million
Interest payments= $5 million
Long-term debt retirement obligations= $7 million
Depreciation on financial statements for next year= $15 million
Depreciation on tax purposes for next year= $18 million
To calculate external financing required by Berea for the coming year, we need to calculate the amount of total fund required for the next year as follows:
Calculation of total fund required for the next year:
Sources of Fund Amount ($)Earnings before interest and taxes (EBIT)$45 million
Increase in current liabilities (excluding bank borrowing) $4 million
Depreciation on financial statements $15 million
Total Sources of Fund$64 million
Application of Fund Amount ($)Capital expenditure program for the coming year $70 million
Dividend payment$12 million
Increase in current asset needs $4 million
Interest payments $5 million
Long-term debt retirement obligations $7 million
Total Application of Fund $98 million
Therefore, Total fund required for the next year = $98 million
Total sources of fund available for the next year = $64 million
External financing required for the next year= Total fund required for the next year - Total sources of fund available for the next year= $98 million - $64 million= $34 million
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-3x lessthan or equal to 3x +3 less than 2x+ 10
Answer:
x ≥ 0Hope this helped :)65 people like cricket or tennis .40 of them like cricket while 30 like cricket only .How many like tennis only?How many like tennis?
Answer:
The overlap is 40 - 30 = 10 which means 10 people like both. 65 - 40 = 25 people like tennis only and 25 + 10 = 35 people like tennis.
to minimize the number of times the hood sash is raised and lowered. Work as much as possible in the
Working efficiently, grouping tasks together, using the hood only when necessary, and proper cleaning and maintenance can all help minimize the number of times the hood sash is raised and lowered.
To minimize the number of times the hood sash is raised and lowered, it's important to work efficiently as possible in the hood. This means planning out your work ahead of time and grouping tasks together that require similar equipment or materials.
For example, if you need to use a particular chemical for multiple experiments, try to do all of those experiments at once rather than opening and closing the hood multiple times throughout the day. Additionally, make sure to properly label and organize your materials so that you can easily find what you need without having to spend time searching for it.Another way to minimize hood usage is to make sure that you are using the hood only when it's necessary. If a task can be completed outside of the hood, do it there instead. This will not only save time and energy, but it will also reduce the risk of contamination within the hood.Lastly, make sure to properly clean and maintain the hood to ensure that it's functioning at its best. A well-maintained hood will reduce the likelihood of needing to raise and lower the sash multiple times throughout the day. In summary, working efficiently, grouping tasks together, using the hood only when necessary, and proper cleaning and maintenance can all help minimize the number of times the hood sash is raised and lowered.Know more about the grouping tasks
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There are 24 hots and 14 hamburgers write the ratio of hotdogs and hamburgers
Answer:
12:7
Step-by-step explanation:
24 is the number of hotdogs and for very 24 hotdogs there are 14 hamburgers:
So it can be wirriten like this: 24:14
But we can simlify it further by dividing each side by 2.
24 / 2 : 14 / 2
12:7
2. find the general solution of the system of differential equations d dt x = 9 3
The general solution to the system of differential equations dx/dt = 9, dy/dt = 3y is:
\(x(t) = 9t + C1\\y(t) = Ce^{(3t)} or y(t) = -Ce^{(3t)\)
To solve this system, we can start by integrating the first equation with respect to t:
x(t) = 9t + C1
where C1 is a constant of integration.
Next, we can solve the second equation by separation of variables:
1/y dy = 3 dt
Integrating both sides, we get:
ln|y| = 3t + C2
where C2 is another constant of integration. Exponentiating both sides, we have:
\(|y| = e^{(3t+C2) }= e^{C2} e^{(3t)\)
Since \(e^C2\) is just another constant, we can write:
y = ± \(Ce^{(3t)\)
where C is a constant.
The general solution to the system of differential equations dx/dt = 9, dy/dt = 3y is:
\(x(t) = 9t + C1\\y(t) = Ce^{(3t)} or y(t) = -Ce^{(3t)\)
where C and C1 are constants of integration.
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Question
find the general solution of the system of differential equations dx/dt = 9
dy/dt = 3y
1. a) Construct the frequency distribution for drive-through service times for Burger King lunches using the accompanying data set. Times begin when a vehicle stops at the order window and end when the vehicle leaves the pickup window. Lunch times were measured between 11:00 AM and 2:00 PM. Begin with a lower class limit of 70 seconds and use a class width of 40 seconds. b) Construct a Cumulative frequency distribution table for the data. c) Using the Frequency distribution in a), find the class boundaries, class midpoints, and then Construct a Histogram using these on the horizontal axis (label both axes);tell why this data is NOT a Normal Distribution. Class Boundaries: Class Midpoints: Histogram in this space:
The answers are as follows a) The table for frequency distribution is: 70 - 109 9 0.225110 - 149 18 0.450150 - 189 11 0.275190 - 229 3 0.075 Total 40 1.000, b) The table is: 70 - 109 9 0.225 0.225110 - 149 18 0.450 0.675150 - 189 11 0.275 0.950190 - 229 3 0.075 1.000, (c) Class boundaries are: 70 - 10970 10969.5 109.5110 - 149110 149109.5 149.5150 - 189150 189149.5 189.5190 - 229190 229189.5 229.5, and Class midpoints are: 70 - 10970 10989.5110 - 149110 149129.5150 - 189150 189169.5190 - 229190 229209.5.
a) To construct the frequency distribution for drive-through service times for Burger King lunches using the accompanying data set, we will have to use a lower class limit of 70 seconds and use a class width of 40 seconds.
The lunch times were measured between 11:00 AM and 2:00 PM. The data set is as follows: 69 71 101 89 99 103 104 102 96 92 78 86 77 94 95 93 85 90 91 79 76 80 97 87 82 75 72 81 84 88 83 100 98 74 73 105 106 107 108
We need to start by listing the lower limits of each class. Lower class limits are rounded down to the nearest whole number. Since the starting lower class limit is 70, then the first class will have a lower limit of 70.
The table for the frequency distribution is given below: Class IntervalFrequencyRelative Frequency 70 - 109 9 0.225110 - 149 18 0.450150 - 189 11 0.275190 - 229 3 0.075 Total 40 1.000
b) To construct the Cumulative frequency distribution table for the data, we will add the relative frequencies for each class. The table is given below: Class IntervalFrequencyRelative FrequencyCumulative Frequency70 - 109 9 0.225 0.225110 - 149 18 0.450 0.675150 - 189 11 0.275 0.950190 - 229 3 0.075 1.000
c) Using the Frequency distribution in a), we can find the class boundaries and class midpoints. Class boundaries are half-way points between upper limit of one class and lower limit of the next class. Class boundaries can be calculated using the formula: Upper limit of one class + lower limit of next class / 2.
Class boundaries are obtained as follows: Class IntervalLower Class LimitUpper Class LimitClass Boundaries70 - 10970 10969.5 109.5110 - 149110 149109.5 149.5150 - 189150 189149.5 189.5190 - 229190 229189.5 229.5
To calculate the class midpoints, we use the formula: Lower limit + upper limit / 2. Class midpoints are obtained as follows: Class IntervalLower Class LimitUpper Class LimitClass Midpoints70 - 10970 10989.5110 - 149110 149129.5150 - 189150 189169.5190 - 229190 229209.5
We can now plot a histogram using the class midpoints on the horizontal axis and the frequencies on the vertical axis. The histogram is given below: The data is not a normal distribution because it is not symmetric and is skewed to the right.
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Find the slope of a line passing through the points (8,-3) and (0,-1)
The senior classes at high school A and high school B planned separate trips to the county fail. The senior class at high school A rented and filled 7 vans and 12 busses with 640 student. High school B rented and filled 12 vans and 6 busses with 456 students. Each van and each bus carried the same number of students. Find the number of students in each van and each bus.
7v + 12b = 640
12v + 6b = 456
Multiply the bottom equation by -2 in order to cancel out 12b with 6b.
7v + 12b = 640
- 24v -12b = -912
-17v = -272
17v = 272
v = 272/17
v = 16 students
If we use this: 7v + 12b = 640 ;then:
7(16) +12b = 640
112 +12b = 640
12b = 640 -112
12b = 528
b = 528/12
b = 44 students
So the number of students in each van is 16, and number of students in each bus is 44.
Solve for x round to the nearest tenth
Answer:
Step-by-step explanation:
1) 8.9
2) 27.8
3) 24.3
4) 11.4
5) 27.5
6) 49.2
7) 8.1
8)4.8
5 and 9 are the example of ____ number
Answer:
Step-by-step explanation:
complex numbers , real numbers , rational numbers , natural numbers , whole numbers
HELP ASAP
The table shows input and output values of a function given a rule. Which function
represents the rule?
Input: x, a number; Output: y, 3 less than 2 times x
Input, x: -2 -1 0 1 2
Output, y: -7 -5 -3 -1 1
y=2x+3
y=2x-3
y=-3x+2
y=2x
Answer:I think its A.
Step-by-step explanation:
I'm too lazy too explain you got your answer please be happy
Which expressions are equal to 11 x 1037 Select all that apply.
A 11 x 100
B. 11,000
C. 11 x 10 x 10 x 10
D. 33,000
E. 11 x 11 x 11
HELPPPPP!!!!!!!!!!!!!!!!!!!! THIS IS DUE IN 17 MINUTES AND THIS IS THE LAST QUESTION I NEED THE ANSWER TO! (((PLEASE ACTUALLY GIVE ME THE ANSWER AD NOT THE LINKY PLEASE!!)))
Answer:
689/1000
hope this helped
Name the Property of Equality that justifies this statement:
If p = q,.
Answer:
Symmetric property
Step-by-step explanation:
Symmetric property of equality tells that for all real numbers p and q, if p=q then q=p. which means if we interchange the sides of an equation then the equation is still a true statement
assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the value of the quartile q3.
The value of the fourth quartile q3=66.951 when the mean is 63.6 inches and the standard deviation is 2.5 inches.
The normal distribution: This is the distribution of type of continuous probability distribution in which most data points cluster toward the middle of the range, while the rest taper off symmetrically toward either extreme.
The middle of the range is also known as the mean of the distribution.
The mean and standard deviation are given
sd=2.5
μ=63.6
P(X<Q3)=0.75
By using the Z- table we get the value of the inv norm(0.75)
inv norm(0.75)=0.6745
Now know all values to find the Q3 substitute in the Q3 formula
Q3=65.4+23*(0.6745)
=66..981350
Q3=66.951
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Use the vertical line test to determine whether y is a function of x
Answer:
Not a function of x
Step-by-step explanation:
A vertical line intersects the graph twice, which immediately tells us that y is not a function of x here. If y were a function, the vertical line would intersect the graph in only one place.
No, A vertical line intersects the graph doubled, which instantly tells us that y exists not a function of x here. If y existed a function, the vertical line would intersect the graph in just one area.
What is Vertical line test?If a vertical line can be drawn to connect the graph of a function in more than one place, then stands NOT a function. If it exists not feasible to draw a vertical line to touch the graph of a function in more than one place, then y exists as a function of x.
No, A vertical line intersects the graph doubled, which instantly tells us that y exists not a function of x here. If y existed a function, the vertical line would intersect the graph in just one area.
Therefore, the correct answer is option B. No.
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At a farmers' market, Frederick buys 4 pounds of apples and 14 pounds of cherries for $38.64. At the same farmers' market, Wilhelmina buys 12 pounds of apples and 7 pounds of cherries for $27.72. Determine the price per pound of apples and cherries at the farmers' market.
Answer:
Price per pound of apple=$0.84
Price per pound of cherry=$2.52
Step-by-step explanation:
Let apple=a
Let cherry =c
Fredrick
4a+14c=38.64. (1)
Wilhelmina
12a+7c=27.72. (2)
Multiply (1) by 1 and (2) by 2
4a+14c=38.64. (3)
24a+14c=55.44 (4)
Subtract (3) from (4)
20a= 16.8
a=16.8/20
a=0.84
Substitute a=0.84 into equ (1)
4a+14c=38.64
4(0.84)+14c=38.64
3.36+14c=38.64
14c=38.64-3.36
14c=35.28
c=35.28/14
c=2.52
Price per pound of apple=$0.84
Price per pound of cherry=$2.52
Check
4(0.84)+14(2.52)
3.36+35.28=38.64
12a+7c=27.72
12(0.84)+7(2.52)
=10.08+17.64
=27.72
What is the slope of the line containing (-2,5) and (4, -4)?
O A. -2
O B.
3
2
O c. 2
O D.
3
2
Answer:
-3/2
Step-by-step explanation:
See attached image
Answer:
\(m=\frac{-3}{2}\)
Step-by-step explanation:
m = slope
\(m=\frac{-4-5}{4--2}\)
\(m=\frac{-9}{6}\)
\(m=\frac{-3}{2}\)
A spherical balloon is inflated so that its volume is increasing
at the rate of 3.8 ft^3/min. How rapidly is the diameter of the
balloon increasing when the diameter is 1.7 feet?
The diameter is incre
The volume of the spherical balloon is increasing at the rate of 3.8ft^3/min.
Diameter of balloon is 1.7ft.
Let's find the relationship between the volume, radius, and diameter of the spherical balloon. The formula for the volume of a sphere is given as V = (4/3)πr³
where r is the radius of the sphere. To find the diameter of a sphere, we use the formula:D = 2r
Differentiating the formula for volume with respect to time, we have:dV/dt = 4πr²(dr/dt)
Here, dV/dt represents the rate of change of volume of the sphere and dr/dt represents the rate of change of the radius of the sphere.
Now, substitute the values given in the question:dV/dt = 3.8 ft³/minr = 1.7/2 = 0.85 ft
When diameter is 1.7 ft, radius (r) = 0.85 ftDifferentiating the formula for diameter with respect to time, we get:d/dt (D) = d/dt (2r)We know that dr/dt = ? (rate of change of radius)Therefore, d/dt (D) = 2 × dr/dt
Substitute the value of dr/dt in the above equation to get:d/dt (D) = 2 × dr/dtd/dt (D) = 2 × [dV/dt ÷ 4πr²]Substitute the given values:d/dt (D) = 2 × [3.8/(4×π×0.85²)]d/dt (D) ≈ 0.868 ft/minTherefore, the diameter of the balloon is increasing at a rate of approximately 0.868 ft/min when the diameter is 1.7 ft.
So, the diameter of the balloon is increasing at a rate of approximately 0.868 ft/min when the diameter is 1.7 ft.
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