what is the length of BC, AC, ED, DK, &’ EK?
sorry there’s so many!! i tried putting it at 25 points!!!!! PLEASE PLEASE HELP ME THIS IS 4 A TEST

Answer:

$42.00

Step-by-step explanation:

We can represent the given information as a ratio:

% of original price : price

                          5% : $2.00

Then, we can multiply both sides of this ratio by 20 (or 100% / 5%) to get 100% of the original price, which IS the original price.

5%      :  $2.00

↓ × 20   ↓ × 20

100%  :  $40.00

Now that we know the original price, we can add $2.00 to get the new price.

$40.00 + $2.00 = $42.00

The tax revenue generated from property taxes is often used to fund expressions public services such as schools, parks, and infrastructure projects in the local community.

In mathematics, you can multiply, divide, add, or subtract. An expression is constructed as follows: Number, expression, and mathematical operator A mathematical expression is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.) It is possible to contrast expressions and phrases. An expression or algebraic expression is any mathematical statement that has variables, integers, and an arithmetic operation between them. For example, the expression 4m + 5 has the terms 4m and 5, as well as the provided expression's variable m, all separated by the arithmetic sign +. The calculation of property tax is typically based on the assessed value of the property and the tax rate set by the local government. The assessed value is determined by a government-appointed assessor who evaluates the value of the property based on factors such as its location, size, age, and condition. The tax rate is then applied to the assessed value to determine the amount of tax owed by the property owner. The tax revenue generated from property taxes is often used to fund public services such as schools, parks, and infrastructure projects in the local community.

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The least amount of money that was originally put in the savings account is $426.

The amount of money in the savings account is a function of the money that was originally in the account and the amount by which the account was increased by.

The inequality that represents the total amount of money in the savings account is:

amount originally in the account + amount deposited > 500

x + $75 > $500

x > $500 - $75

x > $425

The least amount would be $426 because this is the smallest number that is greater than $425 that would make the total amount more than $500.

To check:

$75 + $426 = $501

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The volume of the smaller wedge cut from a sphere of radius 4 by two planes that intersect along a diameter at an angle of π/6 is 1/6.

What is volume ?

Volume is a measurement of three-dimensional space that is occupied. It is frequently expressed quantitatively using SI-derived units, as well as several imperial or US-standard units. Volume and the notion of length are connected.

Consider that the tetrahedron is bounded by the coordinate planes and the plane 8 x+y+z=2

Evaluate the triple integral \(\iiint_E d V$.\)

The lower boundary of tetrahedron is the plane z=0 and the upper boundary of tetrahedron is the plane z=2-8 x-y.

And the projection is y=2-8 x.

The x-limits are obtained by taking y=0 and z=0 in 8 x+y+z=2.

\($$\begin{array}{r}8 x=2 \\x=\frac{2}{8} \\x=\frac{1}{4}\end{array}$$\)

Therefore, the region becomes \($R=\left\{(x, y, z) / 0 \leq x \leq \frac{1}{4}, 0 \leq y \leq 2-8 x, 0 \leq z \leq 2-8 x-y\right\}$\).

Therefore, the integral becomes

\($ \iiint_E d V=\int_0^{\frac{1}{4}} \int_0^{2-8 x} \int_0^{2-8 x-y} d z d y d x $\)

\($=\int_0^{\frac{1}{4}} \int_0^{2-8 x}[z]_0^{2-8 x-y} d y d x $\)

\($ =\int_0^{\frac{1}{4}} \int_0^{2-8 x}[2-8 x-y] d y d x $\)

\($ =\int_0^{\frac{1}{4}}\left[2 y-8 x y-\frac{y^2}{2}\right]_0^{2-8 x} d x . $\)

\($ =\int_0^{\frac{1}{4}}\left[2(2-8 x)-8 x(2-8 x)-\frac{(2-8 x)^2}{2}\right] d x $\)

\($ =\int_0^{\frac{1}{4}}\left[32 x^2-16 x+2\right] d x $\)

\($ =\left[32\left(\frac{x^3}{3}\right)-16\left(\frac{x^2}{2}\right)+2 x\right]_0 $\)

\($ =32\left(\frac{\left(\frac{1}{4}\right)^3}{3}\right)-16\left(\frac{\left(\frac{1}{4}\right)^2}{2}\right)+2\left(\frac{1}{4}\right)-0 $\)

\($ =\frac{1}{6} $\)

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the length of side a is 91 ft (rounded to the nearest whole foot) and the length of side b is 132 ft (rounded to the nearest whole foot). The area of the triangle is approximately 6007 sq ft.

Given: The hypotenuse of the right triangle,

c = 159 ft; angle A = 34°

We know that, in a right-angled triangle:

\($$\sin\theta=\frac{\text{opposite}}\)

\({\text{hypotenuse}}$$$$\cos\theta=\frac{\text{adjacent}}\)

\({\text{hypotenuse}}$$\)

We know the value of the hypotenuse and angle A. Using trigonometric ratios, we can find the length of sides in the right triangle.We will use the following formulas:

\($$\sin\theta=\frac{\text{opposite}}\)

\({\text{hypotenuse}}$$$$\cos\theta=\frac{\text{adjacent}}\)

\({\text{hypotenuse}}$$$$\tan\theta=\frac{\text{opposite}}\)

\({\text{adjacent}}$$\) Length of side a is:

\($$\begin{aligned} \sin A &=\frac{a}{c}\\ a &=c \sin A\\ &= 159\sin 34°\\ &= 91.4 \text{ ft} \end{aligned}$$Length of side b is:$$\begin{aligned} \cos A &=\frac{b}{c}\\ b &=c \cos A\\ &= 159\cos 34°\\ &= 131.5 \text{ ft} \end{aligned}$$\)

Now, we have the values of all sides of the right triangle. We can calculate the area of the triangle by using the formula for the area of a right triangle:

\($$\text{Area} = \frac{1}{2}ab$$\)

Putting the values of a and b:

\($$\begin{aligned} \text{Area} &=\frac{1}{2}ab\\ &=\frac{1}{2}(91.4)(131.5)\\ &= 6006.55 \approx 6007 \text{ sq ft}\end{aligned}$$\)

Therefore, the length of side a is 91 ft (rounded to the nearest whole foot) and the length of side b is 132 ft (rounded to the nearest whole foot). The area of the triangle is approximately 6007 sq ft.

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The probability of selecting 50 jars is 0%

The z score determines by how many standard deviations the raw score is above or below the mean. It is given by:

\(z=\frac{x-\mu}{\sigma/\sqrt{n} } \\\\where \mu=mean,\sigma=standard\ deviation, x=raw\ score,n=sample\ size\\\\Given\ that\ \mu=17,\sigma=0.68,n=50,x=16.8\\\\z=\frac{16.8-17}{0.65/\sqrt{50} } =-5\)

The P(z < -5) = 0%

Therefore the probability of selecting 50 jars is 0%

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It takes 10 minutes for the number of bacteria in the population to double.

To determine the time it takes for the number of bacteria in a population to double, we need to find the value of t when the function f(t) equals twice the initial number of bacteria.

The given function is f(t) = 60,000 * 2^(t/10).

To find the time it takes for the number of bacteria to double, we set f(t) equal to twice the initial number of bacteria, which is 2 * 60,000 = 120,000:

120,000 = 60,000 * 2^(t/10).

Next, we can simplify the equation by dividing both sides by 60,000:

2 = 2^(t/10).

Since both sides of the equation have the same base (2), we can equate the exponents:

t/10 = 1.

To solve for t, we multiply both sides by 10:

t = 10.

Therefore, it takes 10 minutes for the number of bacteria in the population to double.

This result is obtained by setting the growth rate of the bacteria population in the given function. The exponent t/10 determines the rate of growth, and when t is equal to 10, the exponent becomes 1, resulting in a doubling of the initial number of bacteria.

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Given, Abby can buy an 8-pound bag of dog food for $7.40.

The cost of one pound bag when 8-pound bag of dog food for $7.40 is,

Given, 4-pound bag of the same dog food costs $5.38.

Therefore, the cost of one pound bag when 4-pound bag of dog food costs $5.38 is,

Since the cost of one pound bag has a smaller value(=0.925) when an 8-pound bag of dog food is bought, buying an 8-pound bag of dog food for $7.40 would be the best deal.

Answer:

\(d=11\)

Step-by-step explanation:

Distance Formula: \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Simply plug in your 2 coordinates into the distance formula to find distance d:

\(d=\sqrt{(5-(-6))^2+(-4-(-4))^2}\)

\(d=\sqrt{(5+6)^2+(-4+4)^2}\)

\(d=\sqrt{(11)^2+(0)^2}\)

\(d=\sqrt{121+0}\)

\(d=\sqrt{121}\)

\(d=11\)

Answer:

slope: \(-\frac{8}{11}\)

slope-intercept form: y= \(-\frac{8}{11}\)x+\(\frac{248}{11}\)

Step-by-step explanation:

Hope this helps!

Solution:

Given:

To graph the line, at least the coordinates of two points are needed.

Using the x and y-intercepts;

Using the two points, the graph of the line is shown;

Answer:

\(\displaystyle d = \sqrt{74}\)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Point (6, 2) → x₁ = 6, y₁ = 2

Point (1, -5) → x₂ = 1, y₂ = -5

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Answer:

Answer:

(0, 6)

Step-by-step explanation:

Point T has a coordinate pair of (3, 4). That is, at point T, x = 3, while y = 4.

3 points to the left of T would be a movement on the x-axis. This movement is a run across the x-axis. At T, x = 3. Therefore, 3 points to the left would be a decrease by 3 = 3 - 3 = 0.

3 points to the left of T would leave us with an x coordinate of 0.

2 points above T suggest a rise, which is on the y-axis.

Therefore, at T, y = 4. 2 points above 4 = 4 + 2 = 6. y coordinate would now be 6.

In conclusion, the ordered pair representing 3 points to the left, and 2 points above point T is (0, 6).

Answer:

(0, 6)

Step-by-step explanation:

Answer:

The distance of two complex numbers

\(z_{1} z_{2} = \sqrt{82}\)   = 9.055

Step-by-step explanation:

Step(i):-

Given that z₁ = 6-3i and z₂ = -3-4i

We know that 'z' represents a point on the argand plane with absicca 'x' and ordinate 'y'

Now given points are ( x₁ , y₁)  = (6 ,-3) and (x₂, y₂) = (-3 , -4)

Step(ii):-

The distance of two points

               \(\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} - y_{1} )^{2} }\)

     z₁ z₂  \(= \sqrt{(-3-6)^{2} +(-4-(-3)^{2} }\)

     \(z_{1} z_{2} = \sqrt{81+1}\)

    \(z_{1} z_{2} = \sqrt{82}\) =9.055

Answer: 5 weeks

Explanation:

To find out when both siblings will have the same amount of money in their savings accounts, we need to solve the system of equations:

y = 10x + 25

y = 5x + 50

We can set the two equations equal to each other and solve for x:

10x + 25 = 5x + 50

5x = 25

x = 5

Therefore, after 5 weeks, both siblings will have the same amount of money in their savings accounts. So the answer is 5 weeks.

Table

\(\boxed{\begin{array}{c|c}\boxed{\bf x} &\boxed{\bf g(x)} \\ \sf 1&\sf 81 \\ \sf 2&\sf 83 \\ \sf 3&\sf 85\\ \sf 4 &\sf 87(Expected)\end{array}}\)

\(\boxed{\begin{array}{c|c}\boxed{\bf x} &\boxed{\bf f(x)} \\ \sf 1&\sf 80.5 \\ \sf 2&\sf 81 \\ \sf 3&\sf 81.5 \\ \sf 4&\sf 82\end{array}}\)

Now

#Part A:-

Test average for completing test 2 in maths=81

#Part-B

Test average for completing test 2in science=83

#Part C.

The probability of the event between two and five lines, inclusive, are in use is 0.85.

Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event.

Given that,

x         0         1         2       3        4         5         6

p(x)   0.12    0.18   0.20  0.20  0.20   0.07   0.03

a) At most three lines are in use

Here we need to find the probability for x≤3.

P(x≤3)=P(x=0)+P(x=1)+P(x=2)+P(x=3)

= 0.12+0.18+0.20+0.20

= 0.70

b) Fewer than three lines are in use

Here we need to find the probability for x<3.

P(x<3)=P(x=0)+P(x=1)+P(x=2)

= 0.12+0.18+0.20

= 0.50

c) At least three lines are in use

Here we need to find the probability for x≥3.

P(x≥3)=P(x=3)+P(x=4)+P(x=5)+P(x=6)

= 0.20+0.20+0.07+0.03

= 0.50

d) Between two and five lines, inclusive, are in use

Here we need to find the probability for 2≤x≤5.

P(2≤x≤5)= P(x=2)+P(x=3)+P(x=4)+P(x=5)

= 0.18+0.20+0.20+0.20+0.07

= 0.85

Therefore, the probability of the event between two and five lines, inclusive, are in use is 0.85.

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Answer:

D

Step-by-step explanation:

Has only one point on the x- axis.

The situation that cannot be modeled by using an exponential function is A. Jim buys a golf membership for $ 150 and it costs him $ 11 each time he plays a round of golf.

Exponential functions are mathematical functions in which the variable (usually denoted by "x") is in the exponent, rather than the base. They take the form of f(x) = a^x, where a is a constant known as the base of the function, and x is the input variable. These functions are characterized by rapid growth or decay as x increases or decreases.

The situation where Jim buys a golf membership cannot be modelled this way as it is a linear function because there is a given rate of increase that is not exponential.

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Answer:

First, substitute x for 2 in 7x+5=21.

7 * 2 = 14 + 5 = 19

x = 2 is not a solution of 7x+5=21.

Answer:

\(r=19\)

\(IQR=9\)

\(SD=5.81\)

Step-by-step explanation:

Given the following data set:

\(26, 27, 20, 15, 30, 34, 28,20\)

To find the range of a data set we have to find the largest and the smallest number of the set and then subtract them.

\(26, 27, 20, 15, 30, 34, 28,20\)

\(34-15=19\)

\(r=19\)

To find the interquartile range we have to subtract the third quartile by the first quartile.

\(26, 27, 20, 15, 30, 34, 28,20\)

\(IQR=Q3-Q1\)

\(Q1=20\)

\(Q3=29\)

\(IQR=29-20=9\)

\(IQR=9\)

To find the standard deviation of a data set we have to use the formula to calculate standard deviation with the given values.

\(SD=\frac{(26-25)^2+...+(20-25)^2}{8}\)

\(SD=\frac{270}{8} =\sqrt{33.75} =5.8094750193111\)

\(5.8094750193111\)

\(9>5\)

\(SD=5.81\)

Hope this helps.

The table for this arithmetic sequence should be completed as follows:

Position   1     6     8     11     19     25

Term       0   -10   -14   -20   -36   -48

Mathematically, the nth term of an arithmetic sequence can be calculated by using this expression:

aₙ = a₁ + (n - 1)d

Where:

Next, we would determine the common difference by using the 25th term of this arithmetic sequence:

-48 = 0 + (25 - 1)d

-48 = 24d

d = -48/2

d = -2.

For the nth term of this arithmetic sequence with -10, we have:

aₙ = a₁ + (n - 1)d

-10 = 0 + (n - 1)-2

-10 = -2n + 2

2n = 12

n = 6.

For the 8th term of this arithmetic sequence, we have:

a₈ = a₁ + (n - 1)d

a₈ = 0 + (8 - 1)-2

a₈ = -14.

For the nth term of this arithmetic sequence with -20, we have:

aₙ = a₁ + (n - 1)d

-20 = 0 + (n - 1)-2

-20 = -2n + 2

2n = 22

n = 11.

For the 19th term of this arithmetic sequence, we have:

a₁₉ = a₁ + (n - 1)d

a₁₉ = 0 + (19 - 1)-2

a₁₉ = -36.

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Answer:

Step-by-step explanation:

Solution:

A four-digit number 4ab5 is divisible by 55. Then the value of b - a is 1.

a. The x-coordinate of the vertex (2) represents the time it takes for the ball to reach its maximum height, and the y-coordinate (182) represents the maximum height itself.

b. The tennis ball is initially at a height of 126 feet above the ground.

a. The x-coordinate of the vertex is 2. To find the y-coordinate, we substitute this value back into the equation:

h(2) = -14(2)² + 56(2) + 126

h(2) = -14(4) + 112 + 126

h(2) = -56 + 112 + 126

h(2) = 182

Therefore, the vertex of the equation is (2, 182). In this context, the vertex represents the highest point reached by the tennis ball during its trajectory. The x-coordinate of the vertex (2) represents the time it takes for the ball to reach its maximum height, and the y-coordinate (182) represents the maximum height itself.

b. In order to find the y-intercept, we set t equal to zero and evaluate h(t):

h(0) = -14(0)² + 56(0) + 126

h(0) = 126

The y-intercept is 126. In this context, the y-intercept represents the initial height of the ball when it is thrown. Therefore, the tennis ball is initially at a height of 126 feet above the ground.

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Step-by-step explanation:

the value of P(B|A)P(B∣A), rounding to the nearest thousandth

The average number of enrollments per day at the Sunnyside Daycare is 21.

An average is a result obtained by summing some numerical values and then dividing the total by the number of values or variables.

An average is the mean, which is one of the central tendency values.

Day          Number of Enrollments

Monday                 17

Tuesday                19

Wednesday         23

Thursday              14

Friday                  25

Saturday             28

Total =               126

Average enrollments = 21 (126/6)

Thus, the average number of enrollments per day at the Sunnyside Daycare is 21.

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What was the average number of enrollments per day?

Member of the gym: (154 + 92 + 251 + 225 + 94 ) = 816

Boxing class = 251 (member)

Boxing/ total members = 251 / 816 = 0.3076

Answer:

The 36-pack is a better buy by $0.50 per 36 bottles.

Step-by-step explanation:

24 bottles for $3 compared to 36 bottles for $4

Unit rates:

$3/24 = $0.125/bottle

$4/36 = $0.111/bottle

The 36-pack is a better buy since the unit price is lower.

$0.125 - $0.111 = $0.013888...

$0.01388888... * 36 = $0.50

Answer: The 36-pack is a better buy by $0.50 per 36 bottles.