If m1=100°, what is m
?
ACB
Note that the figure may not be to scale.

Answer:

20/3x,  and    60/1x

Step-by-step explanation:

Answer:

Graph A

Step-by-step explanation:

Going through and eliminating graphs based on the criteria, graph A is the only one that shows Wednesday having more tickets sold than Monday and Tuesday combined , as well as having both Thursday and Friday with more than two times the number of tickets sold Wednesday.

Answer:

1 and 4

Step-by-step explanation:

All the other options have corresponding x-values

Answer:

The first and fourth options

Step-by-step explanation:

If it's a function no input and have more than one output.

We analyze two functions: T: R² → R² and O: V → W. T fails the property of additive homogeneity, proving it is not a linear transformation. O satisfies additive homogeneity and preservation of the zero vector, confirming it as a linear transformation.

(a) To prove that the function T: R² → R² is not a linear transformation, we need to find a counterexample that demonstrates the failure of one of the linearity properties. Let's consider the linearity property of additive homogeneity.

Counterexample for additive homogeneity:

We can show that T does not satisfy additive homogeneity by choosing two vectors, (x₁, y₁) and (x₂, y₂), and scalar c, such that:

T(c(x₁, y₁)) ≠ cT(x₁, y₁) + cT(x₂, y₂)

Let's choose (x₁, y₁) = (1, 2), (x₂, y₂) = (3, 4), and c = 2.

T(c(x₁, y₁)) = T(2(1, 2)) = T(2, 4) = (2*4, 2+4) = (8, 6)

cT(x₁, y₁) + cT(x₂, y₂) = 2T(1, 2) + 2T(3, 4) = 2(2, 3) + 2(12, 7) = (4, 6) + (24, 14) = (28, 20)

Since (8, 6) ≠ (28, 20), we have found a counterexample, proving that T is not a linear transformation.

(b) Now let's prove that the zero function O: V → W, given by O(v') = 0'w, is a linear transformation.

To show that O is a linear transformation, we need to verify two properties: additive homogeneity and preservation of the zero vector.

Additive homogeneity:

Let's consider two vectors, v₁ and v₂, and a scalar c.

O(c(v₁ + v₂)) = O(cv₁ + cv₂) = 0'w

By the properties of scalar multiplication and vector addition, we can distribute the scalar c and apply O to each term separately:

O(cv₁ + cv₂) = O(cv₁) + O(cv₂) = cO(v₁) + cO(v₂) = c(0'w) + c(0'w) = 0'w + 0'w = 0'w

Hence, O satisfies the property of additive homogeneity.

Preservation of the zero vector:

O(0v) = 0'w

Since the zero vector multiplied by any scalar is still the zero vector, O(0v) = O(0) = 0'w.

Therefore, O preserves the zero vector.

As O satisfies both properties, it can be concluded that O: V → W is a linear transformation.

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Answer:

p=1/2q-5/2r

x=(-10-z)/y

Step-by-step explanation:

2p+5r=q

2p=q-5r

p=1/2q-5/2r

-10=xy+z

-10-z=xy

(-10-z)/y=x

Answer:

I didnt know that and now that I do idc caus math is well y'know math -_-

Answer: 7,8,9

Step-by-step explanation: all the numbers between 6 and 10

Answer:

$54.6

Step-by-step explanation:

To solve the question, we need to find how much 5% of 52 is

For questions where we need to calculate the percentage, we will multiply the number by given percentage and then divide it by the whole, 100%

52*5/100 = 2.6

Now the price before the tax was 52 and the tax is 2.6

the total price:

2.6 + 52 = 54.6

Among the given options, the description that best fits a frequency table is "a grouping of qualitative data into classes showing the number of observations in each class."

The best description of a frequency table is: "A grouping of qualitative data into classes showing the number of observations in each class."

A frequency table is a statistical tool used to organize and summarize qualitative data by grouping it into classes or categories and displaying the number of observations or frequency in each class.

It provides a clear and concise representation of how the data is distributed across different categories.

In a frequency table, the qualitative data is organized into classes or categories, which are mutually exclusive and exhaustive.

Each class represents a range or a distinct category, and the frequency column displays the count or number of observations that fall within each class.

The frequencies can be absolute frequencies (counts) or relative frequencies (proportions or percentages).

The purpose of a frequency table is to provide a visual summary of the data distribution, allowing for easy identification of patterns, gaps, or outliers.

It helps to understand the frequency or occurrence of different values or categories in the dataset.

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By percentage, a passive home construction is typically around 50% more expensive compared to a conventional home construction.

A passive home construction is generally more expensive compared to a conventional home construction due to several factors. Passive homes are designed to meet stringent energy efficiency standards, requiring specialized materials, insulation, ventilation systems, and high-performance windows and doors. These energy-saving features contribute to the increased cost of construction. Additionally, passive homes often incorporate advanced technologies like heat recovery systems and solar panels, further adding to the expenses.

However, it's important to note that while the initial construction costs of a passive home may be higher, the long-term energy savings and reduced operating costs can offset the higher upfront investment. Passive homes offer improved energy efficiency, better indoor comfort, and reduced environmental impact, making them a viable choice for those seeking sustainable and energy-efficient housing solutions.

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Answer:

A: x/6+x/12=2

Step-by-step explanation:

I'm pretty sure this is right

Answer:

A

Step-by-step explanation:

The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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The value of the expression \(4\frac{1}{10}\times-4\times\frac{5}{12}\) is \(-6\frac{5}{6}\).

A mathematical statement expressed as a string of numbers and unknowable variables is known as a numerical expression. Statements can be used to create numerical expressions.

The given, expression is \(4\frac{1}{10}\times-4\times\frac{5}{12}\).

= (41/10) × (- 4) × (5/12).

= (41×-4×5)/(10×12).

= (-820/120).

= - 82/12.

= - 41/6.

= \(-6\frac{5}{6}\).

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Answer:

as expression your answer inside the bracket 10(5+3)

The equation resulting from Vineet's substitution in solving the system of equations is not provided, so it is not possible to give a direct answer.

To provide an explanation and calculation, we need the specific equations and the substitution made by Vineet. Without this information, it is not possible to proceed with the calculation or analysis.

Without the equation resulting from Vineet's substitution or the specific system of equations being solved, it is not possible to provide a detailed explanation or calculation. It is important to have the complete information in order to analyze Vineet's work accurately. If you can provide the specific equations and the substitution made, I would be happy to assist you further in explaining Vineet's process and reaching a conclusion.

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The forecasted registrations for years 2 through 12 using exponential

smoothing, with a smoothing constant (α) of 0 and a starting forecast of 4.00 for year 1 are:

Year | Forecasted registrations

------- | --------

2 | 4.00

3 | 4.00

4 | 4.00

5 | 4.00

6 | 4.00

7 | 4.00

8 | 4.00

9 | 4.00

10 | 4.00

11 | 4.00

12 | 4.00

Exponential smoothing is a forecasting method that uses past data to predict future values. The smoothing constant (α) determines how much weight is given to the most recent data. In this case, we are using a smoothing constant of 0, which means that all of the weight is given to the most recent data. This means that the forecasted registrations for all years will be the same as the starting forecast of 4.00.

Here is the formula for exponential smoothing:

```

Forecasted registrations = α * most recent data + (1 - α) * previous forecast

```

In this case, α = 0, so the formula becomes:

```

Forecasted registrations = most recent data

```

Since the most recent data is always 4.00, the forecasted registrations will always be 4.00.

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Answer:

(2,4)

Step-by-step explanation:

The expression is simplified to give 2(9x + 2√3x - 5)

First, we need to know that surds are mathematical forms that can no longer be simplified to smaller forms

From the information given, we have that;

(2√3x - 2)(3√3x + 5)

expand the bracket, we get;

6√9x² + 5(2√3x) - 6√3x - 10

Find the square root factor

6(3x)  + 10√3x - 6√3x - 10

collect the like terms, we have;

18x + 4√3x - 10

Factorize the expression, we have;

2(9x + 2√3x - 5)

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The significance level of 0.01 indicates that we want to use a 1% level of significance to evaluate the evidence against the null hypothesis.

The null and alternative hypotheses for testing the claim that the majority of college students' cell phone bills are paid by their parents can be stated as follows:

Null hypothesis (H0): The majority of college students' cell phone bills are not paid by their parents.

Alternative hypothesis (Ha): The majority of college students' cell phone bills are paid by their parents.

In this scenario, the null hypothesis assumes that the proportion of college students whose parents pay their cell phone bills is less than 50% (not a majority), while the alternative hypothesis suggests that the proportion is greater than or equal to 50% (a majority). The significance level of 0.01 indicates that we want to use a 1% level of significance to evaluate the evidence against the null hypothesis.

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There are three major forms of linear equations:

Point slope form:

The point-slope form, as its name suggests, identifies a point on a line and its slope. Not frequently is this form provided to assist with line graphing. To get from a verbal or visual representation of a line to its slope-intercept or standard form, however, is where it is more frequently utilized.

Slope intercept form:

A line's slope and y-intercept are communicated using the slope-intercept form. Technically speaking, it is an exception to the point-slope form.

Standard form:

An equation's conventional form is as follows:

Ax+By=C

Where A is not a negative number and B, C, and all three are whole numbers.

Hence we get the required answer.

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The exiting humidity is 45% and the amount of water passing is 0.0025 kg/h.

Calculating the required rate of heat transfer

The required rate of heat transfer can be calculated using the following equation:

Q = m * cp * (\(T_2\) - \(T_1\))

where:

Q is the rate of heat transfer (kW)

m is the mass flow rate of air (kg/s)

cp is the specific heat of air (kJ/kgK)

\(T_2\) is the final temperature of the air (K)

\(T_1\) is the initial temperature of the air (K)

In this case, we have:

m = 2.5 kg/s

cp = 1.005 kJ/kgK

\(T_2\) = 50°C + 273.15 = 323.15 K

\(T_1\) = 25°C + 273.15 = 298.15 K

Therefore, the required rate of heat transfer is:

Q = 2.5 * 1.005 * (323.15 - 298.15) = 6.31 kW

Calculating the amount of water added in an hour

The amount of water added in an hour can be calculated using the following equation:

\(m_w\) = m * (\(w_2\) - \(w_1\))

where:

\(m_w\) is the mass of water added (kg/h)

m is the mass flow rate of air (kg/s)

\(w_2\) is the final humidity ratio of the air (kg/kg)

\(w_1\) is the initial humidity ratio of the air (kg/kg)

In this case, we have:

m = 2.5 kg/s

\(w_2\) = 0.05 (50% humidity)

\(w_1\) = 0.035 (35% humidity)

Therefore, the amount of water added in an hour is:

\(m_w\) = 2.5 * (0.05 - 0.035) = 0.035 kg/h

Calculating the exiting humidity and the amount of water passing though the wicks per hour

The exiting humidity can be calculated using the following equation:

\(w_e\) = \(w_1\) * (\(T_2\) / \(T_1\))

where:

\(w_e\) is the exiting humidity ratio of the air (kg/kg)

\(w_1\) is the initial humidity ratio of the air (kg/kg)

\(T_2\) is the final temperature of the air (K)

\(T_1\) is the initial temperature of the air (K)

In this case, we have:

\(w_e\) = 0.035 * (50°C + 273.15) / (25°C + 273.15) = 0.045

The amount of water passing though the wicks per hour can be calculated using the following equation:

\(m_w\) = \(m_w\) * (\(w_e\) - \(w_2\))

where:

\(m_w\) is the amount of water added (kg/h)

\(w_e\) is the exiting humidity ratio of the air (kg/kg)

\(w_2\) is the final humidity ratio of the air (kg/kg)

In this case, we have:

\(m_w\) = 0.035 * (0.045 - 0.05) = 0.0025 kg/h

Therefore, the exiting humidity is 45% and the amount of water passing though the wicks per hour is 0.0025 kg/h.

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Therefore, when rounding to the nearest 2 decimal places, the correct rounded value for 3.25678 is 3.26.

To round 3.25678 to the nearest 2 decimal places, you would look at the third decimal place. If the digit in the third decimal place is 5 or greater, you round up the second decimal place. If the digit in the third decimal place is less than 5, you simply leave the second decimal place as it is. In this case, the digit in the third decimal place is 6, which is greater than 5.

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To round 3.25678 to the nearest 2 decimal places, we will round up as the third decimal place is greater than 5. The rounded value is 3.26.

To round 3.25678 to the nearest 2 decimal places, we will focus on the third decimal place. If the digit in the third decimal place is 5 or greater, we will round up. If the digit is less than 5, we will round down.

In this case, the digit in the third decimal place is 6, which is greater than 5. Therefore, we will round up the value. The rounded value to the nearest 2 decimal places is 3.26.

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The position of the mass in the undamped spring-mass system can be represented by the equation u(t) = (A cos(ωt) + B sin(ωt)) / k. Therefore, position of the mass at any time t in feet is given by u(t) = 4.5 cos(4t).

In this case, the external force acting on the system is 108 cos(4t) lb. To determine the position of the mass, we need to solve the differential equation that represents the motion of the system.

Using Newton's second law, F = ma, and considering that the mass m = 24 lb, the equation becomes:

24 * d^2u/dt^2 = 108 cos(4t)

Simplifying, we have:

d^2u/dt^2 = 4.5 cos(4t)

This is a second-order linear homogeneous differential equation with a constant coefficient. The solution to this equation will be a linear combination of the homogeneous and particular solutions.

The homogeneous solution, representing the free oscillation of the system, is u_h(t) = C1 cos(2t) + C2 sin(2t).

The particular solution, representing the forced motion caused by the external force, can be assumed in the form u_p(t) = A cos(4t) + B sin(4t).

By substituting u_p(t) into the differential equation, we can determine the values of A and B.

Solving the differential equation for the particular solution, we find:

A = 18 and B = 0

The complete solution for the position of the mass in feet is:

u(t) = (18 cos(4t)) / 4

Simplifying further, we get:

u(t) = 4.5 cos(4t)

Therefore, the position of the mass at any time t in feet is given by u(t) = 4.5 cos(4t).

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If the number of cups of water w, needed for f cups of flour is described by the equation w = 0.75f, 0.75 represents the number of cups of water needed for one cup of flour

The equation is

w = 0.75f

Where w is the number of cups waters needed for f cups of flour.

Here w is is dependent variable and f is the independent variable

We can see that w is proportional to the f, the 0.75 is the constant.

w = 0.75f

Move the f to left hand side of the equation

w/f = 0.75

Hence, If the number of cups of water w, needed for f cups of flour is described by the equation w = 0.75f, 0.75 represents the number of cups of water needed for one cup of flour

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The expression approximating the CDF P(Y ≤ x) in terms of µ, σ^2, and n is Φ((x - µ)/(σ/√n)), where Φ is the standard normal CDF.

The Central Limit Theorem (CLT) states that for a random sample of size n with a large enough sample size, the sample mean (Y) will be approximately normally distributed with mean µ and variance σ^2/n.

Using this information, we can approximate the cumulative distribution function (CDF) P(Y ≤ x) by transforming it into the standard normal CDF:

P(Y≤ x) ≈ P((Y - µ)/(σ/√n) ≤ (x - µ)/(σ/√n))

Let Z denote the standard normal random variable with mean 0 and variance 1. By standardizing the expression above, we can rewrite it as:

P(Y ≤ x) ≈ P(Z ≤ (x - µ)/(σ/√n))

Finally, we can use the standard normal CDF, denoted as Φ, to approximate the CDF:

P(Y ≤ x) ≈ Φ((x - µ)/(σ/√n))

Therefore, the expression approximating the CDF P(Y ≤ x) in terms of µ, σ^2, and n is Φ((x - µ)/(σ/√n)), where Φ is the standard normal CDF.

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Answer:

I cant tell you the answer but think of this formula.

Step-by-step explanation:

Answer:

C.

Step-by-step explanation:

The angle D. is acute

Answer:

X = -10

Step-by-step explanation:

2 = -8 -X

2+X = -8

X = -10

Answer:

x = - 10

Step-by-step explanation:

Comment

The trick to any equation like this one is to get the numbers on one side and the term with an unknown on the other side. That way, your last step is to divide by the number in front of the letter into a number on the other side.

Solution

2 = - 8 - x                                 Add 8 to both sides

2 + 8 = -8 + 8 - x                      Combine

10 = - x                                     The number in front of x is - 1. Divide.

10/-1 = -x/-1                        

-10 =x

The letter usually has to be expressed as a number greater than 0. In other words x is positive for this question

use distributive property

0.5 x -10 = -5

0.5 x k = 0.5k

0.5(-10 + k) = 0.5k -5

The probability that a point within the white circle lies on the red circle is P = 0.44

The probability will be given by the quotient between the area of the red square and the area of the circle.

On the diagram we can only see two squares, so Im assuming that it should say "square" instead of circle.

The area of the large square is:

A = 3*3 = 9

The area of the red square is:

A' = 2*2 = 4

Then the probability is:

P = 4/9 = 0.44

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