so if you take 60 by x and The sides of an octagon which is 8 you should have your answer
a rectangle has a length of 25x^3 and a width of 5x^2. Fkns the area.
Answer:
Step-by-step explanation:
I hope you want the area.
Area = L * W
L = 24x^3
W = 5x^2
Area = 24x^3 * 5x^2
Area = 120 * x^(3 + 2)
Area = 120 * x^5
Note
When you multiply numbers or letters that have powers, if the base for both of them is the same, the powers are added.
The above answer is an example x^2 * x ^3 are letters (x) that are raised to the 2nd power and the 3rd power. You add the powers.
Numbers can do the same thing
2^5 * 2^3 = 2^82*8 = 2562^5 = 642^3 = 864 * 8 = 256
Data where the difference between data values has meaning but there is no defined starting point
Examples of such data include stock prices, economic indicators, and meteorological data such as temperature, wind speed, and barometric pressure.
These types of data often have a trend or pattern, but the difference between the data points has meaning and does not necessarily have a defined starting point.
1. Data where the difference between data values has meaning but there is no defined starting point can be defined as data that is not linearly dependent.
2. Examples of such data include stock prices, economic indicators, and meteorological data. These types of data often have a trend or pattern, but the difference between the data points has meaning and does not necessarily have a defined starting point.
3. Stock prices, economic indicators, and meteorological data all have different scales and can move in different directions, making it difficult to track the exact difference between data points.
4. Despite this, these types of data still allow for meaningful analysis and can be used to make predictions and draw conclusions.
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Carol rolled a dice 150 times she rolled a six 29 times
Use carols data to estimate the probability of rolling a six with this dice
Give your answer as a fraction
Answer:
If Carol rolled a six 29 times in total (out of the 150 dice rolls) then the fraction would be 29/150
Step-by-step explanation: I think
During a "big air competition, snowboarders launch themselves from a half-pipe, perform tricks in the air, and land back in the half-pipe. The height / (in feet) of a
snowboarder above the bottom of the half-pipe can be modeled by h=-16t^2+24t + 16.4, where t is the time (in seconds) after the snowboarder launches into the air. The snowboard
lands 3.2 feet lower than the height of the launch. About how long is the snowboarder in the air?
For 2 sec the snowboarder in the air.
We have,
The height (in feet) of a snowboarder above the bottom of the half-pipe can be modeled by h=-16t²+24t + 16.4
So, 3.2 = -16t² + 24t + 16.4
-16t² + 24t + 12.4 = 0
Now, solving the above quadratic equation we get
t = -0.40650, 1.90650
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Graph the equation and tell whether it is linear. y=1/5 x
Answer:
This is a linear equation.
Graph the points (-10, -2), (0, 0), and (10, 2). Then draw a line through all three points.
If 6 times the 6th term of an A.P., is equal to 9 times the 9th term, find its 15th term
As per arithmetic progression the value of 15th term is 0.
An arithmetic progression, or A.P., is a sequence of numbers in which the difference between consecutive terms is constant.
To start, let's call the common difference "d" and the first term "a". We can use the formula for the nth term of an A.P., which is Tn = a + (n-1)d, where Tn is the nth term and n is the position of the term in the A.P.
Using this formula, we can find the 6th term and 9th term. For the 6th term, T6 = a + (6-1)d = a + 5d. For the 9th term, T9 = a + (9-1)d = a + 8d.
Now, using the information given, we can create an equation: 6(a + 5d) = 9(a + 8d). Expanding both sides and simplifying, we get:
6a + 30d = 9a + 72d
Subtracting 9a from both sides, we get:
-3a + 30d = 72d
Subtracting 30d from both sides, we get:
-3a = 42d
Dividing both sides by -3, we get:
a = -14d
Now that we have found the value of "a", we can use the formula for the nth term again to find the 15th term. T15 = a + (15-1)d = -14d + 14d = 0.
So, the 15th term of the A.P. is 0.
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Obtaining Information about the Graph of a function 1. Consider the function f(x)=x+1/ x+2 a) is the point (1,1/2 ) on the graph of ?? b) If x=2, what in f(x) ? What point is on the graph of 1? c) If f(x)=2, what is x ? What point is on the graph of t ? d) What are the x-intercepts of the graph? What points are on the graph? e) What is the y-intercept of the graph? What point is on the graph?
Answer:
a) To determine if the point (1, 1/2) is on the graph of the function f(x) = x+1 / x+2, we can substitute x = 1 into the function to check if we get y = 1/2.
f(1) = (1+1) / (1+2) = 2/3
Since f(1) is not equal to 1/2, the point (1, 1/2) is not on the graph of the function f(x) = x+1 / x+2.
b) To find f(2), we can substitute x = 2 into the function.
f(2) = (2+1) / (2+2) = 3/4
So, if x = 2, the point on the graph of f(x) would be (2, 3/4).
c) To find the value of x when f(x) = 2, we can set the function equal to 2 and solve for x.
2 = x+1 / x+2
Multiplying both sides by x+2 gives:
2x + 4 = x + 1
Simplifying gives:
x = -3
So, if f(x) = 2, the point on the graph of f(x) would be (-3, 2).
d) To find the x-intercepts of the graph, we can set y equal to zero and solve for x.
0 = x+1 / x+2
Multiplying both sides by x+2 gives:
0 = x + 1
Simplifying gives:
x = -1
So, the x-intercept of the graph is (-1, 0).
e) To find the y-intercept of the graph, we can set x equal to zero and evaluate the function.
f(0) = (0+1) / (0+2) = 1/2
So, the y-intercept of the graph is (0, 1/2).
Step-by-step explanation:
A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then stretched an additional 1 inch and released. Find the equation of motion, the amplitude, and the period. Neglect friction. Then y(t) = cos(sqrt(100/(1/32)*t) where t is time in (seconds) and y(t) is displacement (in feet). Hint: Be careful about units here. In particular, remember that the pound is a unit of force. You will need to use the fact that gravitational acceleration is 32 ft/s? in order to convert to units of mass. Amplitude: __ inch(es) Period: ___ second(s).
First, we need to convert the given weight to mass. Since we know that gravitational acceleration is 32 ft/s² and the weight is 1 pound, we can calculate the mass.
Weight = Mass × Gravitational acceleration
1 lb = Mass × 32 ft/s²
Mass = 1 lb / 32 ft/s² = 1/32 slugs
Now, we need to find the angular frequency (ω) using the formula ω = sqrt(k/m):
ω = sqrt(100 lb/ft / (1/32 slugs)) = sqrt(3200) = 40 rad/s
The equation of motion will be:
y(t) = A * cos(ωt)
Since the spring is stretched an additional 1 inch (1/12 ft), that will be the amplitude (A): Amplitude = 1/12 ft
Now we can write the complete equation of motion:
y(t) = (1/12) * cos(40t)
In conclusion: Amplitude: 1 inch (1/12 ft)
Period: π/20 seconds
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How can we write 1.25+1.25 +1.25 as a multiplication, using words, and as a single number? Make sure you answer all three parts of this question.
Answer:
1) 1.25*3
2) 1.25 multiplied by 3
3) 3.75
Step-by-step explanation:
helppppp please i tont get these answers will get brainly i swear
Answer:15-A
Step-by-step explanation:
Suppose that a person regards ham and cheese as pure complements—he or she will always use one slice of ham in combination with one slice of cheese to make a ham and cheese sandwich. Suppose also that ham and cheese are the only goods that this person buys and that bread is free.
a. If the price of ham is equal to the price of cheese, show that the own-price elasticity of demand for ham is _0.5 and that the cross-price elasticity of demand for ham with respect to the price of cheese is also _0.5.
b. Explain why the results from part (a) reflect only income effects, not substitution effects. What are the compensated price elasticities in this problem?
c. Use the results from part (b) to show how your answers to part (a) would change if a slice of ham cost twice the price of a slice of cheese.
d. Explain how this problem could be solved intuitively by assuming this person consumes only one good—a ham and cheese sandwich.
When ham and cheese are regarded as natural complements and the charges of ham and cheese are the same, the very own-price elasticity of demand for ham and the cross-price elasticity of demand for ham with recognition to the rate of cheese are each 0.5. These elasticity measures reflect profits outcomes and now not substitution effects.
A. Given that ham and cheese are natural complements and the person always makes use of one slice of every to make a sandwich, the demand for ham is at once dependent on the charge of cheese. Therefore, we will determine the own-charge elasticity of the call for ham and the cross-charge elasticity of the call for ham with recognition of the rate of cheese.
Let's denote the price of ham as Ph and the rate of cheese as Pc. The call for a feature for ham may be expressed as Qh = f(Pc), in which Qh is the amount of ham demanded.
The own-fee elasticity of demand for ham (εh) is given through the system:
εh = (%ΔQh) / (%ΔPh)
Since Ph = Pc (the expenses of ham and cheese are identical), the percentage exchange in Ph and Pc can be the same. Therefore, the denominator of the pliancy system will cancel out, ensuing in εh = (%ΔQh) / (%ΔPc).
Given that ham and cheese are naturally enhanced and always eaten up collectively, the percentage alternate in the quantity demanded of ham (%ΔQh) could be the same as the percentage change inside the fee of cheese (%ΔPc). This means that εh = 1.
Similarly, the cross-charge elasticity of demand for ham with appreciate to the fee of cheese (εhc) can be calculated using the formulation:
εhc = (%ΔQh) / (%ΔPc)
Since Ph = Pc, the proportion alternate in Ph and Pc could be equal, ensuing in εhc = (%ΔQh) / (%ΔPc) = 1.
Thus, the very own-fee elasticity of the call for ham is 0.5, and the pass-fee elasticity of demand for ham with recognition of the price of cheese is also 0.5.
B. The results from element (a) reflect the most effective earnings outcomes because the charges of ham and cheese are assumed to be the same. Therefore, any changes in the quantity demanded of ham are complete because of changes in income, now not substitution outcomes.
Compensated fee elasticities bear in mind each income and substitution outcome and might provide greater comprehensive expertise on the responsiveness of demand to charge adjustments in this situation.
C. If a slice of ham fees twice the rate of a slice of cheese, the charges of ham and cheese are now not identical. Let's denote the brand-new rate of ham as Ph' = 2Pc. The personal-fee elasticity of demand for ham (εh') and the pass-price elasticity of call for ham with appreciation to the charge of cheese (εhc') can be calculated with the use of the equal formulas as in element (a).
εh' = (%ΔQh) / (%ΔPh') = (%ΔQh) / (%Δ(2Pc)) = 0.5
εhc' = (%ΔQh) / (%ΔPc) = (%ΔQh) / (%ΔPc) = 0.5
Thus, in spite of the change in costs, the personal-rate elasticity of demand for ham and the go-charge elasticity of demand for ham with admiration to the price of cheese remain at 0.5.
D. From an intuitive standpoint, if the individual consumes only one accurate—a ham and cheese sandwich—their demand for ham may be constant. Regardless of the charge of ham or cheese, the individual will usually consume one slice of ham with one slice of cheese to make a sandwich.
This simplification gets rid of the want to not forget elasticity measures and reflects a regular demand for ham because of the complementary relationship between ham and cheese inside the sandwich.
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a. The own-price elasticity of demand for ham is 0.
The cross-price elasticity of demand for ham with respect to the price of cheese is also 0.
b. The compensated price elasticities in this problem would be equal to zero because the person's consumption of ham and cheese is fixed and does not change with the price of ham or cheese.
c. The own-price elasticity of demand for ham would still be 0 and the cross-price elasticity of demand for ham with respect to the price of cheese would still be 0.
d. The person's demand for ham and cheese is perfectly inelastic, and the own-price elasticity of demand for ham is 0.
a. The own-price elasticity of demand measures the responsiveness of the quantity demanded of a good to a change in its own price.
In this case, since ham and cheese are pure complements, the person always uses one slice of ham in combination with one slice of cheese to make a ham and cheese sandwich.
Therefore, if the price of ham is equal to the price of cheese, a change in the price of ham will not affect the quantity demanded of ham because the person will still need one slice of ham for each slice of cheese.
This means that the own-price elasticity of demand for ham is 0.
The cross-price elasticity of demand measures the responsiveness of the quantity demanded of one good to a change in the price of another good.
In this case, since ham and cheese are pure complements, the person will always buy one slice of ham and one slice of cheese together.
Therefore, if the price of cheese changes, the person will still buy the same quantity of ham because they need one slice of ham for each slice of cheese.
This means that the cross-price elasticity of demand for ham with respect to the price of cheese is also 0.
b. The results from part (a) reflect only income effects and not substitution effects because the person's consumption of ham and cheese is fixed and does not change with the price of ham or cheese.
The person will always buy one slice of ham and one slice of cheese together, regardless of their prices.
The compensated price elasticities in this problem would be equal to zero because the person's consumption of ham and cheese is fixed and does not change with the price of ham or cheese.
c. If a slice of ham costs twice the price of a slice of cheese, the person's consumption of ham and cheese would remain the same.
The person will still buy one slice of ham and one slice of cheese together, regardless of their prices.
Therefore, the own-price elasticity of demand for ham would still be 0 and the cross-price elasticity of demand for ham with respect to the price of cheese would still be 0.
d. This problem can be solved intuitively by assuming that the person consumes only one good - a ham and cheese sandwich.
Since the person always uses one slice of ham in combination with one slice of cheese to make a sandwich, the price of ham and cheese will not affect the person's consumption decision.
Therefore, the person's demand for ham and cheese is perfectly inelastic, and the own-price elasticity of demand for ham is 0.
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Put the following equation of a line into slope-intercept form, simplifying all
fractions. I
42 + 3y = -6
Answer:
The solution not in slope intercept is -16. Slope intercept isn't working for me.
Step-by-step explanation:
Need help with number 8 and 9
Answer:
45° and 12
Step-by-step explanation:
The sum of the exterior angles of a polygon = 360°
(8)
The polygon has n = 8, that is 8 exterior angles, thus
exterior angle = 360° ÷ 8 = 45°
(9)
The number of sides n is
n = 360 ÷ 30 = 12
Answer:
45° 12 sides
Step-by-step explanation:
1) Every polygons interior angles is equal to 180 times two less than the amount of sides it has (i.e 180•(4-2)=360:quadrilateral) So applying that here we have eight sides so 180(8-2)=1080. Now divide that by 8 to get the measure of one angle and subtract it from 180 to get the exterior angle 45°
2) if the exterior angle is 30° then the interior angle is 150°. For this part i guess and checked but you can refer to the equation above. (180(x-2)=y/150)
consider the sequence of numbers: $4$, $7$, $1$, $8$, $9$, $7$, $6$, $\ldots$. for $n>2$, the $n$th term of the sequence is the units digit of the sum of the two previous terms. let $s n$ denote the sum of the first $n$ terms of this sequence. what is $s {100}?$
The sum of the first 100 terms of the sequence is $620$.
\($s_3 = 4 + 7 = 11$\)
\($s_4 = 11 + 1 = 12$\)
\($s_5 = 12 + 8 = 20$\)
\($s_6 = 20 + 9 = 29$\)
\($s_7 = 29 + 7 = 36$\)
\($s_8 = 36 + 6 = 42$\)
\($s_9 = 42 + 4 = 46$\)
\($s_{10} = 46 + 7 = 53$\)
\($s_{100} = 620$\)
The given sequence is 4, 7, 1, 8, 9, 7, 6 and so on. The nth term of the sequence is the units digit of the sum of the two previous terms. To find the sum of the first 100 terms, we need to calculate the sum of the first two terms, 4 and 7. This is 11. The next term is the units digit of 11, 1. The sum of the first three terms is 12. The next term is the units digit of 12, which is 2. This process is repeated until we reach the 100th term. The sum of the first 100 terms is 620.
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Please help me. Thank you.
Answer:
B: 2x= -14
Step-by-step explanation:
180° is max for a triangle so subtract the given angle. 180- 84 is 96. the equation you get left with is 96= x + 59 + x + 51, which can become 2x + 110=96. Subtract 110 from 96 to get 2x by itself, which is now -14.
Sketch a graph showing the solution to each system.If you can't do both then do Question C.
(C)
Given data:
The given inequalities.
The graph of the given inequalities is shown below.
You have $6.44 to spend on easter sweets You buy 1 chocolate bunny for $2.19 and 1 chocolate egg for $1.83. with the money left , which flower could you buy? the daisy costs $2.35 and the rose costs $2.55.
Answer:
DAISY
Step-by-step explanation:
6.44-2.19-1.83=2.42.
You can buy the DAISY
(in the nonstatistical term, you can tell that it could be the daisy because if you had 2.55 you could buy both)
Daisy
Step-by-step explanation:
$6.44 - $2.19 = $4.25 $4.25 - $1.83 = $2.42
You only have $2.42 left. Daisy cost $2.35 and Rose cost $2.55
4k + 12 = 52
using algbra
Answer:
k=10
Step-by-step explanation:
4k + 12= 52
minus 12 on both sides
4k=40
now divide by 4
k=10
Help Me! ASAP! I'll Mark The Brainliest! Ernesto brings his dog to training classes. the equation -60x+2y-120=0 relates y the total. cost of a pets training and x, the number of classes taken. Ernesto states that the y-intercerpt of the line represented by the equation is 30. Is he correct? Explain your reasoning.
Answer:
ok put into y=mx+b form
2y=60x+120
y=30x+60
so we know 60 is the y-intercept so he is not correct
if u want more:
-60x+2y-120=0 add 60x
2y-120=60x add 120
2y=60x+120 divide by 2
y=30x+60
Hope this helps plz hit the crown :D
it shows also that the barn will be used as part of the fencing on one side. find the largest area that can be enclosed if 88 feet of fencing material is available
The largest area that can be enclosed if 88 feet of fencing material is available is 484 feet².
Given, a barn has a perimeter of 88 feet.
Now, the perimeter of the rectangle i.e. Barn is 88 feet.
Perimeter = 2(l + b)
88 = 2(l + b)
l + b = 44
b = 44 - l
Now, area = l × b
Area = l × (44 - l)
Area = 44l - l²
On differentiating both the sides, we get
A' = 44 - 2l
On putting A' = 0
44 - 2l = 0
l = 22
Now, for l = 22 the area will be the largest.
if l = 22
then, 22 + b = 44
b = 22
So, the largest area will be 22×22 = 484
Hence, the largest area that can be enclosed if 88 feet of fencing material is available is 484 feet².
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An object of mass 30 kg is in free fall in a vacuum where there is no air resistance. Determine
the acceleration of the object.
Answer:
a= g=9.81 m/s square
Mass given to us = 30 kg
Therefore we have to find the acceleration of the object,
As there is no air and mass is irrelevant in free fall, the acceleration the object experiences will be equal to the force of gravity. On our planet, the gravitational pull on an item falling there is approximately:
9.81 m/s square.
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There are 20 pens in a package. Ten of the pens are black, 8 are blue, and the rest are red.
Which ratio represents the number of red pens to black pens?
A: 1/10
B: 1/5
C: 4/5
D: 5/1
What is the name of the segment inside the large triangle?
1. Perpendicular bisector
2.Midsegment
3.Angle Bisector
4.Median
The name of the segment inside the large triangle is called the: 3. angle bisector.
What is an Angle Bisector?The word "bisect" means to divide into two equal halves. Therefore, an angle bisector can be defined as a line segment that divides the an angle in a triangle into two parts that are of the same angle measure.
The image shows a triangle which has a segment that divides a vertex angle into equal parts. Thus, the segment can be named as an angle bisector.
A perpendicular bisector divides a segment into two equal halves at right angle, while a midsegment joins the middle points of two sides of a triangle. The median also, is a segment that joins a vertex of a triangle to the midpoint of the side that is opposite the angle.
Therefore, we can state that the name of the segment is: 3. angle bisector.
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calculate the coefficient of variation for a sample of cereal boxes with a mean weight of 340 grams and a standard deviation of 5.2 grams.? 0.15% A
1.53% B
15.29% C
0.65% D
The coefficient of variation (CV) is a measure of relative variability and is calculated by dividing the standard deviation by the mean, and then multiplying by 100 to express it as a percentage.
In this case, the mean weight is 340 grams, and the standard deviation is 5.2 grams.
CV = (Standard Deviation / Mean) * 100
CV = (5.2 / 340) * 100
CV ≈ 1.53%
Therefore, the correct answer is option B: 1.53%.
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URGENT PLS IM DESPERATE!!! IT'S DUE IN 35 MINUTES!!! Write an equation for each table, graph, and verbal description. (A) Table of X and Y values. When X is 1, Y is 9. When X is 2, Y is eighteen. When X is 3, Y is twenty-seven. When X is 4, Y is thirty-six. y = x (B) First quadrant of a coordinate plane. The points 0 comma 0, 2 comma 5, 4 comma ten, 6 comma fifteen, 8 comma twenty, and ten comma twenty-five are graphed and connected with a line. y = x (C) Each hour, Milo reads 24 pages. y = x
Your answer will be:
y = 9x
y = 2.5x
y = 24x
I hope this helps!
A perpetuity immediate has annual payments of 1, 3, 5, 7, 9, 11,……..
If the interest rate is 10% for the first 10 years and 5% after that,
a) Write down the 12 payments for the first 12 years
b) Give an actuarial expression for the present value of the perpetuity. No need for
calculation here but be sure to indicate the interest rate for any terms you use.
a) Year 1: 1.00,Year 2: 1.10,Year 3: 1.21,Year 4: 1.33,Year 5: 1.46, Year 6: 1.60, Year 7: 1.76, Year 8: 1.94, Year 9: 2.13 ,Year 10: 2.34, Year 11: 2.46, Year 12: 2.59.
b) The actuarial expression for the present value of the perpetuity immediate can be written as:
\(PV = (1/0.10) \times [1 - (1/1.10^{10})] + (1/0.05) \times [1/1.10^{10}] \times [1 - (1/1.05^∞)]\)
a) The first 12 payments for the perpetuity immediate with annual payments of 1, 3, 5, 7, 9, 11,……. and interest rate of 10% for the first 10 years and 5% after that are:
Year 1: 1.00
Year 2: 1.10
Year 3: 1.21
Year 4: 1.33
Year 5: 1.46
Year 6: 1.60
Year 7: 1.76
Year 8: 1.94
Year 9: 2.13
Year 10: 2.34
Year 11: 2.46
Year 12: 2.59
b) The actuarial expression for the present value of the perpetuity immediate can be written as:
\(PV = (1/0.10) \times [1 - (1/1.10^{10})] + (1/0.05) \times [1/1.10^{10}] \times [1 - (1/1.05^∞)]\)
where PV is the present value of the perpetuity, 0.10 is the interest rate for the first 10 years, 0.05 is the interest rate
after the first 10 years, and ∞ represents infinity (i.e., the perpetuity continues forever).
This formula takes into account the different interest rates for the two periods and discounts the future payments to
their present value.
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Using the number line shown, place a point at 4 and the opposite of 4 . Place a point at −2 and at the opposite of −2 . Place a point at 0 . For parts (b) and (c), type each answer in the box below. b. Explain why the opposite of a positive number will always be a negative number. c. Explain why zero is its own opposite number.
Answer:
1/4
Step-by-step explanation:
2d²y/dx² + yd²y/dx² = 0, dy/dx at x = 0 = 0, dy/dx at x = infinite = 1, dy/dx at x = 5 = 0.99 d²z/dx² + k/2y dz/dx = 0 z(0) = 0 and z(infinite) = 1 k is just a constant. Solve the differential equations with boundary conditions. By using Runge kutta4 method with MATLAB
Adjust the parameters as needed, such as the step size (h) and the final x-value (xn), and run the code to obtain the solution for y(x).
The resulting plot will show the solution curve.
To solve the given set of differential equations using the Runge-Kutta method in MATLAB, we need to convert the second-order differential equations into a system of first-order differential equations.
Let's define new variables:
y = y(x)
z = dz/dx
Now, we have the following system of first-order differential equations:
dy/dx = z (1)
dz/dx = -k/(2y) (2)
To apply the Runge-Kutta method, we need to discretize the domain of x. Let's assume a step size h for the discretization. We'll start at x = 0 and proceed until x = infinite.
The general formula for the fourth-order Runge-Kutta method is as follows:
k₁ = h f(xn, yn, zn)
k₂ = h f(xn + h/2, yn + k₁/2, zn + l₁/2)
k₃ = h f(xn + h/2, yn + k₂/2, zn + l₂/2)
k₄ = h f(xn + h, yn + k₃, zn + l₃)
yn+1 = yn + (k₁ + 2k₂ + 2k₃ + k₄)/6
zn+1 = zn + (l₁ + 2l₂ + 2l₃ + l₄)/6
where f(x, y, z) represents the right-hand side of equations (1) and (2).
We can now write the MATLAB code to solve the differential equations using the Runge-Kutta method:
function [x, y, z] = rungeKuttaMethod()
% Parameters
k = 1; % Constant k
h = 0.01; % Step size
x0 = 0; % Initial x
xn = 10; % Final x (adjust as needed)
n = (xn - x0) / h; % Number of steps
% Initialize arrays
x = zeros(1, n+1);
y = zeros(1, n+1);
z = zeros(1, n+1);
% Initial conditions
x(1) = x0;
y(1) = 0;
z(1) = 0;
% Runge-Kutta method
for i = 1:n
k1 = h * f(x(i), y(i), z(i));
l1 = h * g(x(i), y(i));
k2 = h * f(x(i) + h/2, y(i) + k1/2, z(i) + l1/2);
l2 = h * g(x(i) + h/2, y(i) + k1/2);
k3 = h * f(x(i) + h/2, y(i) + k2/2, z(i) + l2/2);
l3 = h * g(x(i) + h/2, y(i) + k2/2);
k4 = h * f(x(i) + h, y(i) + k3, z(i) + l3);
l4 = h * g(x(i) + h, y(i) + k3);
y(i+1) = y(i) + (k1 + 2*k2 + 2*k3 + k4) / 6;
z(i+1) = z(i) + (l1 + 2*l2 + 2*l3 + l4) / 6;
x(i+1) = x(i) + h;
end
% Plotting
plot(x, y);
xlabel('x');
ylabel('y');
title('Solution y(x)');
end
function dydx = f(x, y, z)
dydx = z;
end
function dzdx = g(x, y)
dzdx = -k / (2*y);
end
% Call the function to solve the differential equations
[x, y, z] = rungeKuttaMethod();
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Can someone help me with this
Answer:
use system of equations
Step-by-step explanation:
Set one up for the Smith family and one for the Jones family
Which of the following is not a condition to check when doing atwo-sample z-test of proportions?
A.
The samples are independent of each other and independent within samples
B.
The sample are random
C.
The samples are sufficiently large
D.
All of the above conditions are important conditions to check
Option D is not a condition to check when doing a two-sample z-test of proportions.
The correct option is D. All of the above conditions are important conditions to check when doing a two-sample z-test of proportions.
The two-sample z-test of proportions is a statistical test that is used to compare the proportion of two populations.
This statistical test helps in determining whether or not there is a significant difference between the two proportions.
The following are the conditions to check when doing a two-sample z-test of proportions:The samples are independent of each other and independent within samples.
The sample is random.
The samples are sufficiently large.
Therefore, the given statement "All of the above conditions are important conditions to check when doing a two-sample z-test of proportions" is correct.
In conclusion, option D is not a condition to check when doing a two-sample z-test of proportions.
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