What is the area of the shaded region?
(25/1 - 48) cm
(2571 - 30) cm
(2572 - 24) cm
(2571 – 12) cm2

Answer:

Step-by-step explanation:

15+5x=20x

   -5x  -5x  => Subtract 5x from each side

You get

15 = 15x

Divide both sides by 15

1=x

Answer:

11 1/2 years old

Step-by-step explanation:

Let Amanda's age be a.

Let the company's age be c.

The company is 24 years older than Amanda. This means that:

c = 24 + a ______(1)

The sum of Amanda's age and the company's age is 121 years. This means that:

c + a = 121 ________(2)

Put (1) in (2):

24 + a + a = 121

2a = 121 - 24

2a = 97

a = 97 / 2 = 48 1/2 years

She has been there for 37 years, therefore, her age when she started working there is:

48 1/2 - 37 = 11 1/2 years old

NOTE: This age doesn't seem right but I worked based on the parameters given.

ANSWER:

STEP-BY-STEP EXPLANATION:

Let C be the number of medals from Canada and N the number of medals from Norway, the algebraic expression would be:

Answer:

0.902 = 90.2% probability that the flight would leave on time when it is not raining

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

\(P(B|A) = \frac{P(A \cap B)}{P(A)}\)

In which

P(B|A) is the probability of event B happening, given that A happened.

\(P(A \cap B)\) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Not raining

Event B: Flight leaving on time.

The probability that it will rain is  0.18.

This means that there is a 1 - 0.18 = 0.82 probability of not raining. So \(P(A) = 0.82\)

The probability that it  will not rain and the flight will leave on time is 0.74.

This means that \(P(A \cap B) = 0.74\)

What is the probability that the  flight would leave on time when it is not raining?

\(P(B|A) = \frac{0.74}{0.82} = 0.902\)

0.902 = 90.2% probability that the flight would leave on time when it is not raining

The annualized return for the entire period is the closest to 10.5%.

To calculate the annualized return for the entire period, we need to consider the returns for each year and the return in the first quarter of Year 4. Since the returns are given for each period, we can use the geometric mean to calculate the annualized return.

The formula for calculating the geometric mean return is:

Geometric Mean Return = [(1 + R1) * (1 + R2) * (1 + R3) * (1 + R4)]^(1/n) - 1

Where R1, R2, R3, and R4 are the returns for each respective period, and n is the number of periods.

Given the returns:

Year 1 return: 5% or 0.05

Year 2 return: 12% or 0.12

Year 3 return: -6% or -0.06

First quarter of Year 4 return: 2% or 0.02

Using the formula, we can calculate the annualized return:

Annualized Return = [(1 + 0.05) * (1 + 0.12) * (1 - 0.06) * (1 + 0.02)]^(1/3) - 1

Annualized Return = (1.05 * 1.12 * 0.94 * 1.02)^(1/3) - 1

Annualized Return = 1.121485^(1/3) - 1

Annualized Return ≈ 0.105 or 10.5%

Therefore, the annualized return for the entire period is approximately 10.5%.

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Answer:

Доброе утро, отвеT           2.8 B

Step-by-step explanation:

Answer:

(89.2 - 92.4) ± 1.666*√(3.1²/38 + 3.8²/37)

Step-by-step explanation:

Very clear deck :

n1 = 38

x1 = 89.2

s1 = 3.1

Sure seal

n2 = 37

x2 = 92.4

s2 = 3.8

Confidence interval for difference in sample means :

(X1 - X2) ± margin of error

(X1 - X2) ± Tcritical * sqrt(s1²/n1 + s2²/n2))

Using the degree of freedom calculator ; df = 70

Margin of Error : Tcritical * sqrt(s1²/n1 + s2²/n2))

Tcritical at 90% confidence interval, df = 70 = 1.688

Margin of Error = 1.666 * sqrt(3.1²/38 + 3.8²/37)

Confidence interval :

(89.2 - 92.4) ± 1.666*√(3.1²/38 + 3.8²/37)

Answer:

0, 14

Step-by-step explanation:

-2, is 8 away from 6, so you add 8 to 6 to reflect it and get 14

The limit of the function as x approaches -2 is 20.To find the limit of the function (if it exists), we can substitute the given value into the function and simplify. Given function: f(x) = 4x² + 5x - 6x + 2

To find the limit as x approaches -2, we substitute -2 into the function:

f(-2) = 4(-2)² + 5(-2) - 6(-2) + 2
      = 4(4) - 10 + 12 + 2
      = 16 - 10 + 12 + 2
      = 20

Therefore, the limit of the function as x approaches -2 is 20.

To write a simpler function that agrees with the given function at all but one point, we can use a graphing utility. By plotting the given function and observing its behavior, we can create a simpler function that matches the original function except at one point.

However, without further information about the specific behavior of the given function, it is not possible to provide a more detailed explanation or a graph of the simpler function.

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Answer:

a. 5/17

b.12/17

c.0/17

d.17/17

Step-by-step explanation:

Answer:

-3 is the answer of this question

Answer:

(a)-3

Step-by-step explanation:

\(5 - 8x = 29 \\ - 8x = 29 - 5 \\ - 8x = 24 \\ x = \frac{24}{ - 8} \\ x = - 3\)

Option(B) is the correct answer. The answer is - Adding data from a student who is 154 cm tall and weighs 69kg.

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Answer:

The answer is 729

Step-by-step explanation:

to get the next term, the sequence multiples the previous number by -3

1 * -3 = -3

-3 * -3 = 9

and so on.

To get the 7th term:

-27 * -3 = 81 (5th term)

81 * -3 = -243 (6th)

-243 * -3 = 729 (7th)

Answer:

The seventh term in the sequence is -729.

Step-by-step explanation:

Notice that the sequence is not increasing linearly. Therefore, this is a geometric sequence.

Recall that the explicit formula for a geometric sequence is given by:

\(x_n=a(r)^{n-1}\)

Where a is the first term, r is the common ratio, and n denotes the nth term.

From the sequence, we can see that our first term a is -1.

Because each term is thrice the previous, our common ratio r is 3.

By substitution:

\(x_n=-(3)^{n-1}\)

Hence, the seventh term is:

\(\displaystyle \begin{aligned} x_7 & = -(3)^{(7)-1} \\ \\ & = -(3)^{6} \\ \\ & = -729\end{aligned}\)

In conclusion, the seventh term is -729.

Answer:

should be 41.5 lbs

Step-by-step explanation:

multiply 8.3 by 5

8.3×5= 41.5

Answer:

  see attached

Step-by-step explanation:

When the signs of the x^2 and y^2 terms of a relation quadratic in both x and y are different, the relation represents a hyperbola. The graph of the hyperbola is shown in the attachment.

__

If the signs are the same, the relation represents an ellipse. If the coefficients of the squared terms are also the same, then that ellipse is a circle.

Answer:

104.6

Step-by-step explanation:

I rounded the product to the nearest tenth

The equation of a circle that is congruent to circle C and is centered at point P is (x - 5)² + (y - 1)² = 5².

In Geometry, the standard form of the equation of a circle is modeled by this mathematical equation;

(x - h)² + (y - k)² = r²

Where:

Based on the information provided, we have the following parameters for the equation of this circle:

By substituting the given parameters, we have:

(x - h)² + (y - k)² = r²

(x - 5)² + (y - 1)² = 5²

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The scale factor that was used to convert triangle ABC into the image in A ' B ' C ' is 1 / 2.

To find the scale factor, you need to find the length of a side of triangle ABC and then the length of the corresponding side in A ' B ' C '.

The side length we will pick is AB which is:

= 6 - 2

= 4 units

The side length of the other triangle is A' B' :

= 3 - 1

= 2 units

The scale factor is:

= 2 / 4

= 1 / 2

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Answer:

gh1

Step-by-step explanation:

19 is prime and 29 is not divisible by 19 therefore 1g is the highest. 5 and 3 are both prime so again, 1h and finally, 5 is a prime number so gh1 is the greatest factor

Answer:

12.

Step-by-step explanation:

if to re-write the given condition, then

\(\frac{3}{0.25} =\frac{18}{1.5} =\frac{30}{2.5} =\frac{36}{3} ;\)

it is clear, the required constant is 12 (12 per hour).

Answer:

C)  Domain:  all real numbers x except x = ±2

E)  f(x) → ∞ as x → -2⁻ and as x → 2⁺, f(x) → -∞ as x → -2⁺ and as x → 2⁻

Step-by-step explanation:

Given function:

\(f(x)=\dfrac{3x^2}{x^2-4}\)

The domain of a function is the set of all possible input values (x-values).

A rational function is undefined when the denominator is equal to zero.

The denominator of the given function is zero when:

\(\implies x^2-4=0\)

\(\implies x^2=4\)

\(\implies \sqrt{x^2}=\sqrt{4}\)

\(\implies x= \pm 2\)

Therefore the domain of the function is:

The excluded x-values are x = -2 and x = 2.

To find the behaviour of the function near the excluded x-values, input values of x that are very near either side of excluded values:

\(x \rightarrow -2^-: \quad f(-2.001)=\dfrac{3(-2.001)^2}{(-2.001)^2-4}=3002.250...\)

\(x \rightarrow -2^+: \quad f(-1.999)=\dfrac{3(-1.999)^2}{(-1.999)^2-4}=-2997,750...\)

\(x \rightarrow 2^-: \quad f(1.999)=\dfrac{3(1.999)^2}{(1.999)^2-4}=-2997.750...\)

\(x \rightarrow -2^+: \quad f(2.001)=\dfrac{3(2.001)^2}{(2.001)^2-4}=3002.250...\)

Therefore, the behaviour of the function near the excluded x-values:

Answer:

the value of 8 in the first one is 8

in the second one is 80

Answer:

who asked

Step-by-step explanation:

The best measure of variability for this data is the range, and its value is 10.

The range, which is the difference between the dataset's largest and smallest values, is the appropriate variable for the data at hand.

We simply subtract the smallest value from the largest value to determine the range:

Range = 12 - 2 = 10

Therefore, the best measure of variability for this data is the range, and its value is 10.

Variability, not mean and median, are measures of central tendency. Another way to measure variability is the IQR (interquartile range), but it's not the best option for this dataset because it only takes into account the middle half of the data and may not cover the whole range of values.

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The equation x / y = 4 is an example of direct variation formula. (Correct choice: A)

Herein we find four types of equations, of which we must determine what choice represents a direct variation formula, whose definition is shown below:

y ∝ x

y = k · x

Where k is the constant of proportionality.

This form is equivalent to the following expressions:

y / x = k, x / y = 1 / k

Then, by direct inspection, we see that equation x / y = 4 represents a direct variation formula.

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Answer:

f'(x) = 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]

Step-by-step explanation:

f' of tan(x) = sec²(x)

f' of csc(x) = -csc(x)cot(x)

General Power Rule: uⁿ = xuⁿ⁻¹ · u'

Step 1: Write equation

2tan³(x) + 5csc⁴(x)

Step 2: Rewrite

2(tan(x))³ + 5(csc(x))⁴

Step 3: Find derivative

d/dx  2(tan(x))³ + 5(csc(x))⁴

Answer:

2.0 i think thats the answer