What is the composition, in weight percent of an alloy that consists of 94.1 at% Ag and 5.9 at% Cu? The atomic weights for Ag and Cu
are 107.87 g/mol and 63.55 g/mol, respectively
O 9.6 wt% Ag and 90.4 wt% Cu

Answer:

True

Explanation:

Because a object is a smart thing to use doing them problem

Answer:

0.02795 m

Explanation:

Neglecting shaft weight Design the shaft using maximum shear stress theory and determine the required diameter

factor of safety = 1.5

length of shaft = 10 meters

material yield strength = 350 MPa

Torque = 500 N.m

The required shaft diameter = 0.02795 m

attached below is a detailed solution of the problem

Answer:

That's not true, if your house is burning down, leave. Let the firefighters do their jobs.

Explanation:

To solve this problem, we can use the ideal gas law and the equation for polytropic process.

The ideal gas law is a fundamental law of physics that describes the behavior of an ideal gas. It relates the pressure, volume, temperature, and number of particles of a gas using the following equation:

PV = nRT

a) First, we need to find the mass of the carbon dioxide in the tank. The ideal gas law is:

PV = mRT

where P is the pressure, V is the volume, m is the mass, R is the universal gas constant, and T is the temperature. Rearranging for the mass, we get:

m = PV / RT

Substituting the given values, we have:

m = (200 kPa)(0.3 m3) / [(0.287 kPam3/kgK)(27°C + 273.15)] = 3.87 kg

So the mass of the carbon dioxide in the tank is 3.87 kg.

b) To determine the work done by the gas during the process, we can use the equation for polytropic process:

P1V1^n = P2V2^n

where P1 and V1 are the initial pressure and volume, P2 and V2 are the final pressure and volume, and n is the polytropic index. Substituting the given values, we have:

(200 kPa)(0.3 m3)^n = (4)(0.6 m3)^n

Dividing both sides by (0.3 m3)^n and taking the logarithm of both sides, we get:

log(200) + nlog(0.3) = log(4) + nlog(0.6)

Solving for n, we get:

n = log(4/200) / log(0.6/0.3) ≈ 1.235

Using the polytropic work equation:

W = (P2V2 - P1V1) / (1 - n)

Substituting the given values, we have:

W = [(4 kPa)(0.6 m3) - (200 kPa)(0.3 m3)] / (1 - 1.235) = 233.7 kJ

So the work done by the gas during the process is 233.7 kJ.

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Answer:

metals, composite, ceramics and polymers.

Explanation:

The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.

i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.

ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.

iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.

iv) Polymers: They  have low weight and are poor conductors of electricity and heat

An improvement in automation processes exemplifies technological change.

Technological change refers to the introduction and adoption of new technologies or improvements in existing technologies that lead to increased efficiency, productivity, and effectiveness in various processes. Automation involves the use of technology and software to perform tasks or operations with minimal human intervention. By automating processes, organizations can streamline operations, reduce errors, enhance productivity, and achieve cost savings.

Automation can be applied to various areas in different industries, including manufacturing, healthcare, finance, and logistics, among others. It often involves the use of advanced technologies such as robotics, artificial intelligence (AI), machine learning, and process automation software.

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Answer:

Explanation:

The most common HFC used in air conditioners is R-410A. This refrigerant is better than R-22 in terms of “Ozone Depletion” potential and energy efficiency, but it still causes global warming. A few more HFCs that are commonly used are: R-32 in Air Conditioners and R-134A in refrigerators.

Answer:

The most common refrigerants used for air conditioning over the years include

Explanation:

The most common refrigerants used for air conditioning over the years include.

yes it will

Explanation:

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

Answer:

power = 49.95 W

and it is self locking screw

Explanation:

given data

weight W = 100 kg = 1000 N

diameter d = 20mm

pitch p = 2mm

friction coefficient of steel f = 0.1

Gravity constant is g = 10 N/kg

solution

we know T is

T = w tan(α + φ ) \(\frac{dm}{2}\)     ...................1

here dm is = do - 0.5 P

dm = 20 - 1

dm = 19 mm

and

tan(α) = \(\frac{L}{\pi dm}\)      ...............2

here lead L = n × p

so tan(α) = \(\frac{2\times 2}{\pi 19}\)

α = 3.83°  

and

f = 0.1

so tanφ = 0.1

so that φ = 5.71°

and  now we will put all value in equation 1 we get

T = 1000 × tan(3.83 + 5.71 ) \(\frac{19\times 10^{-3}}{2}\)  

T = 1.59 Nm

so

power = \(\frac{2\pi N \ T }{60}\)     .................3

put here value

power = \(\frac{2\pi \times 300\times 1.59}{60}\)

power = 49.95 W

and

as φ > α

so it is self locking screw

Answer:

Reduce manufacturing costs.

Explanation:

Hope This Helps

Have A Great Day

When required to drill holes on a roof that has no power supply the best drill for the job would be a cordless drill.

It should be noted that a power supply is an electrical device which supplies electric power to an electrical load.

In this case, the main purpose of a power supply is simply to be able to convert electric current from the source to the correct current, and frequency.

In this case, the power supply unit converts the main AC to a low-voltage regulated DC power. Therefore, When required to drill holes on a roof that has no power supply the best drill for the job would be a cordless drill.

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Answer:

Elasticity

Explanation:

Cloud computing comprises of three (3) service models and these are;

1. Platform as a Service (PaaS).

2. Software as a Service (SaaS).

3. Infrastructure as a Service (IaaS).

The common workplace for both science and math pathways, with engineering and technology in laboratories and ships. Thus, option A is correct.

A workplace is given as the location or the place at which the employee are performing their jobs and tasks.

The science or technology-mediated employees are related to research where they perform the tests in laboratories, as well as the ships are the location for the engineering and the math candidates for the analysis of the studies and to perform the job.

Hence, the location in the workplace common for both engineering and technology candidates has been the laboratories and the ships. Thus, option A is correct.

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Gain of the amplifier is decreased by negative feedback. Furthermore, instability, noise, and distortion are reduced.

Complete Response. Conclusion: Current-shunt feedback causes the output resistance to rise as the input resistance in an amplifier decreases.

The amplifier's input impedance rises during voltage-series feedback, but the output impedance falls. Much less noise and distortion is present. There is negative feedback in a power amplifier. The bandwidth is increased while the distortion and noise are decreased by the application of negative feedback.

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Answer:

I don't know the answer sorry

The number of tie-downs can be increased for extra safety. Therefore, it is essential to consult the FMCSA regulations and the manufacturer's guidelines to determine the appropriate number of tie-downs required for a 20-foot load. 150 words

The number of tie-downs required for a 20-foot load will depend on the type of cargo, the weight, the size, and the configuration of the vehicle, among other factors.

The Federal Motor Carrier Safety Administration (FMCSA) regulates the use of tie-downs to secure cargo on commercial motor vehicles. The FMCSA requires that all cargo be adequately secured to prevent shifting during transportation, especially on open trucks, flatbeds, and trailers. Therefore, the number of tie-downs will depend on the weight and type of cargo being transported. It is essential to note that the FMCSA has specific regulations and requirements for different types of cargo. For instance, FMCSA regulations require that a 20-foot load weighing less than 1,100 pounds may require at least one tie-down.

However, the rules can change depending on the length and weight of the load. For a 20-foot load weighing between 1,100 pounds and 2,200 pounds, two tie-downs are required. For loads weighing between 2,200 pounds and 5,000 pounds, the number of tie-downs required will depend on the length of the load and the type of cargo. In general, at least two tie-downs are required for cargo shorter than 5 feet, while longer cargo may require at least four tie-downs to secure the load.

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The one that is not a part of a rack-and-pinion steering system are the pitman arm, idler arm, and center link. The correct option is d. all answers are correct.

Rack and pinion steering employs a gear set to transform the steering wheel's circular motion into the linear motion required to turn the wheels. Tie rods, the shaft, and rack and pinion are the key components of a rack and pinion system.

When the steering wheel is rotated, the shaft transfers the steering wheel's action to the gear. This causes the gear to rotate, which causes the rack to move.

Therefore, the correct option is d. all answers are correct

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The f(4) using is found using newton's interpolating polynomials of order 4.

function y=CL10_Exercise(part)

%% Input

% part: string for part a,b,c,d

%

%% Output

% y value of the underlying function at x=4

%

%% Write your code here

X=[1,2,3,5,6];

Y=[15,8,5.5,30,52];

x=4;

y=1;

switch part

case 'a'

%% Newton interpolation (Order 4)

a=X;

b=Y;

%x=input('Enter x: ');

[m,n]=size(a);

fx=0;

for i=1:n

%_____________Calculating Dividing Difference_____________________

s=0;

for j=1:i

p=1;

for k=1:i %Denominator part product

if(k~=j)

p=p*(a(j)-a(k));

end

end

s=s+b(j)/p; %summation f(x)/product

end

%_________________________________________________________________

p=1;

for j=1:i-1 %coefficient part of f[...]

p=p.*(x-a(j));

end

fx=fx+s.*p; %Polynomial!

end

y=fx;

case 'b'

%% not-a-knot spline

case 'c'

%% clamped spline

case 'd'

%% Hermite spline

end

end

Hence, the f(4) using is found using newton's interpolating polynomials of order 4.

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The python code that estimates pi using a given text is shown below

A Python code to estimate pi using the given text where comments (#) are used for explanatory purpose is as follows:

import string

# read the text file

with open('text.txt', 'r') as file:

   text = file.read()

# convert all uppercase letters to lowercase

text = text.lower()

# remove all characters that are not in the alphabet Ax

text = ''.join(filter(lambda x: x in string.ascii_lowercase + ' ', text))

# create the character vector x

x = list(text)

# calculate the frequency of each letter

freq = {}

for letter in string.ascii_lowercase:

   freq[letter] = x.count(letter) / len(x)

# print the estimated pi for each letter

for letter in string.ascii_lowercase:

   print(f"p({letter}) = {freq[letter]}")

Note that you need to replace text.txt with the name of the text file that contains the text you want to parse.

This code reads the text file, converts all uppercase letters to lowercase, removes all characters that are not in the alphabet Ax, and creates the character vector x.

Then it calculates the frequency of each letter in x and prints the estimated pi for each letter.

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The value of the output from the 5 kW solar PV system per year in a sunny location where each 1 kW of capacity generates 115 kWh/month year-round is estimated to be $1,620.

The calculation is as follows: (5 kW x 115 kWh/month x 12 months) x $0.12/kWh = $1,620. This figure is calculated by multiplying the system size of 5 kW with the monthly output of 115 kWh/month and then multiplying that by 12 months to get the total output for the year. This figure is then multiplied by the cost of electricity of $0.12/kWh to get the value of the output from the system per year.

The solar PV investment in a sunny location with a system size of 5 kW rated and electricity cost of $0.12/kWh is estimated to be worth $1,620 per year.

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Answer:

1. True

2. True

3. False

Explanation:

The office location is where the soil layer is not uniform. The thickness of the soil varies which could lead to doors being jammed. The engineer needs to estimate the differential in clay soil.

The inclined surface can hold less weight than a vertical surface. The capacity to hold the weight is due to the gravitational force which is exerted to the load.

a) The normal stress on the acrylic plastic rod is approximately 191.013 N/mm².

b) The final length of the rod, considering a strain of 0.04, is 208 mm.

c) The strain (ε) of the acrylic plastic rod is 0.04.

To calculate the normal stress, we use the formula: Normal stress = Force / Area. Given that the force applied is 300 N and the diameter of the rod is 10 mm, we first need to calculate the area of the rod's cross-section.

The area is determined using the formula: Area = π * (radius)². Since the diameter is 10 mm, the radius is half of that, which is 5 mm. Substituting the values into the formula, we find the area. Then, dividing the force by the area gives us the normal stress.

To determine the final length of the rod, we use the formula: Final length = Initial length + (Strain * Initial length). Given that the initial length is 200 mm and the strain is 0.04, we can substitute these values into the formula to calculate the final length.

The strain is a measure of the deformation or elongation of a material relative to its original length. It is calculated using the formula: Strain = ΔL / L, where ΔL is the change in length and L is the original length. In this case, the strain is given as 0.04.

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Pliers should never be used to hold work while welding or soldering.

The heat from these processes can transfer to the pliers and cause burns to the user's hands or damage to the pliers.

Also, pliers are not designed to withstand the pressure and force of welding or soldering, which can result in the pliers slipping and causing an accident. Pliers should be used only for their intended purposes, such as gripping, cutting, or bending materials, and the user should always use appropriate tools and equipment for each task.

Failure to do so can result in injury or damage to the materials being worked on.

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Answer:

A) condenser pressure = 9.73 kPa,

B) 10242 kw

C) 36.9%

Explanation:

given data

entrance pressure of steam = 12.5 MPa

temperature of steam = 550⁰c

flow rate of steam = 7.7 kg/s

outer pressure = 2 MPa

reheated steam temperature = 450⁰c

isentropic efficiency of turbine( nt ) = 85% = 0.85

isentropic efficiency of pump = 90% = 0.90

From steam tables

at 12.5 MPa and 550⁰c ; h3 = 3476.5 kJ/kg,  S3 = 6.6317 kJ/kgK

also for an Isentropic expansion

S4s = S3 .

therefore when S4s = 6.6317 kJ/kg and P4 = 2 MPa

h4s = 2948.1 kJ/kg

nt = 0.85

nt (0.85) = \(\frac{h3-h4}{h3-h4s}\) = \(\frac{3476.5 - h4}{3476.5 - 2948.1}\)

making h4 subject of the equation

h4 = 3476.5 - 0.85 (3476.5 - 2948.1)

h4 = 3027.3 kj/kg

at P5 = 2 MPa and T5 = 450⁰c

h5 = 3358.2 kj/kg,  s5 = 7.2815 kj/kgk

at P6 , x6 = 0.95  and s5 = s6

using nt = 0.85 we can calculate for h6 and h6s

from the chart attached below we can see that

p6 = 9.73 kPa, h6 = 2463.3 kj/kg

B) the net power output

solution is attached below

c) thermal efficiency

thermal efficiency = 1 - \(\frac{qout}{qin}\) = 1 - ( 2273.7/ 3603.8) = 36.9% ≈ 37%

First, because a current greater than its capacity is being flowed through, the fuse burns out repeatedly. Now,. I and R have an inverse relationship (current).  The fuse wire's length and current rating are independent. Fuse wire is capable of carrying electricity over any distance, but thickness—which regulates melting—is crucial.

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Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

Given the input string "abcdcba", the output of the algorithm is 4

The pseudocode represents a dynamic programming algorithm to find the length of the longest palindromic subsequence in a given string.

The algorithm initializes a 2D array arr of size (n+1) x (n+1), where n is the length of the input string. It then iterates through the string and compares characters at different positions.

If the characters are equal, it adds 1 to the previous diagonal element in the array. Otherwise, it takes the maximum value between the element on the left and the element above in the array.

Finally, it returns the value at arr[n][n], which represents the length of the longest palindromic subsequence.

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