What is the frequency of light emitted when an electron in a hydrogen atom jumps
from 2nd orbit to 1st orbit?

Answers

Answer 1

The frequency of light emitted is 24.63 x \(10^1^5\) Hz when an electron jumps from the 2nd to the 1st orbit in a hydrogen atom.

According to Bohr, the electrons in the atom's structure are situated around the nucleus at particular energy levels. An electron must either acquire or lose energy as it transitions from one of these energy levels to another. It is known as an absorption when an electron obtains energy and as an emittance when it loses energy. Both processes involve the absorption or emission of a PHOTON energy particle, which in turn causes the absorption or emission of light. Because various elements have varying energies, they each emit or absorb light in varying quantities (wavelengths).

The wavelength or wave number is used to compute the frequency of light emitted

The frequency of light emitted is inversely proportional to its wavelength.

Given:

Jump from 2nd orbit to 1st orbit

Planck’s constant, h = 6.626 x \(10^-^3^4\)

To find:

Frequency of light emitted, υ = ?

Formula:

E = hυ

Calculations:

\(E = 13.6 * Z^2( \frac{1}{n_1^2} - \frac{1}{n_2^2} )\)

E = hυ = 13.6 x 1 x \((1 - \frac{1}{4})\)

υ x 6.626 x \(10^-^3^4\) = 10.2 x 1.6 x \(10^-^1^9\)

υ = 24.63 x \(10^1^5\) Hz

Result:

The frequency of light emitted is 24.63 x \(10^1^5\) Hz.

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Related Questions

a runner sprints a race, starting at 0 m/s and ending at 3 m/s in 6 seconds. what is the runner's acceleration?

Answers

The runner's acceleration during the race is 0.5 m/s².

To find the runner's acceleration, we will use the formula for acceleration, which is:

Acceleration (a) = (Final Velocity (vf) - Initial Velocity (vi)) / Time (t)

Given that the runner starts at 0 m/s (Initial Velocity) and ends at 3 m/s (Final Velocity) in 6 seconds (Time), we can plug these values into the formula:

a = (3 m/s - 0 m/s) / 6 s

a = 3 m/s / 6 s

a = 0.5 m/s²

The runner's acceleration during the race is 0.5 m/s².

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A person has long hair hanging straight down from their head. A second person rubs a balloon with felt so that the balloon is negatively charged, then brings it near the first person's hair without allowing the balloon to touch the hair. They notice that strands of the first person's hair are attracted to the balloon. The second person then rubs another balloon with plastic wrap so that it is positively charged, and again they notice that the balloon attracts strands of the first person's hair. Which is the best explanation for the attraction of the hair to the balloon

Answers

Answer:

The best explanation is that the first person is grounded to the earth, and his/her body either draws up negative charges from the earth, or tend to conducts negative charges to the earth, depending on the charge on the balloon.

Explanation:

The earth is an infinite store for charges. In the first case where the second person brings a negatively charged balloon towards the first person, the negative charges on the balloon induces the first person's body to tend to attract the negative charges on the balloon through the first person's body to the positive charges within the earth. In the second case when again a positively charged balloon is brought near the first person's hair, the positive charges on the balloon induce the first person's body into drawing up negative charges from within the earth. This charges, and their opposite induced charges, create an attractive force between the hair strands and the balloons.

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Answers

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Answers

Newton's 2nd law of motion says:

Net force = (mass) · (acceleration) .

Newton didn't make up this law for his health.

Let's use it to answer this question about the car moving down the road.

Net force on the car = (car's mass) · (car's acceleration).

But the net force on the car is zero.  So we can write:

0 = (car's mass) · (car's acceleration).

Look at the right side of this equation.

Newton's law tells us that the product of the car's mass and the car's acceleration is zero.

That tells us that at least one of three things must be true.

Either 1). the car's mass is zero, or 2). the car's acceleration is zero, or 3). Newton was crazy.

We're pretty sure that 1). and 3). are false. The car's acceleration is zero.

What does this mean ? It means that the car's speed and direction are not changing.

That's exactly what Choice-B says.

Which of the following is a combustion reaction?
O A. 2503 (9)
->
2502 (9) + 02 (9)
O B. 2Na (s) + Cl2 (9) → 2NaCl (s)
C. C3H8 (g) + 502 (9) — 3C02 (9) + 4H20 (9)
O D. 2KCIO3 (s) — 2KCI (s) + 303 (9)

Answers

Answer:

Option C

Explanation:

Hydrocarbon + Oxygen = Carbon dioxide + Water

is example of combustion reaction

I think c The best answer for your questions

What is the magnitude and direction of the momentum of a 1200 kg truck traveling at 20m/s towards the east

Answers

Given :

A 1200 kg truck traveling at 20 m/s towards the east.

To Find :

The magnitude and direction of the momentum.

Solution :

We know, momentum is given by :

Momentum, P = mv

P = 1200 × 20 kg m/s

P = 24000 kg m/s

Now, we know, direction of momentum is same as the direction of velocity.

Therefore, momentum of truck is 24000 kg m/s and direction is towards the east.

Rhodes research indicates that people are generally accurate in guessing the ages of unfamiliar persons based on their faces. This research has important implications for

Answers

The available options are:

A. bartenders serving alcohol

B. students identifying their professors.

C. Doctors diagnosing cases of schizophrenia.

D. eyewitnesses identifying suspects from a lineup.

Answer:

A.  bartenders serving alcohol

Explanation:

This is because of the underage rule concerning sale of alcohol. Thus, there are occasional period in which underage person or a minor will want to buy alcohol, and without necessarily asking for the birth certificate or ID card that contains Age information, it is therefore, necessary for bartenders to be able to tell the age of their unfamiliar customers, by mere looking at them, so as not to sell to a minor.

Hemce, Rhodes research in guessing the age of unfamiliar person has important implications for BARTENDERS SERVING ALCOHOL, because it will guide them to determine Underage or Minor, that want to buy alcohol from them.

A car starts from rest and travels 243 m in 7.86 s with constant acceleration. what is its velocity when it crosses the finish line?

Answers

The car that starts from rest and travels 243 m in 7.86 s with constant acceleration has a velocity when it crosses the finish line of: 61.82 m/s

The formulas and procedures we will use to solve this exercise are:

a = 2 * [x - (vi * t)] / t²vf = vi + (a * t)

Where:

x = distancet = timevi = initial velocitya = accelerationvf = final velocity

Information about the problem:

vi = 0 m/sx = 243 mt = 7.86 sa=?vf=?

Applying the acceleration formula we have:

a = 2 * [x - (vi * t)] / t²

a = 2 * [243 m - (0 m/s * 7.86 s)] / (7.86 s)²

a = 2 * [243 m - (0 m)] / 61.779 s²

a = 2 * [243 m] / 61.779 s²

a = 486 m/ 61.779 s²

a = 7.866 m/s²

Applying the final velocity formula we have:

vf = vi + (a * t)

vf = 0 m/s + (7.866 m/s² *7.86 s)

vf = 0 m/s + 61.82 m/s

vf = 61.82 m/s

What is acceleration?

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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A car starts from rest and travels 243 m in 7.86 s with constant acceleration. what is its velocity when

What may also be called breakers? Crusher, Grappler, Hydraulic Hammer, Trencher

Answers

I believe it’s ‘Hydraulic Hammer’..

the magnitude of the force of gravity acting on an object is

Answers

The magnitude of force of gravity on an object, mg is called weight of the object on earth.

In physics, gravity (from Latin gravitas 'weight') is a fundamental interaction which reasons mutual enchantment between all matters with mass or strength. Gravity is, by a long way, the weakest of the 4 fundamental interactions, approximately 1038 instances weaker than the strong interaction, 1036 times weaker than the electromagnetic pressure and 1029 times weaker than the weak interaction.

As an end result, it has no significant have an impact on at the level of subatomic debris. but gravity is the most significant interaction among objects at the macroscopic scale, and it determines the movement of planets, stars, galaxies, or even mild.

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Complete Question: -

The magnitude of the force of gravity on an object, mg", is called the object's.

Explain how forces of attraction and repulsion exist within an atom. describe how an electric charge is developed by friction or by contact. contrast electron movement within conductors and insulators. list the ways in which lightning can be produced.

Answers

There are three kinds of forces within the atom:

  i) Electromagnetic force of attraction between the electrons and protons

  ii) Electromagnetic force of repulsion between the protons or weak nuclear force

  iii) Strong nuclear force between the electrons and protons

What is nuclear force?

The electromagnetic force of attraction:

Electrons circle in the orbits above the nucleus. There exists an electromagnetic force of pull between the electrons and protons. That’s why electrons do not depart the atom.

Weak nuclear force:

It is an electromagnetic significance of revulsion between the protons in the nucleus of the atoms.

Strong nuclear force:

This force is strongest from all the fundamental details and exists between the protons and neutrons in the nucleus of an atom. This pressure overcomes the weak nuclear force and does not allow protons to stray out.

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Answer:

1.)Electrons surrounding a nucleus are attracted to the protons within it because electrons and protons have opposite charges. Electrons closest to the nucleus are attracted with such a force that they can’t escape from the atom. These electrons tend to shield the protons from electrons that are farther away because electrons have the same charge and repel each other. Electrons that are farther away have less attraction to the protons within the nucleus and are more likely to be detached from the atom.

2.)Electrons can be transferred from atoms of one body to atoms of another body through friction. This can occur when one body is rubbed against another or when a liquid flows across a solid. In either case, one body may be given a positive charge while the other body is given a negative charge of the same magnitude. Both charges are developed at the same time. Electrons can also be transferred from one body to another when a charged body comes into contact with an uncharged body. The electrons move in the direction that will equalize the charges; thus, the uncharged body will be given the same charge as the charged body.

3.)Free electrons move from points of negative charge to points of positive charge. When these electrons move freely from one point to another with little resistance, the material they’re traveling through is said to be a conductor. Conductors have a large number of free electrons. Insulators, on the other hand, have very few free electrons and offer great resistance to the movement of these electrons. Electric charges produced on one end of a body composed of insulating materials will most likely not spread throughout the body. In a conductor, this charge would spread throughout the entire body. Metals are generally conductors; oils, rubber, air, porcelain, and plastics are good insulators.

4.)Lightning is produced by the rapid transfer of free electrons when one of the following conditions exist:

One part of a cloud is positively charged and a neighboring part of the same cloud is negatively charged.

A positively charged cloud comes near a negatively charged cloud.

A cloud with either a positive charge or a negative charge comes near the earth.

Explanation:

PENN FOSTER

PLZZZZ HELP QUICK . 30 points. Emma weighs 560 N, she has decided to stay in shape so she is working out every morning, This morning she ran and lifted weight! 1. Calculate Emma's mass ( Gravity g= 9.8 N/kg). 2. If she ran 350 meters in 65 seconds, what was her velocity? 3. When she lifted weights, she exerted a 35 N to lift one of the weight 2 meters over the ground, what is the amount of work she performed? Note that units are important, so do not give any number without a unit to avoid losing points.​

Answers

Force equals mass time acceleration. Weight is a force and it can replace force in the equation. The acceleration would be gravity, which is an acceleration.

1.)

Fw (weight) = m (mass) · g (gravity, 9.8 m/s²)

Fw = m * 9.81 m/s²

560N = m · 9.81 m/s²

m ≈ 57.08 kg

2.)

d = 350 meters

t = 65 seconds

velocity = d/t

velocity = 350 meters / 65 seconds

velocity ≈ 5.38 meters/sec

3.)

Force = 35N

Distance = 2 meters

Work = Force · Distance

Work = 35N · 2 meters

Work = 70 J

A soccer ball is kicked and leaved the ground at an angle 38 degrees above the horizontal, moving at 15m/s.Hang time of the ball. Initial horizontal velocity. Initial vertical velocity

Answers

Both initial velocities will be 0

In the lab, You have a highly reactive metal like sodium. It is so reactive that water sets it off. How would you store it?

Answers

Answer:

Sodium is stored under paraffin oil

Explanation:

Group 1 metals are known to be very highly reactive. The chemical reactivity of the members of the group decreases down the group.

Sodium reacts violently with water and upon exposure to the atmosphere. As a result of this, it must be stored under paraffin oil.

The volume of gas decreases at constant temperature to 80% of the inital value. How does the pressure value change relative to the initial value

Answers

Answer:

The pressure value changes 400 % relative to the initial value.

Explanation:

Let suppose that the gas behaves ideally and represents a closed system, that is, a system with no mass interactions so that number of moles is conserved (\(n\)). Since the variables involved in the isothermal process are pressure (\(P\)) and volume (\(V\)). Finally, the process is represented by the following relationship:

\(P_{1}\cdot V_{1} = P_{2}\cdot V_{2}\) (1)

Where:

\(P_{1}, P_{2}\) - Initial and final pressures.

\(V_{1}, V_{2}\) - Initial and final volumes.

If we know that \(P_{1} = P_{o}\), \(V_{1} = V_{o}\) and \(V_{2} = 0.2\cdot V_{o}\), then the final pressure of the closed system is:

\(P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)\)

\(P_{2} = 5\cdot P_{o}\)

The pressure value changes 400 % relative to the initial value.

If an object is accelerating toward a point, then it must be getting closer and closer to that point. True or false?.

Answers

False, If an object is accelerating toward a point, then it must not be getting closer and closer to that point.

What do you mean by acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. An object has positive acceleration if it is accelerating and traveling in the right direction. Positive acceleration was demonstrated in the first example by the speeding car. The acceleration is occurring in the same direction as the car's motion, which is forward and speeding up. The meter per second squared (m s2) is the unit of acceleration used in the SI system.

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What must be in cm, the barometric height so that the pressure is 1000 mbar?Density of mercury: 13.6

Answers

75.064 cm

Explanation

to solve this we need to know the equivalence

\(1mmbar=0.075006cmHg\)

then

let's use a equivalente fraction to convert the measure

\(1000\text{ mbar(}\frac{0.075006\text{ cm HG}}{1\text{ mbar}})=75.064\text{ cm Hg}\)

hence, the answer is 75.064 cm

I hope this helps you

Un tren emite un sonido a 480hz determina la frecuencia que percibe el observador cuando el observador se aleja a 12m/s del tren que ha quedado en reposo velocidad del sonido en el aire 340m/s

Answers

Answer:

La frecuencia que percibe el observador es 463 Hz.

Explanation:

El efecto Doppler se define como el cambio de frecuencia aparente de una onda producida por el movimiento relativo de la fuente respecto a su observador. En otras palabras, este efecto es el cambio en la frecuencia percibida de cualquier movimiento ondulatorio cuando el emisor y el receptor, u observador, se desplazan uno respecto a otro.

La siguiente expresión se considera el caso general del efecto Doppler:

\(f'=f*\frac{v+-vR}{v-+vE}\)

Donde:

f’, f: Frecuencia percibida por el receptor y frecuencia emitida por el emisor respectivamente. Su unidad de medida en el Sistema Internacional (S.I.) es el Hertz (Hz), que es la unidad inversa del segundo (1 Hz = 1 s-1) v: Velocidad de propagación de la onda en el medio. Es constante y depende de las características del medio.  En este caso se considera que la velocidad del sonido en el aire es de 340 m/s vR, vE: Velocidad del receptor y del emisor respectivamente. Su unidad de medida en el S.I. es el m/s ±, ∓:  

Utilizaremos el signo +:

En el numerador si el receptor se acerca al emisor

En el denominador si el emisor se aleja del receptor

Utilizaremos el signo -:

En el numerador si el receptor se aleja del emisor

En el denominador si el emisor se acerca al receptor

En este caso:

f= 480 Hzv= 340 m/svR= 12 m/s (el receptor es el observador)vE=0 (el emisor es el tren, que se encuentra en reposo)

Y como el receptor se aleja del emisor, la expresión del efecto Doppler queda determinada como:

\(f'=480 Hz*\frac{340 m/s-12 m/s}{340 m/s-+0 m/s}\)

Resolviendo se obtiene:

\(f'=480 Hz*\frac{340 m/s-12 m/s}{340 m/s}\)

\(f'=480 Hz*\frac{328 m/s}{340 m/s}\)

f'= 463 Hz

La frecuencia que percibe el observador es 463 Hz.

A bullet from a gun at 30° to the horizontal remains in flight for 25s before touching the ground.Calculate the velocity of the projection.​

Answers

Answer: The velocity of the bullet will be more than half of its earlier velocity

Explanation: I did it on a test and it was right because i calculated 30 degrees within 25 seconds and it was half times the velocity

i hope this helps sorry if i got it wrong

Can sum one pls help me with this assignment I will mark brainlieniest for whoever helps me (:

Can sum one pls help me with this assignment I will mark brainlieniest for whoever helps me (:

Answers

Answer:

problem 1 would be 2 homogeneous & 2 heterogeneous

problem 2 would be 4 tall and 0 short

Explanation:

if you fill in the boxes, homo is same and heterogeneous is different. the big letter determines if it is tall or short as well.

If an object falls from rest and lands 3.2 seconds later, how many
meters did it fall

Answers

Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

\(d=\frac{1}{2}*g*t^{2}\)

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8\(m/s^{2}\) , t is the time in seconds

Therefore, \(d = \frac{1}{2}*9.8*(3.2)^{2}\)

d= 50.176 ≈ 50.2m

A rocket of mass 5kg is travelling horizontally with a speed of 200m/s when it explodes into two parts.
one part of mass 3kg continues in the original direction with a speed of 100m/s and the other part continues in the same direction.

*Calculate the unknown speed of the other part*
(please solve with steps + explanation) ​

Answers

Answer:

350 m/s

Explanation:

Before the explosion, the rocket's momentum is given by:

p = m*v where

p = momentum

m = mass of the rocket

v = velocity of the rocket

Given that the mass of the rocket is 5 kg and its velocity is 200 m/s, we can calculate the momentum as:

p = m*v = 5 kg * 200 m/s = 1000 kg·m/s

After the explosion, the momentum is conserved, which means the total momentum of the two parts is still 1000 kg·m/s. We can use this principle to solve for the velocity of the second part.

Let v1 be the velocity of the 3 kg part, and v2 be the velocity of the other part. Since they are both moving in the same direction, we can write:

p = m1v1 + m2v2

where m1 = 3 kg is the mass of the first part, and m2 is the mass of the second part.

Substituting the known values, we get:

1000 kg·m/s = 3 kg * 100 m/s + m2 * v2

Solving for v2, we get:

v2 = (1000 kg·m/s - 300 kg·m/s) / m2

v2 = 700 kg·m/s / m2

We still need to find the mass of the second part. Since the rocket initially had a mass of 5 kg, and one part has a mass of 3 kg, the other part must have a mass of:

m2 = 5 kg - 3 kg = 2 kg

Substituting this into the equation for v2, we get:

v2 = 700 kg·m/s / 2 kg

v2 = 350 m/s

Therefore, the unknown speed of the other part is 350 m/s.

Monochromatic light of wavelength λ = 620 nm from a distant source passes through a slit 0.450 mm wide. The diffraction pattern is observed on a screen 3.00 m from the slit. a) In terms of the intensity Io at the peak of the central maximum, what is the intensity of the light at the screen at the distance 1.00 mm from the center of the central maximum? b) In terms of the intensity Io at the peak of the central maximum, what is the intensity of the light at the screen at the distance 3.00 mm from the center of the central maximum? c) In terms of the intensity Io at the peak of the central maximum, what is the intensity of the light at the screen at the distance 5.00 mm from the center of the central maximum?

Answers

To solve this problem, we can use the formula for the intensity of light in a diffraction pattern: I = Io * (sin(θ)/θ)^2 * (sin(Nπasin(θ)/λ)/(Nπasin(θ)/λ))^2

where:

I = Intensity of light at a certain point on the screen

Io = Intensity at the peak of the central maximum

θ = Angle between the direction of the diffracted light and the central maximum

N = Number of bright fringes away from the central maximum

a = Width of the slit

λ = Wavelength of light

Given:

λ = 620 nm = 620 x 10^(-9) m

Slit width = 0.450 mm = 0.450 x 10^(-3) m

Distance to the screen (D) = 3.00 m

a) Distance from the center of the central maximum = 1.00 mm = 1.00 x 10^(-3) m

To find the angle θ, we can use the small angle approximation:

θ = Distance / Distance to the screen = (1.00 x 10^(-3)) / 3.00 = 3.33 x 10^(-4) radians

Using the formula, we can calculate the intensity:

I = Io * (sin(θ)/θ)^2 * (sin(Nπasin(θ)/λ)/(Nπasin(θ)/λ))^2

For the central maximum (N = 0), the second term becomes 1:

I = Io * (sin(θ)/θ)^2

b) Distance from the center of the central maximum = 3.00 mm = 3.00 x 10^(-3) m

Using the same method as above, we calculate the angle θ:

θ = (3.00 x 10^(-3)) / 3.00 = 1.00 x 10^(-3) radians

c) Distance from the center of the central maximum = 5.00 mm = 5.00 x 10^(-3) m

Using the same method as above, we calculate the angle θ:

θ = (5.00 x 10^(-3)) / 3.00 = 1.67 x 10^(-3) radians

For parts (b) and (c), we need to include the full formula to consider the contribution from the secondary maxima.

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please help me with my question I will like and mark as brainliest NO LINKS THEY DON'T WORK AND IF U DON'T KNOW THE ANSWER PLS DON'T ANSWER AT ALL​

please help me with my question I will like and mark as brainliest NO LINKS THEY DON'T WORK AND IF U

Answers

Answer:

a)

Weight in Air = 0.3N

Weight in Water = 0.25N

Weight in Liquid = 0.24N.

Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)

= 0.3 – 0.25

= 0.5N.

b) R.D of Body = Density of Body/Density of Standard Fluid(Water).

There's a Derived Formula for RD.

I'm gonna Apply it here.

Ask me for the derivation in the Comment section if you need it.

RD = α/ρ = (Weight in Air) / (Upthrust Force)

Where

α = density of the Body(or reference substance)

ρ = density of standard fluid (water)

= 0.3/0.05 = 6.

c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)

Or we just go by that formula

RD of Liquid = Weight in Air/Upthrust(In Liquid)

We'll be using the Upthrust in that Liquid now.

= 0.3 – 0.24 = 0.06

RD = 0.3/0.06 = 5.

Two persons A and B are walking with speed 5 km/h and 6 km/h
respectively in the same direction. Find how far will B be from A after
2 hours.


a 6 km
b 2 km
C 5 km
d 3 km

Answers

Answer:

b

Explanation:

The relative distance can calculate by dividing the time travelled by the speed difference between points A and B. Considering that B is going more quickly than A, we substract A's speed from B's speed.

Relative Speed = Speed of B - Speed of A

Relative Speed = 6 km/h - 5 km/h

Relative Speed = 1 km/h

Now, we can calculate the relative distance traveled by B after 2 hours:

Relative Distance = Relative Speed * Time

Relative Distance = 1 km/h * 2 hours

Relative Distance = 2 km

Therefore, B will be 2 kilometers away from A after 2 hours of walking in the same direction.

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Derive an algebraic equation for the vertical forc

Answers

To derive the algebraic equation for the vertical force, we must consider the forces acting in the vertical direction and apply Newton's second law of motion.

Newton's second law states that the net force acting on an object is equal to the product of its mass (m) and its acceleration (a). In the vertical direction, the forces that typically act on an object are gravity and any other forces such as the normal force or applied forces.

Assume that the vertical force is denoted as Fv. Forces acting in the vertical direction are typically mass (mg) and the normal force (N) exerted by the surface, if present. Therefore, the equation for the vertical force can be expressed as:

Fv = N - mg,

where:

Fv is the vertical force,

N is the normal force,

m is the mass of the object,

g is the acceleration due to gravity (approximately 9.8 m/s² on Earth).

The normal force N is equal to the weight of the object if the object is at rest on a horizontal surface. In this case, N = mg. However, if the object is on an inclined plane or is subject to other forces, the normal force may differ from the weight.

By substituting the appropriate values ​​for the normal force and mass (mg), you can derive an algebraic equation for the vertical force based on the specific scenario you are considering.

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The small and large pistons of a hydraulic press
have areas of 2 m2 and 4 m2. If the load on the large piston in 3200 N, what is the input force (effort) that must be applied on the small piston

Answers

Answer:

1600 N

Explanation:

pascals principle says..

\(\frac{A_{out}}{A_{in}} = \frac{F_{out}}{F_{in}} \\\)

so lets do

\(\frac{2}{4} = \frac{x}{3200}\)

so multiply one half (2/4 simplified) by 3200

1600 is equal to x

1600 N

YAAAAAAAAAAAAAAY

A 5.05 μF capacitor is initially charged to a potential of 15.2 V. It is then connected in series with a 3.75mH inductor. What is the maximum current in the inductor? Express your answer in amperes.

Answers

The maximum current in the inductor is approximately 1.21 amperes when a 5.05 μF capacitor initially charged to 15.2 V is connected in series with a 3.75 mH inductor.

How to find maximum current?

To determine the maximum current in the inductor when a 5.05 μF capacitor initially charged to a potential of 15.2 V is connected in series with a 3.75 mH inductor, we can use the formula for the resonant frequency of an LC circuit.

The resonant frequency (fr) of an LC circuit is given by:

fr = 1 / (2π√(LC))

Given:

C = 5.05 μF = 5.05 × \(10^{-6}\)F

L = 3.75 mH = 3.75 × \(10^{-3}\) H

Plugging the values into the formula:

fr = 1 / (2π√(5.05 × \(10^{-6}\) × 3.75 × \(10^{-3}\)))

  = 1 / (2π√(1.89125 ×\(10^{-8}\)))

  ≈ 530,012 Hz

The maximum current (Imax) in the inductor can be calculated using the formula:

Imax = V / Xl

Where:

V is the initial potential (voltage) across the capacitor (15.2 V), and

Xl is the inductive reactance.

The inductive reactance (Xl) is given by:

Xl = 2πfL

Plugging the values into the formula:

Xl = 2π(530,012)(3.75 × \(10^{-3}\))

  ≈ 12.556 Ω

Plugging the values into the formula for Imax:

Imax = 15.2 V / 12.556 Ω  ≈ 1.21 A

Therefore, the maximum current in the inductor is approximately 1.21 amperes.

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When you see an object that is not a light source, you are seeing light waves ___ by the object

A. reflected
B. absorbed
C. refracted

Answers

probably a or b not sure

Hello:)! how to do 1(c)?

Hello:)! how to do 1(c)?

Answers

The ship doesn’t completely stop because the engines are so big that they have to have time to completely stop in order to have the ship at a complete stop

Answer:

It does not come to a complete stop immediately because of inertia.

Explanation:

Inertia is the reluctance of an object to change its state of motion or rest. In this case, it is the state of motion since the ship was moving initially. Inertia is directly related to mass. Thus, the heavier the mass, the larger the inertia. The ship has a large mass and therefore it has a large inertia. This causes the ship to slowly come to a stop instead of stopping immediately when the engines are switched off.

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