Which describes the cost to produce one item?
A. Benefit
B. Unit price
C. Fixed cost
D. Unit cost

Reccesive disorders are more  common because they are not easily eliminated by natural selection.

The autosomal dominant disorders refers to those disorders that have no gender preference and have possible male to male transmission.

The  autosomal dominant disorders are much more rare than the recessive disorders because they do not occur on a s-ex-linked chromosome. Note also that it is more common to have dominant mutations eleiminated by the process of natural selection.

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Sets of values that could be the intensities of Amber’s exercise during the fourth, fifth, and sixth visits are -

66%, 69%, 72%

63%, 65%, 67%

What is intensity?

In physics, the power transferred per unit area is known as the intensity or flux of radiant energy, where the area is measured on a plane perpendicular to the direction of the energy's propagation.

The program recommends a pattern of constant intensity for 3 visits, increasing intensity over 3 visits, and then decreasing intensity for 3 visits before restarting the pattern.

Let's call the starting intensity level "x".

Then the intensity levels for the first 3 visits are all equal to x, the intensity levels for the next 3 visits are increasing, and the intensity levels for the following 3 visits are decreasing.

To determine which sets of values could be the intensities of Amber's exercise during the fourth, fifth, and sixth visits, we need to follow the pattern.

If the intensity level for the first 3 visits is x, then the intensity levels for the next 3 visits are x plus some value y, and the intensity levels for the following 3 visits are x plus some value z, where y and z are positive.

If we assume that the initial intensity level x is some value between 60% and 70%, then we can eliminate the last option of 67%, 72%, and 77% because the initial intensity level is too high.

Now let's check the remaining options -

63%, 63%, 63%: This set of values corresponds to a pattern of constant intensity for all 9 visits, which is not consistent with the program's recommendation.

Therefore, this option is not valid.

66%, 69%, 72%: This set of values corresponds to a pattern of increasing intensity over 3 visits, which is consistent with the program's recommendation.

Therefore, this option is valid.

66%, 62%, 58%: This set of values corresponds to a pattern of decreasing intensity over 3 visits, which is not consistent with the program's recommendation.

Therefore, this option is not valid.

63%, 65%, 67%: This set of values corresponds to a pattern of increasing intensity followed by decreasing intensity, which is consistent with the program's recommendation.

Therefore, this option is valid.

Therefore, there are only two valid options -

66%, 69%, 72%

63%, 65%, 67%

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We cannot write \(\sqrt{103}\) as a ratio of integers, so that's why it's irrational.

Note that \(\sqrt{103} \approx 10.1488915650922\)

The decimal digits go on forever without any pattern. If the digits repeated themselves, then we would have a rational number.

A quick way to tell if it is rational or not, without using a calculator, is to note that 103 is not a perfect square. The list of perfect squares are:

1,4,9,16,25,36,49,64,81,100,121,...

we see that 100 is the closest perfect square, but 103 is not in that list. Each perfect square is of the form x^2, where x is some positive whole number.

Answer:

Yes this is irrational like the guy above me said you cannot write it as a ratio, of integer since rational numbers are:

A rational number is any integer,

fraction,

terminating decimal,

or repeating decimal.

So its Not Rational

The numbers from sets B and D are combined to make zero. The correct option is A.

A number line in elementary mathematics is a representation of a graduated straight line that serves as an abstraction for real numbers, represented by the symbol R." It is assumed that every point on a number line corresponds to a real number and that every real number corresponds to a point.

Given that the sets of numbers are,

B : { -9-8-7-6-5-4-3-2-1 }

D : { 0 1 2 3 4 5 6 7 8 9 }

The numbers can be,

-9 + 9 =0

-8 + 8 = 0

-7 + 7 =0

-6 + 6 = 0

-5 + 5 =0

-4 + 4 =0

-3 + 3 = 0

-2 + 2 = 0

-1 +1 = 0

Hence, option A is correct.

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Answer: 14,605 pieces.

Step-by-step explanation:

In the second quarter, the company produced 795 pieces more than in the first quarter.

So, the total pieces produced in the second quarter can be calculated as:

6905 + 795 = 7700

The total pieces produced in the first semester (two quarters) can be calculated as:

6905 + 7700 = 14,605

Therefore, the company produced 14,605 pieces in the first semester.

The number of pieces the company produced in the first semester was 14,605 pieces.

The question asks to calculate how many pieces a company produced in the first semester, considering the production of two quarters.

In the first quarter, the company produced 6,905 pieces, as indicated in the question.

Already in the second quarter, the company produced 795 more pieces than in the first quarter, which means that the production in the second quarter was:

6,905 + 795 = 7,700 pieces.

To know the company's total production in the first semester, just add the productions of the two quarters:

6,905 + 7,700 = 14,605 pieces

Note that; i = √-1

Divide using the rule

10/2i = -5i

Best of Luck!

We can conclude that the hypotheses of the Existence and Uniqueness Theorem are satisfied in any rectangular region in the ty-plane that does not contain the curve t² + y² = -1.

The Existence and Uniqueness Theorem for first-order ordinary differential equations states that if a differential equation of the form y' = f(t, y) satisfies the following conditions in some rectangular region in the ty-plane:

1. f(t, y) is continuous in the region.

2. f(t, y) satisfies a Lipschitz condition in y in the region, i.e., there exists a constant L > 0 such that |f(t, y₁) - f(t, y₂)| ≤ L|y₁ - y₂| for all t and y₁, y₂ in the region.

then there exists a unique solution to the differential equation that passes through any point in the region.

In the case of the differential equation y' = (y cot(2t)) / (t² + y² + 1), we have:

f(t, y) = (y cot(2t)) / (t² + y² + 1)

This function is continuous everywhere except at the points where t² + y² + 1 = 0, which is the curve t² + y² = -1 in the ty-plane. Since this curve is not included in any rectangular region, we can say that f(t, y) is continuous in any rectangular region in the ty-plane.

To check if f(t, y) satisfies a Lipschitz condition in y, we can take the partial derivative of f with respect to y and check if it is bounded in any rectangular region. We have:

∂f/∂y = cot(2t) / (t² + y² + 1) - (2y² cot(2t)) / (t² + y² + 1)²

Taking the absolute value and simplifying, we get:

|∂f/∂y| = |cot(2t) / (t² + y² + 1) - (2y² cot(2t)) / (t² + y² + 1)²|

= |cot(2t) / (t² + y² + 1)| * |1 - (2y² / (t² + y² + 1)))|

Since 0 ≤ (2y² / (t² + y² + 1)) ≤ 1 for all t and y, we have:

1/2 ≤ |1 - (2y² / (t² + y² + 1)))| ≤ 1

Also, cot(2t) is bounded in any rectangular region that does not contain the points where cot(2t) is undefined (i.e., where t = (k + 1/2)π for some integer k). Therefore, we can find a constant L > 0 such that |∂f/∂y| ≤ L for all t and y in any rectangular region that does not contain the curve t² + y² = -1.

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Answer:

c

Step-by-step explanation:

It is given that m∠AOB = 42° and m∠EOF = 66°. By the congruent rule m∠EOF ≅ m∠BOC. Therefore, m∠BOC = 66°. By the sum of m∠AOB and m∠BOC, m∠AOC = 108°, and by the supplementary rule m∠AOC + m∠COD = 180°. After application of the supplementary rule, m∠COD = 72°

Congruent angles are angles that have the same measure, in degrees and are often represented by the symbol "≅"

m∠EOF and m∠BOC are vertical angles and so they are equal and satisfy the congruent rule.

The angles m∠AOB and m∠BOC form the larger angle m∠AOC so;

m∠AOC = 42° + 66° = 108°

The supplementary rule states that if two angles add up to 180°, they are considered supplementary angles, thus m∠AOC + m∠COD = 180° is correct as m∠AOC and m∠COD both lie on a straight line AD.

Therefore, application of the supplementary rule will give the size of the angle m∠COD = 72° as follows:

108° + m∠COD = 180°

m∠COD = 180 - 108°

m∠COD = 72°.

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Answer:

11 ALSO SOMEONE PLS ANSWER MY QUESTION

Step-by-step explanation:

24+24=48

70-48=22

22/2=11

Answer:

4

Step-by-step explanation:

Slope is \(\frac{rise}{run}\). Or, in other words the distance it travels in the y direction divided by the distance it travels in the x direction. Each time the y variable increments +4 and the x variable increments +1. Which means the line rises 4 units every time it runs 1 unit.

Slope=\(\frac{rise}{run}=\frac{4}{1}=4\)

Answer:

d. 340

Step-by-step explanation:

4 x 4 = 16

4 x 4 = 16

11 x 24 = 264

11 x 4 = 44

16 + 16 + 264 + 44 = 340

Answer:

the area of the rectangle is 35.25 square meters.

Step-by-step explanation:

To find the area of a rectangle, we multiply the length by the width.

First, we need to convert the mixed numbers to improper fractions to make the multiplication easier:

4 and 2/4 = 4 + 2/4 = 16/4 + 2/4 = 18/4

7 and 5/6 = 7 + 5/6 = 42/6 + 5/6 = 47/6

Now we can multiply the length and width:

Area = (18/4) * (47/6)

Area = (9/2) * (47/6) (canceling the common factor of 2 between 18/4 and 6 in 47/6)

Area = (9 * 47) / (2 * 6)

Area = 423/12

Area = 35.25

Therefore, the area of the rectangle is 35.25 square meters.

The shortest side is the middle side minus 14. The length of the shortest side is x=-12.

Length is the measurement of something. It is measured n meters and kilometers.

Since the triangle is a right triangle you can use the Pythagorean theorem to find the lengths of each side

a² + b² = c²

The longest side of every right triangle is the hypotenuse so right away we know that 26 m.

One side is a = x and the other is b = 14 + a. This is because it says "One of the shorter sides is 7 m longer than the other" which can be translated into the equation 7 + x which leaves the remaining side as simply x.

Put these equations into the Pythagorean Theorem.

c = 26

a = x

b = 7 + x

a² + b² = c²

x² + (14 + x)² = 26²

Distribute then solve for x to find the shortest side.

x² + x² + 26x + 196  = 676

2x² + 26x - 480 = 0

x² + 13x - 240 = 0

x + -12

x=-12 x=5

Thus, the shortest length is x = 12.

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Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

\(W_1,W_2\)... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

\(E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))\)

\(= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}\)

\(= 1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}\)

\(= 1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}\)

Now \(P(X(s) \leq 0) = P(X(s) = 0)\)

(b)  We can Determine the conditional mean E[W3|X(t)=5] as follows;

\(E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\ = 1- P (X(s) \leq 2 | X (t) = 5 ) \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}\)

Now; \(P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)\)

(c) Determine the conditional probability density function for W2, given that X(t)=5.

So ; the conditional probability density function of \(W_2\) given that  X(t)=5 is:

\(f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 ) \\ \\ = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)\)

Answer: I believe

M = 80

Step-by-step explanation:

100 - 20 = 80

The Volume of Pyramid is 512 in³.

Each thing in three dimensions takes up some space. The volume of this area is what is being measured. The space occupied within an object's borders in three dimensions is referred to as its volume.

Given:

Hypotenuse= 10 inch

leg length= 8 inch

Using Pythagorean Theorem

h² = 10² - 8²

h²= 100 - 64

h = 6 inch

So, the Volume of Pyramid

= lwh/3

= 6 x 16 x 16 /3

= 2 x 196

= 512 in³

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The equation formed after the transformations is given as follows:

\(g(x) = \frac{1}{6}\sqrt{x + 3}\)

The parent function in this problem is defined as follows:

\(f(x) = \sqrt{x}\)

For the vertical shrink by a factor of 1/6, the function is multiplied by 1/6, hence it is given as follows:

\(g(x) = \frac{1}{6}\sqrt{x}\)

For the translation left 3 units, we have that x -> x + 3, hence:

\(g(x) = \frac{1}{6}\sqrt{x + 3}\)

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Answer:

\(3^{-2} * 3^3\)

Step-by-step explanation:

Multiply 1/9 and 27 to get 27/9 which reduces to 3. When doing these equations, you add up the exponents. To get 3, you would have to have 3^1. The get this, the only equation that would work is 3^-2 x 3^3

-2+3 gets 1. So 3^1 which gets you 3. So this is the answer.

Answer:

To one decimal place,

y = 16.3 m

Step-by-step explanation:

Using SOHCAHTOA,

In this case we need to use CAH,

WE know the angle = 25 and the hypotenuse H = 18,

so,

y = adjacent

\(cos(angle) = y/H\\y = (18)(cos(25))\\y = 16.3135\\y = 16.3\)

Answer: 16.3 in.

Step-by-step explanation:

use SOH CAH TOA

cos x = adj/hyp

cos 25  = y/18

18 cos 25  = y

y= 16.3

Answer:

5

Step-by-step explanation:

2(x+6)=22

(x+6)=11

x=5

Sathish will be going to pay a total of $64.8 for the gas.

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Summation = addition of two or more numbers or variable

For example = 2 + 8 + 9

Subtraction = Minus of any two or more numbers with each other called subtraction.

For example = 4 - 8

Division = divide any two numbers or variable called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

For example 5 × 7.

The First 150 and last 150 km will cover by Satish only

Since 6 liters covers 100 km

So,

Cost of 300 km (18 liters) ⇒ 18×1.2 = 21.6

Now,

The journey 2100 - 300 = 1800 km has been covered by all three

Split 1800/3 = 600 km of money Satish will pay

So,

Cost of 600km(36 liters) ⇒ 36 × 1.2 = 43.2

Total paid = 21.6 + 43.2 = 64.8.

Hence "Satis will be going to pay a total of $64.8 for the gas".

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Answer:

While some call having one to two months' wages in reserve ideal, most financial experts say that the recommended emergency fund amount should cover three to six months' worth of household expenses. That's a great idea, and a key part of any sound financial plan, but it also requires some effort to achieve.

Answer:

The parabola is translated down 2 units.

Step-by-step explanation:

You have the parabola f(x) = 2x² – 5x + 3

To change this parabola to f(x) = 2x² - 5x + 1, you must have performed the following calculation:

f(x) = 2x² – 5x + 3 -2= 2x² - 5x + 1  Expresion A

The algebraic expression of the parabola that results from translating the parabola f (x) = ax² horizontally and vertically is g (x) = a(x - p)² + q, translating in the same way as the function.

In the expression A it can be observed then that q = -2 and is less than 0. So the displacement is down 2 units.

This can also be seen graphically, in the attached image, where the red parabola corresponds to the function f(x) = 2x² – 5x + 3 and the blue one to the parabola f(x) = 2x² – 5x + 1.

In conclusion, the parabola is translated down 2 units.

Answer:

= 13.51351351

Step-by-step explanation:

Sol:

(750×4)/222

= 3000/222

= 13.51351351

Step-by-step explanation:

hope it is helpful to you ☺️

No, I don't agree with Sundeep. The mixture wont simply add up

When two liquids are mixed together, their volumes don't simply add up to equal the total volume of the mixture.

When sugar is mixed with water, the total volume of the mixture is usually slightly greater than the volume of the water alone, because the sugar particles take up space between the water molecules.

The volume of the mixture will be equal to the sum of the individual volumes only if the two liquids are completely immiscible, meaning they don't mix together at all. In this case, the total volume of the mixture will be equal to the sum of the volumes of water and sugar, which is 400 mL.

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