BRAINLIEST IF ANSWERED CORRECTLY WITH EXPLANATION! HELP PLEASE:)

BRAINLIEST IF ANSWERED CORRECTLY WITH EXPLANATION! HELP PLEASE:)

Answers

Answer 1

First question

\(Pb(NO_3)_2 + KI \rightarrow PbI_2 + KNO_3\)

Balaneced:

\(Pb(NO_3)_2 + 2KI \rightarrow PbI_2 + 2KNO_3\)

Find how many moles potassium iodide it is in 345.0 grams

\(n_{KI} = \frac{345.0 \ g}{166.0 \ g/mol} = 2.078 \ mole\)

Find how many moles potassium nitrate there is for 2.078 moles \(KI\)

\(n_{KNO_3} = \frac{2}{2} \cdot n_{KI} = 2.078 \ mole\)

Find how many grams potassium nitrate there is in 2.078 moles \(KNO_3\)

\(m_{KNO_3} = 2.078 \ mol \cdot 101.1 \ g/mol = 210.1 \ g\)

Second question

\(yield \ \% = \frac{experimental}{theoretical} \cdot 100 = \frac{195.3 \ grams}{210.1 \ grams} \cdot 100 = 93.0 \ \%\)


Related Questions

what is the change in mass of A in
60 minutes?
Mass of A (g)
12.4
10.4
9.1
7.7
6.2
Time
O
15
30
45
60

Answers

Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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Consider the equilibrium of methanol vapor and the liquid.
CH₂OH(1) CH₂OH(g)
What is the vapor pressure of the methanol at -30 °C?
What is the vapor pressure of the methanol at 40 °C?
Thermodynamic Table at 25 °C
Substance AH; (kJ/mol) S (J/mol-K) AG; (kJ/mol)
CH₂OH(1)
126.8
CH₂OH(g)
239.9
Pvap 5
Pap
=
=
-239.2
-201.0
-166.6
-162.3
atm
atm

Answers

The vapor pressure of methanol at 40°C is 0.234 atm.

What distinguishes ethanol from methanol?

Only two types of alcohol are methanol and ethanol. Ethanol, sometimes referred to as ethyl alcohol, has a chemical composition of two carbon atoms. Methanol, sometimes referred to as methyl alcohol, is made up of just one carbon atom.

ln(P2/P1) = (ΔHvap/R) x (1/T1 - 1/T2)

ΔGvap = -RTln(Pvap/P) = ΔHvap - TΔSvap

ΔGvap = -RTln(Pvap/P) = -166.6 kJ/mol

ΔSvap = S(g) - S(l) = 239.9 J/mol-K - 126.8 J/mol-K = 113.1 J/mol-K

ΔHvap = ΔGvap + TΔSvap = -166.6 kJ/mol + (298.15 K)(113.1 J/mol-K) = -134.6 kJ/mol

Now we can use the Clausius-Clapeyron equation to find the vapor pressure of methanol at -30°C and 40°C.

At -30°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = -30°C + 273.15 = 243.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/243.15 K)

P2 = 0.0038 atm

Therefore, the vapor pressure of methanol at -30°C is 0.0038 atm.

At 40°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = 40°C + 273.15 = 313.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/313.15 K)

P2 = 0.234 atm

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100.00 mL of the 0.0250 M HNO3 solution by dilution of the 1.00 M HNO3
solution provided in the lab.

Answers

Taking into account the definition of dilution, the initial volume of the 1 M HNO₃ solution is 25 mL.

Definition of dilution

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volume

Volume required

Assuming that you want to know the volume of HNO₃ required to produce the dilution, you know:

Ci= 1.00 MVi= ?Cf= 0.250 MVf= 100 mL

Replacing in the definition of dilution:

1 M× Vi= 0.250 M× 100 mL

Solving:

Vi= (0.250 M× 100 mL)÷ 1 M

Vi= 25 mL

In summary, the initial volume of the 1 M HNO₃ solution is 25 mL.

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A sample of sugar (C12H22O11) contains
1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample? Answer without doing any calculations.

Answers

Answer: 0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N =  number of particles

Nᵃ = Avogadros constant = 6.02 x

So, n=

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

How many moles of MgS are in 1.00g MgS?

Answers

Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

Calculate the amount of heat required (in J) that is required to raise the temperature of a 4.516 g sample of a substance having a specific heat of 0.847 cal/g•°C from 41.2°C to 66.6°C.

Answers

Amount of heat required to raise the temperature of 4.516 g sample from 41.2°C to 66.6°C  is 406748 J.

What is specific heat?

Specific heat of a substance is defined as the amount of heat required to raise the temperature when one gram of substance is present by one degree Celsius.

Concept of specific heat was discovered when it came to notice that different substances require different amount of heat to raise the same amount of temperature.

It is usually given by the equation,

Q=mcΔT

where Q= heat

m=mass and c= specific heat

ΔT= change in temperature

For the given example, amount of heat is calculated by substituting the values in above equation

Q=4.516×3546.21×25.4=406748 J.

where,0.847 cal/g°C=3546.219 J/kgK

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An unknown compound, B, has the molecular formula C7H12. On catalytic hydrogenation 1 mol of B absorbs 2 mol of hydrogen and yields 2-methylhexane. B has significant IR absorption band at about 3300 and 2200 cm-1. Which compound best represents B?

Answers

Answer:

5-methylhex-1-yne//5-methylhex-2-yne//2-methylhex-3-yne

Explanation:

We have to start with the information on the IR spectrum. The signal at 3300 is due to a C-H bend sp carbon and the signal in 2200 is due to the stretch carbon-carbon. Therefore we will have an alkyne. Now if we have 2-methylhexane as the product of hydrogenation we have several options to put the triple bond. Between carbons 1 and 2 (5-methylhex-1-yne), between carbons 2 and 3 (5-methylhex-2-yne) and between carbons 3 and 4 (2-methylhex-3-yne). On carbon 5 we have a tertiary carbon therefore we dont have any other options.

See figure 1

I hope it helps!

An unknown compound, B, has the molecular formula C7H12. On catalytic hydrogenation 1 mol of B absorbs

- How many grams are in 1.4 x 10¹5 atoms of calcium?

Answers

Answer:

40 g= 6.022×10²³

x=1.4×10¹⁵

x=40g×6.022×10²³/1.4×10¹⁵

x=17.77×10⁸

a 24.37mol of gas occupied 5.32ml vessel. what mole of the gas should be removed to get a volume of 2.56ml?

Answers

Mole of the gas should be removed to get a volume of 2.56ml is 10.26 mol.

Equation :

Given data,

Volume₁ = 5.32ml

number of moles at 5.32ml n₁ = 24.37mol

Molarity = ?

Volume₂ = 2.56ml

number of moles = ?

First to find molarity of gas using formula,

M = nV

where,

M is molarity

n is numbers of mole

V is volume

So, putting the values of volume₁,

M = 24.37mol x 5.32ml

M = 129.65 mol/ml

So again to get moles of second volume in same formula we have,

M = nV

So,

n = M / V

n₂ = 129.65 / 2.56ml

n = 50.64mol

So,

n₂ - n₁ = 50.64mol - 24.37mol

n = 26.27

So,

mole of the gas removed = 26.27 / 2.56

mole of the gas removed = 10.26mol

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I am an unknown element located between Krypton and Argon. I am +1/2, +1/2, +1/2 in the p area when looking at my orbital configuration. I am a household item used to kill organisms. What am I?

Answers

The element between Krypton and Argon as decribed is; Niobium (Nb).

An element which is +1/2, +1/2, +1/2 in the p area when looking at it's orbital configuration can be described as follows;

Has 3 electrons in its outermost p-orbital.

In essence, it has, 5 electrons in its outermost shell including its 2 electrons in its outermost s-orbital.

The element is therefore am element with valency 5 between Krypton and Argon.

The element in discuss is Niobium (Nb).

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Draw the electron dot formula for carbon dioxide, CO2. How many nonbonding electron pairs are in a carbon dioxide molecule

Answers

Answer:

O=C=O.

Four nonbonding electron pairs.

Explanation:

Hello!

In this case, as you can see on the attached picture, there are two double bonds between the central carbon atom and those two oxygen atoms because each oxygen shares two electrons to the central carbon for them to attain the octet. Moreover, the enclosed dots represent the nonbonding electron pairs, which are four in total. It is importante to notice that carbon dioxide (O=C=O) has a complete octet whereas carbon monoxide (C=O) does has an incomplete octet for C.

Best regards!

Draw the electron dot formula for carbon dioxide, CO2. How many nonbonding electron pairs are in a carbon

cloruro de litio mas sodio​

Answers

Answer:

El cloruro de litio se utiliza para fabricar litio metálico. El cloruro de litio se funde y electroliza. Esto produce litio metálico líquido.

Explanation:

sowwy si mi español es malo

Answer:

give him brainliest

Explanation:

I NEED THIS DONE TODAY !!!!!!!!Electromagnetic Spectrum Lab Report
Destructions: In this virtual lab, you will use a virtual spectrometer to analyze astronomical
bodies in space. Record your hypothesis and spectrometric recular in the lab report below. You
will submit your completed report to your butructor.
Name and Title:
Include your name, instru
1
and name of lab.
Objectives (1):
In your own words, what is the purpose of this lab?
Hypothesis:
In this section, please include the predictions you developed during your lab activity. These
statements reflect your predicted outcomes for the experiment.
Procedure:
The materials and procedures are listed in your virtual lab. You do not need to repeat them here.
However, you should note if you experienced any errors or other factors that might affect your
outcome. Using your summary questions at the end of your virtual lab activity, please clearly
define the dependent and independent variables of the experiment.
Data:
Record the elements present in each unknown astronomical object. Be sure to indicate "yes" or
"no" for each element.
Hydrogen Helium Lithium Sodiam Carbon
Moon One
Moon Two
Planet One
Planet Two
Nitrogen
Conclusion:
Your conclusion will inchade a summary of the lab results and an interpretation of the results.
Please answer all questions in complete sentences using your own words.
1. Using two to three sentences, summarize what you investigated and observed in this lab
2. Astronomers use a wide variety of technology to explore space and the electromagnetic
spectrum; why do you believe it is essential to use many types of equipment when
studying space?
3. If carbon was the most common element found in the moons and planets, what element is
missing that would make them splat to Earth? Explain why. (Hint: Think about the
carbon cycle)
4.
We know that the electromagnetic spectrum uses wavelengths and frequencies to
determine a lot about outer space. How does it help us find out the make-up of stars?
5. Why might it be useful to determine the elements that a planet or moon is made up of?

 I NEED THIS DONE TODAY !!!!!!!!Electromagnetic Spectrum Lab ReportDestructions: In this virtual lab,

Answers

The answers to the virtual lab that specifies the use of a virtual spectrometer is given below:

The Results of the Virtual Lab

2. Space consists of bodies with different types of electromagnetic spectrum.

This includes high-energy bodies emitting radiation in short wavelengths and extremely short wavelengths such as in UV spectrum, X rays, and gamma rays.

Conversely, other bodies might be emitting radiations in longer wavelengths such as Microwaves and Radio waves.

Since these radiations are at two different ends of the electromagnetic spectrum, a large number of equipment would be required for individually studying these space-based radiation sources and their characteristics.

3. The element missing from the moons and the planets would be Oxygen. It is to be remembered that Oxygen forms the base of the sustenance of life forms on Earth and forms an indispensable part of the carbon cycle. In the absence of oxygen, these planets and moons remain lifeless.

4. Stars emit heat and light. Along with the heat and light, radiations are emitted by the star. These radiations travel outward from stars and work as the signature of the stars. By analyzing the radiations from the stars, scientists back on Earth could deduce the physical conditions in the heart of a star including its constitution, temperature, and surface conditions.

E.g., If the star is emitting radiation in longer wavelengths, this is an indication that the star is cooling down and the temperature is relatively low.

5. The knowledge of the constitution of the elements making up the moon or planet is necessary to ascertain the life-sustaining capability of the same. Through adequate knowledge of the composition of the moon/planet, the possibility of the life-sustaining ability of the same could be deduced.

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Which one of the following substances is a liquid fuel used in rocket engines?A) Potassium perchlorateB) Sodium nitrateC) AmmoniaD) Liquid oxygen

Answers

Most liquid chemical rockets use 2 separate propellants: a fuel and an oxidizer. Fuels include kerosene, alcohol, hydrazine, its derivatives, and liquid hydrogen.

Oxidizers include nitric acid, nitrogen tetroxide, liquid oxygen, and liquid fluorine.

Answer: D) Liquid oxygen

Calculate the amount of copper in moles in a 27.5g pure copper sheet

Answers

The amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To calculate the amount of copper in moles in a pure copper sheet, we need to use the molar mass of copper and the given mass of the sheet.

The molar mass of copper (Cu) is approximately 63.55 g/mol. This value represents the mass of one mole of copper atoms.

Given that the mass of the pure copper sheet is 27.5 g, we can calculate the number of moles using the following formula:

moles = mass / molar mass

Substituting the values:

moles = 27.5 g / 63.55 g/mol

moles ≈ 0.433 mol

Therefore, the amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To arrive at this result, we divided the given mass of the sheet (27.5 g) by the molar mass of copper (63.55 g/mol). This calculation allows us to convert the mass of the sheet into the corresponding number of moles of copper.

The result tells us that the 27.5 g pure copper sheet contains approximately 0.433 moles of copper atoms. This conversion to moles is useful in various chemical calculations and allows for easier comparison and analysis of quantities on a molecular scale.

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Match the solution with the correct concentration.

Match the solution with the correct concentration.

Answers

Answer:

1. is Molar (with capital M)

2. is molal (m)

Explanation:

By definition, 1 Molar solutions have 1 mol of solute in 1 L of solution and 1 molal solutions have 1 mol of solute in 1 Kg of solvent

how many grams of Na2SO4, (molar mass =142.0 g/mol) are there in 15 mL of 0.50 m Na2SO4 solution?

Answers

Answer:

1.1 g Na2SO4

Explanation:

First convert mL to L. Then multiply by the Molarity to get moles, then multiply by the molar mass to get grams.

15 mL x     1 L       x       0.50 mol Na2SO4     x        142 g        =          1.1 g

              10^3 mL                 1 L                                   mol                     Na2SO4

In a formula unit, there are 48 gram of Na2SO4 atoms of each element. In terms of molar mass (gram mass unit): 45.98 g Na2SO4 in total 142.04 g sodium sulphate

How many moles of Na2SO4 are there?

A mole of sodium sulphate is created when two moles of sodium (45.98 g), one mole of sulphur (32.06 g), and four moles of oxygen (64.00 g) are combined (142.04 g).

The atomic mass of sodium sulphite is equal to 10 moles times the molecular mass, or 1260 grams. Consequently, 1260 grams are the mass of 10 moles of sodium sulphite (Na2SO4).

We first obtain the atomic weights of the different elements in a periodic table in order to compute the molar mass of a molecule. Then, we multiply the total number of atoms by each one's atomic mass. Finally, we calculate the molar mass by combining all the atomic masses.

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embalming authorization may be given by all of the following except the? Bailee, next of kin, spouse, or decedent

Answers

The correct answer is "decendent." Embalming authorization may be given by the bailee, next of kin, or spouse, but not by the decedent.

When is the authorization given?

The term "decedent" refers to the person who has died; they are unable to give consent for embalming or any other post-mortem procedures. According to legal and cultural customs, the choice to embalm is often taken by the designated representative, such as the bailee (person in charge of the body), next of kin, or spouse.

Hence, embalming authorization may be given by the bailee, next of kin, or spouse, but not by the decedent.

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Identify which of the following equations are balanced and which ones are not balanced

A. CH4 +202 —> CO2 + 2H20

B. 6CO2 + 6H2O—> C6H12O6+602

C. 2Na + H2O —> 2NaOH+ H2

Answers

Answer:

A. balancedB. UnblalancedC. Unbalanced

Explanation:

solve the equation 2x-9=13​

Answers

I think it is x=11.

2x=13+9
2x=22
X=11

Answer:

x = 11

Explanation:

2x - 9 = 13

2x = 13 + 9

2x = 22

x = 11

Use the reaction to answer the question.
Fe2O3 + 3H2SO4
How many atoms of oxygen will be found in the product(s) of the reaction?
4
15
12
3

Answers

Answer:

The Correct answer is 15

Answer:

B). 15

Explanation:

How many moles of nitrogen gas is 40.0 g?

Answers

Answer:

1.43 moles N₂

Explanation:

To determine the moles of nitrogen gas (N₂), you need to multiply the given value by the molar mass. The molar mass is a ratio comparing the mass (g) of nitrogen gas per 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (grams should be in the denominator). The final answer should have 3 sig figs to match the given value.

Molar Mass (N₂): 2(14.007 g/mol)

Molar Mass (N₂): 28.014 g/mol

 40.0 grams N₂                1 mole
-------------------------  x  ------------------------  =  1.43 moles N₂
                                    28.014 grams

i think the answer could be 1.43 moles

CaC2 + 2H2O ➞ C2H2 + Ca(OH)2
a) If 32.0 g CaC2 are used in this reaction, how many moles of calcium hydroxide are produced?
b) How many moles of water are needed to produce 56.8 g C2H2?

Answers

Answer:

A. 0.5 mole of Ca(OH)₂.

B. 4.37 moles of H₂O.

Explanation:

The balanced equation for the reaction is given below:

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

Next, we shall determine the mass of CaC₂ that reacted and the mass of C₂H₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaC₂ = 40 + (12×2)

= 40 + 24

= 64 g/mol

Mass of CaC₂ from the balanced equation = 1 × 64 = 64 g

Molar mass of C₂H₂ = (12×2) + (2×1)

= 24 + 2

= 26 g/mol

Mass of C₂H₂ from the balanced equation = 1 × 26 = 26 g

SUMMARY:

From the balanced equation above,

64 g of CaC₂ reacted with 2 moles of H₂O to produce 26 g of C₂H₂ and 1 mole of Ca(OH)₂.

A. Determination of the number of mole of Ca(OH)₂ produced by the reaction of 32.0 g of CaC₂.

From the balanced equation above,

64 g of CaC₂ reacted to produce 1 mole of Ca(OH)₂.

Therefore, 32 g of CaC₂ will react to produce = (32 × 1)/64 = 0.5 mole of Ca(OH)₂.

Thus, 0.5 mole of Ca(OH)₂ were obtained from the reaction.

B. Determination of the number of mole of H₂O needed to produce 56.8 g C₂H₂.

From the balanced equation above,

2 moles of H₂O reacted to produce 26 g of C₂H₂.

Therefore, Xmol of H₂O will react to produce 56.8 g C₂H₂ i.e

Xmol of H₂O = (2 × 56.8)/26

Xmol of H₂O = 4.37 moles

Thus, 4.37 moles of H₂O is needed for the reaction.

1. How many ATOMS of carbon are present in 7.48 grams of carbon monoxide ?

Answers

Answer:

The answer is 1.61 × 10²³ atoms

Explanation:

To determine number of atoms, we will use the formula below

Number of atoms = number of moles (n) × avogadro's constant (6.02 x 10²³)

n was not provided, hence we will solve for n

n = mass/ molar mass

molar mass of carbon monoxide, CO (where C is 12 and O is 16) is 12 + 16 = 28

mass was provided in the question as 7.48

n = 7.48/28

n = 0.267

Hence,

number of atoms = 0.267 × 6.02 x 10²³

= 1.61 × 10²³ atoms

Net ionic equation for potassium sulfide and magnesium iodide

Answers

The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. At standard temperature and pressure (STP; 273.15 K and 1 atm , respectively), one mole of gas occupies 22.4 L of volume. What mass of methanol ( CH3OH ) could you form if you reacted 7.82 L of a gas mixture (at STP) that contains an equal number of carbon monoxide ( CO ) and hydrogen gas ( H2 ) molecules?

Answers

You could form approximately 5.8 grams of methanol (CH3OH) from the given gas mixture at STP.

What is the mass?

Using the Ideal gas equation;

n = PV / RT

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

From the question;

nCO = n / 2

nH2 = n / 2

Then;

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n = 0.362 mol

nCO = n / 2 = 0.362 mol / 2 = 0.181 mol

nH2 = n / 2 = 0.362 mol / 2 = 0.181 mol

By stoichiometry;

methanol= nCO = 0.181 mol

Mass of methanol =  0.181 mol * 32.04 g/mol

= 5.8 g

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The graph shows the altitude and temperature for different layers of Earth’s atmosphere. Based on the diagram, which of the following identifies a characteristic of the atmosphere between the stratopause and the tropopause?
answer choices
Cloud formation occurs in the stratosphere.
The warmest air is found in the mesosphere.
The ozone layer is in the stratosphere.
The troposphere is the closest layer to the sun.

The graph shows the altitude and temperature for different layers of Earths atmosphere. Based on the

Answers

The ozone layer is present in the stratosphere layer of the Earth's atmosphere. Therefore, option (C) is correct.

What is the atmosphere?

An atmosphere can be defined as layers of gases that envelop a planet and is held in place due to the gravity of the planetary body. A planet contains an atmosphere when the gravity is great and the temperature of the atmosphere of any planet is low.

Earth's atmosphere is made of Nitrogen (78 %), Oxygen (21%), Argon (0.9%), and Carbon dioxide (0.04 %).  The troposphere can be defined as the lowest layer of the atmosphere. The troposphere contains 75 to 80 % of the mass of the atmosphere.

The stratosphere contains the ozone layer, at an altitude between 15km and 35km. This atmospheric layer absorbs most of the UV radiation that Earth receives from the Sun.

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How many moles of NaCl are there in 40.3 g of sodium chloride?

Please answer all the questions in the picture below
Thank you

How many moles of NaCl are there in 40.3 g of sodium chloride?Please answer all the questions in the

Answers

Answer:

58.44277 gram

Explanation:

A student sets up the following equations to convert a measurement

A student sets up the following equations to convert a measurement

Answers

1dl/100ml is the missing part of the equation

How to solve the equation

Equations are not typically measured in the same way that physical quantities are measured.

An equation is a mathematical statement that shows that two expressions are equal. Equations can be used to represent a variety of relationships in mathematics, physics, chemistry, and other fields.

we know that 0.01 dl is the same as 1 ml = 1 / 100

-3.4 x 10^3 ml x 1 dl/100 = -34 dl

hence the answer to the missing part is given as 1dl/100

The solution of the equation is given as -34dl

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(c) 45 g C,H, react with 45 g Cl₂ according to the equation:
Cl₂ + C6H6 C6H5Cl + HCI. What is the limiting reactant? What mass of HCI will be produced?
-

Answers

In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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