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The dual for the given linear programming problems are as follows:

(i) Minimize Z' = 10a + 12b Subject to: a + 7b ≥ 3 2a + 3b ≥ 4 a + 9b ≥ 5 a, b ≥ 0.

(ii) Maximize Z' = 5a + 6b + 2c Subject to: 3a + 2b + c ≤ 1 4a + 6b + c ≤ 2 a + b ≤ 0 a, b, c ≥ 0.

In the first problem, we have a maximization problem with three variables (x, y, z) and two constraints. The dual formulation involves minimizing a new objective function with two variables (a, b) and four constraints. The coefficients of the variables and the constraints are transformed according to the rules of duality.

The primal problem is:

Maximize Z = 3x + 4y + 5z

Subject to:

x + 2y + z ≤ 10

7x + 3y + 9z ≤ 12

x, y, z ≥ 0

To find the dual, we introduce the dual variables a and b for the constraints:

Minimize Z' = 10a + 12b

Subject to:

a + 7b ≥ 3

2a + 3b ≥ 4

a + 9b ≥ 5

a, b ≥ 0

In the second problem, we have a minimization problem with two variables (y1, y2) and three constraints. The dual formulation requires maximizing a new objective function with three variables (a, b, c) and four constraints. Again, the coefficients and constraints are transformed accordingly.

The primal problem is:

Minimize Z = y1 + 2y2

Subject to:

3y1 + 4y2 > 5

2y1 + 6y2 ≥ 6

y1 + y2 ≥ 2

To find the dual, we introduce the dual variables a, b, and c for the constraints:

Maximize Z' = 5a + 6b + 2c

Subject to:

3a + 2b + c ≤ 1

4a + 6b + c ≤ 2

a + b ≤ 0

a, b, c ≥ 0

The duality principle in linear programming allows us to find a lower bound (for maximization) or an upper bound (for minimization) on the optimal objective value by solving the dual problem. It provides useful insights into the relationships between the primal and dual variables, as well as the economic interpretation of the problem.

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Solving for q will give us the optimal quantity that maximizes the profit,  a function that gives the total profit earned can be written as:

Profit(q) = (Revenue per item - Cost per item) * q

Assuming that the revenue and cost are functions of the quantity sold (q), the total profit can be calculated as follows:

Profit(q) = Revenue(q) - Cost(q)

To find the quantity which maximizes the profit, we can take the derivative of the profit function with respect to q and set it equal to zero, and then solve for q:

Profit'(q) = Revenue'(q) - Cost'(q) = 0

Solving for q will give us the quantity that maximizes the profit. However, without knowing the specific forms of the revenue and cost functions, we cannot write a specific profit function or find the quantity that maximizes the profit.

In general, the profit function can be written as:

Profit(q) = (Revenue per item - Cost per item) * q

where the revenue per item and cost per item are functions of q. To find the quantity that maximizes the profit, we need to differentiate the profit function with respect to q and set it equal to zero:

Profit'(q) = Revenue'(q) - Cost'(q) = 0

Solving for q will give us the optimal quantity that maximizes the profit.

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Answer:

x = 2

Step-by-step explanation:

AB is given as 3(3x-1) multiply inside the parenthesis with 3

AB = 9x - 3

AC is given as 5(2x+2) multiply inside the parenthesis with 5

AC = 10x + 10

if B is midpoint of AC then AB = BC and AC = AB + BC if we write this equation using the given values

9x - 3 + 9x - 3 = 10x + 10 add like terms

18x - 6 = 10x + 10 transfer like terms to the same side of the equation

18x - 10x = 10 + 6

8x = 16 divide both sides by 8

x = 2 replace x with 2 in given expressions to find the value of each component

Answer:   x = 2; AB = 15; BC = 15; AC = 30

Step-by-step explanation:

AB = BC = 3(3x - 1) = 9x - 3

AC = 5(2x + 2) = 10x + 10

AB + BC = AC

(9x - 3) + (9x - 3) = 10x + 10

   9x - 3 + 9x - 3 = 10x + 10

               18x - 6 = 10x + 10

                8x - 6 = 10

                      8x = 16

                        x = 2

Plug x = 2 to find AB, BC, and AC.

AC = BC = 3(3x - 1) = 9x - 3 = 9(2) - 3 = 18 - 3 = 15

AC = 5(2x + 2) = 10x + 10 = 10(2) + 10 = 20 + 10 = 30

Answer:

A

Step-by-step explanation:

If the equation of the line is written in slope-intercept form, y = mx + b then the value of b will be -21; the correct answer is option A.

Slope tells how vertical a line is.

The more the slope is, the more the line is vertical. When slope is zero, the line is horizontal.

To find the slope, we take the ratio of how much the line's height increases as we go forward or backward on the horizontal axis.

This is because the more the height of the line to thee amount we walk or run on the horizontal axis, the more the slope is. That is why we took difference of horizontal axis in denominator and difference of vertical axis on numerator.

Formula for slope, thus, is;

Slope = (y₂ - y₁) / (x₂ - x₁)

Parameters;

J(-4, -5) and K(-6, 3)

= (3 - (-5)) / (-6 - (-4))

= (3 + 5) / (-6 + 4)

= 8 / -2

= -4

Substitute one of the coordinates into the formula to solve for b

y = mx + b

y = -4x + b

3 = -4(-6) + b

3 = 24 + b

3 - 24 = b

b = - 21

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9514 1404 393

Answer:

  2

Step-by-step explanation:

The steps in x are 1 -(-2) = 3, and the steps in y are -5 -(-11) = 6. The "rate of change" is the ratio of the change in y to the change in x:

  m = ∆y/∆x = 6/3 = 2

The rate of change represented by the values in the table is 2.

_____

Additional comment

The table can be described by ...

  y = 2x -7

Answer:

101.8 lb

Step-by-step explanation:

1760 sq ft are covered by 40 lb

4480 sq ft are covered by x

1760/40 = 4480/x

1760x = 40 × 4480

x = 179,200/1760

x = 101.818181...

Answer: 101.8 lb

Answer:

b

Step-by-step explanation:

You multiply from left to right

Step-by-step explanation:

ABC is an isoceles triangle (both legs are equally long). and AB is its baseline.

OC is now a median for ABC splitting the angle at C and AB in half.

so, we have 2 right-angled triangles : OAC and OBC.

the half-angles at C are 42/2 = 21°.

the angles at A and B are 90°.

and the half-angles at O are 180 - 90 - 21 = 69°.

remember that the sum of all angles in a triangle must always be 180°.

AB are the heights of both of these triangles.

the single height is sin(69)×7 = 6.535062985... cm

and so,

AB = 2× height = 13.07012597... cm.

The correct statement are:

Based on the given information, we can make the following conclusions:

A. The interquartile range for high school students is smaller than college students.

The statement is False

B. The mean for high school students is smaller than college students.

The statement is False because the mean of College is 25.28 and mean for High school is 30.4.

C. The range for high school students is larger than college students.

The statement is True .

D. The college median is equal to the high school median.

The statement is True because the median for both is 24..

E. The mean absolute deviation is larger for college students than high school students.

The statement is False.

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This proof shows that the zero vector is in Col A, the vector Ax C Aw is in Col A, and c.Ax/ is in Col A, given a scalar c. This proves Theorem 3, which states that an element in Col A has the form Ax for some x in Rn.

a. The zero vector is in Col A because it is the result of multiplying the zero vector in Rn by matrix A. Therefore, A(0) = 0, which is the zero vector in Col A.

b. To show that the vector Ax C Aw is in Col A, we need to show that Ax C Aw can be written in the form A(x + w) for some vectors x and w in Rn. Since Ax and Aw are in Col A, they can be written as A(x) and A(w) for some vectors x and w in Rn. Therefore, Ax C Aw = A(x + w). Thus, the vector Ax C Aw is in Col A.

c. Given a scalar c, we need to show that c.Ax/ is in Col A. We can rewrite c.Ax/ as cA(x). Since A(x) is in Col A, then cA(x) is also in Col A. Therefore, c.Ax/ is in Col A.

This proof shows that the zero vector is in Col A, the vector Ax C Aw is in Col A, and c.Ax/ is in Col A, given a scalar c. This proves Theorem 3, which states that an element in Col A has the form Ax for some x in Rn.

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Answer:

I have the same question and I need it answeeed

Step-by-step explanation:

Answer:

22.538890116862454

Step-by-step explanation:

......

The ∆ABC is an isosceles triangle and have the base angles m∠A and m∠C equal to 51° and the angle m∠B is equal to 78°.

An isosceles triangle have the measure of its base angles to be equal, and the sum of the interior angles sum up to 180°.

Given that sides AB ≅ BC, then the triangle ∆ABC has two sides with similar length and base angles so;

angles m∠A and m∠C are the base angles are both equal to 51°

m∠B = 180° - (51 + 51)° {sum of interior angles of a triangle}

m∠B = 180° - 102°

m∠B = 78°

Therefore, the isosceles triangle ∆ABC have the base angles m∠A and m∠C equal to 51° and the angle m∠B is equal to 78°.

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Nested loops are a key component of pattern matching algorithms, as they are used to search for a pattern within a larger set of data.

Pattern matching algorithms typically involve comparing each element of the pattern to each element of the data set, which is accomplished using nested loops. The outer loop iterates over the data set, while the inner loop iterates over the pattern. For each iteration of the outer loop, the inner loop compares the elements of the pattern to the corresponding element in the data set. If the elements match, the algorithm continues to the next iteration of the inner loop. If all elements of the pattern match their corresponding elements in the data set, then the algorithm has found the pattern and can take the appropriate action.

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The line of the  best fit for the data points plotted in the scatter plot is y = -0.88x + 8

From the question, we have the following parameters that can be used in our computation:

The graph

Using the line of the best fit, we have"

(x, y) = (8, 1) and (0, 8)

A linear equation is represented as

y = mx + c

Where

c = y when x = 0

So, we have

y = mx + 8

Using the points, we have

1 = 8m + 8

This gives

m = -0.88

So, we have

y = -0.88x + 8

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Answer:

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find an equation of a line given two points first find the slope / gradient

Slope of the line using points (-1,4) and (-2,2) is

\(m = \frac{2 - 4}{ - 2 + 1} = \frac{ - 2}{ - 1} = 2\)

So the equation of the line using point (-1,4) is

Hope this helps you

The equation of the function is: H = 4t + 10.

The y-intercept of the function is 10, which is the height of the plant when Liam initially bought it.

To write the equation of a function, first, find the slope (m) = rise / run. You can pick any two points on the line to find the slope. Next, find the y-intercept (b) which is the point where the line intercepts the vertical axis of the graph.

Find the slope using the two points from the given graph, (5, 30) and (10, 50):

Slope (m) = change in H / change in t = (50 - 30) / (10 - 5) = 20/5

m = 4

The y-intercept is b = 10 [in this context, it is the height of the plant when Liam initially bought it]

To write the equation of the function, substitute m = 4 and b = 10 into H = mt + b:

H = 4t + 10

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Answer:

y=(-4x+6)/9

Step-by-step explanation:

minus 4x from both sides

divide by 9

Answer: -4/9 x + 2/3

Step-by-step explanation:

Let's solve for y.

6=4x+9y

Step 1: Flip the equation.

4x+9y=6

Step 2: Add -4x to both sides.

4x+9y+−4x=6+−4x

9y=−4x+6

Step 3: Divide both sides by 9.

9y/9 = -4x+6/9

Answer:

y= -4/9x + 2/3

The expression that would render the both the sides equivalent is 3x+2-2

In Algebra, the like terms are defined as the terms that contain the same variable which is raised to the same power. In algebraic like terms, only the numerical coefficients can vary. We can combine the like terms to simplify the algebraic expressions.

Given here: The expression 2+8x-16

To find its equivalent we have an incomplete expression 5(x-3)+1

Now 5(x-3)+1=5x-15+1

                     =5x-14

Thus Adding 3x+2-2 to this expression we get

5x-14+3x+2-2=2+8x-16

Therefore, we can deduce that the missing term must be 3x+2-2

Hence, The missing expression is 3x+2-2

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Answer:

g(6) = 9

Step-by-step explanation:

Explanation attached

72 = 3x + 6 equation represents if each pie was then cut into six pieces and sold. There were a total of 72 pieces to sell.

In mathematics, an equation is an expression or a statement that consists of two algebraic expressions that have the same value and are separated from one another by the equal symbol. It is an otherwise stated proposition that has been mathematically quantified. There are numerous possible equation types. To equate two expressions, we employ equations.

Given,

The Cooking Club made some pies to sell during lunch to raise money for a field trip. The cafeteria helped by donating three pies to the club.

Each pie was then cut into six pieces and sold.

There were a total of 72 pieces to sell.

Equation representing this equation is:

72 = 3x + 6

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Thus, the test for homogeneity follows the same procedures as the test for independence because the assumptions for performing the chi-square test for independence and chi-square test for homogeneity are the same.

The procedures for the chi-square test of homogeneity are the same as for the chi-square test of independence. The data is different for both tests. Tests of independence are used to determine whether there is a significant relationship between two categorical variables from the same population. One population is segmented based on the value of two variables. So there will be a column variable and a row variable.

The chi-square test of homogeneity of proportions can be used to compare population proportions from two or more independent samples, determining whether the frequency counts are distributed identically among different populations.

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The standard form of the given numbers is 207360 × 10¹⁷.

The number system is a way to represent or express numbers.

A decimal number is a very common number that we use frequently.

Since the decimal number system employs ten digits from 0 to 9, it has a base of 10.

Any of the multiple sets of symbols and the guidelines for utilizing them to represent numbers are included in the Number System.

Given the numbers is  (5 x 1,000,000) (6 x 100,000) (4 x 10,000) (8 x 1,000) (3 x 100) (2 x 10) (4 x 0.1) (9 x 0.001)

Now standard form means we need to write the exponents form.

So,

5 x 6 x 4 x 8 x 3 x 2 x 4 x 9 = 207360

And

1,000,000 x  100000 x 10000 x 1000 x 100 x 10 x 0.1 x 0.001 = 10¹⁷

So, combine 207360 x  10¹⁷

Hence "The standard form of the given numbers is 207360 × 10¹⁷".

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Answer:

7^2+2ab - 4b^2

Step-by-step explanation:

A² + b² = 7b

b² + (2b-a) ²= 7²

FOIL

b^2 +4b^2-4ba+a^2= 7^2

Rewriting

a^2 -2ab + b^2    +4b^2 -2ab = 7^2

Add 2ab and subtract 4b^2 from each side

a^2 -2ab + b^2    +4b^2 - 4b^2 -2ab+2ab = 7^2+2ab - 4b^2

a^2 -2ab + b^2    = 7^2+2ab - 4b^2

(a-b)^2 = 7^2+2ab - 4b^2

Answer:

8

Step-by-step explanation:

In order to find the range you need to subtract maximum card number from the minimum card number. We know that the range is 5 and that the minimum card is 6 so we can set up the equation like this to find the maximum shown as x.

\(5=x-6\)

Add 6 to both sides

\(11=x\)

Now we know all the the numbers of the three cards Anthony has since we were given the minimum = 6, 7, and solved for the last card which was the maximum = 11. In order to find the mean we have to add all of the numbers then divide by how many numbers there are (in this case it will be 3):

\(mean=\frac{6+7+11}{3}\)

Add 6+7+11

\(mean=\frac{24}{3}\)

Divide by 3

\(mean=8\)

Answer:

Step-by-step explanation:

STU is an equilateral triangle. And:

All sides are equal. Then take one pair and solve for x:

Substitute x to find the side length:

64.77% of a given amount remains after 900 years.

To determine the percentage of radioactive radium remaining after 900 years, we'll use the half-life formula:

Final Amount = Initial Amount * \(1/2^{(time elapsed / half-life)}\)

In this case, the half-life is 1599 years and the time elapsed is 900 years. We want to find the percentage remaining, so let's assume the initial amount is 100%.

Final Amount = 100 * \((1/2)^{(900 / 1599)}\)

Now, we'll calculate the exponent:

Exponent = 900 / 1599 ≈ 0.5635

Then, we'll compute the final amount:

Final Amount ≈ 100 * \((1/2)^{0.5635}\) ≈ 100 * 0.6477 ≈ 64.77%

After 900 years, approximately 64.77% of the initial radioactive radium remains. This percentage was found using the half-life formula, which accounts for the exponential decay of radioactive substances over time.

The formula shows how the remaining amount of a substance decreases as time progresses based on its half-life, which is the time it takes for half of the substance to decay. In this scenario, radium's half-life of 1599 years and the 900-year time frame were used to determine that roughly 64.77% of the initial radium remains.

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Answer:

Left box:  1/2n

Right box = 2n - 22

Step-by-step explanation:

Since we want one-half the number and n represents the unknown number, we have 1/2n on the left-hand side of the equation.

Thus, you want to put 1/2n in box on the left.

Twice the number and 22 less than this is given by:  y: 2n - 22 less than this means we subtract.  Thus, we have 2n - 22 as the numerator on the right hand side of the equation.

Thus, you want to put 2n - 22 in the box on the right.

Answer:

Step-by-step explanation:

The account value is given by the compound interest formula:

  A = P(1 +r/12)^n

Principal P invested at annual rate r compounded monthly for n months.

__

Using your parameters, the account balance would be ...

  A = $3000(1 +0.016/12)^66 = $3275.77 . . . account balance

The interest is the difference between this balance and the original investment amount:

  interest = $3000 -3275.77 = $275.77 . . . interest

Answer:

The explicit rule is N = s · 4

Step-by-step explanation:

Shapes (s) is multiplied by 4 which equals N