Brand X sells 21 oz. bags of mixed nuts that contain 29% peanuts. To make their product they combine Brand A mixed nuts which contain 35% peanuts and Brand B mixed nuts which contain 25% peanuts. How much of each do they need to use? Show all work.

explain your steps and answer clearly

Therefore, to the nearest tenth, about 25.8% of Kylie's commutes will be shorter than 45 minutes.

Percentage is a way of expressing a number as a fraction of 100. It is often represented by the symbol "%". For example, if you have 50 apples and you want to express what proportion of those apples are red, you might say "50% of the apples are red". This means that 50 out of 100, or 0.5 out of 1, of the apples are red.

Given by the question.

We can use the Z-score formula to calculate the percentage of Kylie's commutes that will be shorter than 45 minutes:

Z = (X - μ) / σ

where X is the value, we want to find the probability for, μ is the mean, and σ is the standard deviation.

Substituting the given values, we get:

Z = (45 - 47) / 3 = -0.67

To find the percentage of commutes that will be shorter than 45 minutes, we need to find the area under the normal distribution curve to the left of the Z-score of -0.67. We can use a standard normal distribution table or calculator to find this area, which is approximately 25.8%.

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The exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3

To verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5], we need to check if the following conditions are satisfied:

Let's check each condition:

f(x) = x³ - 10x² + 31x - 30 is a polynomial function and is continuous for all real values of x. So, it is continuous on [2, 5].

To check the differentiability, we need to find f'(x):

f'(x) = 3x² - 20x + 31.

The derivative f'(x) exists and is continuous for all real values of x. So, f(x) is differentiable on (2, 5).

Now, let's evaluate f(2) and f(5):

f(2) = (2)³ - 10(2)² + 31(2) - 30 = -10

f(5) = (5)³ - 10(5)² + 31(5) - 30 = 95

Since f(2) = -10 is not equal to f(5) = 95, we can conclude that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5] after differentiable.

To find the values of c in the interval (2, 5) such that f'(c) = 0, we need to solve the equation f'(c) = 3c² - 20c + 31 = 0.

Using quadratic formula:

c = (-(-20) ± sqrt((-20)² - 4(3)(31))) / (2(3))

c = (20 ± sqrt(400 - 372)) / 6

c = (20 ± sqrt(28)) / 6

c = (20 ± 2sqrt(7)) / 6

c = (10 ± sqrt(7)) / 3

The values of c in the interval (2, 5) such that f'(c) = 0 are:

c = (10 + sqrt(7)) / 3

c = (10 - sqrt(7)) / 3

Therefore, the exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3.

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Incomplete question:

Verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² +31x-30 on the interval [2, 5]. Then find all values of c in the interval such that f' (c) = 0.

Enter the exact answers in increasing order.

To enter √a, type sqrt(a)

c = ?

Answer:

the answer is no solution

Answer:

2

Step-by-step explanation:

Answer:

2x + 19.

Step-by-step explanation:

The reasoning behind this is that one must find the disparity between the first and second expressions - 9x+14 and 7x-5.  To do this, one subtracts 7x-5 from 9x+14.  Set this up as though it were a normal subtraction problem - 9x+14 over 7x-5 with the little subtraction symbol to the left.  When subtracting the negative five from fourteen, one adds the five to the fourteen due to the fact that the five was already negative and as such the negatives cancel out.  The 7x is simply subtracted from the 9x, resulting in 2x.  This leads to 2x + 19.

Answer:

The order of rotational symmetry of the wheel is;

C) 12

Step-by-step explanation:

The order of rotational symmetry of a shape is given by the sum of the times the shape can by rotated round 360° and still appears to be exactly the same as it was before being rotated

The given wheel has 6 pairs of similar in-line spokes such that there are a total of 12 spokes

The wheel looks the same each time the next spoke moves to the position of the previous spoke

Therefore, the number of times the wheel looks exactly the same while turning 360° is 12 times

Therefore, the order of rotational symmetry of the wheel = 12.

300 degrees

Step-by-step explanation:

Rearrange first

9,13,37,39

median=13+37÷2

=25

median is 25

mean=9+13+37+39÷4

=98÷4=24.5

Mean=24.5

Answer:

2109 meter squared

Step-by-step explanation:

\(Area \: of \: path \\ = (400+3)(300+3)-400 \times 300 \\ = 403 \times 303 - 120000 \\ = 122,109 - 120000 \\ = 2109 \: {m}^{2} \)

The scenario assumed to be the number of flips until you land on a head is P(x) = 1 + (1 - p)/p.

Given info,

If you have an unfair coin with probability p heads, what is the expected number of flips before you end up with a head,

To solve the above condition, have a formula;

P(x) = 1 + ( 1 - p )/p

Hence, P(x) = 1 + ( 1 - p )/p is the case expected to number of flips before you end up with a head.

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Answer:

17.25

Step-by-step explanation:

divide the pay by hours worked

Answer:

-3.6*10-1

Step-by-step explanation:

(38-9)-(74-8)=29-66=-37

Answer:

0.0061728395

Step-by-step explanation:

BOOM

Answer:

Step-by-step explanation:

Sum of digits of rank even - sum of digits of rank odd  must be a multiple of 11

(5+4+m+1)-(1+6+0)=11*k

10+m-7=11*k

3+m=11*k

m=8

Proof: 1086415/11=98765

To estimate the project's beta, we need to make assumptions and use available data. Given the information provided for a publicly traded firm in the same line of business, including the debt outstanding, number of shares, stock price per share, book value of equity per share, and the beta of equity, we can calculate an estimate of the project's beta.

The beta measures the systematic risk of an investment relative to the overall market. To estimate the project's beta, we can use the leveraged beta approach. Since the project will be financed with equity, we assume that the project's beta will be equal to the equity beta of the publicly-traded firm in the same line of business. Therefore, the estimated beta of the project would be 1.19, based on the given information.

It is important to note that this estimation relies on the assumption that the project's risk profile and systematic risk are similar to that of the publicly-traded firm used as a reference. Additionally, this approach assumes that the project is solely financed with equity and does not take into account any potential debt financing or other factors that may affect the project's beta.

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The correct statement is "Stores A and B have an equal spread." (option b).

To determine the spread of the data, we first need to find the range. The range is calculated by subtracting the smallest number from the largest number in a dataset.

For Store A:

The smallest number recorded is 2, and the largest number is 4. Therefore, the range of Store A is 4 - 2 = 2.

For Store B:

The smallest number recorded is 3, and the largest number is 5. Thus, the range of Store B is 5 - 3 = 2.

Comparing the ranges of both stores, we see that both Store A and Store B have the same range, which means the spread of the data is equal for both stores.

Therefore, the correct statement is:

b) Stores A and B have an equal spread.

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Answer:

48

Step-by-step explanation:

Answer:

48

Step-by-step explanation:

A Type II error occurs when we fail to reject a null hypothesis that is actually false. In this case, the null hypothesis is that the proportion of students who were quarantined at some point during the Fall Semester of 2020 is equal to or less than 0.65.

The alternative hypothesis is that the proportion is greater than 0.65. If we make a Type II error, we fail to reject the null hypothesis when it is actually false, meaning we do not conclude that the proportion is higher than 0.65 even though it actually is higher.

Therefore, the correct explanation for a Type II error, in this case, we would be: "Did not conclude the percent was higher than 65%, but it was higher."

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The probability that event will not occur is 0.68 (1-0.32). The odds for event are 32:68 or simplified to 8:17 (divide both sides by 4). The odds against event are 68:32 or simplified to 17:8 (divide both sides by 4).

Given that the probability of the event occurring is 0.32, we can find the probability of the event not occurring by subtracting this value from 1:

Probability (Event Not Occurring) = 1 - Probability (Event Occurring) = 1 - 0.32 = 0.68

So, the probability that the event will not occur is 0.68.

Now, let's find the odds for the event. Odds for an event is calculated as:

Odds For = Probability (Event Occurring) / Probability (Event Not Occurring) = 0.32 / 0.68 ≈ 0.47

So, the odds for the event are approximately 0.47 to 1.

Lastly, let's calculate the odds against the event:

Odds Against = Probability (Event Not Occurring) / Probability (Event Occurring) = 0.68 / 0.32 ≈ 2.13

Therefore, the odds against the event are approximately 2.13 to 1.

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Using the properties of densit function,

we get that f(y) has satisfied property of a density function. So, it a density function.

A probability density function, or density function, returns the value of a function at a given value of x.

The probability density function must satisfy two requirements:

We have given that, Y is a random variable and

b f(y) = by² , y>b

where , b --> the minimum possible time needed to traverse the maze.

we have check that f(y) is Probability density function or not . For this check above two requirements ,

(i) f(y) ≥ 0 for all y > 0

so, it's satisfied

(ii) Integral over all values of the random variable ₓ∫ⁿ f(y)dy = ₓ∫ⁿ(b/y²)dy where n=∞ and x = b

= ₓ[ -b/y]ⁿ

= -(0-1) = 1

Hence , f(y) is density function.

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The radius of convergence, R, of the series is 1/7. The interval of convergence, I, is (-8, -6) U (-6, -6 + 1/7) U (-6 + 1/7, -6 + 2/7) U (-6 + 2/7, -6 + 3/7) U ... U (∞, ∞).

To find the radius of convergence, we can use the ratio test. Let's apply the ratio test to the given series:

\[ \lim_{{n \to \infty}} \left| \frac{{a_{n+1}}}{{a_n}} \right| = \lim_{{n \to \infty}} \left| \frac{{2(x + 7)^{n+1} 7^{n+1} \ln(n+1)}}{{2(x + 7)^n 7^n \ln(n)}} \right| \]

Simplifying this expression, we get:

\[ \lim_{{n \to \infty}} \left| \frac{{2(x + 7) 7 \ln(n+1)}}{{\ln(n)}} \right| \]

We can rewrite this as:

\[ 2(x + 7) 7 \lim_{{n \to \infty}} \left| \frac{{\ln(n+1)}}{{\ln(n)}} \right| \]

Now, we evaluate the limit of the ratio of natural logarithms:

\[ \lim_{{n \to \infty}} \left| \frac{{\ln(n+1)}}{{\ln(n)}} \right| = 1 \]

Therefore, the ratio test simplifies to:

\[ 2(x + 7) 7 \]

For the series to converge, this value must be less than 1. So we have:

\[ 2(x + 7) 7 < 1 \]

Solving for x, we find:

\[ x < -\frac{1}{14} \]

Thus, the radius of convergence, R, is 1/7.

To determine the interval of convergence, we consider the endpoints of the interval. When x = -6, the series becomes:

\[ \sum_{{n=2}}^{\infty} 2(1)^n 7^n \ln(n) = \sum_{{n=2}}^{\infty} 2 \cdot 7^n \ln(n) \]

This series is divergent. When x = -8, the series becomes:

\[ \sum_{{n=2}}^{\infty} 2(-1)^n 7^n \ln(n) \]

This series is also divergent. Therefore, the interval of convergence, I, is (-8, -6) U (-6, -6 + 1/7) U (-6 + 1/7, -6 + 2/7) U (-6 + 2/7, -6 + 3/7) U ... U (∞, ∞).

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If the diagonal of the quadrilateral bisect each other at a right angle. Then the quadrilateral will be a rhombus.

It is a polygon with four sides. The total interior angle is 360 degrees. A rhombus's opposite sides are parallel and equal.

The diagonal of the rhombus will intersect at a right angle.

From the diagram, the diagonal of the rhombus will intersect at a right angle.

That means the diagonals bisect each other.

Thus, if the diagonal of the quadrilateral bisect each other at a right angle. Then the quadrilateral will be a rhombus.

The diagram is given below.

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The number on round off to each place will be 45,621.

The decimal number is rounded to any place by the following concept -

We look at the number to the right of concerned digit. If that number is more than five or exactly five, then we add 1 to our number. However, if it is less than five, then the number remains same.

For instance, if we round 45.621 to nearest tenth, we will get 45.6. This is because on right to it, the number 2 is less than 5. Now, in the mentioned digit which is 45,621, we see there is no decimal and number after that. So, as the digits are 0 which is less than 5, the number will remain as it is.

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The limit doesn't exist.

The value that a function (or sequence) approaches when the input (or index) gets closer to a particular value is known as a limit. Calculus and mathematical analysis are impossible without limits, which are also required to determine continuity, derivatives, and integrals.

In addition to being closely related to limit and direct limit in category theory, the idea of a limit of a sequence is further generalized to include the concept of a limit of a topological net.

A function's limit is typically expressed in formulas as

\(\lim_{x \to c } F(x) = L\)

It is typically used to assign values to specific functions at locations where none are defined while maintaining consistency with existing values.

\(F(x) = -x+8 ,x\leq 0\)

\(F(x) = 4x+9 , if x > 0\)

\(\lim_{x \to 0^{+} } F(x) = \lim_{n \to 0^{+} } (4x+9) = 9\)

\(\lim_{x \to 0^{-} } F(x) = \lim_{x \to 0^{-} } (-x+8) =8\)

\(\lim_{x \to 0^{+} } F(x) \neq \lim_{x \to 0^{-} } F(x)\)

So limit doesn't exist

For limit to exist

\(\lim_{x \to 0^{+} } F(x) = \lim_{x \to 0^{-} } F(x) = \lim_{x \to 0} f(x)\)

must be satisfied

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The algebraic expression for Mr. Robinson's budget constraint if running shoes and basketball shorts cost $20 each is:

200 = 20S + 20B, where S is the number of running shoes and B is the number of basketball shorts

The algebraic expression for Mr. Robinson's budget constraint if the cost of the basketball shorts rises to $30 each is:

200 = 20S + 30B

a) If Mr. Robinson spends his entire income on running shoes and basketball shorts, which cost $20 each, we can write the budget constraint as:
200 = 20S + 20B, where S is the number of running shoes and B is the number of basketball shorts.

b) To determine the number of goods he will buy, we need more information about his preferences. Without any further information, we cannot determine the exact quantities of running shoes (S) and basketball shorts (B) he will buy.

c) If the price of basketball shorts rises to $30 each, the budget constraint becomes:
200 = 20S + 30B

d) Again, to determine the number of goods he will buy with the new prices, we need more information about his preferences.

e) To illustrate the results in parts (a) and (c), you would create a graph with running shoes on the x-axis and basketball shorts on the y-axis. The budget constraint in part (a) would be a straight line with a slope of -1 and an intercept of 10 on both axes. For part (c), the budget constraint would be a straight line with a slope of -2/3 and an intercept of 10 on the x-axis and 6.67 on the y-axis.

As for the decomposition of the income and substitution effect, this cannot be determined without more information about Robinson's preferences or the shape of his indifference curves.

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The amount of material needed = the surface area of the cylindrical can which is approximately calculated as: 332 square centimeters.

The material used = surface area of cylindrical can = 2πr(h + r).

Given the dimensions of the cylindrical can, we have:

radius (r) = 7/2 = 3.5 cm

height of cylindrical can (h) = 11.6 cm

π = 3.14

Amount of tin used = surface area = 2 * 3.14 * 3.5 * (11.6 + 3.5)

≈ 332 square centimeters

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Answer:

741.63 km

Corrected question:

Diameter of the earth is 12,756 km in 1996 an new planet was discovered whose diameter is 5/86 of the diameter of the earth find the diameter of this planet in km

Step-by-step explanation:

Let d1 and d2 represent the diameter of the earth and the new planet respectively.

Given:

Diameter of earth d1 = 12756 km

Diameter of new planet d2 = 5/86 of the diameter of earth

d2 = 5/86 × d1

Substituting the value of d1;

Diameter of new planet d2

d2 = 5/86 × 12756 km

d2 = 741.63 km

Diameter of new planet = 741.63 km

The values of x in the interval [0, 2π] that satisfy the equation 8sin(2x) = 4 are π/12 and 5π/12.

To find the values of x that satisfy the equation 8sin(2x) = 4 in the interval [0, 2π], we can solve for x by isolating sin(2x) first and then finding the corresponding angles.

Let's solve the equation step by step:

8sin(2x) = 4

Divide both sides of the equation by 8:

sin(2x) = 4/8

sin(2x) = 1/2

To find the values of x, we need to determine the angles whose sine is 1/2. These angles occur in the first and second quadrants.

In the first quadrant, the reference angle whose sine is 1/2 is π/6.

In the second quadrant, the reference angle whose sine is 1/2 is also π/6.

However, since we're dealing with 2x, we need to consider the corresponding angles for π/6 in each quadrant.

In the first quadrant, the corresponding angle is π/6.

In the second quadrant, the corresponding angle is π - π/6 = 5π/6.

Now, let's find the values of x in the interval [0, 2π] that satisfy the equation:

For the first quadrant:

2x = π/6

x = π/12

For the second quadrant:

2x = 5π/6

x = 5π/12

Therefore, the values of x in the interval [0, 2π] that satisfy the equation 8sin(2x) = 4 are π/12 and 5π/12.

So, the comma-separated list of values is π/12, 5π/12.

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Answer:

\(pi > 2\\3.14 > 3.1\)

Hope this helps, have a great day! ♣

The 90% confidence interval for the proportion of district residents in favor of starting the school day 15 minutes later is (0.392, 0.548). The true proportion is estimated to lie within this interval with 90% confidence.

To calculate the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later, we can use the following formula:

CI = p ± z*(√(p*(1-p)/n))

where:

CI: confidence interval

p: proportion of residents in favor of starting the day later

z: z- score based on the confidence level (90% in this case)

n: sample size

First, we need to calculate the sample proportion:

p = 94/200 = 0.47

Next, we need to find the z- score corresponding to the 90% confidence level. Since we want a two-tailed test, we need to find the z- score that cuts off 5% of the area in each tail of the standard normal distribution. Using a z-table, we find that the z- score is 1.645.

Substituting the values into the formula, we get:

CI = 0.47 ± 1.645*(√(0.47*(1-0.47)/200))

Simplifying this expression gives:

CI = 0.47 ± 0.078

Therefore, the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later is (0.392, 0.548). We can be 90% confident that the true proportion lies within this interval.

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Answer:

V = 54 π units³

OR

V = 169.6 units³

Step-by-step explanation:

Volume of a cylinder = \(\pi r^2 h\)

V = (3.14)(3)²(6)

V = (3.14)(54)

V = 54 π units³

OR

V = 169.6 units³