Brandi has a deck of 12 cards labeled A through L. Brandi draws a card from the deck and returns it, then draws a card again. What is the theoretical probability that Brandi draws a card with a vowel both times?
A) 6.25%

B) 2.08%

C) 25%

D) 75%

Answer:

a.(x)=7

b.(x)=14

Step-by-step explanation:

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Answer:

For A x equals 7

For B x equals 14

Explanation:

Simply cross multiply

A. 21×2=42÷6=7

Or find the relationship

B. 150÷6=25

84÷6=14

Hope this helps, mark BRAINLIEST please...

Answer:

y = 1.44

Step-by-step explanation:

What are you aiming to do here?  Please share all instructions with each problem.

If you want to solve 4.5/y = 12.5/4 for y:  Multiply both sides by 4y:

18 = 12.5y.  Then y = 1.44

Answer:

Step-by-step explanation:

Mario bakes:

x loaves of bread on Sunday

90 + x Loaves on Saturday

70 + x Loaves on Monday

70 + x = 340

x = 340 -70 = 270 loaves

now sub value of X

On Saturday he baked 90 + 270 = 360 Loaves

Number 1 is 5y = 50

Number 2 is h = 7

Number 3 is multiplication

Number 4 is addition

Based on equations, Angus worked 6 hours on Saturday and 10 hours at his after-school job last week earning a total of $127.80.

The hourly rate at Angus' Saturday job = $8.80

The hourly rate at Angus' after-school job = $7.50

The total earnings last week = $127.80

Let the hours Angus worked at Saturday job = x

Let the hours Angus worked after-school = 4 + x

The total hours worked = x + x + 4

2x + 4

The total earnings last week 127.80 = 8.8x + 7.5x + 4 (7.5)

127.80 = 8.8x + 7.5x + 30

127.8 - 30 = 16.3x

x = 6 hours

x + 4 = 10 hours

2x + 4 = 16 (12 + 4)

Check:

Earnings at Saturday job = $52.80 ($8.80 x 6)

Earnings at after-school job = $75.00 ($7.50 x 10)

Total earnings = $127.80

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the data suggests that the difference in average tension bond strengths is greater than 0. In other words, the polymer latex modified mortar has a higher tension bond strength than the unmodified mortar.

a) The rejection region for this one-tailed hypothesis test is z ? z > 2.33.

The test statistic value is z = 2.76.

Therefore, the conclusion is that we reject H0. The data suggests that the difference in average tension bond strengths is greater than 0.

For this one-tailed hypothesis test, we must reject the null hypothesis (H0: m1 - m2 = 0) if the test statistic is greater than 2.33. Our test statistic value is 2.76, which is greater than 2.33, so we reject H0. This indicates that the data suggests that the difference in average tension bond strengths is greater than 0. In other words, the polymer latex modified mortar has a higher tension bond strength than the unmodified mortar.

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Answer:

The slope of the tangent line to the curve at the given point is -11/7.

Step-by-step explanation:

Differentiation is an algebraic process that finds the gradient (slope) of a curve.  At a point, the gradient of a curve is the same as the gradient of the tangent line to the curve at that point.

Given function:

\(4x^2+5xy+y^4=370\)

To differentiate an equation that contains a mixture of x and y terms, use implicit differentiation.

Begin by placing d/dx in front of each term of the equation:

\(\dfrac{\text{d}}{\text{d}x}4x^2+\dfrac{\text{d}}{\text{d}x}5xy+\dfrac{\text{d}}{\text{d}x}y^4=\dfrac{\text{d}}{\text{d}x}370\)

Differentiate the terms in x only (and constant terms):

\(\implies 8x+\dfrac{\text{d}}{\text{d}x}5xy+\dfrac{\text{d}}{\text{d}x}y^4=0\)

Use the chain rule to differentiate terms in y only. In practice, this means differentiate with respect to y, and place dy/dx at the end:

\(\implies 8x+\dfrac{\text{d}}{\text{d}x}5xy+4y^3\dfrac{\text{d}y}{\text{d}x}=0\)

Use the product rule to differentiate terms in both x and y.

\(\boxed{\dfrac{\text{d}}{\text{d}x}u(x)v(y)=u(x)\dfrac{\text{d}}{\text{d}x}v(y)+v(y)\dfrac{\text{d}}{\text{d}x}u(x)}\)

\(\implies 8x+\left(5x\dfrac{\text{d}}{\text{d}x}y+y\dfrac{\text{d}}{\text{d}x}5x\right)+4y^3\dfrac{\text{d}y}{\text{d}x}=0\)

\(\implies 8x+5x\dfrac{\text{d}y}{\text{d}x}+5y+4y^3\dfrac{\text{d}y}{\text{d}x}=0\)

Rearrange the resulting equation in x, y and dy/dx to make dy/dx the subject:

\(\implies 5x\dfrac{\text{d}y}{\text{d}x}+4y^3\dfrac{\text{d}y}{\text{d}x}=-8x-5y\)

\(\implies \dfrac{\text{d}y}{\text{d}x}(5x+4y^3)=-8x-5y\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{-8x-5y}{5x+4y^3}\)

To find the slope of the tangent line at the point (-9, -1), substitute x = -9 and y = -1 into the differentiated equation:

\(\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{-8(-9)-5(-1)}{5(-9)+4(-1)^3}\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{72+5}{-45-4}\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=-\dfrac{77}{49}\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=-\dfrac{11}{7}\)

Therefore, slope of the tangent line to the curve at the given point is -11/7.

Answer:

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Step-by-step explanation:

The drawing of the quadrilateral P(-3, 0), N(6, 0), O(3, -6), and M(3, 9) and the drawing of the image, of the quadrilateral with vertices, P'(-1, 0), N'(2, 0), O'(1, -2), and M'(1, 3), following a dilation by a scale factor of 1/3, created with MS Excel.

The coordinates of the vertices of the quadrilateral are;

P(-3, 0), N(6, 0), O(3, -6), M(3, 9)

The coordinates of the image of a point (x, y) following a dilation by a scale factor of c are; (x·c, y·c)

The coordinates of the image following a dilation by a scale factor of 1/3 therefore, are;

P(-3, 0) dilation by a scale factor of 1/3 → P'(-3/3, 0/3) = P'(-1, 0)

N(6, 0) dilation by a scale factor of 1/3 → N'(6/3, 0/3) = N'(2, 0)

O(3, -6) dilation by a scale factor of 1/3 → O'(3/3, -6/3) = O'(1, -2)

M(3, 9) dilation by a scale factor of 1/3 → M'(3/3, 9/3) = M'(1, 3)

The coordinates of the quadrilateral following the dilation transformation are; P'(-1, 0), N'(2, 0), O'(-2, 0), M'(1, 3)

Please find attached the drawing of the image of the quadrilateral MNOP, following the dilation of a scale factor of 1/3

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Answer:

95, and 85 degrees

Step-by-step explanation:

x+x+10=180

2x=180-10

2x=170

x=85,

Angles=85, 85+10=95

Answer:

i think the answer is A: 0.0005

Step-by-step explanation:

i think so because when i divided alaska by rhode island, i got 500000000. so i guess you move the decimal

(a) The sum of the series 1+2+3+4+...+392 is 77,028.

(b) The sum of the series 1+2+3+4...x is (x/2)(1 + x).

(c) The sum of the series 546 + 547 + 548 + 549 is 2,190.

To solve the exercise using Polya's four-step problem-solving strategy, we will apply the procedures presented in the lesson.

(a) For the series 1+2+3+4+...+392:

Using the arithmetic series formula Sn = (n/2)(a + l), where n is the number of terms, a is the first term, and l is the last term, we can substitute the values: Sn = (392/2)(1 + 392) = 196(393) = 77,028.

(b) For the series 1+2+3+4...x:

To find the sum of this series, we need to know the number of terms (n) based on the value of x. Since the series follows a consecutive pattern, the number of terms will be equal to x itself. Thus, the sum of the series would be Sn = (x/2)(1 + x).

(c) For the series 546 + 547 + 548 + 549:

Using the arithmetic series formula Sn = (n/2)(a + l), we can determine the number of terms (n) by subtracting 546 from 549 and then adding 1: n = 549 - 546 + 1 = 4. Substituting the values into the formula: Sn = (4/2)(546 + 549) = 2(1095) = 2,190.

The final answer for each part is:

(a) The sum of the series 1+2+3+4+...+392 is 77,028.

(b) The sum of the series 1+2+3+4...x is (x/2)(1 + x).

(c) The sum of the series 546 + 547 + 548 + 549 is 2,190.

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Answer:

a)Randomization condition: Satisfied, as the subjects were randomly selected.

10% condition: Satisfied, as the sample size is less than 10% of the population (U.S. adults).

Sample size condition: Satisfied, as the product between the smaller proportion and the sample size is bigger than 10.

b) The 90% confidence interval for the population proportion is (0.68, 0.70).

Step-by-step explanation:

a) Evaluating the necessary conditions:

Randomization condition: Satisfied, as the subjects were randomly selected.

10% condition: Satisfied, as the sample size is less than 10% of the population (U.S. adults).

Sample size condition: Satisfied, as the product between the smaller proportion and the sample size is bigger than 10.

\(n(1-p)=4,726\cdot (1-0.69)=4,726\cdot 0.31=1,465>10\)

b) We have to calculate a 90% confidence interval for the proportion.

The sample proportion is p=0.69.

The standard error of the proportion is:

\(\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.69*0.31}{4726}}\\\\\\ \sigma_p=\sqrt{0.000045}=0.007\)

The critical z-value for a 90% confidence interval is z=1.645.

The margin of error (MOE) can be calculated as:

\(MOE=z\cdot \sigma_p=1.645 \cdot 0.007=0.01\)

Then, the lower and upper bounds of the confidence interval are:

\(LL=p-z \cdot \sigma_p = 0.69-0.01=0.68\\\\UL=p+z \cdot \sigma_p = 0.69+0.011=0.70\)

The 90% confidence interval for the population proportion is (0.68, 0.70).

Answer:

f(x) \(\leq\) 3x + 4

g(x)  ≥ -1/2x - 5

Step-by-step explanation:

Point D is below f(x)  and above g(x)

Helping in the name of Jesus.

Answer:

  4 minutes

Step-by-step explanation:

You want to know how long it takes to drain a cylindrical tank 1.8 ft in diameter and 3 ft long at the rate of 1.7 ft³/minute. (π = 3.14)

The volume of a cylinder can be found using the formula ...

  V = (π/4)d²h . . . . . . . diameter d, height h

Then the volume of the oil tank is ...

  V = 3.14/4(1.8 ft)²(3 fft) = 7.6302 ft³

The time it takes to empty the tank is found by dividing the volume by the rate:

  (7.6302 ft³)/(1.7 ft³/min) ≈ 4.49 min ≈ 4 min

It will take about 4 minutes to empty the tank.

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Answer:

If two chords intersect in a circle, then the product of the segments of one chord equals the product of the segments of the other chord.

6(3x) = 4(4x + 1)

18x = 16x + 4

2x = 4

x = 2

\(\large\bf{\underline{Given:}}\)

__________________________________________

\(\large\bf{\underline{To\:find:}}\)

\(\bf{Let\:the\:total\:no.\:of\: kitten\:x}\)

__________________________________________

\(\large\bf{\underline{Therefore}}\)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\(\bf{⟹30\%\:of\:x=3}\)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\(\bf{⟹\frac{30}{100}\times x= 3}\)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\(\bf{⟹x= 3\times \frac{100}{30}}\)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\(\bf{⟹x=10}\)

__________________________________________

\(\large\bf{\underline{Hence}}\)

\(\bf{There\:are\:10\: kittens\:in\:the\: litter}\)

The trade this country will import is given by the option (C) 300 pair of shoes.

The number of shoes exported will be calculated by the formula -

Import = quantity demanded - quantity supplied. The formula is based on the concept that the import of shoes will be carried out once the manufacturing is more than the demand.

The graph indicates the quantity demanded is 1000 and the quantity supplied is 1300. Keep the values in formula to find imports.

Imports = 1300 - 1000

Performing subtraction on Right Hand Side of the equation

Imports = 300

Hence, the import is 300.

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The complete question is attached in figure.

The group of individuals fitting a description is called option D: Population, this is because, in statistics, a population is seen as am entire group of individuals, items, or elements that tends to have or share a common characteristics.

The term "population" describes the complete group of people or things that you are interested in investigating. It is the group of individuals or thing(s) about which you are attempting to draw conclusions.

There are infinite and finite populations. A population with a set quantity of people or things is said to be finite. An endless population is one that has an infinite amount of people or things.

Therefore, the correct option is D

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See full text below

A group of individuals fitting a description is the _____

Which of the term below fit the description above.

A.census

B.sample

C.parameter

D.population

Answer:

4

Step-by-step explanation:

..............................

#1

\(\\ \sf\longmapsto slope=m=\dfrac{-4-5}{2+4}=\dfrac{-9}{6}=\dfrac{-3}{2}\)

Hence equation of the line

\(\\ \sf\longmapsto y=mx+b\)

\(\\ \sf\longmapsto y+4=\dfrac{-3}{2}(x+2)\)

Option D

#2.

(-2,4)

Verification

\(\\ \sf\longmapsto 4-4=-3(-2+2)\)

\(\\ \sf\longmapsto 0=0\)

Option B

\(1 - 132 \\ = - 131\)

\(12 - 11 \\ = 1\)

\(43 - 24 \\ = 19\)

\(12 - 21 \\ = - 9\)

Answer:

I = $ 480.00

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 6%/100 = 0.06 per year,

then, solving our equation

I = 4000 × 0.06 × 2 = 480

I = $ 480.00

The simple interest accumulated

on a principal of $ 4,000.00

at a rate of 6% per year

for 2 years is $ 480.00.

Answer:

Cost for each pound of jelly beans:  $2.75

Cost for each pound of almonds:  $3.75

Step-by-step explanation:

Let J be the cost of one pound of jelly beans.

Let A be the cost of one pound of almonds.

Using the given information, we can create a system of equations.

Given 3 pounds of jelly beans and 5 pounds of almonds cost $27:

\(\implies 3J + 5A = 27\)

Given 9 pounds of jelly beans and 7 pounds of almonds cost $51:

\(\implies 9J + 7A = 51\)

Therefore, the system of equations is:

\(\begin{cases}3J+5A=27\\9J+7A=51\end{cases}\)

To solve the system of equations, multiply the first equation by 3 to create a third equation:

\(3J \cdot 3+5A \cdot 3=27 \cdot 3\)

\(9J+15A=81\)

Subtract the second equation from the third equation to eliminate the J term.

\(\begin{array}{crcrcl}&9J & + & 15A & = & 81\\\vphantom{\dfrac12}- & (9J & + & 7A & = & 51)\\\cline{2-6}\vphantom{\dfrac12} &&&8A&=&30\end{array}\)

Solve the equation for A by dividing both sides by 8:

\(\dfrac{8A}{8}=\dfrac{30}{8}\)

\(A=3.75\)

Therefore, the cost of one pound of almonds is $3.75.

Now that we know the cost of one pound of almonds, we can substitute this value into one of the original equations to solve for J.

Using the first equation:

\(3J+5(3.75)=27\)

\(3J+18.75=27\)

\(3J+18.75-18/75=27-18.75\)

\(3J=8.25\)

\(\dfrac{3J}{3}=\dfrac{8.25}{3}\)

\(J=2.75\)

Therefore, the cost of one pound of jelly beans is $2.75.

Answer:

i think is the last one

Step-by-step explanation:

72.99% of days have a high temperature between 66 and 80 degrees.

It is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

here, we have,

Let random variable x denote the daily temperature in a variation resort city.

then E(x) = μ = 75

and S.D. = √var(x) = σ = 6

x is approximately normal

x ≈ N(75, 6²)

then Z = (X - 75) / 6

Z ~ N(0,L)

P(66< x < 80) = P((66-75 / 6) < (x - 75 / 6) < 20 - 75 / 6)

= P( -1.5 < z < 0.23), where Z = (x - 75 / 6)

=P(z<0.23) - P(z ≤ -1.5)

= 0.7967 - 0.0668

= 0.7299

P(66< x < 80) = 0.7299

Therefore, 72.99% of days have a high temperature between 66 and 80 degrees.

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Answer: \(y-1=-\frac{9}{2}(x-7)\)

Step-by-step explanation:

The slope of the line is \(\frac{-8-1}{9-7}=-\frac{9}{2}\).

So, the equation in point-slope form is \(y-1=-\frac{9}{2}(x-7)\).

The way the numbers will be placed in the square box will be:

First row = 4 12 14

Second row = 2 10 18

Third row = 6 8 16

It should be noted that the question is simply about adding the numbers and getting 39 in each place.

This will be:

First row = 4 12 14 = 4 + 12 + 14 = 30

Second row = 2 10 18 = 2 + 10 + 18 = 30

Third row = 6 8 16 = 6 + 8 + 16 = 30

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Certainly! The problem can be solved using the Pythagorean theorem,

which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, the ladder acts as the hypotenuse, and we need to find the length of the vertical side (height) it reaches up the wall.

The ladder forms the hypotenuse, and its length is given as 12 meters. The distance from the foot of the ladder to the base of the wall represents one side of the triangle, which is 4.5 meters.

By substituting the given values into the Pythagorean theorem equation: (12m)^2 = h^2 + (4.5m)^2, we can solve for the unknown height 'h'.

Squaring 12m gives us 144m^2, and squaring 4.5m yields 20.25m^2. By subtracting 20.25m^2 from both sides of the equation, we isolate 'h^2'.

We then take the square root of both sides to find 'h'. The square root of 123.75m^2 is approximately 11.12m.

Therefore, the ladder reaches a height of approximately 11.12 meters up the wall.

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