Answer:
25.
Explanation:
5
because you're taking off the front number which is one
Which of the following is an example of velocity?
O a. 2 m/s
O b. 25 N
O c. 55 miles per hour South
O d. 2m/s2 west
Answer:
C
Explanation:
b is 55 miles per hour south or 55mph[South]
the important part to understand is that velocity is a vector meaning it also has to have a direction, in this case south. That is why a (2m/s) is not a velocity, however 2m/s is a speed.
does anyone have answers to this ;(\
From the above information provided, the blood type of the individual is O- (O negative) which is found by the reactions of the blood sample with the different antibodies:
Anti-A serum: No reaction
Anti-B serum: No reaction
Anti-Rh serum: No reaction
The individual do not have the A, B, or Rh antigens on their red blood cells, that is corresponding to blood type O-.
What are Rh antigens?Rh antigens, also called Rhesus antigens, are described as transmembrane proteins expressed at the surface of erythrocytes and they appear to be used for the transport of CO2 and/or ammonia across the plasma membrane.
In conclusion, the main Rh antigens on red cells – C, c, D, E, e of which the most important of these is the Rh D.
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Transcribed image text: The position of a ball rolling in a straight line is given by x = 2.0 - 3.6t + 1.7t2 where x is in meters and t in seconds, (a) What do the numbers 2.0, 3.6, and 1.7 refer to? (b) What are the units of each of these numbers? (c) Determine the position of the ball at t = 1.0 s, 2.0 s, and 3.0 s. (d) What is the average velocity over the interval t = 1.0 s to t = 3.0 s? Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining
a) 2.0 represents the initial position of the ball, -3.6 represents the initial velocity of the ball and 1.7 represents the acceleration of the ball.
b)The unit of 2.0 is meters, the unit of -3.6 is meters per second, and the unit of 1.7 is meters per second squared.
c) Position of of ball at t=1, 2, 3 are -1.9, 5.4 and 9.1 meters respectively
d) Average velocity is 5.5 meter per second
Part a
In the equation x = 2.0 - 3.6t + 1.7t2, the number 2.0 represents the initial position of the ball (i.e., the position of the ball at t = 0 seconds), -3.6 represents the initial velocity of the ball (i.e., the velocity of the ball at t = 0 seconds), and 1.7 represents the acceleration of the ball.
Part b
The unit of 2.0 is meters, the unit of -3.6 is meters per second, and the unit of 1.7 is meters per second squared.
Part c
To determine the position of the ball at t = 1.0 s, 2.0 s, and 3.0 s, we simply substitute these values into the equation:
When t = 1.0 s: x = 2.0 - 3.6(1.0) + 1.7(1.0)^2 = -1.9 meters
When t = 2.0 s: x = 2.0 - 3.6(2.0) + 1.7(2.0)^2 = 5.4 meters
When t = 3.0 s: x = 2.0 - 3.6(3.0) + 1.7(3.0)^2 = 9.1 meters
Part d
The average velocity over the interval t = 1.0 s to t = 3.0 s can be calculated by taking the displacement of the ball during this time interval and dividing it by the time interval:
Displacement = x(3.0) - x(1.0) = 9.1 - (-1.9) = 11.0 meters
Time interval = 3.0 s - 1.0 s = 2.0 s
Average velocity = Displacement / Time interval = 11.0 meters / 2.0 seconds = 5.5 meters per second.
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the accidental on the top f alters the numeric size of this interval.
True
False
False. The accidental on the top does not alter the numeric size of an interval. Accidental symbols, such as sharps (#), flats (b), and naturals (♮), are used to modify the pitch of a note.
They indicate a temporary alteration from the original pitch, but they do not affect the numeric size or interval between two notes. The interval between two notes is determined by the distance in terms of steps or semitones between them, regardless of any accidental symbols present.
The accidental on the top note only affects the pitch of that note, not the interval itself. For example, if a perfect fifth interval is C to G, adding an accidental to the G note will change its pitch but not the fact that it is still a perfect fifth interval. The accidental may create a different type of interval (e.g., raising the G to G# would create an augmented fifth), but it does not change the numeric size of the original interval.
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Describe your favourite star story from Ghillar Anderson.
For history of astronomy class.
My favorite star story from Ghillar Anderson is the story of the Seven Sisters.
What are the Seven Sisters alluded to?The Seven Sisters are a group of stars in the constellation of Taurus. They are said to be the daughters of the creator spirit, Baiame. Baiame was a great hunter, and he had seven daughters. One day, Baiame was out hunting when he came across a group of men who were harassing his daughters. Baiame was angry, and he turned the men into stars. The seven stars are still visible in the night sky, and they are a reminder of Baiame's power and his love for his daughters.
I like this story because it shows how Aboriginal people have a deep understanding of the night sky. They have been observing the stars for thousands of years, and they have developed a rich mythology about them. This story also shows how Aboriginal people see the stars as being connected to their own culture and history. The Seven Sisters are not just stars, they are the daughters of Baiame. They are a reminder of Baiame's power and his love for his people.
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Please help ASAP, studying for finals.
A racecar rounds a curve on the track at a constant speed of 180 mph. Is the car accelerating?
1)No, its mass is constant.
2)Yes, its mass is constant.
3) No, its speed is constant.
4)Yes, its speed is constant.
Answer:
3)No, it's speed is constant.
Need Help !
A 1500 kg car on flat ground is
moving 5.25 m/s. Its engine
creates a 1250 N forward force as the car moves 42.8 m. What is its final velocity?
Answer: 5.96m/s
Explanation:
Given the following :
Mass of car (m) = 1500kg
Velocity (V) = 5.25m/s
Forward force of engine = 1250N
Diatance moved = 4.8m
Final Velocity =?
Final kinetic energy = Initial kinetic energy + work done by engine
Initial kinetic energy = 0.5 × mass × velocity^2
Initial kinetic energy = 0.5 × 1500 × 5.25^2
Initial kinetic energy = 20671.875 J
Work done by engine = Force × distance
Work done by engine = 1250 × 4.8 = 6000J
Final kinetic energy = (20671.875 + 6000) J
= 26671.875 J
From kinetic energy = 0.5mv^2
26671.875 = 1/2 × 1500 × v^2
53343.75 = 1500v^2
v^2 = 35.5625
v = sqrt(35.5625)
v = 5.96m/s
Determine the photodiode sensitivity in uA/mW/cm2 assumir.g the unattenuated laser beam to have an incident power of 2.75mW and a beam diameter of Imm
Answer:
A photodiode is a semiconductor-based light detector that measures the intensity of light. It is commonly used for a variety of applications, such as detecting the intensity of incident light, sensing environmental light levels, and measuring spectroscopy in research. The sensitivity of a photodiode is usually expressed in units of uA/mW/cm2, which is the current produced by the diode for a given incident light power per unit area. This article will discuss how to determine the photodiode sensitivity in uA/mW/cm2 assuming the unattenuated laser beam to have an incident power of 2.75mW and a beam diameter of 1mm.
Explanation:
Process of Photodiode Sensitivity DeterminationTo determine the sensitivity of a photodiode, the incident light power (P) and the beam diameter (D) must be known. In the case of the unattenuated laser beam, these can be directly measured. The sensitivity can then be calculated as follows:
Sensitivity (uA/mW/cm2) = P/(πD2)
Where P is the incident light power in mW and D is the beam diameter in mm.
For the example given, the sensitivity can be calculated as follows:
Sensitivity (uA/mW/cm2) = 2.75/(πx1x1)
Sensitivity (uA/mW/cm2) = 2.75/(π)
Sensitivity (uA/mW/cm2) = 0.87 uA/mW/cm2
I hope I helped, have a good day!
Valentina is going for a bike ride . Below is a distance time graph that describes her full journey.
distance
0
10
20
30
time
17:00
17:15
17:30
17:45
18:00
18:15
a)How long was she stationary for?
b) What was the total distance travelled during her journey?
c) what was the speed in kilometers per hour between 17:15 and 17:45?
We need to locate the places on the graph where the distance is not changing, suggesting that Valentina was not moving, in order to calculate how long she was stationary for. By examining the graph, we can tell that Valentina was still for 15 minutes, from 17:30 to 17:45.
How should a speed-time graph be answered?The particle's acceleration is represented by the gradient of the line of the speed-time graph (for straight lines acceleration is constant). Line gradient = change in velocity time = v ut = a. Line gradient is equal to the change in velocity over time, or v u t, or a. The distance traveled by a particle is indicated by the area under the speed-time graph.
What is displayed on a speed-time graph?On a speed-time graph, we can see how the speed of a moving object changes with time. The steeper the graph, the greater the acceleration. A horizontal line means the object is moving at a constant speed.
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A ship is 425 m from a perpendicular cliff at the coast. The ship's siren is sounded and an echo is heard after 2,5 s. Calculate the speed of sound from the data supplied.
The speed of sound when a echo is heard 2.5 s later is 340 m/s.
What is an echo?An echo is a sound that is repeated due to the reflection of a sound wave in a medium.
To calculate the speed of light from the data supplied, we use the formula below.
Formula:
v = 2d/t...................... Equation 1Where:
v = Speed of soundd = Distance of the from the cliff = 425 mt = Time taken to hear the echo = 2.5 sSubstitute these values into equation 1
v = (2×425)/2.5v = 340 m/sHence, the speed of sound is 340 m/s.
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the massless spring of a spring gun has a force constant n/cm. when the gun is aimed vertically, a 10-g projectile is shot to a height of 5.0 m above the end of the expanded spring. how much was the spring compressed initially?
x = \(\sqrt{((0.49 N) * (100 / k))}\)
The very last expression gives the initial compression of the spring, x, in the suitable devices primarily based on the pressure consistently provided.
To determine the preliminary compression of the spring in the spring gun, we will use the concepts of potential power and Hooke's Law.
Given:
The force constant of the spring (k): n/cm
Mass of the projectile (m): 10 g = zero.01 kg
The height reached by way of the projectile (h): five. Zero m
We know that the potential energy gained through the projectile is equal to the capability power saved within the compressed spring. The ability strength gained via the projectile is given by using:
Potential Energy (PE) = m * g * h
wherein g is the acceleration due to gravity (approximately 9.8 m/s²).
Now, in line with Hooke's Law, the capacity energy stored in the spring is given through:
Potential Energy (PE) = (half of) * k * x²
where x is the preliminary compression of the spring.
Equating the two expressions for potential energy, we've:
m * g * h = (half) * k * x²
Substituting the known values:
0.01 kg * 9.8 m/s^2 * 5.0 m = (1/2) * k * x²
Simplifying the equation:
0.49 N = k * x²
Now, we need to transform the force constant from n/cm to N/m:
1 N/m = 1 (n/cm) / (one hundred cm/m)
So, we have:
0.49 N = (k / 100) * x²
Rearranging the equation to solve for x:
x² = (0.49 N) / ((k / 100))
x ²= (0.49 N) * (100 / k)
x = \(\sqrt{((0.49 N) * (100 / k))}\)
The very last expression gives the initial compression of the spring, x, in the suitable devices primarily based on the pressure consistently provided.
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hubble's law can be used to determine distances to the farthest objects in the universe.
T/F
True. Hubble's law, which states that the recessional velocity of a galaxy is proportional to its distance from Earth, can be used to determine the distance to faraway galaxies.
By measuring the redshift of light emitted by galaxies, astronomers can calculate their recession velocity, and from there, use Hubble's law to calculate their distance from Earth. This has allowed us to estimate the size and age of the observable universe, and to study the large-scale structure of the cosmos.
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T/F: a car traveling at 20 mph on a curved exit ramp has a constant velocity.
False.
A car traveling at 20 mph on a curved exit ramp does not have a constant velocity. This is because the car is changing direction as it navigates the curved ramp, meaning its velocity is constantly changing. Constant velocity requires both a steady speed and a straight path of travel.
False: A car traveling at 20 mph on a curved exit ramp does not have a constant velocity. This is because velocity is a vector quantity, which means it has both magnitude (speed) and direction. While the car may maintain a constant speed of 20 mph, its direction is changing due to the curve of the exit ramp, resulting in a changing velocity.
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Describe the relationships between wavelengths and health risks.
In general, the shorter the wavelength, the greater the danger to living things. Although longer wavelengths also have their hazards, very short wavelengths, such as X-rays and gamma rays, can easily damage living tissue
What is wavelength ?UV radiation is more damaging when its wavelength is shorter. Shorter wavelength UV light, however, has a lower ability to enter skin. Three bands make up the UV area, which has a wavelength range of 100 to 400 nm. UVA (315-400 nm) (315-400 nm)
A waveform signal's wavelength is defined as the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or along a wire. Its length in wireless systems is typically expressed in metres (m), centimetres (cm), or millimetres (mm) (mm).
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An object of mass m is at rest at the top of a smooth slope of height h and length l . the coefficient of kinetic friction between the object and the surface, μk, is small enough that the object will slide down the slope if given a very small push to get it started.
Sam, whose mass is 70 kg , stands at the top of a 14-m-high, 120-m-long snow-covered slope. His skis have a coefficient of kinetic friction on snow of 0.07. If he uses his poles to get started, then glides down, what is his speed at the bottom?
The expression for the object's speed at the bottom of the slope is:
v = sqrt(2gh - 2gLsinθ/mu_k)
To solve this problem, we can use the conservation of energy principle, which states that the total energy of a system remains constant as long as there are no external forces acting on it.
At the top of the slope, the object has only potential energy, given by:
Ep = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the slope.
As the object slides down the slope, it loses potential energy and gains kinetic energy. The work done by the force of gravity is equal to the change in potential energy, so we have:
mgLsinθ = mgh - (1/2)mv^2
where θ is the angle of the slope, and v is the speed of the object at the bottom of the slope. The left-hand side of this equation represents the work done by the force of gravity as the object slides down the slope, while the right-hand side represents the loss of potential energy and the gain of kinetic energy.
Solving for v, we get:
v = sqrt(2gh - 2gLsinθ/mu_k)
where mu_k is the coefficient of kinetic friction between the object and the surface.
Therefore, the expression for the object's speed at the bottom of the slope is:
v = sqrt(2gh - 2gLsinθ/mu_k)
in terms of the variables m, mu_k, L, h, and appropriate constants.
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The given question is incomplete, the complete question is:
An object of mass m is at rest at the top of a smooth slope of height h and length L. The coefficient of kinetic friction between the object and the surface, mu k, is small enough that the object will slide down the slope if given a very small push to get it started. Part A Find an expression for the object's speed at the bottom of the slope. Express your answer in terms of the variables m, mu k, L, h, and appropriate constants.
"Nuclear stability is based on (choose
all that apply)
the ratio of protons to neutrons
the number of valence electrons
the ratio of protons to electrons
the size of the nucleus
the amount of energy in the nucleus"
Answer:
the ratio of protons to neutrons
Explanation:
Nuclear stability is based on the ratio of protons to neutrons. The nuclear space is made up of protons and neutrons that occupies the nucleus of an atom.
For every atomic nucleus, there is a specific neutron/proton ratio which ensures the stability of the nucleus.
For sodium, Na, the neutron/proton ratio for stability is 12/11.
Any nucleus with a neutron/proton combination different from its stability ratio will be unstable.
thermal energy is transferred between objects only when they have different ______.
Thermal energy is transferred between objects only when they have different temperatures.
The movement of atoms and molecules within a substance is a form of energy known as thermal energy.
When two objects are in contact, or even in proximity, the atoms and molecules in the hotter object collide with those in the colder object.
Because of these effects, a portion of the kinetic energy from the more sizzling object is moved to the colder object, raising the temperature of the previous and bringing down the temperature of the last option.
A material's thermal conductivity — an estimation of how well it moves heat — decides how rapidly heat is moved between various sorts of materials.
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What is Theoretical displacement
Displacement is the movement of unfavorable emotions from one thing or person to another.
As a kind of self-preservation, displacement is the act of shifting one's unfavorable emotions from one thing or person to another.
According to the notion, releasing stress or worry on a non-threatening target helps a person deal with negative emotions like fear or rage.
For instance, if a person feels angry because their boss yells at them, they might project those feelings onto someone or something else, such a member of their family or a piece of furniture.
For fear of losing their work, the person could feel unable to face their manager. As a result, they might vent their rage on a less dangerous person like their partner or housemate.
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A cable of 10 mm outside is to be laid in an atmosphere of 25 degree Celsius (h = 12.5 W/m2 degree) and its surface temperature is likely to be 75 degree Celsius due to heat generated within it. How would the heat flow from the cable be affected if it is insulated with rubber having thermal conductivity k = 0.15 W/m degree?
a) 43.80 W per meter length
b) 53.80 W per meter length
c) 63.80 W per meter length
d) 73.80 W per meter length
Insulating the cable with rubber having a thermal conductivity of 0.15 W/m degree increases the heat flow from the cable to 63.80 W per meter length compared to a non-insulated cable in an atmosphere with a temperature difference of 50 degrees Celsius. The correct option is C.
To determine how the heat flow from the cable is affected by insulation, we need to calculate the heat transfer rate for both the insulated and non-insulated cases. The heat transfer rate can be determined using the formula:
Q = (T2 - T1) / (R_total)
Where:
Q is the heat transfer rate per unit length (W/m),
T2 is the surface temperature of the cable (75 degrees Celsius),
T1 is the ambient temperature (25 degrees Celsius),
R_total is the total thermal resistance.
For the non-insulated case:
R_total = R_convection
For the insulated case:
R_total = R_convection + R_insulation
Let's calculate the heat transfer rate for both cases:
Non-insulated case:
R_convection = 1 / (h * A)
A = 2 * π * r * L (surface area of the cable)
Q_non-insulated = (T₂ - T₁) / (R_convection)
Insulated case:
R_insulation = d / (k * A)
Q_insulated = (T₂ - T₁) / (R_convection + R_insulation)
Given the information:
h = 12.5 W/m² degree
k = 0.15 W/m degree
d = 10 mm = 0.01 m
T₂ = 75 degrees Celsius
T₁ = 25 degrees Celsius
By comparing the heat transfer rates for the non-insulated and insulated cases, we can determine the effect of insulation on the heat flow from the cable.
Therefore, by Calculating the values and comparing the heat transfer rates, we find that the correct option is c) 63.80 W per meter length.
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A sports car moving at constant velocity travels 120m in 5.0s. If it then brakes and comes to a stop in 4.0s,what is the magnitude of it's acceleration?
✔ First calculating the speed :
V = d(in m)/t(in s)
V = 120/5 V = 24 m/s✔ You now know the average car's speed, is time it takes to stop it completely, so you can calculate its acceleration :
a = V/t
a = -24/4 a = 6 m/s² The car has an acceleration of 6 m/s².which term describes a lens with a surface that curves outward like the exterior of a sphere?
Answer:
Convex lens
hope that helps you
Which of the motion variables is the same in both thex and y axis?
A) velocity
B) acceleration
C) time
D) displacement
Answer:
Acceleration (b) not sure tho
Explanation:
An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complete swings in a time of 257 seconds. From this measurement she calculates the acceleration due to gravity on Pluto. What is her result
Answer:
The acceleration due to gravity at Pluto is 0.0597 m/s^2.
Explanation:
Length, L = 1 m
10 oscillations in 257 seconds
Time period, T = 257/10 = 25.7 s
Let the acceleration due to gravity is g.
Use the formula of time period of simple pendulum
\(T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2\)
A uniform electric field is established in the space within a parallel plate capacitor. Determine its magnitude if the plate separation is 3.60 cm and the capacitor is charged at a voltage of 62.00 V.
The electric field on a capacitor is given by:
\(E=\frac{V}{d}\)where d is the distance between the plates and V is the voltage in the capacitor. In this case, the voltage is 62 V and the distance is 0.036 m; plugging these values we have:
\(E=\frac{62}{0.036}=1722.22\)Therefore, the electric field i 1722.322 V/m
Question 3 1 / 1 pts A line of charge exists along the y axis between y = +2cm and y = -1cm. The charge -34C density is uniform with = cm What is the direction of the electric field of this line of charge at the point y = -2cm? positive y direction negative x direction o positive x direction o negative y direction
The electric field is zero because the sin(180°) term is zero. This means that the direction of the electric field is undefined or indeterminate, since there is no net electric field at the point.
The electric field at a point due to a line of charge is given by the equation:
E = (kλ/r) sinθ
where k is the Coulomb's constant (k = 9 × 10^9 N⋅m^2/C^2), λ is the linear charge density (C/m), r is the distance from the point to the line of charge (m), and θ is the angle between the line perpendicular to the line of charge and the line connecting the point to the line of charge.
In this case, the line of charge is along the y-axis and the point of interest is on the negative y-axis, so r = 1 cm = 0.01 m and θ = 180°. The linear charge density is given as λ = -34 C/m, with a negative sign indicating that the charge is negative.
Therefore, the electric field at the point y = -2 cm = -0.02 m is:
E = (9 × 10^9 N⋅m^2/C^2) × (-34 C/m) / (0.01 m) × sin(180°) = 0
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Use the drop-down menus to identify the order of these images for the formation of our solar system. A collapsed nebula flattens into a disc. A collapsed solar nebula. An image of our solar system. nebula. An image of our solar system.
Answer: 2 1 3
is your answer
Explanation:
your'e welcome
Answer:
First one = 2
Second one = 1
Third one = 3
Explanation:
2 1 3
can i get brainliest I need it please
Which piece of evidence suggests that the inner planets were formed from the same rotating cloud of gas and dust?
The piece of evidence that suggests that the inner planets were formed from the same rotating cloud of gas and dust is that the planets orbit the sun in the same direction and in the same plane
Smaller planets like Mercury, Venus, Earth, and Mars are considered inner planets. Mercury is thought to be the smallest inner planet, with Earth being the largest. The vastly larger outer planets, such as Jupiter, Saturn, Uranus, and Neptune, are the opposite.
A route that an object or planet in space follows around another body is referred to as an orbit. Moons are satellites that orbit many planets. A man-made satellite is also possible, such as the International Space Station.
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The acceleration due to gravity (g) is determined by using simple of length l=(100±0.1)cm. If the time period is T=(2±0.01)s, find the maximum percentage error in the measurment of g.
To determine the acceleration due to gravity (g) using the simple pendulum formula, we use the equation:
\(g = 4π^2l/T^2\)
Using the values given, we can find the value of g:
\(g = 4π^2(100 cm)/(2 s)^2g = 980.7 cm/s^2\)
To find the maximum percentage error in the measurement of g, we need to calculate the maximum possible error in g. This can be found using the formula:
max error in\(g = |∆g/g| x 100%\)
where\(∆g\) is the maximum possible error in g.
To find ∆g, we need to consider the uncertainties in the length and time measurements. The formula for the maximum error in g can be written as:
max error in\(g = |(∆l/l) + 2(∆T/T)| x 100%\)
where ∆l is the maximum possible error in the length measurement and ∆T is the maximum possible error in the time measurement.
Using the given uncertainties, we can calculate\(∆l and ∆T:\)
\(∆l = 0.1 cm∆T = 0.01 s\)
Substituting these values into the formula for the maximum error in g, we get:
\(max error in g = |(0.1 cm/100 cm) + 2(0.01 s/2 s)| x 100%max error in g = 2.1%\)
Therefore, the maximum percentage error in the measurement of g is \(2.1%.\)
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Which of thr following is aharmful effectvof oil spills
A ball released from rest on an elevated ramp uniformly accelerates at a rate of 3.52 m/s2 for 23.3m. what is the final speed of the ball?
The final speed of the ball when it accelerate uniformly at a rate of 3.52 m/s² for 23.3 m is 12.81 m/s.
What is speed?Speed can be defined as the ratio of distance to time.
The S.I unit of speed is m/s.
To calculate the final speed of the ball, we use the formula below.
Formula:
v² = u²+2as........... Equation 1Where:
v = Final speedu = Initial speeda = accelerations = distance.From the question,
Given:
u = 0 m/s from resta = 3.52 m/s²s = 23.3 mSubstitute these values into equation 1
v² = 0²+2×3.52×23.3v² = 164.032v = √(164.032)v = 12.81 m/s.Hence, the final speed of the ball is 12.81 m/s.
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