(c) Referring circuit in Figure Q1(c), calculate the \( v_{o}(t) \). (10 marks) Figure Q1(c)

To calculate the average deceleration of the bus, we can use the following formula:

Here, the initial velocity (v1) is 60 km/h, the final velocity (v2) is 40 km/h, and the time taken (t) is 8 seconds. To make the units consistent, we'll convert the velocities from km/h to m/s.

Now, we can plug the values into the formula:

Now, we'll find a common denominator for the fractions and simplify:

So, the average deceleration of the bus is approximately -150/216 m/s².

The menstrual cycle is the monthly series of changes a woman's body goes through in preparation for the possibility of pregnancy. Each month, one of the ovaries releases an egg — a process called ovulation.

At the same time, hormonal changes prepare the uterus for pregnancy. If ovulation takes place and the egg isn't fertilized, the lining of the uterus sheds through the vagina. This is a menstrual period.

The menstrual cycle, which is counted from the first day of one period to the first day of the next, isn't the same for every woman. Menstrual flow might occur every 21 to 35 days and last two to seven days.

For the first few years after menstruation begins, long cycles are common. However, menstrual cycles tend to shorten and become more regular as you age.

Therefore, The menstrual cycle is the monthly series of changes a woman's body goes through in preparation for the possibility of pregnancy. Each month, one of the ovaries releases an egg — a process called ovulation.

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The loss of body heat involving the transfer of heat from the surface of one object to the surface of another without physical contact is called radiation.

Radiation is a type of heat transfer that occurs through electromagnetic waves. In the case of the human body, radiation can occur when the body is in close proximity to colder objects or surfaces. This type of heat loss can happen even when the air temperature is relatively warm. For example, on a sunny day, a person may feel cooler when standing in the shade because the body is losing heat through radiation to the cooler shaded area.
It is important to be aware of radiation as a potential cause of heat loss and take appropriate measures to stay warm in cold environments. Wearing protective clothing and staying in warm areas can help reduce the amount of heat lost through radiation.
In summary, radiation is the transfer of heat from the surface of one object to the surface of another without physical contact and can result in the loss of body heat.

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Answer:

Initial momentum: \(0\; {\rm kg \cdot m \cdot s^{-1}}\).

Final momentum: \(150\; {\rm kg \cdot m\cdot s^{-1}}\).

Force on the mass (assuming that the force is constant): \(75\; {\rm N}\).

Impulse on the mass: \(150\; {\rm kg \cdot m \cdot s^{-1}}\).

Explanation:

The momentum \(p\) of an object is equal to the product of mass \(m\) and velocity (a vector) \(v\).

The initial momentum of this mass was \(0\; {\rm kg \cdot m \cdot s^{-1}}\) since the velocity of this object was initially \(0\; {\rm m\cdot s^{-1}}\).

At \(v = 3\; {\rm m\cdot s^{-1}}\), the momentum of this mass (\(m = 50\; {\rm kg}\)) would be:

\(\begin{aligned}p &= m\, v \\ &= 50\; {\rm kg} \times 3\; {\rm m\cdot s^{-1}} \\ &= 150\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

Assume that the external force \(F\) on this mass is constant. By Newton's Second Law of motion, the external force on this mass would be equal to the rate of change in the momentum of this mass.

Since the momentum of this mass increased by \(\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}\) in \(\Delta t = 2\; {\rm s}\), the external force on this mass would be:

\(\begin{aligned}F &= \frac{\Delta v}{\Delta t} \\ &= \frac{150\; {\rm kg \cdot m \cdot s^{-1}}}{2\; {\rm s}} \\ &= 75\; {\rm kg \cdot m \cdot s^{-2}} \\ &= 75\; {\rm N}\end{aligned}\).

The impulse of an external force on an object is equal to the change in the momentum of that object. Since the change in momentum of this mass was \(\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}\), the corresponding impulse would also be \(150\; {\rm kg \cdot m\cdot s^{-1}}\):

\(\begin{aligned}J &= \Delta v \\ &= 150\; {\rm kg \cdot m\cdot s^{-1}} \\ &= 150\; {\rm N \cdot s}\end{aligned}\).

Answer:a

Explanation:because I know

Answer:

B & C

Explanation:

the first block will not move

Answer:

Ask a question.

Explanation:

Your question is the basis of any theory.

Answer:

The kinetic energy of the sliding block is =1/2×m×v  

2

 =1/2×4×2  

2

=8 J

Now since there is no friction on the surface then it is a conservative system. So all the energy of the block will be transferred to the spring and will store as a potential energy. Suppose it will compress the spring by an amount of x m. So the potential energy of the spring will be =1/2×k×x  

2

Equating there two energies and solving for x, we will get, 1/2×k×x  

2

=8

Or  0.5(400)x  

2

=8

⟹x=0.2 m.  

Explanation:

Answer: If i'm not mistaken I think it A) potential

Digital Subscriber Line (DSL) is a family of point-to-point technologies designed to provide high-speed data transmission over traditional telephone lines.

DSL, or Digital Subscriber Line, is a set of technologies that enable high-speed data transmission over existing telephone lines. It revolutionizes the use of traditional telephone infrastructure by allowing users to access the internet at faster speeds without requiring costly upgrades or laying new cables.

DSL technology utilizes the existing copper wire infrastructure of telephone networks to transmit data digitally, offering faster connection speeds compared to traditional dial-up modems.

By employing different variations such as Asymmetric DSL (ADSL), Symmetric DSL (SDSL), and Very-high-bit-rate DSL (VDSL), DSL provides users with reliable and high-speed internet access.

ADSL, the most common form of DSL, offers faster download speeds than upload speeds, making it suitable for applications such as web browsing, video streaming, and online gaming.

SDSL, on the other hand, provides equal upload and download speeds, making it ideal for businesses that require efficient data transfer in both directions.

VDSL, the fastest variant of DSL, offers significantly higher speeds and is commonly used for delivering high-bandwidth services like high-definition video streaming, video conferencing, and VoIP telephony.

DSL technology has played a vital role in bridging the digital divide by providing broadband access to areas where fiber-optic or cable connections are not available or economically feasible.

It has empowered countless individuals, households, and businesses by enabling them to access and utilize online resources, services, and opportunities.

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The acceleration of the mass center is \(a = 7.857 rad / s^2\)

and the angular acceleration of the beam at this instant, \(a_{G} = 34.1 ft/ s^2\)

The mass moment of inertia of the beam :

Thus Ig  = 1/2 ml^2

this implies Ig = 1/2 ( 150/ 32.2 ) (12^2)

Thus the required value of Ig = 55.90 slug ft^2

Sigma f of x = m(a g)x

which is equal to Sigma f of x  = 21.47 ft/s^2 --------- 1

because 200 cos 60 = 150/ 32.2 (ag)x

and Sigma f of y = m a (g)y = 26.45 ft^2 --------2

because 200 sin 60 = 55.90α + 100(6)

The acceleration of the mass centre is a = 7.857 rad / s^2

Thus the magnitude of the acceleration is

aG = \(\sqrt{21.47^2+ 26.45^2}\)

aG = 34.1 ft/ s^2

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Answer:

Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.

Gradual shift of North Magnetic Pole's position on Earth, steady rise in planet's average temperature and reduction in the Moon's light reflection.

Using climate models, Dr. Washington and his team were able to simulate the effects of physics on a number of weather-related factors, such as "how heat energy, water vapor, and chemicals travel between Earth's seas and the atmosphere." Following that, computers used data from climate models to predict changes in the atmosphere.

These models were utilised to back the 2007 Intergovernmental Panel on Climate Change (IPCC) report's findings that human behaviour directly affects the environment.

Dr. Washington and his group received the 2007 Nobel Peace Prize3 as a result.

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Note: The question given on the portal is incomplete. here is the complete question.

Question: The work of Warren Washington would be most likely to explain which of the following phenomena

Gradual shift of North Magnetic Pole's position on Earth

Steady rise in planet's average temperature

Reduction in the Moon's light reflection.

Increase in Moon light's reflection.

Answer:

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Explanation:

Given:

Blue light of wavelength λ1 = 435 nm

n2 in diamond = 2.42

Find:

Wavelength of light in  diamond λ2

Computation:

Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.

So,

n1λ1 = n2λ2

(1)(435) = (2.42)λ2

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Answer:

180

Explanation:

got it right on acellus

Answer:

pushes or pulls

Explanation:

hope this helps....

Answer:

GPE = Mgh = 132J

Explanation:

Mgh

4.5×9.8×3

132J

Answer: Ferromagnetism is a phenomenon that occurs in some metals, most notably iron, cobalt and nickel, that causes the metal to become magnetic. The atoms in these metals have an unpaired electron, and when the metal is exposed to a sufficiently strong magnetic field, these electrons' spins line up parallel to each other.

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=\(\frac{1}{2}m(v^2-u^2)\)

Using the formula

Work done, W\(=\frac{1}{2}(0.145)((25)^2-0)\)

Work done=\(\frac{1}{2}(0.145)(625)\)

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

The planetary body with the fastest orbit is Mercury, and the one with the slowest orbit is Neptune.

There is a general pattern between orbital velocity and orbital radius known as Kepler's second law of planetary motion. According to this law, a planet sweeps out equal areas in equal times as it orbits the Sun. This implies that planets closer to the Sun have smaller orbital radii and must travel faster to cover the same area in the same amount of time.

The relationship between orbital velocity and orbital radius can be expressed as v ∝ 1/r, where v represents the orbital velocity and r denotes the orbital radius. This relationship shows that as the orbital radius increases, the orbital velocity decreases. In other words, planets farther from the Sun have slower orbital velocities compared to those closer to the Sun.

This pattern is consistent with observations in our solar system. The inner planets, such as Mercury, have smaller orbital radii and faster orbital velocities, while the outer planets, like Neptune, have larger orbital radii and slower orbital velocities.

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F3 is the greatest of all forces , hence 3rd case in which masses were 200kg and 150 kg separated with a distance of 10 will have greatest force of all

The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them is called gravitation force of attraction

gravitation force = Gm1 m2 / \(r^{2}\)

G = gravitational constant

m1 = mass of one object

m2 = mass of other object

r = distance between them

case 1

F1 = G (50) (100) / \(20^{2}\) = 12.5 G

F2 = G (50) (10) / \(10^{2}\)  = 5 G

F3 = G (200) (150) / \(10^{2}\) = 300 G

F4 =  G (200) (150) / \(30^{2}\) = 33.33 G

F3 is the greatest of all forces , hence 3rd case in which masses were 200kg and 150 kg separated with a distance of 10 will have greatest force of all

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Answer:

Echolocating animals emit calls out to the environment and listen to the echoes of those calls that return from various objects near them. They use these echoes to locate and identify the objects. Echolocation is used for navigation, foraging, and hunting in various environments.

Answer:

The velocity of the mass after 10.0 seconds is 50.0 m/s.

Explanation:

Explanation: We can use the formula v = (F t)/m to calculate the velocity of the mass. Given that the force applied is 10.0 N, the mass is 2.00 kg, and the time elapsed is 10.0 s, we can substitute these values into the formula to get:

v = (10.0 N * 10.0 s) / 2.00 kg = 50.0 m/s

Therefore, the velocity of the mass after 10.0 seconds is 50.0 m/s.

Answer:

C: Karl Schwarzschild correctly analyzed the relationship between the size of a black hole and its mass.

Explanation:

Karl Schwarzschild correctly analyzed the relationship between the size of a black hole and its mass. The correct option is C.

A black hole is an area of spacetime in which gravity is so powerful that nothing, not even light or other electromagnetic waves, can escape. According to general relativity theory, a sufficiently compact mass can bend spacetime to generate a black hole.

Karl Schwarzschild, a German physicist, was the first to "find" black holes. In 1915, he proposed a general relativity solution that was applicable to the simple (i.e., nonrotating, uncharged, and boring) example of a perfectly spherical object contained in otherwise empty space.

These suggestions are now known as the Schwarzschild radius and the singularity. Every item is allocated a Schwarzschild radius, which is determined by the object's mass. Gravity's behaviour begins to become strange within this radius.

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Answer:

d = 513 m

Explanation:

Given that,

An echo returned in 3s.

We need to find the distance of the reflecting surface from the source, given that the speed of sound is 342 m/s.

The sound will cover 2d distance. The formula for the speed is given by :

v = d/t

So,

\(v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{342\times 3}{2}\\\\d=513\ m\)

So, the required distance is 513 m.

Answer:

Venus....

Explanation:No explanation just simple answers

Answer:

a. 8.0m/s, b. see below

Explanation:

a. use conservation of linear momentum to find v:

mv_0 + m(0) = m(0) + mv, v_0 = v = 8.0 m/s

b. KE_i = 1/2(4)(8)^2 = 128

KE_f = 1/2(4)(8)^2 = 128

KE_i = KE_f so there's no change in kinetic energy, which proves its an elastic head-on collision

The largest deflection from the isoelectric line in the ECG is found in the QRS complex.

The correct option is D.

An ECG (electrocardiogram) is a medical test that records the electrical activity of the heart. It is a non-invasive procedure that involves attaching electrodes to the skin of the chest, arms, and legs, which detects the electrical signals generated by the heart as it beats. These signals are amplified and recorded, producing a visual representation of the heart's electrical activity over time, known as an ECG waveform.

The QRS complex is the largest deflection from the isoelectric line in the ECG. It represents the depolarization of the ventricles and is typically a sharp, narrow peak.

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Answer:

a) Direction, direction

The driver should be at least 39 meters behind the vehicle in front at 30mph. Rounded to 2 significant figures, this is 39 meters

The recommended safe following distance while driving is at least 3 seconds behind the vehicle in front of you. At 30mph (or approximately 13 meters per second), a 2-second following distance would be:

3 seconds x 13 meters/second = 39 meters

Therefore, the driver should be at least 39 meters behind the vehicle in front at 30mph. Rounded to 2 significant figures, it could then be concluded that the driver should be at least 39 meters.

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