calculate δs∘rxn for the balanced chemical equation: 2h2s(g) 3o2(g)→2h2o(g) 2so2(g)

Answer:

5.0

Explanation:

Answer:

option . D

Increase in temperature

is an indicator of a chemical reaction

hope it helps

Answer:

answer is D

Explanation:

some signs of a chemical change are a change in colour and the formation of bubbles.

the five conditions of chemical change: colour change, formation of precipitate, formation of a gas ,odor change, temperature change.

I think it will use for you

In scenario 1. the value of w, work done is positive. 2. the value of w is negative. 3. the value of w or q is positive or negative depending on the situation.

The terms in the given problem are w and q. Let us find out whether the value of w or q is positive or negative in each scenario. Person rolls a bowling ball across the floor, where the bowling ball is defined as the system. (W)In this scenario, the bowling ball has the energy, therefore, work is done on the floor. As the floor receives energy, it would have a positive work. Hence, the value of w is positive.

Person rolls a bowling ball across the floor, where the person is defined as the system. (w)In this scenario, the person has the energy. Therefore, the work is done on the bowling ball. As the bowling ball receives energy, it would have a negative work. Hence, the value of w is negative.

An ice pack is placed on a person's sore back, where the ice pack is defined as the system. (q)In this scenario, the transfer of heat occurs from a hot object (person's back) to a colder object (ice pack). As the heat transfer occurs from the person's back, which is the system, it would have a negative value of q. Hence, the value of w or q is positive or negative depending on the situation.

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Answer:

All objects can have the same size but have a different mass!

This is true, although it sounds fake. This is one example, there is a Neutron star, and Neutron stars are as big as a city, but they have a mass which is hundreds of times greater than our sun's mass. Because of them having so much mass, they are also having so much gravitational energy, which makes them also have gravity. They're so small, but have so much mass that they can do much. Even a drop of a neutron star can punch open the earth! It's true, so yes, it is possible for objects the SAME size to be having different masses according to that example.

But let's look on how they can have different mass.

They can have different masses becase of different densities. Put a iron ball inside water, and put an apple as close to the iron ball's side, what happens? The apple floats, becuase the apple's mass is less than the water, and the iron ball's mass is MORE than the water. So, because the iron ball is denser than the apple, that's why, it has more mass than the apple. The apple isn't much dense, it isn't as dense as water or the iron ball. But the iron ball is much more denser than the water. So because of the different material densities of the material, that's why it can have different masses.

Remember to Remember those 2 examples I gave you... (neutron star vs sun, iron ball vs apple on water)

75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.

To determine the amount of a 0.20% (m/v) KCl IV solution that can be prepared from a 5.0% (m/v) stock solution, the following formula can be used:

C1V1 = C2V2

where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the desired concentration of the final solution, and V2 is the volume of the final solution.

In this case, C1 = 5.0%, V1 = 3.0 L, C2 = 0.20%, and V2 is what we are trying to find.

First, convert the percentages to decimals:

C1 = 0.050

C2 = 0.0020

Now we can plug in the values and solve for V2:

(0.050)(3.0) = (0.0020)(V2)

0.15 = 0.0020V2

V2 = 75 L

Therefore, 75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.

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75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.

To determine the amount of a 0.20% (m/v) KCl IV solution that can be prepared from a 5.0% (m/v) stock solution, the following formula can be used:

C1V1 = C2V2

where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the desired concentration of the final solution, and V2 is the volume of the final solution.

In this case, C1 = 5.0%, V1 = 3.0 L, C2 = 0.20%, and V2 is what we are trying to find.

First, convert the percentages to decimals:

C1 = 0.050

C2 = 0.0020

Now we can plug in the values and solve for V2:

(0.050)(3.0) = (0.0020)(V2)

0.15 = 0.0020V2

V2 = 75 L

Therefore, 75 liters of a 0.20% (m/v) KCl IV solution can be prepared from 3.0 L of a 5.0% (m/v) stock solution.


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Answer:

8

Explanation:

This number normally equals the number of electrons that atom needs to have a total of eight electrons (an octet) in its outer shell.

Answer:

Be sure to answer all parts. this is a two-part question. first, draw the minor alkene product that should be formed in the reaction. second, draw a stepwise mechanism that shows the formation of the major product: part 1: 2xsafari + view structure major product minor product part 2: view structure h5mech30504 view structure + br+ br− ch3obr+ ch3oh2+ part 3 out of 3 edit structure ... arr edit structure ... + br+ ch3oh2+ ch3obr+ br−

Explanation:

The major organic product for the given transformation is a β-hydroxy carbonyl compound formed through enolate ion formation, nucleophilic addition, and protonation steps.

To determine the major organic product for the following transformation using 1) LDA, -78°C, THF; 2) CH₃CHO, THF; 3) H₂O, follow these steps:

Step 1: LDA (lithium diisopropylamide) is a strong base that deprotonates the most acidic proton in the starting material at -78°C in THF (tetrahydrofuran) solvent. This step generates an enolate ion.

Step 2: CH₃CHO (acetaldehyde) reacts with the enolate ion in THF through a nucleophilic addition reaction. The enolate ion attacks the carbonyl carbon of CH₃CHO, forming an alkoxide intermediate.

Step 3: H₂O (water) is added to the reaction mixture to protonate the alkoxide intermediate, which yields the final major organic product, typically a β-hydroxy carbonyl compound.

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Answer: It will expand to fill the room.

Explanation:

Gases will expand or compact to fill the available space.

Answer:

500/100=5m

W=F*D

W=20*5=100Nm

Explanation:

The work done in Nm on the object is 100 Nm

Since A force of 20N acts on an object. It causes a displacement of 500 cm in the direction of the force.

Since the displacement is in cm

So, in meters, it should be like

= 500 / 100

= 5 m

Now we know that

Work done = force * displacement

= 20N * 5

= 100 Nm

hence, The work done in Nm on the object is 100 Nm

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Answer:

Oxidation state for Mg(s) is 0

Explanation:

This is redox reaction, where one element is oxidized and another is reduced.

H from water is being reduced while the Mg which is in ground state is oxidized.

When the element is reduced, the oxidation state is decreased:

2H⁺ + 2e⁻  ⇄  H₂

When the element is oxidized, the oxidation state is increased

Mg ⇄ Mg²⁺ + 2e⁻

As Mg(s) in the product side, is at ground state, the oxidation state is 0.

Any element in ground state has 0, as oxidation state.

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

The molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution is 1.79.

Molarity of a given solution is known as the total number of moles of solute per litre of the solution.  A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.

Molarity = (No. of moles of solute ÷ Volume of solution in liters)

The unit of molarity is mol L⁻¹.

Molarity is temperature dependent because as temperature changes, volume of the solution also changes.

Given,

No. of moles = 0.256

Volume of solution = 143ml

Molarity = (0.256 ÷ 0.143) = 1.79

Therefore, The molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution is 1.79.

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The balanced equation for the given chemical reaction is:

Cu(s) + 4 HNO3(aq) → Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l)

In this chemical reaction, copper (Cu) reacts with nitric acid (HNO3) to produce copper nitrate, nitrogen dioxide, and water.

A balanced equation is one where the number of atoms on both sides of the equation is the same. The balanced equation shows that one copper (Cu) atom reacts with four nitric acid (HNO3) molecules, forming one copper nitrate (Cu(NO3)2) molecule, two nitrogen dioxide (NO2) molecules, and two water (H2O) molecules.

Thus, when the given equation is balanced with the lowest whole-number coefficients, the coefficients are:

Cu(s) + 4 HNO3(aq) = Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l).

Therefore, the coefficients of the equation are Cu(s) + 4HNO3(aq) + Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l).

The solution to the problem above was provided with the correct balanced equation and a thorough explanation.

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Answer:

Last option is the correct choice.

Explanation:

Number of protons = 60-33 = 27

Superscript 60 Subscript 27 upper C o.

Best Regards!

yeah, its D. 60/27Co

Answer: both

Explanation:

Explanation:

The force of friction is proportional  to the normal force =  mg cos (angle)

   as the angle increases ( shorter incline) the normal force becomes less ( so friction is less)

       the steep ramp is shorter and the force of friction is less  so the longer, less inclined plane will waste more work because friction is higher and ramp is longer.

Another way to look at it....as the ramp becomes steeper and steeper it becomes closer to being vertical....when there would be no friction...thus less wasted work on friction

The temperature at which the pressure will be equal to 1.75 atm, given that the tank has an initial pressure of 101325 Pa is 257.25 degrees celsius

First, we shall list out the given parameters from the question. This is shown below:

The final temperature can be obtain as follow:

P₁ / T₁ = P₂ / T₂

1 / 303 = 1.75 / T₂

Cross multiply

1 × T₂ = 303 × 1.75

T₂ = 530.25 K

Subtract 273 to obtain answer in degree celsius

T₂ = 530.25 – 273 K

T₂ = 257.25 degrees celsius

Thus, the temperature required is 257.25 degrees celsius

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The percent composition of the carbon in the C₆H₁₂O₆ is 40 %.

The chemical compound is  C₆H₁₂O₆.

The molar mass of the compound  C₆H₁₂O₆ = 180 g/mol

The mass of the carbon = 12 g

The percent composition is as follows :

Percent composition of the carbon = ( mass of the carbon / total mass of the compound ) × 100 %

Percent composition of the carbon = ( 72 / 180 ) × 100 %

Percent composition of the carbon  = 40 %

Thus the percentage composition if the carbon is 40 percent in the chemical compound  C₆H₁₂O₆ that is glucose.

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Answer:

2 moles of sugar in 1,000g of water

There are approximately 1.387 moles in 25 grams of water (1) and 134.46 grams in 4.5 moles of Li₂O (2).

1. To calculate the number of moles, we need to divide the given mass of water by the molar mass of water, which is approximately 18.015 g/mol.

Number of moles = 25 grams / 18.015 g/mol

≈ 1.387 moles

Therefore, there are approximately 1.387 moles in 25 grams of water.

2. To calculate the mass in grams, we need to multiply the number of moles by the molar mass of Li₂O, which is approximately 29.88 g/mol.

Mass in grams = 4.5 moles x 29.88 g/mol

≈ 134.46 grams

Therefore, there are approximately 134.46 grams in 4.5 moles of Li₂O.

3. To determine the number of molecules in 23 moles of oxygen, we can use Avogadro's number, which states that there are 6.022 x 10²³ molecules in one mole of any substance. Therefore, for 23 moles of oxygen, we can calculate:

Number of molecules = 23 moles x 6.022 x 10²³ molecules/mole

= 1.38646 x 10²⁵ molecules

So, there are approximately 1.38646 x 10²⁵ molecules in 23 moles of oxygen.

4. To determine the number of moles in 3.4 x 10²³ molecules of H₂SO₄, we can use Avogadro's number. Since one mole contains 6.022 x 10²³ molecules, we can calculate:

Number of moles = (3.4 x 10²³ molecules) / (6.022 x 10²³ molecules/mole)

= 0.564 moles

So, there are approximately 0.564 moles in 3.4 x 10²³ molecules of H₂SO₄.

5. To determine the number of molecules in 25 grams of NH₃, we need to convert grams to moles using the molar mass of NH₃. The molar mass of NH₃ is 17.03 g/mol.

Number of moles = 25 grams / 17.03 g/mol

≈ 1.468 moles

Using Avogadro's number, we can calculate the number of molecules:

Number of molecules = (1.468 moles) x (6.022 x 10²³ molecules/mole)

= 8.831 x 10²³ molecules

So, there are approximately 8.831 x 10²³ molecules in 25 grams of NH₃.

The complete question is:

Answer the following questions:

1) How many moles are in 25 grams of water?

2) How many grams are in 4.5 moles of Li₂O?

3) How many molecules are in 23 moles of oxygen?

4) How many moles are in 3.4 x 10²³ molecules of H₂SO₄?

5) How many molecules are in 25 grams of NH₃ ?

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Answer:

1045 J

Explanation:

By using the formula Eh= mass×specific heat capacity × change in tempreture

With it being a known fact that the specific heat capacity of water is 4.16g/j/°c

The mammoth bone is approximately 11,000 years old. Since the half-life of 14C is 5,500 years and only 25% of the original 14C remains, the bone has undergone two half-lives (50% remaining after 1 half-life, 25% remaining after 2 half-lives). Therefore, 2 half-lives * 5,500 years per half-life = 11,000 years.

To answer your question, we need to use the formula for radioactive decay, which is:

Amount of remaining material = Original amount x (1/2)^(number of half-lives)

In this case, we know that the half-life of 14C is approximately 5500 years. We also know that only 25% of the original 14C is left in the mammoth bone. So, we can set up the equation like this:

0.25 = 1 x (1/2)^(number of half-lives)

We can solve for the number of half-lives by taking the logarithm of both sides of the equation:

log(0.25) = log(1) - number of half-lives x log(2)

Simplifying this equation gives us:

number of half-lives = log(1/0.25) / log(2)

number of half-lives = 2

Now that we know the number of half-lives, we can use the half-life of 14C to calculate the age of the mammoth bone. Since there are two half-lives, the age of the mammoth bone is:

Age = 2 x 5500 years

Age = 11,000 years

So the mammoth bone is approximately 11,000 years old. I hope that helps! Let me know if you have any further questions.

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Answer:I’m 100% it’s the second one

Explanation:

I have done it before and missed one but not this question

After a proton is removed from the -OH group, the compound that will form a cyclic ether more rapidly is an alcohol compound containing a primary alcohol \((-CH_{2}OH)\) than that containing a secondary alcohol (-CHOH) group.

Protons can be removed from the OH group of alcohols by the use of strong bases. Primary alcohols have a \((-CH_{2}OH)\) group attached to the carbonyl carbon, while secondary alcohols have a CHOH group attached to it. In general, primary alcohols form cyclic ethers more rapidly than secondary alcohols after the removal of a proton from the -OH group.

This is due to the fact that the carbonyl carbon of a primary alcohol is less hindered than the carbonyl carbon of a secondary alcohol. As a result, the formation of a cyclic ether from a primary alcohol is less energy-intensive and hence occurs more quickly than the formation of a cyclic ether from a secondary alcohol.

Therefore, the alcohol compound containing a primary alcohol \((-CH_{2}OH)\) will form a cyclic ether more rapidly than the alcohol compound containing a secondary alcohol (-CHOH) group after the removal of a proton from the -OH group.

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Answer: D. Synthesis

Explanation:

Sodium Oxide + Water = Sodium Hydroxide

Answer:

16 g Ag

General Formulas and Concepts:

Chemistry - Stoichiometry

Chemistry - Atomic Structure

Explanation:

Step 1: Define

[RxN]   Cu (s) + AgNO₃ (aq) → CuNO₃ (aq) + Ag (s)

[Given]   25 g AgNO₃

Step 2: Identify Conversions

[RxN]   1 mol AgNO₃ = 1 mol Ag

Molar Mass of Ag - 107.87 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Step 3: Stoichiometry

\(25 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3} )(\frac{1 \ mol \ Ag}{1 \ mol \ AgNO_3} )(\frac{107.87 \ g \ Ag}{1 \ mol \ Ag} )\) = 15.8744 g Ag

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

15.8744 g Ag ≈ 16 g Ag

Answer:

\(\boxed {\boxed {\sf About \ 16 \ grams \ of \ silver}}\)

Explanation:

We are given the reaction:

\(Cu_{s}+AgNO_{3(aq)} \rightarrow CuNO_{3(aq)}+Ag_{s}\)

We know that there are 25 grams of silver nitrate, or AgNO₃. First, we must find the molar mass of silver nitrate.

Silver Nitrate (AgNO₃)

Identify the molar masses of each element in silver nitrate using the Peirodic Table.

Next, calculate the molar mass. There is a subscript of 3 after the O, so we must multiply oxygen's molar mass by 3.

AgNO₃= (107.868 g/mol) + (14.007 g/mol)+(49.997 g/mol)=169.872 g/mol

Silver

Next, use stoichometry to find the mass of the silver.

\(25 \ g \ AgNO_3*\frac{1 \ mol \ AgNO_3}{169.872 \ g \ AgNO_3}\\\)

\(\frac{25 \ mol \ AgNO_3}{169.872}= 0.1471696336 \ mol \ AgNO_3\)

In this reaction, 1 mole of silver nitrate yields 1 mole of silver.

   2. Convert moles of silver nitrate to moles of silver.

\(0.1471696336 \ mol \ AgNO_3*\frac{1 \ mol \ Ag}{1 \ mol \ AgNO_3}=0.1471696336 \ mol \ Ag\)

We know that silver's molar mass is 107.868 grams per mole.

   3. Convert moles of silver to grams of silver.

\(0.1471696336 \ mol \ Ag*\frac{107.868 \ g\ Ag}{1 \ mol \ Ag }\)

\(0.1471696336 *{107.868 \ g\ Ag}=15.87489404 \ g\ Ag\)

   4. Round

The original measurement given had 2 siginficant figures (25= 2 and 5). Therefore, we must round to 2 sig figs or the nearest whole number for this problem.

The 8 in the tenth place tells us to round up to the nearest whole number.

\(15.87489404 \ g \ Ag \approx 16 \ g\ Ag\)

About 16 grams of silver would be produced.

The  tendency for water molecules to be attracted and stick to other substances is called adhesion.

There are two forces of attraction that exists between molecules of substances.

The two forces of attraction are as follows:

Cohesion - this is the force of attraction that exists between molecules of the same substance, for example between water molecules.

Adhesion - this is the force of attraction between molecules of the different substances, for example water molecules and glass.

Therefore, the tendency for water molecules to be attracted and stick to other substances is called adhesion.

In conclusion, the forces of attraction between molecules are cohesion and adhesion.

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