calculate the de broglie wavelength for a proton moving with a speed of 1.3 x 10^6 m/s.

Answer:

The angle of incidence is equal to the angle of reflection.

Explanation:

angle of incidence (i) = angle of reflection (r)

So if the angle of incidence was 45°, the angle of reflection would also be 45°.

Given,

The initial speed, u=20.00 m/s

The distance between the submerine and the target is d=2000.0m

The sound of impact is heard after T=101.4 s.

To find

The speed of sound in water.

Explanation

Here the total time taken to reach the submarine is the sum of thetime taken by the torpedo to reach the target and the time taken for it to come back.

Let the speed be v.

Thus,

Conclusion

Speed of the sound in water is 1428.6 m/s

Answer:

63016

Explanation:

Ri+R2+R3 this is called series circuit

Answer:

200

Explanation:

100+200=300

1/300+1/600=200

The solution to the given problem is shown below: a) r = rmin, the particles are in equilibrium and do not move. b) The particles are bound because they need an external energy of 0.703E to be separated to an infinite distance.

a). Plot Etotal and KE as a function of r.

The potential energy (U) for the given potential function isU(r) = 2.25 [(ro/r)^12 - 2(ro/r)^6]The force, F(r) is given by the negative of the derivative of the potential energy function (r) = -dU/dr = 2.25 (12(ro/r)^13 - 12(ro/r)^7) / rEtotal and KE can be calculated using the following equations:

Etotal = KE + UKE = (1/2) mu^2Here,

m = mass of each particle and

u = relative velocity of the particles

We know that the total energy (Etotal) of the particles is 1.2E.

Therefore, KE = Etotal - U

The plot of Etotal and KE as a function of r is shown below:

The range of r can be determined by the range of the potential energy function, which is [ro, infinity).

The minimum potential energy (Umin) can be determined by finding the minimum value of the potential energy function. This can be found by equating dU/dr = 0, which gives (ro/r)^13 = (ro/r)^7.

Solving this equation gives r = ro (rmin).

At r = rmin,

the potential energy function has its minimum value Umin = -0.703E.

The maximum force (Fmax) can be found by equating dF/dr = 0, which gives

r = 1.122 ro.

At r = 1.122 ro,

the force has its maximum value Fmax = 2.355E.

The plot shows that Etotal is minimum at r = rmin and maximum at r = infinity.

KE is zero at r = rmin and maximum at r = infinity.

At r = rmin, the particles are in equilibrium and do not move.

b) The particles described above are bound. The potential energy function has a minimum value of Umin = -0.703E. Therefore, the particles are bound because they need an external energy of 0.703E to be separated to an infinite distance.

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Answer:

hhuuufuhrhuuuryheu7uhhehfu

The force exerted by only the fluid on the window of an instrument probe at this depth is 740 N.

To determine the force exerted by only the fluid on the window of an instrument probe, we need to use the equation for pressure:

pressure = density x gravity x depth

where density is the density of the fluid, gravity is the acceleration due to gravity, and depth is the distance from the surface of the fluid to the window of the instrument probe.

Assuming that the fluid is water, with a density of 1000 kg/m³, and that the instrument probe is at a depth of 10 meters, we can calculate the pressure:

pressure = 1000 kg/m³ x 9.81 m/s² x 10 m
pressure = 98,100 Pa

To find the force exerted on the circular window, we need to calculate the area of the window:

area = π x (diameter/2)²
area = π x (3.10 cm/2)²
area = 7.55 cm²

Now we can calculate the force:

force = pressure x area
force = 98,100 Pa x 7.55 cm²
force = 740 N

Therefore, the force exerted by only the fluid on the window of an instrument probe at this depth is 740 N.

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If we apply same force  to both-an apple or a couch, the object which will accelerate less is couch.

What is acceleration?

Acceleration is the term used to describe the pace at which speed and direction of velocity vary over time. Something is said to be accelerating when it starts to move faster or slower. Even when the speed is constant, motion on a circle accelerates because the direction is always keeps shifting. Both impacts cause all other motions to speed up.

The couch will accelerate less because

F = m a

where, F = force, m = mass, a = acceleration.

This equation can also be written as

a = F/m

It tells us that the acceleration is inversely proportional to mass.

so, in the question given the mass of couch will greater as compared to an apple so the acceleration of the couch will be lesser as compared to apple.

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The speed of water in the constriction is faster when compared to the rest of the pipe.

The venturi effect consists of a physical phenomenon applied in fluid dynamics in which the pressure of flow decreases when there is a constraint in the conduct, accompanied by an increase in velocity of the fluid due to a decrease in cross-sectional area of the conduct.

The constriction is said to have a lower radius when compared to the rest of the pipe.

Applying the equation of continuity, A₁ v₁ = A₂ v₂

where, A is the area

v is the velocity

It is said from the above equation that, if area decreases velocity increases and if area increases velocity decreases, as velocity and area are inversely proportional to each other.

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We could derive this , as ;

\(\sf \longrightarrow Work = F s cos\theta \\ \)

\(\sf \longrightarrow Work = (ma)(s)(cos0^o)\\\)

\(\sf \longrightarrow\pink{ Work = m \ a \ s } \dots (i)\)

\(\sf \longrightarrow 2as = v^2 -u^2\)

where the symbols have their usual meaning.

\(\sf \longrightarrow as =\dfrac{1}{2}(v - u)^2\\ \)

Multiplying both sides by m,

\(\sf \longrightarrow mas = \dfrac{m}{2}(v-u)^2 \)

Now from equation (i),

\(\sf \longrightarrow Work = \underbrace{\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2} \)

Above term on RHS is change in the Kinetic energy , therefore ,

\(\sf \longrightarrow \underline{\boxed{\bf Work = \Delta Energy_{(Kinetic)} }}\)

a) The force diagram of the block and all the forces are in the image attached.

(b) The weight of the block and its parallel component is  98.1 N and 33.55 N respectively.

(c) The applied force on the block is 52.75 N

(a) The force diagram of the block include, the parallel and pedicular component, as well as friction force.

(b) The weight of the block and its parallel component is calculated as;

Fg = mg

where;

Fg = 10 kg x 9.81 m/s²

Fg = 98.1 N

Fgₓ = mgsinθ

Fgₓ = 98.1 N x sin(20)

Fgₓ = 33.55 N

(c) The applied force on the block is calculated as follows;

F - Fgₓ - μFgcosθ = ma

where;

μ = a/g

μ = 1 / 9.81 = 0.1

F - 33.55 - 0.1(98.1 x cos20) = 10 x 1

F - 33.55 - 9.2 = 10

F = 10 + 33.55 + 9.2

F = 52.75 N

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Answer:

D. Nuclear energy

Explanation:

A nucleus is the result of nuclear energy if it is split into an other the same result shall happen it being nuclear energy.

We are given two vectors and we are asked to determine the direction of their sum. To do that we will rewrite them on coordinates form. For vector A, since it is a horizontal vector it only has an x-coordinate equivalent to its magnitude, like this:

For vector B we will use the following formula:

Replacing the values:

Solving the operations

If it is critical to measure the wavelengths precisely for a given lamp, the grating with the highest number of lines per centimeter (lines/cm) should be used. In this case, the grating with 800 lines/cm would be the most suitable option.

Gratings are optical devices with a periodic pattern of equally spaced lines or grooves. They are commonly used in spectroscopy to disperse light into its component wavelengths. The number of lines per centimeter on a grating determines its resolution or ability to separate closely spaced wavelengths.

Higher line densities (more lines/cm) provide finer resolution and allow for more precise measurement of wavelengths. With a grating having 800 lines/cm, it would offer a higher resolution compared to the gratings with 400 lines/cm or 100 lines/cm. This means it would enable more accurate determination of the specific wavelengths present in the lamp's emission spectrum.

By using the grating with the highest line density, finer details in the lamp's spectrum can be resolved, resulting in more precise measurements of the wavelengths.

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Answer:  I'm unable to directly draw figures. However, I can provide you with a verbal description of how the wave pulse on the string would look at different times.

Given:

Wave speed = 40 cm/s

Time intervals: t = 15 ms, 20 ms, 25 ms, 30 ms, 35 ms, 40 ms, and 45 ms

a) Assuming point 0 is a fixed end:

At t = 0 ms (initial position):

The pulse starts at point 0 and propagates to the right.

At t = 15 ms:

The pulse has traveled 15 ms * 40 cm/s = 600 cm (or 6 meters) to the right from the initial position.

At t = 20 ms:

The pulse has traveled 20 ms * 40 cm/s = 800 cm (or 8 meters) to the right from the initial position.

At t = 25 ms:

The pulse has traveled 25 ms * 40 cm/s = 1000 cm (or 10 meters) to the right from the initial position.

At t = 30 ms:

The pulse has traveled 30 ms * 40 cm/s = 1200 cm (or 12 meters) to the right from the initial position.

At t = 35 ms:

The pulse has traveled 35 ms * 40 cm/s = 1400 cm (or 14 meters) to the right from the initial position.

At t = 40 ms:

The pulse has traveled 40 ms * 40 cm/s = 1600 cm (or 16 meters) to the right from the initial position.

At t = 45 ms:

The pulse has traveled 45 ms * 40 cm/s = 1800 cm (or 18 meters) to the right from the initial position.

b) If point 0 is a free end:

The behavior of the wave pulse will be different when point 0 is a free end. Instead of reflecting back, the pulse will continue to propagate and undergo superposition with the transmitted pulse.

The transmitted pulse will travel to the right, while a reflected pulse from the free end will travel to the left. The superposition of these two pulses will create a more complex wave pattern.

To accurately describe the total wave on the string at each given time, it would be helpful to have more information about the shape and characteristics of the initial pulse, such as its amplitude and shape.

At each given time, the wave pulse will simply have moved 40 cm further in the same direction from its initial position.If point 0 is a fixed end, the wave pulse will undergo reflection at point 0 and invert its direction.

The wave speed is 40 cm/s, so in 1 ms (millisecond), the wave will travel 40 cm.At t = 15 ms, the wave pulse will have traveled 40 cm in one direction from point 0.

At t = 20 ms, the wave pulse will have reached point 0 and started to reflect back, resulting in a double amplitude.At t = 25 ms, the wave pulse will have traveled 40 cm in the opposite direction.This reflection and propagation pattern continues. At t = 30 ms, the pulse will have reached point 0 again, and so on.

If point 0 is a free end, there will be no reflection. The wave pulse will propagate freely in one direction with a constant speed of 40 cm/s.

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when the dog catches up with the man, the man would have traveled approximately 3.58 meters, and the dog would have traveled approximately 3.79 meters.

To find the distance traveled by the man and the dog when the dog catches up with the man, we need to calculate the time it takes for the dog to catch up.

Let's assume that the time it takes for the dog to catch up is t seconds.

During this time, the man would have already been jogging for t seconds at a speed of 1.1 m/s. Therefore, the distance traveled by the man is given by:

Distance_man = (speed_man) * (time) = (1.1 m/s) * (t)

On the other hand, the dog starts running after waiting for 2.1 seconds. So, the time the dog runs is t - 2.1 seconds. The distance traveled by the dog is then given by:

Distance_dog = (speed_dog) * (time) = (3.1 m/s) * (t - 2.1)

Since the dog catches up with the man, the distances traveled by the man and the dog will be equal. Therefore, we can set up the equation:

(1.1 m/s) * (t) = (3.1 m/s) * (t - 2.1)

Simplifying this equation, we get:

1.1t = 3.1t - 6.51

2t = 6.51

t = 3.255 seconds

Now, we can substitute this value back into the expressions for Distance_man and Distance_dog to find the distances traveled:

Distance_man = (1.1 m/s) * (3.255 s) ≈ 3.58 meters

Distance_dog = (3.1 m/s) * (3.255 s - 2.1 s) ≈ 3.79 meters

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Answer:

858.7 N

Explanation:

The magnetic force on the charge F = Bqv where B = magnetic field strength = 4.02 mT = 4.02 × 10⁻³ T, q = charge = 7.12 μC = 7.12 × 10⁻⁶ C and v = c = speed of light = 3 × 10⁸ m/s

F = Bqc

=  4.02 × 10⁻³ T × 7.12 × 10⁻⁶ C × 3 × 10⁸ m/s

= 858.7 N

The marking on the scale is 4.79 cm

A crucial numeracy skill is the ability to read scales. Additionally, it supports theories about the density of the number line. Students require a firm grasp of decimal notation in order to make readings between labeled points on a scale. If it's a scale, such as a bathroom scale, it effectively tells you how much pressure is exerted on it. A weight or mass might be the reading since they are proportionate. However, since your weight would be lower there, if you used that scale on the surface of the moon, it would read lower. Scale factor = Dimension of the new shape Dimension of the original shape is the fundamental formula used to calculate it.

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Answer:

The answer is false

because they are held an electric forces or attraction

while the planets are held bt Gravitational foces

which allows them to move about their axis.

Answer: False

This statement is false

\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

The given statements are :

Q1) Distance formula is displacement/time T/F?

- False

Q2)velocity formula is = displacement/time T/F?

- True

The period of the string’s oscillation if the string of a cello playing the note "C" oscillates at 264 Hz is 0.00378 seconds.

We define periodic motion to be a motion that repeats itself at regular time intervals, such as exhibited by the guitar string or by an object on a spring moving up and down. The time to complete one oscillation remains constant and is called the period T.

To calculate the period of the string's oscillation, the formula is given as;`

T=1/f`

Where T is the period of oscillation and f is the frequency of the wave.

Given that the frequency of the wave is 264 Hz, we can calculate the period as;`

T=1/f = 1/264

T = 0.00378 seconds (rounded to five significant figures)

Therefore, the period of the string's oscillation is 0.00378 seconds.

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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Sorry but I can't help you cuz the words you use makes no sens if you are going to ask a question pls do and dont joke around about it thank you very much and have a great day! ^^

(a) The angle the planks make with the ground in order for the lathe to slide down at constant velocity is 90⁰.

(b) Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

The given parameters:

The net force on the wooden skids is calculated as follows;

\(\Sigma F = 0\\\\F - \mu mg cos\theta = 0\\\\ma - \mu mg cos\theta = 0\\\\ma = \mu mg cos \theta \\\\a = \mu g cos\theta\\\\at \ constant \ velocity , \ a = 0\\\\0 = \mu g cos \theta\\\\cos \theta = 0\\\\\theta = 90 ^0\)

Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

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We are asked to find the gravitational force that you exert on earth.

First, convert the mass of 100 pounds into kg.

1 kg is equal to 2.205 pounds.

Recall Newton's Universal law of gravitation given by

Where M is the mass of Earth, m is the mass of the person, G is the gravitational constant, and R is the radius of the Earth.

G = 6.67×10⁻¹¹ m³/kg⋅s²

M = 5.97×10²⁴ kg

R = 6.37×10⁶ m

m = 45.36

Let us substitute all the given values into the above formula

Therefore, the gravitational force that you exert on earth is 445.14 N

gas is the answer for this question

can you make me a brainlist