Calculate the heat absorbed, in kJ, when 2000. g of water is heated from 20.0 °C to 99.7 °C in an electric kettle

Answer: sodium (Na +) cation and fluoride (F -) anion

Explanation:

Formula and structure: The chemical formula of sodium fluoride is NaF and its molar mass is 41.99 g/mol. It is a simple ionic compound, made of the sodium (Na +) cation and fluoride (F -) anion. The solid salt exists as cubic crystals similar to the crystal structure of sodium chloride (NaCl).

Answer:

only 2.5% is fresh water on earth

Answer:

The answer is 3%

Explanation:

Answer:

30 I guess

Explanation:

Particle arrangement, shape, and size of the four states of matter generally decreases from solids to plasma, whereas particle motion and compressibility increases from solids to plasma.

The four states of matter are:

Comparison of the properties of the four states of matter in terms of particle arrangement, particle motion, shape, size, and compressibility can be summarized as follows:

Therefore, the particle arrangement, shape, and size of the four states of matter generally decreases from solids to plasma, whereas particle motion and compressibility increases from solids to plasma.

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Answer:

“Newton’s Law of Gravity” gives the gravity force between two objects with masses m

and M separated by distance r:



F  G

m M

r

2

G is called the Gravitational Constant, and has the value



6.671011N m

2

kg2

(N is for

Newton, the physicists’ unit of force) or



1.51011 lbm

2

kg2

.

Let’s go back to the example given in the text: two 150 lb people separated by 1 meter.

The mass of each person is



150lb

2.2

lb

kg

 68kg

. Putting these into the formula gives



F 1.5101 1 lb m

2

kg2



(68kg)

2

(1m)

2

107

lb.

Newton’s Law of Gravity actually gives the force only between two small objects. If one

of the objects is a sphere (such as the Earth) then it turns out that you can still use the

formula, but you must use the distance to the center of the sphere as the value for r. As

an example, let’s put in numbers for a 1 kg object sitting on the surface of the Earth.

Then the force of attraction is given by the gravity equation with m = 1 kg, M = the mass

of the Earth =

24 610

kg, and r = radius of the Earth (that’s the distance to the center of

the sphere). This distance is r = 6371 km ≈

6

610

meters. Without plugging in the

numbers, can you guess what the answer will turn out to be? Guess, and then check this

footnote2

to see if you guessed correctly.

Suppose you weigh 150 lbs on the Earth. Then your mass is



150lb

2.2

lb

kg

 68kg

. What will

you weigh on the Moon? We can calculate that by using Newton’s Law of Gravity, and

putting in the M = the mass of the Moon =

22 7.310

kg, r = the radius of the moon =

6

1.710

meters. The answer is F = 25 lb. That means you will weigh 25 lb. on the

surface of the Moon.

Explanation:

hope this helps :)

Alkenes are useful in the production of polymers. They create polymers when smaller molecules are arranged end to end. The smallest molecules are known as monomers. The polymer's tensile strength grows as chain length and cross-linking do.

A monomer is a molecule from a group of substances, primarily organic compounds, that can combine with other molecules to produce much larger molecules, or polymers. A monomer's ability to create chemical interactions with at least two other monomer molecules, known as polyfunctionality, is its primary characteristic.

Monomers include substances like ethylene, amino acids, vinyl chloride, and glucose. Each monomer has a different manner of linking to create a variety of polymers.

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Answer:

The number of years it would take you to earn what Mike Trout will earn on his contract is 4,265

Explanation:

Mike Trout of the Los Angeles Angels has a contract worth $426,500,000

On the other side, you earn $100,000 per year.

To calculate the number of years it would take for you to earn what Mike Trout will earn from his contract, you must divide the amount Mike earned by the amount you earned during a year:

$426,500,000 ÷ $100,000 per year= 4,265

The number of years it would take you to earn what Mike Trout will earn on his contract is 4,265

Answer:

oxygen ion O2-

Explanation:

because it has 8 protons and gave gained 2 electron so O2-.

Answer:Yes. Adding or losing neutrons will change the atomic mass without forming a different element.

Explanation: Brainly

Explanation:

9/4 Be +2 (the 9 and 4 are stacked next to Be). Atomic #: 4

Mass #: 9, # protons: 4, # neutrons: 5, #electrons: 2.

31/15 P (31 is stacked over 15 next to the P). Atomic #: 15,

Mass #: 31, # protons: 15, # neutrons: 16, # electrons: 15.

Answer:

D. Pressure

Explanation:

The rate of a reaction is defined as the speed at which the reactants are converted into products. Factors influencing the rate of a reaction are concentration, catalyst, temperature, surface area,  and pressure, etc.

In case of the reaction rate of gases, pressure will only have its affect as pressure do not have any influence on solid and liquid.

While concentration, surface area and catalyst influence all reaction rates including solid, liquids and gases.

Hence, the correct option is (d) pressure.

Explanation:

KMnO4 + H2S + HCl --> KCl + MnCl2 + H2O + S8

Did Cl change oxidation number?

The oxidation  number of Cl in Reactant side is -1

The oxidation number of Cl in product side is -1

NO

Did Oxygen change oxidation number?

The oxidation number of O in Reactant side is -2

The oxidation number of O in product side is -2

NO

Did H change oxidation number?

The oxidation number of H in Reactant side is 1

The oxidation number of H in product side is 1

NO

Did Mn change oxidation number?

The oxidation number of Mn in Reactant side is +7

The oxidation number of Mn in product side is +2

YES

Did S change oxidation number?

The oxidation number of S in Reactant side is -2

The oxidation number of S in product side is 0

YES

Oxidizing agent (element with decrease in oxidation number) = Mn

Reducing agent (element with Increase in oxidation number) = S

Answer:

The IUPAC structure only shows bond pairs and lone pairs. In the flouromethane structure above, there is only one bond pair and three lone pairs of electrons. Therefore there is one electron remaining, but since it doesn't not make up a pair, it is ignored in the structure but theoretically it is present.

\(.\)

Answer:

therefore there is one electron remaining , but since it doesn't make up a pair . It is ignored in the structure but theoretically it is present .

K (s) + ZnCl (aq) ====》 KCl ( aq) + Zn (s)

Answer:

4.8x10⁻³ Liters are required

Explanation:

Molarity is an unit of concentration in chemistry defined as the ratio between moles of solute (In this case, silver nitrate) and liters of solution.

The 0.50M solution contains 0.50 moles of silver nitrate per liter of solution.

To provide 2.4x10⁻³ moles Silver nitrate are required:

2.4x10⁻³ moles * (1L / 0.50 moles) =

Answer:

option C 11

is the correct answer

A heavy-duty oxygen regulator is the best choice for oxyacetylene cutting because it ensures a consistent and precise flow of oxygen to the torch.

This is essential for maintaining a stable flame and achieving clean and accurate cuts. Additionally, a heavy-duty regulator is designed to handle the high-pressure demands of oxyacetylene cutting, making it more durable and reliable for this specific application.

Furthermore, a heavy-duty regulator typically includes features that enhance safety during oxyacetylene cutting. These may include pressure relief valves and gauges that allow for precise monitoring of oxygen flow and pressure.  

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Answer:

Molar mass of the unknown gas is 8.96g/mol

Explanation:

Hello,

According to Graham's law of diffusion, its states that the rate of diffusion of a gas is inversely proportional to the square root of its molecular mass

R = k (1/√(M))

R = rate of diffusion

M = molecular mass

R₁ / R₂ = √(M₂ / M₁)

R₁ = nitrogen = 68.3s

R₂ = unknown gas = 85.6s

M₂ = molecular mass of the unknown gas

M₁ = molecular mass of nitrogen = 14g/mol

68.3 / 85.6 = (√M₂ / 14)

0.8 = (√M₂ / 14)

Take square of both sides

0.8² = M₂ / 14

M₂ = 14 × 0.64

M₂ = 8.96g/mol

The molar mass of the unknown gas is 8.96g/mol

If Half- life of an isotope is 30 days and it was assumed that the person ate 100 Bq of isotope, there are 50 transformations in the stomach.

The radioactive decay of a sample of an isotope can be characterized by the half-life of that isotope. When a radioisotope undergoes decay, its nucleus becomes unstable, and it emits particles or energy to become more stable. The half-life of an isotope is the time it takes for half of the original sample to decay. The question states that the half-life of an isotope is 30 days, and the person ingested 100 Bq of isotope. It also says to calculate the number of transformations in the stomach using GI track model information .

Since the isotope has a half-life of 30 days, we can use the following formula to find the number of transformations in the stomach:` N = N₀ (1/2)^(t/T₁/₂)`where: N₀ = initial number of nuclei N = final number of nuclei (after time t)T₁/₂ = half-life of the isotope The isotope has a half-life of 30 days, so T₁/₂ = 30 days. The question doesn't specify how long the person has had the isotope in their stomach, so we'll assume it's been there for one half-life, or 30 days. Therefore, t = 30 days.

Substituting into the formula:` N = 100 (1/2)^(30/30)`Simplifying:` N = 100 (1/2)^1`Evaluating:`N = 50`So after 30 days in the stomach, the person would have 50 Bq of the isotope left. Therefore, the number of transformations in the stomach is the difference between the initial number of transformations (100 Bq) and the final number of transformations (50 Bq):`Number of transformations in stomach = 100 - 50 = 50 transformations. Therefore, there are 50 transformations in the stomach.

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The energy of a photon absorbed or emitted during the transition of an electron in a hydrogen atom can be calculated using the Rydberg formula.

The Rydberg formula is given by:

1/λ = R_H x (1/n₁² - 1/n₂²)

Where:

λ is the wavelength of the photon

R_H is the Rydberg constant for hydrogen (approximately 1.097 × 10⁻⁷ m⁻¹)

n₁ is the initial energy level

n₂ is the final energy level

To find the energy of the photon, we can use the equation:

E = h x c / λ

Where:

E is the energy of the photon

h is Planck's constant (approximately 6.626 × 10⁻³⁴ J·s)

c is the speed of light in a vacuum (approximately 3.00 × 10^8 m/s)

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Answer:

I think it's the last one I'm sorry if it's wrong

Explanation:

it sounds like it fits

The percent composition of (a) SiO2 is : Si= 46.70% ; O = 53.30% ; (b) H2SO4 : H= 2.06% ; S = 32.70% ; O = 65.24% ; (c) Na3AlF6 : Na = 32.88% ; Al = 12.86% ; F = 54.26% ; (d) Fe3O4 : Fe = 72.36% ; O = 27.64% ; (e) SO2 : S = 50.11% ; O = 49.89% ; (f) Ca(OH)2 : Ca = 54.08% ; O = 43.17% ; H = 2.74% ; (g) C11H12N205C12 : C = 42.75% ; H = 3.92% ; N = 4.53% ; O = 25.89% ; Cl = 22.91%

The percent composition of the following compounds are as follows:

a) SiO2
Mass of Si = 28.09 g/mol
Mass of O = 2 x 16.00 g/mol = 32.00 g/mol
Molar mass of SiO2 = 28.09 g/mol + 32.00 g/mol = 60.09 g/mol
Percent composition of Si = (28.09 g/mol / 60.09 g/mol) x 100% = 46.70%
Percent composition of O = (32.00 g/mol / 60.09 g/mol) x 100% = 53.30%

b) H2SO4
Mass of H = 2 x 1.01 g/mol = 2.02 g/mol
Mass of S = 32.07 g/mol
Mass of O = 4 x 16.00 g/mol = 64.00 g/mol
Molar mass of H2SO4 = 2.02 g/mol + 32.07 g/mol + 64.00 g/mol = 98.09 g/mol
Percent composition of H = (2.02 g/mol / 98.09 g/mol) x 100% = 2.06%
Percent composition of S = (32.07 g/mol / 98.09 g/mol) x 100% = 32.70%
Percent composition of O = (64.00 g/mol / 98.09 g/mol) x 100% = 65.24%

c) Na3AlF6
Mass of Na = 3 x 22.99 g/mol = 68.97 g/mol
Mass of Al = 26.98 g/mol
Mass of F = 6 x 18.99 g/mol = 113.94 g/mol
Molar mass of Na3AlF6 = 68.97 g/mol + 26.98 g/mol + 113.94 g/mol = 209.89 g/mol
Percent composition of Na = (68.97 g/mol / 209.89 g/mol) x 100% = 32.88%
Percent composition of Al = (26.98 g/mol / 209.89 g/mol) x 100% = 12.86%
Percent composition of F = (113.94 g/mol / 209.89 g/mol) x 100% = 54.26%

d) Fe3O4
Mass of Fe = 3 x 55.85 g/mol = 167.55 g/mol
Mass of O = 4 x 16.00 g/mol = 64.00 g/mol
Molar mass of Fe3O4 = 167.55 g/mol + 64.00 g/mol = 231.55 g/mol
Percent composition of Fe = (167.55 g/mol / 231.55 g/mol) x 100% = 72.36%
Percent composition of O = (64.00 g/mol / 231.55 g/mol) x 100% = 27.64%

e) SO2
Mass of S = 32.07 g/mol
Mass of O = 2 x 16.00 g/mol = 32.00 g/mol
Molar mass of SO2 = 32.07 g/mol + 32.00 g/mol = 64.07 g/mol
Percent composition of S = (32.07 g/mol / 64.07 g/mol) x 100% = 50.11%
Percent composition of O = (32.00 g/mol / 64.07 g/mol) x 100% = 49.89%

f) Ca(OH)2
Mass of Ca = 40.08 g/mol
Mass of O = 2 x 16.00 g/mol = 32.00 g/mol
Mass of H = 2 x 1.01 g/mol = 2.02 g/mol
Molar mass of Ca(OH)2 = 40.08 g/mol + 32.00 g/mol + 2.02 g/mol = 74.10 g/mol
Percent composition of Ca = (40.08 g/mol / 74.10 g/mol) x 100% = 54.08%
Percent composition of O = (32.00 g/mol / 74.10 g/mol) x 100% = 43.17%
Percent composition of H = (2.02 g/mol / 74.10 g/mol) x 100% = 2.74%

g) C11H12N205C12
Mass of C = 11 x 12.01 g/mol = 132.11 g/mol
Mass of H = 12 x 1.01 g/mol = 12.12 g/mol
Mass of N = 1 x 14.01 g/mol = 14.01 g/mol
Mass of O = 5 x 16.00 g/mol = 80.00 g/mol
Mass of Cl = 2 x 35.45 g/mol = 70.90 g/mol
Molar mass of C11H12N205C12 = 132.11 g/mol + 12.12 g/mol + 14.01 g/mol + 80.00 g/mol + 70.90 g/mol = 309.14 g/mol
Percent composition of C = (132.11 g/mol / 309.14 g/mol) x 100% = 42.75%
Percent composition of H = (12.12 g/mol / 309.14 g/mol) x 100% = 3.92%
Percent composition of N = (14.01 g/mol / 309.14 g/mol) x 100% = 4.53%
Percent composition of O = (80.00 g/mol / 309.14 g/mol) x 100% = 25.89%
Percent composition of Cl = (70.90 g/mol / 309.14 g/mol) x 100% = 22.91%

Thus, the percent composition of (a) SiO2 is : Si= 46.70% ; O = 53.30% ; (b) H2SO4 : H= 2.06% ; S = 32.70% ; O = 65.24% ; (c) Na3AlF6 : Na = 32.88% ; Al = 12.86% ; F = 54.26% ; (d) Fe3O4 : Fe = 72.36% ; O = 27.64% ; (e) SO2 : S = 50.11% ; O = 49.89% ; (f) =Ca(OH)2 : Ca = 54.08% ; O = 43.17% ; H = 2.74% ; (g)  C11H12N205C12 : C = 42.75% ; H = 3.92% ; N = 4.53% ; O = 25.89% ; Cl = 22.91%

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In an acidic aqueous solution, the reduction of bismuth oxide ion (BiO₃) to bismuth ion (Bi³⁺) can be represented by the balanced half-reaction:

2 BiO₃ (s) + 6 H⁺ (aq) + 12 e⁻ → 2 Bi³⁺ (aq) + 9 H₂O (l)

The reduction half-reaction involves the conversion of bismuth oxide ion (BiO₃) to bismuth ion (Bi³⁺) in acidic aqueous solution.

To balance the equation, we need to ensure that the number of atoms and charges are equal on both sides.

Start by balancing the atoms other than oxygen and hydrogen. In this case, the only relevant element is bismuth (Bi).

Since there are 3 Bi atoms in BiO₃ and 2 Bi atoms in Bi³⁺, we need a coefficient of 2 in front of BiO₃ to balance the number of Bi atoms.

Next, balance the oxygen atoms by adding water (H₂O) molecules to the side that lacks oxygen. In this case, BiO₃ already contains 3 oxygen atoms, and Bi³⁺ does not contain any oxygen atoms. Therefore, we need 3 water molecules on the product side to balance the oxygen atoms.

Balance the hydrogen atoms by adding hydrogen ions (H⁺) to the side that lacks hydrogen. In this case, BiO₃ does not contain any hydrogen atoms, and Bi³⁺ requires 9 hydrogen atoms to balance. Therefore, we need 9 hydrogen ions on the reactant side.

Finally, balance the charges by adding electrons (e⁻) to the side that is more positively charged. In this case, BiO₃ has a charge of 3- while Bi³⁺ has a charge of 3+. To balance the charges, we need to add 12 electrons on the reactant side.

The balanced half-reaction for the reduction of BiO₃ to Bi³⁺ in acidic aqueous solution is as follows:

2 BiO₃ (s) + 6 H⁺ (aq) + 12 e⁻ → 2 Bi³⁺ (aq) + 9 H₂O (l)

In an acidic aqueous solution, the reduction of bismuth oxide ion (BiO₃) to bismuth ion (Bi³⁺) can be represented by the balanced half-reaction:

2 BiO₃ (s) + 6 H⁺ (aq) + 12 e⁻ → 2 Bi³⁺ (aq) + 9 H₂O (l)

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1s²2s²2p¹.

Explanation:

The electronic configuration of Boron is 1s²2s²2p¹ .

The electron configuration for boron is 1s²2s²2p¹.

Electron configuration of an element describes how electrons are distributed in its atomic orbitals. Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells (with the number of electrons they hold written in superscript) are placed in a sequence.

Electron configuration can be written according to the following rules-

1. Aufbau Principle

2. Pauli's exclusion principle

3. Hund's rule

Electrons will be filled according to the increasing order of the energy as per the n+l rule. Boron has atomic number as 5 that means it has 5 electrons.

Therefore, The electron configuration for boron is 1s²2s²2p¹.

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According to the phase diagram, nitrogen does not have a stable liquid phase at 1 atm. It exists as a gas under normal atmospheric conditions. To observe nitrogen in a liquid state, it requires lower temperatures and/or higher pressures.

The phase diagram for nitrogen typically consists of a graph that shows the temperature (y-axis) plotted against the pressure (x-axis). The diagram includes the regions representing the solid (ice), liquid (water), and gas (vapor) phases of nitrogen.

At standard atmospheric pressure (1 atm), the phase diagram of nitrogen indicates that nitrogen exists as a gas. The line separating the gas phase from the liquid phase is known as the vapor pressure curve. For nitrogen, the vapor pressure curve shows that at 1 atm, the temperature is below the boiling point of nitrogen.

The boiling point of nitrogen is approximately -195.8 degrees Celsius (-320.4 degrees Fahrenheit). At temperatures above the boiling point, nitrogen transitions from a liquid to a gas. However, at 1 atm pressure and temperatures below the boiling point, nitrogen remains in the gas phase.

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Expected results from this experiment suggest that baking soda will provide the most significant relief from acid indigestion.

To conduct an experiment to find out which of the substances, Epsom salt, baking soda, and lemon juice, will ease the discomfort caused by acid indigestion, follow these steps:
1. Begin by administering a set amount of acid indigestion to your grandmother. You can use a standardized quantity of a food item that is known to cause indigestion or use any other reliable method to induce it.

2. Once your grandmother has reported experiencing acid indigestion, give her one of the three substances, i.e. Epsom salt, baking soda, or lemon juice. Use a control group where no substance is given, and the grandmother is left to recover on her own.

3. Monitor her discomfort levels for a specified period, e.g. 30 minutes, 1 hour, 2 hours, etc. Record the time when she reports a reduction in discomfort levels.

4. Repeat the experiment with the other two substances and record the results.

5. Analyze the data and note which substance provided the fastest relief from acid indigestion. Compare the results with the control group.

Baking soda is an alkaline substance, and it can neutralize stomach acid, reducing the discomfort caused by indigestion. Epsom salt and lemon juice are less effective than baking soda, and they may even aggravate the symptoms of indigestion. However, it is always best to consult a healthcare professional if the indigestion persists.

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Explanation:

The two half equations are;

3e + HNO3 → NO

S→ H2SO4 + 6e

When balancing half equations, we have to make sure the number of electrons gained is equal to the number of electrons lost.

Which factor will you use for the top equation?

We multiply by 2 to make the number of electrons =  6e

Which factor will you use for the bottom equation?

We multiply by 1 to make the number of electrons = 6e

Answer:

2

1

Explanation:

9.14moles

According to the Avogadro's constant,

We are to determine the moles of 5.50 x 10^24 molecules of butane. This is expressed as:

Therefore the required mole of butane is 9.14moles

Reduction half-reaction for the conversion of aqueous hydrogen peroxide (H2O2) to liquid water (H2O) in basic aqueous solution is: H2O2 + 2e- → 2OH- + H2O.

Hydrogen peroxide (H2O2) can be reduced to water (H2O) by the addition of electrons and hydroxide ions (OH-) in basic solution. The balanced half-reaction for the reduction of H2O2 involves the addition of two electrons and two hydroxide ions to the molecule of hydrogen peroxide, which results in the formation of two water molecules and two hydroxide ions. The reduction of H2O2 is an oxidation-reduction reaction, and the half-reaction for the reduction of H2O2 is balanced by adding two electrons and two hydroxide ions to the reactant side to ensure that the charge is balanced. The reduction of H2O2 to H2O is a useful reaction in many chemical and biological processes and is often used as a source of oxygen in the chemical industry.

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