Calculate the mass of iron (iii) oxide that contains a trillion iron atoms

Answer:

There are different ways to write this:

N\(a^{+}\) + C\(l^{-}\) + H2O

N\(a^{+}\)(aq) + C\(l^{-}\)(aq)

Explanation:

(aq) means aqueous in water, which means dissolved in water.

Hope this helps.

- profparis

The molar mass of the sugar is 1350 g/mol.

We define the osmotic pressure as the pressure that needs to be applied to  effect the movement of the solvent across a semi permeable membrane.

Number of moles of the sugar solution = 0.459 g/MM

Where MM = molar mass

We know that the osmotic pressure is obtained from;

π = icRT

i = Van't Hoff factor

c = concentration

R = molar gas constant

T = temperature

Let us obtain the concentration;

c = π/iRT

c =  0.0824 atm/ 1 * 0.082 * 298

c = 0.0034 M

Now;

Concentration = Number of moles/volume

Volume = 100.0 mL or 0.1 L

0.0034 = 0.459/MM/0.1

0.0034 = 0.459/0.1MM

0.0034 * 0.1MM = 0.459

MM = 0.459/ 0.0034 * 0.1

MM = 1350 g/mol

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Answer:

B

Explanation:

The picture looks like it is of fungi and fungi is not identified as either plants or animals. They form their own kingdom of life and don't classify as plants or animals.

\(Hello!\)

Your answer is correct.

Because, it doesn't classifed as a animal nor a plant.

Hopefully, this helps you!!

\(Sokka\)

The capacity of a phosphorus atom to create double bonds with other elements like oxygen, nitrogen, and sulfur is further hampered by its size.

Four phosphorus atoms are joined by covalent bonds to form a closed ring structure in white phosphorus molecules. This shape results in a low bond angle, which causes strain inside the molecule and accounts for its extraordinarily reactive properties.

The periodic table's group V elements include nitrogen and phosphorus. Due to their comparable outermost shell electrons, they have several shared characteristics, particularly when forming compounds. Both feature an electron configuration with a ns2 np3 valence shell. Our bodies contain the fourth greatest amount of nitrogen.

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Answer:

a. 2-heptanone is more reactive than 4-heptanone

b. chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone

Explanation:

The reactivity of the carbonyl compound (ketone ) is affected by the steric effect. The steric effect is a hindrance that occurs in the structure or reactivity of a molecule, which is affected by the physical size and the proximity of the adjacent parts of the molecule.

Between 2-heptanone or 4-heptanone, 2-heptanone is more reactive than 4-heptanone. This is because 2-heptanone is less affected by the steric hindrance, unlike the 4-heptanone.

Similarly, the reactivity of the carbonyl compound (ketone) is also affected by the polarity on the carbon compound, which is associated with how electronegative the substituent attached is to the carbonyl compound. From the periodic table, the electronegativity of the Halogen family decreases down the group. Therefore chlorine is more electronegative than bromine.

As such, chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone.

The new volume assuming that the pressure and temperature remain constant is 0.46 L and the correct option is option 1.

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as-

                        PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Initial volume = 1.5 L

Initial moles = 7.5 moles.

Moles remaining = 2.3 moles

\(\frac{n_{1} }{V_{1} } = \frac{n_{2} }{V_{2} }\)

\(\frac{7.5}{1.5 } = \frac{2.3}{V_{2} } }\)

V₂ = 0.46 L

Thus, the ideal selection is option 1.

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Answer:

recognition, intrusion and distraction

Explanation:

If a strong base is added to a buffer the pH will change only slightly. In the non-buffered solution changing the pH significantly.

If a strong base is added to a buffer, the weak acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base: HA + OH- → A- + H2O. Since the added OH- is consumed by this reaction, the pH will change only slightly.

In the non-buffered solution, the added hydronium or hydroxide ions have nothing to react with so the concentrations increase rapidly, changing the pH significantly.  If a base is added to an acidic solution, the solution becomes less acidic and moves toward the middle of the pH scale.

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Answer:

mass number = 120

Explanation:

mass number = proton (atomic number) + neutron

mass number = 55 + 65 = 120

The coordination number of the Pb²⁺ ion in CH₃NH₃PbI₃ is 6. It forms an octahedral arrangement with the six iodine atoms surrounding the central Pb²⁺ ion.

The coordination number of an ion refers to the number of other ions or molecules surrounding it and coordinating with it through bonds. In the case of cations like Pb²⁺, the coordination number indicates the number of surrounding anions that are coordinated with the cation through ionic bonds.

The coordination number is important in determining the physical and chemical properties of compounds and in understanding their structures and reactivity.

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Answer:

The rotation of the Earth.

The mean of the data set is approximately 4.0626, and the 90% confidence interval is [4.060925, 4.064275].

The sample mean (x) is calculated as follows:

x = (4.0620 + 4.0550 + 4.0650 + 4.0740 + 4.0550 + 4.0660) / 6

x ≈ 4.0626 (rounded to four decimal places)

The 90% confidence interval is calculated as follows;

Standard deviation (s):

(4.0620 - 4.0626)² = 0.00000036

(4.0550 - 4.0626)² = 0.00000576

(4.0650 - 4.0626)² = 0.00000006

(4.0740 - 4.0626)² = 0.00001328

(4.0550 - 4.0626)² = 0.00000576

(4.0660 - 4.0626)² = 0.00000012

average of the squared differences:

(0.00000036 + 0.00000576 + 0.00000006 + 0.00001328 + 0.00000576 + 0.00000012) / 6 ≈ 0.00000624

s = √(0.00000624)

s ≈ 0.002496

the standard error of the mean (SEM):

SEM = 0.002496 / √6

SEM ≈ 0.001018

For a 90% confidence interval, the z value is approximately 1.645.

ME = 1.645 * 0.001018 ≈ 0.001675

CI = x ± ME

CI = 4.0626 ± 0.001675

CI ≈ [4.060925, 4.064275]

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Answer:

Example 1

palladium(II) nitrate,

Example 2

Metal catalysts such as Fe, Ni, Mo, and Co are routinely used in the manufacture of CNMs.

Explanation

The three metals used in catalytic converters — rhodium, platinum and palladium — are part of a category known as platinum group metals, or PGMs, which are known for their catalytic properties.

because since there are now 4 electrons(-) you can tell that it had 4 protons (+) before so -4+4 is 0 which makes it neutral. hope it helps.

Answer:

Because it takes 8 electron's to become a netural atom there fore when you add 4 electrons to Beryllium it becomes a netural atom and a stable substadnce.

Explanation:

1. The number of mole of C₃H₈ needed to make 15.5 moles of CO₂ is 5.2 moles

2. The number of moles of O₂ needed is 25.8 moles

The number of mole of C₃H₈ needed can be obtained as illustrasted below:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 1 mole of C₃H₈

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 1) / 3 = 5.2 moles of C₃H₈

Thus, number of mole of C₃H₈ needed is 5.2 moles

We can obtain the number of mole of O₂ needed as follow:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 5 moles of O₂

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 5) / 3 = 25.8 moles of O₂

Thus, number of mole of O₂ needed is 25.8 moles

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Complete question:

How many moles of C₃H₈ are needed to make

15.5 moles of CO₂? How much O₂ will be needed?

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

Diamonds are composed of carbon in a tetrahedral lattice. That is option C.

A diamond of defined as an allotrope or one of the major forms of the element, carbon in nature.

These carbon atoms are arranged within the diamond in a face centered cubic tetrahedral lattice shape.

Therefore, Diamonds are composed of carbon in a tetrahedral lattice.

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Diamonds are composed of carbon in a tetrahedral lattice. The correct option is C.

Diamonds are one of the allotropes of carbon. The other allotrope of carbon is graphite.

Thus, diamonds are made up of carbon atoms that are tightly packed together. Each carbon atom in a diamond is strongly bonded to 4 other carbon atoms, resulting in the formation of a tetrahedral structure.

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The reaction that would most likely require the use of an inert electrode is a reaction involving highly reactive substances or species that can react with or be oxidized by the electrode material itself.

One such reaction that often requires the use of an inert electrode is the electrolysis of aqueous solutions containing halide ions (Cl-, Br-, I-). When halide ions are electrolyzed, they can undergo oxidation at the anode, resulting in the formation of halogen gas (Cl2, Br2, I2). However, these halogens are highly reactive and can react with many common electrode materials, such as metals, leading to unwanted side reactions.

To prevent these undesired reactions, an inert electrode, usually made of materials such as platinum, gold, or graphite, is employed. Inert electrodes do not react with the halogen gases formed during electrolysis, allowing the desired reaction to take place without interference from the electrode material itself.

For example, in the electrolysis of a sodium chloride (NaCl) solution, chloride ions (Cl-) can be oxidized at the anode to form chlorine gas (Cl2). To ensure that the chlorine gas is produced without any reactions involving the anode material, an inert electrode like platinum or graphite is used.

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Answer:

When carbon dioxide reacts with water carbonic acid is formed, from which hydrogen ions dissociate increasing the acidity of the systemCarbon dioxide emissions to the atmosphere can therefore increase the acidity of land, sea and air

Explanation:

True: bulk deformation of magnesium is only possible at hot-working temperatures somewhat above the melting point

Magnesium supports muscle and neuron function as well as energy synthesis in the body, among many other vital functions. Typically, low magnesium levels don't result in any symptoms. On the other hand, persistently low levels can raise your risk of osteoporosis, type 2 diabetes, high blood pressure, and heart disease.

The chemical element magnesium has the atomic number 12 and the letter Mg as its symbol. It is a glossy grey metal that is similar to the other five alkaline earth metals in terms of both physical and chemical characteristics (group 2 of the periodic table).

Only in the presence of other elements does magnesium naturally arise, and in these situations, it almost invariably possesses a +2 oxidation state. The artificially created free element (metal) is very reactive. The liberated metal emits a distinctive brilliant-white light during combustion.

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The correct answer for emperical and molecular formula = C5H14N2 .

3.23 g x (12.011 / 44.0098) = 0.8815 g carbon

1.865 g x (2.016 / 18.0152) = 0.2087 g Hydrogen

1.58 g x (28.014 / 108.009) = 0.4098 g Nitrogen

1.50 g minus (0.8815 + 0.2087 + 0.4098) = 0.

Convert each element's mass to moles.

0.8815 g/12.011 g/mol = 0.0734 mol carbon

0.2087 g 1.008 g/mol = 0.207 mol Hydrogen

0.4098 g 14.007 g/mol = 0.02926 mol Nitrogen

Step three is to calculate the ratio of molar amounts expressed in the smallest, whole numbers.

0.0734 mol 0.02926 mol = 2.51 carbon

7.07 mol hydrogen = 0.207 mol 0.02926 mol

Nitrogen: 0.02926 mol = 1 Nitrogen: 0.02926 mol = 1

Doubling each value yields C = 5, H = 14.14, and N = 2, resulting in the empirical formula C5H14N2. 

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Spectroscopy be used to distinguish between the following is the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

Spectroscopy is the study of emission or absorption of light. It is used to study the structure of atoms and molecules.

The three types of spectroscopy are:

Thus, the correct option is B, the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

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Answer:

W = 615.91 kJ

Explanation:

We need to use the following expression:

W = ΔG° * mol   (1)

But in order to determine the ΔG° we need the following expression:

ΔG° = -n * F * E°   (2)

Where F is a constant and is 96,500 J/V mol

n is the number of transferred electrons in the reaction. As we are passing from Al to Al³⁺ we can say that the number of electrons are 3.

Finally to get the moles, we need the the atomic weight of aluminum which is 26.98 g/mol, so the moles:

moles = m/MM   (3)

Let's calculate the moles of aluminum:

moles = 50 / 26.98 = 1.85 moles of aluminum

Now let's calculate the gibbs energy using (2):

ΔG° = -3 * 96,500 * 1.15

ΔG° = -332,925 J or simply -332.925 kJ/mol

Finally, using (1) we can determine the work done:

W = 332.925 * 1.85

Hope this helps

The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

The cell potential, Ecell, is the measure of the potential difference between two half cells in an electrochemical cell.

Expression for work done ;

W = ΔG° x mol   (1)

But, to determine the ΔG°

ΔG° = -n x F x E°   (2)

Where,

(As there is variation from Al to Al³⁺ the change in number of electrons are 3)

To get the moles,

moles = m/MM  (3)

moles = 50 / 26.98 = 1.85 moles of aluminum

Now,

ΔG° = -3 x 96,500 x 1.15

ΔG° = -332,925 J  

       = -332.925 kJ/mol

Now, using (1) we can determine the work done:

W = 332.925 x 1.85

W = 615.91 kJ

Hence, The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ

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Answer: A

Explanation:

Answer:

4.67 liters of SO2 with sig figs

Explanation:

To do this reaction, we first must find the limiting agent.
in this problem, 5 liters of H2S are reacted with 7 liters of O2, and each two moles of H2S corresponds to 3 moles of O2. Assuming ideal behavior, 1 liter of H2S has the same number of moles as 1 liter of O2 has. So, 2 liters of H2S react with 3 liters of O2. To find the limiting reagent, focus on one reagent and calculate how much of the other reagents would be needed to fully consume that one reagent.
Focus on H2S:
5 liters of H2S would require 7.5 liters of O2 (since each 2 liters of H2S requires 3 liters of O2)

Focus on O2:
7 liters of O2 would require 14/3, or 4.666... liters of H2S.

Since we don't have 7.5 liters of O2 (we only have 7 liters) to react with all 5 liters of H2S, we would say that O2 is the limiting reagent, and that we have 7 liters of it.

Next, figure out how much product can be produced per mole of that limiting reagent. 3 moles of O2 and 2 moles of H2S turns into 2 moles of SO2 and 2 moles of H2O. Thus, the ratio of O2 to SO2 is 3:2
We have 7 liters of O2, and since the ratio of O2 to SO2 is 3:2, we can set up the equation:
7:x = 3:2 where x is the number of liters of SO2
cross multiply (or solve with another method) to get:
x = 14/3, or 4.666... liters of SO2

Answer:

Decreasing pH decreases the solubility; increasing salinity increases the salinity.

Explanation:

Atmospheric carbon dioxide in seawater is involved in the following equilibria:

(i)   CO₂(g) ⇌ CO₂(aq)

(ii)  CO₂(aq) + H₂O ⇌ H₂CO₃(aq)  

(iii) H₂CO₃(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HCO₃⁻(aq)  

(iv) HCO₃⁻(aq)+ H₂O(l) ⇌ H₃O⁺(aq) + CO₃²⁻(aq)

1. Effect of pH  

Decreasing pH increases [H₃O⁺].

According to Le Châtelier's Principle, the position of equilibrium of (iv) will be pushed to the left.  

This, in turn, pushes the positions of equilibrium of (iii), (ii), and (i) to the left.

The net effect is that CO₂ is pushed out of the solution and back into the atmosphere.

Thus, decreasing the pH decreases the solubility of atmospheric CO₂.

2. Effect of salinity

Salinity includes the measurement of all ions in seawater, not just Na⁺ and Cl⁻.

An important ion that contributes to salinity is Ca²⁺.

Ca²⁺ ions are involved in the equilibrium  

Ca²⁺(aq) + CO₃²⁻(aq) ⇌ CaCO₃(s).

Thus, increasing the salinity ([Ca²⁺]) removes CO₃²⁻ from the solution and pulls the position of equilibrium of (iv) to the right.

The effect goes back through the chain of equilibria.

The net result is that more atmospheric CO₂(g) dissolves in the seawater to replace the CO₃²⁻ that has been removed.

Increasing the salinity increases the solubility of atmospheric CO₂.

Answer:

A heterotroph is an organism that eats other plants or animals for energy and nutrients. The term stems from the Greek words hetero for “other” and trophe for “nourishment.”

Answer:

when berilium and sulper combines it becomes Berilium Sulphate.

Answer:

1200 cal

Explanation:

80 cal/g * 15 g = 1200 cal

Answer: The mass in grams is 514.8.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number \(6.023\times 10^{23}\) of particles.

To calculate the number of moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadros number}}\)

given molecules = \(7.03\times 10^{24}\)  

Putting in the values we get:

\(\text{Number of moles}=\frac{7.03\times 10^{24}}{6.023\times 10^{23}}=11.7moles\)

mass of \(CO_2=moles\times {\text {Molar mass}}=11.7mol\times 44g/mol=514.8g\)

The mass in grams is 514.8.

Answer: The reaction's equilibrium constant (K) will be around 0.1333.

Explanation:

In order to do this, first off you need to know the reactant and product equilibrium concentrations in order to determine the equilibrium constant (K) for the given reaction. The equilibrium concentrations are as follows based on the data given:

[SO2] = 0.75 M [O2] = 0.30 M

[SO3] = 0.15 M

For the indicated reaction, the equation for the equilibrium constant is:

K is equal to ([SO3]2 / ([SO2]2 * [O2])

the equilibrium concentrations into the equation:

K = (0.15^2) / (0.75^2 * 0.30)

K = 0.0225 / 0.16875

(Rounded to four decimal places) K = 0.1333

As a result, the reaction's equilibrium constant (K) is around 0.1333.