Answer: The molecular mass of carbon dioxide is 44.01amu. The molar mass of any compound is the mass in grams of one mole of that compound. One mole of carbon dioxide molecules has a mass of 44.01g, while one mole of sodium sulfide formula units has a mass of 78.04g. The molar masses are 44.01g/mol and 78.04g/mol respectively.
What's an example of an ionic bond and why is it ionic
Ionic bonding in sodium chloride. An atom of sodium (Na) donates one of its electrons to an atom of chlorine (Cl) in a chemical reaction, and the resulting positive ion (Na+) and negative ion (Cl−) form a stable ionic compound (sodium chloride; common table salt) based on this ionic bond.
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Can u mark me as......
But its OK if u didnt
I really need some help on this stuff.
Answer:
The answer is b.
Explanation:
Amorphous solids have two characteristic properties. When cleaved or broken, they produce fragments with irregular, often curved surfaces; and they have poorly defined patterns when exposed to x-rays because their components are not arranged in a regular array. An amorphous, translucent solid is called a glass.
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draw the structure of the predominant form of ch3ch2nh3 (pka = 11.0) at ph = 14.
The predominant form of CH3CH2NH3 at pH = 14 will be the ionized form.
This is because at high pH, the solution is basic, and there are excess hydroxide ions. The hydroxide ions remove a proton from the ammonium ion, forming ammonia and water. The chemical equation for this reaction is as follows:CH3CH2NH3+ OH- → CH3CH2NH2 + H2O
The predominant form of CH3CH2NH3 at pH = 14 is CH3CH2NH2. This is the ionized form of the compound, which has lost a proton to become an amine. The structure of the predominant form of CH3CH2NH3 at pH = 14 is shown below:CH3CH2NH2
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SEP Construct an Explanation What challenges do the three industries have in making better batteries? What solutions are being suggested?
The three industries commonly associated with battery technology are the automotive, electronics, and renewable energy sectors. Each of these industries faces specific challenges when it comes to developing better batteries.
Automotive Industry:
Energy Density: One of the primary challenges for electric vehicles (EVs) is improving battery energy density, which refers to the amount of energy that can be stored per unit of volume or weight. Higher energy density batteries would allow for longer driving ranges and reduced charging times.Cost: Batteries constitute a significant portion of an electric vehicle's cost. Therefore, reducing the cost of battery production is crucial for making EVs more affordable and competitive with traditional internal combustion engine vehicles.Charging Infrastructure: The limited availability of charging stations and relatively longer charging times compared to refueling a conventional vehicle remain challenges. The industry is focusing on expanding charging infrastructure and developing fast-charging technologies to address this issue.Electronics Industry:
Power Density: Electronic devices, such as smartphones and laptops, require batteries with high power density to support their energy-intensive operations. However, increasing power density while maintaining safety and minimizing size is a challenge.Battery Lifespan: Consumers expect electronic devices to have a longer battery life before needing a recharge. Enhancing battery lifespan through improved materials, design, and management systems is an ongoing pursuit.Environmental Impact: The electronics industry is increasingly concerned about the environmental impact of batteries, particularly regarding the disposal and recycling of lithium-ion batteries. Developing sustainable and eco-friendly battery technologies is a suggested solution.Renewable Energy Industry:
Energy Storage Capacity: Renewable energy sources like solar and wind are intermittent, meaning they are not continuously available. Efficient energy storage solutions are needed to store excess energy produced during peak times and supply it during periods of low or no generation. Integration with the Grid: Integrating renewable energy sources with the existing electrical grid is a challenge due to fluctuations in supply and demand. Advanced battery technologies can help stabilize the grid by providing rapid response and balancing services.Durability and Longevity: Renewable energy projects, such as utility-scale installations, require long-lasting and durable batteries that can withstand frequent charge-discharge cycles without significant degradation. Enhancing battery life and reliability is a focus for the industry.For such more questions on technology
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What happens to iron in a bolt as the bolt rusts?
Answer:
write the following as fractions in their simplest form
Hey guys! How is the answer C? I need steps plz
What is the mass of 6.78x1050 molecules of NaCl
Answer:
Explanation:
As
Molar mass of NaCl= 58.44 gm
So we got it that,
58.44 mass of NaCl contain = 6.023*10^23 molecules of Na Cl
x mass will contain = 6.78*10^50
by cross multiplication , we get
x= 58.44*(6.78*10^50)/ 6.023*10^23
x= 65.785 * 10^27 molecules
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Can someone pls help me
Answer:
A
Explanation:
That angle is a complementary angle which adds up to 90 degrees. So you write out the equation to solve for X. Equation= 2x-33+5x-31=90. Solve for x and you get 22 degrees.
Answer:
22(don't forget to add the degrees
Explanation:
\(2x - 33 + 5x - 31 = 90\)
\(2x + 5x = 90 + 31 + 33\)
\(7x = 154\)
\(x = 154 \div 7\)
\(x = 22\)
in the area below, write a series of chemical reactions that leads to the formation of tropospheric ozone in photochemical smog
The formation of tropospheric ozone in photochemical smog involves a series of chemical reactions primarily driven by sunlight.
Here is a simplified representation of the reactions:
Nitrogen Dioxide (NO2) reacts with sunlight (UV radiation) to produce Nitric Oxide (NO) and an Oxygen atom (O).
NO2 + UV radiation → NO + O
Nitric Oxide (NO) reacts with Oxygen molecules (O2) to form Nitrogen Dioxide (NO2) again.
NO + O2 → NO2
The Oxygen atom (O) produced in reaction 1 reacts with an Oxygen molecule (O2) to form Ozone (O3)
.O + O2 → O3Ozone (O3) can react with Nitric Oxide (NO) to form Nitrogen Dioxide (NO2) and Oxygen (O2).
O3 + NO → NO2 + O2
These reactions are part of a complex set of photochemical reactions involving various pollutants such as nitrogen oxides (NOx), volatile organic compounds (VOCs), and sunlight. The primary precursors for tropospheric ozone formation in photochemical smog are Nitrogen Dioxide (NO2) and volatile organic compounds (VOCs). The reactions outlined above represent a simplified version of the process and do not capture the full complexity of atmospheric chemistry involved in the formation of tropospheric ozone.
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if we are heated a metal with 28g mass then we add it in a coffee cup with 28g water. the water temperature raised from 19 degree to 23.8 oc. what was the initial temperature of the metal. the water specific heat of water is 4.184 j/g oc.
Specific Heat of the metal will be = 4.184 J/C
Mass of metal = 28 g
Mass of water = 28 g
Rise in temperature = 23.8 - 19 = 4.8 C
Specific heat of water = 4.184 J/C
Let the specific heat of metal =S
The heat released by metal =mass of metal * specific heat of metal * Change in temperature
\(& =28\times S \times 4.8{ }^{\circ} \mathrm{C} \\& =134.4 S^{\circ} \mathrm{C}\)
Heat absorbed by water = mass of water x specific heat of water x change in temp. \(=28 \times 4.184 \times 4.8=562.3296 J\)
Using the principal of Caloriemeter:
We have, Heat released by metal = Heat absorbed by water
134.4S = 562.3296 =>4.184 J/C
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The correct question should be:
if we are heated a metal with 28g mass then we add it in a coffee cup with 28g water. the water temperature raised from 19 degree to 23.8 oc. what was the specific heat of the metal. the water specific heat of water is 4.184 j/g oc.
A swimming pool reading reports that chlorine is present at 130 ppm. How many grams of chlorine are present per liter of pool water?
130 ppm will contain 0.12985167 grams of chlorine present in per liter of pool water.
What is ppm?This is an abbreviation for "parts per million" and it also can be expressed as milligrams per liter (mg/L).
1001.142303 ppm is equal to 1 g/L
So, 130 ppm will contain \(\frac{130}{1001.142303}\) grams of chlorine present in per liter of pool water which is equal to 0.12985167 gram/L.
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How many moles of C are in a sample of C5H12 that also contains 22.5g of H?
The number of moles of C present in C₅H₁₂ that contains 22.5 g of H is 9.375 moles
How to determine the mass of C₅H₁₂ that contains 22.5 g of H
1 mole of C₅H₁₂ = (12×5) + (1×12) = 72 g
Mass of H in 1 mole of C₅H₁₂ = 12 × 1 = 12 g
Thus,
12 g of H is present in 72 g of C₅H₁₂
Therefore,
22.5 g of H will be present in = (22.5 × 72) / 12 = 135 g of C₅H₁₂
How to determine the mole of C present in 135 g of C₅H₁₂72 g of C₅H₁₂ contains 5 moles of C
Therefore,
135 g of C₅H₁₂ will contain = (135 × 5) / 72 = 9.375 moles of C
Thus, 9.375 moles of C is present in C₅H₁₂ that contains 22.5 g of H
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What is one thing rock, air and water all have in common
Answer: all can be affected by the natural environment ( not sure answer hope it helped)
Explanation:
Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, rock, air and water all are matter.
What is matter?Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.
Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.
So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter. Rock, air and water all are matter.
Therefore, rock, air and water all are matter.
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calculate the ph of a buffer solution obtained by dissolving 30.0 g of kh2po4(s) and 49.0 g of na2hpo4(s) in water and then diluting to 1.00 l.
The pH of the buffer solution is approximately 7.65.
To calculate the pH of a buffer solution, first determine the concentration of \(KH_{2} PO_{4}\) and \(Na_{2} HPO_{4}\).
Calculate moles of \(KH_{2} PO_{4}\) and \(Na_{2} HPO_{4}\):
- \(KH_{2} PO_{4}\): (30.0 g) / (136.09 g/mol) = 0.2203 mol
- \(Na_{2} HPO_{4}\): (49.0 g) / (141.96 g/mol) = 0.3451 mol
Calculate concentrations in the 1.00 L solution:
- [\(KH_{2} PO_{4}\)] = 0.2203 mol / 1.00 L = 0.2203 M
- [\(Na_{2} HPO_{4}\)] = 0.3451 mol / 1.00 L = 0.3451 M
Use the Henderson-Hasselbalch equation:
pH = pKa + log ([A-]/[HA])
- For \(H_{2} PO_{4}\)-/HPO4²-, the pKa = 7.21.
- pH = 7.21 + log (0.3451/0.2203)
Calculate the pH:
- pH ≈ 7.21 + 0.438 = 7.65
The pH of the buffer solution is approximately 7.65.
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PLEASE HELP ME FAST Name the parts of the distillation apparatus set-up. 2. 3. 5. 70 6. 10 7 8. 15 14 13. 10 09 13
Answer:
2. Distillation Flask
3. Fractionating column
4. Thermometer
5. Condenser
6. cold water in
7. cold water out
8. Recieving flask
13. Electric heater
What type of reactive intermediate is formed in the reaction of an alkene with Br2 and water to give a bromohydrin?
a.carbocation
b.carbanion
c.radical
d.cyclic bromonium ion
The type of reactive intermediate that is formed in the reaction of an alkene with Br2 and water to give a bromohydrin is a cyclic bromonium ion.
What is a cyclic bromonium ion? Explain more?
A cyclic bromonium ion is a positively charged intermediate with a three-membered ring containing two carbon atoms and a bromine atom. It is generated during the bromination of alkenes, where Br2 is reacted with an alkene to produce a bromohydrin. The electrophilic addition mechanism is responsible for the formation of a cyclic bromonium ion.
The electrophilic addition reaction is when the nucleophile attacks an electrophile. The carbocation, carbanion, and radical intermediates are generated in the electrophilic addition reactions. But in the reaction of an alkene with Br2 and water to give a bromohydrin, cyclic bromonium ions are formed, making option D the correct answer.
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Hi I really need help with this question, please
What is the mean of the data set?
{−5, 0, 2, −4, −7, 1, −4, 3, −2, 5, −9}
−4.0
−2.0
−1.8
9.0
Answer:
it's
-2.0
Explanation:
.....................
Answer:
-1.8
Explanation:
Since this is the mean we add all and divide by how many terms we have
-5+0+2-4-7+1-4+3-2+5-9 = -20
-20/11= -1.81818181818
round
= -1.8
What were some of the causes of the Amu Darya and Syr Darya rivers being ruined?
urban sewer drainage
tannery dumping
tourism
drying up
agricultural chemicals
Answer:
drying up
agricultural chemicals
Explanation:
15ml of 3M H2SO4 is needed neutralized 60ml of koh... the hat is the molarity of the kOH ?
Answer:
5
Explanation:
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CAN ANYONE HELP ME PLEASE!!!!!!!!!!!!!
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A carpenter uses a saw to cut a wooden board into two different sized pieces. Which of the following physical properties is most
likely to be the same for both pieces of wood?
1. density
2. mass
3. volume
4. weight
Determine the value of AG for a reaction at 25°C which has an equilibrium constant of 20.2. -7.567 kJ/mol See Hint Part 2 (1 pt) Calculate AGfor the reaction below at 25°C when 2.50 atm of A and 5.70 atm of Bare present. AG° = +5.44 kJ/mol for this reaction. A(g) = 2B(8) kJ/mol
The Gibbs free energy change (ΔG) can be calculated using the formula ΔG° = -RTlnK, the value of ΔG for the reaction at 25°C is approximately -4.83 kJ/mol.
Value of K is 20.2, and the temperature is 25°C or 298 K. Thus, we can calculate the standard Gibbs free energy change (ΔG°) as follows:ΔG° = -RTlnK= -(8.314 J/mol K)(298 K)ln(20.2)= -35,380.2 J/mol≈ -35.4 kJ/mol We can also calculate the Gibbs free energy change (ΔG) at non-standard conditions using the formula ΔG = ΔG° + RTln(Q), where Q is the reaction quotient.
The given reaction is A(g) ⇌ 2B(g), and the value of ΔG° is +5.44 kJ/mol. The reaction quotient Q can be calculated using the partial pressures of A and B as follows: Q = (PA) / (PB)2= (2.50 atm) / (5.70 atm)2≈ 0.15Substituting these values into the formula for ΔG gives:ΔG = ΔG° + RTln(Q)= (+5.44 kJ/mol) + (8.314 J/mol K)(298 K)ln(0.15)= -4,828.2 J/mol≈ -4.83 kJ/mol.
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23.73 g of some metal has a volume of 3.0mL.
Find this metals density.
Answer:
7.91 g/mLExplanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \\\)
From the question we have
\(density = \frac{23.73}{3.0} \\ \)
We have the final answer as
7.91 g/mLHope this helps you
4) The principle of ________ states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past.
A) catastrophism
B) plate tectonics
C) plutonism
D) Uniformitarianism
The principle of option D. Uniformitarianism states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the
Option D. Uniformitarianism is the principle stating that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past. It is based on the idea that the present is the key to the past. In other words, the same natural laws that operate in the universe today have been operating since the beginning of time.
James Hutton was the first to propose this principle in the late 18th century. He suggested that the Earth was shaped by slow-acting geological forces such as erosion, sedimentation, and uplift over long periods of time. He believed that the same processes were still happening today and that they had operated in the past.
This principle is an important concept in geology because it allows scientists to interpret the Earth's history based on the processes that they observe today. By understanding how these processes work and how they have changed over time, scientists can reconstruct the history of the Earth and its environments.
Uniformitarianism has been tested and proven through many observations and experiments. For example, the study of sedimentary rocks has shown that they were formed in the past through the same processes that are observed today, such as deposition of sediment by water, wind, or ice.
Similarly, the study of volcanoes has shown that they are formed by the same processes as today, such as the movement of magma from deep within the Earth.
In conclusion, Uniformitarianism is the principle that allows us to interpret the Earth's history by observing the processes that shape it today. It is a fundamental concept in geology and has been tested and proven through many observations and experiments.
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Select all statements that correctly describe the typical number of covalent bonds formed by common neutral atoms. a. Atoms with 5 valence electrons typically form 5 covalent bonds. b. Atoms with 3 valence electrons typically form 3 covalent bonds. c. Atoms with 8 valence electrons do not typically form bonds. d. Atoms with 7 valence electrons typically form 1 bond.
The (b) claim is true. 3 covalent bonds are often formed by atoms having 3 valence electrons. A, c, and d are false statements.
Covalent bonds are created when atoms share electrons in order to finish the valence shell, the atom's outermost electron shell. In order to completely fill their valence shell, atoms having three valence electrons, like boron, often establish three covalent bonds. The boron atom can then achieve a stable configuration that is comparable to the noble gas configuration as a result. Nevertheless, contrary to what assertions a, c, and d indicate, atoms with 5, 7, or 8 valence electrons do not often form the same number of covalent bonds. In order to complete their valence shell, they often create fewer bonds by sharing electrons with other atoms.
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1. The vapor pressure of pure water at 26°Cis 25.21 mmHg. What is the vapor pressure of a solution which contains 179.38 g of iron (III)sulfate[Fe2(SO4)3]in 450.0 g of water?The molar mass of iron (III)sulfateand water are 399.88g/mol and 18.0 g/mol, respectively.
Answer: 26C is 25.0 torr
Explanation: The decrease in vapor pressure is proportional to the molality of the solution, so the vapor pressure of the solution at 26°C is 25.0 torr.
First, we need to find the number of moles of glucose and water present in the solution:
n(glucose) = 16.0 g / 180.0 g/mol = 0.089 mol
n(water) = 80.0 g / 18.0 g/mol = 4.44 mol
Next, we'll find the mole fraction of water in the solution:
X_water = n(water) / (n(glucose) + n(water)) = 4.44 / (0.089 + 4.44) = 0.989
Finally, we can find the vapor pressure of the solution using Raoult's law:
P_solution = X_water * P_purewater = 0.989 * 25.21 torr = 25.0 torr
So the vapor pressure of the solution at 26°C is 25.0 torr.
Write the full atomic symbol for each isotope:
(a) 8 protons, 9 neutrons
(b) Atomic number 50, mass number 119
(c) 12 neutrons, atomic number 11
(d) 28 protons, mass number 58
(e) 81 neutrons, symbol Ba
Answer:
a) Oxygen-17
b) Tin-119
c) Sodium-23
d) Nickel-58
e) Barium-137
A World Health Organization study of health in various countries reported that in Canada, systolic blood pressure readings have a mean of 121 and a standard deviation of 16 . A reading above 140 is considered to be high blood pressure. Complete parts a through d below. a. What is the z− score for a blood pressure reading of 140 ? z= (Round to two decimal places as needed.) b. If systolic blood pressure in Canada has a normal distribution, what proportion of Canadians suffers from high blood pressure? The proportion of Canadians with high blood pressure is (Round to four decimal places as needed.) c. What proportion of Canadians has systolic blood pressure in the range from 100 to 140 ? The proportion with systolic blood pressure between 100 and 140 is (Round to four decimal places as needed.) d. Find the 85 th percentile of blood pressure readings. The 85 th percentile of blood pressure readings is
The 85th percentile of blood pressure readings is approximately 137.64. a. To calculate the z-score for a blood pressure reading of 140, we can use the formula:
z = (x - μ) / σ
where x is the value (140 in this case), μ is the mean (121), and σ is the standard deviation (16).
Substituting the values into the formula:
z = (140 - 121) / 16
z ≈ 1.19 (rounded to two decimal places)
b. To find the proportion of Canadians with high blood pressure, we need to calculate the area under the normal distribution curve for values above 140. This can be done by finding the cumulative probability using the z-score.
Using a standard normal distribution table or a calculator, we can find that the cumulative probability corresponding to a z-score of 1.19 is approximately 0.881.
Therefore, the proportion of Canadians with high blood pressure is approximately 0.881 (rounded to four decimal places).
c. To find the proportion of Canadians with systolic blood pressure in the range from 100 to 140, we need to calculate the area under the normal distribution curve between these two values.
Using the z-scores corresponding to 100 and 140, we can find the cumulative probabilities for each value. The cumulative probability for a z-score of -1.25 (corresponding to 100) is approximately 0.105, and the cumulative probability for a z-score of 1.19 (corresponding to 140) is approximately 0.881 (as calculated in part b).
The proportion with systolic blood pressure between 100 and 140 is the difference between these two probabilities:
Proportion = 0.881 - 0.105 ≈ 0.776 (rounded to four decimal places)
d. The 85th percentile represents the value below which 85% of the blood pressure readings fall. To find the 85th percentile, we need to determine the z-score that corresponds to an area of 0.85 under the normal distribution curve.
Using a standard normal distribution table or a calculator, we can find that the z-score corresponding to an area of 0.85 is approximately 1.04.
To find the actual blood pressure reading at the 85th percentile, we can use the z-score formula:
x = μ + (z * σ)
Substituting the values:
x = 121 + (1.04 * 16)
x ≈ 137.64
Therefore, the 85th percentile of blood pressure readings is approximately 137.64.
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Answer true or false.(a) The functional group of an alcohol is the -OH (hydroxyl) group.(b) The parent name of an alcohol is the name of the longest carbon chain that contains the -OH group.(c) A primary alcohol contains one -OH group, and a tertiary alcohol contains three -OH groups. (d) In the IUPAC system, the presence of three -OH groups is shown by the ending –triol. (e) A glycol is a compound that contains two -OH groups. The simplest glycol is ethylene glycol, HOCH2CH2iOH. (f) Because of the presence of an -OH group, all alcohols are polar compounds. (g) The boiling points of alcohols increase with increasing molecular weight. (h) The solubility of alcohols in water increases with increasing molecular weight.
Here is the answerregarding Functional group to your question using the provided terms:
(a) True, (b) True, (c) False, (d) True, (e) True, (f) True, (g) True, (h) True
(a) True - The functional group of an alcohol is the -OH (hydroxyl) group.
(b) True - The parent name of an alcohol is the name of the longest carbon chain that contains the -OH group.
(c) False - A primary alcohol has the -OH group on a carbon with only one other carbon attached, while a tertiary alcohol has the -OH group on a carbon with three other carbons attached.
(d) True - In the IUPAC system, the presence of three -OH groups is shown by the ending -triol.
(e) True - A glycol is a compound that contains two -OH groups. The simplest glycol is ethylene glycol, HOCH2CH2OH.
(f) True - Because of the presence of an -OH group, all alcohols are polar compounds.
(g) True - The boiling points of alcohols increase with increasing molecular weight.
(h) False - The solubility of alcohols in water decreases with increasing molecular weight.
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is a compound made of only similar atoms
Explanation:
chemical compound, any substance composed of identical molecules consisting of atoms of two or more chemical elements. All the matter in the universe is composed of the atoms of more than 100 different chemical elements, which are found both in pure form and combined in chemical compounds
Answer:
no
Explanation:
Compounds are made of two or more atoms of different elements