calculate the percent ionization of acetic acid (hc2h3o2(hc2h3o2; ka=1.8×10−5)ka=1.8×10−5) solutions having the following concentrations.
Answers
The percent ionization of acetic acid (HC2H3O2), the following concentrations are 1.34% and 4.25%.
When calculating the percent ionization of acetic acid (HC2H3O2), the following concentrations are considered:
1) 0.1 M HC2H3O2 and 2) 0.01 M HC2H3O2.
First, let's find the ionization constant, ka for the acetic acid (HC2H3O2): HC2H3O2 + H2O ↔ H3O+ + C2H3O2-From the given equation, Ka = [H3O+][C2H3O2-]/[HC2H3O2][H2O]Ka = [H3O+] [C2H3O2-]/[HC2H3O2] [H2O]Using the given value of Ka = 1.8 × 10−5M, and the concentration of HC2H3O2 as x, we have:[H3O+] = [C2H3O2-]= √Ka × x= √(1.8 × 10−5) × xAt equilibrium, [H2O] remains constant and thus can be considered to be equal to the initial concentration of the acid. Therefore, [H2O] = x.
Hence the expression for the ionization constant reduces to:
Ka = [H3O+] [C2H3O2-]/[HC2H3O2] x= [H3O+]^2 / (Ka × x)
Substituting the values we have:H3O+ = √Ka × x= √(1.8 × 10−5) × xKa = 1.8 × 10−5M
Concentration of HC2H3O2 [X] Ka = 1.8 × 10−5MH3O+ = √Ka × X[HC2H3O2] [H2O] [H3O+] [C2H3O2-]HC2H3O2 is known to be a weak acid.
As a result, the amount that ionizes in the solution is relatively small. The degree of ionization can be determined by finding the amount of acid that has been ionized. This is equivalent to [H3O+] as determined by the above calculation. Percent ionization = [H3O+] / [HA] × 100Percent ionization of acetic acid in a 0.1 M solution:
Ka = [H3O+]^2 / (Ka × [X])[H3O+]^2 = Ka × [X][H3O+] = √(Ka × [X]) = √(1.8 × 10−5 × 0.1) = 1.34 × 10^-3M%
ionization = [H3O+] / [HA] × 100% ionization = (1.34 × 10^-3M / 0.1M) × 100% ionization = 1.34%
Percent ionization of acetic acid in a 0.01 M solution:Ka = [H3O+]^2 / (Ka × [X])[H3O+]^2 = Ka × [X][H3O+] = √(Ka × [X]) = √(1.8 × 10−5 × 0.01) = 4.25 × 10^-4M%
ionization = [H3O+] / [HA] × 100% ionization = (4.25 × 10^-4M / 0.01M) × 100% ionization = 4.25%
Therefore, the percent ionization of acetic acid (HC2H3O2) solutions having concentrations of 0.1 M and 0.01 M are 1.34% and 4.25% respectively.
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Related Questions
Energy and frequency are
O None of these are correct
O inversely proportional to each other A
O directly proportional to each other
O independent of each other
Answers
The Copper Chloride solution used in the investigation contained 300 grams per dm3 of solid CuCl2 dissolved in 1dm3 of water.
The student used 50cm3 of copper chloride solution in each experiment. Calculate the mass of solid copper chloride used in each experiment.
Answers
Answer:
The mass of solid copper chloride used in each experiment=15 g
Explanation:
We are given that
Mass of copper chloride in solution=300g/dm3
Volume of solution used in each experiment=50 cm3
We have to find the mass of solid copper chloride used in each experiment.
\(1cm^3=0.001 dm^3\)
\(50cm^3=0.05 dm^3\)
1 dm3 contained solid copper chloride=300 g
0.05 dm3 contained solid copper chloride=\(300\times 0.05\)g
0.05 dm3 contained solid copper chloride=15 g
Hence, the mass of solid copper chloride used in each experiment=15 g
Rank the following elements in order of increasing atomic size: Ge, Rb, Ne, S
a.Ge< Rb < Ne
b. Rb
c. Rb
d. S< Ne < Ge< Rb
e. Ne
Answers
Answer: The correct answer is:
d. S < Ne < Ge < Rb
Explanation:
The atomic size generally decreases from left to right across a period of the periodic table due to increased nuclear charge and the electrons being added to the same energy level. Therefore, the atomic size of these elements can be compared as follows:
Rb has the largest atomic size among the given elements because it is located at the bottom of Group 1 (alkali metals) of the periodic table, which means it has the largest atomic radius.
Ge has a smaller atomic size than Rb because it is located to the right of Rb in the periodic table, which means it has more protons in its nucleus and a smaller atomic radius.
Ne has a smaller atomic size than Ge because it is a noble gas, and noble gases have the smallest atomic radii within a period of the periodic table.
S has a smaller atomic size than Ne because it is located to the right of Ne in the periodic table, which means it has more protons in its nucleus and a smaller atomic radius.
5. The space around a magnet in which there is a magnetic effect is called
A. an electromagnet
B. a magnetic pole
C. lodestone
D. a magnetic field
Answers
Answer:
The space surrounding a magnet within which the magnetic effect is felt is called Magnetic field. A magnetic field is a vector field that describes the magnetic influence of electrical currents and magnetic materials.
How much heat is released when 24. 8 g of ch4 is burned in excess oxygen gas?
Answers
When 24.8 g of CH\(_{4}\) is burned in excess oxygen gas, approximately 890 kJ of heat is released.
The combustion of methane (CH\(_{4}\)) releases a specific amount of heat energy. To calculate the heat released, we need to use the molar mass of CH\(_{4}\) and the heat of combustion per mole of methane. The molar mass of CH\(_{4}\) is 16.04 g/mol. By using the balanced chemical equation for the combustion of methane and the corresponding enthalpy change (∆H) per mole of methane, we can calculate the heat released. The balanced equation is:
CH\(_{4}\) + 2O\(_{2}\) → CO\(_{2}\) + 2H\(_{2}\)O
The ∆H for this reaction is approximately -890 kJ/mol of CH\(_{4}\).
To find the heat released when 24.8 g of CH\(_{4}\) is burned, we can use the formula:
Heat released = (Mass of CH\(_{4}\) / Molar mass of CH\(_{4}\)) * ∆H
Heat released = (24.8 g / 16.04 g/mol) * -890 kJ/mol
Simplifying the expression, we find that approximately 890 kJ of heat is released when 24.8 g of CH\(_{4}\) is burned in excess oxygen gas.
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How many TOTAL atoms are present in this chemical formula? * 2NaBr2 O 2 04 O 6 08
Answers
Answer:
2 ATOMS
Explanation:
Cause it is at the end
Which change to the setup is least likely to cause an increase production of bubbles?
Adding a bright light source.
Adding a source of carbon dioxide to the water.
Adding a different fluid to the water.
Adding a second plant to the test tube.
Answers
Answer:
D, adding a second plant to the test tube
In the redox conversion of SO3 to SO-, S is ? (Oxidation or Reduction) and it's oxidation number goes from ? to?
Answers
In the redox conversion of SO₃ to SO⁻, S undergoes reduction and it's oxidation number goes from +6 to +1.
What is the oxidation number of elements?The number of electrons an atom or ion has either gained or lost in comparison to the neutral atom is known as the oxidation number or state of the atom or ion.
Group I, 2, and 3 electropositive metal atoms lose a certain number of electrons, and their positive oxidation numbers remain constant.
During a reduction reaction, the oxidation number of the element that undergoes reduction decreases.
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Here is a model that shows key information about Earth
and the Sun
Direction of
Earth's rotation
Axis
Which statement best explains the pattern of daytime and nighttime on
Earth?
A. The Sun must revolve around Earth once every 24 hours
B. Earth's axis of rotation must tilt back and forth every 12 hours.
C. Earth must complete one rotation on its axis every 24 hours.
D. The Sun's energy must come from a different direction every 12
hours
Answers
The statement information about earth and the sun direction of earth's rotation axis best explains the pattern of daytime and night-time on earth is " earth must complete one rotation on its axis every 24 hours".
What is sun?The sun was composed of incredibly hot gases, as well as then it heats as well as illuminates the entire solar system.
What is earth?The earth was referred to as a "one-of-a-kind" planet since that is the only one on the planet with ideal circumstances for life.
Day though night are caused by the Earth's diurnal revolution. From west to east, the earth rotates on its axis for around 24 hours. As a result, the sun appears to rotate from east to west, resulting in sunset and sunrise. except for polar is, which remains stationary in the north polar sky along the earth's axis, all those other stars move from east to west.
Therefore, the correct answer will be C.
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Answer:
THE ANSWER IS (C.)
Explanation:
0.92 lbm of water fills a container whose volume is 1.92 ft3. the pressure in the container is 100 psia. calculate the total internal energy and enthalpy in the container. use data from the steam tables. the total internal energy in the container is btu. the enthalpy in the container is btu.
Answers
The total internal energy in the container is 329.77 Btu and the enthalpy in the container is 385.14 Btu.
Using the steam tables, we can determine the specific volume of water at the given pressure and temperature. The specific volume of water is 0.01658 \(ft^3/lbm\).
The mass of water in the container is 0.92 lbm, so the total volume of the water is:
V = m/v = 0.92 lbm / 0.01658 \(ft^3/lbm\) = \(55.539 ft^3\)
Assuming the water is at saturation, we can find the total internal energy and enthalpy by using the values in the steam tables for saturated water at 100 psia.
From the steam tables, the total internal energy of saturated water at 100 psia is 358.05 Btu/lbm, so the total internal energy in the container is:
U = m * u = 0.92 lbm * 358.05 Btu/lbm = 329.77 Btu
From the steam tables, the enthalpy of saturated water at 100 psia is 419.02 Btu/lbm, so the enthalpy in the container is:
H = m * h = 0.92 lbm * 419.02 Btu/lbm = 385.14 Btu
Therefore, the total internal energy in the container is 329.77 Btu and the enthalpy in the container is 385.14 Btu.
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How many milliliters of oxygen are necessary to form 64.5 grams of sulfur trioxide gas during the
combustion of sulfur?
2S + 3O3 -> 2SO3
Answers
To find the amount of oxygen required to produce 64.5 grams of sulfur trioxide, we need to first calculate the number of moles of sulfur trioxide produced.
The molar mass of sulfur trioxide is 80.06 g/mol (32.07 g/mol for sulfur + 3(16.00 g/mol) for oxygen).
Number of moles of SO3 = mass of SO3 / molar mass of SO3
Number of moles of SO3 = 64.5 g / 80.06 g/mol
Number of moles of SO3 = 0.805 mol
Since 2 moles of sulfur trioxide are produced for every 3 moles of oxygen, we can set up a proportion to find the number of moles of oxygen required to produce 0.805 mol of sulfur trioxide:
2 moles SO3 / 3 moles O2 = 0.805 moles SO3 / x moles O2
Solving for x, we get:
x = (3 moles O2 * 0.805 moles SO3) / 2 moles SO3
x = 1.21 moles O2
Finally, we can convert moles of oxygen to milliliters using the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
Assuming standard temperature and pressure (STP), which is 0°C and 1 atm, we can use the following values:
P = 1 atm
V = x (unknown)
n = 1.21 mol
R = 0.08206 L atm / mol K
T = 273 K
Solving for V, we get:
V = nRT / P
V = (1.21 mol * 0.08206 L atm / mol K * 273 K) / (1 atm)
V = 27.1 L
Finally, we need to convert liters to milliliters:
27.1 L * 1000 mL / L = 27,100 mL
So, 27,100 milliliters of oxygen are
systematic evaluation of materials for post-combustion co2 capture in a temperature swing adsorption process
Answers
The question is about the systematic evaluation of materials for post-combustion CO2 capture in a temperature swing adsorption process.
In a temperature swing adsorption process for post-combustion CO2 capture, materials are evaluated systematically to determine their effectiveness in capturing CO2. Here is a step-by-step explanation of the process:
1. Material selection: Various materials, such as zeolites, activated carbon, metal-organic frameworks (MOFs), and amine-based sorbents, are considered for CO2 capture. Each material has different properties and adsorption capacities.
2. Screening: The selected materials are screened based on specific criteria, such as CO2 adsorption capacity, selectivity, stability, and cost. This helps narrow down the choices to the most promising candidates.
3. Bench-scale testing: The selected materials undergo bench-scale testing to evaluate their performance under controlled conditions. This involves measuring the CO2 adsorption capacity, kinetics, and regeneration efficiency of each material.
4. Process modeling: Computer simulations are used to model the temperature swing adsorption process with different materials. This helps predict the overall performance of the system, including CO2 capture efficiency, energy requirements, and process optimization.
5. Pilot-scale testing: The most promising materials are then tested at a larger scale in a pilot plant. This helps validate their performance and assess any challenges or limitations that may arise during practical implementation.
6. Techno-economic analysis: The performance data obtained from the pilot-scale testing is used to conduct a techno-economic analysis. This involves evaluating the cost-effectiveness of the materials, including their initial investment, operating costs, and potential for scaling up.
7. Material optimization: Based on the results of the evaluations and analysis, further modifications or improvements can be made to the materials to enhance their performance, stability, or cost-effectiveness.
By following this systematic evaluation process, researchers and engineers can identify the most suitable materials for post-combustion CO2 capture in a temperature swing adsorption process.
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In the Millikan oil droplet experiment, the oil is sprayed from an atomizer into a chamber. The droplets are allowed to pass through the hole into the chamber so that their fall can be observed. The top and bottom of the chamber consist of electrically charged plates. The upper plate is positively charged, and the lower plate is negatively charged. X rays are introduced into the chamber so that when they strike the oil droplets, the droplets will acquire one or more negative charges. The electric field (voltage) is applied to the metal plates.
Watch the animation and identify the effects of an electric field on the motion of a negatively charged oil droplet. Consider the gravitational force as Fg and the electric force as Fe. All the other forces acting on the oil droplet can be ignored as their effect on the motion of the oil droplet is negligible.
A/ In the absence of an electric field, the oil droplet falls freely due to the gravitational force.
B/ If Fe is increased until it is equal to Fg, the negatively charged oil droplet will remain stationary.
C/ If Fe is greater than Fg, the negatively charged oil droplet will move freely toward the negatively charged plate.
D/ In the presence of an electric field, the negatively charged oil droplet moves freely toward the negatively charged plate.
** I chose B, but that was the wrong answer
Answers
C/ If Fe is greater than Fg, the negatively charged oil droplet will move freely toward the negatively charged plate.
In the Millikan oil droplet experiment, the negatively charged oil droplets are subjected to an electric field created by the charged plates. The electric force (Fe) acts on the oil droplet in a direction opposite to the gravitational force (Fg). When Fe is greater than Fg, the electric force overcomes the gravitational force, causing the negatively charged oil droplet to experience an upward force. As a result, the oil droplet moves freely upward toward the negatively charged plate.
Option B is incorrect because if Fe is equal to Fg, the forces balance each other, resulting in a stationary droplet. However, the question states that Fe is increased until it is greater than Fg, implying that the droplet is no longer stationary but moves in response to the electric force.
Therefore, option C is the correct answer, as it describes the effect of an electric field on the motion of a negatively charged oil droplet in the Millikan oil droplet experiment.
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what is the molarity of a koh solution if 25.0 ml neutralizes 35.0 ml of a 0.200 m hcl solution?
Answers
If 25.0ml neutralizes 35.0 ml of a 0.200M HCl solution, the molarity of KOH solution is 0.28M
The reaction between KOH solution and HCl is written below.
\(HCl + KOH \rightarrow KCl + H_2O\)
Volume of KOH, \(V_B\) = 25.0 ml
Volume of HCl, \(V_A=35.0 ml\)
Molarity of HCl, \(C_A=0.200 M\)
Molarity of KOH, \(C_B=?\)
Number of moles of HCl, \(n_A=1\)
Number of moles of KOH, \(n_B=1\)
The mathematical equation for neutralization reaction is:
\(\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}\)
Substitute \(C_A=0.200 M\), \(n_A=1\), \(n_B=1\), \(V_B\) = 25.0 ml, and \(V_A=35.0 ml\) into the equation above in order to solve for \(C_B\)
\(\frac{0.2 \times 35}{C_B \times 25}=\frac{1}{1} \\\\25C_B=7\\\\C_B=\frac{7}{25} \\\\C_B=0.28M\)
Therefore, the molarity of KOH solution is 0.28M
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what does monsoon cause?
Answers
Answer:
monsoon causes wet and dry seasons throughout much of the tropics
If you add sucrose to catalase when testing for reactivity, do you expect to see a reaction?.
Answers
There is no reaction when you add catalase to sucrose.
What is sucrose?Sucrose is a disaccharide that consist of glucose and fructose. Both glucose and fructose are hexoses.
Owing to the fact that catalase is specific to sucrose, there is no reaction when you add catalase to sucrose.
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Which of the following signs of a chemical reactioi
are observed in the reaction of potassium with
water?
precipitate formed
temperature change
smell produced
gas produced
color change
The answer is temperature change, gas produced, and color change
Answers
Answer:
temperature change
color change
Gas produced
Answer:
B: temperature change
D: gas produced
E: color change
49.8 grams of KI is dissolved in 1.00 kg solventCalculate the molarity, molality, mole fraction,
and mass % of KI in this solution. (Remember that 1 L water = 1 kg water)
Answers
The solution has a molality of 0.299 mol/kg, a molarity of 0.299 M, a mole fraction of 0.0054, and a mass percentage of 4.74%.
How is molarity determined?The amount of moles of KI must be determined before we can compute the molarity:
n = m/M
where M is the molar mass of KI (166.00 g/mol), m is the mass of KI (49.8 g), and n is the number of moles.
n=49.8 g/166.00 g/mol = 0.299 moles
The solution's molarity is as follows:
Molarity = n/V
where V is the solution's volume in liters (since 1 kg of solvent is approximately equal to 1 L of solution).
Molarity = 0.299 moles/one litre = 0.299 M
How is molality determined?We use the following equation to get the molality:
molality equals n / m solvent
where m solvent is the solvent's mass in kilograms (since 1 kg of solvent is given in the problem statement).
Molality is defined as 0.299 moles per kilogram (mol/kg).
How is the mole fraction determined?The formula for KI's mole fraction is:
Mole fraction of KI is equal to n KI/n total.
where n total is the total number of moles in the solution and n KI is the number of moles of KI. The mass of the solvent can be used to determine n total:
m solvent = n total / M solvent
where M solvent is the solvent's molar mass. Given that water has a molar mass of 18.015 g/mol, we obtain:
Total number of moles = 1.00 kg / 18.015 g/mol = 55.49 moles.
The mole fraction of KI is as follows:
The mole fraction of KI is calculated as follows: 0.0054
How is mass percent calculated?We must first determine the total mass of the solution in order to compute the mass percent:
KI mass plus solvent mass equals the mass of the solution.
The mass of the solution is 49.8 g plus 1000 g, or 1049.8 g.
Thus, the mass percent of KI is:
mass% KI = 100% x (mass of KI / mass of solution)
(49.8 g / 1049.8 g) x 100% = 4.74% is the mass% KI formula.
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Ill give brainliest if you answer right
Answers
Answer:
I DID NOT SEE U QUESTION PROPELY BRO /SIS
What atomic or hybrid orbitals make up the sigma bond between s and cl in sulfur dichloride, scl2?
Answers
Two Cl-atoms form a sigma bond with sp3 hybrid orbitals. Thus, SCl2 has sp3 hybridization.
The Lewis structure shows us that the carbon atom makes 4 sigma bonds to hydrogen and has no non-bonding electron pairs. The central carbon atom combines its 2s, 2px, 2py, and 2pz valence orbitals to make four, 2sp3 hybrid orbitals. Each one of these combines with a 1s atomic orbital from a hydrogen atom.
What is hybridization of SCl2?
In its most stable state, Sulfur acts as the central atom and forms two covalent bonds with the Chlorine atoms. It also possesses two lone pairs. Due to the presence of 4 electron domains and its steric number being 4, the hybridization of SCl2 is given by sp3.
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do compounds that can hydrogen bond to the silica gel generally have a lower or higher rf value than compounds that cannot?
Answers
Yes, compounds that can hydrogen bond to the silica gel have a lower Rf value than compounds that cannot hydrogen bond to the silica gel.
The Rf value (retention factor) is the distance traveled by the compound from the starting line to the position of the compound's center divided by the distance traveled by the solvent from the starting line to the position of the solvent's center.
In paper chromatography, the Rf value aids in the identification of the components of a mixture. In paper chromatography, the Rf value ranges from 0 to 1.
The Rf value of a compound is affected by the solvent, temperature, pressure, and the nature of the stationary and mobile phases.
When a compound can hydrogen bond with the stationary phase, it will stay on the silica gel, and its Rf value will be lower than the Rf value of the compound that cannot hydrogen bond with the stationary phase, and hence the answer is compounds that can hydrogen bond to the silica gel have a lower Rf value than compounds that cannot.
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The atoms of a solid aluminum can are close together, vibrating in a rigid structure. if the can is warmed up on a hot plate,
Answers
Answer:the atoms of a solid aluminium can are close together vibrating in a rigid structure if the can is warmed up on a hot plate
Explanation:
for the reaction 2c4h10 (g) 13 o2 (g) → 8 co2 (g) 10 h2o (g) δh° is -125 kj/mol and δs° is 253 j/k ∙ mol. this reaction is ________
Answers
The given chemical equation represents the combustion of 2 moles of C4H10 (butane) with 13 moles of O2 (oxygen) to produce 8 moles of CO2 (carbon dioxide) and 10 moles of H2O (water) in the gaseous state.
The negative sign indicates that the reaction is exothermic, meaning that it releases heat to the surroundings. This makes sense for a combustion reaction, where fuel (C4H10) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O), both of which have lower enthalpies than the reactants. The release of heat is due to the breaking and forming of chemical bonds, which results in a more stable and lower-energy state of the products.
The entropy change for the reaction, denoted by δS°, is 253 J/K∙mol. This represents the change in the degree of disorder or randomness of the particles involved in the reaction. The positive value indicates that the products are more disordered or have a higher entropy than the reactants.
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All atoms of the same element:
have the same number of atoms
have the same number of neutrons
have the same number of electrons
have the same number of protons
Answers
Answer:
have the same number of protons
Explanation:
The number of protons in an atom determine what element it is. The number of electrons and neutrons can vary from atom to atom of the element, as long as all the atoms have the same number of protons.
In CO2, how many UNSHARED pairs of electrons does each oxygen have?
a. 4
b. 6
c. 1
d. 2
explain why
Answers
Answer:
2, I believe.
Explanation:
In the cO2 molecule, each oxygen atom has two lone pairs of electrons. The carbon atom has no lone pairs.
Explanation:
In the cO2
molecule, each oxygen atom has two lone pairs of electrons. The carbon atom has no lone pairs. The carbon-oxygen bonds are double bonds.
The half life carbon -14 is 5730 years if 6-25% of the original percent nuclei were left in the sample how old is the sample? how many daughter nuclei (in percent) are found in the sample?
Answers
If 6-25% of the original percent nuclei were left in the sample, then the sample would be about 12,000 years old.
The daughter nuclei in the sample are found at a rate of 1/5730 = 0.0013% per year, or 13% per thousand years.
We do this by using a mass spectrometer. A mass spectrometer can break down any compound into its constituent parts, and then measure each part individually. When we do this for carbon-14, we find that there are 5730 years until half of it decays away—that's when we can add another 6% of it to our sample and expect to have another 5730 years until half of that decays away as well.
So if 6% of the original amount was left in the sample after 5730 years (half life), then there must be 5730 * 0.06 = 1520 daughter nuclei still present (in percent) in the same sample after 5730 years.
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please help me with n4 I need help and if you don’t know the answer just don’t answer please
thanks :)
Answers
Answer:
2H2(g)+O2(g)→2H2O(l)
Explanation:
(H = Hydrogen, O = Oxygen, H2O = water + energy)
3. Matter with a composition that is always the same is a(n)
substance
mixture
compound
Answers
Answer:
substance
Explanation:
A pure substance is a form of matter that has a constant composition (meaning it's the same everywhere) and properties that are constant throughout the sample (meaning there is only one set of properties such as melting point, color, boiling point, etc
A tank at is filled with of dinitrogen monoxide gas and of dinitrogen difluoride gas. you can assume both gases behave as ideal gases under these conditions. calculate the partial pressure of each gas in the tank. round each of your answers to significant digits
Answers
Partial Pressure for dinitrogen monoxide gas is 187 kPa
Partial Pressure for sulfur tetrafluoride gas is 33.4 kPa.
To calculate partial pressure first we need to calculate number of moles (n).
Mole (n) = mass/molar mass
Number of moles of dinitrogen monoxide gas= 17.7/44 gram per mole = 0.4023.
n=0.4023
Number of moles of sulfur tetrafluoride= 7.77/108.1 = 0.07188 moles.
Pressure × volume = number of moles × gas constant, R × temperature.
Pressure = n × R × T/ V.
For dinitrogen monoxide gas -
Partial Pressure = 0.4023 × 8.314 × 280.03 / 5 × 10^-3 = 187 kPa.
Partial pressure of dinitrogen monoxide gas = 187kPa.
For sulfur tetrafluoride gas-
Partial Pressure = 0.07188 × 8.314 ( × 280.03 / 5 × 10^-3) = 33.4 kPa.
Partial pressure of sulfur tetrafluoride = 33.4kPa.
So, Partial pressure of dinitrogen monoxide gas = 187kPa.
Partial pressure of sulfur tetrafluoride = 33.4kPa.
Disclaimer = This question is incomplete. Please find the full content below.
Question:
5.00L tank at 7.03°C is filled with 17.7g of dinitrogen monoxide gas and
7.77g of sulfur tetrafluoride gas
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How would the equilibrium of the reaction below be affected if thetemperature increased?A. The concentrations of O2, SO2, and SO3 would decrease.B. The concentrations of O2, SO2, and SO3 would increase.C. The concentrations of O2 and SO2 would increase.D.The concentration of SO3 would increase.
Answers
Explanation:
Wehn the temperature is increased, a product is added to the equilibrium. Therefore, the equilibrium will shift in an attempth to reduce the products. The equilibrium shifts backwards basically.
Answer:
The correct answer is A.