Calculate the volume in liters occupied by 39.6 grams of NO at 5.54 atm and 72°C

Answer:

D Fracture

Explanation:

jus took the test

Answer:

V=24,3mL

Explanation:

1)n(AgNO3)=Cm*V=0.063l*0.192M=0.012

2)n(AgNO3)/2=n(MgCl2) => MgCl2=0.012/2=0.006

3)V(MgCl2)=n/Cm=0.006/0.247=0.0243L=24,3ml

Answer: It decreases.

Explanation:

The Kc is 2.8 * 10^24

In chemistry, Kp usually refers to the equilibrium constant of a reaction that involves gases. It is defined as the ratio of the partial pressures of the products to the partial pressures of the reactants, each raised to the power of their stoichiometric coefficients.

Kp= Kc (RT)^Δn

Thus;

Kc = Kp/(RT)^Δn

Kc = 2.24 × 10²² /(0.082 * 1546)^-1

Kc = 2.8 * 10^24

Thus the Kc of the reaction when we consider the concentration of the reactants is  2.8 * 10^24

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Answer:

Explanation:

The decay of a single nucleus is random. In groups, behavior is predictable (you can predict half-life), but we can't predict when an atom will decay.

Answer:Examples of physical change include changes in the size or shape of matter. Changes of state—for example, from solid to liquid or from liquid to gas—are also physical changes. Some of the processes that cause physical changes include cutting, bending, dissolving, freezing, boiling, and melting

Explanation:

Answer:

MgI₂, MgO, PbI₄, PbO₂

Explanation:

For an ionic compound to be formed, it must be neutral, that is the total positive charge must be equal to the total negative charge.

Mg²⁺ and I⁻: The neutral ionic compound requires 1 Mg²⁺ and 2 I⁻ and the resulting empirical formula is MgI₂.

Mg²⁺ and O²⁻: The neutral ionic compound requires 1 Mg²⁺ and 1 O²⁻ and the resulting empirical formula is MgO.

Pb⁴⁺ and I⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 4 I⁻ and the resulting empirical formula is PbI₄.

Pb⁴⁺ and O²⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 2 O²⁻ and the resulting empirical formula is PbO₂.

Answer:

grams H₂O produced = 8.7 grams

Explanation:

Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)

               7g           18g                             ?g

Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water

Moles Reactants

moles C₂H₆ = 7g/30g/mol = 0.233mol

moles O₂ = 18g/32g/mol = 0.563mol

Limiting Reactant => (Test for Limiting Reactant)  Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.

moles C₂H₆/2 = 0.233/2 = 0.12

moles O₂/7 = 0.08

Limiting Reactant is O₂

Moles and Grams of H₂O:

Use Limiting Reactant moles (not division value) to calculate moles of H₂O.

moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield

grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O

Answer:

Explanation:

Nitrogen is use to store semen for artificial insemination because if it's inert characteristics which it help to maintain the semen inertness and also it maintain the low temperature of the semen which is good for it's quality.

Nitrogen also help to prevent it's biological deterioration thereby maintaining it's viability and effectiveness.

Answer:

152.57 g

Explanation:

The balanced chemical equation for the reaction between calcium and nitrogen gas to form calcium nitride is:

3Ca + N2 → Ca3N2

From the balanced equation, we can see that the mole ratio between calcium and calcium nitride is 3:1. This means that 3 moles of calcium react to form 1 mole of calcium nitride.

First, let's calculate the number of moles of calcium and nitrogen gas given:

Mass of calcium = 56.6 g

Molar mass of calcium (Ca) = 40.08 g/mol

Moles of calcium = Mass of calcium / Molar mass of calcium = 56.6 g / 40.08 g/mol = 1.41 mol

Mass of nitrogen gas = 30.5 g

Molar mass of nitrogen gas (N2) = 28.02 g/mol

Moles of nitrogen gas = Mass of nitrogen gas / Molar mass of nitrogen gas = 30.5 g / 28.02 g/mol = 1.09 mol

Since the reaction has a 90% yield, only 90% of the limiting reactant (which is calcium in this case) will be converted to product. Therefore, we need to multiply the moles of calcium by 0.90 to account for the yield:

Moles of calcium nitride formed = Moles of calcium x Yield = 1.41 mol x 0.90 = 1.27 mol

Now, using the mole ratio from the balanced equation, we can determine the mass of calcium nitride formed:

Molar mass of calcium nitride (Ca3N2) = 40.08 g/mol (molar mass of calcium) x 3 + 14.01 g/mol (molar mass of nitrogen) x 2 = 120.25 g/mol

Mass of calcium nitride formed = Moles of calcium nitride formed x Molar mass of calcium nitride = 1.27 mol x 120.25 g/mol = 152.57 g

So, the mass of calcium nitride formed in the reaction is 152.57 g.

The standard enthalpy change for the reaction 2A+B⇌2C+2D is  664 kJ/mol and The heat that is absorbed when 3.70 mol of A reacts is 2456.8  J

The heat changes that take place as reactants combine to generate a product are measured by the enthalpy of a reaction.

The following formula can be used to determine the enthalpy change of a reaction:

Hess's law states that

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Considering the given reaction: 2A + B ⇌ 2C + 2D  

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Enthalpy of reaction (ΔH°f) = (2 C + 2 D) - (2 * A + B)

Enthalpy of reaction  (ΔH°f)  = {[2(223) + 2(-523)] - [2(-245) + 2(-387)]}

Enthalpy of reaction  (ΔH°f)  = 664 kJ/mol

ΔH = q ÷ n

ΔH = molar enthalpy (heat) of solution

q = amount of energy (heat) released or absorbed

n = moles of solute

so. q = ΔH xn

q = ΔH xn

q = 664 kJ/mol x 3.70 mol

Q= 2456.8  J

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Explanation:

n2 ×2b is the only solution

Answer:

a. +0.40 V

Explanation:

Reduction of O2 in acid medium is +1.23 V. The reduction of O2 in basic medium will be calculated by subtracting equation of acidic medium from equation in base medium.

Kw^4 = [10^-14 ] ^ 4

solving we get -0.8274

Subtracting the value from oxygen reduction in acidic medium;

+ 1.23 - 0.8274 = +0.4026

Oxidation in chemistry occurs when the atoms of an element lose electrons and the oxidation state of the element increases while reduction occurs when the atom of an element gains electrons and reduces the oxidation number.

The atom being reduced is the oxidizing agent while the atom being oxidized is the reducing agent.

Oxidation number is the hypothetical charge of an atom within a molecule. The oxidation number of an element can be calculated as follows;

2x - 2(5) = 0

2x - 10 = 0

2x = 10

x = 5

2x - 6 = 0

2x = 6

x = 3

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Taking into account the definition of density, the length of each side of the cube is 4 cm.

In other words, density is a quantity that allows to measure the amount of mass in a certain volume of a substance.

The expression for the calculation of density is:

density= mass÷ volume

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case, you know that:

Replacing in the definition of density:

2 g/cm³= 128 g÷ volume

Solving:

2 g/cm³× volume= 128 g

volume= 128 g÷ 2 g/cm³

volume= 64 cm³

The volume of a cube is equal to the measure of its side to the cube. That is to say:

Volume = side x side x side = side³

So, the length of each side of the cube can be calculated as:

64 cm³= side³

∛64 cm³= side

4 cm= side

In summary, each side of the cube has a measure of 4 cm.

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Explanation:

83.6-24.2= 59.4 which is the change in heat

Answer: 212

Explanation:

According to Dalton's law of partial pressure, the pressure of the oxygen collected is 98.02 kPa.

Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.

There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .

In this case,  pressure of the oxygen collected is obtained by Dalton's law of partial pressure, as 101-2.98=98.02 kPa.

Thus, the  pressure of the oxygen collected is 98.02 kPa.

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When you step on the scale, you might see a reading of 160 lbs, but in actuality, you might weigh 160.11111 pounds, that would be challenging to determine with a standard bathroom scale.

Describe scale.

 A fish's external body covering, specifically, consists of a tiny, flattened, stiff, and unmistakably delimited plate. B: A tiny, thin plate with mica scales that resemble the scales of a moth's wing.

A little weighing scale – what is it?

It is a compact weighing scale with an easy-to-read digital screen that is portable. It is a compact weighing scale with an easy-to-read computer indicator that is portable. It is a versatile scale that works well for weighing big goods in various locations.

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Answer: -13% to 3 sig figs

Explanation:

A piece of potato had an original mass of 3.2g and after being left in a sugar solution for 24 hours it then had a mass of 2.8g. Calculate the percentage mass decrease of the potato.

the change in mass is 2.8 -3.2 = -0.4 gm

the % change fro  the origial piece is ( -0.4/3.2) X 100 = -12.5%

or  -13% to 3 sig figs

Despite having polar bonds, the molecule of carbon dioxide (CO2) is nonpolar. The linear structure of CO2 is. Due to their identical amplitude and opposite polarity, the distinct bond dipoles cancel one another.

A polar covalent molecule is water.

A water molecule has two poles: a positive charge on the hydrogen pole (side) and a negative charge on the oxygen pole due to the unequal sharing of electrons between the atoms and the asymmetrical form of the molecule (side).

CO and NH3; NH4+ and HCl; and Polar covalent bonds are present in all of the species.

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Answer:

c

Explanation:

Solution :

Given that the violet line from Balmer series having a recorded wavelength of 410 nm. As the recorded wavelength is 410 nm we know, the wavelength range of violet light is 380 nm -450 nm. So the 410 nm is corresponding to violet light wavelength.

We know, among all the series of lines spectrum of \($H_2$\) atom, only the Balmer series are in visible range. For Balmer series, the equation of wavelength associated with the e-transition of n = 2 orbit to n > 2 is

\($\frac{1}{\lambda}=R\left[\frac{1}{2^2}-\frac{1}{n^2}\right]$\)

where, R = Rydberg constant = 109678 per cm

            λ = wavelength

Here the recorded λ = 410 nm = \($410 \times 14^{-7} \ cm$\)

∴ \($\frac{1}{410 \times 10^{-7}}=109678\left[\frac{1}{2^2}-\frac{1}{n^2}\right]$\)

\($\frac{1}{2^2}-\frac{1}{n^2}=\frac{1}{410 \times 10^{-7}\times 109678}$\)

\($\frac{1}{4}-\frac{1}{n^2}=0.222$\)

\($\frac{1}{n^2}=\frac{1}{4}-0.222$\)

\($n^2=\frac{1}{0.0276}$\)

\($n^2=36.2$\)

\($n^2 $\) ≈ 36

n = ±6

Here, n is the principle quantum number. It cannot be negative, so the value of n = 6 for hydrogen atom if the violet line from Balmer series that has a recorded wavelength of 410 nm.

The value of n for the Hydrogen transition in the Balmer series with the wavelength 410 nm has been 6.

The principal quantum number in the Balmer series transition has been given by n. The minimum transition for the Balmer series has been from the 2 energy level.

The expression for the wavelength transition can be given by:

\(\rm \dfrac{1}{\lambda}\;=\;R\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\lambda\) = Wavelength = 410 nm = 410 \(\rm \times\;10^-^7\) cm

R = Rydbreg constant = 109678/cm

\(\rm \dfrac{1}{410\;\times\;10^-^7}\;=\;109678\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\rm \dfrac{1}{410\;\times\;10^-^7\;\times\;109678}\;=\;\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\rm 0.222\;=\;\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\rm 0.222\;=\;\;[\dfrac{1}{4}\;-\;\dfrac{1}{n^2} ]\)

\(\rm 0.222\;-\;\dfrac{1}{4}\;=\;\dfrac{1}{n^2}\)

\(\rm n^2\;=\;36.2\)

n = 6

The value of n for the Hydrogen transition in the Balmer series with the wavelength 410 nm has been 6.

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Answer:

5H2 + 4NO = 2N2 +4H2O + H2

Explanation:

Reactants:

Five molecules that contains two hydrogen = 5H2

Four molecules that contains one nitrogen and one oxygen = 4NO

Products:

Two molecules that contains two nitrogen = 2N2

Four molecules that contains one oxygen and two hydrogen = H2O

One molecules that contains two hydrogen = 1H2 or H2

The balanced chemical equation for the reaction will be: 5 H₂ + 4 NO → 2 N₂ + 4 H₂O + H₂, and there is no limiting reactant in this reaction.

To write the balanced chemical equation for the reaction, let's first identify the reactants and products based on the information provided:

Reactants:

5 molecules contain 2 white spheres (Hydrogen): 5 H₂

4 molecules contain 1 red (Oxygen) and 1 blue (Nitrogen) sphere: 4 NO

Products:

2 molecules contain 2 blue spheres (Nitrogen): 2 N₂

4 molecules contain 1 red (Oxygen) and 2 white (Hydrogen) spheres: 4 H₂O

1 molecule contains 2 white spheres (Hydrogen): 1 H₂

Now, let's write the balanced chemical equation by ensuring that the number of atoms of each element is the same on both sides of the equation:

Reactants: 5 H₂ + 4 NO

Products: 2 N₂ + 4 H₂O + 1 H₂

The balanced chemical equation for the reaction is:

5 H₂ + 4 NO → 2 N₂ + 4 H₂O + H₂

Now, let's determine the limiting reactant:

From the balanced equation, we can see that the stoichiometric ratio between H₂ and NO is 5:4. This means that for every 5 molecules of H₂, we need 4 molecules of NO for the reaction to proceed completely.

Since we have 5 molecules of H₂ and 4 molecules of NO, both reactants are present in the exact stoichiometric ratio required for the reaction. Therefore, neither H₂ nor NO is in excess, and both will be fully consumed during the reaction. As a result, there is no limiting reactant in this reaction.

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--The given question is incomplete, the complete question is

"Oxygen is represented by a red sphere. Nitrogen is represented by a blue sphere. Hydrogen is represented by a white sphere. In the reactants there are five molecules that contain two white spheres and four molecules that contains one red and one blue sphere. In the products there are two molecules that contain two blue spheres, four molecules that contain one red and two white spheres, and one molecule that contains two white spheres. What is the chemical formula for the limiting reactant in the reaction shown? chemical formula: Write the balanced chemical equation for the reaction, using lowest whole-number coefficients."--

Answer:

Did you get the answer to this?

Explanation:

I need this too.

Answer:

hmmm

Explanation: