Calculate the wavelength λ2 for visible light of frequency f2 = 5.25×1014 Hz .

Answers

Answer 1

To calculate the wavelength (λ2) of visible light with a frequency (f2) of 5.25×10¹⁴ Hz, we'll use the formula:

c = λ × f

where c is the speed of light (approximately 3.0×10⁸ m/s), λ is the wavelength, and f is the frequency.
First, rearrange the formula to solve for λ:
λ = c / f

Next, plug in the values for c and f2:

λ2 = (3.0×10⁸ m/s) / (5.25×10¹⁴ Hz)

Now, calculate λ2:
λ2 ≈ 5.71×10⁻⁷ m
So, the wavelength (λ2) of visible light with a frequency (f2) of 5.25×10¹⁴ Hz is approximately 5.71×10⁻⁷ meters.

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Related Questions

At what frequency should a 200-turn, flat coil of cross sectional area of 300. 0 cm2 be rotated in a uniform 30. 0-mt magnetic field to have a maximum value of the induced emf equal to 8. 0 v?.

Answers

F  = 7.1 Hz

By Emf = -N∆(BA)/∆t

8 = [200 x 30 x 10^-3 x 300 x 10^-4]/∆t

∆t = 0.023 sec

n = 1/T = 1/0.023 = 44.44 Hz

angular frequency = 44.44/2pi

   = 7.1 Hz

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compare and contrast nuclear fusion and nuclear fission. please use proper grammar and mechanics.

Answers

Answer:

The main difference between the two is - nuclear fusion results in fusing many smaller atoms into one, while in nuclear fission, the atom splits into two or more smaller ones.

Explanation:

Firstly, "fusion" generally means combining many things to one, while "fission" refers to breaking down one thing into different components. Also, nuclear fission is not common in nature, while nuclear fusion does (like in stars, for example).

if a toaster oven is labeled as 1 kw. if it is connected to a 120 v source.
(a) What current (in A) does the toaster carry?
(b) What is its resistance (in Ω)

Answers

a) The toaster carries a current of 8.33 A.

b) The resistance of the toaster oven is approximately 14.4 Ω.


(a) To find the current (in A) that the toaster carries, we can use the formula:

Power (P) = Voltage (V) × Current (I)

We're given that the toaster oven is labeled as 1 kW, which means the power (P) is 1000 W (since 1 kW = 1000 W). We also know that the voltage (V) is 120 V. We can rearrange the formula to solve for the current (I):

I = P / V

Now, plug in the given values:

I = 1000 W / 120 V

I = 8.33 A

Therefore, the toaster has an 8.33 A current.

(b) To find the resistance (in Ω) of the toaster, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

We know the voltage (V) is 120 V, and we found the current (I) to be 8.33 A. Now, we can rearrange the formula to solve for the resistance (R):

R = V / I

Now, plug in the given values:

R = 120 V / 8.33 A

R ≈ 14.4 Ω

Therefore, the toaster oven has a resistance of about 14.4.

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A car is initially moving at 10.5 m/s and accelerates uniformly to reach a speed of 21.7 m/s in 4.34 s. How far did the car move during this acceleration?
A. 69.9m
B. 6.99m
C. 69.6m/s
D. 6.99m/s

Answers

Answer:

A. 69.9m

Explanation:

Given parameters:

Initial velocity = 10.5m/s

Final velocity  = 21.7m/s

Time  = 4.34s

Unknown:

Distance traveled = ?

Solution:

Let us first find the acceleration of the car;

  Acceleration  = \(\frac{v - u}{t}\)

  v is final velocity

   u is initial velocity

   t is the time

     Acceleration  = \(\frac{21.7 - 10.5}{4.34}\)   = 2.58m/s²

Distance traveled;

     V² = U² + 2aS

    21.7² = 10.5² + 2 x 2.58 x S

   360.64 = 2 x 2.58 x S

     S = 69.9m

Melissa was putting on her makeup when she accidentally ran into a stopped car at a red light, 11. 01 m in front of her. Melissa's 1,219 kg car was moving at 8. 133 m/s and came to a complete stop in 0. 3994 seconds. What is the magnitude of the force that stopped Melissa's car?


a

2. 970E4 N

b

1. 535E4 N

c

1. 934E4 N

d

4. 550E4 N

e

4. 295E4 N

f

3. 400E4 N

g

3. 821E4 N

h

2. 482E4 N

Answers

The required magnitude of the force that stopped Melissa's car is 118608.7 N.

What are 1st 2nd and 3rd laws of motion?

According to the first law, unless a force acts on an object, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.

According to question:

An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.

Given,

speed=8.133 m/s

final velocity=0 (due to impact)

time=0.3994 seconds

distance=11.01m

Then,

S = ut + (at^2)/2

a = 2(s - ut)t^2

a = 97.3 m/s^2

So,

Force = ma

Force = 1219(97.3)

Force = 118608.7 N

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What are the two answeres?

Answers

Answer:

what do u mean?

Explanation:

Answer:

But where is the a Question???

an image formed on a screen is always​

Answers

Answer:

diminished and erect( upright)

Explanation:

A transformer for a laptop computer converts a 220-V input to a 10-V output. Write down the equations that show that the primary coil has twenty two times as many turns as the secondary coil.

Answers

The transformer operates based on the principle of electromagnetic induction this equation shows that the primary coil has twenty-two times as many turns as the secondary coil.

Let's denote the number of turns in the primary coil as Np and the number of turns in the secondary coil as Ns.

The transformer operates based on the principle of electromagnetic induction, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the input voltage to the output voltage. Mathematically, this can be expressed as:

Np / Ns = Vin / Vout

In this case, the input voltage (Vin) is 220 V and the output voltage (Vout) is 10 V. Substituting these values into the equation, we get:

Np / Ns = 220 / 10

Simplifying further:

Np / Ns = 22

This equation shows that the primary coil has 22 times as many turns as the secondary coil.

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Information about mars' moons.

Answers

Answer:

mars is a fourth planet of the sun and the second planet in the solar system

moon is a natural satellite of the earth it isthe fifth largest moon in the solar system

In how many places did the object stop moving? How do you know?

In how many places did the object stop moving? How do you know?

Answers

Explanation:

The object stops moving in 5 places (namely B, D, F, H, and position after 28 seconds which isn't marked ).

We know that the object has stopped moving, since its position does not change with the passage of time i.e. at rest.

what is reflection of light ? Which type of surface is required for a regular reflection​

Answers

Answer:

MIRROR

Explanation:

Answer:

reflection of light is the bouncing back of light rats when it falls on a smooth surface or polish surface.

awnser thiss i need awnsers​

awnser thiss i need awnsers

Answers

Answer:

B

Explanation:

Density = mass / volume

Less dense objects float to the surface so if the liquid becomes 1000 kg/m3 then it is the densest thing in the mixture, except for Q which has a density = to that of the water so it will stay in place around the middle, since the other two are more dense they will go to the bottom of the container.

The answer to this question is b

A stone is allow to fall from the top of a tower 100 m height and at the same time another stone is projected vertically upward from the ground with a velocity of 25 m/s when and where both stones meet? Calculate.g=10 m/s².​

Answers

The answer is that the two stones meet 31.25 meters above the ground, after 4.47 seconds, when they are both at the same height.

What is the time of motion of the two stones?

Let's start by finding out how long it takes for the first stone to fall to the ground.

We can use the formula:

h = 1/2gt²

where;

h is the initial height of the stone (100 m), g is the acceleration due to gravity (10 m/s²), and t is the time it takes to fall.

Plugging in the values, we get:

100 = 1/2 x 10 t²

Simplifying:

t² = 20

t ≈ 4.47 s

So it takes approximately 4.47 seconds for the first stone to fall to the ground.

Now let's find out how high the second stone goes before it starts to fall. We can use the formula:

v² = u² + 2gh

where;

v  is the final velocity (0 m/s), u is the initial velocity (25 m/s), g is the acceleration due to gravity (10 m/s²), and h is the maximum height reached by the stone.

Plugging in the values, we get:

0² = 25² - 2 x 10 x h

Simplifying:

h = 31.25 m

So the second stone reaches a maximum height of 31.25 meters before it starts to fall.

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Identify the three subatomic particles.
Where are each of the particles located
within the atom?

Answers

the three subatomic particles are protons, neutrons, & electrons
protons & neutrons are located in the nucleus
electrons are located on the rings or energy levels.
hope this can help you <3

at what frequency would the reactance of a 15 mu or micro ff capacitor equal that of a 1.5 mh inductor?

Answers

The capacitor's reactance decreases as the frequency being applied to it rises. Similarly, the reactance value of the capacitor increases as the frequency across it decreases. The complex impedance of the capacitor is the name of this variation.

Because capacitance equals inductive reaction

Xc = XL

2*pi*frequency*L = 1/(2*pi*frequency*C)

frequency^2 = 1/(4*pi^2*L*C)

frequency = 1/2 * pi * sqrt(L*C)

frequency = 1/ (2*3.142*sqrt(1.1*10^-3*11*10^-6))

frequency = 1446.67 Hz

Reactance is the resistance that a capacitor and an inductor provide to an AC current in a circuit. Reactance and resistance are relatively similar, although reactance changes depending on the frequency of the ac voltage source. Ohms are used to measure it.

Either an increase in frequency or capacitance causes a reduction in capacitive reactance. As the frequency approaches zero in the limit, the capacitive reactance reaches an infinite value. Zero frequency for the generator implies the presence of a battery or other dc source.

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what is happening when two waves with identical crests and troughs meet?

Answers

Answer:

When two waves meet in such a way that their crests line up together, then it's called constructive interference. The resulting wave has a higher amplitude. In destructive interference, the crest of one wave meets the trough of another, and the result is a lower total amplitude.

A model rocket on earth has a weight of 980N. It’s engines at full power can provide an acceleration of 2.24 m/s^2 upwards while on the earth’s surface. If the rocket is now on the moon, what upwards acceleration will the same engine provide? (Assume no air friction while on earth)

Answers

The same engine on the Moon will provide an upward acceleration of approximately 0.62 m/s²

The weight of the model rocket on Earth is 980N, which is the force exerted on it due to gravity. When the rocket's engines are at full power on Earth, they provide an acceleration of 2.24 m/s^2 upwards, effectively counteracting the force of gravity. This allows the rocket to overcome Earth's gravitational pull and ascend.

However, the gravitational acceleration on the Moon is significantly lower compared to Earth. The Moon's gravitational acceleration is approximately 1/6th of Earth's, approximately 1.62 m/s^2.

When the rocket is on the Moon, it will experience a lower force of gravity compared to Earth. Despite this decrease, the same engines that provided an upward acceleration of 2.24 m/s^2 on Earth will continue to generate the same thrust on the Moon.

Considering this, the resultant upward acceleration on the Moon will be the acceleration provided by the engines (2.24 m/s^2) minus the gravitational acceleration on the Moon (1.62 m/s^2). Therefore, the same engine will provide an upward acceleration of approximately 0.62 m/s^2 on the Moon.

In summary, due to the lower gravitational acceleration on the Moon, the rocket's engines will still provide an upward acceleration but at a reduced rate compared to when on Earth.

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Why does the Earth have gravity?​

Answers

Answer:

All its mass makes a combined gravitational pull on all the mass in your body.

Explanation:

Basically anything with mass has gravity

A merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m

A. How many revolutions will it make in 3 minutes?

B. How many revolutions will it make in 10.0 seconds?

C. How long does it take for a person to make 1 complete revolution?

D. What is the velocity in m/s of person standing on its edge?

Answers

Answer:

A.) 4 revolution

B.) 0.2 revolution

C.) 4 seconds

D.) 2.75 m/s

Explanation:

Given that a merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m

Solution

1 revolution = 2πr

Where r = 1.75m

A. How many revolutions will it make in 3 minutes?

(2π × 1.75) / 3

10.9955 / 3

3.665 RPM

Number of revolution = 15 / 3.665

Number of revolution = 4 revolution

B. How many revolutions will it make in 10.0 seconds?

First convert 10 seconds to minutes

10/60 = 0.167 minute

(2π × 1.75) / 0.167

10.9955 / 0.167

65.973

Number of revolution = 15 / 65.973

Number of revolution = 0.2 revolution

C. How long does it take for a person to make 1 complete revolution?

15 = 1 / t

Make t the subject of formula

t = 1/15

t = 0.0667 minute

t = 4 seconds

D. What is the velocity in m/s of person standing on its edge?

Velocity in m/ s will be:

Velocity = (15 × 2pi × r) / 60

Velocity = 164.9334 / 60

Velocity = 2.75 m/s

Somebody help!?
13. The graph below represents the speed of a car vs. time. Circle the letter(s) with the lowest acceleration.
What is the acceleration? How do you know?​

Somebody help!?13. The graph below represents the speed of a car vs. time. Circle the letter(s) with

Answers

Answer:

acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.

Explanation:

Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .

A positively charged particle moves north in a region where the magnetic field is to the east. The magnetic force on this particle is _______.

Answers

When a positively charged particle moves north in a region where the magnetic field is to the east, the magnetic force on this particle is directed west.

The direction of the magnetic force can be found using the right-hand rule, which states that if the thumb of your right hand points in the direction of the particle's velocity, and your fingers curl in the direction of the magnetic field, then the direction in which your palm faces is the direction of the magnetic force.

In this scenario, the particle is moving north, so the thumb points north. The magnetic field is to the east, so the fingers curl to the east. This means that the palm of your hand faces west, which is the direction of the magnetic force on the positively charged particle.

The force acts perpendicular to both the velocity of the particle and the direction of the magnetic field.A positively charged particle moving in a magnetic field experiences a force perpendicular to both the direction of the magnetic field and the direction of its motion.

The magnitude of this force is given by the equation F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the magnetic field, and θ is the angle between the direction of the particle's velocity and the magnetic field.

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If you determined the electric field intensity in a field using a test charge of 1.0×10−6 C and then repeated the process with a test charge of 2.0×10−6 C, would the forces on the charges be the same? Would you find the value for E?

Answers

The force F exerted by an electric field on a test charge q is given by:

\(F=qE\)

From this equation we notice that if we change the test charge then the force will change as well.

Therefore, the forces on the charges will not be the same.

We can't determine the electric field without further information on the problem; we need the force on one of the test charges to determine the magnitude of the field.

which of the four ray traces correctly describes the formation of an image i from an object o through a concave mirror?

Answers

Ray trace A correctly describes the formation of an image from an object through a concave mirror.

To determine which of the four ray traces correctly describes the formation of an image from an object through a concave mirror, we need to consider the behavior of light rays as they interact with the mirror.

In the case of a concave mirror, the mirror surface curves inward, causing the reflected light rays to converge. The formation of an image depends on the location of the object with respect to the focal point of the mirror.

Based on this information, we can analyze the four ray traces:

1. Ray trace A: This ray trace correctly shows a parallel incident ray being reflected through the focal point of the mirror. It also shows a diverging ray being reflected parallel to the principal axis. This ray trace represents the correct behavior for a concave mirror and is consistent with the formation of a real, inverted image.

2. Ray trace B: This ray trace shows a parallel incident ray being reflected away from the focal point of the mirror. This behavior is not consistent with a concave mirror and does not represent the formation of an image accurately.

3. Ray trace C: This ray trace shows a parallel incident ray being reflected parallel to the principal axis. This behavior is not consistent with a concave mirror and does not represent the formation of an image accurately.

4. Ray trace D: This ray trace shows a parallel incident ray being reflected towards the focal point of the mirror. This behavior is not consistent with a concave mirror and does not represent the formation of an image accurately.

Based on the analysis, only ray trace A correctly describes the formation of an image from an object through a concave mirror.

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suppose a telescope has two eyepieces: eyepiece a with focal length 10 mm and b with 20 mm. suppose the magnifying power with eyepiece a is 200. what is the magnifying power with eyepiece b? hint: it is an inverse (opposite) relationship between power and focal length.

Answers

With eyepiece b, the magnification is 100.

What distinguishes a telescope's 10 mm and 20 mm lenses?

Simply dividing the focal length of the telescope by the focal length of the eyepiece yields the magnification. This implies that a higher magnification is provided by a smaller number on an eyepiece. The magnification offered by a 10mm eyepiece would be twice that of a 20mm eyepiece.

What is magnifying and how is it calculated?

The ratio of the image's height to the object's height is represented by the formula for magnification. Additionally, the letter "m" stands for the object's magnification. Additionally, its formula is Magnification (m) is equal to h/h. Here, h is the object's height and h' is its the item's height.

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which observation by galileo proved that the ptolemaic model of the solar system was incorrect?

Answers

Galileo's observation of the phases of Venus provided evidence that the Ptolemaic model of the solar system was incorrect. In the Ptolemaic model, Venus was supposed to orbit the Earth in a circular path.

However, Galileo observed that Venus went through a full set of phases, similar to the phases of the Moon, indicating that Venus must be orbiting the Sun and not the Earth. This observation was consistent with the heliocentric model of the solar system proposed by Copernicus, in which the planets orbit the Sun.

Galileo's observations of the moons of Jupiter and the sunspots also supported the heliocentric model and challenged the Ptolemaic model of the universe.

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Galileo's observation of Venus' changing phases proved that the Ptolemaic model, which suggested that Venus orbited Earth, was incorrect.

What Galileo's observation disproved the Ptolemaic model of the solar system?

Galileo's observations of the phases of Venus played a significant role in proving that the Ptolemaic model of the solar system was incorrect.

According to the Ptolemaic model, Venus should always appear either in a crescent or gibbous phase, similar to the phases of the moon. However, Galileo observed that Venus went through a full set of phases, ranging from a crescent to a full disk and back to a crescent again, just like the moon.

This observation was only possible if Venus orbits the Sun and not the Earth, as the Ptolemaic model suggested. The phases of Venus provided strong evidence that the Sun, not the Earth, was at the center of the solar system. This observation supported the heliocentric model of the solar system proposed by Copernicus and challenged the geocentric model proposed by Ptolemy.

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To minimize signal distortion, at each end of the J-1939 CAN-bus there is a(n)_____________resistor.

Answers

5-ohm
Extra
Variable
120-ohm
Variable
Pg. 614

Ratio of acceleration due to grabity and universal gravitational constant

Answers

Answer:

acceleration due to gravity = 9.8m/s^2

universal gravitational constant= 6.67×10 ^_11 nm^2 kg_2

now, ratio=9.8/6.67×10^_11.

Students are playing tug-of-war. Which of these would cause the rope to move to the right?
A. A net force that points to the right
B. Balanced forces
C. A net force that points to the left
D. A net force of 0

Answers

Answer:

A, a net force that points to the right

Explanation:

This would make it move to the right because the net force would be above 0, and moving to the right.

Answer:

A net force that points to the right.

Explanation:

Look at the question, then use common sense while looking at the answers. Don't overthink it to much.

This is correct on a-p-e-x

The following table contains the applied forces and corresponding extension of a perfect spring. Determine the spring stiffness. Provide your answer in N/m to 4 decimal places. X (m) F (N) 0. 43 59. 34 0. 52 71. 76 0. 57 78. 66 0. 74 102. 12 0. 81 111. 78 0. 88 121. 44 0. 96 132. 48 Answer:

Answers

The spring stiffness, or spring constant, of the given perfect spring is approximately 137.9623 N/m. This means that for every meter of extension, the spring will exert a force of 137.9623 N.

This value was obtained by applying Hooke's Law and calculating the ratio of the change in force to the change in extension using two data points from the table.

To determine the spring stiffness, we need to calculate the spring constant (k) using Hooke's Law, which states that the force applied on a spring is directly proportional to the extension it undergoes.

Hooke's Law can be represented as F = kx, where F is the applied force and x is the extension of the spring.

In the given table, we have the applied forces (F) and corresponding extensions (x). We can use any two data points from the table to find the spring constant.

Let's choose the first and last data points from the table:

(x1, F1) = (0.43 m, 59.34 N) and (x2, F2) = (0.96 m, 132.48 N).

Using Hooke's Law, we can calculate the spring constant (k) as follows:

k = (F2 - F1) / (x2 - x1)
  = (132.48 N - 59.34 N) / (0.96 m - 0.43 m)
  = 73.14 N / 0.53 m
  ≈ 137.9623 N/m (rounded to 4 decimal places)

Therefore, the spring stiffness, or spring constant, is approximately 137.9623 N/m.

Hooke's Law is a fundamental concept in physics that describes the relationship between the force applied on a spring and the resulting extension it undergoes.

The formula F = kx represents this relationship, where F is the applied force, k is the spring constant, and x is the extension of the spring.

By using two data points from the table, we can calculate the spring constant by finding the ratio of the change in force to the change in extension.

This calculation allows us to quantify the stiffness of the spring.
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1) A 3.00-kg block is placed at the top of a track consisting of two frictionless quarter circles of radius R equal to 1.54 m connected by a 7.00-m-long, straight, horizontal surface (see the figure below). The coefficient of kinetic friction between the block and the horizontal surface is μkμk equal to 0.100. The block is released from rest. 1) Find where the block stops, as measured from the left end of the horizontal surface, marked x = 0 on the figure. (Express your answer to three significant figures.)
2)A bicyclist maintains a constant speed of 4.00 m/s up a hill that is inclined at 10.0∘ with the horizontal. Calculate the work done by the person and the work done by gravity if the bicycle moves a distance of 18.0 m up the hill. The combined mass of the rider and the bike is 81.0 kg.1)Calculate the work done by gravity. (Express your answer to three significant figures.)2)Calculate the work done by the person. (Express your answer to three significant figures.)

Answers

1) The block stops at a distance of 2.95 m from the left end of the horizontal surface.

2) a) The work done by gravity is 426 J.

b) The work done by the person is 1.38 × 10^4 J.

1) Find where the block stops, as measured from the left end of the horizontal surface, marked x = 0 on the figure. (Express your answer to three significant figures.)Answer:The length of the horizontal surface is 7.00 m. From the initial position to the lowest point of the first quarter-circle, the block goes through a height of 1.54 m.

The total height difference between the starting position and the ending position is therefore 2 × 1.54 m = 3.08 m. The speed at the end of the horizontal section is v = √(2gR) where R is the radius of each quarter circle. The time it takes to go from the end of the horizontal surface to the top of the second quarter circle is t = √(2R/g).

Using the law of conservation of energy, the total energy Ei at the start is Ei = mgh = 3.00 × 9.81 × 3.08 = 91.9 J. The energy Ef at the end of the second quarter circle is Ef = mv²/2, where v is the speed at the end of the horizontal section. The work done by the friction force during the horizontal section is wf = μkmgx, where x is the distance from the left end of the horizontal section to the stopping point. T

he work done by the friction force is negative because it is opposite to the direction of motion of the block. Using the work-energy principle, the net work done on the block is W = Ef - Ei - wf. Setting W = 0 givesEf - Ei - wf = 0mv²/2 - mgh - μkmgx = 0v²/2 - gh - μkgx = 0v²/2 - 9.81 × 3.08 - 0.100 × 3.00 × 9.81 × x = 0x = 2.95 m

2) a) Calculate the work done by gravity. (Express your answer to three significant figures.)Answer:Work done by gravity can be determined using the formulaW = mgh, where W is work, m is mass, g is acceleration due to gravity, and h is height difference.The force of gravity acting on the combined mass of the rider and the bike is

Fg = mg = 81.0 × 9.81 = 796 N. The component of this force acting along the incline is Fg sin θ = 796 × sin 10.0° = 137 N.The height difference between the starting and ending points is h = 18.0 sin 10.0° = 3.11 m.Using the formula,W = Fg sin θ h = 137 × 3.11 = 426 JWork done by gravity is 426 J.

b)  Work done by the person can be determined using the formulaW = Fd, where W is work, F is force, and d is displacement.The force required to maintain a constant speed on an incline is

F = mg sin θThe distance travelled up the incline is d = 18.0 m.The work done by the person is

W = Fd = mg sin θ d = 81.0 × 9.81 × sin 10.0° × 18.0 = 1.38 × 10^4 J

Work done by the person is 1.38 × 10^4 J.

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(a) Determine the depreciation rate for a car that originally cost $17,000 and is worth $13,000 affer 5 yr. Round to the nearest tenth of a percent. Identify the strength and weakness of BMB from the case study A moving source tends to compress the sound waves in the direction it is moving. Is this true or false? Susan counted a total of 36 red and green cars in the parking lot. There were 8 times as many red cars as green cars. How many red cars did Susan count? Write an equation of a line in slope intercept form given the line passes through the points (-5, 3) and (0, -7) Which of the following causes a frameshift mutation?There may be more than one correct answer.Select all that apply.O DeletionO SubstitutionO InsertionO Only 602 divided by 1836, x 100 The __________ phase of the secsdlc, the team studies the documents from earlier and looks at of relevant legal issues that could affect the design of the security solution. create your fitness program...I really need it... when analyzing an argument, which elements should you focus on most? select three options.counterclaimclaimreasonsdissentevidence Find the number that belongsin the green box.Round your answer to the nearest tenth. Lumber LLC files a suit against Mill Company to enforce an oral contract that would otherwise be unenforceable under the Statute of Frauds. The court could enforce such a contract ifA. Lumber foreseeably and justifiably relied on Mill's promise.B. neither party has begun to perform.C. the deal does not involve customized goods.D. Mill denies the existence of any contract. Which statements are true about the solution of 15 > 22 + x? Select all that apply.A.-6 is part of the solution.B. x < -7c. Thegraph has a closed circle.D. x > -7E.-7 is part of the solution. a client reports to the nurse that her mother had macular degeneration and is concerned that she, too, may be at risk. what should the nurse tell the client? A ship travels due west for 94 miles. It then travels in a northwest direction for 119 miles and ends up 173miles from its original position. To the nearest tenth of a degree, how many degrees north of west (x) did itturn when it changed direction? Show your work. what is a recessive trait how did eugenics contribute to the passing of sterilization laws in the u.s., and how common were these laws in the u.s. by 1935? did north carolina have a sterilization law? The Corner Store sells 4 bottles of energy drinks for $11.56, Bev's sells 6 bottles for $17.94. Which is the better buy? how to make an array with txt file java the difference between two numbers is -1. their sum is -27. find the numbers. let x represent the first number and y represent the second number. solve using system s of equations.