Calculate
(123-90.2)x1.25
123 (90.2×1.25)

Answer:

\(\frac{224}{10}=22.4\\ \frac{5315}{10}=531.5\\\frac{3783}{100}=37.83\\ \frac{34502}{1000}=34.502\)

Step-by-step explanation:

To solve the problem, we need to write each fraction in decimal form.

Notice that each denominator is 10 based, which means we only have to move the decimal point according to the total number of zeros have the denominators. If the denominator is 10, we move the decimal point one spot to the left, if the denominator is 1000, we move the decimal point three spots to the left, and so on.

\(\frac{224}{10}=22.4\\ \frac{5315}{10}=531.5\\\frac{3783}{100}=37.83\\ \frac{34502}{1000}=34.502\)

Answer:

Step-by-step explanation:

I think the only way you can solve this is to assume that <R means PRT in the given ratio. If I am wrong, I don't think the problem can be solved.

Find <T

Let <T = x

and <PRT = 3x

KLMN is a Parallelagram and therefore two adjacent angles are supplementary.

<PRT + <T = 180 degress

3x + x = 180 degrees

4x = 180

x = 45

So <T = 45

<PRT = 3*45 = 135

If RD is perpendicular to PS then <PDR = 90o

Here's the trick.

RD is also Perpendicular to RT

<MRD + <MRT = 90

<MRT = 180 - 90 - <T

<MRT = 180 - 90 - 45

<MRT = 45

Here comes your answer

=================

<MRD + MRT = 90

<MRD + 45 = 90

<MRD = 45

====================

Note: you must ignore everything to do with the diagram. It is not drawn to scale and the letters are not the same as in the question. The only thing you use is that the figure is a ||gm

Answer: y = x + 19

Step-by-step explanation:

y=4x+15-4x+4=12

y=4x-4x=15+12+4

y=x+19

Answer:

c: 3 ⅓

Step-by-step explanation:

C has been simplified. If we converted the fraction ⅓ to 2/6 the answer would equal 20.

This is because we can do (whole number × denominator) 3 × 6 = 18 and then 18 + 2 (numerator) = 20

Answer:

Step-by-step explanation:

Answer:

  θ = 83°

Step-by-step explanation:

For acute angles, the sine of an angle is the cosine of its complement, and vice versa.

__

  sin(θ) = cos(90° -θ) . . . . relation between sine and cosine

  sin(θ) = cos(7°) . . . . . . . . given

  90° -θ = 7° . . . . . . . . . matching arguments of cos( )

  θ = 83° . . . . . . . . . add θ -7° to both sides

To find the maximum possible value of the error between the Maclaurin polynomial T3 of f(x) = e^x and the function value at x = 1.8, we need to use the Error Bound formula. The formula states that the absolute value of the error, |f(x) - Tn(x)|, is less than or equal to the maximum value of the nth derivative of f(x) times the absolute value of (x - a) raised to the power of n+1, divided by (n+1)!.

For the given function f(x) = e^x and Maclaurin polynomial T3, we have n = 3 and a = 0. The nth derivative of f(x) is also e^x. Substituting these values into the Error Bound formula, we get:

|f(x) - T3(x)| ≤ (e^c) * (x - 0)^4 / 4!

where 0 < c < x. Since we need to find the maximum possible value of the error for x = 1.8, we need to find the maximum value of e^c in the interval (0, 1.8). This maximum value occurs at c = 1.8, so we have:

|f(1.8) - T3(1.8)| ≤ (e^1.8) * (1.8)^4 / 4!

Rounding this to four decimal places, we get:

If(1.8) - T3(1.8) < 0.0105

The maximum possible value of the error between f(x) = e^x and its Maclaurin polynomial T3 at x = 1.8 is 0.0105. This means that T3(1.8) is a very good approximation of f(1.8), with an error of less than 0.011.

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Answer:

x=12

Step-by-step explanation:

(x-6)=6

x=12

Given:

Price of  gold in 2001 = (0.5x+300)

Its price tripled in 2008 and then doubled in 2011. In 2016, its price dropped to \(\dfrac{2}{3}\) of the price in 2011.

To find:

An expression for the price of gold per ounce in 2016.

Solution:

We have,

Price of  gold in 2001 \(= (0.5x+300)\)

Its price tripled in 2008.

Price of  gold in 2008 \(= 3(0.5x+300)\)

Then doubled in 2011.

Price of  gold in 2011 \(= 2\times 3(0.5x+300)\)

In 2016, its price dropped to \(\dfrac{2}{3}\) of the price in 2011.

Price of  gold in 2016 \(=\dfrac{2}{3}\times 2\times 3(0.5x+300)\)

                                    \(=2\times 2(0.5x+300)\)

                                    \(=4(0.5x+300)\)

                                    \(=4(0.5x)+4(300)\)

                                    \(=2x+1200\)

Therefore, the required expression for the price of gold per ounce is (2x+1200).

Answer:

10h + 2b = 155

12h + 3b = 189

Step-by-step explanation:

Hope this helps :D

Answer:

Step-by-step explanation:

2590

Answer:

Box e

Step-by-step explanation:

14/20=0.7

Step-by-step explanation:

to find x its

\( \sqrt{ {19.5}^{2} + {1.5}^{2} } = \sqrt{380.25 + 2.25} = 19.5576072156\)

Answer: The equation 20x³-25x²+4x-5 can be factored by finding its roots, which are the values of x that make the equation equal to zero.

To find the roots, you can use one of the following methods:

Rational Root Theorem

Synthetic Division

Factor Theorem

Binomial Expansion

I would recommend using the Rational Root Theorem, which states that if a polynomial has a rational root, then it can be expressed as a product of linear factors with rational coefficients.

First, list out the possible rational roots of the equation: ±1, ±2, ±5, ±1/2, ±1/5.

Next, test each root by dividing the equation by (x-root), using synthetic division. If the remainder is zero, then the root is a factor of the equation. Repeat this process until you have found all of the roots.

Finally, factor the equation by grouping the roots into pairs and multiplying each pair to obtain a quadratic factor. Factor each quadratic and simplify the expression.

It is important to note that this is a rather advanced topic in algebra and finding the roots of polynomials can be quite challenging. If you need further assistance, I recommend seeking help from a tutor or textbook on algebra.

Step-by-step explanation:

\( \purple{ \huge{ \tt{ \: ✨ Answer ✨ \: }}}\)

\(The \: \: answer \: \: is \: \: \red{ \boxed{ \boxed{ \huge{ \tt{ \: c. \: \frac{2}{7} \: \: }}}} }\)

i) The multiplication of (3.1x\(10^0\)) and (1.5x10) results in 4.65x\(10^1\).

j) The division of (3.1x10) by (1.5x\(10^{-1\)) equals 2.07x\(10^1\).

i) To multiply numbers in scientific notation, we multiply the coefficients (3.1 and 1.5) and add the exponents (0 and 1) together. In this case, 3.1 multiplied by 1.5 gives us 4.65. Adding the exponents, \(10^0\) multiplied by \(10^1\) results in \(10^1\). Therefore, the final result is 4.65x\(10^1\).

j) When dividing numbers in scientific notation, we divide the coefficients (3.1 and 1.5) and subtract the exponents (1 and -1) from each other. Dividing 3.1 by 1.5 gives us approximately 2.07. Subtracting the exponents, \(10^1\)divided by \(10^{-1\) is equivalent to \(10^{(1-(-1))}\) which simplifies to 10^2. Hence, the result is 2.07x\(10^1\).

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Answer:

4

Step-by-step explanation:

your slope-intercept will be 4

Answer:

y = 4x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 4x - 3 ← is in slope- intercept form

with slope m = 4

Parallel lines have equal slopes

Thus parallel line has m = 4 and c = 5

y = 4x + 5 ← equation of parallel line

The stack pointer is decremented by a multiple of 4, as required by the MIPS architecture.

To solve the MIPS stack pointer question, we need to reserve enough space on the stack for 2 integers and the\(`$ra`\)register. Each integer and the ra register occupy 4 bytes, so the total space required is 12 bytes.

However, since the stack pointer is manipulated in multiples of 4, we need to find the closest multiple of 4 to -12, which is -16.

Hence, the value of XX in the instruction \(`addiu $sp, $sp, XX`\) should be -16 to reserve enough room on the stack for 2 integers and the ra register.

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Explanation:

1 hat = 45 dollars

6 hats = 6*45 = 270 dollars

1 phone = 40 dollars

4 phones = 4*40 = 160 dollars

total = $270 + $160 = $430

Felicia spent a total of $430. Since this amount of money leaves her account, this means we write a negative sign out front to end up with the final answer of -430

In other words, her account balance went down by $430 which is why we use a negative. If someone gave her $430, then the answer would be positive.

The perimeter of the triangle will be the addition of all its sides.

It should be noted that the perimeter of a triangle is calculated by adding the values of all its sides

Die example, of the sides are 4cm, 7cm and 5cm. The perimeter of the triangle will be:

= 4cm + 7cm + 5cm

= 16cm

Based on the information given, it's important to add the equations together and equate them to 78 to get the value of AB.

Note that an overview was given as the question is incomplete.

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Data definition involves describing the properties of the data that go into each database table, specifically the fields or columns that make up the database.

What is a field record table and query?

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Answer:

System of equations:

J = 2S - 8

5S + 3J = 273

Prices:

Jacket: $46

Shirt: $27

Step-by-step explanation:

Let J = price of jacket.

Let S = price of shirt.

J = 2S - 8

5S + 3J = 273

Since the first equation is already solved for J, use substitution.

5S + 3(2S - 8) = 273

5S + 6S - 24 = 273

11S = 297

S = 27

J = 2S - 8

J = 2(27) - 8

J = 54 - 8

J = 46

Answer:

System of equations:

J = 2S - 8

5S + 3J = 273

Prices:

Jacket: $46

Shirt: $27

The due date of the loan in the amount of $14,800, opened on January 22, at an interest rate of 9% and with the maturity value of the loan as $15,799, is a. October 22nd.

The due date can be determined using an online finance calculator, which shows that it will take almost 9 months for the loan's due date.

I/Y (Interest per year) = 9%

PV (Present Value) = $14,800

PMT (Periodic Payment) = $0

FV (Future Value) = $15,799

Results:

Loan Period (N) = 8.742 months

≈ 9 months

Total Interest = $999.00

Thus, 9 months to January 22 falls on October 22nd.

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L(x) if x is 4.12 inches per second is $21.

To estimate the tolerance for the firm to minimize its quality-related cost (loss), we need to determine the range of acceptable speeds that minimize the cost. The tolerance can be calculated as the difference between the upper and lower limits of the acceptable speed range.

Given that the desired speed is 4 inches per second and the quality specification allows a deviation of 0.17 inches per second, we can calculate the upper and lower limits as follows:

Upper Limit = Desired Speed + Tolerance

Lower Limit = Desired Speed - Tolerance

Let's assume the tolerance is represented by 't'.

Upper Limit = 4 + t

Lower Limit = 4 - t

To minimize the quality-related cost, we want to find the smallest value of 't' that satisfies the condition.

The cost can be minimized when the difference between the upper and lower limits is equal to twice the return cost of $28.

Upper Limit - Lower Limit = 2 * $28

(4 + t) - (4 - t) = 2 * $28

2t = 2 * $28

t = $28

Therefore, the estimated tolerance for the firm to minimize its quality-related cost is 0.28 inches per second (rounded to 4 decimal places).

Note: In this scenario, the tolerance is set to 0.28 inches per second to ensure that the cost of returns is minimized for the company.

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Answer:

No.

In a right triangle one of the angles is right angle i.e 90° and, therefore, sum of other two angles will always be equal to 90°, which means the other two angles will be acute angles

Answer:

Option C, 93.6 mi³

Step-by-step explanation:

Volume of the triangular prism,

base area × height

= (8×3.9/2)×6

= 93.6 mi³

There are 792 different, unique ways you can sort the 7 green apples and 5 red apples while keeping track of the order.

To determine the number of different, unique ways you can sort the 7 green apples and 5 red apples while keeping track of the order, you can use the concept of permutations.

Since you have a total of 12 apples, the number of ways to arrange them can be calculated using the formula for permutations of objects with repetition.

In this case, we have 7 green apples and 5 red apples, so the formula becomes:

P(12; 7, 5) = 12! / (7! * 5!)

Calculating this expression, we get:

P(12; 7, 5) = (12 * 11 * 10 * 9 * 8 * 7 * 6) / (7 * 6 * 5 * 4 * 3 * 2 * 1) * (5 * 4 * 3 * 2 * 1)

Simplifying, we have:

P(12; 7, 5) = 792

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If the algorithm has a constant number of steps independent of the input size, s(n) remains the same when n is doubled.

Then the effect on the number of steps required, denoted as s(n), when the number of items being processed (n) is doubled will depend on the specific algorithm and its complexity.

Here are a few possibilities:

1. Constant Time Complexity (O(1)): If the algorithm has a constant time complexity, it means that the number of steps required remains the same, regardless of the input size. In this case, doubling n would not have any impact on s(n).

2. Linear Time Complexity (O(n)): If the algorithm has a linear time complexity, it means that the number of steps required is directly proportional to the input size. Doubling n would approximately double the number of steps as well. Thus, s(n) would increase in a linear manner.

3. Quadratic Time Complexity (O(n^2)): If the algorithm has a quadratic time complexity, it means that the number of steps required grows quadratically with the input size. When n is doubled, the number of steps would be approximately four times the original amount. Thus, s(n) would increase significantly.

4. Logarithmic Time Complexity (O(log n)): If the algorithm has logarithmic time complexity, doubling n would not have a substantial impact on the number of steps required. The increase in s(n) would be relatively small compared to the increase in n.

These are just a few examples, and there are various other complexities that algorithms can exhibit.

Each algorithm has its own time complexity, which determines how the number of steps required changes as the input size is doubled.

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