Answers
Calculations:
• Let ,x , represent electron in a body.
,• use the following formula tocalculagte excess electrons acquired.
,• Charge = 125mC /10000 =1.25 x10^-2
\(\begin{gathered} \text{Charge = electron }\cdot\text{ electron charge } \\ 1.25X10^{-2\text{ }}=\text{ x }\cdot1.6X10^{-19} \\ x\text{ = }\frac{1.25X10^{-2}}{1.6X10^{-19}} \\ \text{ }\therefore x\text{= }7.8125X10^{-22} \end{gathered}\)This means that there are 7.8125x10^-22 excess electron aqcuired.Related Questions
How much heated must be absorbed by 125 g of ethanol to change temperature from 21.5 to 34,8 C
Answers
Answer:
4.02 kJ
Explanation:
We must convert the answer to kJ 4023.25 J . 1kJ /1000 =4.02kJ
The interior of an incandescent light bulb is at about 610 mm hg. What is the pressure in a lightbulb in atmospheres
Answers
Answer:0.802atm
Explanation:
To convert pressure from millimeters of mercury (mmHg) to atmospheres (atm), you can use the conversion factor:
1 atm = 760 mmHg
So, to convert the pressure of the light bulb from mmHg to atm, divide the given pressure by 760:
Pressure (in atm) = 610 mmHg / 760 mmHg
Pressure (in atm) ≈ 0.802 atm
Therefore, the pressure inside the light bulb is approximately 0.802 atmosphe
Which of the following never changes no matter where you are in the universe?
A Mass
B Weight
C) Pounds
D) Force
Answers
Answer: i think its A but i also think its D correct me if im wrong
Explanation:
Answer:
Mass
Explanation:
The mass of an object will be the same no matter where in the universe that object is located. Mass is never altered by location, the pull of gravity, speed or even the existence of other forces.
A 645 g piece of iron is plunged into 375 g of water. The temperature of the water increases from 26 C to 87 C. If the heat capacity of iron is 0.449 J/g C, what must have been the original temperature (in C) of the piece of iron
Answers
Answer:
417 °C
Explanation:
From the question given above, the following data were obtained:
Mass of iron (Mᵢ) = 645 g
Specific heat capacity of iron (Cᵢ) = 0.449 J/gºC
Mass of water (Mᵥᵥ) = 375 g
Initial temperature of water (Tᵥᵥ) = 26 °C
Equilibrium temperature (Tₑ) = 87 °C
Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC
Initial temperature of iron (Tᵢ) =?
The initial temperature of iron can be obtained as follow:
Heat lost by iron = heat gain by water
MᵢCᵢ(Tᵢ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
645 × 0.449(Tᵢ – 87) = 375 × 4.184 (87 –26)
289.605(Tᵢ – 87) = 1569 × 61
289.605Tᵢ – 25195.635 = 95709
Collect like terms
289.605Tᵢ = 95709 + 25195.635
289.605Tᵢ = 120904.635
Divide both side by 289.605
Tᵢ = 120904.635 / 289.605
Tᵢ ≈ 417 °C
Thus, the original temperature of the iron is 417 °C
Experiment 4: A chemist mixes aqueous solutions of sodium hydroxide and aluminum chloride in a double-displacement reaction, which forms a white solid precipitate and a clear solution. Write the complete, balanced molecular equation for the reaction. Include physical states.
balanced equation:
Answers
The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)
In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.
The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.
The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.
In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.
It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.
Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.
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Find the SDS for regular bleach
Answers
The Safety Data Sheet (SDS) for regular bleach can be obtained from the manufacturer or supplier of the specific brand or product. It contains important information regarding the hazardous properties, handling, storage, and emergency procedures related to the bleach.
An SDS typically includes details such as the product's chemical composition, physical and chemical properties, potential hazards to health and the environment, precautionary measures for safe handling and storage, first-aid procedures, and information about proper disposal. It also provides guidance on personal protective equipment (PPE) to be used when handling the product and steps to take in case of accidental release or exposure.
The SDS serves as a crucial resource for understanding the potential risks associated with the use of regular bleach and helps ensure that appropriate safety measures are implemented. It is important to review and follow the information provided in the SDS to minimize the risk of accidents, injuries, or adverse health effects associated with the use of the product.
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the heat produced by 3 kg of fuel a is 50000 J the heat produced by 5 kg of fuel b is 3000 KJ which fuel is more efficient
Answers
you dissolve 0.01 moles of glycine in 1 liter of water and begin to titrate the resulting solution using concentrated naoh (insignificant volume added).a. Draw the titration curve in terms of pH vs equivalents of base. Locate and label any buffering regions that may be present.b. You adjust the pH to 7.0. After that you add 0.005 moles of NaOH. Draw the structure(s) of the species ofglycine present in the solution and indicate the proportion of each species.c. What is the approximate pH of the solution in part b?d, Would this solution be a good buffer?
Answers
The pH of the solution, which is set at 3, depends on the kinds and amounts of glycine present in the solution as well as the pka of the NH2 group, which ranges from 9 to 78. pH = equivalent = 9.78, thus
What is glycerine's advantage?
Glycerine, an amino acid, provides a wide range of incredible health benefits. Your body needs glycerine to make essential compounds including glutathione, creating, and collagen. This amino acid may also protect your liver from the negative effects of alcohol while improving your heart health and sleep.
who shouldn't consume glycerin?
A single amino acid should not be consumed in large amounts over a lengthy period of time. Avoid consuming isolated amino acids in large amounts without first talking to a doctor. Glycine supplements shouldn't be taken by women who are pregnant or breastfeeding.
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How does the altitude of the Sun change throughout the year in Reno, NV?
Question 1 options:
The angle of the Sun is lower during the winter months and higher in the sky during the summer.
The angle of the Sun is higher during the winter months and lower in the sky during the summer.
Answers
Answer:
The angle of the Sun is lower during the winter months and higher in the sky during the summer.
Explanation:
i took the test
A sample of oxygen is subjected to an absolute pressure of 2.4 atm. If the specific internal energy of the sample at 310 K is 5700 J/mol relative to a known reference state, what is the specific enthalpy of the oxygen relative to that same reference state?
Answers
Answer:
The required specific enthalpy for oxygen = 8277.34 J/mol
Explanation:
Given that :
Pressure = 2.4 atm
Temperature = 310 K
specific internal energy U = 5700 J/mol
To find the specific enthalpy using the formula:
H = U + PV
where;
H is known as the specific enthalpy
Recall that from ideal gas equation
PV = nRT
For specific enthalpy, it is constant that n = 1
Thus;
PV = RT
replacing that into the equation (H = U + PV), we have:
here;
R = 8.314 J/mol K (constant)
H = U + RT
H = 5700 J/mol +( 8.314 J/mol K × 310 K)
H = 5700 J/mol + ( 2577.34 J/mol)
H = 8277.34 J/mol
In the picture this is my last question pls.
Answers
Answer:
Chromosomes and I think its too many
Explanation:
a 10 gram ball is rolling at 20 m/s. what energy does the ball have
Answers
Answer:
2 joule
Explanation:
10 gram= 0,01kg
The ball has kinetic enegry
K=1/2 *m *speed²
K=1/2 *0,01 * 400
K=2 Joule
What is the best way to measure the pH of a natural solution while out in a forest?
Answers
The best way to measure the pH of a natural solution while out in a forest is to use a portable pH meter or pH test strips specifically designed for field use. These instruments provide accurate and reliable pH measurements and are convenient for outdoor applications.
1. Prepare the necessary equipment: Before heading out to the forest, gather the required tools. You will need a portable pH meter or pH test strips, as well as the necessary reagents or calibration solutions if using a pH meter.
2. Collect the sample: Locate the natural solution you want to measure the pH of, such as a stream, pond, or soil. Use a clean container to collect a representative sample of the solution.
3. Calibrate the pH meter (if applicable): If you are using a portable pH meter, it is essential to calibrate it before taking measurements. Follow the manufacturer's instructions to calibrate the meter using the provided calibration solutions.
4. Conduct the measurement: For pH meters, immerse the electrode into the collected sample. Allow some time for the reading to stabilize, and then record the pH value indicated on the meter's display.
5. Using pH test strips: If you are using pH test strips, dip the strip into the collected sample for the recommended amount of time. Remove the strip and compare the color change with the provided color chart. Determine the corresponding pH value from the chart.
6. Repeat for accuracy: To ensure reliability, repeat the measurement process at least once and compare the results. This step helps confirm the accuracy of your measurements.
7. Record and analyze the data: Note down the pH values obtained and any relevant observations. Analyze the data as needed for your research or monitoring purposes.
By following these steps and using the appropriate equipment, you can effectively measure the pH of a natural solution while in a forest setting.
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how many grams does 6.02 x 1023 atoms of he weight
Answers
Answer:
=16.00 g/mole
Explanation:Oxygen’s atomic weight is 16.00 amu.
1 mole of oxygen is 6.02 x 1023 atoms of oxygen
1 amu = 1.661 x 10-24g
What is the molar mass (g/mole) of oxygen?
16.00 amu/oxygen atom x 1.661 x 10-24g/amu
= 2.657 x 10-24 g/atom x 6.02 x 1023 atoms/mole
=16.00 g/mole
Molar mass (in grams) is always equal to the atomic weight
1. The region north of 66½° N latitude is the Arctic Circle. Use the simulator to determine the length of the day during each time of year.
Answer:
Time of Year Length of Day (in hours)
Winter solstice
Spring equinox
Summer solstice
Fall equinox
Answers
The Arctic Circle is located north of 6612° N latitude. The simulation of the duration of the day at each season is based on the winter solstice.
Is the Arctic Circle located north of 66 1 2 N latitude?The Arctic Circle is a hypothetical line, or latitude, that circles the globe around 66 12 degrees north of the equator. The area immediately south of the Arctic circle is referred to as the "North Temperate Zone," whereas everything north of the Arctic circle is referred to as the "Arctic region."
What method was used to map the Arctic Circle?The axial tilt (angle) of the Earth's polar axis of rotation with respect to the ecliptic determines where the Arctic Circle is located. This stance has a complicated motion that is not constant and is controlled by numerous cycles of short to extremely long intervals. Its average value in 2000 was roughly 23°26′21′′.
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What type of ions do metals produce?
Answers
Answer:
Ionic bonds
Explanation:
It rymes. haha i dont even know how to spell it! ;)
4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)
How many moles of ammonia (NH3) are needed if 2.75 moles of water (H2O) were produced?
4.13 mol
1.83 mol
4 mol
(only respond if you have the answer)
6.8 mol
Answers
Answer: from multipliers of substances and real amount of moles you get an equation
For x = amount of ammonia in moles. X/4 = 2.75/6 and x = 11/6 = 1.83 mol
Explanation:
At which part of a river would you have the best luck growing food?
A. Bend
B. Delta
C. Alluvial fan
D. Source
Answers
Answer:
B. Delta
Explanation:
What functional group results when cyclopentanone reacts with ethylamine in the presence of trace acid? A) cyanohydrin B) semicarbazone C) imine D) enamine E) oxime
Answers
Calculate the number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water.
Answers
The number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water is 0.025 moles.
The reaction of potassium with an excess amount of water is:
2K + 2H\(_2\)O \(\rightarrow\) 2KOH + H\(_2\)
To calculate the moles of hydrogen gas first we need to calculate moles of potassium in 2.00g
No. of moles = (mass) / (molecular mass)
The mass given is 2.00 g and the Molecular mass is 39.09 units
∴ No. of moles = (2) / (39.09) = 0.05
From the above reaction, we get that 2 moles of potassium give 1 mole of hydrogen gas. Thus, 0.05 moles of potassium gives 0.025 moles of hydrogen gas.
Therefore, the no. of moles of hydrogen gas produced is 0.025 moles.
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The reaction of benzene with (CH3)3CCH2Cl in the presence of anhydrous aluminum chloride produces principally which of these?
Answers
Answer:
See explanation and image attached
Explanation:
When the carbocation is formed by the action of AlCl3 on the (CH3)3CCH2Cl, a primary carbocation is formed. The formation of the carbonation is followed by a 1,2-alkyl shift to give a tertiary carbocation which subsequently adds to the benzene ring as shown in the image attached to this answer.
The reaction of Benzene in the presence of anhydrous aluminum chlorides will produce :
A carbocation and 1,2 -alkyl shift that produces a tertiary carbocation which is added to the Benzene ring.CarbocationCarbocation is a cation which contains an even number of electrons and has a large percentage of its positive charge residing in a carbon atom. when Benzene reacts in the presence of anhydrous aluminum chloride a carbocation is formed.
Hence we can conclude that The reaction of Benzene in the presence of anhydrous aluminum chlorides will produce : A carbocation and 1,2 -alkyl shift that produces a tertiary carbocation which is added to the Benzene ring.
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Let's do this!
Balance each equation so there are the same number of each type of atom on both sides of the
equation There is a chart above each problem to help you count the atoms
First-Count up the
number of atoms you
currently have Write
that number in the
chart for both sides of
the equation
Second-If the
numbers don't match,
try adjusting the
coefficients one at at
time Make sure to
change the number in
the chart
Remember- you can't
change the formulas!
2
Reactants
Mg
M
Mg
LI
Reactants
H
LO +
Products
Mg
N
L
O
H
но →
_Math
Products
LIOH
You should
do this in
pencil
Answers
The balanced chemical equations of the reactions are given below:
1. Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)
2. 2 Li (s) + 2 H₂O (l) ----> LiOH (aq) + H₂ (g)
What is a balanced equation?A balanced chemical equation is an equation in which the number of moles of atoms of elements in a given reaction is equal to the sum of the number of moles of atoms of each element that is produced.
A balanced chemical equation is in accordance with the law of conservation of mass which states that matter can neither be created nor destroyed.
When balancing chemical equations, numerical coefficients are added in front of moles of atoms of an element or moles of a given compound taking part in the reaction.
The balanced chemical equation of the reaction of magnesium and water as well as the reaction of lithium and water is given below:
Magnesium and water:
Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)
Lithium and water:
2 Li (s) + 2 H₂O (l) ----> LiOH (aq) + H₂ (g)
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In 13C NMR spectroscopy, which of the following chemical shifts is most likely associated with a carbon atom of an aromatic ring? 200 ppm 50 ppm 120 ppm
20 ppm90 ppm
Answers
120 ppm is the most likely associated with a carbon atom of an aromatic ring.
This is due to the fact that in 13C NMR spectroscopy, aromatic rings often resonate at levels between 100 and 150 ppm. This is as a result of the ring's electrons being delocalized, which increases the ring's electron density. The carbon atoms in the ring are shielded more magnetically as a result of the increased electron density, which makes them appear as a peak at a lower frequency on the NMR spectrum. The other values on the list are either too high or too low to be connected to an aromatic ring.
A type of spectroscopy called nuclear magnetic resonance (NMR) spectroscopy employs the magnetic characteristics of certain nuclei to ascertain the structure of molecules. This method can be used to identify the type of chemical bonding as well as the structure of complex compounds like proteins and carbohydrates. The method is also employed to research the behaviour of molecules in solutions and to analyse the kinetics of chemical reactions.
A potent method for examining the structure and make-up of organic compounds is 13C NMR spectroscopy. It is based on the idea that when exposed to a magnetic field, the nuclei of some atoms act in a different way. Chemists can identify and count the many types of carbon atoms present in a molecule using 13C NMR spectroscopy, which examines the chemical environment of the carbon atoms in a molecule. Additionally, it can reveal details about the other atoms in the molecule's chemical environment, such as the kinds of bonds they make and the separations between them.
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Explain how a rainbow is produced
Answers
A rainbow is produced through a proces that includes refraction, reflection, and dispersion of sunlight.
What more should you know about the production of rainbows?A rainbow is formed when sulinght is refracted and reflected by rain drops in the atmospher.
The sunlight is split into its component colors, which is why rainbows appear as having an array of colors. This is due to each color being bent by a different amount during refraction.
The colors of a rainbow are always in the same order, with red on the outside and violet on the inside.
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I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE
Answers
The number of mole of Ba₃(PO₄)₂ produced from 3.54 L of 0.373 M BaCl₂ is 0.44 mole
How do i determine the mole of Ba₃(PO₄)₂ produced?We'll begin our calculation by obtaining the mole of BaCl₂ in 3.54 L of 0.373 M BaCl₂. This is shown below:
Volume = 3.54 LMolarity = 0.373 MMole of BaCl₂ =?Mole = molarity × volume
Mole of BaCl₂ = 0.373 × 3.54
Mole of BaCl₂ = 1.32 mole
Finally, we can determine the number of mole of Ba₃(PO₄)₂ produced from the reaction. This is illustrated below:
Balanced equation for the reaction:
3BaCl₂ + 2H₃PO₄ -> Ba₃(PO₄)₂ + 6HCl
From the balanced equation above,
3 moles of BaCl₂ reacted to produce 1 mole of Ba₃(PO₄)₂
Therefore,
1.32 mole of BaCl₂ will react to produce = 1.32 / 3 = 0.44 mole of Ba₃(PO₄)₂
Thus, we can conclude from the calculation made above that the number of mole of Ba₃(PO₄)₂ produced is 0.44 mole
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Calculate the grams of O2 required for the combustion of 25.9 g of ethylcyclopentane
Answers
C11H20 + 15O2 → 11CO2 + 10H2O
From the balanced equation, we can see that 15 moles of O2 are required to react with 1 mole of C11H20.
To calculate the grams of O2 required, we can use the following steps:
1. Calculate the number of moles of C11H20:
moles of C11H20 = mass of C11H20 / molar mass of C11H20
moles of C11H20 = 25.9 g / 140.28 g/mol
moles of C11H20 = 0.1847 mol
2. Calculate the number of moles of O2 required:
moles of O2 = 15 moles of O2 / 1 mole of C11H20 * 0.1847 moles of C11H20
moles of O2 = 2.7705 moles
3. Calculate the mass of O2 required:
mass of O2 = moles of O2 * molar mass of O2
mass of O2 = 2.7705 mol * 32.00 g/mol
mass of O2 = 88.97 g
Therefore, the grams of O2 required for the combustion of 25.9 g of ethylcyclopentane is 88.97 g.
871g of sodium chloride is how many moles
Answers
Answer:
14.9 mol
Explanation:
To find the number of moles in a given mass of a sample of sodium chloride (NaCl), we can multiply the number of grams in the sample by the molar mass of sodium chloride, which is 58.44 g/mol.
871 g × (1 mol / 58.44 g)
= 871/58.44 mol
≈ 14.9 mol
Note that we rounded to 3 significant figures in the final answer because that is how many significant figures were given in the mass measurement of the sodium chloride sample.
Which of the following is considered a form of technology?
Select one:
a. A line of thought used to explain logically what happened in an experiment.
b. A beaker used in an experiment.
C. A series of procedures followed in an experiment.
d. The ethical practice of considering human and animal rights in research studies.
Answers
Answer:
B. a beaker used in an experiment
Explanation:
When two butanoic acid molecules undergo a dehydration, losing water, the name of the product formed is
Answers
Answer:
What is the structure of the product from the reaction of butanoic acid and methylamine? To what class of compounds does this belong? Write a balanced chemical equation for the reaction.
Explanation:
you have two solutions of sodium chloride. one is a 2.00 m solution, the other is a 4.00 m solution. you have much more of the 4.00 m solution and you add the solutions together. which of the following could be the concentration of the final solution?
Answers
When two solutions are mixed, the concentration of the resulting solution will depend on the volumes and concentrations of the two original solutions.
The final concentration can be calculated using the following formula:
Cfinal = (C1V1 + C2V2) / (V1 + V2)
where C1 and C2 are the concentrations of the two solutions, V1 and V2 are their volumes, and Cfinal is the concentration of the final solution.
In this case, one solution has a concentration of 2.00 M, and the other has a concentration of 4.00 M. Let's assume that we have much more of the 4.00 M solution, and that we mix 100 mL of the 2.00 M solution with 400 mL of the 4.00 M solution. We can calculate the resulting concentration of the mixed solution as follows:
Cfinal = (2.00 M x 100 mL + 4.00 M x 400 mL) / (100 mL + 400 mL) = 3.20 M
Therefore, a possible concentration of the final solution is 3.20 M. The actual concentration of the mixed solution will depend on the volumes and concentrations of the original solutions used.
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