Calcule el volumen de disolución de LiOH a 3.5 M, necesario para neutralizar una disolución de 25 ml de H2SO3 cuya densidad es de 1.03 g/ml y su riqueza del 60%. (60 PTS.) Alguien puede ayudarme con esto porfabor

The titrant must be used to ensure that when added to the buret it will not be diluted with water.

As with pipettes, burettes should be rinsed with distilled water followed by the filling solution to avoid contamination problems.

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Answer:

Specific heat capacity

If the value of ΔG° is equal to 0, then the value of K or Kp is equal to 1 and the system is said to be in equilibrium.

A change in temperature occurs when heat flow increases or decreases the temperature. This changes the chemical equilibrium towards the products or the reactants. This can be identified by examining the reaction and determining whether it is an endothermic reaction or an exothermic reaction.

If the temperature is raised, the equilibrium constant decreases. If the forward reaction has an endothermic nature, the equilibrium constant increases. The equilibrium position also changes when the temperature is changed.

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Answer:

C. AlCl3 is a covalent compound.

Explanation:

It is formed by mutual sharing of electrons between two atoms each contributing equal number of electrons to the electron pair.

The pH of the buffer solution is approximately 7.001.

To calculate the pH of the buffer solution, we need to consider the Henderson-Hasselbalch equation, which relates the pH of a buffer to the pKa and the ratio of the concentrations of the acidic and basic components of the buffer.

The Henderson-Hasselbalch equation is:

pH = pKa + log ([A-]/[HA])

In this case, the acidic component is NaH2PO4 and its concentration is 0.1 mole, while the basic component is Na2HPO4 and its concentration is 0.2 moles.

First, we need to determine the ratio [A-]/[HA]. Since NaH2PO4 is a monobasic acid and Na2HPO4 is a dibasic salt, the ratio will be 2:1.

Now, let's substitute the values into the equation:

pH = 6.7 + log (0.2/0.1)

pH = 6.7 + log (2)

pH = 6.7 + 0.301

pH ≈ 7.001

Therefore, the pH of the buffer solution is approximately 7.001.

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When a substrate concentration is much greater than KM, the rate of catalysis is almost equal to Vmax. (B)

KM (Michaelis constant) is a measure of the substrate concentration at which the reaction rate is half of its maximum rate (Vmax). When the substrate concentration is much greater than KM, the enzymes are saturated with substrate and the rate of catalysis approaches Vmax.

This is because the enzymes have enough substrate to work with and the rate-limiting step is the rate of the actual chemical reaction, not the binding of substrate to the enzyme.

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C. 0.1 M barium chloride following would produce maximum elevation in boiling point

Because both the hydroxyl and carboxylic acid groups might take part in intermolecular hydrogen bonding, compound IV would have the greatest boiling point. Additionally, compound IV exhibits stronger dipole-dipole attraction due to its increased polarity (more polarized carbon-oxygen bonds).

The element with the lowest temperature at which an element would smolder is helium, while the element with the highest temperature is tungsten. The melting point is measured in degrees Celsius (C).

The most particles will be produced by BaCl2 after dissociation. Consequently, it causes the greatest rise of boiling point.

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Step 1

% by mass:

Mass of solute ---- 100 of solution

Mass of solution = mass of solute + mass of solvent = 55.0 g + 137 g = 192 g

Solute = NH4Cl

Solvent = Water (H2O)

-----------------------------

Step 2

Procedure:

55.0 g NH4Cl --------- 192 g solution

X ---------- 100 g solution

X = 29 g NH4Cl = 29 % by mass approx.

Answer: 29 % by mass

Explanation:

Abiotic factors such as rainfall, temperature, and soil conditions are the most responsible for the trend seen in the populations of large canopy trees and grass. Rainfall can affect the growth and survival of plants, and variations in temperature can influence the distribution of species. Soil conditions, such as nutrient levels and pH, can also play a role in determining which plants can thrive in a given area. Biotic factors, such as competition among plants and herbivory, can also influence the population trend of large canopy trees and grass, but these are typically driven by abiotic factors.

The trend seen in the populations of large canopy trees and grass is most likely due to abiotic factors, specifically changes in climate and temperature.

Large canopy trees typically require specific environmental conditions, such as adequate rainfall, humidity, and moderate temperatures, to thrive. As climate patterns shift and temperatures increase, these conditions may no longer be present in certain areas, which can result in a decline in the population of large canopy trees.

Similarly, grass populations are also influenced by changes in temperature and rainfall patterns. Grasses are adapted to grow in specific conditions, and as these conditions change, their populations can be impacted.

For example, prolonged drought conditions can lead to a decline in grass populations, while increased rainfall can promote growth.

While biotic factors such as competition between species and population dynamics can also influence the trend seen in the populations of large canopy trees and grass, abiotic factors are generally considered to be the primary drivers of these trends.

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Answer:

A: 92.02 g

Explanation:

Equation of the reaction;

N2 (g)+ 2O2(g)------> 2NO2(g)

Note that the balanced reaction equation is the first step in solving any problem on stoichiometry. Once the reaction equation is correct, the question can be easily solved...

The following equations to calculate the resolution, selectivity factor, and column length:

(a) Resolution = \(w_1 / (w_2 - w_1)\)

(b) Selectivity factor = \(w_1 / w_2\)

(c) Column length =\(L / (2 * pi * D / w_1)\)

(d) Time required = \(Q * L / (4 * pi * D^2 / w_1)\)

The resolution is defined as the ratio of the width of the peak for the two components to the difference in their retention times.

The selectivity factor (a) is defined as the ratio of the width of the peak for the two components to their retention times.

The length of the column (L) is the distance between the inlet and the outlet of the column.

The flow rate (Q) is the volume of the mobile phase that passes through the column per unit time.

We can start by finding the retention times of the two components, We can use the equation:

Ti = h/k

here h is the column height and k is the distribution coefficient of the component.

We can also find the width of the peak for each component, We can use the equation:

w = 2 * π * D / L

here D is the diameter of the column.

Next, we can use the following equations to calculate the resolution, selectivity factor, and column length:

(a) Resolution = \(w_1 / (w_2 - w_1)\)

(b) Selectivity factor = \(w_1 / w_2\)

(c) Column length =\(L / (2 * pi * D / w_1)\)

(d) Time required = \(Q * L / (4 * pi * D^2 / w_1)\)

We can substitute the values of the parameters we have found into these equations to solve for the values of the resolution, selectivity factor, and column length.  

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Answer:

C. 1 atm

Explanation:

More specifically it's .986 atm, but it's rounded up for this question.

Answer:

......it's letter C 1atm

It is true that For a gas-phase reaction where the temperature and the pressure remain constant, any mole ratio is equal to a volume ratio.

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Answer:

The sun.

Explanation:

:)) :) :):)) :)

Answer:

A

Explanation:

All energy originates from the sun.

Answer:

347.4 (19.3 mole)

Explanation:

CH4 + 2O2 = CO2 + 2H2O

1(mole) - 9.65(mole)

2(mole) - x ⇒x = 9.65*2=19.3

m=n*M ⇒ m= 19.3*(1*2+16)= 19.3*18=347.4(g)

Aluminum metal is produced by passing an electric current through a solution of aluminum oxide (Al2O3) dissolved in molten cryolite (Na3AlF6).  the molar masses of Al2O3 is 101.96g/mol and Na3AlF6 is 209.94g/mol.

Electric currents are streams of electrically charged particles, such as electrons or ions, moving through a conductor or a void. It is calculated as the net rate of electric charge flowing through a surface or into a control volume. 622 The moving particles are the charge carriers, which can be any of a variety of particle types depending on the conductor. Electric circuits typically use electrons flowing through a wire as charge carriers. In semiconductors, they could either be electrons or holes. In an electrolyte, ions are the charge carriers, whereas in plasma, an ionized gas, ions and electrons are the charge carriers.

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Hard water is not typically caused by the concentration of dissolved oslolum (assuming you meant "solutes") but rather by the presence of high concentrations of dissolved minerals, such as calcium and magnesium ions

The net ionic equation for the formation of calcium carbonate (CaCO3) is as follows:

Ca2+ (aq) + CO32- (aq) → CaCO3 (s)

In this equation, the calcium ions (Ca2+) from the dissolved calcium compounds in hard water react with carbonate ions (CO32-) to form insoluble calcium carbonate precipitate (CaCO3), which appears as a white solid. The precipitation occurs because the solubility product of calcium carbonate is exceeded, resulting in the formation of a solid.

The formation of a precipitate is driven by the principle of solubility. When the concentration of a dissolved compound exceeds its solubility limit, the excess ions come together and form a solid. In the case of hard water, when the concentration of calcium ions and carbonate ions surpasses their respective solubility limits, calcium carbonate precipitate forms.

Regarding the replacement of calcium ions with sodium ions, if calcium ions were replaced with sodium ions in the net ionic equation, the reaction would be different. Sodium ions (Na+) do not form insoluble compounds with carbonate ions, and sodium carbonate (Na2CO3) is soluble in water.

In summary, the formation of calcium carbonate precipitate in hard water is driven by the reaction between calcium ions and carbonate ions, leading to the exceeding of the solubility product and subsequent precipitation. If calcium ions are replaced with sodium ions, no precipitate would form as sodium carbonate remains soluble in water.

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Answer:

condensation stage is when clouds form

Answer:

the answer is 9.6853

Explanation:

I got it right

Answer:

\(MgI_{2}\)

Explanation:

To write the correct formula for magnesium iodide, we can use the periodic table to see how many valence electrons they will lose/gain. Since Magnesium will lose two electrons and Iodine will gain 1 electron, you need two Iodine for every Magnesium ion. Therefore, the formula is      \(MgI_{2}\).

Stone used for buildings, chemicals in fertilizers, and sand used to make glass are all examples of mineral resources known as industrial minerals.

These minerals are commonly used in construction, agriculture, and manufacturing processes. Fertilizers, in particular, may contain a variety of minerals and chemicals, such as nitrogen, phosphorus, and potassium, which are essential for plant growth and crop production. However, the use of fertilizers and other chemicals can also have negative environmental impacts, such as water pollution and soil degradation.

Industrial mineral is a naturally occuring mineral which has economic value.Widely used industrial minerals include limestone,clay , sand,kaoline etc

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Iron and pure nickel can be differentiate by the it appearance as well as the density.

There are few property which can differentiate iron metal and pure nickel metal.

1)The density of iron= 7.87 \(gcm^{-3}\)

The density of pure nickel = 8.91  \(gcm^{-3}\)

2)The atomic number of iron = 26

The atomic number of nickel = 28

3)Appearance of iron = silver-grey metal

Appearance of pure nickel = silver -white metal.

Therefore, pure nickel and iron can be easily differentiate with the help of appearance and dansity.

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The formula NaO,CaO represents one ionic compound and one covalent compound.

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Answer:

yes

Explanation:

every element is different. some elements have higher melting points and others have lower melting points.

Answer:

B. kilogram

Explanation:

The basic SI unit of mass is the kilogram.

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When working in the fume hood, it is important to make an effort to minimize airflow disruption, Only keep items in the hood if they are being used for experiments, Do not store chemicals in the fume hood unless instructed to do so.

When working in a fume hood, the goal is to minimize the disruption of airflow in the hood to help ensure that hazardous chemicals and fumes stay inside the hood and away from the person using it. To do this, you should only keep items in the hood that are actively being used for experiments. Do not store chemicals in the fume hood, unless you have been specifically instructed to do so by a lab supervisor or another authority figure.

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The total time required for the decay is approximately 1416.0 hours, which is closest to the given option C. 1006.9 hours.

Option (C) is correct.

To calculate the number of half-lives required for the decay. The half-life of 140 Ba is given as 283.2 hours.

First, we calculate the fraction of the original amount remaining after each half-life. Since the half-life represents the time it takes for half of the substance to decay, the fraction remaining after each half-life is 1/2.

To find the number of half-lives required to decay from 35 mg to 1.0 mg, we can set up the following equation:

(35 mg) * (1/2)ⁿ = 1.0 mg

Where 'n' is the number of half-lives.

Now, let's solve for 'n':

(1/2)ⁿ = 1.0 mg / 35 mg

(1/2)ⁿ = 0.02857

To find 'n', we can take the logarithm (base 1/2) of both sides:

n = log base 1/2 (0.02857)

Using the logarithmic property, we know that log base a (b) = log base c (b) / log base c (a):

n = log (0.02857) / log (1/2)

Using a calculator, we can find:

n ≈ 4.243

Since 'n' represents the number of half-lives, and we usually round up to the nearest whole number for half-life calculations, we get:

n ≈ 5

Therefore, it would take approximately 5 half-lives for the 35 mg sample of 140 Ba to decay to 1.0 mg.

To calculate the total time required, we multiply the half-life by the number of half-lives:

Total time = 283.2 hours * 5

Total time ≈ 1416 hours

Rounding to one decimal place, the total time required for the decay is approximately 1416.0 hours, which is closest to the given option C. 1006.9 hours.

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Answer:

combining iron, carbon and transition metals such as chromium and nickel.

Explanation:

Steels are alloys of iron and carbon. Steel is hard, tough and strong. The amount of carbon present in varies between 0.1 and 1.5% and it determines the hardness of steel. The higher the carbon content, the harder the steel produced. Also, the amount of heat treatment as well as presence of other elements determines the properties of steel produced.

Steel can be combined with other elements such as nickel, chromium, and manganese to produce various other alloys of steel . These alloys have various desirable properties than ordinary steel such as resistance to corrosion, high tensile strength and luster.

The time that is required to deposit 1.00 g of chromium metal is 30.9 mins.

Faraday's II Law of electrolysis states that if the equal quantity of energy is handed thru extraordinary electrolytes, the loads of ions deposited on the electrodes are without delay proportional to their chemical equivalents.

The chemical equation of the reaction can be represented as follows:

Cr6+ + 6e → Cr

Moles of Cr = mass / molar mass = 1 / 52 = 0.0192 mol

Moles of electrons needed = 6 * moles of Cr = 6 * 0.0192 = 0.1152 mol

Charge needed = moles of e * charge per mole of e = 0.1152 * 96485.33 = 11115.110 C

Now time needed = charge / current = 11115.110 / 6 = 1852.52 seconds = 1852.52 / 60 min = 30.9 min

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The concentration (M) of sodium ions in a 0.268 mol/L Na3P solution can be calculated by considering the stoichiometry of the compound. The concentration of sodium ions in the 4.57 L Na3P solution is 0.268 M

In this case, the concentration of Na3P is 0.268 mol/L, and the volume of the solution is given as 4.57 L. Multiplying these values together gives us the number of moles of Na3P in the solution, which is 1.225 mol. Since there are three sodium ions per molecule of Na3P, the number of moles of sodium ions is also 1.225 mol.

To find the concentration of sodium ions, we divide the number of moles of sodium ions by the volume of the solution. Therefore, the concentration of sodium ions in the 4.57 L solution is 1.225 mol / 4.57 L = 0.268 M.

In summary, the concentration of sodium ions in the 4.57 L Na3P solution is 0.268 M, obtained by considering the stoichiometry of Na3P and dividing the number of moles of sodium ions by the volume of the solution.

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