Can anyone explain how to do this?

Can Anyone Explain How To Do This?

Answers

Answer 1
Answer: 85 units ^2

Step-by-step explanation:

Using the equation \(a^{2} + b^{2} = c^{2}\)

so \(a^{2} = 35\) and \(b^{2} =50\)

\(a^{2} + b^{2} = 85^{2}\)

Answer 2

Answer:

85 units²

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

The hypotenuse is the side opposite the right angle ( third side ) , then

area = 35 + 50 = 85 units²


Related Questions

how would you change x + 3y = 18 -3x - 12y = -75 to eliminate y

Answers

Answer:  \(\bold{y=-\dfrac{1}{3}x+6}\)

                \(\bold{y=-\dfrac{1}{4}x+\dfrac{25}{4}}\)

Step-by-step explanation:

  x + 3y = 18

- x           -x

        3y = -x + 18

      ÷3     ÷3 ÷3

         y = (-1/3)x + 6

-3x - 12y = -75

+3x           +3x

        -12y = 3x - 75

       ÷-12    ÷-12 ÷-12

           y = (-1/4)x + (25/4)

The marching band sells cases of oranges and grapefruit for a fundraiser. Shakira sells 5 cases of oranges and 8 cases of grapefruit for $235. Jeff sells 3 cases of oranges and 2 cases of grapefruit for $85. How much would 1 case of each fruit cost altogether?

Answers

Answer:

Cost of 1 case of oranges is $ 15 and cost of 1 case of grapefruits is $ 20

(Cost of 1 case of oranges and 1 case of grapefruits altogether equal to \(15+20=\$35\))

Step-by-step explanation:

Let cost of 1 case of oranges be \(\$x\) and cost of 1 case of grapefruits be \(\$y\)

As  cost of 5 cases of oranges and 8 cases of grapefruit is $235,

\(5x+8y=235\)           ...(i)

As  cost of 3 cases of oranges and 2 cases of grapefruit is $85,

\(3x+2y=85\)          ...(ii)

Multiply equation (ii) by \(-4\)

\(-12x-8y=-340\)      ...(iii)

Add (i) and (iii)

\(-7x=235-340\\-7x=-105\\x=\frac{-105}{-7}\\ =15\)

Put \(x=15\) in (i)

\(5(15)+8y=235\\75+8y=235\\8y=235-75\\8y=160\\y=\frac{160}{8}=20\)

So,

Cost of 1 case of oranges is $ 15 and cost of 1 case of grapefruits is $ 20

Therefore,

Cost of 1 case of oranges and 1 case of grapefruits altogether equal to \(15+20=\$35\)

Find the value of x when: -2(3x - 5) = 52

Answers

The correct answer is x= -7

Answer:

-7

Step-by-step explanation:

-2(3x-5)=52

-6x+10=52

-6x=52-10

-6x=42

x=42/-6

x=-7

Divide. Write your answer in simplest form.
7
— /8
6

Answers

Answer:

7/64

Step-by-step explanation:

7/6÷8=7/6*1/8=7/64

Hope this helps :)

Please help! Easy question, answer pls, 15 pts.

Please help! Easy question, answer pls, 15 pts.

Answers

Answer:

360 in

Step-by-step explanation:

To figure out how many inches the dressmaker has in 10, 3 ft rolls, we can multiply by the conversion ratio:

\(\dfrac{12 \text{ in}}{1\text{ ft}} \\ \\ \text{} \ \ \implies (10 \cdot 3 \text{ ft}) \cdot \dfrac{12 \text{ in}}{1\text{ ft}} \\ \\ \text{} \ \ \implies 30 \text{ ft} \cdot \dfrac{12 \text{ in}}{1\text{ ft}} \\ \\ \text{} \ \ \implies 30\cdot 12 \text{ in} \\ \\ \text{} \ \ \implies \boxed{360 \text{ in}}\)

So, the dressmaker has 360 in of ribbon.

What is the average time it took for the tablet to dissolve in room temperature water?

ANSWER FOR 30 POINTS!!!

Answers

Answer:

It may take 20 to 30 seconds.

Step-by-step explanation: Hope this helped

brainliest?

The average time it took for a tablet to dissolve in water that was 22 °C in temperature was 28.3 seconds.

What is a drug?

Any substance that, when consumed, alters the physiology or psychology of an organism qualifies as a drug.

What are the factors that affect the solubility of drug?

The properties of the API (active pharmaceutical ingredient) such as

solubility, wettability, particle size, surface area, morphology, the formulation's composition hardness, manufacturing process.

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Chuck, a single taxpayer, earns $76,000 in taxable income and $1 in interest from an investment in city of heflin bonds. if chuck earns additional 40,000 of taxable income, what is the marginal tax rate on this income?

Answers

If chuck earns additional 40,000 of taxable income, 23.52% the marginal tax rate on this income

Chuck, a single taxpayer, earns $76,000 in taxable income and $1 in interest from an investment in city of heflin bonds.

Tax on $76,000

4,617.5 + (76,000 - 40,125) * 22% = 12,510.0

Taxable income 76,000 + 40,000 = 116,000

Tax on $116,000  

14,605.5 + (116,000 - 85,525) * 24% = 21,919.5

Marginal tax rate

(21,919.5 - 12,510) / 40,000 = 23.52%

       

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Let f(x) = 6x³ + 5x¹ - 2 Use interval notation to indicate the largest set where f is continuous. Largest set of continuity:

Answers

In interval notation, we can represent the largest set of continuity as (-∞, ∞). This means that the function is continuous for all values of x.

To determine the largest set where f is continuous, we need to consider the factors that could cause discontinuity in the function. One possible cause is a vertical asymptote, which occurs when the denominator of a fraction in the function approaches zero. However, since there are no fractions in the given function f(x), we do not need to worry about vertical asymptotes.

Another possible cause of discontinuity is a jump or a hole in the function, which occurs when the function has different values or is undefined at a specific point. To determine if there are any jumps or holes in f(x), we need to find the roots of the function by setting f(x) equal to zero and solving for x:

6x³ + 5x¹ - 2 = 0

We can factor this equation by grouping:

(2x - 1)(3x² + 3x + 2) = 0

Using the quadratic formula to solve for the roots of the second factor, we get:

x = (-3 ± sqrt(3² - 4(3)(2))) / (2(3))

x = (-3 ± sqrt(-15)) / 6

x = (-1 ± i*sqrt(5)) / 2

Since these roots are complex numbers, they do not affect the continuity of the function on the real number line. Therefore, there are no jumps or holes in f(x) and the function is continuous on the entire real number line.

In interval notation, we can represent the largest set of continuity as (-∞, ∞). This means that the function is continuous for all values of x.

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a metric ruler contains ten equally spaced increments between each labeled centimeter. when using this ruler to record the length of an object in centimeters, how many decimal places should be recorded?

Answers

When using a metric ruler with ten equally spaced increments between each labeled centimeter, the length of an object can be recorded to one decimal place.

A metric ruler is typically divided into centimeters (cm) and millimeters (mm). The ruler has ten equally spaced increments between each labeled centimeter, which means that each centimeter can be divided into ten equal parts. Each of these parts represents a millimeter, and they can be used to measure smaller lengths with more precision.

When using a metric ruler to record the length of an object in centimeters, the smallest division on the ruler that can be used to measure the length is a millimeter. The length of the object can be estimated to the nearest millimeter by aligning it with the closest division on the ruler.

To express the length of the object in centimeters, the number of millimeters must be divided by 10. The resulting value will represent the length of the object in centimeters, rounded to the nearest tenth of a centimeter. This means that the length of the object can be recorded to one decimal place.

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Graph the solution to this inequality on the number line.

−4m+3>11

Graph the solution to this inequality on the number line.4m+3>11

Answers

Move constant

Subtract numbers
-4m>11-3

Evaluate and subtract
-4m>8

Divide by -4

Solution

M<-2

Answer: The person above me is correct. Here is a picture if you still dont get it..

Step-by-step explanation:

Graph the solution to this inequality on the number line.4m+3&gt;11

find the critical valuesfind the critical values 2 f'(x)= 3 (x+4) 13

Answers

Since the second derivative is zero at x = -4, the second derivative test is inconclusive.

What are critical values ?

In mathematics, critical values refer to the values of a function where the derivative is zero or undefined. They are important because they can help us identify the maximum and minimum points of a function.

To find the critical values of the function f(x) whose derivative is

2f'(x) =  \((x + 4)^{13}\) we need to solve the equation f'(x) = 0, or equivalently,  \((x + 4)^{13}\) = 0

This equation has only one solution, which is x = -4. Therefore, the critical value of f(x) is x = -4.

To determine whether this critical value is a maximum, minimum, or neither, we need to use the second derivative test. The second derivative of f(x) is given by:

f''(x) = 39\((x + 4)^{12 }\)

Evaluating f''(-4), we get:

f''(-4) = 39(0) = 0

Therefore, Since the second derivative is zero at x = -4, the second derivative test is inconclusive.

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The Sackur-Tetrode equation gives the analytic expression for the entropy of an ideal gas, Invert this equation to obtain U(S, V, N). Derive the expression for T, p, and µ. Verify the ideal gas law pV = N kBT, where nR = N kB. (Hint: Start from U = TdS − pdV + µdN)

Answers

The inversion of the Sackur-Tetrode equation yields the expression for the internal energy U(S, V, N) of an ideal gas. By using the thermodynamic identity, expressions for temperature T, pressure p, and chemical potential µ can be derived. The ideal gas law pV = NkBT is verified through this derivation.

The Sackur-Tetrode equation for the entropy of an ideal gas is:

S = Nk [ ln (V/N (4πmU/3Nh²\()^{3/2}\)) + 5/2 ]

Inverting this equation to obtain U(S, V, N)

U = 3/2 (S/Nk - 5/2 k ln(V/N(4πm/3Nh²\()^{3/2}\))

Next, using the thermodynamic identity U = TdS − pdV + µdN, we can derive expressions for T, p, and µ:

T = (∂U/∂S)|V,N = 3/2 k[(∂S/∂S)|V,N] = 3/2 k

p = - (∂U/∂V)|S,N = NkT/V

µ = (∂U/∂N)|S,V = -5/2 kT ln(V/N(4πm/3Nh²\()^{3/2}\))

Finally, we can verify the ideal gas law pV = NkBT by substituting the expression for T into the expression for p, giving:

pV = NkT/V * V = NkT

which is consistent with pV = NkBT. Thus, we have derived the expression for U(S, V, N), as well as expressions for T, p, and µ, and verified the ideal gas law.

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On a negatively skewed curve, which of the following statements is true?
a. The mean, median, and mode is the same.
b. The mode is lower than the mean which is lower than the median.
c. The median is lower than the mode which is lower than the mean.
d. The mean is lower than the mode which is lower than the median.
e. The mean is lower than the median which is lower than the mode.

Answers

Answer:

The mean is lower than the median which is lower than the mode.

Step-by-step explanation:

Suppose IQ scores were obtained for randomly selected sets of . The pairs of measurements yield , , r , P-value 0.000, and , where x represents the IQ score of the . Find the best predicted value of given that the has an IQ of ?

Use a significance level of 0.05. 20 siblings 20 x=99.42 y=97.2 =0.867 = = −21.33+1.19x y older child y older child 97 Click the icon to view the critical values of the Pearson correlation coefficient r.1 The best predicted value of is . y (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r n 0.05 α = 0.01 α = NOTE: To test H0 : 0 against H1: 0, reject H0 if the absolute value of r is greater than the critical value in the table. rho= rho≠4 0.950 0.990 5 0.878 0.959 6 0.811 0.917

Answers

The best predicted value given that a person has an IQ of 91 is 94.03.

Here, we are given that-

sample size n = 20

sample mean for the independent value x = 100.39

sample mean for the dependent value y = 103.6

coefficient of correlation r = 0.925

The general expression for representing a linear model is given by-

y = β₀ + β₁x

where β₀ is the intercept and β₁ is the slope

For the above given case, the linear model will be given as-

y = -3.34 + 1.07x

where -3.34 is the intercept and 1.07 the slope.

To find the best predicted value when X = 91, we substitute the value of x as 91 in the equation as follows-

y = -3.34 + 1.07(91)

y = 94.03

Thus, the best predicted value given that a person has an IQ of 91 is 94.03.

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Guys, I’m back from nearly a year later went on hiatus on The Brainly because of myself as an anxiety and a very stressful year with A.D.H.D., and I really need help from my own schoolwork from my own school about, “A Perimeter Of The Composite Figures” with only 2 more perimeter questions left to go as soon as possible before it’s too late, please! :O

Please read it as soon as possible before answering to 2 of my own perimeter questions and thank you guys. :)

There’s only 55 points for you to answer to my own 2 of my own perimeter questions, guys! :D

Well good luck, guys! :D

Guys, Im back from nearly a year later went on hiatus on The Brainly because of myself as an anxiety

Answers

Answer:

  2. 26.2 m

  3. 117.2 cm

Step-by-step explanation:

You want the perimeters of two figures involving that are a composite of parts of circles and parts of rectangles.

2. Semicircular arch

The circumference of a circle is given by ...

  C = πd . . . . . where d is the diameter

The length of the semicircle of diameter 12.6 m will be ...

  1/2C = 1/2(π)(12.6 m) = 6.3π m ≈ 19.8 m

The two lighted sides of the rectangle have a total length of ...

  3.2 m + 3.2 m = 6.4 m

The length of the light string is the sum of these values:

  19.8 m + 6.4 m = 26.2 m

The length of the string of lights is about 26.2 meters.

3. Fan shape

The perimeter of the figure is the sum of four quarter-circles of radius 11.4 cm, and 4 straight edges of length 11.4 cm.

Four quarter-circles total one full circle in length, so we can use the formula for the circumference of a circle:

  C = 2πr

  C = 2π·(11.4 cm) = 22.8π cm ≈ 71.6 cm

The four straight sides total ...

  4 × 11.4 cm = 45.6 cm

The perimeter of the figure is the sum of the lengths of the curved sides and the straight sides:

  71.6 cm + 45.6 cm = 117.2 cm

The design has a perimeter of about 117.2 cm.

__

Additional comment

The bottom 12.6 m edge in the figure of problem 2 is part of the perimeter of the shape, but is not included in the length of the light string.

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Child Health and Development Studies (CHDS) has been collecting data about expectant mothers in Oakland, CA since 1959. One of the measurements taken by CHDS is the weight increase (in pounds) for expectant mothers in the second trimester. In a fictitious study, suppose that CHDS finds the average weight increase in the second trimester is 14 pounds. Suppose also that, in 2015, a random sample of 40 expectant mothers have mean weight increase of 16 pounds in the second trimester, with a standard deviation of 6 pounds. At the 5% significance level, we can conduct a one-sided T-test to see if the mean weight increase in 2015 is greater than 14 pounds. Statistical software tells us that the p-value = 0.021.Which of the following is the most appropriate conclusion?There is a 2.1% chance that a random sample of 40 expectant mothers will have a mean weight increase of 16 pounds or greater if the mean second trimester weight gain for all expectant mothers is 14 pounds.There is a 2.1% chance that mean second trimester weight gain for all expectant mothers is 14 pounds in 2015.There is a 2.1% chance that mean second trimester weight gain for all expectant mothers is 16 pounds in 2015.There is 2.1% chance that the population of expectant mothers will have a mean weight increase of 16 pounds or greater in 2015 if the mean second trimester weight gain for all expectant mothers was 14 pounds in 1959.Find the p-value for the hypothesis test. A random sample of size 50 is taken. The sample has a mean of 420 and a standard deviation of 81.H0: µ = 400Ha: µ > 400The p-value for the hypothesis test is

Answers

We accert H1 alternative that is result is population mean greater than 400.

There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.

What is standard deviation?

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the established mean.

We have given: μ = 14, x bar = 16, n = 40, s = 6,  α = 5%, = 0.05

To test μ0 : μ = 14   Vs  H1: μ > 14

Test statistics = (X bar - μx)√n / sx = (2 x 6.3245) / 6 = 2.1081

So, P value = 0.021

Conclusion: There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.

P value for the hypothesis test

n = 50, x bar = 420, sx = 81, μ = 400,

To test:  H0: μ 400    Vs   H1:  μ > 400

It is right tail test

Test statistics =  (X bar - μx)√n / sx = (420 - 400) √50 / 81 =

z = 1.7459

P value = 0.04093

Declsion: We reject H0 is p value < α

Here α = 0.05

Hence P value < α

Conclusion: We accert H1 alternative that is result is population mean greater than 400.

Hence, we accert H1 alternative that is result is population mean greater than 400.

There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.

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Four children are playing a card game. The chart shows the number of cards each child has in his or her stack.
Name Number of Cards
Chris 7
Mike 8
Sally 10
Susan 25

Which is equivalent to Mike’s portion of the total number of cards?
A.) 2/25
B.) 16%
C.) 8/25
D.) 80%
(PLEASE EXPLAIN HOW YOU GOT THIS ANSWER)

Answers

The requried equivalent to Mike’s portion of the total number of cards is 16%. Option B is correct.

What is the percentage?

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

Here,
From the given data,
Name Number of Cards

Chris      7

Mike       8

Sally       10

Susan     25
Total cards = 50

Now equivalent to Mike’s portion of the total number of cards is given as ,
= Mike cards/total card
= 8 / 50 × 100%
= 4/25×400%
= 16%

Thus, the requried equivalent to Mike’s portion of the total number of cards is 16%. Option B is correct.

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a nurse manager approves two staff nurses to attend a national conference

Answers

The nurse manager approves two staff nurses to attend a national conference.

The nurse manager has given their authorization or consent for two staff nurses to participate in and attend a national conference. This decision indicates that the nurse manager recognizes the value and relevance of the conference for professional development and sees the benefit of the staff nurses' participation. By approving their attendance, the nurse manager demonstrates support for their growth, learning, and exposure to new knowledge, experiences, and networking opportunities available at the conference.

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D Let R be the region bounded by the graph of y = 2x – 2, the horizontal line y = 2, and the vertical line x = 1. Which of the following gives the volume of the solid generated when region R is revolved about the vertical line x 1
A π∫_1^2▒〖((y+2)/2〗-1 ) ^2 dy
B π∫_0^2▒〖((y+2)/2〗-1 ) ^2 dy
C π∫_1^2▒〖(2-(2x-〗 2))^2 ^2 dy
D π∫_0^2▒〖((y+2)/2〗)^2-1^2 ) ^2 dy

Answers

The correct option is B: V = π ∫[0,2] ((y + 2)/2 - 1)^2 dy

This integral will give us the Volume of the solid generated when region R is revolved about the vertical line x = 1.

The volume of the solid generated when region R is revolved about the vertical line x = 1, we can use the method of cylindrical shells.

The formula for the volume of a solid generated by revolving a region R about a vertical line is given by:

V = 2π ∫[a,b] x * f(x) dx

In this case, since we are revolving the region R about the vertical line x = 1, the limits of integration will be from y = 2 (where the horizontal line y = 2 intersects the graph y = 2x - 2) to y = 0 (where the graph y = 2x - 2 intersects the x-axis).

Let's analyze the options provided:

A. π ∫[1,2] ((y + 2)/2 - 1)^2 dy

B. π ∫[0,2] ((y + 2)/2 - 1)^2 dy

C. π ∫[1,2] (2 - (2x - 2))^2 dy

D. π ∫[0,2] ((y + 2)/2)^2 - 1^2 dy

Option A: The limits of integration are incorrect. We need to integrate with respect to y, not x.

Option B: This appears to be the correct integral setup, integrating with respect to y and using the correct limits of integration.

Option C: This option incorrectly uses the expression (2 - (2x - 2))^2, which doesn't match the function y = 2x - 2.

Option D: The limits of integration are incorrect. We need to integrate from y = 2 to y = 0.

Therefore, the correct option is B:

V = π ∫[0,2] ((y + 2)/2 - 1)^2 dy

This integral will give us the volume of the solid generated when region R is revolved about the vertical line x = 1.

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Find the angle of the sector given the radius and the area of the sector.
Radius = 12 ft
Area of sector is 339.3 ft2

Find the angle of the sector given the radius and the area of the sector.Radius = 12 ftArea of sector

Answers

Answer:

270 degrees

Step-by-step explanation:

\(Area \: of \: the \: sector \\ \\ = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ 339.3 = \frac{ \theta}{360 \degree} \times 3.14 {(12)}^{2} \\ \\ 339.3 = \frac{ \theta}{360 \degree} \times 3.14 \times 144 \\ \\ \theta = \frac{339.3 \times 360 \degree}{3.14 \times 144} \\ \\ \theta = \frac{122,148\degree}{452.16} \\ \\ \theta= 270.143312 \degree \\ \\ \theta \approx \: 270\degree\)

mr kelly sets off a bottle rocket from the ground. the height of the rocket over time is modeled by the function h(t) = -16t^2 + 48t, where t stands for time in seconds and the height off the rocket is measured in feet.

a. find h(2). use a sentence to explain what it means in context.
b. When will the rocket hit the ground?

Answers

a) Height at 2, h(2) = 64 feet

b) The rocket will hit the ground 3 seconds after it was launched.

a. To find h(2), we simply substitute t = 2 in the given equation:

h(2) = -16\((2)^{2}\) + 48(2) = 64 feet

This means that 2 seconds after the bottle rocket was launched, it had reached a height of 64 feet.

b. We know that the rocket will hit the ground when its height h(t) equals zero. So, we need to solve the equation:

-16\(t^{2}\) + 48t = 0

We can factor out -16t to get:

-16t(t - 3) = 0

This gives us two possible solutions:

t = 0 (which corresponds to the time when the rocket was launched)

t = 3 (which corresponds to the time when the rocket hits the ground)

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A Mika rode her bike around a trail in the park.
The trail is 3 miles long. Mika rode around the
trail 4 times. How many miles did she travel in all?

Answers

Answer:

12 miles

Step-by-step explanation:

Total miles = Length of trail ×

Number of times she rode

Total miles = 3 miles × 4 times

Total miles = 12 miles

Mika traveled a total of 12 miles.

The largest number of the following number is ( _________) A. (101001)2 B. (2B)16 C. (52)s D. 50

Answers

The largest number among the given options is (101001)2, which is option D.

To determine the largest number among the given options, we need to convert each number into its decimal form and compare them.

A. (101001)2 A. (101001)2:

This number is in binary format. To convert it to decimal, we use the place value system. Starting from the rightmost digit, we assign powers of 2 to each bit. The decimal value is calculated by adding up the values of the bits multiplied by their respective powers of 2.

(101001)2 = 12^5 + 02^4 + 12^3 + 02^2 + 02^1 + 12^0

= 32 + 0 + 8 + 0 + 0 + 1

= 41

B. (2B)16 = 216^1 + 1116^0 = 32 + 11 = 43

C. (52)s: The base "s" is not specified, so we cannot determine its decimal value.

D. 50

Comparing the values we obtained:

41 < 43 < 50

Therefore, the largest number among the given options is 50, which corresponds to option D.

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Select THREE expressions equivalent to - 81x + 27.

Answers

Answer:

9(-9x+3), 27(-3x+1), -27(3x-1)

Step-by-step explanation:

If u calculate everything together u will definitely get your answer of -81x + 27

Please help me out I will give brainliest to the first correct answer

Please help me out I will give brainliest to the first correct answer

Answers

Answer:

E

Step-by-step explanation:

Have a good day :)

Please help. I need this urgently whoever can help, thank you.

Please help. I need this urgently whoever can help, thank you.

Answers

Answer:

Answered Perimeter and Area

Step-by-step explanation:

I am unsure of what you need here but here's 2 possible answers

Area

We can use composite shapes to figure out the area here (splitting one shape into more then adding up their total areas)

This shape has a rectangle with an Area of (24*30mm) but wwith a square cut out (20^2)

If we just solve we get the Area

A = (24*30) - 20^2

A = 720 - 400

A = 320mm^2

Perimeter

Perimeter is also pretty easy since we just add up side lengths.

(30 + (24*2) + (10*2) + (20*3))

(30 + 96 + 20 + 60)

= 206mm

Charlotte and Layla are workers in a factory making widgets. Layla can make 20
widgets per day in the factory. Charlotte is able to produce 10% fewer widgets per day
than Layla. How many widgets can Charlotte make per day?

Answers

Charlotte can make 18 widgets a day

If 4.3m=0.086, then find the value of m

Answers

m=0.086:4.3=0.02
M=0.02

Answer:

\(m=0.02\)

Step-by-step explanation:

\(4.3m=0.086\\m=\frac{0.086}{4.3} \\m=0.02\)


Solve for x
x = 5
x = 18
x= 30°
x = 36

Solve for xx = 5x = 18x= 30x = 36

Answers

Answer:

x=36

Step-by-step explanation:

5x=180

x=180/5=36

Answer:x=36

Step-by-step explanation:

Took the test and got it right!

Please help I'm struggling​

Please help I'm struggling

Answers

Answer:

the first is  1/5 what are the other options

Step-by-step explanation:

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