Can someone help me do 13, 14 and 15 thank u

Answer: (-2,-1)

Step-by-step explanation: First, plot the point. Then you go to the left 4 times. Then you plot your new point. Then go down 2 times. Plot your final point.

The balloons reached the same altitude after 30 seconds.

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units. 

Let's say you go to the store to buy six apples.

You are informed by the shopkeeper that he is offering 10 apples for Rs 100. In this instance, the value and the units are the price of the apples. Recognizing the units and values is crucial when using the unitary technique to a problem.

Always write the items that need to be computed on the right side and the things that are known on the left side to simplify things.

We are aware of the quantity of apples and the amount of money in the aforesaid problem.

According to our question-

Purple balloon altitude = 2.5 t+0 m = 2.5 t

Starting at a height of 15 meters above sea level, the gold balloon rose 2 meters every second.

Altitude of the gold balloon: 2 t + 15 m

Hence , The balloons reached the same altitude after 30 seconds.

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Answer:

The other side = \(\frac{1}{12}\) units

Step-by-step explanation:

A right triangle has a side of length \(\frac{1}{4}\) units and;

the hypotenuse is \(\frac{1}{3}\)

According to Pythagorean theorem,

a² + b² = c² , where a and b are the two legs of a triangle and c is the hypotenuse.

Lets say a² = \((\frac{1}{4}) ^2\)   and  c² = (\((\frac{1}{3} )^2\)

b² = c² - a²

b² = \(\frac{1}{9}\) - \(\frac{1}{16}\) = \(\frac{1}{144}\)

So b = \(\sqrt{1/144}\) = \(\frac{1}{12}\) units.

So the other side = \(\frac{1}{12}\) units.

The Probability density Function of Z is given by:
\(f_Z(z)\) = { 2z, 0 ≤ z ≤ 1   , 0  otherwise. }

To find the CDF of Z = |X - Y|, we need to consider two cases:
Case 1: z < 0

If z < 0, then P(Z < z) = 0 since Z is always non-negative.

Case 2: z ≥ 0
If z ≥ 0, then we can express the event {Z < z} in terms of X and Y as follows:
{Z < z} = {(X,Y) : |X - Y| < z}
This event corresponds to a square region in the unit square with vertices at (0,0), (1-z, z), (z,1-z), and (1,1).
The area of this square is \(1 - (1-z)^2 = 2z - z^2.\)
Since X and Y are independent and uniformly distributed in [0,1], the joint PDF of (X,Y) is fXY(x,y) = 1 for 0 ≤ x,y ≤ 1, and zero elsewhere.

Therefore, the probability of the event {Z < z} is given by the double integral:

P(Z < z) = ∫\(\int {Z < z} f_{XY}(x,y) dxdy\)

= ∫∫|x-y| < z 1 dxdy

\(= 2 \int z^0 y^z 1 dxdy\)

= 2∫\(z^0\)(z-y) dy

= z^2.

Thus, the CDF of Z is given by:

FZ(z) = P(Z ≤ z)

= 0, if z < 0

= z², if 0 ≤ z ≤ 1

= 1, if z > 1.

To find the PDF of Z, we can differentiate the CDF:

fZ(z) = d/dz FZ(z)

= 2z, if 0 ≤ z ≤ 1

= 0, otherwise.

Therefore, the PDF of Z is given by:

\(f_Z(z)\) = { 2z, 0 ≤ z ≤ 1

0, otherwise. }

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Answer:

The number is 4/9

Step-by-step explanation:

3(6*(4/9))=3*(2+(2/3))=8

Answer:

light blue

red

purple

Step-by-step explanation:

Answer:

-4/9

Step-by-step explanation:

I used a calculator.

5/6(−8/15) in simplest form is -4/9.

A fraction is written in the form of a numerator and a denominator.There are two types of fractions. One is proper fraction in which numerator is less than the denominator and another one is improper fraction in which denominator is less than the numerator.All fractions can be written in the form of p/q, where q ≠ 0 cause anything divided by 0 is undefined.

According to the given questions we have to multiply two fractions        (5/6)(-8/15) which is

= -40/90.

= -4/9.

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From the graph, the complex number with the greatest modulus is z1

From the question, we have the following parameters that can be used in our computation:

The complex numbers z1, z2, z3 and z4

The general rule of modulus of complex numbers is that

The complex number that has the greatest modulus is the complex number that is at the farthest distance from the origin

Using the above as a guide, we have the following:

From the graph, the complex number that is at the farthest distance from the origin is the complex number z1

Hence, the complex number with the greatest modulus is z1

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A ratio has two or more numbers that symbolize relation to each other. Ratios are used to compare the numbers, and you can compare them using division.

To find out what the simplest form is of the ratio 5: 2\(\frac{1}{2}\), we can divide both sides by 2\(\frac{1}{2}\).

The ratio simplified is 2: 1.

To determine the simplest form of the ration 5 : \(2\frac{1}{2}\) , we can first simplify the mixed fraction \(2\frac{1}{2\\}\)

So, \(2\frac{1}{2\\}\) = \(\frac{5}{2}\)

∴ 5 : \(2\frac{1}{2\\}\) = 5 : \(\frac{5}{2}\)

            = ( 5 x 2 ) : ( \(\frac{5}{2\\}\) x 2 )

            =  10 : 5

            =  \(\frac{10}{5}\) x \(\frac{5}{5}\)

            =  2 : 1

Hence, the simplest form of the ratio given is 2 : 1

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To find the quantity that will maximize profit, we need to first calculate the total revenue and total cost functions. Total revenue is given by the product of the price and quantity, which is p*x.

Therefore, the total revenue function is R = (700-1/2x)*x = 700x - 1/2x^2. Total cost is given by the sum of the average fixed cost and average variable cost, which is C = 400 + 2x. Therefore, total cost function is C = (400+2x)*x = 400x + 2x^2.

Next, we can find the profit function by subtracting total cost from total revenue:
P = R - C = 700x - 1/2x^2 - 400x - 2x^2 = -5/2x^2 + 300x.

To maximize profit, we need to take the first derivative of the profit function and set it equal to zero:
dP/dx = -5x + 300 = 0
x = 60

Therefore, the quantity that will maximize profit is 60 units.

To find the selling price at this optimal quantity, we can substitute x=60 into the demand function:
p = 700 - 1/2(60) = $670 per unit.

Therefore, the selling price at this optimal quantity is $670 per unit.

To find the maximum profit, we can substitute x=60 into the profit function:
P = -5/2(60)^2 + 300(60) = $12,000.

Therefore, the maximum profit is $12,000.

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Answer:

AM sorry cant help

Step-by-step explanation:

a) The 90% confidence interval for the population proportion is approximately (0.7777, 0.8423).

b) The 95% confidence interval for the population proportion is approximately (0.7737, 0.8463).

To calculate the confidence intervals for the population proportion, we can use the formula:

Confidence Interval = sample proportion ± margin of error

The margin of error can be calculated using the formula:

Margin of Error = critical value * standard error

where the critical value is determined based on the desired confidence level and the standard error is calculated as:

Standard Error = \(\sqrt{((p * (1 - p)) / n)}\)

Given that the sample proportion (p) is 0.81 and the sample size (n) is 500, we can calculate the confidence intervals.

a. 90% Confidence Interval:

To find the critical value for a 90% confidence interval, we need to determine the z-score associated with the desired confidence level. The z-score can be found using a standard normal distribution table or calculator. For a 90% confidence level, the critical value is approximately 1.645.

Margin of Error = \(1.645 * \sqrt{(0.81 * (1 - 0.81)) / 500)}\)

≈ 0.0323

Confidence Interval = 0.81 ± 0.0323

≈ (0.7777, 0.8423)

Therefore, the 90% confidence interval for the population proportion is approximately (0.7777, 0.8423).

b. 95% Confidence Interval:

For a 95% confidence level, the critical value is approximately 1.96.

Margin of Error = \(1.96 * \sqrt{(0.81 * (1 - 0.81)) / 500)}\)

≈ 0.0363

Confidence Interval = 0.81 ± 0.0363

≈ (0.7737, 0.8463)

Thus, the 95% confidence interval for the population proportion is approximately (0.7737, 0.8463).

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Therefore , the solution of the given problem of equation comes out to be k1 = - 0.67 and k2 = -0.1.

A mathematical equation is a formula that joins two statements and uses the equal symbol (=) to indicate equality. A scientific statement that verifies the equality of two formalisms is known as an equation in algebra. For instance, the pieces ptdc + 6 and 12 are separated by an equal sign in the solution obd + 6 = 12. The relationship between the two phrases on either flank of a letter is described by a mathematical formula. Often, there is only one variable, which also serves as the symbol. for instance, 4x – 4 = 0.

Here,

If y varies in this case simply also as square of x

k is the proportionality constant, and

y = kx² in mathematics.

Considering y = -54 and x = 9,

y = kx²

k = y/ x²

k = -54/ 9²

k = -54/81

k1 = - 0.67

Moreover, if y=-11/3 and x=6,

k = y/x²

k = -3.667/ (6)²

k = -3.667/36

k2 = -0.1

Therefore , the solution of the given problem of equation comes out to be k1 = - 0.67 and k2 = -0.1.

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Answer:

not enough info, make another question with the problem attached

Step-by-step explanation:

Answer:

Step-by-step explanation:

In this scenario, you are given a point and the equations of two lines, and you are asked for the point on each line nearest to the given point.

There are several ways you could approach this. Perhaps the most straightforward is to write the equation of the perpendicular line through the given point, then solve the system of equations for the point of intersection between the given line and its perpendicular.

We note that you are asked to use the desmos graphing tool. That tool simplifies a lot of this effort. It easily graphs the equations, and it tells you the points at which the lines intersect.

Exit from Hwy 2

The equation for Hwy 2 is y=2x+5. This is in slope-intercept form. The slope is the coefficient of x, which is 2. The perpendicular line will have a slope that is the opposite reciprocal of this: -1/2. That means we can write the point-slope equation of the line from the Hwy 2 exit to the park in point-slope form as ...

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -4 = -1/2(x -3) . . . . line with slope -1/2 through point (4, 3), the park

Desmos will plot this equation and show us the point of intersection with Hwy 2. The exit from Hwy 2 is located at (0.2, 5.4).

Exit from Hwy 10

The equation for Hwy 10 is y=-0.5x+2. This has slope -0.5, so its perpendicular has slope -1/-0.5 = 2. The equation of the line from the Hwy 10 exit to the park is ...

  y -4 = 2(x -3)

Desmos shows the Hwy 10 exit location to be (1.6, 1.2).

_____

The two highways in Scenario 1 are perpendicular to each other. The equations for the exit routes are perpendicular to those. This means the four equations of Scenario 1 are four equations that create lines that form a figure with right angles.

As it happens, the distance from each exit to the park is the same, so the rectangle formed is a square. None of these lines is aligned with the grid.

Effectively, the equations of Scenario 1 are a solution to Scenario 2.

Just for consistency, we can write each equation in standard form.

Hwy 2: y = 2x+5  ⇒  2x -y = -5

Exit from Hwy 2: y -4 = -1/2(x -3)  ⇒  2y -8 = -x +3  ⇒  x +2y = 11

Hwy 10: y = -0.5x +2  ⇒  2y = -x +4  ⇒  x +2y = 4

Exit from Hwy 10: y -4 = 2(x -3)  ⇒  y -4 = 2x -6  ⇒  2x -y = 2

__

The distance from Exit 2 to the park is ...

  d = √((x2 -x1)² +(y2 -y1)²) = √((0.2 -3)² +(5.4 -4)²) = √((-2.8)² +1.4²) = √9.8

The distance from Exit 10 to the park is ...

  d = √((1.6 -3)² +(1.2 -4)²) = √((-1.4)² +(-2.8)²) = √9.8

Adjacent sides of the rectangle are the same length, so the rectangle is a square.

Answer:

312

Step-by-step explanation:

First we need to determine the width

A = l*w

6.2 * 10 ^3 = 1.55 * 10 ^2 * w

Divide each side by 1.55 * 10 ^2

6.2 ^ 10 ^3  /1.55 * 10 ^2 = 1.55 * 10 ^2 * w / 1.55 * 10 ^2

Changing from scientific notation to standard

6200/155 = w

40 = w

Then we need to determine the perimeter

P = 2(l+w)

P = 2( 155+40)

P =2( 195)

P = 390

Now multiply by the price

390 *.80

312

For any price of h and k = -12, the system x + 3y = h and -4x + ky = -9 will haven't any answer.

To determine the values of h and okay for which the device of equations has no answer, we want to locate the situations underneath which the equations are inconsistent or parallel.

The given system of equations is:

Equation 1: x + 3y = h

Equation 2: -4x + ky = -9

For the gadget to haven't any answer, the lines represented with the aid of these equations should be parallel and in no way intersect. In different phrases, the slopes of the traces need to be equal, but the y-intercepts should be specific.

Let's first discover the slopes of the traces. The slope-intercept form of Equation 1 is y = (-1/3)x + (h/3), wherein the slope is -1/3. The slope-intercept shape of Equation 2 is y = (4/k)x - (9/k), wherein the slope is 4/k.

For the strains to be parallel, the slopes should be equal. Therefore, we have the condition: -1/3 = 4/k.

To locate the values of h and okay for which the gadget has no answer, we need to locate the values of h that satisfy the situation -1/3 = 4/k.

Solving this equation for ok, we've got:

-1/3 = 4/k

-1 = 12/k

k = -12

Substituting k = -12 returned into the equation -1/3 = 4/k, we've:

-1/3 = 4/(-12)

-1/3 = -1/3

Since the equation holds real for any value of h, there aren't any restrictions at the price of h.

Therefore, for any price of h and k = -12, the system x + 3y = h and -4x + ky = -9 will haven't any answer.

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The system of equations has no solution when k is equal to 12. The value of h can be any real number.

To determine the values of h and f for which the system has no solution, we need to analyze the coefficients of the variables and the constants in the equations.

The given system of equations is:

x + 3y = h

-4x + ky = -9

We can rewrite the second equation as:

-4x + ky = -9

Dividing both sides of the equation by -4, we get:

x - (k/4)y = 9/4

Comparing the coefficients of x and y in the two equations, we can see that the slopes of the lines represented by the equations are different when k is not equal to 12.

Therefore, for the system to have no solution, k must be equal to 12.

As for the value of h, it can be any real number since it does not affect the slopes of the lines.

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Answer:

she profited $35

Step-by-step explanation:

Answer:

The answer is \(3^3\times 2^2\).

Step-by-step explanation:

According to the rules of exponents

a^n = a x a x a x .... n times

So,

\(3^{2}\times (2^{3}+4)\\\\=9\times (8 +4)\\\\=108\\\\=3^{3}\times 2^{2}\)

Answer:

  24 feet

Step-by-step explanation:

Let w represent the width of the rectangle. Then its length is 2w, and its area is ...

  A = Lw

  32 = (2w)(w) = 2w^2 . . . fill in the given values

  16 = w^2 . . . . . . . . . . . . divide by 2

  4 = w . . . . . . . . . . . . . . take the square root

  8 = 2w = L . . . . . . . . . find the length

The dimensions of the yard are 8 feet long and 4 feet wide.

__

The perimeter is ...

  P = 2(L +w) = 2(8 +4) = 2(12) = 24 . . . . feet

The perimeter of the rectangular back yard is 24 feet.

Answer: \(y=-\frac{7}{2}x+7\)

Step-by-step explanation:

The slope of the line is \(\frac{7-0}{0-2}=-\frac{7}{2}\).

So, since the y-intercept is 7, the equation is \(y=-\frac{7}{2}x+7\).

Using strong induction, we can prove that the square root of -2 is irrational by showing that it cannot be expressed as a fraction of coprime odd integers.

To prove that √-2 is irrational using strong induction, we need to show that for any natural number n, if the square root of -2 can be expressed as a fraction a/b, where a and b are coprime integers, then a and b must be odd.

We can start by using the base case, n = 1. Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers.

Now, let's assume that for all n ≤ k, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. We want to prove that this also holds for n = k+1.

Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers with a and b odd. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd.

By strong induction, we have proven that for any natural number n, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Therefore, √-2 is irrational.

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The required points (x ,y ) for the curve x = 6t² + 5 , y = t³ -7  has slope 1/2  are ( 29,1).

Slope of the tangent line to the curve = dy/dx

dy/dx = ( dy / dt ) × ( dt / dx )  __(1)

y = t³ -7

⇒ dy /dt = 3t²

x = 6t² + 5

⇒ dx / dt = 12t

Now substitute the value of dy/dt and dx/dt in (1) we get,

dy / dx = 3t² / 12t

⇒ dy /dx = t /4

Slope (dy /dx ) = 1 /2

⇒ t /4 = 1 /2

⇒ t = 2

Point ( x , y ) = ( 6(2)² + 5 , 2³ -7 )

                    = ( 29, 1 )

Therefore, the points (x ,y ) for the curve with tangent line to the curve has slope 1/2 is equal to ( 29, 1) .

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For circular motion on a circle of radius r, linear speed equals angular speed divided by r. This statement is false.

What is angular speed?

The definition of angular speed is the rate at which angular displacement changes, and it is written as follows -

ω = θ/t

where θ is the angular displacement, t is the time and ω is the angular speed.

The statement says that for circular motion on a circle of radius r, linear speed equals angular speed divided by r.

Consider that an object moves around a circle of radius r at a constant speed v.

If s is the distance travelled in time t around the circle then linear speed v is defined as v = s/t.

Also if θ is the angle swept out by this object in time t then the angular speed is defined as ω = θ/t.

Thus, there is some relationship between linear speed and angular speed -

Linear speed = v = s/t

= rθ/t = r(θ/t) = rω

where is ω measured in radians per unit time and for a circle of radius r, a central angle of radians subtends an arc whose length s is s = rθ.

Hence, notice that linear speed is equal angular speed multiplied, not divided, by r.

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The area in the first quadrant between the given circles is 2π.

The given equation of circles are:

x²+y²=16,

x²+y²=16,

x²−4x+y²=0

To evaluate the integral, we'll need to convert the equations into polar coordinates.

The first circle, x² + y² = 16.

In polar coordinates,

x = rcosθ

y = rsinθ.

Substituting these into the equation,

we get r²cos²θ + r²sin²θ = 16.

Simplifying this equation, we have r² = 16,

which simplifies further to r = 4.

The second circle, x² - 4x + y² = 0.

Converting this into polar coordinates, we have

(rcosθ)² - 4(rcosθ) + (rsinθ)² = 0.

Simplifying this equation, we get

r² - 4rcosθ = 0,

Which leads to r = 4cosθ.

To find the area in the first quadrant between these two circles,

Integrate the area element dA over the given region.

The area element in polar coordinates is given by

dA = 1/2 (r² dθ).

Now, set up the integral to evaluate the area:

\(A = \int\limits^{\frac{\pi}{2}}_0 {(\frac{1}{2} r^2)} \, d\theta\\ =\frac{1}{2} \int\limits^{\frac{\pi}{2}}_0 {4cos^2\theta} \, d\theta \\= 8 \int\limits^{\frac{\pi}{2}}_0 {cos^2\theta} \, d\theta\)

Using trigonometric identities,

We can simplify this integral further:

\(= 8 \int\limits^{\frac{\pi}{2}}_0 {(1+cos2\theta)/2} \, d\theta\)                                 [∵ cos2θ = 2cos²θ - 1]

= (1/2) [(8(π/2) + 4sin(2(π/2))) - (8(0) + 4sin(2(0)))]

= (1/2) [(4π + 0) - (0 + 0)]

= 2π

Hence,

The area in the first quadrant between the given circles is 2π.

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Given that ABCD is a rhombus, the value of x is 29. Option A

A rhombus is a parallelogram having four equal sides and, occasionally, one without any right angles.

A rhombus's diagonals are perpendicular to each other.

sum the equation to 180

x + 3x -26 + 90 = 180

4x = 180 - 90 + 26

4x = 116

We have to divide through the equation by 4 in order to get the value of x

4x / 4  = 116 / 4

x = 29

Hence the value of x in the given rhombus is 29

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Answer:29 is the answer

Step-by-step explanation:

The area of the polygon is 12 square units.  In mathematics and everyday life, an estimate is an approximate calculation or guess that is close to the actual value but may not be exact.

To make an estimate or guess, you can square off the parallelogram and create a rectangle and add your squares (or multiply 3x4) to = 12": This part explains a method for estimating the area of a parallelogram. It suggests that if you take a parallelogram and "square it off" (convert it into a rectangle by drawing a perpendicular line), you can then find the area of the rectangle, which is easier to calculate. In this case, the dimensions of the rectangle are given as 3 units for the base and 4 units for the height, and the estimated area is 12 square units.

You can use the formula for the exact area using base x height (3x4) you get the same answer of 12 square units": This part emphasizes that the estimation method used in step 2 (multiplying 3 by 4) produces the same result as the exact formula for finding the area of a parallelogram, which is base times height. In this case, both the estimation and the formula give an area of 12 square units.

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