can someone help me with this please and explain because i’m confused :)) thanks!

Can Someone Help Me With This Please And Explain Because Im Confused :)) Thanks!

Answers

Answer 1

Answer: 0.2121...=7/33     ≈943 hits

Step-by-step explanation:

a.

\(99n=100n-n\\\)

Divide both parts of the equation by 99:

\(\displaystyle\\n=\frac{100n-n}{99} \\\\n=\frac{100*0.2121...-0.2121...}{99} \\\\n=\frac{21.2121...-0.2121...}{99}\\\\n=\frac{21}{99} \\\\n=\frac{7*3}{33*3}\\\\n=\frac{7}{33}\)

b.

\(\displaystyle\\200:\frac{7}{33}=\\\\200*\frac{33}{7} =\\\\\frac{200*33}{7}=\\\\\frac{6600}{7}=\\\\ \approx943\)


Related Questions

GIVING 35 POINTS PLEASE i REALLY NEED HELP WITH THIS PROBLEM PLEASE!!!!!
what is the result of dividing x^3-2x^2-31x-28 by x-7?

A)x^2+5x-4

B)x^2-9x-4

C)x^2-9x+4

D)x^2+5x+4

Answers

my man your answer is b

srry if im wrong

Man I think the answer is D correct if I’m wrong tho

I need help with this math question!!!

I need help with this math question!!!

Answers

Answer:

4.6%

Step-by-step explanation:

50 = 2.3

100 = 4.6%

whats the height of the prism
if you can help me with is question it would mean a lot :) im having some trouble figuring it out

Iready

whats the height of the prismif you can help me with is question it would mean a lot :) im having some

Answers

Answer:

The height of the prism = 3cm

Step-by-step explanation:

Answer:3

Step-by-step explanation:

subtract (2x^2-3x+5)-(3x^2-4x+7)

Answers

Answer:

−x^2+x−2

Step-by-step explanation:

The answer is -x^2 + x - 2

1.)3(x+2)=15
2.)2(x+5)=24
3.)6(x-9)=12
4.)2(3x+5)= -44
5.)5(4x-3)=11
6.)-3(2x+1)=21
7.)-9(x -4)=54
8.)7(x-4)-3=46
9.)2(3x-1)+3=21
10.)2(x+1)+3x=37
11.)12+4(2x+4)=68
12.)3x-2(6x-3)=42

Answers

The solution to the Equations is    x = 3, x = 7, x = 11,  x = -9,  x = 1.3,               x = -4, x = -4,x = -2,x = 11, x = 3.33,x = 7, x = 5,x = -4.

1. To solve 3(x+2)=15, we first distribute the 3 and get 3x + 6 = 15. Then, we subtract 6 from both sides and get 3x = 9. Finally, we divide both sides by 3 and get x = 3.

2. To solve 2(x+5)=24, we first distribute the 2 and get 2x + 10 = 24. Then, we subtract 10 from both sides and get 2x = 14. Finally, we divide both sides by 2 and get x = 7.

3. To solve 6(x-9)=12, we first distribute the 6 and get 6x - 54 = 12. Then, we add 54 to both sides and get 6x = 66. Finally, we divide both sides by 6 and get x = 11.

4. To solve 2(3x+5)= -44, we first distribute the 2 and get 6x + 10 = -44. Then, we subtract 10 from both sides and get 6x = -54. Finally, we divide both sides by 6 and get x = -9.

5. To solve 5(4x-3)=11, we first distribute the 5 and get 20x - 15 = 11. Then, we add 15 to both sides and get 20x = 26. Finally, we divide both sides by 20 and get x = 1.3.

6. To solve -3(2x+1)=21, we first distribute the -3 and get -6x - 3 = 21. Then, we add 3 to both sides and get -6x = 24. Finally, we divide both sides by -6 and get x = -4.

7. To solve -9(x-4)=54, we first distribute the -9 and get -9x + 36 = 54. Then, we subtract 36 from both sides and get -9x = 18. Finally, we divide both sides by -9 and get x = -2.

8. To solve 7(x-4)-3=46, we first distribute the 7 and get 7x - 28 - 3 = 46. Then, we combine like terms and get 7x - 31 = 46. Then, we add 31 to both sides and get 7x = 77. Finally, we divide both sides by 7 and get x = 11.

9. To solve 2(3x-1)+3=21, we first distribute the 2 and get 6x - 2 + 3 = 21. Then, we combine like terms and get 6x + 1 = 21. Then, we subtract 1 from both sides and get 6x = 20. Finally, we divide both sides by 6 and get x = 3.33.

10. To solve 2(x+1)+3x=37, we first distribute the 2 and get 2x + 2 + 3x = 37. Then, we combine like terms and get 5x + 2 = 37. Then, we subtract 2 from both sides and get 5x = 35. Finally, we divide both sides by 5 and get x = 7.

11. To solve 12+4(2x+4)=68, we first distribute the 4 and get 12 + 8x + 16 = 68. Then, we combine like terms  x = 5.

12.To solve 3x - 2(6x - 3) = 42, we first distribute the -2 and get:3x - 12x + 6 = 42,9x + 6 = 42Then, we subtract 6 from both sides:-9x = 36Finally, we divide both sides by -9 and get:x = -4Therefore, the solution to the equation is x = -4.

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The solution to the algebraic expressions are:

1. x = 3

2. x = 7

3. x = 13

4. x = -9

5. x = 1.3

6. x = -4

7. x = -2

8. x = 11

9. x = 10/3

10. x = 5

11. x = 5

12. x = -4

How to solve Algebra Expressions?

1. 3(x + 2) = 15,

Using distributive property, we get 3x + 6 = 15.

3x = 9

x = 9/3

x = 3

2. 2(x + 5) = 24

Using distributive property, we get:

2x + 10 = 24

2x = 14

x = 7

3. 6(x - 9) = 12

Using distributive property, we get:

6x - 54 = 24

6x = 78

x = 78/6

x = 13

4. 2(3x + 5) = -44

Using distributive property, we get:

6x + 10 = -44

6x = -54

x = -9

5. 5(4x - 3) = 11

Using distributive property, we get:

20x - 15 = 11

20x = 26

x = 1.3

6. -3(2x + 1) = 21

-6x - 3 = 21

-6x = 24

x = -4

7. -9(x - 4) = 54

Using distributive property, we get:

-9x + 36 = 54

-9x = 54 - 36

-9x = 18

x = -2

8. 7(x - 4) - 3 = 46

Using distributive property, we get:

7x - 28 - 3 = 46

7x = 77

x = 11

9) 2(3x - 1) + 3 = 21

Using distributive property, we get:

6x - 2 + 3 = 21

6x = 20

x = 20/6

x = 10/3

10) 2(x + 1) + 3x = 37

2x + 2 + 3x = 37

5x = 35

x = 5

11) 12 + 4(2x + 4) = 68

12 + 8x + 16 = 68

8x = 40

x = 5

12) 3x - 2(6x - 3) = 42

3x - 12x + 6 = 42

6 - 9x = 42

9x = -36

x = -36/9

x = -4

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When you flatten a spherical meatball into a hamburger do you increase its volume or surface area?

Answers

when you flatten a spherical meatball into a hamburger, you increase its surface area while keeping the volume constant.

A sphere is a three-dimensional shape that has a curved surface. When you flatten a spherical meatball into a hamburger, you are essentially reshaping it into a flat, disk-like form. By doing so, you increase the area that is in contact with the cooking surface, such as a pan or grill. This larger surface area allows for more even cooking and browning.

However, the total amount of meat remains the same when you flatten the meatball. The volume of an object refers to the amount of space it occupies, and since the meatball is being flattened without adding or removing any meat, the volume remains constant. In other words, the flattened hamburger will have a larger surface area but the same amount of meat as the original spherical meatball.

So, when you flatten a spherical meatball into a hamburger, you increase its surface area while keeping the volume constant.

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When you flatten a spherical meatball into a hamburger, you decrease its volume and increase its surface area.

When a spherical meatball is flattened into a hamburger, its shape changes from a sphere to a flat disk. This transformation affects both the volume and surface area of the meatball.

The volume of a sphere is given by the formula V = (4/3)πr^3, where r is the radius of the sphere. The surface area of a sphere is given by the formula A = 4πr^2.

On the other hand, the volume of a disk (or a circle) is given by the formula V = πr^2, where r is the radius of the disk. The surface area of a disk is given by the formula A = 2πr.

When the meatball is flattened, its radius decreases, resulting in a smaller volume. The volume of the flattened meatball is less than the volume of the original spherical meatball.

However, the surface area of the flattened meatball increases. The surface area of the flattened meatball is greater than the surface area of the original spherical meatball.

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If
LN
and
OQ
are parallel lines and mQPR = 115°, what is mLMP?

If LN and OQ are parallel lines and mQPR = 115, what is mLMP?

Answers

The measurement of angle ∠LMP is 65° when angle QPR is 115°.

What is corresponding angle ?

Any pair of angles that lie on opposite sides of two lines cut by a transversal on the same side.

Here, it is given that LN and OQ are parallel lines and ∠QPR = 115°

First, let us find the measurement of angle QPM as angle QPR and angle QPM are supplementary angles that is there sum will be 180° :

∠QPM + QPR = 180°

∠QPM + 115° =  180°

∠QPM = 180° - 115°  

∠QPM = 65°

Now, angle QPM and angle LMP are corresponding angles there the measurement of both the angles will be same that is ;

∠QPM = ∠LMP = 65°

Therefore, the measurement of angle ∠LMP is 65°

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Use the given conditions to write an equation for the line in standard form Passing through (-6,-2) and parallel to the line whose equation is y - 6 = 1/2 (x-3) Write an equation for the line in standard form. (Type your answer in standard form, using integer coefficients with A≥0.)

Answers

Hello !

Answer:

\(\Large \boxed{\sf x-2y=-2}\)

Step-by-step explanation:

- The slope-intercept form of a line is of the form y=mx+b where m is the slope and b is the y-intercept.

- The standard form is Ax+By=C where A,B and C are integers.

We know that the line :

is parallel to the line whose equation is \(\sf y-6=\frac{1}{2}(x-3)\)passes through (-6,-2)

Let's put \(\sf y-6=\frac{1}{2}(x-3)\) in the slope-intercept form.

Expand right side :

\(\sf y-6=\frac{1}{2}x-\frac{3}{2}\)

Add 6 to both sides to isolate y :

\(\sf y=\frac{1}{2} x+\frac{9}{2}\)

The two lines are parallel and therefore have the same slope : \(\sf \frac{1}{2}\)

We have \(\sf y=\frac{1}{2} x+b\).

We know that the lines passes through (-6,-2).

Let's replace x and y with -6 and -2 and solve for b :

\(\sf -2=\frac{1}{2} (-6)+b\\\iff -2=-3+b\\ \iff b=1\)

The slope-intercept form our line is \(\sf y=\frac{1}{2} x+1\).

Let's put it into standard form :

Multiply both sides by 2 :

\(\sf 2y=x+2\)

Substract 2y from both sides :

\(\sf 0=x-2y+2\)

Finally, substract 2 from both sides :

\(\boxed{\sf x-2y=-2}\)

Have a nice day ;)

Write a subtraction expression that involves two negative integers and has a positive answer.

Answers

Answer:

Here is one :)

x - 12  =  - 8

Write 6 square root squared in the form square root a where a is an integer to be found.

Answers

Answer:

Step-by-step explanation:

−−−√2

We know that −a=−1.a

⟹−1.6−−−−√2

Apply ab−−√c=a−−√cb√c

−1−−−√26–√2

Remember that −1−−−√=i

i26–√2

Apply x−−√2=|x|

|6|i2=6i2

Use i2=−1

⟹−6

f(x)= {x+4 if x<5
{8 if 5 < or equal to x<7
{2x-1 if 7 < or equal to x < or equal to 10

for f(x), evaluate the following:
A. f(0)
B. f(6)
show all of your work.​

Answers

Answer:

  A.  f(0) = 4

  B.  f(6) = 8

Step-by-step explanation:

When evaluating a piecewise function, the fist step is to determine the applicable domain. Then the function defined for that domain is the one that is used for the evaluation.

A.

x = 0 is in the domain x < 5, so the applicable function is f(x) = x+4.

  f(0) = 0 +4 = 4

__

B.

x = 6 is in the domain 5 ≤ x < 7, so the applicable function is f(x) = 8.

  f(6) = 8

A point on the ocean floor is 7,842 m below sea level.

Express this elevation as an integer.

The elevation as an integer is □m

Answers

Answer:

-7842 meters

Step-by-step explanation:

Since the point is below sea level, it is negative

-7842 meters

You have now invested some money in your bank account with an interest rate of 5% every year. At year 3 , you will find out that you have $30,000 in your bank account. How much money will you have in your bank account at year 2?

a. $25,915.13
b. $27,210.88
c. $28,571.43
d. $30,000.00
e. None of the above

Answers

At year 2, you will have approximately $25,915.13 in your bank account, assuming an initial investment with a 5% interest rate compounded annually. The correct answer is (a).


To find out how much money you will have in your bank account at year 2, we can use the compound interest formula:
A = P(1 + r/n)^(nt)
Where:
A = Final amount (in this case, $30,000)
P = Principal amount (initial investment)
R = Annual interest rate (5% or 0.05)
N = Number of times interest is compounded per year (assumed to be once per year)
T = Number of years (in this case, 3)
Let’s solve for P, the principal amount at year 0:
30,000 = P(1 + 0.05/1)^(1*3)
30,000 = P(1.05)^3
Dividing both sides of the equation by (1.05)^3:
P = 30,000 / (1.05)^3
P ≈ 25,915.13
Therefore, at year 2, you will have approximately $25,915.13 in your bank account.
The correct answer is (a) $25,915.13.

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Is 9/25 a whole number

Answers

No it isn’t a whole number

Answer:

no i dont think so

Step-by-step explanation:

the end of each 15 years. If the annual maintenance required is P5,000, find the capitalized cost, if money is worth 5% and the salvage value is P50,000. First Cost Present worth of the annual maintenance cost *Letters only Perpetuity of the depreciation cost a. 178,700 b. 231,700 c. 321,500 d. 400,500 e. 127,700 Capitalized cost a. 372,700

b. 441,700

c. 529,500

d.

Answers

Capitalized cost is the present worth of equipment's purchase and installation costs at an interest rate, deducted from the machine's estimated useful life value. It is calculated using the perpetuity concept, dividing periodic cash flow by interest rate. The capitalized cost is P758,030, calculated by dividing initial cost, annual maintenance, and depreciation costs by 15 years of machine life.

Capitalized Cost:It is defined as the present worth of the actual cost incurred for the purchase and installation of equipment at an interest rate. The amount is then deducted from the amount that could be received by selling the machine at the end of the estimated useful life. The capitalized cost of a piece of equipment is the sum of its purchase price, installation cost, and any other capital costs that are necessary to get the equipment operational.Content loaded at the end of each 15 years, and the annual maintenance required is P5,000. The salvage value is P50,000, and the worth of money is 5%.The value of the machine is calculated by calculating the capitalization of the machine.The capitalized cost is the sum of the present value of the initial cost, the annual maintenance cost, and the present value of the depreciation cost using the perpetuity concept.Whereas, the perpetuity concept states that the periodic payment or receipts are identical, it's possible to calculate the value of an investment by dividing the periodic cash flow by the interest rate.Hence, the capitalized cost is calculated as follows:

Annual depreciation = (Initial cost - Salvage value) / Number of years of machine lifeAnnual depreciation

= (500,000 - 50,000) / 15

Annual depreciation = 30,000 per

annum Capitalized cost = Present worth of initial cost + Present worth of annual maintenance cost + Present worth of the depreciation cost

Present worth of the initial cost = 500,000 x 0.216 = 108,000

Present worth of the annual maintenance cost = 5,000 x 10.006 = 50,030

Present worth of the depreciation cost = 30,000 / 0.05 = 600,000

Capitalized cost = 108,000 + 50,030 + 600,000

Capitalized cost = P758,030Therefore, the capitalized cost is P758,030. The correct option is not provided, which could be obtained by comparing the calculated capitalized cost values to the available options.

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Determine if the sequence is arithmetic. If it is, find the common difference.
1) 35, 32, 29, 26, ...
2) -3, -23, -43, -63, ...

Answers

Answer:

1) Arithmetic since it decreases by 3 so, -3n + 38.

2) Arithmetic since it decreases by 20 each time, so -20n+17

Step-by-step explanation:

What is the slope of the following? y = -6x + 1

Answers

Answer:

-6

Step-by-step explanation:

14.9+1/3(-12 -27x) - 33.2
x=-3

Answers

Answer:

4.7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Step-by-step explanation:

Step 1: Define

14.9 + 1/3(-12 - 27x) - 33.2

x = -3

Step 2: Evaluate

Substitute in x:                    14.9 + 1/3(-12 - 27(-3)) - 33.2Multiply:                               14.9 + 1/3(-12 + 81) - 33.2Add:                                     14.9 + 1/3(69) - 33.2Multiply:                               14.9 + 23 - 33.2Add:                                     37.9 - 33.2Subtract:                              4.7

Frame zero, F0. is the fixed global frame. For each of
the cases below find T 1: 0
(a) F1 is rotated by an angle θ about zo.
(b) F1 is rotated by θ about xo.
(c) F1 is rotated by θ about yo.

Answers

(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`

(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`

(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`

Given that Frame zero, F0 is the fixed global frame.

For each of the cases below find T1

Case (a)

F1 is rotated by an angle θ about zo.

Let O be the origin of the fixed frame F0, A be the origin of the frame F1 and α be the angle between the x-axis of the frame F0 and the projection of the x-axis of the frame F1 on the xy plane of the frame F0.

Let l, m, n be the direction cosines of the vector from O to A, expressed in F0.

The content-loaded frame zero F0 is the fixed global frame, which means that the vectors i, j, k representing the x, y, and z-axis of F0 are fixed and cannot be transformed.

Therefore, the transformation matrix T1:0

in this case is:

`T1:0 = [l1 m1 n1 0; l2 m2 n2 0; l3 m3 n3 0; 0 0 0 1]`

Case (b)

F1 is rotated by θ about xo.

Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.

Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.

The transformation matrix T1:0

in this case is given by:

`T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`

Case (c)

F1 is rotated by θ about yo.

Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.

Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.

The transformation matrix T1:0

in this case is given by:

`T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`

Thus, the transformation matrix T1:0

for the three cases (a), (b), and (c) are given as follows:

(a) `T1:0 = [cosθ sinθ 0 0; -sinθ cosθ 0 0; 0 0 1 0; 0 0 0 1]`

(b) `T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`

(c) `T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`

Given θ = 150,

T1:0 for the three cases are:

(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`

(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`

(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`

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Kate is a buyer for a men’s fashion retail store. She will order a new cloth overcoat from Paris for the fall fashion season. Based on her experience, she expects to sell at least 100 coats, and at most 400, but she feels that any number of sales in between is equally likely. Therefore, she estimates that her sales are uniformly distributed between 100 and 400. The total cost to the store is $100 per coat, and the retail price is set at $180. Any coats left over at the end of season would be sold at $60 each.
part 1: a) How many coats should Kate buy if she wants to maximize profits?
part 2: b) Assume Kate buys the number of coats suggested in part a), what is the probability that the coats sell out? What is the probability that they do not sell out?

Answers

Part 1: Kate should buy 100 coats to maximize profits.Part 2: The probability that the coats sell out is 0.25 (25%), and the probability that they do not sell out is 0.75 (75%).

To maximize profits, Kate should consider the scenario where she sells all the coats without any left over at the end of the season.

Since the sales are uniformly distributed between 100 and 400, buying 100 coats ensures that she meets the minimum expected sales of 100. Purchasing more than 100 coats would increase costs without a guarantee of higher sales, potentially leading to excess inventory and lower profits.

Given that the sales are uniformly distributed between 100 and 400 coats, Kate's purchase of 100 coats covers the minimum expected sales.

The probability of selling out can be calculated by finding the proportion of the range covered by the desired sales (100 out of 300). Therefore, the probability of selling out is 100/300 = 0.25 or 25%. The probability of not selling out is the complement, which is 1 - 0.25 = 0.75 or 75%.

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Select the domain and range of F.
F={(x, y) Ix+y=10].
1. Set F is not a function and does not contain a domain or range
2. Domain: [10] Range: (10)
3. Domain: All Real Numbers Range: All Real Numbers

Answers

The domain and range of F is F={(x, y) Ix+y=10] is: 3. Domain: All Real Numbers Range: All Real Numbers

The given set F={(x, y) | x+y=10} represents a linear equation where the sum of x and y is always equal to 10.

To determine the domain and range of F, we need to consider the

possible values of x and y that satisfy the equation.

Domain: The domain represents the set of all possible values for the independent variable, which in this case is x. Since there are no restrictions on the value of x, the domain is All Real Numbers.

Range: The range represents the set of all possible values for the dependent variable, which in this case is y. By rearranging the equation x+y=10, we can solve for y to get y=10-x. Since x can take any real value, y can also take any real value. Therefore, the range is also All Real Numbers.

The correct answer is: 3. Domain: All Real Numbers Range: All Real Numbers

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Sierra and Amy are selling cheesecakes for a school fundraiser. Customers can buy pecan
cheesecakes and strawberry cheesecakes. Sierra sold 10 pecan cheesecakes and 5 strawberry
cheesecakes for a total of $115. Amy sold 1 pecan cheesecake and 3 strawberry cheesecakes for a
total of $34. Find the systems of equations that best represent the situation.
1. 10p + 5s = 115
1p + 3s - 34
2. 10p + 5s = 34
1p +3s = 115
3. 5p + 10s = 115
1p + 35 = 34
4. 10p + 3s = 115
1p +55 = 34

Answers

Answer:

number 1 option

Step-by-step explanation:

Sierra

10p + 5s = 115

Amy

1p + 3s = 34

Find three consecutive odd integers that have a sum of 75.​

Answers

Let the first number be x

Then the second odd number would be x  +2

The third one would be x + 4

Add them together to equal 75:

x + x +2  + x+4 = 75

Simplify:

3x + 6 = 75

Subtract 6 from both sides:

3x = 69

Divide both sides by 3:

x = 23

First number = 23

Second number = 25

Third number = 27

Consider this equation.

Consider this equation.

Answers

Answer:

B

Step-by-step explanation:

given

tanΘ = \(\frac{3\sqrt{5} }{2}\) = \(\frac{opposite}{adjacent}\)

this ratio relates to a right triangle, with hypotenuse h and

legs 3\(\sqrt{5}\) and 2

using Pythagoras' identity in the right triangle

h² = (3\(\sqrt{5}\) )² + 2² = 45 + 4 = 49 ( take square root of both sides )

h = \(\sqrt{49}\) = 7

then

cosΘ = \(\frac{adjacent}{hypotenuse}\) = \(\frac{2}{7}\)

Is a conditional equation , an identity or a contradiction ?

Answers

A conditional equation is neither an identity nor a contradiction. It is a statement that is only true under certain conditions.

A conditional equation is an equation that expresses a condition. It has two parts: a hypothesis (or antecedent) and a conclusion (or consequent). The hypothesis states that a certain condition must be met in order for the conclusion to be true. For example, the equation "if x = 4, then x + 1 = 5" is a conditional equation. If the condition (x = 4) is true, then the conclusion (x + 1 = 5) is also true. However, if the condition is false, then the conclusion is also false. Therefore, a conditional equation is neither an identity nor a contradiction, but rather a statement that is only true under certain conditions.

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An oxygen ion (O+) moves in the xy-plane with a speed of 2.00 ✕ 103 m/s. If a constant magnetic field is directed along the z-axis with a magnitude of 4.25 ✕ 10−5 T, find the magnitude of the magnetic force acting on the ion and the magnitude of the ion's acceleration. (a) the magnitude (in N) of the magnetic force acting on the ion N (b) the magnitude (in m/s2) of the ion's acceleration m/s2

Answers

a. The magnitude of the magnetic force acting on the ion is 1.72 × 10⁻¹⁴ N.

b. The magnitude of the ion's acceleration is 6.48 × 10¹¹ m/s².

What is magnetic field?

The area in which the force of magnetism acts around a magnetic material or a moving electric charge is known as the magnetic field.

The magnetic force on a charged particle moving in a magnetic field is given by the formula:

F = q v B sin θ

where:

- F is the magnetic force acting on the particle

- q is the charge of the particle

- v is the velocity of the particle

- B is the magnetic field strength

- θ is the angle between the velocity vector and the magnetic field vector

In this problem, the oxygen ion has a charge of +1.6 × 10⁻¹⁹ C and is moving with a speed of 2.00 × 10³ m/s in the xy-plane. The magnetic field is directed along the z-axis with a magnitude of 4.25 × 10⁻⁵ T. Since the velocity vector is perpendicular to the magnetic field vector, the angle between them is 90°, so sin θ = 1.

(a) The magnitude of the magnetic force on the oxygen ion is:

F = q v B sin θ = (1.6 × 10⁻¹⁹ C) × (2.00 × 10³ m/s) × (4.25 × 10⁻⁵ T) × 1 = 1.72 × 10⁻¹⁴ N

Therefore, the magnitude of the magnetic force acting on the ion is 1.72 × 10⁻¹⁴ N.

(b) The magnitude of the ion's acceleration can be found using the formula:

a = F/m

where:

- a is the acceleration of the particle

- F is the magnetic force acting on the particle

- m is the mass of the particle

The mass of an oxygen ion is approximately 2.66 × 10⁻²⁶ kg.

So, the magnitude of the ion's acceleration is:

a = F/m = (1.72 × 10⁻¹⁴ N) / (2.66 × 10⁻²⁶ kg) = 6.48 × 10¹¹ m/s²

Therefore, the magnitude of the ion's acceleration is 6.48 × 10¹¹ m/s².

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Complete the formula to find the area of the triangle.
3 cm
4 cm
5 cm
Area = x base x height
= 1/2 (²) ue

Complete the formula to find the area of the triangle.3 cm4 cm5 cmArea = x base x height= 1/2 () ue

Answers

Answer:

1/2(4)(3)

Step-by-step explanation:

assuming = 1/2 (²) ue it means nothing, just put the base and height in the brackets

=1/2(4)(3)

solution:

1/2 × 4 × 3 =

2 × 3 = 6 cm²

Elise is buying a new car selling for
$21,450. The rate of depreciation on this
type of car is 8% per year. On the graph
of a function that represents this
situation, where does the line cross the y
axis?

Elise is buying a new car selling for$21,450. The rate of depreciation on thistype of car is 8% per year.

Answers

Answer: 21450

Step-by-step explanation:

That is the initial price.

The line cross the y axis at 21450.

The correct option is (C)

What is Percentage?

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. Using the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Given:

Elise is buying a new car selling for $21,450.

The rate of depreciation on this type of car is 8% per year.

Using f(x) = A \((1+r)^x\)

A= $21,450.  and r = -8% (depreciated)

So, f(x) = A \((1+r)^x\)

f(x) = 21450 \((1- 8/100)^x\)

= 21450 x \((0.92)^x\)

Thus, the line cross the y axis at

= 21450 ( initial point)

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Examine the three graphs shown below.
Graph 1
Graph 2
Graph 3

Which graphs have same domain?
O A Graphs 1, 2 and 3
B. Graphs 2 and 3
OC. Graphs 1 and 2
D. Graphs 1 and 3
NEED THIS PLEASE :)

Examine the three graphs shown below.Graph 1Graph 2Graph 3Which graphs have same domain?O A Graphs 1,

Answers

I think it's a

Step-by-step explanation:

it's been a while since I done this kind of work


y = -x + 5
Write in standard form. PLEASE SHOW WORK

Answers

Regroup terms.
y
=
5

x
y=5−x

2 Subtract
5
5 from both sides.
y

5
=

x
y−5=−x

3 Multiply both sides by

1
−1.

y
+
5
=
x
−y+5=x

4 Regroup terms.
5

y
=
x
5−y=x

5 Switch sides.
x
=
5

y
x=5−y
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