can someone please help me with this question

Answer:

Inequality Form:

x<−5 or x>−1

Interval Notation:

(−∞,−5)∪(−1,∞)

Step-by-step explanation:

Displacement is the length of the straight line drawn from an object’s initial position to the object’s final position

The term "displacement" refers to a change in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial position to the ending position. For instance, if an object shifts from position A to position B, its position changes.

If an object moves with respect to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right with respect to a whiteboard, the object's position changes. This change in location is described as displacement.

The displacement is the shortest distance between an object's initial and final positions. Displacement is a vector. It is visualized as an arrow that points from the initial position to the final position, indicating that it has both a direction and a magnitude.

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Answer:

each side to the fence has 6 units added to have an area of 176

Step-by-step explanation:

Let me know if you need anything more !!

Happy to help :)

Answer:

the only thing you need to do is to divide the speed with the distance

Answer:

multiplied 4

9 the same

Step-by-step explanation:

Tina multiplied 4 by 4 to get 16, and 9 by 9 to get 81. she should have multiplied each term by the same number.

The answer to the given linear programming problem, which is solved using the simplex method, is as follows:

The optimal solution to minimize the objective function Z = X1 + 2X2 is X1 = 20 and X2 = 0, with the objective function value Z = -100.

To solve the problem, we'll first convert the inequalities to equations by introducing slack and surplus variables. Then we'll set up the initial simplex tableau and iterate through the simplex algorithm until we reach an optimal solution.

⇒ Convert the inequalities to equations:

A. X1 + 3X2 + S1 = 90 (where S1 is the slack variable)

B. 8X1 + 2X2 + S2 = 160 (where S2 is the slack variable)

C. 3X1 + 2X2 + S3 = 120 (where S3 is the slack variable)

D. X2 + S4 = 70 (where S4 is the surplus variable)

⇒ Set up the initial simplex tableau:

        | X1 | X2 | S1 | S2 | S3 | S4 | RHS |

----------------------------------------------

Z       | -1 | -2 |  0 |  0 |  0 |  0 |  0  |

----------------------------------------------

S1      |  1 |  3 |  1 |  0 |  0 |  0 | 90  |

S2      |  8 |  2 |  0 |  1 |  0 |  0 | 160 |

S3      |  3 |   2 |  0 |  0 |  1 |  0 | 120 |

S4      |  0 |   1 |  0 |  0 |  0 | -1 | 70  |

⇒ a) Select the most negative coefficient in the Z row, which is -2. Choose the corresponding column as the pivot column (X2 column).

b) Find the pivot row by selecting the minimum ratio of the RHS value to the positive values in the pivot column. The minimum ratio is 70/1 = 70. Thus, the pivot row is S4.

c) Perform row operations to make the pivot element (1 in S4 row) equal to 1 and eliminate other elements in the pivot column:

  - Divide the pivot row by the pivot element (1/1 = 1).

  - Replace other elements in the pivot column using row operations:

    - S1 row: S1 = S1 - (1 * S4) = 90 - 70 = 20

    - Z row: Z = Z - (2 * S4) = 0 - 2 * 70 = -140

    - S2 row: S2 = S2 - (0 * S4) = 160

    - S3 row: S3 = S3 - (0 * S4) = 120

d) Update the tableau with the new values:

        | X1 | X2 | S1 | S2 | S3 | S4 | RHS |

----------------------------------------------

Z       | -1 |  0 |  0 |  0 |  2 | -2 | -140|

----------------------------------------------

S1      |  1 |  3 |  1 |  0 |  

0 |  0 | 20  |

S2      |  8 |  2 |  0 |  1 |   0 |  0 | 160 |

S3      |  3 |  2 |  0 |  0 |   1 |  0 | 120 |

S4      |  0 |  1 |  0 |  0 |   0 | -1 | 70  |

e) Repeat steps a to d until all coefficients in the Z row are non-negative.

  - Select the most negative coefficient in the Z row, which is -1. Choose the corresponding column as the pivot column (X1 column).

  - Find the pivot row by selecting the minimum ratio of the RHS value to the positive values in the pivot column. The minimum ratio is 20/1 = 20. Thus, the pivot row is S1.

  - Perform row operations to make the pivot element (1 in S1 row) equal to 1 and eliminate other elements in the pivot column.

  - Update the tableau with the new values.

f) The final simplex tableau is:

        | X1 | X2 | S1 | S2 | S3 | S4 | RHS |

----------------------------------------------

Z       |  0 |  0 |  0 |  0 |  1 | -3 | -100|

----------------------------------------------

X1      |  1 |  3 |  1 |  0 |  0 |  0 | 20  |

S2      |  0 | -22 | -8 |  1 |  0 |  0 | 140 |

S3      |  0 | -7 | -3 |  0 |  1 |  0 | 60  |

S4      |  0 |  1 |  0 |  0 |  0 | -1 | 70  |

⇒ Read the solution from the final tableau:

The optimal solution is X1 = 20 and X2 = 0, with the objective function value Z = -100.

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Answer:

-81i

Step-by-step explanation:

(-3i)^3(-3)=-81i

Answer:

0.65 m to 2 D.P.s

Step-by-step explanation:

F = k/d^2

0.005 = k/2^2

k = 0.005 * 4

k = 0.02.

So F = 0.02/d^2.

When F = 0.048:

0.048 = 0.02/d^2

d^2 = 0.02/0.048

d^2 = 0.41666...

d = √0.41666...

= 0.645497.

The answer is 917

(Hope this helps you! :) )

The final answer is 8arcsin(x/4) - 4sin(2arcsin(x/4)) + C, where C represents the constant of integration. The expression is given in terms of x only.

To evaluate the given integral, we can use trigonometric substitution. Let's substitute x = 4sinθ, which allows us to rewrite the integrand in terms of θ. The differential becomes dx = 4cosθ dθ.

Using this substitution, the integral transforms into ∫(4sinθ)²√(16-(4sinθ)²)(4cosθ) dθ. Simplifying this expression yields 16∫sin²θ√(1-cos²θ)cosθ dθ.

We can apply the double-angle identity sin²θ = (1-cos2θ)/2 to simplify further. This results in 8∫(1-cos2θ)√(1-cos²θ)cosθ dθ.

Next, we can apply the trigonometric identity sin(2θ) = 2sinθcosθ to obtain 8∫(sinθ-sin³θ) dθ.

Finally, integrating term by term and substituting back x = 4sinθ, we arrive at the final answer of 8arcsin(x/4) - 4sin(2arcsin(x/4)) + C. This expression represents the antiderivative of the given function in terms of x only, where C represents the constant of integration.

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The NPV is positive, it is worth taking the Investment.

Net Present Value (NPV) is an assessment method that determines the attractiveness of an investment. It is a technique that determines whether an investment has a positive or negative present value.

This method involves determining the future cash inflows and outflows and adjusting them to their present value. This helps determine the profitability of the investment, taking into account the time value of money and inflation.The formula for calculating NPV is:

NPV = Σ [CFt / (1 + r)t] – CIWhere CFt = the expected cash flow in period t, r = the discount rate, and CI = the initial investment.

The given problem can be solved by using the following steps:

Calculate the present value (PV) of the expected cash inflows:

Year 1: $28,000 / (1 + 0.08)¹ = $25,925.93Year 2: $28,000 / (1 + 0.08)² = $24,009.11Year 3: $28,000 / (1 + 0.08)³ = $22,173.78Total PV = $72,108.82

Calculate the PV of the initial investment: CI = $7,000 / (1 + 0.08)¹ + $35,000 / (1 + 0.08)²CI = $37,287.43Calculate the NPV by subtracting the initial investment from the total PV: NPV = $72,108.82 – $37,287.43 = $34,821.39

Since the NPV is positive, it is worth taking the investment.

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Angles Formulas at the center of a circle can be expressed as:

Central angle, θ = (Arc length × 360º)/(2πr) degrees

Sum of Interior angles=180°(n-2)

The angles formulas are used to find the measures of the angles. An angle is formed by two intersecting rays, called the arms of the angle, sharing a common endpoint.

The corner point of the angle is known as the vertex of the angle. The angle is defined as the measure of the turn between the two lines.

There are various types of formulas for finding an angle; some of them are the central angle formula, double-angle formula, etc...

We use the central angle formula to determine the angle of a segment made in a circle.

We use the sum of the interior angles formula to determine the missing angle in a polygon.

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Answer:

Step-by-step explanation:

f(x) = 2x + 5

f(-6)= 2(-6) + 5 = -12 + 5 = -7

Answer:

40.5 inches

Step-by-step explanation:

15.2*2+5.05*2=30.4+10.1=40.5

Answer:

dc/a-b-d

Step-by-step explanation:

ax – bx = d

x + c

Multiply both sides by x + c

ax – bx

(x + c) = d(x + c)

x + c

Simplify

ax – bx

(x+c): ax – bx

x + c

ax – bx = d(x+c)

Expand d(x+c): dx + cd

ax — bx = dx + cd

Subtract dx from both sides

ax – bx – dx = dx + cd – dx

Simplify

ax – bx – dx = cd

Factor ax – bx – dx: x(a – b – d)

x(a - b- d) = cd

Divide both sides by a – b – d; a + b + d

x(a – b - d) cd

a + b + d

a - b - d

a – b-d

Simplify

X =dc/a-b-d

The value of 'x' in the algebraic equation is  \(\rm x= \frac{dc}{a-b-d} \\\)  where \(\rm a\neq b+d\)

It is given that the algebraic equation  \(\rm \frac{ax-bx}{x+c}= d\)

It is required to solve the algebraic (polynomial) equation if \(\rm a\neq b+d\)

Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.

We have an algebraic equation:

\(\rm \frac{ax-bx}{x+c}= d\)

\(\rm \frac{ax-bx}{x+c}= d\\\\\rm ax-bx=d(x+c)\\\rm ax-bx=dx+dc\\\rm ax-bx-dx=dc\\\rm (a-b-d)x=dc\\\\\rm x= \frac{dc}{a-b-d} \\\)

Thus, the value of 'x' in the algebraic equation is  \(\rm x= \frac{dc}{a-b-d} \\\) where \(\rm a\neq b+d\)

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Answer:

y=8

Step-by-step explanation:

Slope-intercept form

y=mx+b

Plug in values

y=0x+b

8=0(-4)+b

b=8

substitute

y=8

Answer: The best prediction possible for the number of times you roll a three is 1/6 of a roll.

Step-by-step explanation:

When you find the statistics of something like rolling a die, you will need to divide how many times you roll the die by how many sides are on the die.

6 - how many times you roll the die

6 - how many sides are on the die

When you divide 6 by 6,  you will get one. Since both of the statistical numbers are the same, you will get an 1/6 chance of rolling a 1, 2, 3, 4, 5, and 6. So 1/6 is the answer! Hope this helps!!!

P.S (I learned this in 5th grade :))

Answer:

The 3rd one is correct.

Step-by-step explanation:

Answer:

30 because negative x negative = a positive number

Answer: x = 10

Step-by-step explanation:

Answer: x=10

Step-by-step explanation: 9(8)= 72, 72+18=90, 90/9= 10

The size of angle DCA is 480°.

In the given figure, ABCD is a rhombus with angle ABE as a straight line and BCE as an isosceles triangle. We are asked to find the measure of angle DCA.

Since ABCD is a rhombus, opposite angles are congruent. Therefore, angle ACD is equal to angle ABC.

Since BCE is an isosceles triangle, angle BEC is equal to angle BCE.

From the given information, we know that angle ABC + angle BCE + angle ECD = 180 degrees.

Let's denote the measure of angle BCE as "x." Therefore, angle ABC is also "x."

Substituting these values into the equation, we have:

x + x + angle ECD = 180

2x + angle ECD = 180

Since angle ECD is denoted as 480 degrees in the question, we can solve for "x" as follows:

2x + 480 = 180

2x = 180 - 480

2x = -300

x = -150

However, angles cannot have negative measures. Therefore, there is no valid measure for angle DCA given the information provided.

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Answer:

\((x-7)^2+y^2=1\)

Step-by-step explanation:

Hi there!

Equation of a circle: \((x-h)^2+(y-k)^2=r^2\) where the circle is centered at (h,k) and the radius is r

1) Plug in the given center (7,0)

\((x-7)^2+(y-0)^2=r^2\\(x-7)^2+y^2=r^2\)

2) Plug in the radius (1)

\((x-7)^2+y^2=1^2\\(x-7)^2+y^2=1\)

I hope this helps!

Answer:

48

Step-by-step explanation:

jhus cross multiply 12*4=48

Answer:

x = 48

Step-by-step explanation:

x/4 = 12

4x/4 = x = 4(12) = 48

Check answer: 48/4 = 12

Answer:

C. The set of prime numbers.

Thank you ☺️

Answer:

25 and 36

Step-by-step explanation:

1x1=1

2x2=4

3x3=9

4x4=16

5x5=25

6x6=36

7x7=49

and so on..............

Approximately 188 values ​​fall within 2 standard deviations of the mean when 280 sociology students take an exam and the distribution of their scores can be treated as normal.

It states that the grade distribution of 280 sociology students can be considered normal. Let μ be the average score of the students and σ be the standard deviation.

A run appear of thumb is that nearly 68% of the comes almost are interior 1 standard deviation of the pitiless, nearly 95% of the comes around are interior 2 standard deviations of the brutal, and nearly 99.7% of the comes approximately are interior 3 standard deviations of the cruel. 

Since we are interested in finding the number of values ​​within 2 standard deviations of the mean, we can estimate this using a rule of thumb.

We know that about 95% of the results are within 2 standard deviations of the mean. So you can write:

P(μ - 2σ < X < μ + 2σ) = 0.95

where X is the student's score.

We can simplify this expression by subtracting μ from both sides.

P(-2σ < X - μ < 2σ) = 0.95

Now we can find the probability that the standard normal variable Z falls between -2 and 2 using the standard normal distribution. we have:

P(-2 < Z < 2) = 0.95

Using a standard normal distribution table or a calculator capable of calculating the normal probability, we can find that the probability that Z is between -2 and 2 is approximately 0.9545.

So it looks like this:

P(-2 < Z < 2) = P((X - μ)/σ < 2) - P((X - μ)/σ < -2) = 0.9545

Using a standard normal distribution table or a calculator capable of calculating the inverse normal probability, we find that a value of 2 in the standard normal distribution corresponds to a z-score of approximately 1.96.

So it looks like this:

P((X - μ)/σ < 1.96) - P((X - μ)/σ < -1.96) = 0.9545

Since the distribution of values ​​is normal, we know that the standard normal variable (X - μ)/σ follows the standard normal distribution. Therefore, you can find the z-score corresponding to 1.96 using a standard normal distribution table or a calculator capable of calculating the inverse normal probability.

A z-score equal to 1.96 is found to be approximately 0.975.

So it looks like this:

P(Z < 0.975) - P(Z < -0.975) = 0.9545

Using a standard normal distribution table or a calculator capable of calculating normal probabilities, we find:

P(Z < 0.975) = 0.8365 and P(Z < -0.975) = 0.1635

So it looks like this:

0.8365 - 0.1635 = 0.673

Subsequently, roughly 67.3% of the comes about are inside 2 standard deviations of the mean.

To discover the number of comes about that are inside two standard deviations of the cruel, we have to increase that rate by the entire number of understudies.

 Number of outcomes within 2 standard deviations of the mean = 0.673 × 280 ≈ 188

Therefore, approximately 188 values ​​fall within 2 standard deviations of the mean.

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X is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the interquartile range of x.

a. To calculate the sample median of x, we can use the median function in R. So, the code would be:
median(x)
where x is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the sample median of x.
b. To find the .34 quantile of x, we can use the quantile function in R. The code would be:
quantile(x, 0.34)
where x is the variable that we have assigned the agriculture column of swiss to, and 0.34 represents the desired quantile. Running this code would give us the value of the .34 quantile of x.
c. To calculate the interquartile range of x, we can use the IQR function in R. The code would be:
IQR(x)
where x is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the interquartile range of x.

The "fertility", "Switzerland", and "x <- swiss $ agriculture" terms.
a. To calculate the sample median of x (the agriculture column in the Swiss dataset), use the following R command:
median_x <- median(swiss$agriculture)
b. To find the 34th percentile (0.34 quantile) of x using the R quantile function, use the following R command:
quantile_x <- quantile(swiss$agriculture, probs = 0.34)

c. To calculate the interquartile range of x (the agriculture column in the Swiss dataset) using R, use the following R commands:
Q1 <- quantile(swiss$agriculture, probs = 0.25)
Q3 <- quantile(swiss$agriculture, probs = 0.75)
IQR_x <- Q3 - Q1
This will give you the interquartile range (IQR) of the agriculture column in the Swiss dataset.

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The inequality based on the given data is :

d ≥ 5s + 9 .

Step 1: Eliminate fractions by multiplying all terms by the least common denominator of all fractions to solve an inequality.

Step 2 Simplify the inequality by combining like terms on each side.

Step 3 Subtract or add amounts to get the unknown on one side and the numbers on the other.

Here given,

Fixed cost = $9.00

Cost per pound of soil is $5.00

Hence, the equation will be :

d ≥ 5s + 9

Since d must be greater than or equal to this value for Kyle to be able to afford it.

∴ The inequality = d ≥ 5s + 9 .

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