Can someone please help with these questions I’ve been stuck on them all day and literally don’t know what to do!?

Can Someone Please Help With These Questions Ive Been Stuck On Them All Day And Literally Dont Know What

Answers

Answer 1

(1) Here you first calculate the amount of substance from the mass and the molar mass. Then you multiply by the constant.

first: n = m / M             then: n * 6 * 10²³ = number of atoms

a) n = 4 g / 24 g/mol            number of atoms = 0,166 mol * 6 * 10²³ 1/mol

   n = 0,166 mol                   number of atoms = 0,96 * 10²³

b) n = 0,12 g / 12 g/mol       number of atoms = 0,01 mol * 6 * 10²³ 1/mol

   n = 0,01 mol                    number of atoms = 0,06 * 10²³

c) n = 32 g /48 g/mol         number of molecules = 0,666 mol * 6 * 10²³ 1/mol

   n = 0,666 mol                number of molecules = 4 * 10²³

d) n = 14,2 g / 71 g/mol      number of molecules = 0,2 mol * 6 * 10²³ 1/mol

   n = 0,2 mol                     number of molecules = 1,2 * 10²³

   Sodium sulfate has the formula Na2SO4, so it has two sodium atoms per  

   molecule. So you have to multiply the number of molecules by 2.

   number of atoms = number of molecules * 2

   number of atoms = 1,2 * 10²³ * 2

   number of atoms = 2,4 * 10²³

(2) The amount of substance can easily be calculated:

n = m / M

a) n = 16 g / 16 g/mol

   n = 1 mol

b) n = 0,14 g / 14 g/mol

   n = 0,01 mol

c) n = 5,4 g / 108 g/mol

   n = 0,05 mol

d) n = 8,88 g / 35,5 g/mol

   n = 0,25 mol

(3) With the same formula the mass can now be calculated, for this it only has to be converted according to the mass:

n = m / M      | *M

m = n * M

a) m = 0,05 mol * 16 g/mol

   m = 0,8 g

b) m = 10 mol * 23 g/mol

   m = 230 g

c) m = 0,01 mol * 1 g/mol

   m = 0,01 g

d) m = 0,25 mol * 65,4 g/mol

   m = 16,35 g

(4) The molar mass of a molecule is obtained by adding the molar masses of the individual atoms:

a) Br = 80 g/mol → Br2 = 2 * 80 g/mol = 160 g/mol

b) C = 12 g/mol, O = 16 g/mol → CO2 = 12 g/mol + 2 * 16 g/mol = 44 g/mol

c) H = 1 g/mol, N = 14 g/mol, O = 16 g/mol

  → HNO3 = 1 g/mol + 14 g/mol + 3* 16 g/mol = 63 g/mol

d) Cu = 64 g/mol, S = 32 g/mol, O = 16 g/mol,  H = 1 g/mol

   →CuSO4*5H2O = 64 g/mol + 32 g/mol + 4 * 16 g/mol + 5 * (2 * 1 g/mol +

     16 g/mol) = 250 g/mol

(5) Exercise 5 works exactly like exercise 2 and 4:

first: Calculate molar mass                    then: n = m / M

a) n = 128 g / 16 g/mol

   n = 8 mol

b) M = 39 g/mol + 14 g/mol + 3 * 16 g/mol

   M = 101 g/mol

   n = 25,25 g / 101 g/mol

   n = 0,25 mol

c) M = 2 * 12 g/mol + 6 * 1 g/mol + 16 g/mol

   M = 46 g/mol

   n = 414 g / 46 g/mol

   n = 9 mol

(6) Exercise 6 works exactly the same as exercises 3 and 4:

first: Calculate molar mass                    then: m = n * M

a) M = 32 g/mol + 2 * 16 g/mol

   M = 64 g/mol

 

   m = 2 mol * 64 g/mol

   m = 128 g

b) M = 2 * 1 g/mol + 32 g/mol + 4 * 16 g/mol

   M = 98 g/mol

 

   m = 20 mol * 98 g/mol

   m = 1960 g

c) M = 23 g/mol + 16 g/mol + 1 g/mol

   M = 40 g/mol

 

   m = 0,5 mol * 40 g/mol

   m = 20 g


Related Questions

The last point of comparison is to look at oxygen isotope data for this time interval. It is a tricky business to estimate temperature from isotope values from so long ago because quite a bit can change about both oceans and organisms over such a long time. People who study these super ancient isotope records feel that some corrections are needed to account for these changes. I am mostly (but not 100%) convinced that they are justified. If you want, I can give you the paper where they explain the basis for the corrections, but it involves some serious chemistry.
C) Chemical proxies for temperature
In the graph below, the uncorrected values are shown with the blue line. The corrected values are shown with either the red or the dashed black line (there are two different ways of doing the corrections). They are roughly the same, so let's use the dashed black line as it is a little easier to see. 5) How well do the uncorrected dOvalues correspond with CO, levels? What about the corrected dashed black line? Sometimes we are looking at whether something is increasing or decreasing. In this case I want you to also look at where the values lie relative to today (the horizontal dashed line at 0°C)
6) Does this argue for or against the notion that CO2 concentration is one of

Answers

We can analyze the relationship between the uncorrected dO (oxygen isotope) values and CO2 levels, as well as the corrected dashed black line values.

In terms of the uncorrected dO values, it is unclear how well they correspond with CO2 levels since the specific correlation or trend is not mentioned. Without further details or data, we cannot determine the exact relationship between the uncorrected dO values and CO2 levels.

However, regarding the corrected dashed black line values, we can observe their alignment with the horizontal dashed line at 0°C, which represents today's temperature. By assessing where the corrected values lie relative to this line, we can gain insights into temperature changes over time.

Based on the information provided, we cannot definitively conclude whether this argues for or against the notion that CO2 concentration is one of the main drivers of climate change. The given context focuses on comparing the dO values with CO2 levels and temperature, without explicitly addressing the relationship between CO2 concentration and climate change. To draw conclusions about the impact of CO2 concentration on climate change, further analysis and information about the specific trends and patterns are required.

Overall, without additional data and details, it is challenging to determine the exact correspondence between the uncorrected dO values and CO2 levels, as well as the implications for the role of CO2 concentration in climate change. Further examination of the provided paper and relevant scientific literature would provide a more comprehensive understanding of the topic.

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Which transition metals are paramagnetic but can easily form ferromagnetic alloys with other metals? Question 17 options: A) Transition metals in groups 1-5, periods 5 and 6 B) Transition metals in groups 11 and 12, periods 4 and 5 C) Transition metals in groups 8-10, periods 4 and 5 D) Transition metals in groups 8-10, periods 5 and 6

Answers

The transition metals that are paramagnetic but can easily form ferromagnetic alloys with other metals are Iron, Cobalt, and Nickel.

Hence, the correct option is C: Transition metals in groups 8-10, periods 4 and 5.

What are paramagnetic and ferromagnetic substances?

Paramagnetic substances are substances that are weakly attracted to magnets. The atoms of paramagnetic substances contain electrons that mostly spin in the same direction. They include aluminum, gold, and copper.

Ferromagnetic substances are substances that are strongly attracted to magnets when placed near magnets. They include metals such as Iron, Cobalt, and Nickel.

Transition metals are metals that have partially filled D-orbitals. Hence, transition metals are paramagnetic as well as ferromagnetic.

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Answer:  C) Transition metals in groups 8-10, periods 4

Explanation:

Round to 3 significant figures.
1.235

Answers

Answer:

1.24

Explanation:

According to the concept of significant figures, rounding off to  3 significant figures gives 1.24.

What are significant figures?

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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hi!! please help :( lots of points !

hi!! please help :( lots of points !

Answers

Answer:

Structure:

Differences-  A polymer is a collection of a large number of molecules whereas a monomer is a single molecule.

A monomer is a single molecule, which has the ability to chemically bond with other monomers in a long chain. A polymer is a chain that is made when monomers bind with other monomers.

Similarities-  They are both molecules

Properties:

Differences- Monomers have polyfunctionality, which is the capacity to form chemical bonds to at least two other monomer molecules. Polymers are chemically unreactive, solids at room temperature, malleable, tough, and are electrical insulators.

Similarities- They both makeup larger forms of matter.

Intermolecular Forces

Differences: Polymers are held together by covalent bonds, hydrogen bonds, and dispersion bonds. Monomers are only held together by hydrogen bonds.

Similarities: They can both be bonded together by hydrogen bonds.

How many mm are in 38,987 L?

Answers

Answer:

38987000

Explanation:

there are 1000 ml in a Liter.

Hope this helps!

The mm in 38,987 L will be 38987000.

What are measurements units?

Measurement units are the units that are used to measure the quantity of a substance or other values. There are seven measurement units that are used to measure the different values and magnitudes of objects.

The basic seven measurement values are second (symbol s, the unit of time), ampere (A, electric current), kelvin (K, thermodynamic temperature), metre (m, length), candela (cd, luminous intensity), kilogram (kg, mass),  and mole (mol, amount of substance).

Unit of measurement of mass: Kilogram(Kg)

Unit of measurement of Power: Watt(W)

Unit of measurement of Gravity: m/s²

1 m = 1000000 L

So, 38,987 L = 38987000.

Measurement units are converted from one unit to another unit.

Thus, the mm in 38,987 L will be 38987000.

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1) Name the following covalent compounds (using the naming rules from the text and lecture) (5 points).

N2H4 _____
HBr(aq) ______
N2O _______
C6H6 (l) _______

2) Write the chemical formula. and indicate net charge where relevant compounds, (> points)

Sulfur hexachloride ________
Sulfate _________
Disilicon tetrafluoride ______
Carbonate ________

Answers

Answer:

Dinitrogen Tetrahydrogen

Hydrogen Monobromide

Dinitrogen Monoxide

Hexacarbon Hexahydrogen

2)Sulfur Hexachloride.SCl6(six should be a subscript) Netcharge = -8.

Sulfate = SO4(4 is subscript) Netcharge = -2

Disilicon Tetrafluoride = S2F4(2 and 4 should be subscript numbers. Net charge = -4.

Carbonate = CO3(3 is subscript). Netcharge=  -2.

Explanation:

Prefixes for covalent compounds are.

1 - mono

2 - di

3 - tri

4 - tetra

5 - penta

6 - hexa

7 - hepta

8 - octa

9 - nona

10 - deca

Sulfur has a charge of -2. Chlorine has a charge of -1. Hexachloride implies 6 chlorine. 6x -1 = -6. Sulfur is -2. -6+-2=-8.

Sulfate is on a common ion sheet.

Disilicon Tetrafluoride is S2F4= S has a charge of -2. -2x2=-4. F has a charge of -1. -1 x 4=-4 -4+-4=-8.

Carbonate is on a common ion sheet.

Carbonate is right the others do not applaud to its potential

The NFPA chemical hazard codes indicate all of the following EXCEPT:

Answers

The NFPA chemical hazard codes indicate the level of health, flammability, and instability hazards associated with a particular chemical. However, they do not indicate the specific chemical composition or properties of the substance.

The NFPA chemical hazard codes indicate all of the following:

1.The level of health hazard associated with a chemical

2.The level of flammability hazard associated with a chemical

3.The level of reactivity hazard associated with a chemical

4.The specific type of protective equipment needed when working with a chemical

The NFPA chemical hazard codes do not indicate the environmental impact of a chemical.

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1. How many atoms would make 7.31 moles of potassium?

Answers

The number of atoms that would make 7.31 moles of potassium is 4.40 × 10²⁴ atoms.

How to calculate number of atoms?

The number of atoms in a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number as follows:

According to this question, there are 7.31 moles of pottasium. The number of atoms can be calculated as follows:

no of atoms = 7.31 moles × 6.02 × 10²³

no of atoms = 4.40 × 10²⁴

Therefore, 4.40 × 10²⁴ atoms is the number of atoms in pottasium.

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Which form of decay produces a nucleus similar to the element helium? alpha particle beta particle gamma ray

Answers

Answer:

ALPHA

Explanation:

How can you distinguish between crystalline allotropic modifications of Sulphur from those of amorphous allotrops?​

Answers

The crystalline allotropes of sulfur are very strong and have a high melting and boiling point while the amorphous allotropes of sulfur are brittle and breaks easily.

What is a crystalline substance?

A crystalline substance is one that has a definite arrangement of the atoms in the substance. An amorphous substance lacks this definite arrangement. We can see this arrangement when we conduct an X-ray crystallography of the sulfur.

Also, the crystalline allotropes of sulfur are very strong and have a high melting and boiling point while the amorphous allotropes of sulfur are brittle and breaks easily.

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What mass of MnO₂ is produced when 445 grams of H₂O are reacted?
H₂O+2MnO4, + Br —> BrO₂+2MnO₂ + 20H
O 5,200 g
O 4,300 g
O 0.430 g
O 8,600 g

Answers

The mass of manganese dioxide produced from one mole or 18 g of water is 174 g. Then, MnO₂ produced from 445 gram of H₂O is 4300 g.

What is permanganate ?

Permanganate MnO₄ is an ion from potassium permanganate. It is an oxidizing agent.  MnO₄  easily reduces to MnO₂. As per the given reaction, 18 g is required by one mole or 174 g of MnO₂.

Molar mass of MnO₂ = 87 g/mol

molar mass of water = 18 g/mol

mass of 2 moles of MnO₂ = 174 g

Thus, 18 g of water gives 174 g of MnO₂.

Mass of MnO₂ produced from 445 g of  water = (445 × 174)/18 = 4300 g

Therefore, the mass of MnO₂ produced is 4300 g.

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Q1. Because metals are malleable, we use some of them to make saucepans. Give two other examples of uses of metals that depend on: (a):their malleability. (b):their ductility. (c):their ability to conduct electricity. [3]

Answers

Explanation:

(a):their malleability:

>iron making. iron worker heat the meat and hammer it to give them the desired shape.

> in the jewelry making process, like the gold or silver you wear are results due to the malleability of metal

(b):their ductility:

>for the making of high tension cable that connects different cities for transferring of electricity.

>for making wire gauze

(c):their ability to conduct electricity:

>for lighting up your house with light bulbs

>for using cooking stoves

>to make refrigerator work.

Answer:

a)gold and silver-used to make jewellery

b)gold and copper(we draw them in wires easily because they are not brittle)

c)copper and iron(this is because both of them are metal and metaps are best conductors of electricity)

Explanation:

uses of copper- to make utensils

to make wires for circuits

uses of silver-to make jewellery

to make mirrors

malleability is the property of a meta in which the metal can be changed into different shapes.

Ductility-can be drawn into thin wires.

Explain what intermolecular forces are, and how they are easily overcome.

Answers

Explanation:

Intermolecular forces are forces that exist between two or more molecules and they can be overcome at high temperatures.

Carbon-14 has a half-life of 5,700 years. Scientist use this fact to determine the age of things made of organic material. Suppose the average page of a book contains approximately 0.5 mg of carbon-14 and the book is put into a time capsule. How much carbon-14 will each page contain after each of the following years.

Answers

The amount of carbon-14 in each page of a book decreases over time due to its radioactive decay. After each year, the amount of carbon-14 will be reduced by half, following its 5,700-year half-life.

Carbon-14 undergoes radioactive decay with a half-life of 5,700 years, which means that after 5,700 years, half of the carbon-14 present initially will have decayed.

Therefore, after the first year, each page of the book will contain 0.25 mg of carbon-14, as it is reduced by half. After another year (2 years total), it will be further reduced by half, resulting in 0.125 mg of carbon-14.

This process continues, with each passing year halving the amount of carbon-14. After 3 years, each page will contain 0.0625 mg, after 4 years it will be 0.03125 mg, and so on. The reduction by half occurs every 5,700 years, representing the half-life of carbon-14.

This pattern continues indefinitely, with the amount of carbon-14 gradually approaching zero as more time passes.

It's important to note that the calculation assumes no additional carbon-14 is introduced into the book or lost through other means. Additionally, the actual age determination of an object requires more complex measurements and considerations, such as calibration with known standards and correction factors for different environmental factors.

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The electron configuration for nitrogen is 1s22s22p3. What is the electron configuration of the nitride anion

Answers

Answer:

1s22s22p6

Explanation:

Nitride anion N3-, has additional 3 electrons than N atom. So just add 3 more to the configuration

p orbitals can occupy a total of 6 electrons so when we add 3 more it becomes 2p6

Nuclear bombs cause much more damage upon
explosion than non-nuclear bombs because
Select one:


- the fallout from a nuclear bomb explosion has a much shorter half-life than the fallout from non-nuclear bombs.

- nuclear bombs are a million time greater in size than bombs that react chemically.

- nuclear explosions emit alpha particle radiation, and non-nuclear bombs emit only beta particle radiation

- energy released by nuclear reaction is much greater than energy released by chemical reaction.

Answers

Answer:

- energy released by nuclear reaction is much greater than energy released by chemical reaction.

Explanation:

This is because nuclear bombs rely on nuclear reactions, which release energy from the splitting of atomic nuclei or the merging of atomic nuclei, whereas non-nuclear bombs rely on chemical reactions, which involve the breaking and forming of chemical bonds. Nuclear reactions release many orders of magnitude more energy than chemical reactions, resulting in much greater destructive power.

____ are small components typically made out of aluminum with fins that help to dissipate heat.
a.
ACs
c.
Heat buses
b.
Fans
d.
Heat sinks

Answers

Heat Sinks are small components typically made out of aluminum with fins that help to dissipate heat.

Heat sinks are often composed of CNC-machined copper or aluminum, and they contain heat sink fins or pins that enhance the component's surface area to aid in the transmission of heat to the surrounding fluid.

A part known as a heat sink facilitates heat transfer away from a hot device. It accomplishes this by increasing the device's operating surface area and the volume of low-temperature fluid that passes through it.

The main purpose of heat sinks is to increase the surface area of an electronic component that is in direct contact with a coolant. This will enable more heat to be easily dispersed, lowering the operating temperature of the device.

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4) Complete the following statement: Different elements...
A) Must have a mass number of at least 18.
B) Have more electrons than protons.
C) Have the same number of protons.
D) Have different numbers or protons.

Answers

Have a different number of protons
D.) Have different numbers of protons.

write a balanced chemical equation based on the following description: the reaction of aluminum metal with aqueous sulfuric acid to form aqueous aluminum sulfate and hydrogen gas.

Answers

The balanced chemical equation of the reaction between aluminum metal with aqueous sulfuric acid to form aqueous aluminum sulfate and hydrogen gas is 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.

What is a balanced chemical equation?

A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

According to this question, aluminum metal reacts with aqueous sulfuric acid to form aqueous aluminum sulfate and hydrogen gas.

This reaction will be balanced only if the atoms of each element on both sides of the equation are the same. The chemical reaction is as follows:

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.

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description of an aldol condensation reaction specific side products and why they form what is needed for an aldol addition product to form a condensation product? when does this process occur spontaneously

Answers

Aldol condensation produces water as a side product, which forms due to the elimination of hydroxyl and hydrogen from adjacent carbons. Aldol addition products can undergo condensation when heated with a strong base. This process can occur spontaneously when the aldol addition product is a cyclic molecule.

During an aldol condensation reaction, the specific side products formed are water and enol. Water forms as a result of the dehydration process that occurs when the alpha-hydrogen and carbonyl groups react to form an enolate ion intermediate, which then undergoes elimination to form the enol. Enols can undergo further reaction to form other products, including ketones or aldehydes.

An aldol addition product can form a condensation product when the reaction conditions favor dehydration, such as when the reaction is carried out in a basic solution, at elevated temperatures, or under anhydrous conditions. The process can occur spontaneously when the reactants are at the appropriate concentration and temperature to promote the reaction.

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--The complete question is, What are the specific side products formed during an aldol condensation reaction, and why do they form? What is required for an aldol addition product to form a condensation product? Additionally, under what conditions does this process occur spontaneously?--

If Ka of HXO3 is > than Ka of HZO3 at 25°C, then it is most likely that…..
a. X is more electronegative than Z
b. X exhibits a higher oxidation state than Z
c. the H―X bond is weaker than the H―Z bond
d. HXO3(aq) + ZO3−(aq) ↔ XO3−(aq) + HZO3(aq) is reactant-favored at 25°C
e. Z is larger than X
c and d are incorrect

Answers

If Ka of HXO3 is greater than Ka of HZO3 at 25°C, then it is most likely that:

a. X is more electronegative than Z

A higher Ka value indicates that HXO3 is a stronger acid than HZO3. In stronger acids, the bond between hydrogen and the electronegative element is more polar, allowing hydrogen to be more easily released as a proton (H+). Therefore, it is likely that X is more electronegative than Z, making HXO3 a stronger acid.

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Given the translation (0,5), translate ordered pairs (9, 0) and (2,-4).

Answers

Answer:

(9,5) and (2,1)

Explanation:

help pleaseeeeeeeeeeee

help pleaseeeeeeeeeeee

Answers

A is 4 B is 3 C is 2 and D is 1
A is connected to 4, B is connected to 3, C is connected to 2, and D is connected to 1. It might be 4321 or something

Molar mass if calcium nitrate

Answers

Answer:

About 164 grams

Explanation:

The molecular formula of calcium nitrate is \(Ca(NO_3)_2\). The molar mass of calcium is about 40, while the molar mass of nitrogen is about 14 and oxygen is about 16. Therefore, the molar mass of it is:

\(40+2(14+3(16))=40+2(14+48)=40+124=164\)

Hope this helps!

. At time t=0, an aluminum bar (thermal diffusivity k=0.86 ) of length Lcm with completely insulated lateral surfaces and constant thermal properties is removed from boiling water (uB​=100 degrees Celsius). Do the following i), ii), iii) for each of the scenarios, a-d, below i) Write down the initial-boundary value problem. That is, the PDE along with any initial and boundary conditions. ii) Without solving for u(x,t), describe the temperature distribution in the bar as t→[infinity] based on physical intuition. iii) Find the solution as t→[infinity] by solving the appropriate steady state equation. a) The two ends of the bar are immediately immersed in a medium with constant temperature 10 degrees Celsius. b) The end at x=0 is immersed in a medium with temperature 0 degrees Celsius and the end at x=L is completely insulated.

Answers

(i) The initial-boundary value problem for the given scenarios are as follows:

a) Scenario a:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 10, u(L, t) = 10 (constant temperature at the ends)

b) Scenario b:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 0 (temperature at x=0), ∂u/∂x(L, t) = 0 (thermal insulation at x=L)

(iii) The solution for the temperature distribution as time approaches infinity can be found by solving the appropriate steady state equation.

What is the expected temperature distribution in the bar as time approaches infinity?

(i) The initial-boundary value problem formulation states the partial differential equation (PDE) governing the temperature distribution in the aluminum bar, along with the initial condition and boundary conditions.

In scenario (a), both ends of the bar are immersed in a medium with a constant temperature of 10 degrees Celsius, while in scenario (b), the end at x=0 is immersed in a medium with temperature 0 degrees Celsius and the end at x=L is insulated.

(ii) As time approaches infinity, the temperature distribution in the bar tends to reach a steady state.

In scenario (a), the temperature throughout the bar will eventually approach a constant value of 10 degrees Celsius, since both ends are immersed in a medium with that temperature.

In scenario (b), the temperature at x=0 will approach 0 degrees Celsius, while the temperature at x=L will remain constant due to thermal insulation.

(iii) To find the solution as time approaches infinity, we need to solve the appropriate steady state equation.

In scenario (a), the steady state equation is ∂²u/∂x² = 0, which implies that the temperature gradient is zero throughout the bar, resulting in a constant temperature of 10 degrees Celsius.

In scenario (b), the steady state equation is ∂²u/∂x² = 0 with the boundary condition u(0) = 0, which implies a linear temperature distribution from 0 degrees Celsius at x=0 to a constant temperature at x=L due to insulation.

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Callie did a lab during which she investigated the difference in cellular respiration rates between two different types of corn: germinating and non-germinating. A germinating seed is one from which a plant has started to grow. A non-germinating seed is usually dry and a new plant has not yet emerged. The data that she gathered are displayed in the graph.

Which of the following statements are true concerning the data that Callie gathered during the lab? Choose the two that apply.

Graph has a horizontal label of time and a vertical label of mL of oxygen consumed. The germinating corn seed line extends from 0-1.6 at the far end of the graph. The non-germinating corn seed line extends from 0-0.2.
A. The germinating corn seed consumed more oxygen than the non-germinating corn seed.
B. The non-germinating corn seed produced more carbon dioxide than the germinating corn seed.
C. The non-germinating corn seed performed more cellular respiration than the germinating corn seed
D. The germinating corn seed produced more energy than the non-germinating corn seed.
E. The non-germinating corn seed performed cellular respiration and the germinating corn seed performed fermentation.

Answers

A germinating seed is one from which a plant has started to grow. A non-germinating seed is usually dry, and a new plant has not yet emerged. The germinating corn seed consumed more oxygen than the non-germinating corn seed. This statement is true.  Therefore, option A is correct.

What is germinating seed ?

A dry seed starts to absorb water through its seed coat when it comes into touch with damp soil or growing medium. The seed swells and the seed coat splits open as it absorbs more water. Small shoots and roots make up the embryo inside the seed. First to appear from the seed is the root.

The prerequisites for seed germination include oxygen, water, temperature, and, only for particular seeds, light. The sprouting of seeds is impacted when one or more of these are missing. Similar internal elements that impact this process include seed viability, dormancy, and embryonic maturity.

Thus, option A is correct.

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6. Neon has 10 electrons - 2 in the inner shell and 8 in the outer shell. This arrangement of 8 electrons in the
outer shell is extremely stable and makes neon inert, with a valence of zero. Sodium has 11 electrons - 2
in the first shell, 8 in the next shell, and I in the outer shell. Fluorine has 9 electrons - 2 in the first shell
and 7 in the outer shell. How could sodium and fluorine from a compound in which both elements would
be like neon with 8 electrons in the outer shell?

Answers

Let look at EC of Sodium(Na)

\(\\ \sf\longmapsto 1s^22s^22p^63s^1\)

valency= +1

Now look at EC of Fluorine

\(\\ \sf\longmapsto 1s^22s^22p^5\)

Valency=-1

Now the Compound will be

\(\\ \sf\longmapsto NaF\)

Calculate the mean kinetic energy {e1rans) in joules of the following molecules at 350 k: (a) he, (b) co2, and (c) uf6. explain your results.

Answers

The mean kinetic energy per molecule is , where  is the Boltzmann constant and T is the absolute temperature.

So at 1000°C, the T = 1273.15 K, kB=1.38 × 10-23, therefore the mean kinetic energy is 2.635 × 10⁻²⁰J.

What is Kinetic energy ?

The energy an item has as a result of motion is known as kinetic energy.

A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the item, which then moves at a new, constant speed. Kinetic energy is the type of energy that is transmitted and is dependent on the mass and speed attained.

Kinetic energy may be converted into other types of energy and transported between things. A flying squirrel may run into a chipmunk that is standing still, for instance. Some of the squirrel's original kinetic energy may have been transferred to the chipmunk or changed into another kind of energy after the impact.

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Which of the chemicals in the following chemical reaction is the base?
CH3OH + HF --> CH3COH2+ + F-

A.)CH3COH2+
B.)F-
C.)HF
D.)CH3OH

Which of the chemicals in the following chemical reaction is the base?CH3OH + HF --> CH3COH2+ + F-A.)CH3COH2+B.)F-C.)HFD.)CH3OH

Answers

D) CH3OH

Base is chemical which have hydroxide ion. so CH3OH is base

What is A,B and C in the following picture?

What is A,B and C in the following picture?

Answers

Answer:

A= Coconut oil, B= Water, C= Sea water

Explanation:

oil is dense, water will allow things to float, but not as well as sea water

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