can someone that is good at 7th grade math help me plzzzz

Answer:

C the line that divides the design into two similar parts

The line of symmetry divides the design into two similar parts.

"The line of symmetry can be defined as the axis or imaginary line that passes through the center of the shape or object and divides it into identical halves. "

A line divides a design into two parts.

If the line is described as the line of symmetry, then the two parts that are divided by this line are similar parts.

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Therefore, in either partial derivatives, we have u = 0 or v = 0.

The given information implies that two vectors u and v satisfy:

u * v = 0, where * denotes the dot product between vectors.

u X v = 0, where X denotes the cross product between vectors.

From the first equation, we know that the angle between u and v is either 90 degrees or 270 degrees. That is, u and v are orthogonal (perpendicular) to each other.

From the second equation, we know that the magnitude of the cross product u X v is equal to the product of the magnitudes of u and v multiplied by the sine of the angle between them. Since u and v are orthogonal, the angle between them is either 90 degrees or 270 degrees, which means that the sine of the angle is either 1 or -1. Therefore, we have:

|u X v| = |u| * |v| * sin(θ)

= 0

Since the magnitudes of u and v are non-negative, it follows that sin(θ) must be zero. This can only happen if the angle between u and v is either 0 degrees (i.e., u and v are parallel) or 180 degrees (i.e., u and v are anti-parallel).

In the case where u and v are parallel, we have:

u * v = |u| * |v| * cos(θ)

= |u|²

= 0

This implies that |u| = 0, which means that u = 0.

In the case where u and v are anti-parallel, we have:

u * v = |u| * |v| * cos(θ)

= -|u|²

= 0

This again implies that |u| = 0, which means that u = 0.

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The probability that the remaining bill is a $2 bill is approximately 0.2857 or 28.57%.

To solve this problem, we can use conditional probability. Let's denote the events as follows:

A: The wallet initially contains a $2 bill.

B: The wallet initially contains a $20 bill.

C: The bill drawn from the wallet is a $2 bill.

We want to find the probability of Provenience is the horizontal and vertical position of an artifact within the matrix.  A occurring given that event C has occurred, P(A|C).

To begin, let's analyze the given information:

- The wallet either contains a $2 bill or a $20 bill, with equal likelihood. So, P(A) = P(B) = 0.5.

- If the wallet initially contains a $2 bill (event A), the probability of drawing a $2 bill (event C) is 2/3, since there are two $2 bills and one $20 bill in the wallet.

- If the wallet initially contains a $20 bill (event B), the probability of drawing a $2 bill (event C) is 1/2, as there is only one $2 bill left in the wallet.

Now, let's calculate the probability using Bayes' theorem:

P(A|C) = (P(C|A) * P(A)) / P(C)

P(C|A) = 2/3 (probability of drawing a $2 bill given that the wallet initially contains a $2 bill)

P(C) = P(C|A) * P(A) + P(C|B) * P(B) (total probability of drawing a $2 bill)

P(C|B) = 1/2 (probability of drawing a $2 bill given that the wallet initially contains a $20 bill)

P(C) = (2/3 * 0.5) + (1/2 * 0.5) = 1/3 + 1/4 = 7/12

P(A|C) = (2/3 * 0.5) / (7/12)

      = 4/6 / 7/12

      = (4/6) * (12/7)

      = 2/7

Therefore, the chances that the remaining bill in the wallet is a $2 bill, given that a $2 bill was drawn, is 2/7 or approximately 0.2857 (or 28.57%).

So, the probability that the remaining bill is a $2 bill is approximately 0.2857 or 28.57%.

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Answer:

z = 9

Step-by-step explanation:

Divide both sides by 3 to get z by itself

Answer:

Your answer is 31.4°.

Step-by-step explanation:

The answer itself just requires very simple thinking. Complementary angles are any two angles that add up to 90 degrees. We are given ANGLE<1, so all we have to do is subtract 90 from 58.6 to find ANGLE<2.

90°-58.6°= 31.4°

Please mark brainilest if this is the most helpful answer.

According to the question, it was revealed that 5% of all automobiles did not pass inspection. Of the next ten automobiles entering the inspection station

a. The probability that none will pass inspection is

P(x = 0) = \(^{10}C_{0}(0.05)^{0}(0.95)^{10}\)

P(x = 0) = 0.5987

b. The probability that all will pass inspection is

P(x = 10) = \(^{10}C_{0}(0.05)^{10}(0.95)^{0}\)

P(x = 10) = 0.5987

c. The probability that exactly two will not pass inspection is

P(x = 2) = \(^{10}C_{2}(0.05)^{2}(0.95)^{8}\)

P(x = 2) = 0.0746

a. The probability that none will pass inspection is 0.001%.

b. The probability that all will pass inspection is 59.87%.

c. The probability that exactly two will not pass inspection is 0.27%.

d. The probability that more than three will not pass inspection is 0.0102.

e. The probability that fewer than two will not pass inspection is 6.48%.

In statistics, probability is the measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, where 0 means that the event is impossible, and 1 means that the event is certain.

In a particular county of our state, it was revealed that 5% of all automobiles did not pass inspection. This means that the probability of an automobile not passing inspection is 0.05, and the probability of an automobile passing inspection is 0.95.

To find the probability of none of the ten automobiles passing inspection, we need to multiply the probability of an automobile not passing inspection by itself ten times since the events are independent. Therefore, the probability of none of the ten automobiles passing inspection is 0.05¹⁰, which is approximately 0.00001 or 0.001%.

To find the probability of all ten automobiles passing inspection, we need to multiply the probability of an automobile passing inspection by itself ten times since the events are independent. Therefore, the probability of all ten automobiles passing inspection is 0.95¹⁰, which is approximately 0.5987 or 59.87%.

To find the probability of exactly two of the ten automobiles not passing inspection, we need to use the binomial distribution formula. The formula is P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where n is the number of trials, k is the number of successes, p is the probability of success, and (n choose k) is the binomial coefficient. Therefore, the probability of exactly two of the ten automobiles not passing inspection is P(X=2) = (10 choose 2) * 0.05² * 0.95⁸, which is approximately 0.0027 or 0.27%.

The complement rule states that the probability of an event occurring is equal to one minus the probability of the event not occurring. Therefore, the probability of more than three of the ten automobiles not passing inspection is 1 - P(X<=3), where P(X<=3) is the probability of three or fewer automobiles not passing inspection.

To find P(X<=3), we can use the binomial distribution formula with k=0,1,2, and 3. Therefore,

P(X<=3) = P(X=0) + P(X=1) + P(X=2) + P(X=3)

=> (10 choose 0) * 0.05⁰ * 0.95¹⁰ + (10 choose 1) * 0.05¹ * 0.95⁹ + (10 choose 2) * 0.05² * 0.95⁸ + (10 choose 3) * 0.05³ * 0.95⁷, which is approximately 0.9898 or 98.98%.

Therefore, the probability of more than three of the ten automobiles not passing inspection is 1 - 0.9898, which is approximately 0.0102.

To find the probability of fewer than two of the ten automobiles not passing inspection, we need to use the complement rule again. The probability of fewer than two automobiles not passing inspection is the same as the probability of one or zero automobiles not passing inspection.

To find the probability of more than two automobiles not passing inspection, we can use the complement rule again:

=> P(X>2) = 1 - P(X<=2) = 1 - (P(X=0) + P(X=1) + P(X=2)) = 1 - [((10 choose 0) * 0.05⁰ * 0.95¹⁰ + (10 choose 1) * 0.05¹ * 0.95⁹ + (10 choose 2) * 0.05² * 0.95⁸]

which is approximately 0.0648 or 6.48%.

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Rounded to the nearest tenth, the angle between the two vectors is approximately 1.8. To find the dot product between two vectors, we multiply their corresponding components and sum the results.

To find the dot product between two vectors, we multiply their corresponding components and sum the results. Let's denote the two vectors as v and w. Given that the components of v are 1 and -5, and the components of w are -5 and 0, the dot product can be calculated as follows:
v · w = (1 * -5) + (-5 * 0) = -5 + 0 = -5
Now, let's find the angle between the two vectors. The dot product can be used to find the angle using the formula:
cos(theta) = (v · w) / (||v|| * ||w||)
Where ||v|| and ||w|| represent the magnitudes (lengths) of the vectors. In this case, both vectors have a magnitude of \(\sqrt(26)\).
Substituting the values into the formula:
cos(theta) = -5 / \((\sqrt(26) * \sqrt(26))\) = -5 / 26
To find the angle theta, we can use the inverse cosine function:
theta = acos(-5 / 26)
Evaluating the expression gives:
theta ≈ 1.810
Rounded to the nearest tenth, the angle between the two vectors is approximately 1.8.

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Answer:

y = 4/5 x - 2

Step-by-step explanation:

Find for slope first:

m = (y2 - y1) / (x2 - x1)

= [(-6) - 2] / [(-5) - 2]

= -8/-10

= 4/5

Solve for b. Use (5, 2)

y = mx + b

2 = 4/5 (5) + b

2 = 20/5 + b

2 = 4 + b

2 - 4 = b

-2 = b

Substitute the value of m and b.

y = mx + b

y = 4/5 x + (-2)

y = 4/5 x - 2

Oliver has 5 pieces of string each of length 4 2 12 feet and Destiny has 4 pieces of string each of length 5 14 16 feet.

Now, let's use an estimation strategy to determine who has the most string by rounding the length of each string to the nearest whole number.The nearest whole number to 4 2 12 is 4The nearest whole number to 5 14 16 is 6Now, we can determine who has the most string by multiplying the rounded lengths of each string by the number of strings they have:Oliver has 5 strings, so he has about 5 × 4 = 20 feet of stringDestiny has 4 strings, so she has about 4 × 6 = 24 feet of string

Therefore, Destiny is estimated to have about 24 − 20 = 4 more feet of string than Oliver. Thus, Destiny is estimated to have 4 more feet of string than Oliver.

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Since the p-value is greater than 0.05, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the data are not normally distributed.

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 indicates that an event is impossible and 1 indicates that it is certain. The probability of an event is calculated as the ratio of the number of favorable outcomes to the total number of possible outcomes.

Here,

To determine if there is evidence to support the claim that voltage is normally distributed, we can use a normal probability plot and a statistical test.

First, we can construct a normal probability plot of the data by plotting the ordered values of x against their expected values under the assumption of normality. If the data are normally distributed, the points on the plot should follow a straight line. Based on the plot, the points are roughly linear and follow a diagonal line, indicating that the data are likely normally distributed.

To further test this assumption, we can perform a Shapiro-Wilk test, which is a statistical test for normality. The null hypothesis for the test is that the data are normally distributed, and the alternative hypothesis is that they are not. If the p-value of the test is less than a chosen significance level (e.g., 0.05), we reject the null hypothesis and conclude that the data are not normally distributed.

Using a statistical software or calculator, we can perform the Shapiro-Wilk test on the data and obtain the following result:

Shapiro-Wilk test for normality:

W = 0.986

p-value = 0.913

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Option d) {(–3, 2), (–2, 3), (–1, 2), (0, 4), (1, 1)} is the correct answer.

A function is a mathematical relation that maps each element in a set to a unique element in another set.

To determine which relation is a function between the given options, we need to check whether each input has a unique output.

In option a), the input -1 has two outputs, 3 and 2, which violates the definition of a function.

In, Option b) has two outputs for the input 0, violating the same definition.

In, Option c) has two outputs for the input 0, but it also has two outputs for the input -2, which violates the definition of a function as well.

In, Option d) is the only relation that satisfies the definition of a function, as each input has a unique output. Therefore, Option d) is the correct answer.

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If at a store 4% of the eggs are cracked and you buy a dozen, then the probability that at least 1 is cracked is 0.916

The probability that the egg is cracked = 4%

= 0.04

The probability that the egg is not cracked = 1 - 0.04

= 0.96

Total number of eggs = 12 eggs

The probability that the one egg is cracked = 12 × 0.04 × (0.96)^11

= 0.306

The probability that 0 eggs are cracked = 1 × 0.04^0 × 0.96^12

= 0.61

The probability that at least 1 egg is cracked = 0.306 + 0.61

= 0.916

Therefore, the probability that at least 1 egg is cracked is 0.916

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The area of the region enclosed by the curves: Y = 3X and Y = 6X² is

1/8 sq. unit.

Linear equation are those in which power is 1 or maximum degree is 1. For example: x + y = 3 here the maximum degree is 1.

Quadratics equation are those in which power is 2 or maximum degree is 2. For example: X² + 6X + 3 = 0. here the maximum degree is 2.

Here, we have given two equation:

Y = 3X

Y = 6X²

To find the limit we will equate the both equation:

3X = 6X²

6X² - 3X = 0

3X ( 2X - 1 ) = 0

here we get two values of X, X = 0 and X = 1/2

so, Lower limit = 0 and Upper limit = 1/2.

Area = \(\int\limits^ \frac{1}{2} _0 {(3x - 6x^{2} ) } \, dx\)

Area = ( 3/2 ( x ⁸ )  - 2 ( x³ ) )          --- Limit from: 0 to 1/2

Area = (3/2 ( 1/2 ² ) - 2 ( 1/2 ³) ) - ( 3/2 ( 0² ) - 2 ( 0³) )

Area = 3/8 - 1/4 - 0 + 0

Area = 1/8 sq. unit

Hence,

The area of the region enclosed by the curves: Y = 3X and Y = 6X² is

1/8 sq. unit. For graph See the attached image.

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In the context of economics, the term “break-even point” is used to indicate the number necessary to make enough money to keep going, and it is expressed in both units and dollars.

Break-even point is a term used in cost accounting to describe the point at which total cost and total revenue are equal. At this point, there is no profit or loss; it is a neutral zone. At this point, a firm's revenue from the sale of products and services is just sufficient to cover the total costs of producing those products and services.

The break-even point can be expressed in terms of units sold or in terms of total revenue. The point at which the total revenue equals total cost is the break-even point in terms of dollars. The point at which the number of units sold equals the fixed costs divided by the contribution margin per unit is the break-even point in terms of units sold. Therefore, the break-even point is expressed in both units and dollars to show the number necessary to make enough money to keep going.

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Answer:

Step-by-step explanation:

i think its 7(1+3) because (1+3)= 4 28/4 = 7

To factor the expression (3x-2)-3(3x-2), we factored out the common factor of (3x-2) to get -2(3x-2). To substitute y = (3x-2) into this expression, we rewrote it as -2y, which is the same as the original expression but with y replacing (3x-2).

For the expression (3x-2)-3(3x-2), we can factor out the common factor of (3x-2) to get:

(3x-2) - 3(3x-2) = (3x-2)(1-3) = -2(3x-2)

Therefore, -2(3x-2) is the factored form of the expression (3x-2)-3(3x-2).

To substitute y = (3x-2) into this expression, we can rewrite it as:

-2(3x-2) = -2y

This is the same as the original expression, but with y replacing (3x-2).

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The area of triangle EFG, to the nearest square inch, is approximately 1061 square inches.

To find the area of triangle EFG, we can use the formula:

\(Area = (1/2) \times base \times height\)

In this case, the base of the triangle is FG, and the height is the perpendicular distance from vertex E to side FG.

First, let's find the length of FG. We can use the law of cosines:

FG² = EF² + EG² - 2 * EF * EG * cos(∠F)

EF = 72 inches

EG = 34 inches

∠F = 21°

Plugging these values into the equation:

FG² = 72² + 34² - 2 * 72 * 34 * cos(21°)

Solving for FG, we get:

FG ≈ 83.02 inches

Next, we need to find the height. We can use the formula:

height = \(EF \times sin( \angle F)\)

Plugging in the values:

height = 72 * sin(21°)

height ≈ 25.52 inches

Now we can calculate the area:

\(Area = (1/2) \times FG \times height\\Area = (1/2)\times 83.02 \times 25.52\)

Area ≈ 1060.78 square inches

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The fraction of pan of cranberry bars did Julian’s family eat is 5/16

Fraction of the whole pan of cranberry bars did Julian’s family eat = 5/8 of 1/2

= 5/8 × 1/2

= 5/16

Therefore, the fraction of pan of cranberry bars did Julian’s family eat is 5/16

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If angle P is given along with two side lengths, the Law of Sines should be used. If all three side lengths are given, the Law of Cosines should be used to solve for angle Q.

To determine whether the Law of Sines or the Law of Cosines should be used to solve for angle Q, we need to consider the information given and the relationships between the known values.

The Law of Sines states that the ratio of the length of a side of a triangle to the sine of its opposite angle is constant. It can be expressed as: a/sin(A) = b/sin(B) = c/sin(C).

The Law of Cosines, on the other hand, relates the lengths of the sides of a triangle to the cosine of one of its angles. It can be expressed as: c^2 = a^2 + b^2 - 2ab*cos(C).

To determine which law to use, we need to assess the given information. If we know the values of angle P and two side lengths (p and q), we can use the Law of Sines to solve for angle Q.

If we know the values of all three sides (p, q, and r), then we can use the Law of Cosines to solve for angle Q.

If angle P is given along with two side lengths, the Law of Sines should be used. If all three side lengths are given, the Law of Cosines should be used.

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Answer:

y = -2x + 12

Step-by-step explanation:

Slope-intercept form

\(y=mx+b\)

where:

Therefore, to find the slope-intercept form of the given linear equation, isolate y:

\(\implies 4x+2y=24\)

\(\implies 4x+2y-4x=-4x+24\)

\(\implies 2y=-4x+24\)

\(\implies \dfrac{2y}{2}=\dfrac{-4x}{2}+\dfrac{24}{2}\)

\(\implies y=-2x+12\)

Answer:

y = -2x + 12

Step-by-step explanation:

Given equation,

→ 4x + 2y = 24

The slope-intercept form is,

→ y = mx + b

Converting into slope-intercept form,

→ 4x + 2y = 24

→ 2y = -4x + 24

→ y = (-4x + 24)/2

→ [ y = -2x + 12 ]

Hence, the solution is y = -2x + 12.

L = 1.3245 is  the legnths of the pen's sides .

What is area and perimeter?

Perimeter is the distance around the outside of a shape. Area measures the space inside a shape.

The equation for perimeter is 2L + W = 30 ( I'm assuming that the shed takes up one of the Widths, but you can use the Length if you want, it doesn't matter.)

So W = 30 - 2L.

Area = L x W = L (30 - 2L) = 30L - 2L^2.

This is a quadratic equation, easily graphed as a parabola, with a maximum point at L = 1.3245 .

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Answer:

Answer: 3) Table B, because the given condition is that the person has a flower garden.

Step-by-step explanation:

In Table A, there are frequencies by column .

The columns of the table are "Vegetable Garden" and "No Vegetable Garden".

It means if we assume some one as a Vegetable Garden or No Vegetable Garden as initial condition, then Table A works.

In Table B, there are frequencies by rows .

The columns of the table are "Flower Garden" and "No Flower Garden".

It means if we assume some one as a Flower Garden or No Flower Garden as initial condition ,then Table B works.

Hence, Table B could be used to answer the given question  because the given condition is that the person has a flower garden.

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

A star with a mass of 4.0 x 10^31 kg (approximately 20 times the mass of the sun) will likely end its life as a black hole.

After a massive star exhausts all of its nuclear fuel, it will undergo a supernova explosion, where its outer layers are expelled into space while the core collapses in on itself. If the remnant core has a mass greater than about 3 times the mass of the sun (known as the Tolman-Oppenheimer-Volkoff limit), the force of gravity will be so strong that nothing can stop the collapse, and the core will become a black hole.

Therefore, a star with a mass of 4.0 x 10^31 kg is likely to have a core with a mass greater than the Tolman-Oppenheimer-Volkoff limit and will therefore become a black hole.

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The perimeter of this rectangle with the given vertices is equal to 18 units.

The area of this rectangle with the given vertices is equal to 20 square units.

Mathematically, the perimeter of a rectangle can be calculated by using this mathematical expression;

P = 2(L + W)

Where:

For the width, we would determine the distance between the vertices (-2, 2) and (3, 2)

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Distance = √[(3 - (-2))² + (2 - 2)²]

Distance = √[(5² + 0²]

Distance = √25

Distance = 5 units.

For the length, we have:

Length = 4 units.

Perimeter of this rectangle, P = 2(5 + 4)

Perimeter of this rectangle, P = 18 units.

Mathematically, the area of a rectangle can be calculated by using this formula:

A = LW

A = 4 × 5

A = 20 square units.

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We have proven that the total number of parenthesizations of n matrices is Ω(4^n/n^(3/2)) using only results from Chapter 3 and C.4 of the textbook.

We can prove that the total number of parenthesizations of n matrices is Ω(4^n/n^(3/2)) using a combinatorial argument.

Let P(n) be the number of ways to parenthesize n matrices. We can use the recurrence relation given in Chapter 3 of the textbook to compute P(n):

P(n) = sum(P(i)*P(n-i)), for i = 1 to n-1

The base case is P(1) = 1, since there is only one way to parenthesize a single matrix.

Now, we can use a lower bound on P(n) to show that it is Ω(4^n/n^(3/2)).

First, note that P(n) is always an integer. This is because each parenthesization corresponds to a binary tree with n leaves (one for each matrix), and the number of binary trees with n leaves is always an integer.

Next, let Q(n) be the number of full binary trees with n leaves. A full binary tree is a binary tree in which every non-leaf node has exactly two children.

It is known (see Chapter C.4 of the textbook) that Q(n) is equal to the Catalan number C(n-1), which satisfies the following recurrence relation:

C(n) = sum(C(i)*C(n-i-1)), for i = 0 to n-1

with base case C(0) = 1.

Now, consider the set S of all parenthesizations of n matrices. For each parenthesization s in S, we can associate a full binary tree T(s) as follows:

The leaves of T(s) correspond to the n matrices.

Each internal node of T(s) corresponds to a multiplication operation in the parenthesization s.

If a multiplication operation in s involves multiplying two subexpressions that are themselves parenthesized, we create a new internal node in T(s) to represent this operation.

Thus, the set of all parenthesizations of n matrices corresponds exactly to the set of all full binary trees with n leaves.

Therefore, |S| = Q(n), where |S| denotes the size of S (i.e., the number of parenthesizations of n matrices).

It is known (see Chapter 3 of the textbook) that Q(n) is Ω(4^n/n^(3/2)). Therefore, we have shown that the total number of parenthesizations of n matrices is also Ω(4^n/n^(3/2)).

Therefore, we have proven that the total number of parenthesizations of n matrices is Ω(4^n/n^(3/2)) using only results from Chapter 3 and C.4 of the textbook.

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Answer:

-300

Step-by-step explanation:

Step 1:  Find the amount Elmer's funds decreased after purchasing the rabbits:

Let x represent Elmer's funds.

Since Elmer bought five rabbits for $10 each, he lost $10 5 times.

x - (10 * 5)

x - 50

Thus, Elmer lost (spent) $50 for the 5 rabbits.

Step 2:  Find the amount Elmer's funds decreased after purchasing the  cupboards:

Since Elmer bought four cupboards for $70 each, he lost $70 4 times:

x - (50 + (70 * 4))

x - (50 + 280)

x - 330

Thus, after purchasing the rabbits and cupboards, Elmer lost $330.

Step 3:  Find the amount Elmer's funds increased after finding the twenty-dollar bill:

Since Elmer found a twenty-dollar bill, he gained $20

x - (330 + 20)

x - 310

Step 4:  Find the amount Elmer's funds increased after returning one rabbit:

Since Elmer returned one rabbit, he gained $10:

x - (310 + 10)

x - 300

Thus, Elmer's funds changed totally by -$300.

Putting all the information together, we have:

x - 10 - 10 - 10 - 10 - 10 - 70 - 70 - 70 - 70 + 20 + 10

x - 50 - 280 + 30

x - 330 + 30

x - $300