Yes, it is possible to achieve the best mechanical and surface qualities simultaneously in Selective Laser Sintering (SLS) by optimizing the process parameters and material selection. SLS is an additive manufacturing technique that uses a laser to selectively sinter powdered material, layer by layer, to create a solid object.
To achieve the best mechanical properties, it is important to use high-quality powder materials, maintain optimal temperature control, and select the appropriate laser power and scanning speed. These factors will ensure the proper bonding of powder particles, resulting in a stronger, more durable part. For the best surface quality, it is crucial to minimize the roughness and porosity typically associated with SLS parts. This can be done by using finer powder particles, optimizing the layer thickness, and employing post-processing techniques, such as polishing or coating, to improve the surface finish. In summary, by carefully selecting materials, controlling the process parameters, and utilizing post-processing techniques, it is possible to achieve both excellent mechanical and surface qualities in SLS-produced parts.
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How many 10" diameter circles can be cut from a semicircular shape that has a 20"
diameter and a flat-side length of 25"?
9514 1404 393
Answer:
1
Explanation:
Only one such circle can be drawn. The diameter of the 10" circle will be a radius of the semicircle. In order for the 10" circle to be wholly contained, the flat side of the semicircle must be tangent to the 10" circle. There is only one position in the figure where that can happen. (see attached).
Answer:
1The diameter measurement of a semi circle having a measure of 10" diameter , 20" diameter and a length of 25.Use the function T(V1, V2: Vz) = (2v, +v2: V; -v) to find the preimage of (4, -1) : (1, -2, 2) (-1,2,2) (-2, 1, t), where t is any real number (1, 2, t), where t is any real number (1, -2, t), where t is any real number
To find the preimage of a given point under the function T(V1, V2, Vz) = (2V1 + V2, Vz; -V1), we need to substitute the coordinates of the given point into the function and solve for the variables V1, V2, and Vz. Let's evaluate each case:
1.For the point (4, -1) : (1, -2, 2):
Substituting the coordinates into the function, we have:
2V1 + V2 = 4
Vz = -1
-V1 = 2
From the third equation, we can solve for V1: V1 = -2.
Substituting V1 = -2 into the first equation, we have: 2(-2) + V2 = 4
Simplifying, we get: V2 = 8.
Therefore, the preimage of (4, -1) : (1, -2, 2) under the given function is (-2, 8).
2.For the point (-1, 2, 2):
Substituting the coordinates into the function, we have:
2V1 + V2 = -1
Vz = 2
-V1 = 2
Solving these equations, we find: V1 = -2, V2 = -3.
Therefore, the preimage of (-1, 2, 2) under the given function is (-2, -3).
3.For the point (-2, 1, t), where t is any real number:
Substituting the coordinates into the function, we have:
2V1 + V2 = -2
Vz = 1
-V1 = t
From the third equation, we can solve for V1: V1 = -t.
Substituting V1 = -t into the first equation, we have: 2(-t) + V2 = -2
Simplifying, we get: V2 = -2 + 2t.
Therefore, the preimage of (-2, 1, t) under the given function is (-t, -2 + 2t).
4.For the point (1, 2, t), where t is any real number:
Substituting the coordinates into the function, we have:
2V1 + V2 = 1
Vz = 2
-V1 = t
From the third equation, we can solve for V1: V1 = -t.
Substituting V1 = -t into the first equation, we have: 2(-t) + V2 = 1
Simplifying, we get: V2 = 1 + 2t.
Therefore, the preimage of (1, 2, t) under the given function is (-t, 1 + 2t).
5.For the point (1, -2, t), where t is any real number:
Substituting the coordinates into the function, we have:
2V1 + V2 = 1
Vz = -2
-V1 = t
From the third equation, we can solve for V1: V1 = -t.
Substituting V1 = -t into the first equation, we have: 2(-t) + V2 = 1
Simplifying, we get: V2 = 1 + 2t.
Therefore, the preimage of (1, -2, t) under the given function is (-t, 1 + 2t).
In summary, the preimages of the given points under the function T(V1, V2, Vz) = (2V1 + V2, Vz; -V1) are:
For (4, -1) : (1, -2, 2), the preimage is (-2, 8).
For (-1, 2, 2), the preimage is (-2, -3).
For (-2, 1, t), where t is any real number, the preimage is (-t, -2 + 2t).
For (1, 2, t), where t is any real number, the preimage is (-t, 1 + 2t).
For (1, -2, t), where t is any real number, the preimage is (-t, 1 + 2t).
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The moment of inertia is a geometric property of a structural
element. Describe how it can be altered and
how it influences the stress due to bending in a beam.
Moment of Inertia is the measure of a structure's resistance to rotation. It is the integral sum of an element's mass and its distance from the axis of rotation.
A moment of inertia can be changed by adjusting the shape of a structure to change the distance of mass from the axis of rotation. A structure's moment of inertia is proportional to the stress due to bending.
A structure with a higher moment of inertia will have a lower stress due to bending than a structure with a lower moment of inertia. A beam's moment of inertia is dependent on its shape.
Rectangular, circular, or I-beam shapes are popular for their ability to handle bending stress. Wider beam shapes distribute bending stress more evenly over the beam's cross-sectional area, resulting in a lower bending stress.
I-beams are designed with a high moment of inertia to resist bending, making them a popular choice for construction. A higher moment of inertia ensures a stronger beam that can better resist bending stress.
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What is "Engineering"?
A tank has a gauge pressure of 552 psi. The cover of an inspection port on the tank has a surface area of 18 square inches. What is the total force the cover is experiencing.
Answer:
44197.55 N
Explanation:
From the question,
Pressure of the pressure guage (P) = Total force experienced by the cover (F)/Area of the cover (A)
P = F/A................ Equation 1
make F the subeject of the equation
F = P×A............... Equation 2
Given: P = 552 psi = (552×6894.76) = 3805907.52 N/m², A = 18 square inches = (18×0.00064516) = 0.01161288 m²
Substitute these values into equation 2
F = ( 3805907.52×0.01161288)
F = 44197.55 N
Which of the following choices accurately contrasts a categorical syllogism with a conditional syllogism?
An argument constructed as a categorical syllogism uses deductive reasoning whereas an argument constructed as a conditional syllogism uses inductive reasoning.
A categorical syllogism contains two premise statements and one conclusion whereas a conditional syllogism contains one premise statement and one conclusion.
A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.
An argument constructed as a categorical syllogism is valid whereas an argument constructed as a conditional syllogism is invalid.
Answer:
The correct option is - A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.
Explanation:
As,
Categorical syllogisms follow an "If A is part of C, then B is part of C" logic.
Conditional syllogisms follow an "If A is true, then B is true" pattern of logic.
So,
The correct option is - A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.
The criminal and traffic code requires that a driver must have a valid driver's license in his/her
immediate possession at any time when operating a motor vehicle.
True
False
Answer:
true
Explanation:
the answer is true because if u don't have a valid license when operating a vehicle and you get pulled over you will get in trouble i know this because my parents got in trouble for it once
What type of socket is best used on rusted or severely tight fasteners?
Use a 6-point socket for a traditional hex-head bolt. That will reduce the chance of accidentally rounding the head or nut.
3. Assertive communication means:
A. Confidently and directly communicating what you think and feel, without being aggressive
or passive
B.O Confidently saying what you think and feel, even If It means overshadowing someone
else's feelings
C.O Saying what you think and feel only If and when the other party gives you permission to
do so
D. None of the above
Answer:
A. Confidently and directly communicating what you think and feel, without being aggressive or passive.
Explanation:
Assertive communication is the ability to express both positive and negative ideas in a way that it is a honest and direct message. It doesn't mean to say things to the other person with the intent of causing harm or making them feel better, it's just saying things as they are.
Problem 2: Question
Consider the circuit diagram below. Reduce this circuit to an equivalent circuit containing only a voltage source and a single resistor.
Note: Your conclusion should state the value of the resistor in the reduced circuit.
Select the best answer for the question. 4. What's the average value of an AC voltage that has a maximum peak voltage of 80 VAC? O A. 50.96 VAC O B. 160 VAC O C. 56.56 VAC O D. 38.31 VAC O Mark for review (Will be highlighted on the review page) << Previous Question Next Question >> M
Answer:
C. 56.56 VAC
Explanation:
The meaning of "average" is unclear in this context.
If the waveform is sinusoidal, or any other symmetrical shape, its average value is zero.
If the waveform is a full-wave rectified sinusoid, its average value is 2/π times the peak, about 50.93 V.
If you are concerned with the RMS value (not the average), that is 1/√2 times the peak, about 56.57 VAC.
Question 5(Multiple Choice Worth 2 points)
The is the amount of time that the camera lets light in to create the photograph.
Aperture
Sensor time
Shutter speed
Power release
Answer:
I believe it is sensor time
Write a Python program named DataByteConvert that asks the user to enter a Data in
MegaBytes (MB) Data is entered only in MegaBytes. The program will then present the
following menu of selections:
1. Convert to Bytes
2. Convert to KiloBytes (KB)
3. Convert to GigaBytes(GB)
4. Convert to TerraBytes(TB)
5. Quit the program
The program will convert the data in MegaBytes(MB) to bytes, kilobytes(KB), GigaBytes(MB),
or TerraBytes(TB), depending on the user's selection rounded to six decimals. Here are the
specific requirements:
• Write a void method named showKiloBytes, which accepts the number of
MegaBytes(MB) as an argument. The method should display the argument
converted to kilobytes(KB). Convert the MB to KB.
• Write a void method named showGigaBytes, which accepts the number of
MegaBytes(MB) as an argument. The method should display the argument
converted to Gigabytes(GB).
• Write a void method named show TerraBytes, which accepts the number of
MegaBytes(MB) as an argument. The method should display the argument
converted to TerraBytes(TB). Convert the MB to TB.
• Write a void method named showBytes, which accepts the number of MegaBytes
(MB) as an argument. The method should display the argument converted to
Bytes(B). Convert the MB to B
• Write a void method named menu that displays the menu of selections. This
method should not accept any arguments.
1. The program should continue to display the menu until the user enters 5 to quit the
program.
2. The program should not accept negative numbers for the data in MegaBytes.
3. If the user selects an invalid choice from the menu, the program should display an error
message.
4. Use Exponential format if needed when converted {:e) formats ...)
5. Use
6. Add comments to show what each function does.
The program to convert MegaBytes to either Bytes, KiloBytes, GigaBytes, or TeraBytes is found in the attached image.
The program defines five helper functions to help the program do its work. The functions are:
showBytes: Accepts an argument in megabytes, converts it by multiplying by 1048576, and prints the resultshowKiloBytes: Accepts an argument in megabytes, converts it by multiplying by 1024, and prints the resultshowGigaBytes: Accepts an argument in megabytes, converts it by dividing by 1024, and prints the resultshowTeraBytes: Accepts an argument in megabytes, converts it by dividing by 1048576, and prints the resultmenu: Displays the menu of options to either convert or quit the programWithin the Main Program, a while loop is used to make sure the menu continues to be presented to the user until the user selects the option to quit.
The inner while loop makes sure the user enters an option within the menu.
Once the user enters an option to convert, the program requests the value to be be converted, in MegaBytes. then an if statement selects the correct conversion function.
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The maximum voltage in a cooling system should not exceed ______ volts.
Answer:2%
When the voltages between the three phases are not equal, the current increases dramatically in the motor winding's, and if allowed to continue, the motor will be damaged.
Explanation:
The following problem refers to triangle ABC, find all missing parts. Round degrees to 1 decimal places and
sides to the nearest whole number.
A = 36.5°C = 67.5°, c = 224 inches
A=
В.
C
O
O
490 do
a =
inches
inches
inches
C-
Answer:
A =41 .....
......
......
....C=21
The angle of attack of a wing directly controls the A) angle of incidence of the wing. B) amount of airflow above and below the wing. C) distribution of pressures acting on the wing.
The angle of attack of a wing directly controls the C) distribution of pressures acting on the wing.
When the angle of attack of a wing is increased, the air moving over the curved upper surface of the wing must travel a greater distance and faster than the air moving beneath the wing's flat lower surface. This creates an area of lower air pressure above the wing and an area of higher air pressure beneath the wing, resulting in lift. The greater the angle of attack, the greater the lift produced.
However, if the angle of attack is too great, the airflow over the wing may separate, causing a loss of lift and potentially leading to a stall. Therefore, proper control of the angle of attack is crucial for safe and efficient flight.
Option C is answer.
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Type the correct answer in the box. Spell all words correctly.
Who focuses on planning a long-term business?
focus on planning a long-term business.
Reset
Next
Explanation:
A business man who really focus on victory achieved through a right procedure will focus on long-term planning.
Let us understand what a short-term and long-term planning is.
Short-term will plan only for two-three years. But a long-term plan will look for future five years income projection, plan of expansion, bigger goals, etc.
A business man is the person who take risks and achieve more. A victory can be achieved in many ways one is taking bigger risks, next is focusing on long-term plans
If this is wrong, give me the answer choices so I know what's right or wrong. I'll edit the question if given to me.
Observe the following recurrences, use master theorem to solve those that can be solved(Please indicate which case). For those that cannot be solved directly, try to devise some guess of the solution, and then use substitution method to prove your guess.
a) T(n)=4T(n/3)+nlgn.
b) T(n)=4T(n/2)+n^2 √n.
c) T(n)=T(n/2)+T(n/4)+T(n/8)+n.
The Master Theorem is a tool used to solve recurrence relations, which are mathematical expressions that describe the run time of a recursive algorithm in terms of its input size. The theorem provides three cases, each of which corresponds to a different type of relationship between the size of the input and the run time of the algorithm.
a) T(n) = 4T(n/3) + nlogn. This recurrence can be solved by case 2 of the Master Theorem, where T(n) = O(nlog^k n) for some constant k. Here, the dominant term is nlogn and the power of log is 1, so k = 1. Thus, the solution is T(n) = O(nlogn).
b) T(n) = 4T(n/2) + n^2√n. This recurrence cannot be directly solved by the Master Theorem. However, a guess of the solution could be T(n) = O(n^(5/2)). By substitution method, it can be proven that T(n) = O(n^(5/2)).
c) T(n) = T(n/2) + T(n/4) + T(n/8) + n. This recurrence can be solved by case 3 of the Master Theorem, where T(n) = O(n^log_b a). Here, the dominant term is n, the size of the subproblems is halved at each step (b = 2), and the work done at each step is a constant (a = 1). Thus, log_2 1 = 0 and the solution is T(n) = O(n).
In conclusion, the Master Theorem is a powerful tool for solving recurrence relations, but it is not always applicable. In some cases, a guess and proof method is needed to find the solution.
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how do architects collaborate with the lean-agile center of excellence
Architects collaborate with the Lean-Agile Center of Excellence (LACE) by providing architectural guidance, participating in agile ceremonies, and contributing to continuous improvement efforts.
Architectural Guidance: Architects collaborate with LACE by providing architectural guidance and expertise, ensuring that software development aligns with architectural principles and standards. They help define architectural strategies, patterns, and guidelines for development teams to follow.
Agile Ceremonies: Architects actively participate in agile ceremonies such as sprint planning, backlog refinement, and sprint reviews. They contribute by providing input on architectural considerations, helping prioritize user stories, and addressing technical debt.
Continuous Improvement: Architects work closely with LACE to promote continuous improvement. They contribute to retrospectives, sharing insights and lessons learned from architectural perspectives. They identify areas for improvement and propose architectural changes to enhance development efficiency, scalability, and quality.
Collaboration and Communication: Architects collaborate closely with LACE, ensuring effective communication between development teams, product owners, and stakeholders. They provide architectural guidance and address any concerns or challenges that arise during the agile development process.
Overall, architects play a critical role in aligning architecture and agile practices, fostering collaboration, and driving continuous improvement efforts within the Lean-Agile Center of Excellence.
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The performance tables of an aircraft for takeoff and climb are based on A— pressure/density altitude. B— cabin altitude. C— true altitude.
The performance tables of an aircraft for takeoff and climb are based on A— pressure/density altitude.
The performance tables of an aircraft for takeoff and climb are typically based on pressure/density altitude. Pressure altitude refers to the altitude above the standard pressure level, while density altitude takes into account variations in atmospheric pressure and temperature, which affect air density. By using pressure/density altitude, the aircraft's performance calculations can be adjusted to account for changes in atmospheric conditions.
Pressure/density altitude is crucial in aircraft performance because it affects various factors that impact the aircraft's takeoff and climb capabilities. As altitude increases, the air density decreases, resulting in reduced engine performance and less lift generation. This reduction in performance affects parameters such as takeoff distance, climb rate, and fuel consumption. Therefore, by considering pressure/density altitude, pilots and aircraft performance engineers can accurately assess the aircraft's capabilities under different atmospheric conditions and make informed decisions regarding takeoff and climb performance.
Hence, pressure/density altitude is the key parameter used in aircraft performance tables for takeoff and climb. It accounts for changes in atmospheric conditions and allows pilots and performance engineers to determine the aircraft's performance capabilities accurately. By using pressure/density altitude, the aircraft's performance calculations can be adjusted to ensure safe and efficient operations during takeoff and climb phases.
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For Python, the term data type can be used interchangeably with what other term? O index O class O object O sequence Which category of data types represents an ordered collection of values? O numeric O sequence O boolean O dictionary All Python data types are immutable. O True O False Python is dynamically typed, meaning each variable can only store one type of value. O True O False The Python type conversion functions are actually what kind of functions? O object constructors O iterators O user-defined types O predicate functions Reorder the terms on the left to match the descriptions on the right. Once you start reordering, be sure to finish before checking your answers. list 7 set 8 int 9 bool A true or false value. A character string. An unordered collection of key/value pairs. A whole number. An immutable list of values. An unordered collection of unique values. A list of values. 10 tuple 11 dict 12 str
The term data type can be used interchangeably with what other term is Object.
Sequence of data types represents an ordered collection of values. set of data types represents an unordered collection of unique values. All Python data types are immutable. False Python is dynamically typed, meaning each variable can only store one type of value. False The Python type conversion functions are actually what kind of functions. Object constructors Reorder the terms on the left to match the descriptions on the right. bool: A true or false value. str: A character string. dict: An unordered collection of key/value pairs. int: A whole number. tuple: An immutable list of values. set: An unordered collection of unique values. list: A list of values.
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9.16 a. How many trap service routines can be implemented in the LC-3? Why? b. Why must a RET instruction be used to return from a TRAP routine? Why won't a BR (Unconditional Branch) instruction work instead? c. How many accesses to memory are made during the processing of a TRAP instruction? Assume the TRAP is already in the IR.
a) there can be a maximum of 256 trap service routines implemented b) The RET (Return) instruction must be used to return from a TRAP routine because the TRAP instruction itself does not automatically provide a mechanism for returning to the original program flow c) there are typically two memory accesses made
Why must a RET instruction be used to return from a TRAP routine?a. In the LC-3 (Little Computer 3) architecture, there can be a maximum of 256 trap service routines implemented. This is because the TRAP instruction uses an 8-bit vector to specify the desired trap service routine. With 8 bits, there are a total of 256 possible combinations, allowing for the implementation of 256 trap service routines.
b. The RET (Return) instruction must be used to return from a TRAP routine because the TRAP instruction itself does not automatically provide a mechanism for returning to the original program flow.
c. During the processing of a TRAP instruction in the LC-3 architecture, there are typically two memory accesses made. The first memory access occurs to retrieve the trap vector address from the memory location specified by the TRAP instruction. This address points to the starting address of the trap service routine.
The second memory access is made when the trap service routine needs to access data or instructions from memory. This access depends on the specific operations performed within the trap service routine itself.
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A transparent film is to be bonded onto the top surface of a solid plate inside a heated chamber. For the bond to cure properly, a temperature of 70°C is to be maintained at the bond, between the film and the solid plate. The transparent film has a thickness of 1 mm and thermal conductivity of 0.05 W/m·K, while the solid plate is 13 mm thick and has a thermal conductivity of 1.2 W/m·K. Inside the heated chamber, the convection heat transfer coefficient is 70 W/m2·K. If the bottom surface of the solid plate is maintained at 52°C.
Required:
Determine the temperature inside the heated chamber and the surface temperature of the transparent film. Assume thermal contact resistance is negligible.
Answer:
1.) 103.23 degree centigrade
2.) 126.96 degree centigrade
Explanation:
Given that a transparent film is to be bonded onto the top surface of a solid plate inside a heated chamber. For the bond to cure properly, a temperature of 70°C is to be maintained at the bond, between the film and the solid plate. The transparent film has a thickness of 1 mm and thermal conductivity of 0.05 W/m·K, while the solid plate is 13 mm thick and has a thermal conductivity of 1.2 W/m·K. Inside the heated chamber, the convection heat transfer coefficient is 70 W/m2·K. If the bottom surface of the solid plate is maintained at 52°C.
To determine the temperature inside the heated Chamber, let us first calculate the heat transfer rate per unit area through the plate by using the formula
Heat transfer rate R = k( Tb - T2)/L
Where
k = 1.2 W/mA.K
Tb = 70 degree
T2 = 52 degree
L = 13mm = 13/1000 = 0.013m
substitute all the parameters into the formula above.
R = 1.2 x ( 70 - 52 )/ 0.013
R = 1.2 x (18/0.013)
R = 1661. 5 W/m^2
the surface temperature of the transparent film will be
Ts = Tb + (RLf/Kf)
Ts = 70 + (1661.5 x 0.001)/0.05
Ts = 70 + (1.6615)/0.05
Ts = 70 + 33.23
Ts = 103.23 degree centigrade
the temperature inside the heated Chamber will be calculated by using the formula
Ti = Ts + (R/h)
Ti = 103.23 + (1661.5/70)
Ti = 103.23 + 23.74
Ti = 126.97 degree centigrade
URGENT NEED HELP BY AN HOUR
C++ ONLY
Given a line of text as input: (1) output the number of characters excluding the three characters commonly used for end-of-sentence punctuation( period, exclamation point, and question mark), (2) then output the number of end-of-sentence punctuation characters that were found. You can just do (1) to pass the first few test cases for partial credit, then do (2) for full credit.
Ex: If the input is "Listen, Sam! Calm down. Please.", the output is:
28
3
Ex: If the input is "What time is it? Time to get a watch! O.K., bye now.", the output is:
43
5
Using the knowledge in computational language in python it is possible to write a code that output the number of characters excluding the three characters commonly used for end-of-sentence punctuation.
Writting the code:import re
def check_sentence(text):
result = re.search(r"^[A-Z][A-Za-z\s]*[\.\?!]$", text)
return result != None
print(check_sentence("Is this is a sentence?")) # True
print(check_sentence("is this is a sentence?")) # False
print(check_sentence("Hello")) # False
print(check_sentence("1-2-3-GO!")) # False
print(check_sentence("A star is born.")) # True
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15 kg of ice at 0°C is heated to water of temperature 20°C. What is the amount of heat required if the specific latent heat of ice fusion is 335 kJ/kg and the specific heat capacity of water is 4.19kJ/kg/°C?
Answer:
6282 kJ
Explanation:
Given that:
The mass (m) = 15 kg
The specific latent heat of ice fusion \(h_{fg}_{ice}\) = 335 kJ/kg
The specific heat capacity of water = 4.19 kJ/kg.c
The initial temperature of the ice \(T_i\)= 0° C
The final temperature of the water \(T_f\) = 20° C
To find the needed amount of heat to convert 0° C ice to 20° C of water.
To do that, we need to find the latent heat required for the phase change from 0° C ice to 0° C water, then the heat required to convert 0° C water to 20° C water.
Heat required = \(m \times h_{fg}_{ice}+ m \times c_{water} \times \Delta T\)
Heat required = (15 × 335) + (15 × 4.19) × (20 - 0)
Heat required = 5025 + 62.85 × 20
Heat required = 5025 + 1257
Heat required = 6282 kJ
referencing table 9.8 a 4.75 cy wheeled loader is moving poor blasted rock to a site 100 feet away. it will travel at its maximum speed in first gear. what is the cycle time? include haul and return times.
The formula to calculate the cycle time is Cycle time = Load time + Haul time + Dump time + Return time. For the given situation, the load time and dump time are given in Table 9.8.
What is the formula to calculate the cycle time?Table 9.8 provides cycle times for a variety of construction equipment, including wheeled loaders of different capacities.
The problem describes a specific situation where a 4.75 cy (cubic yard) wheeled loader is moving poor blasted rock to a site 100 feet away. The loader will be traveling at its maximum speed in first gear, and the problem asks for the cycle time, including haul and return times.
To calculate the cycle time, we can use the formula:
Cycle time = Load time + Haul time + Dump time + Return time
From Table 9.8, we can see that the load time for a 4.75 cy wheeled loader is 0.10 min (6 seconds), and the dump time is 0.05 min (3 seconds).
Assuming that the loader is loaded and dumped instantaneously, we only need to calculate the haul and return times.
To calculate the haul time, we can use the formula:
Haul time = Distance / Speed
The distance in this case is 100 feet, and the maximum speed of the loader in first gear is given in Table 9.8 as 4.0 mph. Converting feet to miles and using the formula, we get:
Haul time = 100 / (4.0 ˣ 5280/60) = 0.0227 min (1.36 seconds)
To calculate the return time, we can assume that it is equal to the haul time, since the loader is traveling at its maximum speed in both directions.
Therefore, the return time is also 0.0227 min (1.36 seconds).
Adding all of the times together, we get:
Cycle time = 0.10 + 0.0227 + 0.05 + 0.0227 = 0.1954 min (11.7 seconds)
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What is Postflow used to protect?
Answer:
The idea is to protect the puddle while it cools
Explanation:
Superheated water vapor at a pressure of 20 MPa, a temperature of 500oC, and a flow rate of 10 kg/s is to be brought to a saturated vapor state at 10 MPa in an open feedwater heater. This process is accomplished by mixing this stream with a stream of liquid water at 20oC and 10 MPa. What flow rate is needed for the liquid stream?
Answer:
1.96 kg/s.
Explanation:
So, we are given the following data or parameters or information which we are going to use in solving this question effectively and these data are;
=> Superheated water vapor at a pressure = 20 MPa,
=> temperature = 500°C,
=> " flow rate of 10 kg/s is to be brought to a saturated vapor state at 10 MPa in an open feedwater heater."
=> "mixing this stream with a stream of liquid water at 20°C and 10 MPa."
K1 = 3241.18, k2 = 93.28 and 2725.47.
Therefore, m1 + m2= m3.
10(3241.18) + m2 (93.28) = (10 + m3) 2725.47.
=> 1.96 kg/s.
which of the following elements does not affect the strength and usefulness of concrete
Air enters a constant-area combustion chamber at a pressure of 101 kPa and a temperature of 70°C with a velocity of 130 m/s. By ignoring the effects of friction, determine the maximum amount of heat that can be transferred to the flow per unit mass of air.
Answer:
451 kj/kg
Explanation:
Velocity = 139m/s
Temperature = 70⁰C
T = 343K
M1 = v/√prt
= 130/√1.4x287x343
= 130/√137817.4
= 130/371.2
= 0.350
T1/To1 = 0.9760
From here we cross multiply and then make To1 the subject of the formula
To1 = T1/0.9760
To1 = 343/0.9760
To1 = 351.43
Then we go to the rayleigh table
At m = 0.35
To1/To* = 0.4389
To* = 351.43/0.4389
= 800k
M2 = 1
Maximum amount of heat
1.005(800-351.43)
= 450.8kj/kg
= 452kj/kg