It was based on their overall quality, considering categorical variables as well as quantitative variables such as reliability rating and acceleration performance.
When determining the rankings of car models, two categorical variables that might be considered are vehicle class and fuel type. Vehicle class refers to the category or segment to which a car belongs, such as compact, sedan, SUV, or sports car. Different classes have varying characteristics and target audiences, and rankings may take into account factors specific to each class, such as comfort, practicality, or performance. Fuel type is another important categorical variable as it can influence factors like environmental impact, fuel efficiency, and driving experience.
In addition to categorical variables, popular magazines also consider quantitative variables to determine car rankings. One important quantitative variable is reliability rating, which measures the likelihood of a car experiencing mechanical issues or breakdowns over time. Another quantitative variable that is often considered is acceleration performance, which measures a car's ability to go from 0 to 60 mph (or 0 to 100 km/h) within a specified time frame. This performance metric reflects a car's speed and power, and rankings may compare acceleration times among different models to assess their performance capabilities.
These rankings serve as valuable resources for consumers, assisting them in making informed decisions when purchasing a car that suits their preferences and requirements.
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Please Help. Question attached. (No Links Please!)
It's D, 15!/(15 - 5)! .
15! is the number of ways of permuting 15 objects. In other words, if you have 15 open positions,
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _
from the 15 total objects you can pick, there are 15 choices for the first position, 14 for the second, 13 for the third, and so on, so that there is a total of
15 * 14 * 13 * … * 2 * 1 = 15!
possible arrangements.
But you're taking 5 objects at a time, so we only have 5 positions to fill:
_ _ _ _ _
and there are 15 choices for the first position, 14 for the second, 13 for the third, 12 for the fourth, and 11 for the fifth, so the total number of arrangements is
15 * 14 * 13 * 12 * 11 = 15!/10! = 15!/(15 - 5)!
(a) find the critical numbers of the function f(x) = x8(x − 3)7.
Therefore, the critical numbers of the function f(x) = x^8(x - 3)^7 are x = 0, x = 3, and x = 8/5.
To find the critical numbers of the function, we need to find the values of x at which the derivative of f(x) is equal to zero or does not exist.
Let's start by finding the derivative of f(x):
f(x) = x^8(x - 3)^7
f'(x) = 8x^7(x - 3)^7 + 7x^8(x - 3)^6
Now, we need to set f'(x) equal to zero and solve for x:
8x^7(x - 3)^7 + 7x^8(x - 3)^6 = 0
Factor out the common term of x^7(x - 3)^6:
x^7(x - 3)^6(8(x - 3) + 7x) = 0
This equation has two factors:
x^7 = 0 (which gives us x = 0 as a critical number)
(x - 3)^6(8(x - 3) + 7x) = 0
Expanding and simplifying the second factor:
(x - 3)^6(15x - 24) = 0
This gives us two more critical numbers:
x = 3 (since (x - 3)^6 cannot be zero)
x = 24/15 = 8/5
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x^2 - 3xb - 40b^2 factor the trinomi
Answer:
− (8b − x) (5b + x)
Step-by-step explanation:
Help Asap 39 points pic below
Allan needs 3 quarts of water to fill a pot for soup.How many times of he need to fill an 8-ounce measuring cup to fill the pot
Answer:
12 times
Step-by-step explanation:
1 quart = 32 ounces
3 quart = x
x = 3 × 32 ounces
x = 96 ounces
The number of times of he need to fill an 8-ounce measuring cup to fill the pot is calculated as:
= 96 ounces/8 ounces measuring cup
= 12 times
Therefore, Alan needs to fill an 8 ounce measuring cup 12 times in order to fill the pot of soup.
Answer this easy geometry question. P=?
The perimeter of the nonagon attached is
124.5
How to find the perimeterThe formula for the perimeter of a nonagon (a polygon with nine sides):
Perimeter = 9 * side length
side length = 2 * apothem * tan(π/9)
= 2 * 19 * tan(π/9)
= 13.831
The perimeter
Perimeter = 9 * side length
Perimeter = 9 * 13.81
Perimeter = 124.5
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Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.
32 kg to 56 kg
Answer:
4/7
Step-by-step explanation:
32:56
32÷2=16
56÷2=28
16:28
16÷2=8
28÷2=14
8:14
8÷2=4
14÷2=7
4:7
32:56 ~ 32/56
=4/7
Please somebody help me ASAP
it's recorded that out of 1000 people, 762 wear the corrective lenses.
just divide 762 from 1000 and multiply that result by 100.
762/ 1000 = .762
.762 x 100 = ? %
which is 76.2 %
so, we predict that 76.2% of Americans would wear corrective lenses.
Answer: 76.2 %The state test scores for 12 randomly selected high school seniors are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. 1420 1227 989 691 726 833 722 747 547 630 1442 948
(a) Find the sample mean. x overbarequals nothing (Round to one decimal place as needed.)
(b) Find the sample standard deviation. sequals nothing (Round to one decimal place as needed.)
(c) Construct a 90% confidence interval for the population mean mu. A 90% confidence interval for the population mean is
A 90% confidence interval for the population mean (μ) is approximately 766.26 to 1054.13(rounded to the nearest whole number).
(a) To find the sample mean (x), we need to sum all the scores and divide by the number of scores (which is 12 in this case):
X = (1420 + 1227 + 989 + 691 + 726 + 833 + 722 + 747 + 547 + 630 + 1442 + 948) / 12
X ≈ 910.16
The sample mean (x) is approximately 838.75 (rounded to one decimal place).
(b) To find the sample standard deviation (s), we need to follow these steps:
Find the sample mean (x) obtained in part (a).
Subtract the sample mean from each individual score, square the result, and sum all the squared values.
Divide the sum of squared values by (n-1) (where n is the number of scores, which is 12 in this case).
Take the square root of the result.
Let's calculate:
x ≈910.16 (from part a)
Calculate the squared differences from the mean and sum them up:
\(=(1420 - 910.16)^2 + (1227 - 910.16)^2 + (989 - 910.16)^2 + (691 - 910.16)^2 + (726 - 910.16)^2 + (833 - 910.16)^2 + (722 - 910.16)^2 + (747 - 910.16)^2 + (547 - 910.16)^2 + (630 - 910.16)^2 + (1442 - 910.16)^2 + (948 - 910.16)^2\)
= 1011125
Divide the sum of squared differences by (n-1):
\(s^2 = 329230.3125 / (12 - 1)\)
\(s^2 \approx 91920.45\)
Take the square root of s^2 to get the sample standard deviation (s):
s ≈ √91920.45
s ≈ 303.18
The sample standard deviation (s) is approximately 303.18 (rounded to one decimal place).
(c) To construct a 90% confidence interval for the population mean (μ), we can use the formula:
Confidence interval = x ± (z * (s / √n))
Since the population is assumed to be normally distributed, we can use a z-table to find the critical value for a 90% confidence level. The critical value for a 90% confidence level is approximately 1.645.
Now, let's calculate the confidence interval:
Confidence interval = 910.16± (1.645 * (303.18/ √12))
Lower bound of the confidence interval = 910.16 - 143.97
= 766.26
Upper bound of the confidence interval = 910.16+143.97 =
= 1054.13
A 90% confidence interval for the population mean (μ) is approximately 766.26 to 1054.13(rounded to the nearest whole number).
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Let A and B be the multisets {3 · a, 2 · b, 1 · c} and {2 · a, 3 · b, 4 · d}, respectively. Find
a) A ∪ B.
b) A ∩ B.
c) A − B.
d) B − A.
e) A + B.
For the multisets {3 · a, 2 · b, 1 · c} and {2 · a, 3 · b, 4 · d} the solutions are A ∪ B is {3 · a, 2 · b, 1 · c, 2 · a, 3 · b, 4 · d},A ∩ B is {2 · a, 2 · b},A − B is {1 · a, 0 · b, 1 · c} ,B − A is {0 · a, 1 · b, 4 · d} and A + B is {5 · a, 5 · b, 1 · c, 4 · d}.
We will use the given multisets A and B:
A = {3 · a, 2 · b, 1 · c}
B = {2 · a, 3 · b, 4 · d}
a) A ∪ B (union): This operation combines all elements of both multisets.
A ∪ B = {3 · a, 2 · b, 1 · c, 2 · a, 3 · b, 4 · d}
b) A ∩ B (intersection): This operation finds the common elements between both multisets.
A ∩ B = {2 · a, 2 · b} (as a and b are the common elements)
c) A − B (difference): This operation removes elements in B from A.
A − B = {1 · a, 0 · b, 1 · c}
d) B − A (difference): This operation removes elements in A from B.
B − A = {0 · a, 1 · b, 4 · d}
e) A + B (sum): This operation adds the counts of the elements in both multisets.
A + B = {5 · a, 5 · b, 1 · c, 4 · d}
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How come we need at least 3 points of a function to prove if the function is a linear or a exponential
You can use the points to determine if the slope is constant or if there is a change.
example 2 major premise: no dogmatists are scholars who encourage free thinking. minor premise: some theologians are scholars who encourage free thinking. conclusion: some theologians are not dogmatists. the major premise in example 2 is an proposition. the minor premise in example 2 is an proposition. the conclusion in example 2 is an proposition. therefore, the mood of the categorical syllogism in example 2 is .
The mood of the categorical syllogism in example 2 is AIO.
In your example, we have the following premises and conclusion:
1. Major Premise: No dogmatists are scholars who encourage free thinking.
2. Minor Premise: Some theologians are scholars who encourage free thinking.
3. Conclusion: Some theologians are not dogmatists.
The major premise in example 2 is an A proposition (All S are not P). The minor premise in example 2 is an I proposition (Some S are P). The conclusion in example 2 is an O proposition (Some S are not P).
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which inequality sign makes the statement true ?
Calculating brilliance in epidemiology Context. What follows is a data table showing the development of brilliance among a small class of PHE 450 students. NOTE: Student #8 came in as an existing case of brilliance and did not develop brilliance as a result of exposure to PHE 450. Student WK 1 WK 2 WK 3 WK 4 WK 5 WK6 WK 7 WK 8 WK 9 WK 10 CASE CASE CASE CASE DROP 1 2 3 4 5 6 7 8 9 10 11 12 CASE CASE CASE DROP CASE DROP ASSIGNMENT Referring to the data above, please answer the following questions What is the point prevalence of brilliance at the end of Week 1? What is the point prevalence of brilliance at the end of Week 2? • What is the point prevalence of brilliance at the end of Week 3? • Using person-weeks as your denominator, what is the incidence of brilliance over the course of the 10-week course?
The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.
The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.
The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.
Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%
In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:
The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.
The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.
The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.
The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation
Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.
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write an equation for a line with a slope of 2, through (4,-2) in standard form
Answer:
y = 2x - 10
Step-by-step explanation:
\(y=mx+b\)
\(y=2x+b\)
\(-2=2(4)+b\)
\(-2=8+b\)
\(b=-2-8\)
\(b=10\)
\(y=2x-10\)
Equation:
\(\sf{y = 2x - 10}\)
Explanation:
First, I will write the equation in point slope:
\(\sf{y-y_1=m(x-x_1)}\)
Where:
m = slopePlug in the data:
\(\sf{y-(-2)=2(x-4)}\)
\(\sf{y+2=2(x-4)}\\\sf{y+2=2x-8}\\\sf{y=2x-8-2}\\\sf{y=2x-10}\)
Hence, the answer is y = 2x - 10.
census bureau figures show that the proportion of married women who are employed increased from 23.8 percent in 1950 to 56.4 percent in 2014 (bureau of labor statistics 2015). the most dramatic increase occurred among:
According to data from the Census Bureau, the percentage of married women who hold jobs rose from 23.8 percent in 1950 to 56.4 percent in 2014(statistics). Women who had children under the age of six saw the biggest increases.
The collection, organization, organization, analysis, interpretation, and presentation of data are the main topics of study in statistics. When applying statistics to a scientific, industrial, or social problem, it is typical to start with a statistical population or a statistical model that will be investigated.Populations can refer to a variety of groupings of individuals or things, such as "every individual living in a nation" or "each atom making up a crystal." Every facet of data, including the planning of data collecting in terms of the layout of surveys and experiments, is covered by statistics.
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convert solar days into minutes
Answer:
1 Solar day = 86,400 seconds (SI Base Unit)
1 day = 1,440 minutes
Step-by-step explanation:
If need anymore help just ask I'm not really good at explaining but I'll try just comment haha ☺️
A comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of _______.
A comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate
What is a rate?
A rate is known as the quantity measured with respect to another measured quantity. It refers to the comparison of a part to a whole.
It is also the measure of a part with respect to a whole or a proportion.
Therefore, a comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate
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Can someone please help me
Answer:
1) B) 10
2) B) 9
Step-by-step explanation:
1) 10x+15=115
10x=100
x=10
2) 12x+17=125
12x=108
x=9
Answer:
B
Step-by-step explanation:
The guy above me is correct
Does there exist a graph with degree sequence (2, 3, 4, 4, 4, 5)? What about (2, 3, 3, 4, 4,5)? In each case, either provide an example of a graph that works or prove that no such graph exists.
There exists a graph with degree sequence (2, 3, 4, 4, 4, 5). An example of such a graph is a cyclic graph with 6 vertices, where each vertex is connected to its two adjacent vertices, and one additional vertex is connected to all other vertices. However, there does not exist a graph with degree sequence (2, 3, 3, 4, 4, 5).
1. For the degree sequence (2, 3, 4, 4, 4, 5):
- We can start by constructing a cyclic graph with 6 vertices. Each vertex is connected to its two adjacent vertices, resulting in a degree sequence of (2, 2, 2, 2, 2, 2).
- To increase the degree of the last vertex to 5, we add an additional vertex and connect it to all other vertices. This new vertex has a degree of 5.
- Therefore, a graph with the degree sequence (2, 3, 4, 4, 4, 5) can be constructed.
2. For the degree sequence (2, 3, 3, 4, 4, 5):
- To determine if a graph exists with this degree sequence, we can use the Havel-Hakimi algorithm.
- Rearranging the degree sequence in non-increasing order, we get (5, 4, 4, 3, 3, 2).
- Using the Havel-Hakimi algorithm, we start by subtracting 1 from the first element (5) and decrementing the next 5 elements by 1 (resulting in (4, 3, 3, 2, 2, 1)).
- Then, we arrange the sequence in non-increasing order again: (4, 3, 3, 2, 2, 1).
- Next, we repeat the process by subtracting 1 from the first element (4) and decrementing the next 4 elements by 1 (resulting in (3, 2, 2, 1, 1, 0)).
- Continuing this process, we end up with (0, 0, 1, 0, 1, -1).
- Since we have a negative number in the sequence, it is not possible to construct a graph with the given degree sequence (2, 3, 3, 4, 4, 5). Therefore, no such graph exists.
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The box-and-whisker plot below represents some data set. What percentage of the data values are greater than or equal to 92?
The percentage of the data values in the box-and-whiskers plot, that are greater than or equal to 92, which is the 75th percentile, based on the five number summary, are 25 percent of the data.
What is the five number summary of a box-and-whiskers plot?The five number summary of a box-and-whiskers plot are value of the minimum, the first quartile, the median, the third quartile and the maximum value of the set of data.
Please find attached the possible box-and-whiskers plot in the question, obtained from a similar question on the internet
The five number summary from the box-and-whiskers plot are;
Minimum value = 82
The first quartile or the 25th percentile = 87
The median, second quartile or the 50th percentile = 90
The third quartile or the 75th percentile = 92
The value 92 on the data represents the 75th percentile, therefore, the percentage of the data that are greater than or equal to 92 are; 100 - 75 = 25 percent
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Which of the following is NOT a possible rational root of the polynomial P(x) = 5x^4 + 3x^3 + 4x^2 + 15
The polynomial has no roots and the possible answer to the question are 1/5, 15 and 3 which are option b, c and d respectively
Roots of a PolynomialRoots of a polynomial refer to the values of a variable for which the given polynomial is equal to zero. If a is the root of the polynomial p(x), then p(a) = 0.
The given polynomial is 5x^4 + 3x^3 + 4x^2 + 15 and we can calculate the roots by finding values in which when we plug into the equation, it will give us zero (0).
The given polynomial has no roots and the answer to the question are option b, c and d
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What is the area of the shaded region in the given circle in terms of pi and in simplest form?
A) (120pi + 6 sqrt 3) m^2
B) (96pi + 36 sqrt 3) m^2
C) (120pi + 36 sqrt 3) m^2
D) (96pi + 6 sqrt 3) m^2
Answer:
Area of the shaded portion = (120π + 36√3)sq. m
Step-by-step explanation:
Area of the shaded region = Area of circle - Area of triangle
Given
radius of the circle = 12m
Area of the circle = πr²
Area of the circle = π(12)²
Area of the circle = 144π m²
Area of the sector = theta/360 * πr²
Area of the sector = 60/360 * 12²π
Area of the sector = 60/360 * 144π = 24π
Area of the triangle = 1/2 bh
Area of the triangle = 1/2 (12cos30)(12)
Area of the triangle = 36√3
Area of the shaded portion = (144π - 24π + 36√3)sq. m
Area of the shaded portion = (120π + 36√3)sq. m
Bob will rent a car for the weekend. He can choose one of two plans. The first plan has an Initial fee of $60 and costs an additional $0.50 per mile driven. The
second plan has no initial fee but costs $0.70 per mile driven. How many miles would Bob need to drive for the two plans to cost the same?
Answer:
Step-by-step explanation:
+55+%2B+.5x+=+.7x+
+.2x+=+55+
+x+=+275+
The cost to make each T-shirt is $10. You estimate that you will
sell 50 shirts. If you want to make a profit of at least $250, what
price will you charge for these T-shirts? Show your solution in two
different ways.
The price per T-shirt should be at least $15 to achieve a profit of $250.
To calculate the price per T-shirt that will yield a profit of at least $250, we need to consider the cost of production, the desired profit, and the number of shirts to be sold.
Given that the cost to make each T-shirt is $10, and we want to sell 50 shirts, the total cost of production would be 10 * 50 = $500.
Now, let's calculate the minimum revenue needed to achieve a profit of $250. We add the desired profit to the total cost of production: $500 + $250 = $750.
Finally, to determine the price per T-shirt, we divide the total revenue by the number of shirts: $750 ÷ 50 = $15.
Therefore, to make a profit of at least $250, the price per T-shirt should be set at $15.
By selling each T-shirt for $15, the total revenue would be $15 * 50 = $750. From this revenue, we subtract the total production cost of $500 to calculate the profit, which amounts to $750 - $500 = $250. Thus, by charging $15 per T-shirt, the desired profit of $250 is achieved.
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please help! will give brainliest
Answer:
x=7
Step-by-step explanation:
Since these angles are complementary, they will add up to 90 degrees, so you can set up the equation like so:
8x+5+3x+8=90
First, combine like terms:
(8x+3x)+(5+8)=90
11x+13=90
Then, subtract 13 from both sides:
11x+13(-13)=90(-13)
11x=77
Then divide both sides by 11:
11x(/11)=77(/11)
x=7
7 is your answer
hope this helps!
Answer:
x=7
Step-by-step explanation:
Said it in the last question you had.
How many cans of paint are needed to cover an area of 2000?
The number of cans required to paint an area of 2000 square units is equal to 5 cans.
As given in the question,
Total area to be painted is equal to 2000 square units.
Area covered by one can of paint is equal to 400 square units
400 square units = 1 can of paint
⇒ 1 square units = ( 1 / 400 ) cans of paint
⇒ 2000 square units = ( 2000 / 400 ) cans of paint
⇒ 2000 square units = 5 cans of paint
Therefore, the number of cans required to paint an area of 2000 square units using given can is equal to 5 cans.
The above question is incomplete, the complete question is:
How many cans of paint are needed to cover an area of 2000 square units if one can of paint covers in area 400 square units?
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Annie reads 8 1/3 pages of a book in 10 minutes. What is her average reading rate in pages per minute?
solve for x
8x+1=-71
Answer:
-9
Step-by-step explanation:
8x + 1 = -71
8x = -72
x = -9
Answer:
x = -9.
Step-by-step explanation:
8x + 1 = -71 Subtract 1 from both sides:
8x + 1 - 1 = -71 - 1
8x = -72
x = -72/8
x = -9.
The following is not from the book. Recall the island of knights and knaves. Every inhabitant is a knight or a knave. A knight can only tell the truth. A knave can only lie. You meet four inhabitants, Phineas, Ferb, Baljeet, and Isabella. Phineas says, "I and Ferb are both knights or both knaves." Baljeet says, "Phineas is a knave or Isabella is a knave." Isabella says, "Phineas is a knave and Baljeet is a knight." Ferb says that Phineas is a knave. State the type (knight or knave) of each inhabitant if possible. Fully justify your answer.
Phineas and Baljeet are knights, while Ferb and Isabella are knaves.
In the given statements, Phineas claims that he and Ferb are either both knights or both knaves. If Phineas is a knight, he must be telling the truth, which means Ferb is also a knight. If Phineas is a knave, he must be lying, which means Ferb is a knight. In either case, Phineas and Ferb are both knights.
Baljeet states that either Phineas is a knave or Isabella is a knave. Since we know Phineas is a knight, Baljeet's statement is false. Therefore, Baljeet is a knave.
Isabella claims that Phineas is a knave and Baljeet is a knight. However, we already established that Phineas is a knight, so Isabella's statement is false. Therefore, is a knave.
Ferb states that Phineas is a knave. Since Ferb is a knave, he can only lie, so his statement is true. Therefore, Ferb is a knave.
In summary, Phineas and Baljeet are knights, while Ferb and Isabella are knaves.
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