Answer: The two jobs I’ve picked are Construction and Being a stock investor
Why ? Construction and labor work has always been a huge dream of mine. Because it involves building and Anything I can build without asking anyone else for is a ton of money I could save.
Why stock investor? I’ve always been interested in stocks. My father is a stock investor who Has taught me lots of knowledge and it’s very interesting to know the other side of labor and blue collar to A suit and Stay at home.
In construction. There are very many stages you are at. I believe the highest is a level 4 which is the boss who sits down and tells everyone what the project is and so forth. The environment is very Loud. Dirty. You are forced to have to get into conditions you might not want to get into but That’s what labor work is to me. the Wages and slavery’s and hour pay are based on the Company. It can go from 50,000$ a year to 120,000$ a year. It’s all
About how much work you’re willing to put in when it comes to a blue collar job.
A stock investor. knows the algorithm of a graph in a stock. Whether it be falling or raising. The whole stock is very hard to read for a normal person. A stock investor can be someone’s financial help. Someone who gains money off of buying stocks through the doors which is why they call it a (stock market) because there’s many to choose from. The Salary is based on how much work you put in. The luck has to be there and you have to have a financial response of money in order to keep this job at its own flow. Salaries can range anywhere from 0$ and year to millions.
Step-by-step explanation: I don’t know if this is wrong. Or not I just did it to finish the assignment
Víctor has 2 times as many trophies as Dean. Together ,víctor and Dean have 27 trophies does víctor have?
Answer:
Victor has 18 trophies
Step-by-step explanation:
Let's set up "let statements"
Let d = Dean's trophies
Since Victor has 2 times as many trophies as Dean, we can set up a let statement for Victor like this...
Let 2d = Victor's trophies
Now we can set up an equation! Since we know Dean and Victor have 27 trophies altogether...our equation has to involve addition...
2d + d = 27
Combine like terms...(2d and d)
3d = 27
Divide 3 on both sides to isolate the variable "d"
3d ÷ 3 = d
27 ÷ 3 = 9
So...
d = 9
That means Dean has 9 trophies. But we are not done yet because we need to figure out how many trophies Victor has. Since Victor has 2 times the number of trophies as Dean we can do...
2 · 9 = 18
Therefore, Victor has 18 trophies!
Hope this helps :)
What is the y-intercept in the equation y = 4x - 3?
answer: -3
remember the equation y = mx + b
m is the slope, and b is the y-intercept
so in the equation y = 4x - 3,
4 replaces the m as the slope and -3 replaces b for the y-intercept
so -3 is your answer
Answer:
-3
Step-by-step explanation:
The sales department wants to place an order for 253,625 third grade math books for a region. Once the order is given, there is always a need for extra math books. How can the sale manager estimate the number of math books to be sure that there are more then enough?
If the sales department wants to place an order for 253,625 third grade math books for a region. How can the sale manager estimate the number of math books to be sure that there are more then enough is: The manager should carryout survey based on the number of people per class and provide 25,362 books.
How the sale can manager estimate the number of math booksSince extra math's books will be needed after giving out the available math's books.
Hence:
Additional maths books=10%× 253,625
Additional maths books=25,362 books
Based on the above calculation the manager should carryout survey based on the number of people per class and provide them with 25,362 books.
Therefore how can the sale manager estimate the number of math books to be sure that there are more then enough is that the manager should carryout survey based on the number of people per class and provide 25,362 books.
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The equation of the line is
Answer:
y = -x +3
Step-by-step explanation:
You want the slope-intercept equation of the line with the same intercept as -3y = -9 +3x, and the same slope as -2x -2y = -8.
Slope-intercept formThe slope-intercept form of the equation of a line is ...
y = mx +b . . . . . where m is the slope, and b is the y-intercept
For the given equations, we can put them in this form to find the desired parameters.
-3y = -9 +3x
y = -x +3 . . . . . . . . . . divide both sides by -3
We observe that the y-intercept is +3, which we will need for our answer.
The slope-intercept form of the second equation is ...
-2x -2y = -8
x + y = 4 . . . . . . . . . . divide by -2
y = -x +4 . . . . . . . . . . subtract x
We observe that the slope (coefficient of x) is -1, which we will need for our answer.
Desired equationWe want the equation of the line with slope -1 and y-intercept 3. It is ...
y = -x +3 . . . . . . . . . . same as the equation of the first line
__
Additional comment
The slope-intercept equation (green) is plotted using dots, so that you can see it is coincident with the line described by the first equation (red). Parallel lines have the same slope, so our desired line must be parallel to the blue line. (It is.)
What translation would map C onto A?
A. (x – 7, y + 3)
B. (x + 3, y – 7)
C. (x – 3, y + 7)
D. (x + 7, y – 3)
Answer:
A
Step-by-step explanation:
consider the coordinates of points C and A
C (4, - 1 ) and A (- 3, 2 )
4 → - 3 in the x- direction is - 7
- 1 → 2 in the y- direction is + 3
then the translation rule is
(x, y ) → (x - 7, y + 3 )
what is the interquartile rang of the following data set? 9,30,2,48,42,18,81,5,55,73,11
a. 75.5 meters in 20 seconds
For what value of 2 will the function f(x), be continuous at x=0?
(See Image) Thanks
(i) \(\lim_{x \to \pi/3}\) f(x) = 1 + √3.
(ii) \(\lim_{x \to \frac{\pi}{4}} f(x)\) does not exist.
For λ = 2.5, the function f(x) will be continuous at x = 0.
Given the function is,
f(x) = 1.5, when x = 0
= 1 -2 sin x, when x < π/4
= 1 + 2 sin x, when x > π/4
= 1 + (sin λx/sin 5x)
Now,
\(\lim_{x \to \pi/3}\) f(x) = \(\lim_{x \to \pi/3}\) (1 + 2 sin x) [Since, π/3 > π/4]
= 1 + 2 sin (π/3)
= 1 + 2√3/2 = 1 + √3
Hence, \(\lim_{x \to \pi/3}\) f(x) = 1 + √3.
Now left hand limit is,
\(\lim_{x \to \frac{\pi^+}{4}}\) f(x) = \(\lim_{x \to \frac{\pi^+}{4}}\) (1 + 2sin x) = 1 +2 sin(π/4) = 1 + 2*(1/√2) = 1 + √2
and right hand limit is,
\(\lim_{x \to \frac{\pi^-}{4}}\) f(x) = \(\lim_{x \to \frac{\pi^-}{4}}\) (1 - 2 sin x) = 1 - 2*(1/√2) = 1 - √2
Since left hand limit and right hand limit are not equal so value of \(\lim_{x \to \frac{\pi}{4}} f(x)\) does not exist.
\(\lim_{x \to 0}\) f(x) = \(\lim_{x \to 0}\) (1 + (sin λx/sin 5x)) = 1 + \(\lim_{x \to 0}\) ((sin λx/λx)/(sin 5x/5x))*(λ/5) = 1 + λ/5
Since f(x) is continuous at x = 0.
So, \(\lim_{x \to 0}\) f(x) = f(0)
1 + λ/5 = 1.5
λ/5 = 1.5 - 1 = 0.5
λ = 2.5
Hence the value of λ will be 2.5.
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parallel and perpendicular——————-
If l || m the values of x and y are x = 8, y = 21.
What are the parallel and perpendicular lines?
Parallel lines are lines in a plane that are always the same distance apart. Parallel lines never intersect. Perpendicular lines are lines that intersect at a right (90 degrees) angle.
(7x + 12)° and (12x - 28)° are alternate interior angles. Alternate interior angles are congruent. Therefore:
(7x + 12)° = (12x - 28)°
Solve for x
7x + 12 = 12x - 28
Collect like terms
7x - 12x = - 12 - 28
-5x = -40
Divide both sides by -5
-5x/-5 = -40/-5
x = 8
(12x - 28)° + (9y - 77)° = 180° (linear pair)
To find y, plug in the value for x = 8.
12(8) - 28 + 9y - 77 = 180
96 - 28 + 9y - 77 = 180
Combine like terms
- 9 + 9y = 180
Add 9 to both sides
-9 + 9y + 9 = 180 + 9
9y = 189
Divide both sides by 9
9y/9 = 189/9
y = 21
Hence, if l || m the values of x and y are x = 8, y = 21.
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In the triangle below,
y = [? ] cm. Round to the
nearest tenth.
15 cm
X
35°
909
Answer:
12.3
Step-by-step explanation:
You will use cosine to solve for y because you are given the hypontenuse and need to find the adjacent side.
cos 35 degrees = adjacent/hypontenuse
cos 35 = y/ 15
15( cos35 ) = y
y=12.287
=12.3
17.Solve minimise the following expression 4a + 5b + 6c subject to the following constraints. a+b>= 11 a-b= 35-12b a>= 0 b >= 0 c >= 0
The minimum value of the expression 4a + 5b + 6c subject to the given constraints is = 66 using the Lagrange multipliers method.
Note that the Lagrange multipliers method can be used when asked to minimize an expression subject to one or more constraints.
Using this Lagrange multipliers method subject to the given constraints:
Let \(L(a, b, c, λ1, λ2, λ3)\) be the Lagrangian function, where \(λ1, λ2, and λ3\) are the Lagrange multipliers associated with the three constraints.
Then, we have:
\(L(a, b, c, λ1, λ2, λ3) = 4a + 5b + 6c + λ1(a + b - 11) + λ2(a - b - 35 + 12b) + λ3(-a) - λ1b - λ2b - λ3c\)
To find the minimum value of the expression, we need to solve the following system of equations:
\(∇L/∇a = 4 + λ1 + λ2 - λ3 = 0\)
\(∇L/∇b = 5 + λ1 - λ2 - λ1 = 0\)
\(∇L/∇c = 6 - λ3 = 0\)
Subjected to
\(a + b > = 11\)
\(a - b = 35 - 12b\)
\(a > = 0\)
\(b > = 0\)
\(c > = 0\)
Solving these equations, we get:
\(λ1 = -3/2, λ2 = -1/2, λ3 = 6\)
\(a = 33/5, b = 8/5, c = 0\)
Therefore, the minimum value of the expression 4a + 5b + 6c subject to the given constraints is:
4(33/5) + 5(8/5) + 6(0) = 66.
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1. A. What is the formula for the Pythagorean Theorem? (1 point)
B. Find the missing leg of the triangle using the Pythagorean Theorem. Remember that drawings may not be to scale (Round to the nearest tenth).
Show your work. (4 points)
20 ft
18 ft
x
Answer:
side 1^2 + side 2 ^2 = hypotenuse ^ 2
18^2 + 20^2 = hypotenuse^2
324 + 400 = 724
hypotenuse^2 = 724
hypotenuse = 26.9072480941474
hypotenuse = 26.9
Step-by-step explanation:
4 movie tickets cost $48. At this rate with is the cost of 1 movie tickets
Answer: $12 for one ticket.
Step-by-step explanation:
simply divide 48 by 4, that's how you find the price for one ticket.
Which point represents the ordered pair ( 1/4, -1/2)?
x = 0.25 , y= -0.5 , (x, y) represents the point (0.25,-0.5) in fourth quadrant of the cartesian plane as shown in the graph below attached.
What are cartesian coordinates in two dimensions ?
A Cartesian coordinate system in two dimensional is defined by x and y axes. Any point in the coordinate system is defined by a perpendicular distance from the x and y axes, (x, y). x and y axes intersect at the point where the value of x and y both is zero; this is called the origin (0,0)
Given ordered pair is ( 1/4, -1/2)
put (x,y) = ( 1/4, -1/2)
x= 1/4 =0.25 and y =(-1/2) = -0.5
This point lie in 4th quadrant
The point in the attached file represents the given point.
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Elsa earns 5140 for working 20 hours
1) What is Elsa's rate of pay for each hour she works?
A) 5650 per hour
B) $7.00 per hour
$7.25 per hour
D) $2.00 per hour
Answer:
$2.57
Step-by-step explanation:
divide 5,140 by 20,
5,140/20=257=2.57
At the farmer’s market, Joan bought apples at $1.20 per pound, cherries for $2.00 per pound and pears for $0.80 per pound. She bought a total of 9 pounds of fruit for $11.00. Joan bought twice as many pounds of apples than cherries. Let A be the weight of the apples, C be the weight of the cherries, and P be the weight of the pears. Formulate a system of equations to determine how many pounds of each type of fruit were bought. Do Not Solve.
We have here a case in which we need to translate a problem into algebraic expressions to solve a problem, and we have the following information from the question:
• We have that Joan bought:
0. Apples at $1.20 per pound
,1. Cherries at $2.00 per pound
,2. Pears at $0.80 per pound
• We know that she bought a total of 9 pounds of fruit.
,• We also know that she spent $11.00 for the 9 pounds of fruit.
,• Joan bought twice as many pounds of apples than cherries.
We need to label weights as follows:
• Weight of apples ---> A
,• Weight of cherries ---> C
,• Weight of pears ---> P
Now to find a system of equations to determine the number of pounds of each type of fruit was bought, we can proceed as follows:
1. We know that if we multiply the price of the fruit per pound by the weight in pounds, we will obtain the amount of money Joan spent in total. Then we have:
\(1.20a+2.00c+0.80p=11.00\rightarrow\text{ \lparen First equation\rparen}\)2. We also know that the total weight of the fruits was equal to 9 pounds. Then we can translate it into an algebraic expression as follows:
\(a+c+p=9\rightarrow(\text{ Second equation\rparen}\)3. And we know that Joan bought twice as many pounds of apples than cherries, and we can translate it as follows too:
\(\begin{gathered} 2a=c \\ \\ \text{ If we subtract c from both sides of the equation, we have:} \\ \\ 2a-c=c-c \\ \\ 2a-c=0\text{ \lparen Third equation\rparen} \end{gathered}\)Now we have the following equations:
\(\begin{gathered} 1.20a+2.00c+0.80p=11.00 \\ \\ \begin{equation*} a+c+p=9 \end{equation*} \\ \\ \begin{equation*} 2a-c=0 \end{equation*} \end{gathered}\)Therefore, we have that the correct option is the first option:
• 1.20a + 2.00c + 0.80p = 11.00
• a + c + p = 9
,• 2a - c = 0
[First option].
What are the center and radius if the equation (x-2)^2 + (y-9)^2
Step-by-step explanation:
(x-2)^2 + (y-9)^2 = r^2
this is of the form fora circle with center h,k and radius r
(x-h)^2 + (y-k)^2 = r^2
for the equation given center = 2, 9 and radius = r
Indicate which property is illustrated in Step 2
7 + (1 + 7) + 0 = 7+ (7 + 1) + 0
= (7 + 7) + (1 + 0)
= (7 + 7) + 1
= 14 +1
Step 1
Step 2
Step 3
Step 4
OA. commutative property of multiplication
OB. identity property of addition
oc. distributive property
OD. associative property of addition
Answer:
the associative property of addition i think
Step-by-step explanation:
Andre ran 2 kilometers in 15 minutes and Jada ran 3 kilometers in 20 minutes. Both ran at a constant speed. Did they run the same rate? Explain or show your reasoning.
You might use:
-ratio tables
-double number lines
-unit rates
-Equivalent ratios
yeah
Answer:
no, Andre ran at a sperm of 8km/hr while jada ran at 9km/hr you can find that by Andre going 2km in 15 minutes which turns to hours by multiplying by 4/4 to get 8/60 which 60 minutes is 1 hour then jada multiply by 3/3 which would be 9/60
Which of the following ratios is used in finding the tangent of an angle in a right triangle?A.hypotenuse/opposite legB.opposite leg/hypotenuseC.opposite leg/adjacent legD.adjacent leg/hypotenusePlease select the best answer from the choices providedABCD
ANSWER
C. opposite leg/adjacent leg
EXPLANATION
The tri
In triangle ABC, AB = 6, BC = 8, and angle ABC = 90 degrees. Find the area of triangle ABC.
Answer:
24
Step-by-step explanation:
The formula for area of any triangle is (length * width) * 1/2. This makes the angle of 90 degrees irrelevant.
6 x 8 = 48
48 / 2 = 24
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9 minutes. Assume that the distribution of taxi and takeoff times is approximately normal. You may assume that the jets are lined up on a runway so that one taxies and takes off immediately after the other, and that they take off one at a time on a given runway.
(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes? (Round your answer to four decimal places.)
(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes? (Round your answer to four decimal places.)
(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes? (Round your answer to four decimal places.)
Answer:
a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.
b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes
c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 8.9 minutes and a standard deviation of 2.9 minutes.
This means that \(\mu = 8.9, \sigma = 2.9\)
Sample of 37:
This means that \(n = 37, s = \frac{2.9}{\sqrt{37}}\)
(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?
320/37 = 8.64865
Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So
\(Z = \frac{X - \mu}{\sigma}\)
By the Central Limit Theorem
\(Z = \frac{X - \mu}{s}\)
\(Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}\)
\(Z = -0.53\)
\(Z = -0.53\) has a p-value of 0.2981
0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.
(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?
275/37 = 7.4324
Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So
\(Z = \frac{X - \mu}{s}\)
\(Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}\)
\(Z = -3.08\)
\(Z = -3.08\) has a p-value of 0.001
1 - 0.001 = 0.999
0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.
(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?
Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So
0.2981 - 0.0010 = 0.2971
0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes
Jamie buys p bags of pears for $8 each and m melons for $6 each.
Write an expression to represent how much Jamie spends in all.
The expression to represent how much Jamie spends in all. we may state,0.40x + 0.40y is 8, 0.30x + 0.30y is 6
What is an expression to represent?Set variables to represent the amounts we wish to identify.
Let x = the quantity of p bagsLet y=the quantity of m melonsThen, using these variables, we create equations that fully capture the narrative.Since the overall cost is $8 and $6 the cost of each bags variety varies, we may state0.40x + 0.40y = 8.0.30x + 0.30y =6The total amount of bags purchased together will be represented by the other equation, as Mark said. Once you have those equations, you may solve the problem for the variables x and y by utilising substitution and elimination techniques.The expression to represent how much Jamie spends in all. we may state,0.40x + 0.40y = 8, 0.30x + 0.30yTo learn more about expression refer to:
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what is 3/4 x 18 pls helpppp
Answer:
18÷4×3=13.5
so 13.5 is the answer
Answer:
13.5 or 13 \(\frac{1}{2}\) or \(\frac{27}{2}\)
Step-by-step explanation:
We can setup this by turning 18 into a fraction. \(\frac{3}{4} * \frac{18}{1}\). All we need to do is multiply the numerators and the denominators together to get \(\frac{54}{4}\). We can now divide 54 by 4 to get 13.5. 13.5 or 13 1/2 or 27/2 is your final answer.
Invent examples of data with
(a) SS(between) = 0 and SS(within) > 0
(b) SS(between) > 0 and SS(within) = 0
For each example, use three samples, each of size 5.
The sample of given data is Sample 1: 1, 2, 3, 4, 5 Sample 2: 6, 7, 8, 9, 10
b)Sample 1: 1, 2, 3, 4, 5 Sample 2: 6, 7, 8, 9, 10
(a) An example of data with SS(between) = 0 and SS(within) > 0 could be the following:
Sample 1: 1, 2, 3, 4, 5
Sample 2: 6, 7, 8, 9, 10
Sample 3: 11, 12, 13, 14, 15
In this example, the means of each sample are all different from each other, but the grand mean (8) is equal to the mean of each sample. Therefore, there is no variability between the means of the samples, resulting in SS(between) = 0. However, there is still variability within each sample, resulting in SS(within) > 0.
(b) An example of data with SS(between) > 0 and SS(within) = 0 could be the following:
Sample 1: 1, 2, 3, 4, 5
Sample 2: 6, 7, 8, 9, 10
Sample 3: 11, 12, 13, 14, 15
In this example, the means of each sample are all the same (8), but the values within each sample are all different from each other. Therefore, there is variability between the means of the samples, resulting in SS(between) > 0. However, there is no variability within each sample, resulting in SS(within) = 0.
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4x^2/x^2-9-2x/x+3=3/x-3
Answer:
x=2/3
Step-by-step explanation:
decimal: 1.5
mix number: 1 1/2
here what one is right?
Answer:
B.
Step-by-step explanation:
The business college computing center wants to determine the proportion of business students who have personal computers (PC's) at home. If the proportion differs from 30%, then the lab will modify a proposed enlargement of its facilities. Suppose a hypothesis test is conducted and the test statistic is 2.5. Find the P-value for a two-tailed test of hypothesis.
The probability of observing such an extreme result by chance alone is 0.0124.
To find the P-value for a two-tailed test of hypothesis, we need to first determine the significance level (alpha) of the test. Let's assume a significance level of 0.05, which is a common choice.
Since this is a two-tailed test, we need to find the probability of observing a test statistic as extreme or more extreme than 2.5 in either direction. We can find this probability using a standard normal distribution table or a calculator.
Using a standard normal distribution table, we can find that the probability of observing a z-score of 2.5 or greater is 0.0062. The probability of observing a z-score of -2.5 or smaller is also 0.0062. Therefore, the P-value for the two-tailed test of hypothesis is:
P-value = 2 * 0.0062
P-value = 0.0124
This means that if the true proportion of business students who have personal computers at home differs from 30%, with a significance level of 0.05, and we obtain a test statistic of 2.5, then the probability of observing such an extreme result by chance alone is 0.0124.
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Right triangle EFG has its right angle at F, EG = 6 , and FG = 4 What is the value of the trigonometric ratio of an angle of the triangle? Drag a value to each box to match the trigonometric ratio with its value .
Answer:
\(\cos G=\dfrac{2}{3}\)
\(\csc E=\dfrac{3}{2}\)
\(\cot G=\dfrac{2}{\sqrt{5}}\)
Step-by-step explanation:
If the right angle of right triangle EFG is ∠F, then EG is the hypotenuse, and EF and FG are the legs of the triangle. (Refer to attached diagram).
Given ΔEFG is a right triangle, and EG = 6 and FG = 4, we can use Pythagoras Theorem to calculate the length of EF.
\(\begin{aligned}EF^2+FG^2&=EG^2\\EF^2+4^2&=6^2\\EF^2+16&=36\\EF^2&=20\\\sqrt{EF^2}&=\sqrt{20}\\EF&=2\sqrt{5}\end{aligned}\)
Therefore:
EF = 2√5FG = 4EG = 6\(\hrulefill\)
To find cos G, use the cosine trigonometric ratio:
\(\boxed{\begin{minipage}{9 cm}\underline{Cosine trigonometric ratio} \\\\$\sf \cos(\theta)=\dfrac{A}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)
For angle G, the adjacent side is FG and the hypotenuse is EG.
Therefore:
\(\cos G=\dfrac{FG}{EG}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(\hrulefill\)
To find csc E, use the cosecant trigonometric ratio:
\(\boxed{\begin{minipage}{9 cm}\underline{Cosecant trigonometric ratio} \\\\$\sf \csc(\theta)=\dfrac{H}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)
For angle E, the hypotenuse is EG and the opposite side is FG.
Therefore:
\(\csc E=\dfrac{EG}{FG}=\dfrac{6}{4}=\dfrac{3}{2}\)
\(\hrulefill\)
To find cot G, use the cotangent trigonometric ratio:
\(\boxed{\begin{minipage}{9 cm}\underline{Cotangent trigonometric ratio} \\\\$\sf \cot(\theta)=\dfrac{A}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)
For angle G, the adjacent side is FG and the opposite side is EF.
Therefore:
\(\cot G=\dfrac{FG}{EF}=\dfrac{4}{2\sqrt{5}}=\dfrac{2}{\sqrt{5}}\)
Which equation can be used to solve for x xx in the following diagram? Choose 1 answer: (Choice A) A ( 5 x + 30 ) − 5 x = 90 (5x+30)−5x=90left parenthesis, 5, x, plus, 30, right parenthesis, minus, 5, x, equals, 90 (Choice B) B ( 5 x + 30 ) + 5 x = 180 (5x+30)+5x=180left parenthesis, 5, x, plus, 30, right parenthesis, plus, 5, x, equals, 180 (Choice C) C ( 5 x + 30 ) + 5 x = 90 (5x+30)+5x=90left parenthesis, 5, x, plus, 30, right parenthesis, plus, 5, x, equals, 90 (Choice D) D 5 x = ( 5 x + 30 ) 5x=(5x+30)
Answer: answer is C
Step-by-step explanation:
for find x
(5x+30)+5x=90
5x+30+5x=90 add like terms
after,
10x+30=90
10x+30-30=90-30
10x/10=60/10
x = 6
to obtain answer as C
it mean
(5x+30)+5x=90
(5(6)+30)+5(6)=90 we know x=6 so add 6 to x and multiply and obtain answer is correct!
30+30+30=90