Answer:
a
Explanation:
A 5.75-kg bowling ball moving at 9.85 m/s collides with a 0.95-kg bowling pin, which is scattered at an angle of θ = 23.5° from the initial direction of the bowling ball, with a speed of 11 m/s.
1. Calculate the direction, in degrees, of the final velocity of the bowling ball. This angle should be measured in the same way that θ is.
2.alculate the magnitude of the final velocity, in meters per second, of the bowling ball.
Answer:
Explanation:
To solve this problem, we can use the principles of conservation of momentum and conservation of kinetic energy.
To calculate the direction of the final velocity of the bowling ball, we can use the concept of vector addition. We know that the bowling pin is scattered at an angle of θ = 23.5° from the initial direction of the bowling ball. Therefore, the final velocity of the bowling ball will be at an angle of 180° - θ = 156.5° from its initial direction.
To calculate the magnitude of the final velocity of the bowling ball, we can use the conservation of momentum. The initial momentum of the system (bowling ball and bowling pin) is given by:
Initial momentum = m1 * v1 + m2 * v2
where m1 and v1 are the mass and velocity of the bowling ball, and m2 and v2 are the mass and velocity of the bowling pin, respectively.
Initial momentum = (5.75 kg * 9.85 m/s) + (0.95 kg * 11 m/s)
Simplifying this equation gives us the initial momentum.
Next, we can use the conservation of momentum to determine the final velocity of the bowling ball. Since there are no external forces acting on the system, the total momentum before the collision is equal to the total momentum after the collision.
Final momentum = Initial momentum
Since we know the mass of the bowling ball and the final velocity of the bowling pin, we can calculate the final velocity of the bowling ball.
Finally, the magnitude of the final velocity of the bowling ball can be found by taking the magnitude of the final velocity vector calculated in step 2.
Please note that for more accurate results, the calculations should consider the vector nature of the velocities.
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A trebuchet at ground levels throws a boulder with an initial velocity of 25 m/s at 30 degrees.
What was the magnitude of the final velocity of the boulder before it hit the ground?
a
30 m/s
b
10 m/s
C С
25 m/s
ОООООО
d
20 m/s
e
27.5 m/s
12.5 m/s
Answer:
The correct option is;
C. 25 m/s
Explanation:
The initial velocity with which the boulder was thrown = 25 m/s
The path in which the boulder projectile moves = 30°
For projectile motion, we have;
The time it takes the boulder to hit the ground is given by the following equation;
y = y₀ + v₀·sin(θ₀)t -¹/₂·g·t²
Where;
y = The height of the boulder
y₀ = The initial height of the boulder = 0
g = The acceleration due to gravity = 9.81 m/s²
When the boulder touches the ground again, the value of y = 0. therefore, we have;
0 = 0 + 25 × sin(30)t -¹/₂ × 9.81 × t²= 12.5·t - 4.905·t²
From which we have, t = 0 or t ≈ 2.55 s
At t = 2.55 s The vertical velocity = v₀sin(θ₀) - g·t = 25 × 0.5 - 9.81×2.55 = -12.5 m/s
The vertical velocity, \(v_y\) = -12.5 m/s
The horizontal velocity, vₓ = v₀·cos(θ₀) = 25×cos(30) ≈ 21.65 m/s
The magnitude of the resultant velocity before, the boulder hits the ground is given as follows
\(\left | v \right |\) = √((vₓ)² + (\(v_y\))²) = √(12.5² + 21.65²) = √625 = 25
The magnitude of the resultant velocity before, the boulder hits the ground is 25 m/c
question 7 options: a photon with 9.01x10-19 joules of energy has a wavelength of nanometers.
The photon with an energy of \(9.01 * 10^{-19}\) J has a wavelength of approximately 220.3 nm.
To find the wavelength of a photon given its energy, we can use the equation:
E = hc/λ
Where:
E is the energy of the photon,
h is the Planck's constant (approximately 6.62607015 × 10^-34 J·s),
c is the speed of light in a vacuum (approximately 2.998 × 10^8 m/s),
λ is the wavelength of the photon.
Rearranging the equation to solve for λ, we have:
λ = hc/E
Given:
\(E = 9.01 * 10^{-19}\) J
Substituting the known values:
\(\lambda = \frac{(6.62607015 * 10^{-34} * 2.998 * 10^8 )}{(9.01 * 10^{-19}}\)
\(\lambda = \frac{(1.98644591 * 10^{-25})}{(9.01 * 10^{-19})}\)
\(\lambda \approx 2.203 * 10^{-7} m\)
To convert this wavelength to nanometers, we can multiply by 10⁹:
=λ ≈ 220.3 nm.
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According to the Theory of Continental Drift, South America and Africa once formed part of a single larger continent called Pangaea that eventually broke apart. Today, the average distance between matching shorelines of South America and Africa is about 8000 km. Measurements indicate that the continents are drifting apart at a speed of about 4.0 cm/year. a. According to these measurements, how long ago did these continents separate? b. What assumptions did you make in order to answer (a)?
According to the Theory of Continental Drift, we can predict that:
a. These continents separate for an average of 200000000 years b. The assumption made is that the current distance is 8000 km which is 800000000 cm.Meaning of Continental DriftContinental Drift can be defined as a hypothesis that was put forth, that the Earth's continents have moved over time relative to each other and as the time goes its keeps on moving, increasing the distance between them.
Continental Drift makes the continents look like they have drifted across the ocean.
In conclusion, Our predictions are stated above.
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What's Alpha beta gamma emission??
a car has two headlights, and their power is derived from the car's battery. the filament in one burns out, but the other headlight stays on. are the headlights connected in series or in parallel?
It is necessary to collimate the light source before using the prisim to disperse the light so that the light rays entering the prisim are parallel series.
What is colimate?
collimator is a tool for converting a point source's divergent radiation into a parallel beam. To perform specific measurements in spectroscopy, geometrical optics, and physical optics, the light must be collimated.
An optical collimator is made up of a tube with a convex lens at one end and a variable aperture at the other end that is located in the lens' focal plane. To examine the image without parallax, radiation entering the aperture exits the collimator as a parallel beam.
Therefore collimation is needed for the light rays entering the prism to be parallel .
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If 2N force is applied on 2 kg mass due east and same magnitude of force due west, thechange in velocity of the body in 2 sec is
Explanation:
F=m(v-u)/t
F=2N
m=2kg
t=2s
2=2(v-u)/2
cross multiply
2*2=2(v-u)
4=2(v-u)
4/2=v-u
v-u=2m/s
v-u is the change is velocity.
The change in velocity of the body in 2 sec is 2m/s
According to Newton's second law which states that the change in momentum of an object is directly proportional to the applied force.
Mathematically:
\(F \ \alpha \ (\dfrac{v-u}{t} )\)
\(F = m (\dfrac{v-u}{t} )\)
where:
m is the mass
(v - u) is the change in velocity
t is the time
F is the applied force
Given the following:
mass m = 2kg
time t = 2secs
Force F = 2N
Required
Change in velocity (v-u)
Substitute the given parameters into the expression shown above:
\(2=2(\dfrac{v-u}{2})\\ 2 \times 2=2(v-u)\\4=2(v-u)\\v-u=\dfrac{4}{2}\\v-u=2m/s\\\)
Hence the change in velocity of the body in 2 sec is 2m/s.
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synonym of an applied force
Answer:
Coerce, compel, constrain
Explanation:
while riding a roller coaster, a girl drops an object. the roller coaster was rising vertically at a velocity of 11.0m/s and was 5.00m above the ground when the object was dropped. how long does it take to reach the ground
Answer:
Approximately \(0.388\; {\rm s}\), assuming that air resistance is negligible and that \(g = 9.81\; {\rm m\cdot s^{-2}}\).
Explanation:
Initial vertical velocity of the object: \(u = 11.0\; {\rm m\cdot s^{-1}}\), upwards (same as that of the rollercoaster.)
Initial height of the object: \(h_{0} = 5.00\; {\rm m}\).
If air resistance is negligible, this object will accelerate downwards at a constant \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\). Note that \(a\) is negative since the object is accelerating downwards.
The SUVAT equation \(h = (1/2)\, a\, t^{2} + u\, t + h_{0}\) gives the height \(h\) of this object at time \(t\). Note that while the initial height is \(5.00\; {\rm m}\), \(h = 0\) when the object reaches the ground.
Since acceleration \(a\), initial velocity \(u\), and initial height \(h_{0}\) are all given, setting \(h\!\) to \(0\) and solving for \(t\) will give the time it takes for this object to reach the ground:
\((1/2)\, a\, t^{2} + u\, t + h_{0} = 0\).
\((1/2)\, (-9.81) \, t^{2} + 11.0\, t + 5.00 = 0\).
\((-4.905)\, t^{2} + 11.0\, t + 5.00 = 0\).
Solve this equation for \(t\!\) using the quadratic formula. Note that \(t > 0\) since \(t\) denotes the amount of time required for the object to reach the ground.
\(\begin{aligned} t &= \frac{-11.0 + \sqrt{11.0^{2} - 4 \times (-4.905) \times 5.00}}{2\times (-4.905)} \\ &\approx 0.388\; {\rm s}\end{aligned}\).
The other root of this quadratic equation is negative and isn't a valid solution to the question.
In other words, it will take approximately \(0.388\; {\rm s}\) for this object to reach the ground.
Visualiza el lanzamiento de un rollo que continene un anuncio de propaganda que cubrirá el lado sur de un edificio. El rollo fue lanzado con una velocidad horizontal de 30.0 m/s, y cayó a una distancia horizontal de 10.0 m de la base del edificio. ¿Cuán alto es el edificio?
Answer:
El edificio tiene una altura de aproximadamente 0.548 m
Explanation:
Podemos utilizar las ecuaciones del movimiento en dos dimensiones para resolver este problema. En primer lugar, podemos descomponer la velocidad inicial en sus componentes horizontal y vertical. Dado que la velocidad inicial es únicamente horizontal, la componente horizontal de la velocidad es de 30.0 m/s, mientras que la componente vertical es cero.
A continuación, podemos utilizar la ecuación de la posición vertical para determinar la altura del edificio. Esta ecuación es:
y = y0 + v0y t + (1/2) a_y t^2
donde y es la posición vertical final, y0 es la posición vertical inicial (en este caso, la altura del lanzamiento), v0y es la componente vertical de la velocidad inicial (en este caso, cero), a_y es la aceleración vertical (en este caso, la aceleración debido a la gravedad, que es de -9.8 m/s^2), y t es el tiempo de vuelo.
La distancia horizontal recorrida durante el vuelo es de 10.0 m, y la componente horizontal de la velocidad es de 30.0 m/s, por lo que podemos calcular el tiempo de vuelo como:
t = d / v0x = 10.0 m / 30.0 m/s = 0.333 s
Sustituyendo este valor en la ecuación de la posición vertical, y teniendo en cuenta que la velocidad vertical final también es cero (ya que el rollo vuelve al nivel del suelo), podemos despejar la altura del edificio:
y = y0 + (1/2) a_y t^2
y = 0 + (1/2) (-9.8 m/s^2) (0.333 s)^2
y = 0.548 m
Por lo tanto, el edificio tiene una altura de aproximadamente 0.548 m.
Heyyyy...Please i need helppp
anticlockwise = clockwise (Force*distance)
1 * 20 = 2 * x
x = 10
If a metal ball suspended by a rod is at rest, which force is responsible for balancing the force due to gravity? a. the tension in the rod b. the friction of the rod c. the electromagnetic force d. the strong force around the rod
If a metal ball is suspended by a rod , the forces acting on the system are balanced so there is no motion observed in the system and this is because of the upward tension in the rod .
Option 1 says : the tension in the rod
The gravitational pull that is acting downwards direction and the tension in rod that is acting in a anti parallel direction to the gravitational pull . being on the same line of action and in opposite directions , these forces cancels each other out .
Option 2 says : the friction of rod
Friction acts in cases of contact forces like a drag or pull not in cases of non-contact forces like gravity , thus friction can't balance it .
Option 3 says : the electromagnetic force
There are no charges or magnets present in the system so the electromagnetic force is absent in this case Thus they cant balance the gravitational force.
Option 4 says : the strong force around the rod
The strong force around is not on the line of action of the gravitational pull so it cant balance it.
So out of all the forces only the tension present in the rod is able to balance the gravitational force
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what is biosphere hydrosphere and atmosphere
Answer:
Biosphere are the regions of the surface, atmosphere, and hydrosphere of the earth.
Hydrosphere is when all the waters on the earth's surface, such as lakes and seas, and sometimes including water over the earth's surface, such as clouds.
Atmosphere is the envelope of gases surrounding the earth or another planet.
Explanation:
Hope this helps you out !!!
Two airplanes leave an airport at the same time. The velocity of the first airplane is 650 m/h at a heading of 16.9 ◦ . The velocity of the second is 590 m/h at a heading of 161◦ . How far apart are they after 1.8 h? Answer in units of m.
Distance of train after 1.8 h is 485.099 m
Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in ordinary language.
Distance of the first plane = 650 x 1.8 = 1170 m
Distance of the second plane = 590 x 1.8 = 1062m
The angle between 2 planes
161◦ - 16.9◦ = 144.1°
Using the law of cosine
d^2 = (1170)^2 + (1062)^2 - 2*1170*1062*cos 144.1°
d = 485.099 m
Hence, distance of train after 1.8 h is 485.099 m
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Calcular la magnitud de la fuerza eléctrica entre dos cargas cuyos valores son q1=2 milicoulombs, q2=4 milicoulombs, al estar separadas en el vacío por una distancia de 30 cm
Answer:
Fe = 7.98*10^5N/C
Explanation:
In order to calculate the electric force between the two charges you use the following formula:
\(F_e=k\frac{q_1q_2}{r^2}\) (1)
k: Coulomb's constant = 8.98*10^9Nm^2/C^2
q1 = 2mC = 2*10^-3C
q2 = 4mC = 4*10^-3C
r: distance between the charge = 30cm = 0.3m
You replace the values of the parameters in the equation (1):
\(F_e=(8.98*10^9Nm^2/C^2)\frac{(2*10^{-3}C)(4*10^{-3}C)}{(0.3)^2}\\\\F_e=7.98*10^5\frac{N}{C}\)
The force between the charges q1 and q2 is 7.98*10^5N/C
wave motion that is parallel to wave direction describes a_ wave
A longitudinal wave is a wave in which the motion of the medium's particles is parallel to the wave's direction of propagation.
What is the name of a parallel wave?Longitudinal waves are waves in which the displacement of the medium is in the same (or the opposite) direction as the wave propagation and the medium vibration is parallel ("along") to the direction the wave travels.
What wave moves parallel to another?Two categories of mechanical waves exist: In longitudinal waves, the movement of the particles is parallel to the motion of the energy, meaning that the medium is displaced in the same direction as the wave.
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The International Energy Agency defines energy access to include all of the following EXCEPT A first connection to electricity An increasing level of electricity consumption over time Access to clean cooking facilities Access to motorized transportation Question Adoption of a cookstove intervention in rural Bangladesh is extremely low. As a consultant to the UN, you are asked for your opinion on why this occurred. Which of the following is/are a plausible explanation(s)? The technology was not well maintained by users All of these answers are correct The stoves failed to take into account regional cooking preferences The stoves failed to take into account regional cooking preferences The chosen stove was too complicated for less well-educated users
The correct answer is: All of these answers are correct.
All the provided explanations can be plausible reasons for the low adoption of a cookstove intervention in rural Bangladesh. It is important to consider factors such as technology maintenance, regional cooking preferences, and the suitability of the chosen stove for the user's level of education.
All of these factors can significantly impact the acceptance and adoption of a new cooking technology.It would hinder their ability to effectively use and benefit from the intervention.
Considering these factors collectively provides insight into why the adoption rate remained low. Addressing these issues is crucial to improving the acceptance and success of cookstove interventions in rural communities.
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A bear scratches his claws on a big pine tree. Does the bear do work on the tree? why or why not?
(btw it has to do with physics) ITS NOT A GENERAL QUESTION.
Answer:
The bear is actually sharpening his claws. That's the only reason he scratches a tree with his claws
Explanation:
what are the uses of convex lens
Answer:A convex lens is employed in microscopes and magnifying glasses to converge all incoming light rays to a particular point. ...
The convex lens is used in cameras. ...
A convex lens is used for the correction of hyperopia. ...
The converging lens is used in the projector as well.
A dentist uses a concave mirror to examine a tooth that is 1cm in front of the mirror. The image of the tooth forms 10cm behind the mirror.
a. What is the mirror's radius of curvature?
b. What is the magnification of the image?
a) The mirror's radius of curvature will be 2.7 cm
B) The magnification of the image will be 4.0.
What is a concave mirror?When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.
From the mirror equation;
\(\frac{1}{p}+\frac{1}{q} =\frac{1}{f} \\\\ \frac{1}{1}+\frac{1}{-10} =\frac{1}{f} \\\\ \frac{1}{f} = 1-\frac{1}{10} \\\\ \frac{1}{f} = \frac{9}{10} \\\\ f= 1.1111\)
Hence,
The radius of curvature is twice of the focal length;
\(\rm R = 2f \\\\ \rm R = 2\times 1.111 \\\\ R=2.2222 \ cm\)
Hence, the mirror's radius of curvature will be 2.7 cm.
The magnification factor is found as;
\(\rm m = \frac{-q}{p} \\\\ m = \frac{-(-10)}{1} \\\\ m = 10\)
Hence, the magnification of the image will be 4.0.
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imagine a unit of time called the cosmic year. in the entire existence of the universe, only one cosmic year has passed. Astronomers estimate that the age of the universe is 13.8 billion normal years. if a cosmic year consists of 365 cosmic days, calculate how many earth years a cosmic day is equivalent to.
A cosmic day is equivalent to approximately 13.8 billion Earth years.
To calculate how many Earth years a cosmic day is equivalent to, we need to determine the length of a cosmic year in Earth years and then divide it by 365 to find the duration of a cosmic day.
Given that the age of the universe is estimated to be 13.8 billion normal years, and only one cosmic year has passed in that time, we can conclude that a cosmic year is equal to 13.8 billion normal years.
To convert this into Earth years, we multiply the length of a cosmic year by 365, since there are 365 days in a normal year.
13.8 billion normal years * 365 = 5.04 trillion Earth years.
Now, to find the duration of a cosmic day, we divide the length of a cosmic year in Earth years by 365 (the number of cosmic days in a cosmic year).
5.04 trillion Earth years / 365 = 13.8 billion Earth years.
Therefore, a cosmic day is equivalent to approximately 13.8 billion Earth years.
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describe the energy transfers of an electron around a circuit when the switch is closed
Answer:
When a switch is closed, electrons move through a circuit from the negative side of a battery to the positive side
Explanation:
Note that current is marked to flow from positive to negative on circuit diagrams, but that's for historical reasons only. Benjamin Franklin did a fabulous job of understanding what was going on, but no one yet knew about protons & electrons, so he assumed current was flowing from positive to negative.
However, what really happens is electrons flow from negative (where they repel each other) to positive (where they are attracted).
As electrons flow through a circuit, they need 'something to do'. In many cases, that something is to light a bulb or heat an element, such as an element on a stove. So, the energy of an electron can be converted to heat or light.
I hope I'm understanding your question correctly
Explain how a raccoon is helping the environment when it eats the fruit of a plant.
Answer: When a raccoon eats a fruit it eats the seeds that are in the fruit. When the raccoon goes to the bathroom it expels the seeds that are in the feces which plants them.
Answer:
The raccoon is helping to spread the seeds of the plant
Explanation:
julie drives 100 mimi to grandmother's house. on the way to grandmother's, julie drives half the distance at 34.0 mphmph and half the distance at 66.0 mphmph . on her return trip, she drives half the time at 34.0 mphmph and half the time at 66.0 mphmph .
The average speed is r=50 mph
What is speed?Teenagers, young adults, and others use the stimulant medication known as "speed" to feel more focused and alert, and occasionally to get euphoric. Several types of speed are also used by some people to suppress their appetite. Different speed types include: Amphetamines (used to treat ADHD, narcolepsy, and depression)
In essence, an object's speed indicates how quickly it is moving. Its velocity reveals how quickly it is moving in a specific direction. In your daily life, you utilize speed measures, but in physics, velocity measurements are more frequently used.
distance=rate*time
total distance=rate*total time
to Grandmother's...
50=34*t
50/34=t
t=25/17 hours for the first 50 miles
50=66*t
50/66=t
t=25/33 hours for the second 50 miles
total distance=50+50=100 miles
total time=25/17+25/33
total time=(825/561)+(425/561)=1250/561 hours
total distance=rate*total time
100=r*(1250/561)
r=(100)(561/1250)
r=56,100/1250
r=5610/125
r=1122/25
r=44.88 mph is the average speed (rounded it is 44.9 mph)
Note: If you are familiar with the simplified form of the harmonic mean you can solve the problem that way. If not, that's okay. You can look it up if you like.
(2*34*66)/(34+66)=4488/100=44.88 again
from Grandmother's house...
because the times are the same you simply add the 2 rates and divide by 2
(34+66)/2=100/2=50 mph is the average speed
d=r*t
100=34*t+66*t (the times are the same, t)
100=100*t
t=1 hour traveling at 34 mph and 1 hour traveling at 66 mph for a total of 2 hours traveling
d=r*t
100=r*2
r=100/2
r=50 mph is the average speed
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What is the correct definition of a rarefaction?
A: region of zero pressure in a medium caused by a passing wave
B: region of low pressure in a medium caused by a passing wave
C: region of low altitude in a medium caused by a passing wave
D: region of high pressure in a medium caused by a passing wave
Answer: B
Explanation:
For a given radius, what happens to the angular acceleration as linear acceleration increases?
Linear acceleration and angular acceleration are directly proportional. The greater the linear acceleration, the larger the angular acceleration.
For example, the greater the angular acceleration of a bike's wheels, the greater the acceleration of the bike.
suppose a rocket launches with an acceleration of 30.5 m/s2. what is the apparent weight of a 92-kg astronaut aboard this rocket?
The apparent weight of a 92-kg astronaut aboard this rocket 3707 N.
What is the apparent weight ?A rocket launches with an acceleration of 30.5 m/s2.
velocity = 30.5 m/s2
astronaut weighs 92 kg.
To locate
The astronaut's apparent weight is equal to
Solution:
According to, the astronaut's overall weight in a rocket is
W = w + F
W stands for the astronaut's perceived weight
astronaut weight on Earth's surface: grams
F = astronaut's force multiplied by ma
W = mg+ma
W = m (g+a)
W = 92 (9.8 + 30.5)
W = 3707 N
As a result, the astronaut in the rocket appears to weigh 3707 N.
The apparent weight of a 92-kg astronaut aboard this rocket 3707 N.
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The variables for Part I of this experiment include whether or not the car hits the barrier and the distance that the washers travel. Use the drop-down menus to identify the independent and dependent variables.
The independent variable, the one that is intentionally manipulated, is
____.
The dependent variable, the one that you measure the response in, is
___.
Answer:
1. An encounter with the barrier
2. The distance traveled by the washer.
Explanation:
Answer:
Peep above me is correct
1.An encounter with the barrier
2.The distance traveled by the washer
Explanation:
got it right on edge2020 have a nice day peeps ^w^
At a specific location, a 25.0-kg mass has a weight of 40.5 newtons. What is the acceleration due to gravity at this location?
A.) 0.617 m/s2
B.) 1.62 m/s2
C.) 9.81 m/s2
D.) 1010 m/s2
Answer:
The answer is option AExplanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
f is the Force
m is the mass
From the question we have
\(a = \frac{25}{40.5} \\ = 0.617283950...\)
We have the final answer as
0.617 m/s²Hope this helps you
Randy has a sheet of paper. He cuts a square out of the center. Which of the following physical properties of the paper changes
Answer:
Mass
Explanation:
Answer:
mass
Explanation: less room is taken up