Cellular respiration is a chemical process in cells that releases energy the cells need to function. What statement below is true about this reaction.

A. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is equal to the energy required to break the bonds of sugar and oxygen.
B. The process of cellular respiration releases energy because the energy that is released when the bonds that are formed in CO2 and water is lost when bonds of glucose and oxygen are broken.
C. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is less than the energy required to break the bonds of sugar and oxygen.
D. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is greater than the energy required to break the bonds of sugar and oxygen.

Answer:

an electrical generator

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

159.69 g/mol

Explanation:

Here's the answer hope it helps

Answer

The matching is numbered and represented in red arrowsi n the diagram below:

Explanation

In a steam turbine electricity generation, the mechanical energy in form of pressure present in steam is extracted and converted into kinetic energy by allowing the steam to flow through the stationary blades. This kinetic energy is transmitted to the moving blades connected to the alternator of a steam turbine generator.

The matching of the process is shown below:

Answer:

francium is the answer

Explanation:

It should be noted that the element in period 5 has the largest atomic radius is Francium.

It should be noted that an atomic radius simply means the measure of the size of the atom from the center of the nucleus.

In this case, the element in period 5 has the largest atomic radius is Francium while Helium has the smallest radius.

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Answer: The final pressure is 0.81 kPa

Explanation:

The combined gas equation is,

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

where,

\(P_1\) = initial pressure of gas = 0.58 kPa

\(P_2\) = final pressure of gas = ?

\(V_1\) = initial volume of gas = v

\(V_2\) = final volume of gas = \(v-\frac{40}{100}\times v=0.6v\)

\(T_1\) = initial temperature of gas = \(25^0C=(25+273)K=298K\)

\(T_2\) = final temperature of gas = \(-22^0C=(-22+273)K=251K\)

Now put all the given values in the above equation, we get:

\(\frac{0.58\times v}{298}=\frac{P_2\times 0.6v}{251}\)

\(P_2=0.81kPa\)

The final pressure is 0.81 kPa

Taking into account the definition of molarity, the number of moles of MgCl₂ present in 60.0 mL of 0.100 M MgCl₂ solution is 0.006 moles.

Molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by:

molarity= number of moles of solute÷ volume

Molarity is expressed in units moles/L.

In this case, you have:

Replacing in the definition of molarity:

0.100 M=number of moles of MgCl₂÷ 0.06 L

Solving:

0.100 M × 0.06 L= number of moles of MgCl₂

0.006 moles= number of moles of MgCl₂

Finally, the number of moles of MgCl₂ is 0.006 moles.

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Differential heating leads to convection currents. Warm material that is lighter and less dense rises whereas cool material that is heavier and more dense sinks. Circulation patterns are created by this movement.

What does heating serve as?

Heating is the act of improving the temperature of the an confined place with the primary goal of assuring the pleasure of the users. Heating helps to maintain a building's structural, hydraulic, and electrical components by controlling the ambient temperature. An open fire was the earliest type of internal heating.

A central heating system: what is it?

heating system. A system of central heating distributes heat from one place to numerous rooms throughout the inside of a structure (or part of a building). The entire system, when combined with additional systems to regulate the indoor environment, may be an HVAC (heating, ventilation, and air con) system.

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For the above compounds, the order of increasing lattice energy is MgO, NaCl, CsI, and AlN.

Because the ionic species in MgO have greater charge (Mg+2 and O2- as opposed to Na+ and Cl-), the ionic bond is stronger than it is in NaCl. As a result, MgO has greater ionic connections than NaCl. MgO is hence more ionic than NaCl.

The size of the ions involved has an inverse relationship with lattice energy in ionic compounds. MgO has the highest lattice energy because Mg2+, the smallest of the four ions (because anion is the same in all), is present.

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312.5 mL of the stock solution are required to prepare 1.5 L of 25 mg mL solution.

In this problem you get that 312.5 mL of the stock solution are required to prepare 1.5 L of 25 mg mL solution.

First of all, you have to know that when it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

120 \(\frac{mg}{mL}\)× Vi= 25

Solving:

\(Vi=\frac{25\frac{mg}{mL}x1500 mL}{120 \frac{mg}{mL}}\)

Vi= 312.5 mL

In summary, 312.5 mL of the stock solution are required to prepare 1.5 L of 25 mg mL solution.

Learn more about dilution:

Answer:

1. AgNO₃ (aq) + NaCl (aq) ----> NaNO₃ (aq) + AgCl (s)

2. Li₂SO₄ (aq) + BaCl₂ (aq) ----> 2 LiCl (aq) + BaSO₄ (s)

3. 2 NaOH (aq) + MgCl₂ (aq) ----> 2 NaCl (aq) + Mg(OH)₂ (s)

Explanation:

The reaction involving the mixing of two soluble solutions to produce a precipitate is known as a precipitation reaction.

A precipitation reaction is double-replacement reaction (a reaction that exchanges the cations or the anions of two ionic compounds) in which one product is a solid precipitate.

Precipitation reactions at useful in the identification of various ions present in a solution. In order to predict the reactions that will produce a precipitate, solubility rules as given in the solubility table below can be used.

From the tables, the reactions that will produce a precipitate, as well as their balanced molecular equations are as follows:

1. AgNO₃ (aq) + NaCl (aq) ----> NaNO₃ (aq) + AgCl (s)

2. Li₂SO₄ (aq) + BaCl₂ (aq) ----> 2 LiCl (aq) + BaSO₄ (s)

3. 2 NaOH (aq) + MgCl₂ (aq) ----> 2 NaCl (aq) + Mg(OH)₂ (s)

Answer:

0.25 grams

Explanation:

mass = (concentration x volume) / 100

The concentration of ketamine is 10.0%w/v and the volume is 2.50 ml.

mass = (10 x 2.50) / 100

mass = 0.25 g

So, there is 0.25 grams of ketamine in 2.50 ml of a 10.0% (w/v) solution.

Taking into consideration their size, impairment Weights should be positioned to enhance equilibrium and stability without compromising mobility. Wheels are angled to increase speed and maneuverability.

The speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar number.

It's easy to understand why. Velocity is the pace and orientation of an item's movement, whereas speed is the tracking at which an entity is travelling along a route.

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The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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Answer:

A

Explanation:

The balanced reaction equation including products as; Al + 3AgCl -------> AlCl3 + 3Ag

The activity series is an arrangement of metals according to their reactivity. The metals that are more reactive are found above in the series while the metals that are least reactive are found below.

Looking at the activity series of metals, if we have the reaction; Al + AgCl, we can write the balanced reaction equation including products as;

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During the formation of a nitrogen molecule, each nitrogen atoms have five valence electrons provided with three electrons to form three electron pairs for sharing. Therefore, a triple bond is formed between the two nitrogen atoms.

Valence electrons are defined as the electrons present in the outermost shell, or energy level, of an atom. For example, element oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell. The electronic configuration of oxygen's valence electrons is 2s²2p⁴.

Hence, nitrogen atoms have five valence electrons provided with three electrons to form three electron pairs for sharing.

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Go to the Data tab > Sort & Filter group, and click Clear.

Go to the Home tab > Editing group, and click Sort & Filter > Clear.

Hello, this is Bing. I can help you with your question. Based on the information I found on the web, **H2** can be broken down into its two atoms of hydrogen (H) by supplying enough energy to overcome the bond that holds them together⁴. This process is called **dissociation** and requires an energy equal to or greater than the **dissociation energy** of H2, which is about 436 kJ/mol⁴.

One way to break down H2 is by using **electricity** to split water (H2O) into hydrogen (H2) and oxygen (O2) through a process called **electrolysis**¹. In this process, water is decomposed into its elements by passing an electric current through it. The electric current is provided by a battery or another source of electricity and the water needs to have an **electrolyte**, such as salt or acid, added to it to make it conductive¹. Two electrodes, usually made of metal or other conductive material, are inserted into the water and connected to the battery. The electrode connected to the positive terminal of the battery is called the **anode** and the one connected to the negative terminal is called the **cathode**¹. When the electric current flows through the water, hydrogen gas bubbles form at the cathode and oxygen gas bubbles form at the anode¹. The overall chemical reaction for electrolysis of water is:

2 H2O → 2 H2 + O2

Another way to break down H2 is by using **heat** to cause a reaction between hydrogen and oxygen that produces water and releases a large amount of energy. This reaction is called **combustion** or **oxidation** and can be ignited by a spark or a flame³. The reaction is very fast and explosive and can be dangerous if not controlled. The overall chemical reaction for combustion of hydrogen is:

2 H2 + O2 → 2 H2O

I hope this helps you understand how H2 can be broken down and what methods are used to do so.

Answer:

Particles of matter possess energy called kinetic energy.

Solid cannot be compressed, but gases are highly compressible.

The Kinetic energy of molecules of gases is very large & solids the least.

On heating a sublimable liquid, the molecules break free & escape from the surface of the solid directly into vapour.

Particles of matter move more rapidly on the application of heat

A reaction that looks to follow second-order kinetics but is not actually a second-order reaction is described by the pseudo-second order (PSO) model.

A chemical reaction that looks to follow second-order kinetics but is not actually a second-order reaction is referred to as pseudo second order (PSO) in a kinetic model.

It is frequently seen in reactions where one reactant's concentration is substantially higher than that of the other reactant, resulting in an abundance of the abundant reactant that remains essentially constant throughout the reaction.

The rate equation in PSO kinetics has the following structure:

1/t = k * [A] * [B]

where [A] and [B] stand for the reactant concentrations, k for the rate constant, and t for the passage of time. According to the equation, the rate of the reaction is inversely proportional to the product of the reactant concentrations.

The consumption of the limiting reactant, which determines the total reaction rate, is what causes the apparent second-order behaviour. The rate of the reaction falls together with the concentration of the limiting reactant with time.

Adsorption reactions, surface reactions, or situations where one reactant is present in excess of the other are frequently described by the PSO model. The PSO model is an approximation and does not imply a real second-order reaction mechanism, it is vital to remember this.

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The pressure of the gas when the temperature changes from -75.0°C to 1000.0°C will be approximately 9.51 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

Given that:

We substitute our values into the expression above.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

\(P_2 = \frac{P_1T_2}{T_1}\\ \\P_2 = \frac{1.480\ *\ 1273.15 }{198.15} \\\\P_2 = 9.51 \ atm\)

Therefore, the final pressure is 9.51 atm.

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The resulting pH of the solution is 1.74(approx).

To solve this problem, we need to use the concept of acid-base equilibrium and the pH scale. The addition of sulfuric acid will increase the concentration of H+ ions in the solution, which will shift the equilibrium of the \(H_2S\)/HS- system. We can use the following equation to calculate the pH of the resulting solution:

Ka = [H+][HS-]/\(H_2S\)]

where Ka is the acid dissociation constant for \(H_2S\), [\(H_2S\)], [HS-], and [H+] are the concentrations of the \(H_2S\), HS-, and H+ ions, respectively.

First, we need to calculate the initial concentrations of\(H_2S\) and HS- in the solution:

[\(H_2S\)] = 0.505 M

[HS-] = 0.505 M

Next, we need to calculate the amount of H+ ions added to the solution by 1 mL of concentrated sulfuric acid. To do this, we can use the following equation:

[H+] = (n/V) = (18.4 mol/L) x (1x\(10^{-3}\) L) = 1.84 x\(10^{-2}\)mol

where n is the amount of sulfuric acid added in moles, V is the volume of the solution in liters, and 18.4 mol/L is the concentration of the sulfuric acid.

Now, we can calculate the new concentrations of \(H_2S\), HS-, and H+ ions in the solution:

[\(H_2S\)] = [\(H_2S\)]0 - [H+] = 0.505 - 1.84x\(10^{-2}\)= 0.486 M

[HS-] = [HS-]0 + [H+] = 0.505 + 1.84x\(10^{-2}\) = 0.524 M

[H+] = 1.84 x \(10^{-2}\)M

Finally, we can use the equation for Ka to calculate the pH of the resulting solution:

Ka = 1.1 x \(10^{-7}\)

[H+] x [HS-]/[\(H_2S\)] = Ka

pH = -log[H+]

Substituting the values, we get:

(1.84 x \(10^{-2}\)) x (0.524)/(0.486) = 1.98 x \(10^{-2}\)

pH = -log(1.98 x \(10^{-2}\)) = 1.74(approx)

Therefore, the resulting pH of the solution is 1.74(approx)

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Answer:The right answer is they don’t belong with it

Explanation:He didn’t cause

Answer:

if you want to find average speed so u need to use this formula

Average speed = \(\frac{Total Displacement}{Total Time}\)

Easy!!

2+17=19

#hope that helps

Answer:

To find the answer you may

2+17=19

Explanation:

so that is the answer I'm sorry,to not give all the solutions

the pH of the aqueous solution is 8.51 with a hydrogen ion concentration of [H+]=3.1×\(10^-9\)M

The pH of the aqueous solution can be calculated using the formula:

pH = -log[H+]

where [H+] is the hydrogen ion concentration of the solution.

Substituting the given value, we get:

pH = -log(3.1×\(10^-9\))

pH = 8.51

An aqueous solution is one in which water serves as the solvent. It is utilised in a variety of applications, including analytical chemistry, biochemistry, and industrial chemistry. It is the most prevalent kind of solution used in chemical reactions. Water serves as both the solvent and the solute in an aqueous solution, where the solute is often a solid, liquid, or gas. Due to its high polarity and capacity to make hydrogen bonds with other molecules, water is an excellent solvent that can dissolve a variety of materials, including polar molecules and ionic compounds. Acid-base reactions, redox reactions, and precipitation reactions are just a few of the numerous chemical processes that take place in aqueous solutions. A variety of variables can have an impact on an aqueous solution's characteristics.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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According to stoichiometry, the mass of phosphorus would be present in the sample is 77.66 grams.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given example, 98 g of phosphorous acid has 30 g phosphorous, thus 253.7 g sample of phosphorous acid will have 253.7×30/98=77.66 grams.

Thus, the mass of phosphorus would be present in the sample is 77.66 grams.

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