Answer:
Hey There!
Refer to the attachment...
or in this way also you can solve shown in second attachment
I hope it is helpful to you...Cheers!_________Which have the longer wavelength, radio waves or microwaves?
The correct answer in that the Radio waves have a longer wavelength than microwaves.
Radio waves have a wavelength range of about 1 millimeter to 100 kilometers, while microwaves have a wavelength range of about 1 millimeter to 1 meter. This means that radio waves have a longer wavelength than microwaves in general. Wavelength is related to the frequency of the electromagnetic wave by the equation: λ = c / f, where λ is the wavelength, c is the speed of light, and f is the frequency. Since the speed of light is constant, a longer wavelength corresponds to a lower frequency and vice versa. Radio waves are commonly used for communication and broadcasting, while microwaves are used for a variety of applications including cooking food, radar, and wireless communication. Understanding the properties of different electromagnetic waves, including their wavelength and frequency, is important for many areas of science and technology.
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help me please!! in a stankey diagram, what does the thickness of the lines represent?
Answer: The thickness of the vertical flow lines indicates the relative quantity.
The thickness of the vertical flow lines indicates the relative quantity.
What is vertical flow?A vertical flow constructed wetland is a planted filter bed that is drained at the bottom. Wastewater is poured or dosed onto the surface from above using a mechanical dosing system. The water flows vertically down through the filter matrix to the bottom of the basin where it is collected in a drainage pipe.Vertical flow immunoassays rely on the same basic principles as the more common lateral flow immunoassay format with some modifications. The most apparent difference between the two methods being the vertical and lateral flow of fluid. However, vertical flow technology has several advantages over traditional lateral flow assays with the most significant being the reduced assay time (<5 minutes), table I.To learn more about vertical flow refer to:
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A car traveling west in a straight line on a highway
decreases its speed from 30.0 meters per second to
23.0 meters per second in 2.00 seconds. The car's average acceleration during this time interval is
1. 3.5 m/s2 east
2.3.5 m/s² west
3.13 m/s² east
4.13 m/s² west
Answer: 7/2, 3.5 and 1
3-----
2
based on the condition given condition, formulate;
30-23/2
Calculate: 30-23/2
How much work is done in the vertical direction if 125 N of force is needed to hold an object at shoulder height as a person walks 2 m forward
Work is the product of force multiplied by the distance moved, but since the distance moved in the vertical direction is zero
Work Done = 0 joules
Given data
Force = 125N
Horizontal Distance = 2 m
Vertical distance = 0 m
Formula for workWork = Force * Distance
Solution
substitute the given information
Work Done in the horizontal direction= 125*2
Work Done = 250 Joules
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pls help with my science homework
3b
A. Time taken for swing of a pendulum is 2.3 seconds per swing.
B. To find the time for one swing more accurately, the student can increase the number of swings, use a stopwatch with higher precision, minimize external disturbances, and repeat the experiment to calculate the average time.
The time taken for 20 swings of a pendulum is 46 seconds. To find the time for one swing, we need to divide the total time by the number of swings.
a. Time for one swing: 46 seconds / 20 swings = 2.3 seconds per swing.
To find the time for one swing more accurately, the student can employ the following techniques:
1. Increase the number of swings: By measuring the time for a larger number of swings, the student can reduce the impact of measurement errors and obtain a more precise average time. For example, measuring the time for 100 swings and then dividing by 100 would provide a more accurate estimate.
2. Use a stopwatch or timer with higher precision: Using a stopwatch or timer that provides more decimal places or higher precision can help capture smaller time intervals more accurately. This can reduce rounding errors and improve the accuracy of the measurement.
3. Minimize external disturbances: To ensure accurate timing, it is important to minimize external disturbances that may affect the pendulum's motion, such as air drafts or vibrations. Conducting the experiment in a controlled environment can help reduce these disturbances and enhance measurement accuracy.
4. Repeat the experiment: Performing the measurement multiple times and calculating the average time can help account for any inconsistencies or random errors in the measurements. This can lead to a more reliable and accurate estimate of the time for one swing.
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a 12.0 kg monkey starts to climb a long rope to reach a banana located at a height of 6.80 m. the rope will snap if the tension exceeds 132 n. calculate the least amount of time the monkey could take to reach the banana without breaking the rope.
The least amount of time it will take to reach the rope without breaking is 0.70 seconds .
Force required to lift it is equal to its weight = 12.0 kg x 9.81 m/s² = 117.72 N.
The rope will snap if the tension exceeds 132 N. Therefore, the tension in the rope must be less than or equal to 132 N.
Tension in the rope :
T = 117.72 N + (12.0 kg x -9.81 m/s²) = 0 N
Time taken to reach banana:
t = d/s = 6.80 m / 9.81 m/s² = 0.70 s
Therefore, the least amount of time the monkey could take to reach the banana without breaking the rope is 0.70 seconds.
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I need help Will give five stars please show work please
Answer:
These has anwers and also the solution. You can recheck if you want.
If speed is measured in meters per seconds (m/s) and time is measured in seconds, the SI unit of acceleration is m/s2. Imagine you are riding a motorcycle that is accelerating at a rate of 6 m/s2. What is the motorcycle’s speed after three seconds of acceleration?
Answer:
please let me know when you find it
Explanation:
i have the same question and cant find it
Answer:
It’s 5m/s^2
Explanation:
Ed biked home from school in 400 seconds. His home is located 2000 m south of the school. What was his velocity?
\(answer = 5 \: \: metre \: per \: second\\ distance = 2000 \: m \\ time = 400 \: seconds \\ velocity = \: \frac{distance \:t ravelled}{time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2000}{400} \\ \: \: \: \: \: \: \: \: \: = 5 \: metre \: per \: second \\ hope \: it \: helps\)
Select the correct answer.
Mary pushes a crate by applying force of 18 newtons. Unable to push it alone, she gets help from her friend, Anne. Together they apply a force of
43 newtons, and the crate just starts moving. If the coefficient of static friction is 0.11, what is the value of the normal force?
OA. 2.0 x 102 newtons
OB.
2.6 x 10² newtons
O C.
O D.
OE.
3.9 x 10² newtons
4.0 x 10² newtons
4.3 x 10² newtons
The value of the normal force is 3.9 x 10² newtons.
The correct answer is option C.
The coefficient of static friction between the crate and the floor is 0.11. The crate just starts moving after the force of 43 N is applied by Mary and Anne. Therefore, the force of friction that acts on the crate is equal to the maximum value of static friction, which is given by the product of the coefficient of static friction and the normal force.
The force of friction is given by: f = μN
where f is the force of friction, μ is the coefficient of static friction and N is the normal force acting on the crate.
Since the crate just starts moving, the applied force must overcome the maximum force of static friction.
Therefore, we have:
f = μNmax
and F applied = F required to overcome friction
= μNmax= 0.11 N
Thus, the maximum value of the normal force acting on the crate is given by:
Nmax = F/f = 43/0.11 = 390.9 N ≈ 3.9 x 10² N
Therefore, the value of the normal force is 3.9 x 10² newtons.
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A kettle transfers 6000 J of energy electrically. 1500 J of this is wasted. What is the efficiency of this kettle?
Answer:
Effi = 75 %
Explanation:
That is, the 6000 [J] is electrical energy that is transferred to the liquid, of that amount of energy 1500 [J] is dissipated or lost.
That is, from that amount of energy the difference between the energy that is supplied and the one that is lost is the energy that absorbs the liquid in the kettle.
\(Q=6000-1500\\Q=4500[J]\)
That is 4500 [J] enter the liquid that is heated.
Efficiency can be calculated as the amount of energy that the liquid receives over the energy that is supplied.
\(Effi = 4500/6000\\Effi = 0.75\)
A 0.68 kg squirrel is resting on a branch 8 meters above the ground. What is the gravitational potential energy of a squirrel? A: 2.27 J. B :5.44 J. C :21.76 J. D :53.312 J
Answer:
The gravitational potential energy of a squirrel is 53.312 J.
Explanation:
We have,
Mass of a squirrel is 0.68 kg
It is placed at a height of 8 m above the ground.
It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :
\(E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J\)
So, the gravitational potential energy of a squirrel is 53.312 J.
Which of the following best reduces atmospheric distortion?
adaptive optics
The best reduces atmospheric distortion is through adaptive optics.
Optical aberrations can be fixed using a technology called adaptive optics (AO). The work that led to the Nobel Prize-winning discovery of a supermassive compact object at the center of our galaxy was made possible by a method that was initially devised to account for the blurring effect of atmospheric turbulence on images in ground-based observatories. We can research the functioning of the visual system and evaluate ocular health in the microscopic domain when AO is employed to compensate for the eye's defective optics.
By detecting retinal changes at the cellular level, AO allows us to adjust for the eye's imperfect optics. AO has expanded the capabilities of imaging in thick tissue specimens, such as when examining neuronal processes in the brain, by correcting for sample-induced blur in microscopy.
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If a 1000 kg car is traveling at 3
meters per second, what is its
kinetic energy?
at the instant shown, rank these six scenarios on the basis of the magnitude of the current in the light bulb.
At the instant shown, the six scenarios can be ranked in terms of the magnitude of current in the light bulb as follows:
1) Scenario 1 - Here, the battery is directly connected to the light bulb without any other resistors in the circuit. Therefore, the current flowing through the bulb will be the maximum among all the scenarios.
2) Scenario 3 - In this case, the battery is connected to the light bulb through a resistor. However, the resistance is less compared to other scenarios, so the current will be higher than in other cases.
3) Scenario 4 - Here, the battery is connected to the light bulb through a higher resistance compared to scenario 3. This will result in a lesser current in the bulb.
4) Scenario 5 - In this scenario, the battery is connected to the light bulb through a much higher resistance than in the previous two scenarios. Therefore, the current flowing through the bulb will be lower.
5) Scenario 6 - Here, the battery is connected to the circuit in such a way that the current will bypass the light bulb. Therefore, the bulb will not light up and the current flowing through it will be zero.
6) Scenario 2 - This scenario is similar to scenario 6 where the switch is open, so the circuit is not complete, and hence there will be no current flowing through the light bulb.
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True or false? The period of an AC supply is equal to the time between an adjacent peak and trough on an oscilloscope trace.
Answer:
false
Explanation:
the time period is for a whole cycle of the wave, so peak-to-peak on an oscilloscope trace.
As the number of resistors in a parallel circuit is increased, what happens to the
equivalent resistance of the circuit and total current in the circuit?
Answer:
resistance- decreases current-increases
Objects on Mars weigh about 38% what they do on Earth. While driving on Earth, a Mars rover moves at a speed of 30 mph. If the rover moves with the same speed on Mars, would it have more, less, or the same momentum as when on Earth
Answer:
The same momentum as when on Earth
Explanation:
From a background understanding of science, the mass of an object is constant irrespective of its location.
This implies that the rover has the same mass on the earth as on the moon.
Now, we shall determine the momentum of the rover on Earth and on the Mar.
For Earth:
Let the mass on Earth (Mₑ) = 1 kg
Velocity on Earth (Vₑ) = 30 mph = 30 × 0.447 = 13.41 m/s
Momentum on Earth (Mₒₑ) =?
Momentum = mass × velocity
Mₒₑ = Mₑ × Vₑ
Mₒₑ = 1 × 13.41
Mₒₑ = 13.41 Kgm/s
Thus the momentum of the rover on Earth is 13.41 Kgm/s
For Mar:
Mass on Mar (Mₘ) = Mass on Earth (Mₑ), since mass is constant.
Mass on Mar (Mₘ) = 1 kg
Velocity on Mar (Vₘ) = Velocity on Earth (Vₑ), since the rover move with the same velocity as described by the question.
Velocity on Mar (Vₘ) = 13.41 m/s
Momentum on Mar (Mₒₘ) =?
Momentum = mass × velocity
Mₒₘ = Mₘ × Vₘ
Mₒₘ = 1 × 13.41
Mₒₘ = 13.41 Kgm/s
Therefore, the momentum of the rover on Mar is 13.41 Kgm/s
Summary:
Momentum on Earth (Mₒₑ) = 13.41 Kgm/s
Momentum on Mar (Mₒₘ) = 13.41 Kgm/s
Thus, the rover will have the same momentum as when on earth
The momentum of the object on Mars will be the same as on Earth.
The given parameters;
speed of the object on Earth and Mars, v = 30 mphWeight is a vector quantity because it changes when acceleration due to gravity on the object changes while mass is scalar quantity, with a constant value in all places in the universe.
The momentum of an object is calculated as;
P = mv (kgm/.s)
Since the speed and mass of the object will be the same on both planets, the momentum will also be the same.
Thus, the momentum of the object on Mars will be the same as on Earth.
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two people are pulling ends of a rope. each person pulls with a force of 100 n. what is the tension in the rope
When two people are pulling ends of a rope each person pulls with a force of each person pulls with a force of 100 N then the tension in the rope is 100N.
Consider changing the circumstance. Simply substitute a wall for one of the pupils. One pupil uses 100N to pull. According to the imagined spring scale between student and wall, the tension in the rope is 100N. If the person and rope are both motionless, we may calculate that the wall produces a reaction force of 100N, implying that no acceleration is feasible. Now, substituting the wall with a student as the response force has no effect on the spring scale reading or rope tension 100N.
Force is responsible for the motion of object.
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State the general purpose of an experiment, using the terms dependent and independent variable
Answer:
Image result for State the general purpose of an experiment, using the terms dependent and independent variable
You can think of independent and dependent variables in terms of cause and effect: an independent variable is the variable you think is the cause, while a dependent variable is the effect. In an experiment, you manipulate the independent variable and measure the outcome in the dependent variable
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47. explain why the abundances of heavy elements in stars correlate with their positions in the galaxy.
The presence of heavy elements in stars correlates with their positions because these elements show which star formed first, and a star's brightness and spectral type show where it is in the galaxy.
Heavy elements are present in population I stars. It is concentrated in the discs of spiral galaxies and typically contains the sun. It is also hot, youthful, and brilliant. The majority of them are found in spiral arms. In globular clusters and the outer galactic halo, where the concentration of heavy elements is relatively low, population II stars are born. The important information to compare the locations of the stars is therefore their abundances of heavy metals. Energy must be added in order for elements heavier than iron and nickel to develop.
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What are the energy transformations that occur during a roller coaster ride? 1 paragraph
Answer:
The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy. Roller coasters rely on gravity to take them to the end of the track. This involves two types of energy, potential energy and kinetic energy.
Explanation: my mom told me lol ..
Answer:
The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy.
Explanation:
That's gonna help right?
The steepest street in the world is Baldwin Street in Dunedin, NZ. It is inclined at an angle of 380 , with the horizontal. A child slides down the street with a constant velocity on a sled with high friction runners. What is the coefficient of friction between the sled runners and the street?
Newton's second law allows to find the result for the friction coefficient of the street is:
The friction coeficinwete is: μ = 0.78
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.
∑ F = m a
Where bold indicates vectors, m is to mass and acceleration.
In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.
Let's use trigonometry to break down the weight.
Sin θ = \(\frac{W_x}{W}\)
cos θ = \(\frac{W_y}{W}\) / W
Wₓ = W sin θ
\(W_y\) = W cos θ
We write Newton's second law for each axis.
y-axis
N- \(W_y\) = 0
N = mg cos θ
x-axis
Wₓ - fr = ma
Since they indicate that the body goes down at a constant speed, the acceleration is zero.
W sin θ = fr
The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.
fr = μ N
we substitute.
fr = μ mg cos θ
mg sin θ = μ cos θ
μ = tan θ
Let's calculate.
μ = tan 38.0
μ = 0.78
In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:
The frivtion coefficient is: μ = 0.78
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rocket a leaves a space station with a speed of 0.811c. later, rocket b leaves in the same direction with a speed of 0.665c. what is the velocity of rocket a as observed from rocket b?
Relative velocity implies the the velocity of a given object being observed from another object. The relative velocity of rocket A relative to B is 4.38 x \(10^{7}\) m/s.
Relative velocity is the velocity of a given object with respect to a reference frame. Thus if the reference frame is another object at motion, then;
i. the velocity of A relative to B (Vab) = Va - Vb
ii. the velocity of B relative to A (Vba) = Va - Vb
In the given question, it can be deduced that:
speed of rocket a = 0.811c
where c = 3.0 x \(10^{8}\)
speed of rocket A = 0.811 x 3 x \(10^{8}\) m/s
= 243300000 m/s
speed of rocket B = 0.665 x 3.0 x \(10^{8}\) m/s
= 199500000 m/s
The velocity of rocket A relative to B = Va - Vb
= 243300000 - 199500000
= 43800000 m/s
The velocity of rocket A as observed from rocket B is 4.38 x \(10^{7}\) m/s.
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A ball is thrown across a field. Its height is given by A(z) ma is the ball's horizontal distance from the thrower's feet.What is the greatest height reached by the ball, and what is the horizontal distance to the thrower's feet at this point? rom what height was the ball thrown? hat is the horizontal distance to the thrower when the ball hits the ground?
The greatest height reached by the ball is given by A(z) and the horizontal distance to the thrower's feet at this point is denoted as D.
The height from which the ball was thrown is represented as H. The horizontal distance to the thrower when the ball hits the ground is denoted as Dg.
The greatest height reached by the ball is A(z), and the horizontal distance to the thrower's feet at this point is D. The ball was thrown from a height of H.
The horizontal distance to the thrower when the ball hits the ground is Dg.
Determine the horizontal distance?To find the greatest height reached by the ball, we need to analyze the function A(z). The horizontal distance D to the thrower's feet at this point can be determined by considering the horizontal component of the ball's motion.
To calculate the height from which the ball was thrown, we can use the initial condition or other given information.
Finally, to determine the horizontal distance Dg when the ball hits the ground, we need to analyze the ball's trajectory and identify the point at which its height becomes zero.
These calculations involve analyzing the ball's motion in both the horizontal and vertical dimensions, incorporating factors such as initial velocity, angle of projection, and gravitational acceleration.
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PLEASE HELP Due Soon!
What are two examples of chemical energy being transformed?
Answer:
Hope I can help you.
Explanation:
Here u go here are some that you can choose from! :)
1) Air bags are activated by a chemical reaction inside the bag. A sensor turns on an electrical circuit, and then sodium azide is ignited. The reaction that occurs generates nitrogen gas, which fills the bag at an extremely rapid rate.
2) Baking soda and vinegar produce carbon dioxide gas when mixed. As this gas grows in volume, it puts pressure on whatever container it is in, and will erupt out of an opening in the container, creating a volcano effect. This chemical reaction is safe, making it a great science activity for kids.
3) Batteries have two terminals: the anode and the cathode. They're separated by an electrolyte, a chemical that allows the anode and cathode to transmit a charge. When something's connected to a battery, chemical reactions take place along the electrodes to produce electricity. Of course, you can't see the energy in the battery when the battery is just sitting around; it is when the electricity is produced that the energy is seen.
4) Explosives: when an explosive goes off, chemical energy that was stored in it is changed and transferred into sound energy, kinetic energy, and thermal energy. Just because chemical energy is being released, it doesn't mean an explosion will occur. But, when a solid material quickly changes into a hot, expanding gas, you may be looking at an explosion. Take TNT, for example. Two units of solid TNT can instantly change into 15 units of hot gas, creating a dark and sooty explosion.
5) Food: chemical energy in food is released when the food is digested and the molecules of food are broken down into smaller pieces. Our bodies digest food by mixing it with acids and enzymes in the stomach. This process turns carbohydrates into glucose. The stomach (and small intestine) then release that glucose into the bloodstream, serving as energy for our bodies.
6) Heating packs (used to warm up cold hands or soothe sore muscles) have chemicals inside them. A lot of them function by "cracking" (or bending) them. This is because they're filled with iron. Once you crack the heating pack, the iron is exposed to the air. As the iron reacts to the oxygen, it transforms into iron oxide, a chemical that can produce heat.
7) Wood, when dry, stores chemical energy. This chemical energy is released as the wood burns, and it is converted into heat, or thermal energy. This also produces light energy. As a result of burning, the wood turns into an entirely new substance - ashes.
The distance that a signal can travel along an internet optical cable before falling below an unrecognizable level is being studied. Sixteen tests are performed with the following results (in km ), which have been ordered from smallest to largest: 73.6, 86.3, 86.5, 91.3, 91.5, 93.7,98.3, 100.7, 101.1,106.4,110.9,113.2,114.0,115.3,125.3,139.4 a) Compute the values of the sample mean and the sample median. b) By how much could the smallest sample observation be increased without affecting the value of the sample median? c) By how much could the smallest sample observation be increased without affecting the value of the sample mean? d) If you had to express the "design" length for this internet optical cable, to avoid becoming unrecognizable, what length would you suggest? Discuss briefly.
The value by which the smallest sample observation could be increased without affecting the value of the sample mean is 1749.7 km.
We need to compute the values of the sample mean and the sample median. The given data has 16 values. Therefore,n = 16. Here are the steps to find the mean and median:
Add up all the values. Divide the sum by n.
If n is even, find the mean of the two middle values. If n is odd, the median is the middle value. After we have arranged the given data from smallest to largest, the mean is given by:
Mean = 1/16 [73.6 + 86.3 + 86.5 + 91.3 + 91.5 + 93.7 + 98.3 + 100.7 + 101.1 + 106.4 + 110.9 + 113.2 + 114.0 + 115.3 + 125.3 + 139.4]
Mean = 104.05625
The median can be found as the average of the two middle values, which are 100.7 and 106.4.
Hence,Median = (100.7 + 106.4)/2 = 103.55 .The sample median is the middle value of the data when it is arranged in ascending order. If the smallest sample observation is increased, it will not affect the value of the sample median if the new value is less than or equal to the original median.
The original median was found to be 103.55. The smallest observation is 73.6. Therefore, the value by which the smallest sample observation could be increased without affecting the value of the sample median is:103.55 - 73.6 = 29.95 km
The sample mean is the sum of all the data divided by the number of observations. If the smallest sample observation is increased, it will increase the sum of all the data.
Therefore, it will affect the value of the sample mean. The original sample mean was found to be 104.05625 km. If the smallest sample observation is increased by x km, the new mean is given by:
New mean = 1/16 [x + 86.3 + 86.5 + 91.3 + 91.5 + 93.7 + 98.3 + 100.7 + 101.1 + 106.4 + 110.9 + 113.2 + 114.0 + 115.3 + 125.3 + 139.4]
We need to find the value of x for which the new mean is equal to the original mean. Therefore,
104.05625 = 1/16 [x + 86.3 + 86.5 + 91.3 + 91.5 + 93.7 + 98.3 + 100.7 + 101.1 + 106.4 + 110.9 + 113.2 + 114.0 + 115.3 + 125.3 + 139.4]16 x 104.05625 = x + 1485.8x = 1823.3 km
Therefore, the smallest sample observation could be increased by 1823.3 - 73.6 = 1749.7 km without affecting the value of the sample mean.
The sample means and sample median of the given data was found to be 104.05625 km and 103.55 km, respectively. The value by which the smallest sample observation could be increased without affecting the value of the sample median is 29.95 km.
The length of the internet optical cable to avoid becoming unrecognizable should be less than or equal to the smallest value of the sample data, which is 73.6 km.
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HELP ASAP physics projectile motion, look at the picture
A long straight conductor carries a current of 100 A. At what distance from the axis is the magnetic field caused by the current equal in magnitude to earth's magnetic field which is 0.5 E-4 T
A) 0.4 m
B) 25 m
C) 2.5 m
D) 4.0 m
The correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.
To find the distance from the conductor at which the magnetic field caused by the current is equal to the Earth's magnetic field, we'll use the formula for the magnetic field around a long straight conductor:
\(B = (de * I) / (2 * \pi * r)\)
Where B is the magnetic field, μ₀ is the permeability of free space (\(4\pi * 10^-7 Tm/A\)), I is the current, and r is the distance from the conductor. We want to find the value of r when B equals Earth's magnetic field (0.5 x 10⁻⁴ T).
\(0.5 * 10^-4 T = (4\pi * 10^-7 Tm/A * 100 A) / (2 * \pi * r)\)
To solve for r, we can first simplify the equation by cancelling the π terms:
\(0.5 * 10^-4 T = (4 * 10^-7 Tm/A * 100 A) / (2 * r)\)
Now, cancel out the A (Amperes) terms:
\(0.5 * 10^-4 T = (4 * 10^-7 Tm) / (2 * r)\)
Divide both sides by 4 x 10⁻⁷ T:
\(r = (0.5 * 10^-4 T) / (4 * 10^-7 T)\)
Simplify the equation:
r = \(0.5 * 10^3 m / 4\)
r = 500 / 4
r = 125
So, the correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.
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describe the energy transformations on a pendulum (kinetic and potential)
Answer:
Explanation:
As a pendulum swings, its potential energy converts to kinetic and back to potential. ... During the course of a swing from left to right, potential energy is converted into kinetic energy and back.
Answer:
Once the weighted end of the pendulum is released, it will become active as gravity pulls it downwards. Potential Energy Is Converted To Kinetic Energy. which is the energy exerted by a moving object. An active pendulum has the most kinetic energy at the lowest point of it's swing when the weight is movin.
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