charli has 100 million!!!

Using proportions, it is found that both can be right, as the amounts found from each operation are the same.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Considering you have 73 cards, and your cousin says that you have 7 less than half the cards he has, his amount is found as follows:

0.5x - 7 = 73

0.5x = 80

x = 160.

Then, one-fourth of his amount is:

(1/4) x 160 = 40.

33 more than this is:

33 + 40 = 73.

Both operations have results (73,160), hence the both can be right.

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a) y = 3x + 6Let's find two points for the line and graph it. Let's consider x = 0 first, then:y = 3(0) + 6y = 6So we have a point (0, 6)Now, let's consider y = 0:0 = 3x + 6-6 = 3xx = -2So we have a point (-2, 0).

We plot these points and draw a line.

We get:graph{y=3x+6 [-10, 10, -5, 5]}d) y = -4x + 10

We will follow the same procedure as in part

a). Let's consider x = 0 first, then:y = -4(0) + 10y = 10So we have a point (0, 10)

Now, let's consider y = 0:0 = -4x + 10-10 = -4x2.5 = xSo we have a point (2.5, 0)

We plot these points and draw a line. We get:graph{y=-4x+10 [-10, 10, -5, 15]}2x + 3y + 10 = 0

We can solve this equation for y:y = (-2/3)x - (10/3)

Let's find two points for the line and graph it.

Let's consider x = 0 first, then:y = (-2/3)(0) - (10/3)y = -10/3

So we have a point (0, -10/3)

Now, let's consider y = 0:0 = (-2/3)x - (10/3)10/3 = (-2/3)x-20/3 = 2x30/3 = x

So we have a point (30/3, 0) = (10, 0)We plot these points and draw a line.

So we have a point (8.75, 0)

We plot these points and draw a line.

We get:graph{y=(-4/5)x+(7/5) [-10, 10, -5, 5]}

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Answer:

A. that is the correct answer

Answer:

0.001, 20, 1001, 2100

Step-by-step explanation:

The Pearson correlation coefficient (r) between height (cm) and arm span (cm) describes significant positive correlation patterns in both male and female study subjects.

As per the question statement, we are required to describe the patterns between height and arm span of the general population of males and females on this planet, separately.

We have taken a  sample of 400 healthy volunteers, 272 (68%) being males and 128 (32%) females with age range from 25 to 45 years. Average height and arm span in males (159.68 ± 4.12 cm and 166.30 ± 4.27 cm, respectively) were found to be significantly (p < 0.001) higher than that of females (149.96 ± 3.04 cm and 155.77 ± 3.13 cm respectively), and thus, the Pearson correlation coefficient (r) between height (cm) and arm span (cm) describes significant positive correlation patterns in both male (r = 0.988, P < 0.001) and female (r = 0.991, P < 0.001) study subjects of the sample of 400 healthy volunteers.

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Answer:

sali's speed was 18.75 km/h

Step-by-step explanation:

Jane took 3.5 hours to cycle the 63 km.

As,   , so the speed of Jane will be:  

Suppose, the speed of Sali is   km/h

Sali caught up with Jane when they had both cycled 30 km.

So, the time required for Jane to cycle 30 km  and the time required for Sali to cycle 30 km  

Given that, Sali started to cycle 4 minutes or  after Jane started to cycle. So, the equation will be.......

Answer:

Ann has 24 $1 bills, 2 $10 bills, and 8 $20 bills.

Step-by-step explanation:

Given that Ann has $1, $10, and $20 bills, and she has 4 times as many $20 bills as $10 bills and 3 times as many $1 bills as $20 bills, taking a total of $204, to determine the number of $1, $10, and $20 bills she has, she needs to perform the following calculation:

1 = 3x20 = 3x4x10 = 12x10

20 = 4x10

10 = 10

(12 x 1) + (4 x 20) + 10 = 12 + 80 + 10 = 102

(24 x 1) + (8 x 20) + (2 x 10) = 24 + 160 + 20 = 204

So Ann has 24 $1 bills, 2 $10 bills, and 8 $20 bills.

Answer:

Yes

Step-by-step explanation:

Step 1: Define

12x - 10x⁵ - 7 + 3x⁴

-10x⁵ + 3x⁴ + 12x - 7

Step 2: Rearrange both equations into standard form

-10x⁵ + 3x⁴ + 12x - 7

-10x⁵ + 3x⁴ + 12x - 7

We see both are equivalent.

Answer: A.14x + 6; the answer is a polynomial

Step-by-step explanation:

Since all of the variables have integer exponents that are positive this is a polynomial.

Answer: The answer is D

Step-by-step explanation:

I got this answer by plugging in y=9^x and y=9^0.8 into a graphing calculator and then I saw that the y intercept for the first equation was (0, 1) and the y intercept for the second equation is (0, 5.8). Once you have this information you take both the y values and put them together to get (1, 5.8).

Answer: A and C

Step-by-step explanation:

So the largest rectangle has sides of 5 length and 2+4 width or 6 right. so 5*6=30 Now we have to find which of these expressions solve to get 30. I would just solve them all but the answer is

A and C

There is a 0.25 and a 0.5 chance that the flight will arrive no more than 5 and 10 minutes late, respectively. 130 minutes is the estimated flight time.

Probability density function: It can take on any value and is used to define the random unknown probability falling inside a specific range of values.

For its flights from Cincinnati to Tampa, Delta Airlines reports a flight duration of 2 hours and 5 minutes.

Let's say we think the range of real flight timings is 2 hours to 2 hours and 20 minutes.

a)Between 120 and 140 minutes, the probability density function for a continuous uniform random variable is given as

\(f(x)=\left \{ {{\frac{1}{140-120},120 \leq x\leq 140}\\ \atop {0.o.e}} \right.\)

b)The likelihood that the flight will arrive no later than five minutes late is

integration from 130 to 125 of 1/20dx=5/20=1/4=0.25

c)There is a 10% chance that the flight will arrive no more than 10 minutes late.

integration from 135 to 125 of 1/20dx=10/20=0.5

d)The anticipated duration of the flight, in minutes, is

integration from 140 to 120 of x/20dx=(5200*5)/(2*20)=130

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Jeff Parent's data supports the presence of a hill on Mile 2, as there is a significant difference in the mean time it takes to ride each mile.

To test the claim that it takes the same time to ride each of the miles, we need to use a one-way ANOVA test.

Using the provided data, we calculate the mean time for each mile and find that Mile 2 has a significantly higher mean time than the other two miles. Therefore, it appears that Mile 2 has a hill.

Jeff Parent's data shows that there is a significant difference in the mean time it takes to ride each mile. Using a one-way ANOVA test with a 0.05 significance level, we found that Mile 2 has a significantly higher mean time than the other two miles. This indicates that there is a hill on Mile 2, which is causing the increased time.

Therefore, we reject the claim that it takes the same time to ride each of the miles and conclude that there is a hill on Mile 2.

Jeff Parent's data supports the presence of a hill on Mile 2, as there is a significant difference in the mean time it takes to ride each mile. This information can be useful for Jeff to adjust his training and race strategy accordingly.

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Answer:

9*10^4

Step-by-step explanation:

Answer:

90,000 is written and 9x 10^4 in scientific notation

The initial speed of the object launched at an angle of 11.7 degrees from the horizontal can be calculated by using the range formula, and it is rounded to 1 decimal place.it is approximately 9.9m/s.

To find the initial speed of the object, we can use the range formula for projectile motion, which is given by:
Range = (initial velocity^2 * sin(2 * launch angle)) / gravity
In this case, the range is given as 15.5 meters, and the launch angle is 11.7 degrees. The gravity is a constant, approximately 9.8 m/s^2.
Rearranging the formula to solve for the initial velocity, we have:
initial velocity = sqrt((range * gravity) / sin(2 * launch angle))
Substituting the given values into the formula, we can calculate the initial velocity:
initial velocity = sqrt((15.5 * 9.8) / sin(2 * 11.7))
Evaluating this expression, the initial velocity comes out to be approximately 9.9 m/s when rounded to 1 decimal place.
Therefore, the initial speed of the object launched at an angle of 11.7 degrees from the horizontal is approximately 9.9 m/s.

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The answer is B. It is 3/4

Answer:

7/4

Step-by-step explanation:

Rounding to the nearest whole number, the total emissions over the 5-year period would be approximately 743,289 kilotons of carbon dioxide.

Percentage is a way of expressing a number as a fraction of 100. It is represented by the symbol "%". For example, 50% is equal to 50/100, which simplifies to 0.5. Percentages are often used to express proportions or ratios in a way that is easier to understand. For instance, if there are 20 red balls and 80 blue balls in a bag, we could say that the ratio of red balls to blue balls is 1:4, or we could express this as a percentage by saying that 20% of the balls are red and 80% are blue.

To calculate the total carbon emissions over the 5-year period, we need to calculate the emissions for each year and then add them up.

Starting with the current emission level of 150,000 kilotons, the emissions in each of the next 5 years will be:

Year 1: 150,000 kilotons (no reduction)

Year 2: 150,000 * (1 - 0.005) = 149,325 kilotons

Year 3: 149,325 * (1 - 0.005) = 148,654 kilotons

Year 4: 148,654 * (1 - 0.005) = 147,987 kilotons

Year 5: 147,987 * (1 - 0.005) = 147,323 kilotons

To get the total emissions over the 5-year period, we add up the emissions for each year:

150,000 + 149,325 + 148,654 + 147,987 + 147,323 = 743,289 kilotons

Therefore, rounding to the nearest whole number, the total emissions over the 5-year period would be approximately 743,289 kilotons of carbon dioxide.

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Answer:742537

Step-by-step explanation: I did the  math, and this is the correct answer

The area of the figure is 825 and its unit is units squared

The given figure is a trapezium. Area of trapezium(A) = 1/2(a+b)h

Considering the labelling on the image  attached:

The distance h spans from -15 to 18. Thus h = 18 - (-15) = 18+15 = 33 units

The distance a spans from -15 to 6. Thus a = 6 - (-15) = 6 +15 = 21 units

The distance b span from -15 to 18. Thus b = 24 - (-15) = 18+15 = 39 units

Note: each square of the graph is 3. You can also get the distance by counting number of squares and then multiply by 3.

Now, Area(A) = 1/2(21+39) x 33

                        = 1/2(50) x 33

                        = 25 x 33 = 825 squared units

Therefore, the area of the composite figure is 825 and the unit is units squared

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to find the expected attendance, multiply the attendance by probability then add the products

6000 * 0.1 = 600

25000 * 0.2 = 5000

15000 * 0.2 = 3000

55000 * 0.5 = 27500

27500 + 3000 + 5000 + 600 = 36100

36100 * 15 = 541500 - 300000 = 241500 - 55000 = 186500

You can infer causality from a correlational result, but only when the r value is greater than:

C. 1

Causality refers to a situation in which one event causes another. When there is a correlation between two variables, it means that they tend to move in the same direction.

However, this does not necessarily mean that one event causes the other. In order for a correlation to indicate causality, the correlation coefficient (r) must be greater than 1. If the correlation coefficient is below 1, then there is not enough evidence to suggest that one event causes the other.

In addition, there are other factors that need to be considered when assessing causality from a correlational result.

For example, the strength of the relationship between the variables, the direction of the relationship, and the consistency of the results over time. It is also important to consider the context in which the research was conducted, as this may have an effect on the results.

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The partial sum of the given sequence, 1 + 10 + 19 + ... + 199, can be found by identifying the pattern and using the formula for the sum of an arithmetic series.  Hence, the partial sum of the sequence 1 + 10 + 19 + ... + 199 equals 4497.

To find the partial sum of the given sequence, we can observe the pattern in the terms. Each term is obtained by adding 9 to the previous term. This indicates that the common difference between consecutive terms is 9.

The formula for the sum of an arithmetic series is Sₙ = (n/2)(a + l), where Sₙ is the sum of the first n terms, a is the first term, and l is the last term.

In this case, the first term a is 1, and we need to find the value of l. Since each term is obtained by adding 9 to the previous term, we can determine l by solving the equation 1 + (n-1) * 9 = 199.

By solving this equation, we find that n = 23, and the last term l = 199.

Substituting the values into the formula for the partial sum, we have:

S₂₃ = (23/2)(1 + 199),

= 23 * 200,

= 4600.

However, this sum includes the terms beyond 199. Since we are interested in the partial sum up to 199, we need to subtract the excess terms.

The excess terms can be calculated by finding the sum of the terms beyond 199, which is (23/2)(9) = 103.5.

Therefore, the partial sum of the given sequence is 4600 - 103.5 = 4496.5, or approximately 4497 when rounded.

Hence, the partial sum of the sequence 1 + 10 + 19 + ... + 199 equals 4497.

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Answer:

A .37

Step-by-step explanation:

B +96 +47 =180

B = 180 - 96 -47

B = 37

1) General solution for second order differential equation, y" – 2y' + y = 0, is y = (c₁x + c₂)eˣ .

2) General solution for differential equation, 9y" + 6y' + y = 0, is y =(c₁x + c₂)e⁻³ˣ.

3) General solution for differential equation, 4y"- 4y'- 3y = 0, is y = c₁ e⁶ˣ+ c₂e⁻⁴ˣ.

4) General solution for differential equation, 4y" + 12y' +9y = 0, is y = (c₁x + c₂)e⁻⁶ˣ.

5) General solution for differential equation, y" – 2y' + 10y = 0, is y = eˣ (c₁cos(6x) + c₂sin(6x)).

6) General solution for differential equation, y" – 6y' +9y = 0 is y = (c₁x + c₂)e³ˣ.

7) General solution for differential equation, 4y" + 17y' + 4y = 0, is y = c₁e⁻ˣ + c₂e⁻¹⁶ˣ.

8) General solution for differential equation, 16y" + 24y' +9y = 0, is y = (c₁x + c₂)e⁻¹²ˣ.

9) General solution for differential equation, 25y" – 20y' + 4y = 0, is y = (c₁x + c₂)e¹⁰ˣ.

10) General solution for differential equation, 2y" + 2y' + y = 0, is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)).

General solution is also called complete solution and complete solution = complemantory function + particular Solution

Here right hand side is zero so particular solution is equals to zero. Therefore, evaluating the complementary function will be sufficient to determine the general solution to the differential equation.

1) y"-2y' + y = 0, --(1)

put D = d/dx, so (D² - 2D + 1)y =0

Auxiliary equation for (1) can be written as, m² - 2m + 1 = 0 , a quadratic equation solving it by using quadratic formula,

\(m =\frac{-(- 2) ± \sqrt { 4 - 4}}{2}\)

=> m = 1 , 1

The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)eˣ .

2) 9y" + 6y' + y = 0 or (9D² + 6D + 1)y =0 Auxiliary equation can be written as, 9m² + 6m + 1 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (6) ± \sqrt {36 - 4×4}}{2}\)

=> m = - 6/2

=> m = -3 , -3

The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻³ˣ.

3) 4y"- 4y'- 3y = 0

put D = d/dx, so (4D² - 4D - 3)y = 0

Auxiliary equation can be written as, 4m² - 4m - 3 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{-(-4) ± \sqrt {16 - 4×4×(-3)}}{2}\)

=> m = (4 ± 8)/2

=> m = -4 , 6

The roots of equation are real and equal. So, general solution is y = c₁ e⁶ˣ + c₂e⁻⁴ˣ.

4) 4y" + 12y' +9y = 0 or (4D² + 12D + 9)y= 0

Auxiliary equation can be written as, 4m² + 12m + 9= 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{-(12) ± \sqrt{144 - 4×4×9}}{2}\)

=> m = -12/2

=> m = -6 , -6

The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻⁶ˣ.

5) y" – 2y' + 10y = 0 or (D² - 2D + 10)y = 0 Auxiliary equation can be written as, m² - 2m + 10 = 0 , a quadratic equation

solving it by using quadratic formula,

\(m =\frac{ - (-2) ± \sqrt {4 - 4×1×10}}{2}\)

=> m = (2 ± 6i)/2 ( since, √-1 = i)

=> m = 1 + 6i , 1-6i

The roots of equation are imaginary and unequal. So, general solution is y =eˣ (c₁cos(6x) + c₂sin(6x)).

6) y" – 6y' +9y = 0 or (D²- 6D + 9)y =0

Auxiliary equation can be written as, m² - 6m + 9 = 0 , a quadratic equation

solving it by using quadratic formula,

\(m =\frac{ - (-6) ± \sqrt {36 - 4×1×9}}{2}\)

=> m = 6/2 = 3,3

The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e³ˣ.

7) 4y" + 17y' + 4y = 0 or (4D²+ 17D + 4)y=0

Auxiliary equation can be written as, 4m² + 17m + 4 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{- (-17) ± \sqrt {16 - 4×4×17}}{2}\)

=> m = ( -17 ± 15)/2

=> m = (-17 + 15)/2, (- 17 - 15)/2= -1, -16

The roots of equation are real and unequal. So, general solution is y = c₁e⁻ˣ + c₂e⁻¹⁶ˣ.

8) 16y"+24y'+9y =0 or (16D²+ 24D + 9)y= 0

Auxiliary equation can be written as, 16m² + 24m + 9 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (24) ± \sqrt {576 - 4×9×16}}{2}\)

=> m = (-24 ± 0)/2

=> m = -12,-12

The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻¹²ˣ.

9) 25y"- 20y' +4y =0 or (25D²-20D + 4)y = 0

Auxiliary equation can be written as, 25m²- 20m + 4 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (-20) ± \sqrt {400 - 4×4×25}}{2}\)

=> m = 20/2

=> m = 10 , 10

The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e¹⁰ˣ.

10) 2y" + 2y' + y = 0 or (2D²+ 2D + 1)y =0

Auxiliary equation can be written as, 2m² + 2m + 1 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (2) ± \sqrt {4 - 4×1×2}}{2}\)

=> m = (- 2 ± 4i)/2 ( since, √-1 = i)

=> m = -1 + 2i , -1 - 2i

The roots of equation are imaginary and unequal. So, general solution is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)). Hence, required solution of differential equation is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)).

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7 is an odd number since it can't be divided evenly by 2.

A negative number taken to an odd power will always be negative.

For example, -1⁵ is -1 because 5 is an odd number.

Answer:

x=3 hope this helps (:

Step-by-step explanation:

Answer:

x=3

Step-by-step explanation:

Answer:

5.83

Step-by-step explanation:

9 / 7.50 = 0.833(repeating)

8.33(repeating) * 7 = 5.833(repeating)

Simplify 5.833(repeating)

Answer:

5.83

Step-by-step explanation:

Answer: (0,1)

Step-by-step explanation:

When a line crosses the y-axis, the x-coordinate must equal to 0.

Now we can plug in x = 0 into the equation given:

y - 4*0 = 1

y- 0 = 1

y = 1

Therefore, the point where the line crosses the y-axis is (0,1)