circular saw blade of diameter 0.190 m starts from rest. In a time interval of 5.80 s it accelerates with constant angular acceleration to an angular velocity of 145 rad/s. Part A Find the angular acceleration. Express your answer in radians per second squared. α = nothing rad/s2 Request Answer Part B Find the angle through which the blade has turned. Express your answer in radians. θ = nothing rad Request Answer Provide Feedback

Answers

Answer 1

Answer:

Explanation:

We shall apply newton's law equation valid for rotational motion .

ωt = ω₀ + α t where ωt  is angular velocity after time t , ω₀ is angular velocity at t= 0 and α is angular acceleration

145 = 0 + α x 5.8

α = 25 rad / s²

B )

θ = ω₀ t +  1/2 α t²

= 0 + .5 x 25 x 5.8 x 5.8

= 420.5 rad .


Related Questions

A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of the baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cm and the maximum velocity achieved by the toy is 3.2 m/s . What is the potential energy (U) of the toy when the spring is compressed 4.4 cm from its equilibrium position? *I found the KE, but need help on PE*

Answers

Answer:

0.14 J

Explanation:

The maximum velocity is the amplitude times the angular frequency.

vmax = Aω

ω = vmax / A

ω = (3.2 m/s) / (0.06 m)

ω = 53.3 rad/s

For a spring-mass system:

ω = √(k / m)

ω² = k / m

k = ω²m

k = (53.3 rad/s)² (0.050 kg)

k = 142 N/m

The elastic potential energy is:

EE = ½ kx²

EE = ½ (142 N/m) (0.044 m)²

EE = 0.14 J

at a distance r1 from a point charge, the magnitude of the electric field created by the charge is 397 n/c. at a distance r2 from the charge, the field has a magnitude of 145 n/c. find the ratio r2/r1.

Answers

The distance ratio r2/r1 is approximately 0.605. 

How to calculate the ratio?

The point charge is given by

E = k*q/r^2

where E is the electric field, k is the Coulomb constant (\(k = 8.99 * 10^9 Nm^2/C^2\)), q is the charge of the point charge, and r is the distance between the point charge and the location. The electric field is measured.

Using this equation, we can find the distance ratio r2/r1.

\(E1 = k*q/r1^2\\E2 = k*q/r2^2\)

Dividing these equations gives:

\(E2/E1 = (kq/r2^2) / (kq/r1^2)\\E2/E1 = (r1/r2)^2\)

Solving for r2/r1 gives:

r2/r1 = √(E2/E1)

Inserting the given value will result in:

r2/r1 = √(145n/C ÷ 397n/C)

r2/r1 = √(0.365)

r2/r1 = 0.605

Therefore, the distance ratio r2/r1 is approximately 0.605. 

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If a quantity of heat equal to the magnitude of the change in mechanical energy of the water goes into the water, what is its increase in temperature

Answers

Increase in temperature of water = 0.53 °C
Explanation:
Change in mechanical energy = Potential energy
Potential energy = mgh
Mass, m = Mass of 1 L water = 1 kg
Acceleration due to gravity, g = 9.81 m/s²
Height, h = 225 m
Potential energy = 1 x 9.81 x 225 = 2207.25 J
Because of this 2207.25 J water gets heated.
Heat energy, E = mcΔT
Mass, m = Mass of 1 L water = 1 kg
Specific heat of water, c = 4200 J/kg/C
Energy, E = 2207.25 J
Change in temperature, ΔT = ?
Substituting
2207.25 = 1 x 4200 x ΔT
ΔT = 0.53 °C
Increase in temperature of water = 0.53 °C

In the blanks below write what the independent variable and the dependent variable would be for each experiment. (what are you testing?) (how are you measuring it?) Independent variable Dependent variables

1. Problem: Does the amount you study a subject affect the scores you get on a test? Independent variable ____did you study_ Dependent variable ___higher test scores_
2. Problem: Does misbehaving in school affect a student’s grades? Independent variable _____________________ Dependent variable _______________________
3. Problem: What gives people more gas; eating beans or cabbage? Independent variable _____________________ Dependent variable _______________________
4. Problem: Can you catch more fish with worms or with shrimp? Independent variable _____________________ Dependent variable _______________________
5. Problem: Does talking to plants help increase their growth? Independent variable _____________________ Dependent variable _______________________ 6. Problem: Does eating breakfast help students perform better in school? Independent variable _____________________ Dependent variable _______________________ 7. Do gerbils or hamsters run faster? Independent variable _____________________ Dependent variable _______________________ 8. Problem: Does eating more candy cause cavities? Independent variable _____________________ Dependent variable _______________________
9. Problem: What diet will allow you to lose the most weight, no sugar or no carbs? Independent variable _____________________ Dependent variable _______________________
10. Problem: What, on average, is larger, a chicken egg or a duck egg? Independent variable _____________________ Dependent variable _______________________

Answers

Answer:

1. independent- if you studied. dependent- test scores

2. independent- behavior of students. dependent-student grades

3. independent- what you eat. dependent- amount of gas

4. independent- which bait you use. dependent- how much fish you catch

5. independent-if you talk to the plants or not. dependent- growth

6. independent- whether you eat breakfast or not. dependent-student performance

7. independent- which animal you test. dependent- speed of the animals

8. independent- how much candy you eat. dependent- cavities or not

9. independent- if you eat no sugar or no carbs. dependent- how much weight you lose

10. independent- which thing you measure. dependent- the measurements

The electrostatic force of attraction between two spheres that are one meter apart is 10 newtons (N). If the charge on each sphere is doubled, what is the new electrostatic force between the two spheres?

20 N
30 N
40 N
80 N

Answers

Answer:

its 20 n because of the temeture

Explanation:

because

How are both electromagnetic and mechanical waves used when people communicate with each other?

Answers

Unlike mechanical waves, which require matter, electromagnetic waves can travel through empty space, as well as through liquids, solids, and gases. There are many similarities between light waves and mechanical waves. They can both be measured by their amplitude, wavelength, and frequency.

It’s a sunny Saturday afternoon and you are walking around the lake by your house, enjoying the last few days of summer. The sidewalk surrounding the perimeter of the circular lake is crowded with walkers and runners. You then notice a runner approaching you wearing a T-shirt with writing on it. You read the first two lines, but are unable to read the third line before he passes. You wonder, ”Hmmm, if he continues around the lake, I bet I’ll see him again but I should anticipate the time when we’ll pass again.” You look at your watch and it is 5:07pm. You estimate your walking speed at 3 m/s and the runner’s speed to be about 14 m/s. You also estimate that the diameter of the lake is about 2 miles. At what time should you expect to read the last line of the t-shirt?

Answers

The anticipated time when he will appear again is 5:17 pm

The given parameters;

your speed, \(V_a\) = 3 m/s

the runner's speed, \(V_b\) = 14 m/s

the diameter of the lake, d = 2 miles = 3218.69 meters

Let the anticipated time when he will appear again = t

The circumference of the lake is calculated as;

\(C = \pi d\\\\C = 3.142 \times 3218.69 = 10,113.12 \ m\)

Apply concept of relative velocity to determine the time, in which he will appear again.

By the time he appears again;

the distance you moved + distance he moved = circumference of the circle

\(V_at + V_bt = 10, 113.12\\\\(V_a + V_b)t = 10,113.12\\\\(3 + 14) t = 10,113.12\\\\17t = 10,113.12\\\\t = \frac{10,113.12}{17} \\\\t = 594.89 \ s = 9.92 \ \min \ \approx 10 \ \min\)

\(t\ \approx \ \ 5:17 \ pm\)

Thus, the anticipated time when he will appear again is 5:17 pm

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A car starts at a position of 1 km and moves to a final position of -3 km. What is the total distance traveled by the car?

Answers

The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.

What is displacement?

Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.

There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider

On the number line, we can see the movement as follows

1 0 -1 -2 -3= 4km

Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.

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a car drives 24 meters to the left in three seconds what is the velocity of the car?

Answers

Answer:

8 m/s to the left.

Explanation:

Applying,

V = d/t...................... Equation 1

Where V = Velocity of the car, d = distance, t = time

From the question,

Given: d = 24 meters, t = 3 seconds

Substitute these values into equation 1

V = 24/3

V = 8 m/s to the left.

Hence the velocity of the car is 8 m/s to the left.

When an object is placed within the focal length of a convex lens, the image appears on the same side as the object itself. This situation is shown below. In this situation, which of the following statements is true?

When an object is placed within the focal length of a convex lens, the image appears on the same side

Answers

Answer:

the image formed is virtual, this means that it is the prolongations of the rays that form the image. It is straight and magnified by the quantity

Explanation:

In a lens there is a relationship between the focal length, the distance to the object and to the image given by the constructor equation

          1 / f = 1 / o + 1 / i

where is the focal length, or and i are the distance to the object and the image respectively.

In the case presented, the object is within the focal length, so the image formed is virtual, this means that it is the prolongations of the rays that form the image. It is straight and magnified by the quantity

         m = - i / o

Answer:A

Explanation:Got it right :)

explain why the length of the pendulum is measured from the lower part of the wooden clamp

Answers

The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.

The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.

The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.

As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.

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Which of the following works of art is from the Amarna Period? How to: Items can be selected or deselected by clicking anywhere on the box. Selected items are highlighted in blue. 1 2 3 4

Answers

Work of art from the Amarna Period that is abstract or descriptive in nature.

What modifications did the Amarna Period bring to the arts?

That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.

What is renowned about the Amarna Period?

Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.

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a 27 kg is accelerated at a rate of 1.7m/s/s . what force does the object experience

Answers

The answer should be (C)46n

When a 2.50 - kg object is hung vertically on a certain light spring described by Hooke’s law, the

spring stretches 2.76 cm. (a) What is the force constant of the spring? (b) If the 2.50 - kg object is

removed, how far will the spring stretch if a 1.25 - kg block is hung on it? (c) How much work must

an external agent do to stretch the same spring 8.00 cm from its unstretched position?​

Answers

The work done in the spring is calculated to be 2.8 J

What is Hooke's law?

Hooke's law states that, the extension of a given material is directly proportional to the applied force as long as the elastic limit is not exceeded . First, we must bear in mind that the material must remain within the elastic limit for us to apply the Hooke's law in solving the problem.

Now;

From Hooke's law;

F = Ke

F = force applied

K = force constant

e = extension

F = W = mg =  2.50 - kg * 9.8 m/s^2 = 24.5 N

K = 24.5 N/ 2.76 * 10^-2

K = 888 N/m

e = F/K

F = W =  1.25 - kg * 9.8 m/s^2 = 12.25 N

e = 12.25 N/ 888 N/m = 0.014 m or 1.4 cm

Work done by an external agent = 1/2 Kx^2

= 0.5 * 888 * (8 * 10^-2)^2

= 2.8 J

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You are driving on the interstate and see a sign that says the speed limit is 50 miles per hour.
This is the correct units for measuring speed (distance and time) according to the international system of units
A)
True
B)
False

Answers

Answer:

a

Explanation:

Answer:

True

Explanation:

This is because an interstate is a road that connects 2 states. For example in the US Alabama-Georgia. Now its like a highway so the appropriate Measurement would be miles. (Resulting in the answer being True)

If a person walks 1 km north, 5 km west, 3 km south and 7 km east, find the resultant displacement vecto

Answers

If a person walks 1km north, 5 km West, 3km south, and 7km east, then the resultant displacement vector would be 2.82 km toward the south east direction

What is displacement?

When an object moves in connection to a reference frame, such as when a passenger travels to the back of an airliner or a professor walks to the right in relation to a whiteboard, its position changes. This movement in position is described as displacement.

as stated in the issue If a person goes one kilometre north, five kilometres west, three kilometres south, and seven kilometres east,

The resulting displacement vector, as we know, is the shortest feasible distance between the beginning and ending points

In the horizontal direction, the outcome is

7-5 pointing east

2 kilometres to the eas

In the vertical direction, the outcome is

3–1 km to the south

2 kilometres to the south

\($\begin{aligned} \text { Resultant displacement } &=\sqrt{ }\left(2^{2}+2^{2}\right) \\ &=2 \cdot \sqrt{2} \\ &=2.82 \end{aligned}$\)

As a result, the resulting displacement vector is 2.82 kilometres to the southeast.

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If the radius of the Earth is 6400.0 km and the atmosphere is 10.0 km high, then the volume of air around the Earth is what? ​

Answers

Answer:

5.16 x 10^18 m^3

Explanation:

A heat engine is used to convert heat into which of the following?

Answers

What are the options?

Answer:

work

Explanation:

We observe a cluster and determine that only stars above 15 solar masses have left the main sequence.

i.) Would you expect to see any giants/supergiants in this cluster at
this time? Why or why not?

ii.) Would you expect to see any white dwarfs in this cluster at this
time? Why or why not?

Answers

When we observe a cluster to determine that only 15 solar masses have left the main sequence, we  expect to see any giant/ supergiant but, dwarfs are not visible.

i.) As the cluster's age increases, the mass of the main sequence turnoff stars decreases. According to the H-R diagram, stars with mass 3 times more than the mass of sun are large, hot and bright. They have short life span and are on the upper right region of the graph, hence they have low temperature and high luminosity. They have large diameter, so we can expect to see giants/ supergiant but disappear at the blink of our eye.

ii) For the white dwarfs to be visible, the temperature should be high, luminosity should be low and the mass should be less, almost 8 solar masses. Since, 15 solar masses have left the sequence, white dwarfs will not be visible.

Hence, giants/supergiant can be seen for a short period of time when 15 solar masses leave the main sequence, but white dwarf will not be seen.

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A cyclist is coasting at 13 m/s when she starts down a 460 m long slope that is 30 m high. The cyclist and her bicycle have a combined mass of 70 kg. A steady 15 N drag force due to air resistance acts on her as she coasts all the way to the bottom. What is her speed at the bottom of the slope?

Answers

Answer:

The value is  \(v = 23.6 \ m/s\)

Explanation:

From the question we are told that

   The velocity is \(u = 13 \ m/s\)

    The  length of the slope is \(l = 460 \ m\)

    The height of the slope is \(h = 30 \ m\)

     The mass of the cyclist and her bicycle is \(m = 70 \ kg\)

   The drag force is  \(F = 15 \ N\)

Generally from the law of energy conservation we have that

      \(PE + KE_t = W * KE_b\)

Here \(PE\) is the potential energy at the top of the slope which is mathematically represented as

       \(PE = m* g * h\)

=>     \(PE = 70 * 9.8 * 30\)  

=>     \(PE = 20580 \ J\)

and   \(KE_t\) is the kinetic energy at the top of the slope which is mathematically represented as

        \(KE_t = \frac{1}{2} * m * u^2\)

=>     \(KE_t = \frac{1}{2} * 70 * 13^2\)

=>     \(KE_t = 5915 \ J\)

And  W is the work done by the bicycle which is mathematically represented as

       \(W = F * l\)

=>     \(W = 15 * 460\)

=>     \(W = 6900 \ J\)

and \(KE_b\) is the kinetic energy at the bottom of the slope which is mathematically represented as

       \(KE_b = \frac{1}{2} * m * v^2\)

=>    \(KE_b = \frac{1}{2} * 70 * v^2\)

=>    \(KE_b = 35 v^2\)

So

       \(20580 + 5915 = 6900 + 35 v^2\)

=>    \(v = 23.6 \ m/s\)

 

A boy throws a rock with an initial velocity of 2.15 m/s at 30.0° above the horizontal. If air resistance is negligible, how long does it take for the rock to reach the maximum height of its trajectory?

Answers

Answer:

t = 0.11 second

The time taken to reach the maximum height of the trajectory is 0.11 second

Explanation:

Taking the vertical component of the initial velocity;

Vy = Vsin∅

Initial velocity V = 2.15 m/s

Angle ∅ = 30°

Vy = 2.15sin30 = 2.15 × 0.5

Vy = 1.075 m/s

The height of the rock at time t during the flight is;

From the equation of motion;

h(t) = Vy×t - 0.5gt^2

g= acceleration due to gravity = 9.8m/s^2

Substituting the given values;

h(t) = 1.075t - 0.5(9.8)t^2

h(t) = 1.075t - 4.9t^2

The rock is at maximum height when dh/dt = 0;

dh(t)/dt = 1.075 - 9.8t = 0

1.075 - 9.8t = 0

9.8t = 1.075

t = 1.075/9.8

t = 0.109693877551 s

t = 0.11 second

The time taken to reach the maximum height of the trajectory is 0.11 second

The time it takes for the rock to reach the maximum height is 0.11 seconds.

Projectile motion is the motion experienced by an object thrown into space and it moves along a curved path.

The time (T) for the rock to reach maximum height is given by:

\(T=\frac{usin(\theta)}{g}\)

where u is the velocity = 2.15 m/s, g is the acceleration due to gravity = 9.81 m/s², θ = angle = 30 degree

\(T=\frac{usin(\theta)}{g}=T=\frac{2.15*sin(30)}{9.81}=0.11 \ s\)

Hence the time it takes for the rock to reach the maximum height is 0.11 seconds.

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Write any 3 difference between work energy power​

Answers

Answer:

Work is referred to as the displacement of an object when a force (push or pull) is applied to it while energy is referred to as the capacity to do the work. It exists in various forms like potential, kinetic, chemical, thermal, nuclear, electrical energy and so on. Power is the work done per unit of time.

Types of Energy:Mechanical energy.Mechanical wave energy.Chemical energy.Electric energy.Magnetic energy.Radiant energy.Nuclear energy.Ionization energy.

power and energy are the same.
Work is usualy doing a task that gets rid of said energy.

The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?

Answers

4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.

The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.

To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.

Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.

ΔE = 4×10^26 W

c = 3×10^8 m/s (speed of light)

Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².

Substituting the values, we have:

Δm = (4×10^26 W) / (3×10^8 m/s)²

Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.

This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.

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What is convectional current?​.... .

Answers

Answer:

Convection is the transfer of heat from one place to another along with the motion of the object's particles. Water is a poor conductor. However, when the bottom water is heated, it turns out that the top water is also hot. This means that there is another way of transferring heat to the water, namely convection.

Explanation:

A convectional current is a process that involves the movement of energy from one place to another.

A projectile is fired straight up with an initial velocity of 40.0 m/s . Approximately how high will the projectile ?

Answers

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

100 POINTS AND BRAINLIST FOR BEST ANSWER!

Please help me i have a 77% in science and i need to bring it up today bc its the end of grades today. If you help me you are seriously the best person in the world, theres 4 questions.

100 POINTS AND BRAINLIST FOR BEST ANSWER!Please help me i have a 77% in science and i need to bring it
100 POINTS AND BRAINLIST FOR BEST ANSWER!Please help me i have a 77% in science and i need to bring it
100 POINTS AND BRAINLIST FOR BEST ANSWER!Please help me i have a 77% in science and i need to bring it
100 POINTS AND BRAINLIST FOR BEST ANSWER!Please help me i have a 77% in science and i need to bring it

Answers

Answer:

Air moves from regions of high pressure to regions of low pressure.

Explanation:

When airs moves horizontally from regions of high pressure to low pressure, it creates wind. If the difference between high and low pressure is greater, then it makes the wind faster.

Best of Luck!

Answer:

C. Air moves from regions of high pressure to regions of low pressure.

Explanation:

The air from the regions of high pressure will hold onto that pressure. So, when it moves into the regions with low pressure it'll turn into wind.  

The greater the pressure, the stronger the wind and vise versa.

Hope this helps!

Part A
The goal of your paper is to describe the history of the discovery and research of Proxima Centauri. Another goal is to find the possibilities of traveling to this star. Some questions that your paper should answer are:

When was Proxima Centauri discovered?
How was Proxima Centauri discovered?
How have scientists researched Proxima Centauri?
What technologies have they used? What types of data do these technologies collect?
Have spacecraft ever reached this star?
What are the limitations of sending spacecraft to Proxima Centauri?
What accommodations would humans need to travel to Proxima Centauri?
Now write down two more questions you have about Proxima Centauri that you plan to answer in your paper.

Answers

Answer:

Proxima Centauri was discovered in 1915.

Robert Innes used a blink comparator to examine a photographic plate showing an area of 60 square degrees around Alpha Centauri.

The sixty-four-meter radio telescope at Parkes Observatory in Australia.

they used the James Webb Space Telescope and The sixty-four-meter radio telescope.

no nothing as been to Proxima Centauri it would take about 54,400 years to get there.  

getting to Proxima Centauri, our solar system's nearest star, would take four years and three months. And that is travelling at light speed, a velocity well beyond our reach. The quickest we could currently get to Proxima Centauri, using our fastest rockets, is 80,000 years.

Explanation:

Researchers studying the possible effects of “heading” a soccer ball--hitting it with the head--use a force plate to measure the interaction force between a ball and a hard surface. (Figure 1) shows smoothed data of the force when a 430 g
soccer ball is fired horizontally at the force plate with a speed of 15 m/s
With what speed does the ball rebound from the plate?

Researchers studying the possible effects of heading a soccer ball--hitting it with the head--use a force

Answers

The speed of the ball rebounding from the plate is approximately 13.2 m/s.

According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.

The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.

The speed of the ball rebounding can be calculated using the formula:

(1/2)mv²= (1/2)mv_0²

where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).

Solving for v, we get:

v = sqrt(v_0² - (2F/m))

where F is the maximum force exerted on the force plate (1900 N).

Plugging in the values, we get:

v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s

Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.

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Joe walked 8 meters from his seat to his teacher's desk to turn in an assignment. On
the way back to his seat Joe stops and talks to Sarah. Sarah's desk is in the front row,
exactly 2 meters from the teacher's desk. What is Joe's displacement in meters?

Answers

Answer:  Joe's displacement is 6

Step-by-step explanation:  

8-2=6

The displacement of Joe for the entire journey is 6 m backwards.

The given parameters;

fist position of Joe, x₁ = 8 mfinal position of Joe, x₂ = 2 m

Displacement is the change in the position of an object. It can also be described as the shortest distance between the final position and the initial position.

Displacement = Δx = x₂ - x₁

Let the forward direction be negativeLet the backward direction be positive

Displacement = -2 - (-8)

Displacement = -2 + 8

Displacement = 6 m backwards

Thus, the displacement of Joe for the entire journey is 6 m backwards.

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Two ice skaters stand face to face and push off and travel directly away from each other. The boy has a velocity of 5 m/s and he weighs 750N. The girl weighs 480 N. What is the girls velocity?

Answers

Given:

Weight 1 = 750N

Weight 2 = 480 N

V1 = velocity 1 = 5 m/s

First, calculate the masses of each one:

w = mg

g= 9.8 m/s

W1 = m1 g

750 = m1 (9.8)

m1= 750 /9.8 = 76.5 kg

m2 = 480/9.8 = 49 kg

Both momentums (p) add up to zero

p = mv

p1 + p2 = 0

m1v1 + m2v2 = 0

(76.5) (5 ) + (49)(v2) = 0

382.5 +49v2 = 0

382.5 = -49v2

382.5/-49 = v2

v2 = -7.8 m/s ( negative since velocity is in the opposite direction of the boy)

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