Clare is paid 90$ for 5 hours of work. At this rate, how many seconds dose it take for her to earn 25 cents?

Reducing the variation of a process will increase the width of a given confidence interval relative to that process.

Option C is correct .

In statistics, the probability that a population parameter will fall between a set of values for a predetermined percentage of the time is referred to as a confidence interval. By employing the dimensions of values used in the computation of the intervals, it is simple to establish the link between components of two confidence intervals. The width is a fundamental component in these range estimates, which are affected by sample size, etc.

Hence, reducing the variation of a process will increase the width of a given confidence interval relative to that process is false.

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i. To show that the function f(x) = (x+2)/x is onto, we need to prove that for every y in the co-domain of f, there exists an x in the domain such that f(x) = y.

i. To prove that f is onto, we need to show that for every y in the co-domain of f, there exists an x in the domain such that f(x) = y.

Let y be any element in the co-domain, which is \(\mathbb{R} \backslash \{1\}\). We want to find an x such that f(x) = y.

Starting with the expression for f(x), we have:

\(f(x) = \frac{x+2}{x}\)

To solve for x, we can cross-multiply:

\(x+2 = xy\)

Rearranging the equation:

\(xy - x = 2\)

Factoring out x:

\(x(y-1) = 2\)

Dividing both sides by (y-1):

\(x = \frac{2}{y-1}\)

Now, we have found an expression for x in terms of y. This shows that for every y in the co-domain, there exists an x in the domain such that f(x) = y. Therefore, f is onto.

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Answer:

1/2x

Step-by-step explanation:

y = 2x

To find the inverse, exchange x and y

x = 2y

Solve for y

Divide each side by 2

x/2 = 2y/2

1/2x = y

The inverse is 1/2x

Answer:

\(\displaystyle Inconsistency\:[No\:Solution]\)

Step-by-step explanation:

We need to isolate one pair of variables so they are set to zero. Now, in this case, we need to split one of the equations in negative half, so we will select the second equation:

\(\displaystyle \left \{ {{3x - 2y = 8} \atop {6x - 4y = 12}} \right. \\ \\ \\ \left \{ {{3x - 2y = 8} \atop {-\frac{1}{2}[6x - 4y = 12]}} \right. \\ \\ \left \{ {{3x - 2y = 8} \atop {-3x + 2y = -6}} \right. \\ \\ \\ \boxed{0 \ne 2}\)

The fact that we have a result like this proves that we cannot obtain a solution from this system, which means that on a graph, these equations are considered parallel [no intersection, so no solution].

I am joyous to assist you at any time.

Answer:

x^15

Step-by-step explanation:

Recall these rules of exponents:

(a^m)^n = a^mn

a^m • a^n = a^(m + n)

(x^6)² • x³ = x^(2 • 6) • x³ = x^12 • x³ = x^(12 + 3) = x^15

Given:

Entrance fee per student: $5(29)

Lunch costs: $4(29 + 6)

Bus fees: $25 + 8($2 + $3)

Total cost: 5(29) + 4(35) + 25 + 8(5)

To find:

The equivalent expressions of the total cost that use the properties of operations to simplify the math.

Solution:

We have,

Total cost = 5(29) + 4(35) + 25 + 8(5)

To simply this expression, we need to write 29 and 35 in the expand form or as the sum of their place values because it is easy to multiply a number with multiply of 10 and single digit.

Total cost = 5(20+9) + 4(30+5) + 25 + 40

Therefore, the correct option is B.

Answer:

Entrance fee per student: $5(29) Lunch costs: $4(29 + 6) Bus fees: $25 + 8($2 + $3) Total cost: 5(29) + 4(35) + 25 + 8(5) To find: The equivalent expressions of the total cost that use the properties of operations to simplify the math. Solution: We have, Total cost = 5(29) + 4(35) + 25 + 8(5) To simply this expression, we need to write 29 and 35 in the expand form or as the sum of their place values because it is easy to multiply a number with multiply of 10 and single digit. Total cost = 5(20+9) + 4(30+5) + 25 + 40 Therefore, the correct option is B.

Step-by-step explanation:

copy me above :)))

Answer: +3

Step-by-step explanation: divide by -3 which you get is +3

and you can check by doing +3 times -3=  -9

FALSE, Bank runs are usually associated with financial crises or economic instability, which can undermine the public's confidence in banks.

each statement about bank runs as true or false.

"Institutions like the Federal Deposit Insurance Corporation (FDIC) decrease the frequency of bank runs." - This statement is TRUE. The FDIC insures deposits, which helps to maintain confidence among customers and prevent bank runs.

"A bank run is when too many of a bank's customers withdraw too much at the same time." - This statement is TRUE. A bank run occurs when a large number of customers withdraw their deposits simultaneously due to concerns about the bank's solvency.

"A bank run is when many of a bank's customers make large deposits at once." - This statement is FALSE. A bank run is related to withdrawals, not deposits.

"A bank run only occurs when the economy is doing well." - This statement is FALSE. Bank runs are usually associated with financial crises or economic instability, which can undermine the public's confidence in banks.

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Among the provided statements, only the statement "Abnormalities in the reflexes can indicate brain damage" is true of newborn reflexes:

Newborn reflexes are automatic, involuntary movements or actions that are exhibited by infants in response to certain stimuli. These reflexes are typically present from birth and serve as important indicators of neurological development and overall health.

Abnormalities or deviations from the expected patterns of newborn reflexes can suggest underlying neurological issues or brain damage.

For example, the absence, asymmetry, or persistence of certain reflexes beyond the expected timeframe can be signs of potential neurological problems that require further evaluation and medical attention.

However, the other statements provided in the options are not accurate:

- Reflexes do not appear until the third week of life: This statement is false. Newborn reflexes are present from birth or shortly after birth, and they can be observed in the early days of a baby's life.

- Newborns have control over their reflexes: This statement is false. Newborn reflexes are instinctual and involuntary responses that occur without conscious control from the infant. As the baby grows and develops, they gain more control over their movements and their reflexes become integrated into voluntary actions.

- These reflexes become involuntary over time: This statement is false. Newborn reflexes are already involuntary from the start. They are not intentionally controlled by the baby and are automatic responses triggered by specific stimuli.

It's important to note that the presence or absence of specific newborn reflexes and their developmental patterns can vary among individuals, but deviations from the norm may indicate potential health concerns and should be addressed by medical professionals.

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The given statement "The this pointer is not automatically passed to static member functions of a class." is false as static member functions can be called without creating an object of the class, and the "this" pointer is used to refer to the current instance of the class. Since no instance is required for static member functions, the "this" pointer is not applicable in this case.

In object-oriented programming, a class is a blueprint for creating objects, and member functions are functions defined within a class that can be called on objects of that class.

Static member functions, also known as class methods, are special member functions that are associated with the class itself rather than any specific object or instance of the class. They are declared using the "static" keyword.

Since static member functions do not operate on specific instances of the class, they do not have access to the "this" pointer. The "this" pointer is a hidden pointer that points to the current object instance, allowing non-static member functions to access the data members and other member functions of the object. However, static member functions do not have this pointer because they are not tied to any specific object.

Static member functions can only access static members of the class, which include static variables and other static member functions. They can be called using the class name itself, without creating an instance of the class. This is because they are not associated with any particular object but rather with the class as a whole.

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The initial value problem calculator is a tool used to calculate differential equations.

An instrument for solving ordinary differential equations with initial conditions is an initial value problem calculator. Finding a function that solves a given differential equation and a set of initial conditions is the goal of this calculator, a particular kind of differential equation problem. The differential equation, the beginning conditions, and other pertinent parameters are entered into the calculator, which then generates a solution that fulfils the initial conditions.

Usually, the answer is provided as a function that specifies how the system behaves over time. In disciplines like physics, engineering, and economics, where differential equations are regularly employed to represent dynamic systems, these calculators are widely used. They can be helpful for obtaining an understanding of a system's behavior and for predicting its upcoming trends

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When the spring is stretched and the distance from point a to point b is 5.3 feet, the value of θ is 53.13  degrees

The distance between point a to point b = 5.3 feet

The length of the top side = 3 feet

Therefore, it will form a right triangle

Here we have to use trigonometric function

Here adjacent side and the hypotenuse of the triangle is given

The trigonometric function that suitable for the given conditions is

cos θ = Adjacent side / Hypotenuse

Substitute the values in the equation

cos θ = 3 / 5

θ = cos^-1(3 / 5)

θ = cos^-1(0.6)

θ = 53.13 degrees

Therefore, the value of θ is 53.13  degrees

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Answer:

perimeter = 7x² + 7y² + 4y - 3x

Step-by-step explanation:

the perimeter (P) is the sum of the 3 sides of the triangle , that is

P = 3x² - y² + 4x² - 7xy + 4y - 3x + 7xy + 8y² ← collect like terms

  = (3x² + 4x²) + (- y² + 8y²) + (- 7xy + 7xy) + 4y - 3x

 = 7x² + 7y² +0 + 4y - 3x

 = 7x² + 7y² + 4y - 3x

The expected number of left-handed students in a typical class of 188 students can be estimated using the prevalence rate of left-handedness in the general population.

According to studies, approximately 10% of the population is left-handed. Therefore, we can expect around 18.8 left-handed students in a class of 188 students.

To calculate the standard deviation, we need additional information. The standard deviation depends on the variability of left-handedness in the population. Without this data, it is not possible to provide an accurate estimation of the standard deviation.

Similarly, the expected number of right-handed students can be estimated by subtracting the expected number of left-handed students (18.8) from the total number of students (188). This gives us an expected number of around 169.2 right-handed students.

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I will have $2500 at the end of 5 years

Interest Rate is the amount of interest due per period, as a proportion of the amount lent, deposited, or borrowed. It is the percentage of principal charged by the lender for the use of its money.It is also percentage a lender charges on the amount of money borrowed.

Where, The principal is the amount of money loaned.

The formula = Principal * Rate * Time/100

Where Principal = $10000

Rate = 5%

Time = 5 years

Simple Interest = 10000 * 5 * 5/100

Simple Interest = 250000/100

Simple Interest = $2500

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Answer:

Step-by-step explanation:

1 1/6 + (x/3 · 1/4) = 1 3/4

solve for x

1 1/6 + x/12 = 1 3/4

1 1/6 - 1 3/4 = -x/12

-7/12 = -x/12

-7 = -x

x = 7

----------------

check

1 1/6 + (7/12 * 1/4) = 1 3/4

1 1/6 + 7/48 = 1 3/4

1 15/16 = 1 3/4

1 3/4 = 1 3/4

the answer is good

Answer:

Step-by-step explanation:

V = L*w*h

L = 3

w = 2

h = ?

V = 24

24 = 2*3 * h       Combine the right

24 = 6* h            Divide both sides by 6

24/6 = 6h/6

4 = h

To decide whether it is sensible for Stacy to utilize the ordinary show for the inspecting conveyance of the test extent, we got to check whether the conditions for utilizing the typical conveyance estimation are met. The conditions are:

The test estimate is expansive sufficient

The test information is autonomous

The populace is at slightest 10 times bigger than the test

The test estimate, in this case, is 50. To check whether it is expansive sufficient, ready to utilize the run the show of thumb that the test measure ought to be at the slightest 10% of the populace estimate.

Hence, based on these conditions, it is sensible for Stacy to utilize the ordinary demonstration for the inspecting conveyance of the test extent. She can accept that the testing dispersion is roughly typical with a cruel of p = 0.11 and a standard deviation of sqrt[(p(1-p))/n] = sqrt[(0.11(0.89))/50] = 0.05.

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We have to solve "700 - 462" with the arrow method.

First, we look at 462 and identify the hundreds, tens and units:

We have 4 hundreds, 6 tens and 2 units.

Then, we can solve this substraction:

1) We substract a hundred 4 times.

2) Then, to the result of the previous step, we substract a ten 6 times.

3) To the result of the previous step we substract 2 units.

Answer: The result of 700 - 462 is 238.

The rotation rule used in this problem is given as follows:

90º counterclockwise rotation.

The five more known rotation rules are given as follows:

The equivalent vertices for this problem are given as follows:

Hence the rule is given as follows:

(x,y) -> (-y,x).

Which is a 90º counterclockwise rotation.

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Answer:

1

Step-by-step explanation:

Therefore, the steady-state responseusing Laplace theorem ia `Yss(t)` of the system is

\((1/4)sin(4t) + (5/8)sin(8t) + (0.015)sin(12t) + (0.01)sin(16t).Answer: `Yss(t) = (1/4)sin(4t) + (5/8)sin(8t) + (0.015)sin(12t) + (0.01)sin(16t)`\)

Given the transfer function of the system and the input frequency as follows:\(0.5y+5y = f(t)where f(t) = sin(4t) + 4sin(8t) + 0.04sin(12t) + 0.06sin(16t)\)

We have to find the steady-state response \(`Yss(t)`\) of the system.

Let's start the solution: Take Laplace transform on both sides of the given equation.\(`(0.5y + 5y)(L) = f(t)(L)`\)

By using linearity of Laplace transform:`\(L(0.5y) + L(5y) = L(f(t))``0.5L(y) + 5L(y) = L(sin(4t)) + 4L(sin(8t)) + 0.04L(sin(12t)) + 0.06L(sin(16t))`\)We know that the Laplace transform of sin(at) is given by:\(`L(sin(at)) = (a) / (s² + a²)`\)

Putting values of Laplace transform of input f(t) into the above equation.\(`0.5L(y) + 5L(y) = (4) / (s² + 16) + 4(8) / (s² + 64) + 0.04(12) / (s² + 144) + 0.06(16) / (s² + 256)`\)

Let's solve for \(L(y).`0.5L(y) + 5L(y) = 0.25 / (s² + 4²) + 1.25 / (s² + 8²) + 0.03 / (s² + 12²) + 0.04 / (s² + 16²)`\)

Factorizing the denominator, we get:  \(`L(y) = [0.25 / (s² + 4²) + 1.25 / (s² + 8²) + 0.03 / (s² + 12²) + 0.04 / (s² + 16²)] / (0.5 + 5)`\)

Evaluating the above expression we get:  \(`L(y) = [0.25 / (s² + 4²) + 1.25 / (s² + 8²) + 0.03 / (s² + 12²) + 0.04 / (s² + 16²)] / 5.5`\)

We know that the inverse Laplace transform of \(`1 / (s² + a²)` is given by: `L⁻¹[1 / (s² + a²)] = (1 / a) sin(at)`\)

Using the above formula and taking inverse Laplace transform on L(y), we get\(:`y(t) = L⁻¹[L(y)]``y(t) = (1/4)sin(4t) + (5/8)sin(8t) + (0.015)sin(12t) + (0.01)sin(16t)`.=\)

Hence, the steady-state response of the given system is:\(`Yss(t) = (1/4)sin(4t) + (5/8)sin(8t) + (0.015)sin(12t) + (0.01)sin(16t)`\)

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The number of spanning trees of a connected graph can be proven to be the product of the number of spanning trees of each of its blocks.

Here are the steps-

1. Consider a connected graph G with blocks B1, B2, ..., Bk. Each block is a maximal connected subgraph with no cut-vertex.

2. The number of spanning trees of G can be denoted as T(G), and the number of spanning trees of each block Bi can be denoted as T(Bi).

3. To prove the given statement, we need to show that\(T(G) = T(B1) * T(B2) * ... * T(Bk).\)

4. We can start by considering a single block B1. Since B1 is a maximal connected subgraph with no cut-vertex, it is a connected graph on its own.

5. The number of spanning trees of B1, T(B1), can be calculated using any method such as Kirchhoff's theorem or counting the number of spanning trees directly.

6. Now, consider the original graph G. We can remove block B1 from G, which leaves us with a graph G' that consists of the remaining blocks B2, B3, ..., Bk.

7. G' is still a connected graph, but it may have cut-vertices. However, the removal of B1 does not affect the connectivity between the other blocks, as each block is a maximal connected subgraph.

8. The number of spanning trees of G', denoted as T(G'), can be calculated using the same method as step 5.

9. Since G' is the remaining part of G after removing B1, the number of spanning trees of G can be expressed as T(G) = T(B1) * T(G').

10. We can repeat this process for the remaining blocks B2, B3, ..., Bk. For each block Bi, we remove it from G and calculate the number of spanning trees of the remaining graph.

11. By repeating steps 6-10 for all blocks, we can express the number of spanning trees of G as-

\(T(G) = T(B1) * T(G')\)

\(= T(B1) * T(B2) * T(G'')\)

= ...

\(= T(B1) * T(B2) * ... * T(Bk).\)

12. Therefore, we have proved that the number of spanning trees of a connected graph G is the product of the number of spanning trees of each of its blocks.

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Step-by-step explanation:

\( \sqrt{9} + \sqrt{25} - 8 \div 2 + {3}^{2} \\ = 3 + 5 - 4 + 9 = 13\)

Answer: 112.5

Step-by-step explanation: When line AB and CD intersect at point E, angle AEC equals BED so you set them equal to each other and find what x is. 5x -20 = x + 50, solving for x, which gives you 17.5. Finding x will tell you what AEC and BED by plugging it in which is 67.5. Angle BED and BEC are supplementary angles which adds up to 180 degrees. So to find angle CEB, subtract 67.5 from 180 and you get 112.5 degrees.

Answer:

83

Step-by-step explanation:

Answer:

83

u subtract 1937 from 2020 and u get dis

Answer:

slope of p= -7/12

slope of q= -3/6.8

slope of r= -16/6.4

slope of m= 6.2/15.5

slope of n= 6.8/17

Step-by-step explanation:

The slopes of the line are given as 2.5 for p and q and -2.5 for r, m and n respectively.

The slope of a straight line is the tangent of the angle formed by it with the positive x axis as the reference.

The negative slope indicates the rate of decrease while the positive shows the rate of increase.

The slope of the given lines can be obtained as follows,

(a) In order to find slope of line p,

Use the formula m = (x₂ - x₁)/(y₂ - y₁) and substitute the corresponding values to get,

m = (-3 - 8)/(0.4 - (-4))

⇒ m = -2.5

(b)  In order to find slope of line q,

Use the formula m = (x₂ - x₁)/(y₂ - y₁) and substitute the corresponding values to get,

m = (13 - 0)/(6.8 - 12)

⇒ m = -2.5

(c)  In order to find slope of line r,

Use the formula m = (x₂ - x₁)/(y₂ - y₁) and substitute the corresponding values to get,

m = (13 - (-3))/(6.8 - 0.4)

⇒ m = 2.5

(d) In order to find slope of line m,

Use the formula m = (x₂ - x₁)/(y₂ - y₁) and substitute the corresponding values to get,

m = (-15.5 - 0)/(0 - 6.2)

⇒ m = 2.5

(e)  In order to find slope of line n,

Use the formula m = (x₂ - x₁)/(y₂ - y₁) and substitute the corresponding values to get,

m = (-5 - 12)/(- 6.8 - 0)

⇒ m = 2.5

Hence, the slopes of first two lines are 2.5 and of the remaining three are 2.5.

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Answer:

5,234

Step-by-step explanation:

Answer:

\( 3^{ -x+3}\)

Step-by-step explanation:

We need to simplify out the given exponential expression . The given expression to us is ,

\(\rm\implies \dfrac{\dfrac{1}{3}}{3^{x-4}} \)

We can use the Law of Exponents to simplify the given expression . Recall that ,

\(\rm\implies \red{\dfrac{a^m}{a^n}= a^{m-n}}\)

Note that , we can write ,

\(\rm\implies \dfrac{1}{3}= 3^{-1}\)

Therefore our expression becomes ,

\(\rm\implies \dfrac{ 3^{-1}}{3^{x-4}}\)

Simpify using the Law of Exponents ,

\(\rm\implies 3^{ -1 - ( x - 4 )}\)

Open the brackets in exponent ,

\(\rm\implies 3^{ -1 - x +4 }\)

Simplify to get final expression ,

\(\rm\implies \boxed{\quad \blue{ 3^{-x+3} \quad}}\)