Clark Grizwald put a neon green blinking tree that weights 2.3 kg on top of his house 50 meters off the ground but he didn't tie it down right. How much velocity does the blinking tree have when it is 2 meters from the ground? Solve

Answer:

a) 1.06*10^-5

b) 0.00105 °C^-1

Explanation:

Given that

Length of the cylinder, L = 1.5 m

Radius of the cylinder, r = 0.25 cm

Voltage across the rod, V = 15 V

I• at Temperature T• = 20° C is 18.5 A

I at Temperature T = 90° C is 17.2 A

See attachment for calculations

Answer:

D

Explanation:

The diagram represents an oxygen ion with a -2 charge.

The Lewis dot structure of a chemical specie represents the electrons present on the outermost or valence shells of atoms in the specie as dots. Lewis structures are used for ions, free atoms and molecules.

Oxygen is a member of group 16 hence it has six electrons in its valence shell. The specie shown in the image has eight valence electrons implying that the oxygen atom gained two valence electrons when the specie was formed.

When oxygen gains two electrons it is said to have acquired a charge of -2. Hence, the diagram represents an oxygen ion with a -2 charge.

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5.48 V is the potential drop across the cable for a copper transmission cable of 50.0 km long and 10.0 cm in diameter carries a current of 105 A

Ohm's Law states that the potential drop is determined by the equation: V = IR, where I is the current and R is the wire resistance.
R=PL/A
Under the assumption that all physical parameters and temperatures remain constant, Ohm's law asserts that the voltage across a conductor is directly proportional to the current flowing through it.

Only when the given temperature and the other physical variables remain constant does Ohm's law apply. Increasing the current causes the temperature to rise in some components. The filament of a light bulb serves as an illustration of this, where the temperature increases as the current increases. Ohm's law cannot be applied in this situation. The filament of the lightbulb defies Ohm's Law.

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Answer:

It is a colorless crystalline compound which is the main nitrogenous breakdown product of protein metabolism in mammals and is excreted in urine.

Answer:

Urea is a compound of nitrogen that is the chief solid substance dissolved in the urine of a mammal and is formed by the breaking down of protein.

(Hope this helps! Btw, I answered first. Brainliest please! :D)

The peak emf in one coil at the given current in the other coil is 1,000 A.

Mutual Inductance between the two coils is defined as the property of the coil due to which it opposes the change of current in the other coil.

The peak emf in one coil when the current in the other coil is i ( t ) = 10 sin ( 1000 t ) depends on the mutual inductance and the peak current.

The peak emf in one coil is calculated as follows;

emf₀ = M di/dt

where;

di/dt = (10 x 1000) cos (1000 t)

di/dt = 10,000 cos(1000 t)

The peak rate of change of current from the derivative of di/dt = 10,000 A/s

emf₀ = (100 x 10⁻³) x (10,000 A/s)

emf₀ = 1,000 V

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Answer:

v = 9.75×10^6 m/s

Explanation:

Using time dilation formula-

T' = T / √[1-(v/c)^2]

Here,

T = 60 min

T' = 61 min

Putting this in eqn.

61 = 60 / √[1-(v/c)^2]

(v/c)^2 = 1 - (60/61)^2

v/c = 0.0325

v = 9.75×10^6 m/s

Therefore, clock should run at speed of 9.75×10^6 m/s.

Answer:

I think it would most likely be 2... but not so sureee

Answer:

parabolic path

Explanation:

As the cart reaches the end of the table with a horizontally directed velocity (only horizontal component), the cart will follow a parabolic path given by the combined action of:

(1) kinematic equation for motion under constant velocity in the horizontal direction (linear expression in terms of time), and

(2) kinematic equation for motion under constant acceleration (that of gravity) in the vertical direction (quadratic expression in terms of time)

Answer:

C.

Explanation:

Due to gravity and air resistance— its gonna make a curved path

The primary locations for the birth of new stars are in galaxies' spiral arms. The proportion of the galaxy that can participate in star formation increases as more gas and dust become available.

We refer to some spiral galaxies as "barred spirals" because the centre bulge seems extended, like a bar. The spiral arms of the galaxy seem to emerge from the ends of the bar in barred spirals. Elliptical galaxies are round or oval in shape, as their name implies, and have a rather uniform distribution of stars.

The Norma and Cygnus arm, Sagittarius, Scutum-Crux, and Perseus arms are the four principal spiral arms of the Milky Way.

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The speed of the wind is 20 miles per hour.

To solve this problem, we can use the formula:

Speed = Distance/Time

Let's assume that the speed of the wind is x miles per hour.

With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:

460 = Airspeed + x

Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:

420 = Airspeed - x

We can solve this system of equations to find the airspeed of the plane:

460 = Airspeed + x

420 = Airspeed - x

Adding the two equations gives:

880 = 2Airspeed

Dividing both sides by 2 gives:

Airspeed = 440 miles per hour

Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:

460 = Airspeed + x

460 = 440 + x

x = 20

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The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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Answer:

has a thick atmosphere which traps heat:))

The above-listed characteristics apply to moving water as an energy source. Thus, moving water can be used as an energy source.

The following are the characteristics of moving water as an energy source:

Water is an excellent resource for producing electricity since it is clean, renewable, and is available in many different forms. When water moves, it has the potential to generate energy, which can be harnessed in several ways to produce electricity. As a result, moving water is an excellent source of renewable energy, as it is available in many different forms and can be used in a variety of ways.The above-listed characteristics apply to moving water as an energy source. Thus, moving water can be used as an energy source.

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Answer: (15 - 0)/1.8 = 8. 33m/s^2

Explanation:

The acceleration of the racehorse is 8.33 m/s²

The given parameters;

initial velocity of the racehorse, u = 0

final velocity of the racehorse, v = 15  m/s

time of motion of the horse, t = 1.8 s

The acceleration of the racehorse is calculated from change in velocity per change in time of motion as shown below;

\(a = \frac{\Delta v}{\Delta t} = \frac{v-u}{t} \\\\a = \frac{15 - 0}{1.8} \\\\a = 8.33 \ m/s^2\)

Thus, the acceleration of the racehorse is 8.33 m/s²

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Answer:

What's the source of energy that powers the human brain?

Mainly sugar, glucose. Glucose is broken down, and in the process it is used to create a gradient of hydrogen ions (Oxygen is also needed, which is why we breath).

brainiest please

The power at which the crane operates, if it can lift a mass of 500 kg is 1225 Watts.

Power is the rate at which work is done.

To calculate the power the crane operates with, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the right option is B. 1225 Watts.

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Answer:

See answers below

Explanation:

a.

(vf)² = (vi)² + 2gy

0 = (27sin30°)² + 2(-9.8)y

y = 36.3 m

b.

vf = vi + gt

0 = (27sin30°) + (-9.8)t

t = 2.72 s

2.72 x 2 = 5.44 s

c.

x = (vi)t + (1/2)at²

x = (27cos30°)(5.44) + 0

x = 22.66 m

According to the question,

then,

(a)

The maximum height will be:

→ \(V_f^2 = V_i^2+2ad\)

    \(0 = (13.5)^2+2(-9.8).d\)

    \(0 = 182+(-19.6)d\)

    \(d = 9.3 \ m\)

(b)

The total time taken will be:

→ \(V_f = -V_i\)

or,

→     \(a = \frac{V_f-V_i}{t}\)

 \(-9.8 = \frac{-13.5-13.5}{t}\)

\(-9.8 \ t = - 27\)

       \(t = \frac{-27}{-9.8}\)

          \(= 2.75 \ sec\)

(c)

The total distance covered will be:

→ \(V_x = \frac{d_x}{t}\)

  \(23=\frac{d_x}{2.75}\)

  \(d_x = 2.75\times 23\)

       \(= 63 \ m\)

Thus the approach above is appropriate.

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Im pretty sure its A cuz is closer to the earth.

Pearson's correlation coefficient (r):

The Pearson's correlation coefficient is a measure of how strong/weak is the association between two variables.

It also tells us the direction of the relationship (positive/negative)

The degrees of freedom for a Pearson's correlation coefficient can be found as

Where n is the sample size.

For the given case, the sample size is 250.

So, the degree of freedom is

Therefore, the degrees of freedom for the Pearson's correlation coefficient is 248

Answer:

B

Explanation:

Shadows are not colored, instead they are dark gray. Although shadows mimic the shape of an object, they do not mimic the color.

The momentum of the blobs after the collision of a 1 kg blob of putty moving at 10 m/s with another 1 kg stationary blob will be 5 m/s.

The term "completely inelastic collision" is used to describe every time two masses cling together after colliding. Any inelastic collision will result in the internal energy of the objects being transformed into kinetic energy. Because of this, even though the system's energy is conserved (no outside forces are at action), its internal energy is changing in an unknowable and unpredictable fashion. This implies that the concept of energy conservation in inelastic collisions is absolutely meaningless to us. However, the conserved quantity that we can monitor is momentum.

Initial momentum is expressed as p = m1v1 + m2v2,

where, I denotes vector quantities.

v2 = 0  (because the second blob is at rest).

As a result, p=m1v1, |p|=m1|v1|=1*10= 10 kg*m/s,

The total amount of momentum is conserved in a closed system. The end momentum is 10 kg*m/s and is therefore also directed in the same direction as the beginning momentum.

The combined mass is now M=m1+m2= 1+1 = 2 kg due to the fact that two blobs are now clumped together. As a result, p = mv= 10 =2v; from this, v= 10/2 = 5 m/s, headed in the same direction as the first blob's starting velocity.

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Answer:

Explanation:

PE = mgh = 2xg

Half way down, half of the potential energy will have been converted.

KE = xg

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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Answer:

deductive reasoning usually follows steps .

Answer:

the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J

Explanation:

Given that the data in the question;

angle of inclination with respect to the ground \(\theta\) = 30°

length of plane d = 2m

m₁ = 1 kg

m₂ = 0.5 kg

now, velocity of the first block at midpoint;

\(\frac{1}{2}\)mv² = mgsin\(\theta\)\(\frac{d}{2}\)

\(\frac{1}{2}\)v² = gsin\(\theta\)\(\frac{d}{2}\)

v² = gsin\(\theta\)d

v = √( gsin\(\theta\)d)

g is 9.8 m/s

so we substitute

v = √( 9.8 × sin30° × 2)

v = √( 19.6 )

v =  3.13 m/s

Now, velocity just after collision of the blocks will be;

(m₁ + m₂)v₂ = m₁v

v₂ = m₁v / (m₁ + m₂)

we substitute

v₂ = (1 × 3.13) / (1 + 0.5)

v₂ = 3.13 / 1.5

v₂ = 2.0866 m/s

now, final kinetic energy will be;

\(KE_f\) = (m₁ + m₂)gsin\(\theta\)\(\frac{d}{2}\) + Initial Kinetic energy

\(KE_f\) = (m₁ + m₂)gsin\(\theta\)\(\frac{d}{2}\) + \(\frac{1}{2}\)mv₂²

we substitute

\(KE_f\) = [(1 + 0.5)9.8 × sin30 × \(\frac{2}{2}\)] + [\(\frac{1}{2}\) × 1.5 × 2.0866 ]

\(KE_f\) = 7.35 + 3.2654

\(KE_f\) = 10.62 J

Therefore, the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J

Answer:

Solids have a definite shape and volume. Liquids have a definite volume.Gases have no definite volume.

To find the distance between two charges, we can use Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:

F = (k * |q1| * |q2|) / r^2

where:

F is the force between the charges,

k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2),

|q1| and |q2| are the magnitudes of the charges, and

r is the distance between the charges.

Given:

|q1| = 2 × 10^-7 C

|q2| = 4.5 × 10^-7 C

F = 0.1 N

k = 8.99 × 10^9 N m^2/C^2

We can rearrange the equation to solve for r:

r^2 = (k * |q1| * |q2|) / F

Plugging in the values:

r^2 = (8.99 × 10^9 N m^2/C^2 * 2 × 10^-7 C * 4.5 × 10^-7 C) / 0.1 N

r^2 = (8.99 × 2 × 4.5) * (10^9 * 10^-7 * 10^-7) / 0.1

r^2 = 80.91 * (10^9 * 10^-7 * 10^-7) / 0.1

r^2 = 80.91 * 10^(-7 + 9 - 1)

r^2 = 80.91 * 10^1

r^2 = 809.1

Taking the square root of both sides:

r = √809.1

r ≈ 28.46

Therefore, the distance between the two charges is approximately 28.46 units.

Answer:

The answer is Spring Potential

Explanation:

Because all the others are a mechanical form of energy