Classify the situations according to whether or not they produce a magnetic field. Produces a magnetic field Does not produce a magnetic field Answer Bank A proton at rest An electron moving with a non-zero velocity A long wire carrying a changing current A loop of wire with a break in the loop A solenoid carrying a current A proton next to an electron, both at rest

Answer: Executive Order on Protecting American Monuments, Memorials, and Statues against our country are public monuments, memorials, and statues.

Explanation: learned it last week

a) The centerline velocity is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ) and the velocity 0.5 cm from the wall is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ).

b) Pressure drop over a 10 m length is ΔP = (128μ(10 m)V)/(3.2768 x 10⁻¹¹ π).

The Reynolds number for water flowing in a circular pipe of diameter 2 cm is 600. This can be calculated using the following equation:

Re = (ρVD)/μ

Where Re is the Reynolds number, ρ is the density of the fluid, V is the average velocity of the fluid, D is the diameter of the pipe, and μ is the dynamic viscosity of the fluid.

To find the centerline velocity and velocity 0.5 cm from the wall, we can use the Hagen-Poiseuille equation:

V = (ΔPπD⁴)/(128μL)

Where V is the average velocity of the fluid, ΔP is the pressure drop over the length of the pipe, D is the diameter of the pipe, μ is the dynamic viscosity of the fluid, and L is the length of the pipe.

a. The centerline velocity and velocity 0.5 cm from the wall can be found by substituting the values into the Hagen-Poiseuille equation:

V = (ΔPπ(2 cm)⁴)/(128μ(10 m))

V = (ΔPπ(0.02 m)⁴)/(128μ(10 m))

V = (ΔPπ(0.000016 m⁴))/(128μ(10 m))

V = (ΔPπ(0.000000000256 m^4))/(128μ(10 m))

V = (ΔPπ)/(128μ(10 m)(0.000000000256 m^4))

V = (ΔPπ)/(3.2768 x 10⁻¹¹μ)

The centerline velocity is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ) and the velocity 0.5 cm from the wall is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ).

b. The pressure drop over a 10 m length can be found by rearranging the Hagen-Poiseuille equation and substituting the values:

ΔP = (128μLV)/(πD⁴)

ΔP = (128μ(10 m)V)/(π(2 cm)⁴

ΔP = (128μ(10 m)V)/(π(0.02 m)⁴)

ΔP = (128μ(10 m)V)/(π(0.000016 m⁴))

ΔP = (128μ(10 m)V)/(π(0.000000000256 m⁴))

ΔP = (128μ(10 m)V)/(3.2768 x 10^-11 π)

The pressure drop over a 10 m length is ΔP = (128μ(10 m)V)/(3.2768 x 10⁻¹¹ π).

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Water flowing in a circular conduit with a diameter of 2 cm has a Reynolds number of 600. The pressure drop over a 10 m length is 0.76 Pa.

To solve the given problem, we need to use the formula for the Reynolds number, which is given by:

Re = ρVD/μ

where ρ is the density of the fluid, V is the velocity, D is the diameter of the pipe, and μ is the dynamic viscosity of the fluid.

Given that the Reynolds number for water flowing in a circular pipe of diameter 2 cm is 600, we can use the formula to find the velocity V:

600 = (1000)(V)(0.02)/0.001

V = 0.2 m/s

a. The centerline velocity is 0.2 m/s. To find the velocity 0.5 cm from the wall, we can use the formula for velocity distribution in laminar flow:

V(r) = (2Vmax/π) * (1 - r/R)

where r is the radial distance from the centerline, R is the radius of the pipe, and Vmax is the maximum velocity at the centerline.

At the centerline, r = 0, so Vmax = 0.2 m/s. At r = 0.005 m (0.5 cm from the wall), we have:

V(0.005) = (2 * 0.2 / π) * (1 - 0.005/0.01)^0.5

V(0.005) = 0.13 m/s

b. To find the pressure drop over a 10 m length, we can use the Hagen-Poiseuille equation:

ΔP = 32μLQ/πD^4

where L is the length of the pipe, Q is the flow rate, and ΔP is the pressure drop.

Assuming a fully developed laminar flow, the flow rate is given by:

Q = πR^2V

Q = π(0.01)^2(0.2)

Q = 0.000125 m^3/s

Substituting the values in the equation, we get:

ΔP = (32)(0.001)(10)(0.000125) / π(0.02)^4

ΔP = 0.76 Pa

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Answer:second class lever needs less force to lift a load

Explanation: because the load is between the fulcrum/pivot point and the force. The fulcrum is far away from the force

The minimum impact velocity of an asteroid depends on several factors, including the mass, size, and composition of the asteroid.

Other factors that play a role in determining the impact velocity of an asteroid include its trajectory and the gravitational forces acting on it. There is a formula to calculate the impact velocity of an asteroid based on its mass, size, and trajectory. This formula takes into account the gravitational forces acting on the asteroid and the angle at which it is approaching the Earth. The velocity at which the asteroid impacts the Earth also depends on the location and angle of impact. For example, an asteroid that impacts the Earth at a steep angle will have a higher impact velocity than one that impacts at a shallower angle.

The composition of an asteroid can also influence its impact velocity. Asteroids made primarily of iron and nickel are more likely to survive the trip through Earth's atmosphere and have a higher impact velocity. On the other hand, asteroids made mostly of ice or other volatile substances will likely break apart before impacting the Earth, resulting in a lower impact velocity.

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A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the other tower. He notes that it takes the wave 0.735 s to reach the opposite tower, 20.0 m awayTherefore, the tension in the tightrope is 2310.89 N.

:v = √T/μwhere

,v = wave speed

T = tensionμ = linear density of rope

We know that μ = m/L,

where m is the mass of the rope (0.305 kg) and L is the length of the rope (1 m). So

,μ = m/L = 0.305 kg/

1 m = 0.305 kg/m.

Now we can substitute the values given:

v = d/t

= 20.0 m / 0.735 s

= 27.211 m/s

From the formula of wave speed, we know that

,v = √T/μ

Squaring both sides, we get

:v² = T/μSubstituting the values, we get:

27.211² = T/0.305

Solving for T,T = 2310.89 N

T = 2310.89 N

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Answer:

sorry i cant figure this out

Explanation:

Answer:

I believe that the answer is B) False

The slope of the graph is acceleration of the car with a value of 3.2 m/s².

The given parameters;

The initial velocity of the car in m/s is calculated as follows;

\(60 \ \frac{km}{hr} \times \frac{1 \ hr}{3600 \ s} \times \frac{1000 \ m}{1 \ km} = 16.67 \ m/s\)

The acceleration of the car is calculated as follows;

\(a = \frac{v- u}{t} \\\\a = \frac{80 - 16.67 }{20} \\\\a = 3.2 \ m/s^2\)

The graph of the velocity against time and acceleration against time is in the image uploaded.

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Answer:

please find attached file

Explanation:

Answer:  D) 0-3 seconds

Explanation:

Answer:

The answer is C.) Lacks all 3 types of antigens.

Answer:

Yes, that is correct, although most velocity is calculated via m/s and therfore you would multiply your 3 hours by 60 twice. Much of the information given is irrelevant and just trying to confuse.

Explanation:

Answer:

  175 m

Explanation:

The average velocity for constant acceleration is the average of the beginning and ending velocities. That is (0+39)/2=19.5 m/s. If the bicyclist rides for 9 seconds, the distance traveled is ...

  (9 s)(19.5 m/s) = 175.5 m

She would travel 175.5 meters in that time.

The distance traveled by the bicyclist at the same time period is 175.5 m.

Your question not complete, i believe it is missing this additional information below:

"Seven bicyclist are racing. Each bicyclist rides for 9s, If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time?"

The given parameter:

initial velocity of the bicyclist, u = 0

final velocity of the bicyclist, v = 39 m/s

time of motion of the each bicyclist, t = 9s

To find:

Let the distance traveled by the bicyclist = s

The distance traveled by the bicyclist at the same time period is calculated as;

\(s = (\frac{u+v}{2} )t\\\\s = (\frac{0 + 39}{2} ) \times 9\\\\s = 19.5 \times 9\\\\s = 175.5 \ m\)

Thus, the distance traveled by the bicyclist at the same time period is 175.5 m.

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Answer:

Amorphous solids are composed of atoms or molecules that are in no particular order. Each particle is in a particular spot, but the particles are in no organized pattern. Examples include rubber and wax. Crystalline solids have a very orderly, three-dimensional arrangement of atoms or molecules

Explanation:

Specialty stores compete on the basis of low prices, high turnover, and high volume, this statement if false.

Specialty stores typically compete based on factors other than low prices, high turnover, and high volume. Specialty stores differentiate themselves by offering unique, high-quality, or niche products to target specific customer segments. They often focus on providing a curated selection of merchandise, personalized customer service, and expertise in their specific product category.

While competitive pricing and turnover can still be important, the primary emphasis is on providing specialized products and a unique shopping experience rather than competing solely on low prices, high turnover, and high volume.

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Lets se

And

\(\\ \rm\Rrightarrow T=2\pi\sqrt{\dfrac{m}{k}}\)

\(\\ \rm\Rrightarrow \sqrt{k}T=2\pi\sqrt{m}\)

So

\(\\ \rm\Rrightarrow k\propto m\)

If spring constant is doubled mass must be doubled

Experimental evidence that supports the new idea

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm maybe

Answer:

its c

Explanation:

Answer:

What happens when you throw a basketball up

toward the hoop? If you are lucky, the ball sinks

into the net, scoring two points before dropping

back down to the ground. The basketball isn’t

that heavy, so why doesn’t it stay up in the air

saying, “What comes up must come down”?

This saying is a simple explanation for what

causes the basketball to fall back to the ground.

It is being acted on by an invisible force called

gravity, which is the basic force in the universe

that attracts all objects to each other.

1 Gravity has existed since the beginning of the universe. It is hard to understand how or why it

works, but we know it is always there because it holds everything in the universe in place. First,

you need to understand that there is a gravitational attraction between you and Earth, between

Earth and the Moon, and between Earth and the Sun. Even though you can’t feel it, the

gravitational attraction between you and Earth is what keeps your feet planted firmly on the

ground. Imagine spinning around and around on a merry-go-round. As long as you are holding

on, then you stay on the merry-go-round, but if you ever let go, you will fly off and land on the

ground. This is a useful analogy in visualizing the gravitational attraction between Earth and

you. Earth is spinning on its axis and thanks to gravity, you are held to your position on Eart

rather than flying out into space. Explanation: this is what i can do!:)

Answer:

I believe gravity is the most important aspect of our universe. Without it we would all be floating off into the universe. There wouldn’t be any orbits; instead, all planetary bodies would simply float around, running into each other when they crossed paths and just wandering forever.

Explanation:

this is the best match

The refrigerator's coefficient of performance is 1.5.

To find the refrigerator's coefficient of performance, we'll use the given information: it takes in 20 J of work and exhausts 50 J of heat.

The coefficient of performance (COP) is the ratio of the useful heat transfer to the work input. In the case of a refrigerator, the useful heat transfer is the amount of heat removed from the refrigerated space (Q_c). The work input is the work done on the refrigerator (W).

COP = Q_c / W

We know that the refrigerator takes in 20 J of work (W = 20 J) and exhausts 50 J of heat (Q_h = 50 J). In a refrigerator, the heat removed from the refrigerated space (Q_c) can be found by subtracting the heat exhausted from the work input:

Q_c = Q_h - W
Q_c = 50 J - 20 J
Q_c = 30 J

Now we can find the coefficient of performance:

COP = Q_c / W
COP = 30 J / 20 J
COP = 1.5

So, the refrigerator's coefficient of performance is 1.5.

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The value of 0.0000153g for the gravity function is 0.00015 m/s²

Acceleration due to gravity (often denoted by "g") is the acceleration that an object in free fall experiences due to the gravitational force exerted by a massive body, such as the Earth.

At the Earth's surface, the standard value of acceleration due to gravity is approximately 9.81 meters per second squared (m/s²). This means that an object in free fall near the Earth's surface will accelerate at a rate of approximately 9.81 m/s², regardless of its mass.

The value of 0.0000153g = 0.0000153 x 9.81 m/s² = 0.00015 m/s²

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Answer:

a=-5.3m/s2

Explanation:

F=-20N

m=3.75kg

a=?

F=am /:m

a=F/m

a=-20N/3.75kg

a=-5.3m/s2

A scientific law is an established principle that explains a phenomenon or behavior in the natural world. It is a concise statement that summarizes the results of many observations and experiments and is widely accepted as true because it has been confirmed over and over again.

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Answer:

It would allow storm systems to stall in an area.

Answer: A weaker jet stream would allow storm systems to stall in one area.

Answer: Fluorine has seven valence electrons, so it is most likely to gain one electron to form an ion wit a 1- charge.

Explanation:

A fluorine atom can attract one additional electron to fill its outermost shell and achieve a stable electron configuration. This ability to attract electrons is due to fluorine's high electronegativity, which is a result of its small atomic size and high nuclear charge. The strong attraction between fluorine and electrons makes it highly reactive and capable of forming strong chemical bonds with other elements.

Atoms are composed of positively charged protons, negatively charged electrons, and neutral neutrons. The number of electrons in an atom determines its chemical properties, as the electrons are involved in chemical bonding. Some atoms have a tendency to attract additional electrons to fill their outermost electron shell, which can result in the formation of ionic or covalent bonds. Fluorine is one such atom that has a strong tendency to attract additional electrons due to its high electronegativity.

Fluorine is a highly electronegative element, meaning it has a strong tendency to attract electrons towards itself. This is due to its small atomic size and high nuclear charge, which results in a strong electrostatic attraction between the positively charged nucleus and the negatively charged electrons.

Fluorine has seven electrons in its outermost shell, which means it is only one electron short of having a full outer shell. This makes fluorine highly reactive, as it has a strong tendency to attract an additional electron to fill its outer shell and achieve a stable electron configuration. When fluorine attracts an additional electron, it forms a negative ion called fluoride.

The strength of fluorine's electronegativity can be quantified using a scale called the Pauling scale. Fluorine has the highest electronegativity of all the elements on the periodic table, with a Pauling electronegativity value of 4.0. This means that fluorine can attract electrons more strongly than any other element, making it highly reactive and capable of forming strong chemical bonds with other elements.

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F = mass × Acceleration ( give Acceleration is 9.8 )

So force of 5 kg mass on A is

F = 5 × 9.8 = 49N

Force of mass 1 kg on A

F = 1 × 9.8 = 9.8 N

Force of mass 10 kg on A is

F = 10 × 9.8 = 98N

Clearly the 10 kg ball experts the most force cause it has more mass

The barycenter, which is the shared point around which the Earth and Moon orbit the Sun, is located a certain distance from the Earth's center. In this context, the question asks for the distance between the barycenter and the Earth's center.

The barycenter is the center of mass between two celestial bodies, in this case, the Earth and the Moon. It is determined by the relative masses and distances of the two bodies. In the Earth-Moon system, the barycenter is located within the Earth because the Earth is significantly more massive than the Moon. Due to this difference in mass, the barycenter is closer to the center of the more massive body, which is the Earth. However, it is important to note that the barycenter is not fixed and can move depending on various factors, such as the positions of the Earth, Moon, and Sun.

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