coherent light with wavelength 460 nm falls on a pair of slits. on a screen 1.85 m away, the distance between dark fringes is 3.96 mm.

Lifting a 25.0 pound (11.4 kg) book bag up to your lab bench, which is 4.50 feet (1.38 m) off the ground, requires 154.17 joules of work.

A joule is a unit of measure used by scientists. To move an object one meter in the force's direction, a force of one newton must exert one joule of energy.

Force multiplied by distance, or F×d is the formula for the amount of work expressed in joules. However, it is clear that no force is applied when a 25.0-pound (11.4 kg) book bag needs to be lifted to your lab bench, which is 4.50 feet (1.38 m) off the ground. On the other hand, we can return to the definition of force, which is defined as the mass times the acceleration, or m×a. Gravitational acceleration in this instance is 9.8 m/s² and the mass is 11.4 kg. These two add up to 111.72 Newtons, which is the unit of force created by combining kilograms and meters per second. Since there is already force, it can be multiplied by the distance, which is 1.38 meters. There is 154.17 J worth of work.

W = F × d

F = m×a

W= (m×a) ×d

W= (11.4 kg × 9.8m/s²) × 1.38 m

W= 111.72 N × 1.38 m

W= 154.17 J.

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The time required for a signal to travel 0.200 m through an optical fiber with an index of refraction of n = 1.55 is approximately 1.03 nanoseconds.

To calculate the time required for a signal to travel through the optical fiber, we need to use the formula:

t = d / v

where t is the time, d is the distance traveled by the signal, and v is the velocity of the signal in the medium (which is determined by the index of refraction).

In this case, we are given that the index of refraction is n = 1.55. The velocity of light in a medium with this index of refraction is:
v = c / n
where c is the speed of light in a vacuum (which is approximately 3 x 10^8 m/s).

Plugging in the numbers, we get:
v = (3 x 10^8 m/s) / 1.55 = 1.94 x 10^8 m/s
Now we can calculate the time required for the signal to travel 0.200 m:

t = d / v = (0.200 m) / (1.94 x 10^8 m/s) = 1.03 x 10^-9 s = 1.03 ns

Therefore, the time required for a signal to travel 0.200 m through an optical fiber with an index of refraction of n = 1.55 is approximately 1.03 nanoseconds.

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Answer:

do you mean how? if so

Explanation:people used newspapersand still kinda do back then they had posters up as they still do and newspapers

75km=75000m

35min=2100 seconds

Velocity=Displacement/Time

=75000/2100

=750/21

=35.71 m/s

Answer:

- 89.523J

Explanation:

We solve the above question using work done(Potential Energy) formula

The formula =

-(mgh)

Where m = Mass = 4.50J

g = Acceleration due to gravity = 9.8m/s²

We are told in the question:

Initially, the cart was 0.670 m above the floor. If the top of the inclined plane is 2.70 m above the floor

Hence, the height =

2.70m - 0.670m = 2.03m

Work done = -(2.03m × 4.5kg× 9.8m/s²)

= - 89.523J

Answer:

1: Because matter has many different forms.

2: The materials that are shown can be organized into 3 different forms; solid, liquid, and gas.

3: The image of the liquids is most likely a material that cannot be found in nature. Liquids have many useful properties, but it depends on the liquid. Bleach is a liquid that has is very useful for sterilizing. Water is useful because without it, life on earth would not exist. And there are many more liquids, but I am going to cut it short here because there too many to put down.

Explanation:

Pls mark Brainliest with the crown.

The force that cannot be the resultant of these forces is 10N since it is less than both given forces

Given the forces with a magnitude of 12N and 24N, the resultant of these forces must not be less than any of the two forces.

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Answer:

we must multiply the speed value by 3.6

Explanation:

To reduce a magnitude from one unit to another, it must be multiplied by the equivalence in the order necessary so that the units do not change.

To reduce speed from m / s to km / h

we write the speed and the two conversion factors

         v [m / s] [1 km / 1000m] [3600 s / 1h

         v 3600/1000

          v 3.6

therefore we must multiply the speed value by 3.6

Answer:

05 m/s =378 km/h

Explanation:

we have to convert the meters per second into kilometers per hour.

1m /sec = (1/1000)/ (1/3600) km/h = 3600/1000 km /h

divide 105 by 1000, and multiply it by 3600.

105 /1000 x 3600 = 378 km/h

Answer:

100 miles North East.

Explanation:

Please see attached photo for diagram.

In the attached photo, X represents the magnitude of the total displacement of the train.

Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:

X² = 80² + 60²

X² = 6400 + 3600

X² = 10000

Take the square root of both side

X = √10000

X = 100 miles.

Therefore, the magnitude of the total displacement of the train is 100 miles North East.

Answer:

C

Explanation:

I would have said B but air pressure acts at ALL angles(directions). C makes sense because the increase in the temperature would cause the molecules to bounce off the walls of the balloon and each other which exerts pressure.

Answer:

C c hagwguawnjaahwbhanwbhsqn2nusbwvwf

Answer:

becomes halved.

Explanation:

trust

Answer:

becomes halved. or is reduced to half

Explanation:

The description of the nature of image formed 2nd if the object X distance from the pole of mirror then find image distance from the pole 3rd if the radius of curvature of mirror is are then write the relation between object distance image distance and focal length of the mirror give one use of concave mirror is given below

A concave mirror is a mirror with a curved, inwardly facing surface. When an object is placed in front of a concave mirror, the mirror will form an image of the object. The nature of the image formed depends on the position of the object relative to the mirror.

To find the image distance from the pole of the mirror, you can use the mirror equation:

1/image distance + 1/object distance

= 1/focal length.

If the object is X distance from the pole of the mirror, you can substitute this value for the object distance in the mirror equation to find the image distance.

The relationship between the object distance, image distance, and focal length of a concave mirror can be expressed using the mirror equation:

1/image distance + 1/object distance

= 1/focal length.

This equation tells us that the sum of the reciprocals of the object distance and image distance is equal to the reciprocal of the focal length.

Therefore, One use of a concave mirror is as a reflector in a flashlight or car headlight. The concave mirror focuses the light to a point in front of the mirror, creating a bright beam of light that can be directed at a specific location.

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A radio frequency identification application would most likely interface with an Operational Data Store.

The Operations Data Store (ODS) is a central database that provides the latest data snapshots from multiple transaction systems for operational reporting.

It allows organizations to combine data in its original format from various sources into a single destination to provide business reporting.

ODS contains integrated updates from operational sources and supports business intelligence (BI) tools to facilitate tactical decision making.

For example, an administrator can configure ODS to pull weekly batches of data from a billing application that is rarely updated, importing individual transaction records as they occur in the sales database(thanks to these database triggers), then combine the two into new relational tables.

As a result, querying and reporting on operational data in ODS comes with the assurance that these integrated tables contain the latest and most relevant snapshots of the business.

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Answer:

Explanation:

The resistance of this device is determined by using the formuia from Ohms Law:

V = IR

where; V = voltage

I = current

R = resistance

From the above equation:

R = V/ I ---- (1)

And

I = P/V    --- (2)

If 1 unit = 1 KWH = 3.6 × 10⁶ J

Then;

2.2 units = (3.6 × 10⁶ × 2.2)

= 7.92 × 10⁶ J

So, Energy = 7.92 × 10⁶ J

Also:

Power = energy/time

Power =  7.92 × 10⁶ J / 1 hour

Power = 7.92 × 10⁶ J / 3600 seconds

Power = 2200 Watts

From equation (2)

I = P/V

I = 2200/220

I = 10 A

Recall that:

Resistance R = V/I

Resistance R = 220/10

Resistance R = 22 ohms

SO, if 1 unit costs = Ts 6.00

Then the cost of 2.2 unit = 2.2 ( Rs  6.00)

= Rs 13.20

Answer:

idek

Explanation:

a. Machine A has a shorter average cycle time compared to Machine B. b. Machine A (1.125 hours) still has a shorter average cycle time compared to Machine B (2.125 hours). c. with an arrival rate of 0.95 job per hour and c = 1, Machine B now has a shorter average cycle time compared to Machine A.

(a) To determine which machine will have a shorter average cycle time, we need to compare their cycle times using the given parameters. The cycle time can be calculated as the sum of the mean effective process time (te) and half of the product of te and SCV (Standard Coefficient of Variation).

For Machine A:

Cycle time for Machine A = te + 0.5 * te * c

Substituting the given values:

Cycle time for Machine A = 1.0 hour + 0.5 * 1.0 hour * 0.25 = 1.125 hours

For Machine B:

Cycle time for Machine B = te + 0.5 * te * c

Substituting the given values:

Cycle time for Machine B = 0.85 hour + 0.5 * 0.85 hour * 4 = 2.125 hours

Therefore, Machine A has a shorter average cycle time compared to Machine B.

(b) When two identical machines of type A are placed in parallel at the station and the arrival rate is doubled, the cycle time for each machine will remain the same. This is because the machines are independent, and each machine will handle its portion of the arrival rate.

Similarly, when two identical machines of type B are placed in parallel at the station and the arrival rate is doubled, the cycle time for each machine will also remain the same.

Comparing the cycle times, Machine A (1.125 hours) still has a shorter average cycle time compared to Machine B (2.125 hours).

(c) For Machine A:

Cycle time for Machine A = te + 0.5 * te * c

Substituting the given values:

Cycle time for Machine A = 1.0 hour + 0.5 * 1.0 hour * 1 = 1.5 hours

For Machine B:

Cycle time for Machine B = te + 0.5 * te * c

Substituting the given values:

Cycle time for Machine B = 0.85 hour + 0.5 * 0.85 hour * 1 = 1.275 hours

Therefore, with an arrival rate of 0.95 job per hour and c = 1, Machine B now has a shorter average cycle time compared to Machine A.

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The width of the box  in order for the n = 2 to n = 1 is : 3.3 * 10⁻¹⁰ m

Given data :

λ = 122 nm

Transition ; n = 2 to n = 1

Determine the width of the box  applying the formulae below

Total energy ( E₁ ) = \(\frac{h^{2} }{8mL^{2} }\) --- ( 1 )

Change in energy = ΔE = \(\frac{hc}{λ}\)  

Next step : Determine the difference in Total energy and change in energy

ΔE - E₁ = \(\frac{hc}{λ}\)

∴ E₁ = \(\frac{hc}{3λ}\) ------ ( 2 )

Equate equations ( 1 ) and ( 2 )

\(\frac{h^{2} }{8mL^{2} }\)  = \(\frac{hc}{3λ}\)   ----- ( 3 )

where ; L = width of the box

Final step : Determine the width of the box

from equation ( 3 )

L² = \(\frac{3hλ }{8mc}\) ---- ( 4 )

∴ L² = ( 6.6 * 10⁻³⁴ * 122 * 3 * 10⁻⁹ ) / ( 8 * 9.1 * 10⁻³¹ * 3 * 10⁸ )

∴ L  = 3.3 * 10⁻¹⁰ m

Hence we can conclude that The width of the box  in order for the n = 2 to n = 1 is : 3.3 * 10⁻¹⁰ m

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Some data related to your question is missing below is the missing data

PART A If the atom is modeled as an electron in a one-dimensional box, what is the width of the box in order for the n = 2 to n = 1 transition to correspond to emission of a photon of this energy?

Answer:

The cap expanded

Explanation:

As you run hot water (Or any substance) onto something it expands, With coldwater it shrinks. Its like clothes, If a shirt is to small wash it in hot water. If it is to big run it in cold water.

The ratio of the sun's gravitational force on the moon to the earth's gravitational force on the moon is approximately 2:1.

The gravitational force that an object with mass exerts on another object with mass is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them. This is known as the universal law of gravitation.

                        The force of gravity between the moon and the earth is stronger than the force of gravity between the moon and the sun because the moon is much closer to the earth than it is to the sun. The sun's gravitational force on the moon is about 46% of the earth's gravitational force on the moon.

                             This means that the ratio of the sun's gravitational force on the moon to the earth's gravitational force on the moon is approximately 2:1 .

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7200 joules of heat and light energy was dissipated into the air. But no work was done ... no force moved through no distance.

The statement is true. The s-wave shadow zone refers to an area on Earth's surface where no s-waves from earthquakes are detected. This shadow zone is caused by the refraction and reflection of s-waves as they pass through the Earth's interior layers, particularly the outer core.

The outer core is composed of molten iron and nickel, and its properties cause s-waves to be refracted and reflected, preventing them from being detected in certain areas on Earth's surface. Therefore, the location of the outer core plays a significant role in determining the location of the s-wave shadow zone.
true. The S-wave shadow zone is indeed caused by the location of the outer core. S-waves, or secondary waves, are a type of seismic wave that cannot travel through liquid. When S-waves encounter the Earth's outer core, which is a liquid layer composed primarily of molten iron and nickel, they are absorbed or refracted, creating a shadow zone on the opposite side of the Earth. This shadow zone helps scientists understand the composition and properties of the Earth's interior layers, including the outer core.

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The correct answer is: D. Al3+ (1 M) , Aluminum ion (Al3+) is capable of oxidizing copper (Cu) to copper ion (Cu2+). This is because aluminum has a higher reduction potential than copper. In a redox reaction, the species with a higher reduction potential can oxidize the species with a lower reduction potential.

When aluminum is in the presence of copper, it can donate electrons to the copper atoms, causing them to lose electrons and become copper ions (Cu2+). The aluminum ions, in turn, are reduced to aluminum atoms. This reaction allows for the oxidation of copper to copper ions.

The other reagents listed, I- (iodide ion), Ni (nickel), Ag+ (silver ion), and H+ (hydrogen ion), do not have a higher reduction potential than copper and therefore are not capable of oxidizing copper to copper ions.

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The force transmitted to the man's leg bones during his downward motion is 14,945 N

State the equations of motion

The fundamentals of an object's motion, such as its position, velocity, or acceleration at different periods, are described by kinematics equations of motion or Newton’s equations of motions.

An object's motion in 1D, 2D, and 3D is controlled by these three equations of motion-

First law of equation: v = u + at

Second law of motion: s = ut + at^2/2

Third law of motion: v^2=u^2 + 2as.

In the question, the following informations are given,

Mass of the man, m = 70kg

Height the man jumps, h = 1.00 m

Time taken to reach the ground, t = 0.02 seconds

Using the 3rd equation of motion we find out the velocity with which the man comes down as-

v^2 = u^2 +2gh

v^2 = 0 + 2 x 9.8 x 1

v^2 = 19.6

v = √19.6

  = 4.27 m/s

Since force is determined by both time and acceleration therefore using the formula of force we find out the velocity as-

F = mass x acceleration

  = mass x velocity/time

  = 70 x 4.27/ 0.02

  = 14,945 N

Hence, the force transmitted to his leg bones is 14,945 N

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The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.

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Given that the progressive wave equation is represented by y=Asin2π(0.15t-0.1x). Let's find the period, amplitude, frequency, wavelength, and velocity.

The wave equation is represented by y=Asin2π(0.15t-0.1x). The standard wave equation can be written asy = Asin(kx-ωt + Φ)Where,k = wave numberω = angular frequencyΦ = phase angle for the given equation, k = 0.1 and ω = 0.15.Amplitude:

Amplitude = A = maximum displacement from the mean position.A = 1Frequency: Frequency is the number of complete oscillations made by a point on the wave in one second. It is denoted by f.f = ω/2πFrequency, f = 0.15/2π = 0.0238 HzPeriod: Period is the time taken by one complete oscillation.

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The conditions necessary to produce a solar eclipse are the moon's position in relation to the sun and Earth, as well as the Earth's position in relation to the sun. A solar eclipse can only occur during a new moon and can be total, partial, or annular.

A solar eclipse is an occurrence when the moon transits between the sun and the Earth, blocking the sun's light and casting a shadow on the Earth's surface.

The conditions needed to produce a solar eclipse are the moon's position in relation to the sun and Earth, as well as the Earth's position in relation to the sun. A solar eclipse only occurs during a new moon when the sun, moon, and Earth are aligned in a straight line with the moon between the sun and Earth.

This occurs approximately twice a year. There are three types of solar eclipses: total, partial, and annular. In a total solar eclipse, the moon completely covers the sun's disk, causing a total blackout.

A partial solar eclipse occurs when the moon covers only a portion of the sun's disk. An annular solar eclipse occurs when the moon is at its farthest point from the Earth and appears smaller, creating a "ring of fire" around the sun.

For a solar eclipse to occur, the moon must be in its new phase, which means it must be on the same side of the Earth as the sun. During this time, the moon's shadow falls on the Earth's surface, creating a path of totality or partiality.

The path of totality is the area where a total solar eclipse can be observed, while the path of partiality is the area where a partial solar eclipse can be observed. In conclusion, a solar eclipse occurs when the moon passes between the sun and the Earth, casting a shadow on the Earth's surface.

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Answer:

they are both curved surfaces

Explanation:

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

Answer:

Jupiter is the largest planet in the solar system, but it's Saturn—the solar system's second largest planet—that takes the prize for least dense. It's less dense than water, which has led many people to postulate that it would float.

Answer:

the level on the top

Explanation:

_+$+$