Answer:
Heat is a form of energy. It is measured in Joules. ... The temperature of an object relates to both the kinetic energy of its particles and the number of particles. Temperature is the average kinetic energy of the particles in a substance.
Explanation:
1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.
We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.
The heat lost by the metal is given by
Q1 = m1c1ΔT1
Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.
The heat gained by the ice is given by
Q2 = m2c2ΔT2
Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.
Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2
m1c1ΔT1 = m2c2ΔT2
Solving for c1, we get
c1 = m2c2ΔT2 / (m1ΔT1)
By putting these values we get
c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]
c1 = 0.902 kJ/kg·K
Hence, the specific heat of the metal is 0.902 kJ/kg·K.
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D 4.8
This is a harder question based on the Law of Conservation of Momentum. Take the time to work
your way through it. Start with a diagram.
A 400 kg bomb sitting at rest on a table explodes into three pieces. A 150 kg piece moves off to the
east with a velocity of 150 m s². A 100 kg piece moves off with a velocity of 200 m s at a direction of
south 60° west. What is the velocity of the third piece?
It is possible
The velocity of the third piece is v₃ = -12500 kg·m/s / m₃
How do we calculate?The law of conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion.
velocity of the third piece = v₃.
The total initial momentum before the explosion = 0
The total final momentum after the explosion= 0
Initial momentum = 0 kg·m/s (since the bomb is at rest)
Final momentum = m₁v₁ + m₂v₂ + m₃v₃
m₁ = mass of the first piece = 150 kg
v₁ = velocity of the first piece = 150 m/s (to the east)
m₂ = mass of the second piece = 100 kg
v₂ = velocity of the second piece = 200 m/s (south 60° west)
m₃ = mass of the third piece = unknown
v₃ = velocity of the third piece = unknown
0 = (150 kg)(150 m/s) + (100 kg)(200 m/s)(cos(60°)) + (m₃)(v₃)
final momentum = 0 and hence v₃ is found as :
0 = 22500 kg·m/s - 10000 kg·m/s + (m₃)(v₃)
-12500 kg·m/s = (m₃)(v₃)
v₃ = -12500 kg·m/s / m₃
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In hiking, what fitness component is required of you
Question 16 1 pts Jessie feels pressured by his parents to get a job. This is an example of the law of?
readiness
disuse
effect
belonging
Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to the rest mass energy of an electron. What should be the accelerating potential that need to be applied on an electron so that it has a de Broglie wavelength equal to that of the proton calculated above?
mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.
What is the energy of an electron that has undergone a 100 kV potential difference?An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.
What is the relationship between kinetic energy and the de Broglie wavelength?De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.
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The dimension of a rectangular shape is 5.9 by 4.1mm s measured with a veneer calliper whose minimum scale is 0.05 mm. The percentage error in its surface area is approximately.
Answer:
e% = 2.2%
Explanation:
In the measurements it is very important the precision of the readings and the knowledge of how the uncertainty or errors in each measurement propagates when carrying out the different calculations
In this case the area of the body is its length l = 5.9 mm, for its width a = 4.1 mm
S = l a
The error can be calculated using derivatives and considered the worst of all cases
Δs = ds /dl Δl + dS /da Δa
in this case the derivatives are very simple
dS / dl = a
dS / Da = l
we substitute
ΔS = a Δl + l Δa
this is the absolute error
Let's calculate its value
Δs = 4.1 0.05 + 5.1 0.05
Δs = 0.5 mm²
the percentage error is this error between the magnitude of the mediated by 100
e% = ΔS / S 100
e% = 0.5 / (5.1 4.1) 100
e% = 2.2%
Fossils are remains of organisms found in sedimentary rock. These remains are found in thousands of rock layers around the world and provide evidence for Earth's long history of changing lifeforms.
Rock layers that formed more recently
Answer:
metamorphic rocks
Explanation:
I hope this helps you, I'm sorry if it's wrong!
If it's right please don't forget to mark me as brainliest!
Answer:
the top layers
Explanation:
sedimentary layers are deposited on top of each other over time
What do you understand by the term "Eigen function and Eigen value" in quantum mechanics. Give an example each.
In quantum mechanics, an eigenfunction is a function that satisfies a particular differential equation and is used to describe the behavior of a physical system. An eigenvalue is a scalar value that corresponds to an eigenfunction and represents the magnitude of a physical property of the system.
An example of an eigenfunction in quantum mechanics is the wavefunction, which is used to describe the probability distribution of a particle in a particular state. The wavefunction is an eigenfunction of the Schrödinger equation, which is a fundamental equation in quantum mechanics that describes the time evolution of a physical system.
An example of an eigenvalue in quantum mechanics is the energy of an atom in a particular state. The energy of an atom is an eigenvalue of the Hamiltonian operator, which is a mathematical operator that describes the energy of a physical system.
In general, eigenfunctions and eigenvalues play a central role in the analysis of quantum mechanical systems and are important tools for understanding the behavior of particles at the atomic and subatomic scales.
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1. List five examples of pseudoscience found on the Internet. These could be websites, blogs, or online newspaper and magazine articles.
The five examples of pseudoscience found on the Internet include the following:
Ancient Astronauts and Crop CirclesMoon Landing Conspiracy or the Flat EarthAstrologyPolygraphs and HypnosisConversion TherapyWhat are Pseudosciences?Pseudosciences is defined as the science that is regarded as false science because it deals with something that has no connection to proper scientific methodology and cannot be proven realistically.
The different types of Pseudosciences include the following:
Ancient Astronauts and Crop Circles: This believes that a point in time, that aliens must have visited the earth to influence civilization.Moon Landing Conspiracy or the Flat Earth: This believed that original moon landing by astronauts didn't occur and that the earth is flat in shape.Astrology: This believes that celestial bodies have some effect on the behavior or future of a person's life.Polygraphs and Hypnosis.Conversion Therapy.Learn more about earth shape here:
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Raju completes one round of a circular track of diameter 200m in 30s. Calculate
a. The distance travelled by Raju
b. The magnitude of displacement travelled by Raju at the end of 30 s.
Explanation:
Given:
Diameter = 200 m
Radius, r = 200/2 = 100 m
Time taken, t = 30 seconds
Formula to be used:
Distance traveled, = circumference of circle = 2πr
Answer:
Putting all the values, we get
Distance traveled = 2πr
Distance traveled = 2 × 22/7 × 100 Distance traveled = 4400/7 Distance traveled = 628.57 mSo, the distance traveled by Raju is 628.57 m.
Now, magnitude of the displacement,
At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.
apply the loop rule to loop 2 (the smaller loop on the right). sum the voltage changes across each circuit element around this loop going in the direction of the arrow. remember that the current meter is ideal.express the voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.
The voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.ΣΔV = 0 = I3 ⋅ R3 - I2 ⋅ R2.
When applying Kirchhoff's second rule the loop rule we need to identify closed loops and decide whether to loop clockwise or counterclockwise. For example, in Figure 3 the loop was traversed in the same direction as the current.
Loop 1 is the full loop and Loop 2 is the small loop on the right. To apply the loop rule, add all those voltage changes. Kirchhoff's Second Law, also known as Kirchhoff's Voltage Law states that the sum of all voltages around the closed loop of any circuit must be zero. This is a result of charge conservation and energy conservation.
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Dropping a pebble into water . Is this acceleration?
Answer: dropping a pebble in the water is acceleration
hang on I need to poop
Explanation:
You place an ice cube in a microwave oven. If it requires 32,270 J to melt the ice cube and the oven delivers 108 W of power to the ice cube, determine the time (in min) needed to melt the ice cube.
min
The time needed to melt the ice cube in the microwave oven is approximately 5 minutes.
To calculate the time needed to melt the ice cube, we can use the formula:
Energy (in joules) = Power (in watts) × Time (in seconds)
First, let's convert the power from watts to joules per second:
108 W = 108 J/s
Now, we can rearrange the formula to solve for time:
Time (in seconds) = Energy (in joules) / Power (in joules per second)
Given that it requires 32,270 J to melt the ice cube and the power delivered by the oven is 108 J/s, we can substitute these values into the formula:
Time (in seconds) = 32,270 J / 108 J/s
Time (in seconds) ≈ 299.537 s
Finally, we convert the time from seconds to minutes:
Time (in minutes) = 299.537 s / 60 s/min ≈ 4.992 min
Therefore, it would take approximately 5 minutes to melt the ice cube in the microwave oven.
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How can a water molecule from an apple eventually make its way inside a cloud and then back to Earth?
When an apple tree takes up water from the soil, it moves up through the roots, stems, and into the leaves. In the leaves, water is combined with carbon dioxide during photosynthesis to create glucose (sugar) and oxygen. Through transpiration, water is released from the leaves back into the atmosphere. This water vapor can then rise and eventually form clouds through a process called condensation, in which the water vapor cools and changes into liquid droplets or ice crystals. When the clouds become heavy with moisture, precipitation occurs, such as rain or snow, and the water droplets or ice crystals fall back to Earth. Therefore, a water molecule from an apple can eventually end up in a cloud and back to Earth through the natural water cycle.
Which of the following questions could you ask if you wanted to expand on the following piece of data?
Standardized testing helps hold schools and teachers accountable for students' performance.
A. Are there any negative effects associated with standardized testing?
B. How effective are the tests at assessing whether a student has learned a particular skill?
C. Who decides what should be included in a standardized test?
D. All of the above are correct.
A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.
When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e
Answer:
e
Explanation:
Normal temperature of human body is 98.6F while its atmosphere temperature is 84.6F what will be temperature of dead body in such atmosphere
A. 84.6F
B. 98.6F
C. 92.5F
D. 185F
Answer:
B. 98.6F is the temperature of dead body in 84.6F atmosphere.
Answer:
See below
Explanation:
After a while, the body will assume the temperature of its surroundings
and will be 84.6 degrees F
IMMEDIATLY after death the body will still be at 98.6 F ...but beginning to cool......
On a calm day, a windmill blade 6 m long turns 0.20 rad in 1s. What is the linear velocity of the tip of the blade?
We are given the following information
Length of the windmill blade = 6 m
Angular velocity of the windmill = 0.20 rad/s
We are asked to find the linear velocity of the tip of the blade.
The linear velocity of the tip of the blade is given by
\(v=\omega\cdot L\)Where ω is the angular velocity of the windmill and L is the length of the blade.
Substituting the given values into the above formula, we get
\(\begin{gathered} v=0.20\cdot6 \\ v=1.2\; \; \frac{m}{s} \end{gathered}\)Therefore, the linear velocity of the tip of the blade is 1.2 m/s
(7%) Problem 14: A robot cheetah can jump over obstacles. Suppose the launch speed is vo = 4.74 m/s, and the launch angle is 0 = 25.5
degrees above horizontal.
What is the maximum height in meters?
Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?
The height that will illustrate the distance will be d = 6.36m
How to calculate the height?Based on the information given, the length of the vine will be:
L = ✓(16² + 27.7)²
L = 32m
The velocity of Jane when she reaches position B will be:
V = ✓2gh
V = ✓(2 × 9.8 × 4.3)
V = 9.18m/s
We will apply the conversation of momentum. This will be:
50 × 9.18 = (50 + 80)V1
V1 = 3.53m/s
Therefore, the height that will illustrate the distance will be:
31.36² + d² = 32²
d² = 32² - 31.36²
d = 6.36m
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What is the difference between classical mechanics and quantum mechanics?
Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.
~~~Harsha~~~
A 177.3 gram mass is attached to a 85.3 cm long string which is tied to a support at the other end. The mass is pulled to the side and released so that it swings like a pendulum. At the lowest point of the circular path that the mass takes, it is moving at a speed of 1.33 m/s. Determine the force of tension in the string at this point in Newtons.
The force of tension in the string at the lowest point of the circular path is 2.1 N.
What is the centripetal acceleration of the mass?
The centripetal acceleration of the mass is calculated as follows;
a = v²/r
where;
v is the linear speed of the mass = 1.33 m/sr is the radius of the mass = 85.3 cm = 0.853 ma = (1.33²) / (0.853)
a = 2.07 m/s²
The force of tension in the string at the lowest point of the circular path is calculated as follows;
T = ma + mg
T = m(a + g)
where;
g is acceleration due to gravitya is the centripetal acceleration of the massm is the mass, m = 177.3 g = 0.1773 kgT = 0.1773(2.07 + 9.8)
T = 2.1 N
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In the circuit shown, the galvanometer shows zero current. The value of resistance R is :
A) 1 W
B) 2 W
C) 4 W
D) 9 W
Answer:
its supposed to be (a) 1W
19. A pitcher throws a baseball toward a batter at 30m/s. The batter swings his
bat and hits the baseball. The baseball flies away in the opposite direction at a
speed of 35m/s. Is there a transfer of energy in this situation? (SC.7.P.11.4)
a) Yes, because both the bat and the ball are moving after the collision.
b) No, because the ball and the bat only touched for a short time.
c) Yes, because the force from the bat changes the motion of the ball
A pitcher throws a baseball towards a batter at 30m/s. The batter swings his bat and hits the baseball, then there is a transfer of energy in this situation : c) Yes, because the force from the bat changes the motion of the ball.
How is energy transferred from baseball bat to a baseball?Although baseball may appear hard and solid, it actually behaves much like a rubber ball. In the fraction of a second that ball collides with the swinging bat, ball compresses as the energy of motion goes into deforming the ball and transforms it into an elastic potential energy.
The collision of baseball with bat is elastic and the collision between baseball and glove is nearly inelastic.
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Question 5 (15 points)
You stand on a bridge above a river and drop a rock into the water below from a
height of 35 m. (Assume no air resistance.)
a.
The acceleration of the rock as it falls is 9.8 m/s^2, which is the acceleration due to gravity.
b.
The time it takes to hit the water is 2.236 s
c.
The time it takes for the rock to hit the water if it is thrown horizontally is 0
How do we calculate?The time it takes to hit the water can be calculated using the equation:
t = √(2*h/g)
where h is the height (25 m), g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
t = √(2*25/9.8) = √(5) = 2.236 s
c. The time it takes for the rock to hit the water if it is thrown horizontally can be calculated using the equation:
t = x/v
where x is the horizontal distance, v is the initial horizontal velocity (20 m/s), and t is the time. To find the horizontal distance, we can use the equation:
x = vt + 0.5a*t^2
25 = 20t + 0.59.8t^2
0.59.8t^2 + 20t - 25 = 0
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A small car moving at 20 m/sec collides head on with an oncoming large truck moving at 25 m/sec. Which vehicle undergoes the largest change in its momentum
Answer:
The truck will undergo the largest change in momentum if it has a greater mass than the small car.
Explanation:
The change in momentum of an object can be calculated using the equation:
Δp = m * Δv
where Δp represents the change in momentum, m represents the mass of the object, and Δv represents the change in velocity.
Since we are comparing the change in momentum of the car and the truck, we need to consider the masses of both vehicles.
Let's assume the mass of the car is represented by m_car, and the mass of the truck is represented by m_truck.
Since both vehicles collide head-on, the change in velocity (Δv) will be the difference between their initial velocities, considering that they are moving in opposite directions:
Δv = v_truck - v_car
Now, let's compare the change in momentum for the car and the truck:
For the car:
Δp_car = m_car * Δv
For the truck:
Δp_truck = m_truck * Δv
Comparing the magnitudes of the change in momentum, we can neglect the negative sign:
|Δp_car| = |m_car * Δv|
|Δp_truck| = |m_truck * Δv|
Since both Δv and Δp are positive values, we can conclude that the vehicle with the greater mass will undergo the largest change in its momentum.
Therefore, if the mass of the truck (m_truck) is greater than the mass of the car (m_car), then the truck will undergo the largest change in its momentum. Conversely, if the mass of the car is greater, then the car will undergo the largest change in its momentum.
If the truck has a mass of 2,000 kilograms , what's its momentum?(v=35 m/s)
Answer:
\(\boxed {\boxed {\sf 70,000 \ kg*m/s}}\)
Explanation:
Momentum is the product of mass and velocity.
\(p=m*v\)
The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.
\(m= 2000 \ kg \\v= 35 \ m/s\)
Substitute the values into the formula and multiply.
\(p= 2000 \ kg * 35 \ m/s \\p= 70,000 \ kg*m/s\)
The truck's momentum is 70,000 kilograms meters per second.
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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Chapter 9 Chapter Review
297
6. The starting line of a cross country foot race is at the
bottom of a hill. Which form(s) of mechanical energy of
the runners will change when the starting gun is fired?
Kinetic energy only
a.
b.
Potential energy only
1
c.
Both kinetic and potential energy
d. Neither kinetic nor potential energy
02 Simple Machines
Answer:
c. Both kinetic and potential energy
Explanation:
When the starting gun is fired at the beginning of a cross country foot race, the runners will begin to move from a stationary position at the bottom of a hill. This movement will result in a change in both their kinetic energy and potential energy.
Kinetic energy is the energy of motion, and it will increase as the runners accelerate from a stationary position and begin moving at a faster speed.
Potential energy is energy stored in an object due to its position or shape. The runners at the starting line have potential energy due to their position at the bottom of a hill. As they begin to move upward, their potential energy will decrease as they move further away from the ground.
Therefore, both kinetic and potential energy will change when the starting gun is fired at the beginning of a cross country foot race.
For an advanced lab project you decide to look at the red line in the Balmer series. According to the Bohr Theory, this is a single line. However, when you examine it at high resolution, you find that it is a closely-spaced doublet. From your research, you determine that this line is the 3s to 2p transition in the hydrogen spectrum. When an electron is in the 2p subshell, its orbital motion creates a magnetic field and as a result, the atom's energy is slightly different depending on whether the electron is spin-up or spin-down in this field. The difference in energy between these two states is ΔE = 2μBB, where μB is the Bohr magneton and B is the magnetic field created by the orbiting electron. The figure below shows your conclusion regarding the energy levels and your measured values for the two wavelengths in the doublet are λa = 6.544550 ✕ 10−7 m and λb = 6.544750 ✕ 10−7 m. (Let h = 6.626069 ✕ 10−34 J · s, c = 2.997925 ✕ 108 m/s, and μB = 9.274009 ✕ 10−24 J/T.) Determine the magnitude of the internal magnetic field (in T) experienced by the electron. When doing calculations, express all quantities in scientific notation, when possible keep six places beyond the decimal, and round your answer off to at least three significant figures at the end.
Answer:
1.000153 T
Explanation:
The energy change ΔE = hc(1/λb - 1/λa)
= 6.626069 ✕ 10⁻³⁴ J · s 2.997925 × 10⁸ m/s(1/6.544750 × 10⁻⁷ m - 1/6.544550 × 10⁻⁷ m)
= 19.864457907 × 10⁻²⁶(1527942.2438 - 1527988.9374) = 19.864457907 × 10⁻²⁶(-46.6936)
= 927.543052 × 10⁻²⁶
= -9.275431× 10⁻²⁴ J.
This energy change ΔE = 2μBB. So the magnetic field, B is
B = ΔE/2μB where μB = 9.274009 ✕ 10⁻²⁴ J/T
B = -9.275431× 10⁻²⁴ J/9.274009 ✕ 10⁻²⁴ J/T = -1.000153 T
The magnitude of the magnetic field B = 1.000153 T