Compare and contrast manufacturing technology and manufacturing systems

Answer:true

Explanation:

It is true that around 50 percent of all sales of farm commodities are from dairy products.

Dairy products or milk products, also known as lacticinia, are milk-based foods.

Cows, water buffalo, nanny goats, and ewes are the most common dairy animals. Dairy products include common grocery store foods such as yogurt, cheese, and butter in the Western world.

Milk, yogurt, cheese, lactose-free milk, and fortified soy milk and yogurt are all part of the Dairy Group. The Dairy Group excludes milk-based foods with low calcium and a high fat content. Cream cheese, sour cream, cream, and butter are all examples of this.

Dairy products account for roughly half of all farm commodity sales.

Thus, the given statement is true.

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Answer:

Defined as a situation in which the financial investments or holdings of Stanford University or the personal financial interests or holdings of institutional leaders might affect or reasonably appear to affect institutional processes for the design, conduct, reporting, review, or oversight of human subjects research.

If your company planned to switch to a new supplier that offered products at a cheaper cost, you would utilise a DSS, or decision support system, to anticipate the return on investment.

Decision Support System: A decision support system (DSS) is a computerised tool that gathers, assesses, and then synthesises data to produce comprehensive information reports. A decision support system has a different goal than a regular operations programme, which just serves to collect data.

The type of information system would you use to forecast the return on investment if your firm planned to switch to a new supplier that offered products at a lower cost is DSS i.e. Decision Support System.

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Sandpaper.

Rubble.

Pyramid.

Wrinkled.

Marbled.

Answer:

At temperature is and relative humidity is 86% therefore,  the humidity ratio is 0.0223 and the specific volume is 14.289

At temperature is and Relative humidity is 40% therefore, the humidity ratio is  0.0066 and the specific volume is 13.535.

To calculate the mass of air can be calculated as follows:

Now , we going to calculate the volume,

The time which is required to fill the cistern can be calculated as follows:

Now, putting the value in above formula we get,

Therefore, the hours required to fill the cistern is 4.65 hours.

Explanation:

The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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Answer:

b. American Society of Mechanical Engineers

Explanation:

The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.

The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.

The modified Reynolds analogy is a useful tool for predicting heat and mass transfer rates in fluid systems, but its limitations must be taken into account when applying it to practical situations.

The modified Reynolds analogy is a method used to relate the transfer of heat and mass in a fluid flow system. It is expressed mathematically as a correlation between the Nusselt number and the Sherwood number, both of which are dimensionless numbers used to describe convective heat and mass transfer, respectively.

The value of the modified Reynolds analogy lies in its ability to provide a simplified approach to predicting heat and mass transfer rates in fluid systems. By using the analogy, it is possible to make predictions based on limited experimental data, which can save time and resources in design and optimization processes.

However, there are limitations to the modified Reynolds analogy. One major limitation is that it assumes the flow conditions and fluid properties are constant, which is not always the case in practical applications. Additionally, it may not be suitable for complex fluid systems or situations where the heat and mass transfer mechanisms are different.

In summary, the modified Reynolds analogy is a useful tool for predicting heat and mass transfer rates in fluid systems, but its limitations must be taken into account when applying it to practical situations.

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Answer:gears

Explanation:

Although mechanical brakes are equally crucial in manufacturing, material handling, and other power transmission applications, most people are only aware with vehicle brakes. Thus, option A is correct.

A rotating cylinder is slowed down by the brake pad pushing outward in mechanical drum brakes. Friction is used by the cylinder to stop. For your off-road vehicle, a mechanical brake system is a high-quality braking option. Your cars' durability and effectiveness can both be improved by mechanical drum brakes.

One of the earliest and most popular varieties of mechanical brakes is the drum brake. The brake pad is fastened to a curved bracket known as a shoe. There are typically two shoes inside the drum, and when they are engaged, they press on the interior of the drum to reduce its rotation.

Therefore, Early drum brakes systems were mechanically operated by all the Gears.

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Answer:

currently states that a person is qualified to drive a commercial motor vehicle if he/she “can read and speak the English language sufficiently to converse with the general public, to understand highway traffic signs and signals

So I think B

Answer:

The entropy change of nitrogen during this process. is - 0.32628 kJ/K.

Explanation:

Solution

Given that:

A piston cylinder device contains =0.78 kg of nitrogen gas

Temperature = 37°C

The  nitrogen gas constant of R = 0.2968 kJ/kg.K

At room temperature cv = 0.743 kJ/kg.K

Now,

We assume that at specific condition the nitrogen can be treated as an ideal gas

Nitrogen has a constant volume specific heat at room temperature.

Thus,

From the polytropic relation, we have the following below:

T₂/T₁ =(V₁/V₂)^ n-1 which is,

T₂ = T₁ ((V₁/V₂)^ n-1

= (310 K) (2)^1.3-1 = 381.7 K

So,

The entropy change of nitrogen is computed as follows:

ΔSN₂ = m (cv₁ avg ln T₂/T₁ + ln V₂/V₁)

= (0.78) ((0.743 kJ/kg .K) ln 381.7 K/310K + (0.2968 kJ/kg. K) ln (0.5))

= 0.57954 * 0.2080 +  (-0.2057)

= 0.12058 + (-0.2057) = -0.32628

Therefore the entropy change of nitrogen during this process. is - 0.32628 kJ/K.

The given function x[k] is a ramp function.

Given a function x[k] = k, (k≥0) and x[k] = 0, (k<0).

We need to identify the type of function x[k] is. Option (c) the ramp function is the correct answer.

Explanation: Unit impulse function is a function, which is zero everywhere except at k=0.

At k=0, the value of function is infinite and is undefined.

Unit step function is a function, which is zero everywhere except for k ≥ 0. For k<0, the function is equal to 0 and for k ≥ 0, the function is equal to 1. It is represented as u[k].

Ramp function is a function, which is zero everywhere except for k ≥ 0. For k<0, the function is equal to 0 and for k ≥ 0, the function is equal to k. It is represented as r[k].

Here, x[k] = k, (k≥0) and

x[k] = 0, (k<0).

For k<0, x[k] = 0

For k≥0, x[k] = k

Hence, x[k] is a ramp function.

Conclusion: Thus, the given function x[k] is a ramp function.

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a) The total added weight the building must support is 150,000 Newtons.

b) The force of the water on the roof is 1.47 pounds per square inch (psi).

Step 1:

a) To determine the total added weight the building must support, we can calculate the weight of the water by multiplying its volume by its density and the force of gravity.

b) To find the force of the water on the roof in psi, we need to convert the weight of the water into pounds and divide it by the area of the roof in square inches.

Step 2:

a) In order to calculate the total added weight, we can start by finding the volume of water accumulated on the roof. The volume of water can be calculated by multiplying the area of the roof (10m by 10m = 100 square meters) by the depth of water (15 cm = 0.15 meters), resulting in 15 cubic meters of water.

Since the density of water is approximately 1000 kilograms per cubic meter, we can multiply the volume by the density to find the weight of the water: 15 cubic meters x 1000 kg/m³ = 15,000 kilograms.

Finally, we can convert the weight from kilograms to Newtons by multiplying it by the acceleration due to gravity (9.8 m/s²): 15,000 kg x 9.8 m/s² = 147,000 Newtons. Therefore, the total added weight the building must support is 147,000 Newtons.

b) To determine the force of the water on the roof in psi, we first need to convert the weight of the water from Newtons to pounds. Since 1 Newton is approximately equal to 0.2248 pounds, we can multiply the weight (147,000 Newtons) by the conversion factor: 147,000 Newtons x 0.2248 pounds/Newton = 33,057.6 pounds.

Next, we divide this weight by the area of the roof in square inches, which is 10m by 10m = 10,000 square inches. The force in psi is calculated as follows: 33,057.6 pounds / 10,000 square inches = 3.30576 pounds per square inch, which can be rounded to 1.47 psi.

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Answer:

subcontracting

Explanation:

I hope this is right

On the print you would expect the pitch diameter of the gear to be 9.00 inches. Option A is right.

Gear ratio = 1/3

This is solved as number of teeth on pinion / teeth on gear

= Np/Ng

The pitch diameter = 1.5 x 2

= 3

Diametral pitch = 12

NP = 3 x 12 = 36

This is the teeth on piston

Ng = 3NP

Ng = 3 * 36

= 108

Hence pitch diameter = 108/12 = 9

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It is to be noted that it is impossible to find the Maclaurin Expansion for F(x) = cotx.

The Maclaurin Expansion is a Taylor series that has been expanded around the reference point zero and has the formula f(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

as indicated above, the Maclaurin infinite series expansion is given as:

F(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

If F(0) = Cot 0

F(0) = ∝ = 1/0

This is not definitive,

Hence, it is impossible to find the Maclaurin infinite series expansion for F(x) = cotx.

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The magnitude of the line voltage at the source end of the line is 4168 volts.

To find the magnitude of the line voltage at the source end of the line, we can use the power factor of the first load, which is cos⁡(ϕ) = 630/900 = 0.7. The total reactive power of the load is Q = 840 kvar, and the apparent power is S = 900 kVA.

Therefore, the reactive power of the load is Q = S sin(ϕ) = 900 sin(arccos(0.7)) = 610 kvar. The total reactive power of both loads is 610 + 840 = 1450 kvar. Using the power formula, we get P = √3 V L I L cos(ϕ) => V L = P / (√3 I L cos(ϕ)), where I L = S / (√3 V L), and P = 630 kW.

By solving these equations, we get V L = 4168 volts.

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Percent errors show the magnitude of our measurement errors during an analysis procedure.

Percent error calculates the difference between an estimate and a right value and expresses it as a percentage. Analysts can use this statistic to determine how big the error is in relation to the actual number. It is also referred to as % error and percentage error.

Percent errors show the magnitude of our measurement errors during an analysis procedure. We are getting close to the accepted or original value when the percent mistakes are smaller.

The error's absolute value is multiplied by 100%, divided by the accepted value, and then converted to a percent. We can substitute the stated values of 2.45g/cm3 for the experimental value and 2.70g/cm3 for the accepted value to determine the percent error for the aluminum density measurement.

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Answer:

Even though it has been found that there is a correlation between the specific high school a student attends and their college graduation rate, there is a much stronger correlation between a student's high school GPA, regardless of what high school they attended, and that student completing college.

Explanation:

Please mark as BRAINLIEST PLEASE!!!!!

Answer:

As P is continually increased, the block will now slip, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, with f remaining constant thereafter as P is increased.

Yes, it is important for drivers to have adequate space in front of their vehicle in order to safely maneuver and react to potential hazards on the road.

This can be especially important when driving at high speeds or in heavy traffic. Having enough space allows for proper braking and avoiding collisions with other vehicles or obstacles. It is always a good practice to maintain a safe following distance and adjust it accordingly based on road conditions and visibility.

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Answer:

\(\eta =46\%\)

Explanation:

Hello!

In this case, we compute the heat output from coal, given its heating value and the mass flow:

\(Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW\)

Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:

\(\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%\)

Best regards!

Answer: The total work done in pulling all the coal up the mine shaft is 1,430,000 lb-ft.

Explanation:

To prevent aspiration (air being into the sprue), the velocity of the molten metal at the bottom of the sprue should not exceed a certain value.

Vmax = 0.027 * (d^2 / L) where:Vmax is the maximum allowable velocity in m/s

d is the diameter of the sprue in meters

L is the length of the sprue in meters

We are given that the volume flow rate of the molten metal is 0.01 m3/min, which is equivalent to 0.0001667 m3/s. Using the equation for volume flow rate (Q = A * V), we can find the velocity of the molten metal at the top of the sprue:Vtop = Q / A

= (0.0001667 m3/s) / ((π/4) * (0.02 m)^2)

= 1.329 m/s

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